Name three examples of how the atom has changed since Rutherford's discovery of the nucleus .

Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=

V

nRT

​

 . Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}

mol⋅K

atm⋅L

​

 :

P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=

V

nRT

​

=

15.0

L

​

(0.33

mol

)(0.0821

mol⋅K

atm⋅

L

​

​

)(248.15

K

​

)

​

=0.4482atm

In conclusion, the pressure of this gas is P=0.4482 atm.

Reference:

Chang, R. (2010). Chemistry. McGraw-Hill, New York.

The answer is FALSE. I did it on ck-12

Carbon has an atomic number of 6 so its electron configuration will be 1s² 2s² 2p². It has two orbitals as indicated with the 2 as its period number with the outer orbital have 4 valence electrons. So carbon is in the p-orbital, period 2 and in group 4.

Inhalation, the following may result in chronic airway resistance is c. Nitrogen dioxide

Nitrogen dioxide is a toxic gas released primarily from vehicle exhausts and industrial processes involving the burning of fossil fuels. Long-term exposure to this pollutant can lead to increased airway resistance due to inflammation and damage to the lining of the airways. It can also aggravate pre-existing respiratory conditions, such as asthma and chronic obstructive pulmonary disease (COPD).

In contrast, carbon monoxide (a) and carbon dioxide (b) do not typically cause chronic airway resistance, though they can be harmful in other ways. Sulfur dioxide (d) can cause respiratory issues, but its effects tend to be more short-lived compared to nitrogen dioxide. Overall, nitrogen dioxide is the most likely to cause chronic airway resistance among the options provided. Inhalation, the following may result in chronic airway resistance is c. Nitrogen dioxide

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Answer:

Chemical reactions that absorb (or use) energy overall are called endothermic. In endothermic reactions, more energy is absorbed when the bonds in the reactants are broken than is released when new bonds are formed in the products.

Answer:

Hard water is water that has high mineral content, Soft water is free from dissolved salts of such metals as calcium, iron, or magnesium

Explanation:

Answer:

B) 10.5

Explanation:

PV= NRT     -> N=PV/RT

N= mols .     P= pressure . V= volume in Liters    T= temp in Kelvin (Celsius degree = 273.15) .  R= Gas constant (.0821 for atm)

N=(.77 x 65.5)/(.0821x235) = 2.614 mols of Helium

Mols x Molecular weight = weight in grams

2.614x4.003(Molecular weight ot He) = 10.46 round to 10.5  

Answer:

17.1L

Explanation:

use ideal gas law

PV=nRT

101.325x = 0.7 x 8.314 x 298.15

^
Solve for x

X = 17.12424525 ~~ 17.1L

Answer:

17.11 L

Explanation:

The molar volume of a gas at room temperature (25°C) and pressure (1 atm) is 24.45 L/mol.

0.1 mole of propane reacts with oxygen to form 0.1 x 3 = 0.3 mole of carbon dioxide and 0.1 x 4 = 0.4 mole of water vapor.

The total volume of the gaseous products is 0.3 + 0.4 = 0.7 mole of gas.

Therefore, the volume of gaseous products obtained from the complete combustion of 0.1 mole of propane is 0.7 x 24.45 L/mol = 17.11 L.

The speed of the particles rises with the temperature of the solid, liquid, or gas. The particles slow down with decreasing temperature.

A liquid can turn into a solid if it is cooled down far enough.

The average kinetic energy of the molecules falls as a liquid cools.

The liquid eventually turns into a solid when the quantity of heat removed is sufficient to cause the molecules to be attracted to one another.

Freezing is the process of transitioning from a liquid to a solid.

It loses thermal energy when the liquid cools. Its constituent particles therefore decelerate down and converge.

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Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

Answer:

The answer is - C. Sweat, tears, skin, and mucus membranes.

Explanation:

Answer:

plasma flows but is a solid

Explanation:

example toothpaste flows but is a solid

Answer:

90.3%

Explanation:

The ionization values belong to the element magnesium (Mg). Ionization values help us determine the amount of energy that will be required to remove one or more electrons from an atom. The third period is where we can locate the element that has these ionization values.

These ionization values are listed in the table given below:Element: Mg (Magnesium)First ionization energy: 738 kJ/molSecond ionization energy: 1450 kJ/molThird ionization energy: 7732.7 kJ/mol

For a neutral atom, the first ionization energy (IE1) is the amount of energy required to remove an electron from the outermost shell. As we move from left to right in a period, the ionization energy increases. In the third period, Mg (magnesium) has first, second, and third ionization energies of 738 kJ/mol, 1450 kJ/mol, and 7732.7 kJ/mol, respectively. Magnesium is a chemical element that has an atomic number of 12. It has two valence electrons and is located in group 2 of the periodic table. Magnesium has a melting point of 1,202°F (650°C) and a boiling point of 1,994°F (1,090°C). It is a silver-white metal that is widely used in the manufacture of alloys and other industrial applications.

