not sure how to do this

the topic is limited reactants
i could do the first 2 but i’m stuck on this one because i don’t know the formula

Equilibrium. Option C is correct

This law states that a new equilibrium state is achieved if the changes in temperature, pressure, concentration and volume will cause a predictable and opposing changes in the system.

This shows that Le Chatelier's principle can be used to predict the properties above to determine the effect equilibrium have on a system.

Based on the above explanations, we can conclude that Le Chatelier's Principle governs the property of Equilibrium.

Answer:

Aluminum and Zinc

Explanation:

Amphoteric oxides have both acidic and basic properties. The oxides of aluminium and zinc are examples. They form salts when they react with acids. They also react with alkalis to form complex salts.

Answer:

The answer to the question is 148.3 g

Explanation:

To find moles, you want to get rid of the grams by finding molar mass. Then, you have to get rid of grams using cross multiplication. This is why 148.3 grams is on the bottom; it will get rid of the grams on