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The exact percentage of KHP in the original sample is approximately 78.05%.

Let's calculate the exact values step by step:

Given:

Mass of KHP sample = 0.5366 g

Volume of NaOH solution used = 21.35 mL

Molarity of NaOH solution = 0.09854 M

Step 1: Calculate the moles of NaOH used in the titration

Volume of NaOH solution (in liters) = 21.35 mL / 1000 mL/L = 0.02135 L

Moles of NaOH = Molarity of NaOH × Volume of NaOH solution

Moles of NaOH = 0.09854 M × 0.02135 L = 0.002101639 moles

Step 2: Moles of KHP = Moles of NaOH

Moles of KHP = 0.002101639 moles

Step 3: Calculate the molar mass of KHP

Molar mass of KHP = (8 × atomic mass of carbon) + (5 × atomic mass of hydrogen) + atomic mass of potassium + (4 × atomic mass of oxygen)

Molar mass of KHP = (8 × 12.01) + (5 × 1.01) + 39.10 + (4 × 16.00)

Molar mass of KHP = 204.221 g/mol

Step 4: Calculate the percentage of KHP

Percentage of KHP = (Moles of KHP × Molar mass of KHP) / Mass of KHP sample × 100%

Percentage of KHP = (0.002101639 moles × 204.221 g/mol) / 0.5366 g × 100%

Percentage of KHP ≈ 78.05%

Therefore, the exact percentage of KHP in the original sample is approximately 78.05%.

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The right response is that the forward and reverse reaction rates are equivalent.

The concentrations of reactants and products are no longer changing macroscopically when the rate of the forward reaction equals the rate of the reverse reaction. On a microscopic level, there might still be very slight variations.

As some reactant(s) will remain at equilibrium, the reaction has not completely ended.

In a chemical reaction, the forward reaction rate is the rate at which reactants are converted into products, while the reverse reaction rate is the rate at which products are converted back into reactants.

The reverse reaction rate can be influenced by factors such as temperature, pressure, and the concentrations.

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Answer:

The molarity of the final solutions if these two solutions are mixed is 27.14 \(\frac{moles}{L}\)

Explanation:

Yo know:

Molarity being the number of moles of solute per liter of solution, expressed by:

\(Molarity (M)= \frac{number of moles}{volume}\)

You can determine the number of moles that are mixed from each solution as:

Number of moles= Molarity*Volume

So, being 1 L=1000 mL, for each solution you get:

When mixing both solutions, it is obtained that the volume is the sum of both solutions:

Total volume= volume solution-1 + volume solution-2

and the number of total moles will be the sum of the moles of solution-1 and solution-2:

Total moles= moles of solution-1 + moles of solution-2

So the molarity of the final solution is:

\(Molarity (M)= \frac{moles of solution 1 + moles of solution 2}{Volume solution 1 + Volume solution 2}\)

In this case, you have:

Replacing:

\(Molarity (M)=\frac{10 moles + 9 moles}{0.400 L + 0.300 L}\)

Solving:

\(Molarity (M)=\frac{19 moles}{0.700 L}\)

Molarity= 27.14 \(\frac{moles}{L}\)

The molarity of the final solutions if these two solutions are mixed is 27.14 \(\frac{moles}{L}\)

Moles of Water

Moles = mass ÷ molar mass

          = 56.00 g ÷ 18.015 g/mol

          = 3.1085 mol

Molecules of Water

Number of molecules = moles × Avogadro's Number

                                    =  3.1085 mol × (6.022 × 10²³ molecules/mol)

                                    =  1.872 × 10²⁴ molecules

Note: We could do all this calculation in one step but I separated it to make it clearer.

The reaction rate of Compound A with respect to benzene refers to the speed at which Compound A reacts with benzene in a chemical reaction.

It is typically measured by monitoring the rate of formation of a product or the disappearance of a reactant over time. The reaction rate can be influenced by various factors, such as temperature, concentration, pressure, and the presence of catalysts or inhibitors. Understanding the reaction rate of each compound analyzed with respect to benzene is important in determining the efficiency and effectiveness of the reaction, as well as in optimizing reaction conditions for maximum yield and purity of the desired product.

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--The complete question is, What is the reaction rate of Compound A with respect to benzene? --

Answer:

1.0535×10(exponent24)

Explanation:

N (number of molecules)

n(number of moles)

L( Avogadro's constant )

N=n×L

N=1.75×6.02×10(exponent 23)

Explanation:

In one mole we always have:

1 mol = 6.02 X 10²³ molecules

So emulates simple rule of 3 we will have;

1 mol ----------> 6.02 X 10²³

1.75 moles ----> X

X = 1.0535 X 10²⁴ molecules

Hope this helps, Good studies!

According to molar concentration, the  molarity of potassium chloride solution is 0.315 M.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In case of 2 solutions, it is calculated as, M₁V₁=M₂V₂ which on substitution gives M₁=0.105×60/20=0.315 M.

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Appropriate benefit of dietary fiber intake to its associated disease.- c. Decreases intestinal transit time and exposure to potential toxins

Cardiovascular diseases (CVDs) are the most common cause of death worldwide, claiming the lives of an estimated 17.9 million persons each year. CVDs are a group of heart and blood disorders that include coronary artery disease, vascular disease, rheumatic fever, and others. Coronary heart disease could be cured, but treatment can help manage the symptoms and lower the risk of conditions such as heart attacks. Treatment may include changes in lifestyle, such as physical activity and quitting smoking. The most common symptom of heart disease is heart disease (CHD), which kills approximately 382,820 people every year. Every year, approximately 805,000 Americans suffer a heart attack.

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The situation described can be solved using the combined gas law, which states:

(P1 x V1) / (T1) = (P2 x V2) / (T2)

Where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, respectively. P2, V2, and T2 are the final pressure, volume, and temperature of the gas, respectively.

To solve for the final temperature (T2), we can rearrange the equation as:

T2 = (P2 x V2 x T1) / (P1 x V1)

Let's plug in the given values:

P1 = 700 mm

P2 = 800 mm

V1 = V2 (since the volume is doubled)

T1 = 0°C + 273.15 = 273.15 K (converting to Kelvin)

So, we have:

T2 = (800 mm x 2V1 x 273.15 K) / (700 mm x V1)

T2 = (1600/7) x 273.15 K

T2 = 392.2 K

Therefore, the final temperature at which the volume of gas would be doubled, if the pressure increases from 700-800 mm and the gas is initially at 0°C, is approximately 392.2 Kelvin (which is approximately 119°C or 246°F).

Answer:

0.00050553

Explanation:

when the power of ten is negative, move the decimal to the left

hope this helped!

Option b, which consists of 6.22 g of sodium and 1.48 g of chlorine, could be the result of the decomposition of the other sample consistent with the law of constant composition.

The law of constant composition states that a compound always contains the same elements in the same proportion by mass. In this case, we are given that one sample of sodium chloride produced 1.06 g of sodium and 1.63 g of chlorine.

To determine which option is consistent with the law of constant composition, we need to calculate the mass ratio of sodium to chlorine in each option:

a. Mass ratio: sodium/chlorine = 6.22 g / 16.8 g ≈ 0.37

b. Mass ratio: sodium/chlorine = 6.22 g / 1.48 g ≈ 4.20

c. Mass ratio: sodium/chlorine = 6.22 g / 3.11 g ≈ 2.00

d. Mass ratio: sodium/chlorine = 6.22 g / 9.58 g ≈ 0.65

Comparing these ratios to the mass ratio obtained from the first sample (approximately 0.65), we can see that only option b has a similar ratio.

Therefore, option b could be the result of the decomposition of the other sample, consistent with the law of constant composition. The mass ratio of sodium to chlorine in option b is approximately the same as the mass ratio observed in the first sample, indicating that the elements are present in the same proportion as in sodium chloride.

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Answer:

Fluorine: non-metal

Bromine: non-metal

Hydrogen: non-metal

Beryllium: metal

Nitrogen:non-metal

i) you would need 60 mL of the 50X TAE Buffer stock. ii)You would need 2940 mL of distilled water (dH2O) to make up the 1X TAE Buffer to a total volume of 3 liters.

To dilute the 50X TAE Buffer to a 1X working solution for a total volume of 3 liters, you would use the following calculations:

(i) 1X TAE Buffer - stock:

For a 1X TAE Buffer, the dilution factor is 50X. Since you want to prepare a total volume of 3 liters, the volume of the stock solution needed can be calculated as follows:

Volume of 50X TAE Buffer stock = (Final volume / Dilution factor)

                              = (3 L / 50)

                              = 0.06 L or 60 mL

Therefore, you would need 60 mL of the 50X TAE Buffer stock.

(ii) 1X TAE Buffer - dH2O: To make up the remaining volume with distilled water (dH2O), subtract the volume of the stock solution from the final volume:

Volume of dH2O = (Final volume - Volume of 50X TAE Buffer stock)

             = (3 L - 0.06 L)

             = 2.94 L or 2940 mL

Therefore, you would need 2940 mL of distilled water (dH2O) to make up the 1X TAE Buffer to a total volume of 3 liters.

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Answer:

I think B but I'm not sure.

Answer: Amplitude of the light wave impacts brightness; the wavelength is what impacts/is associated with color.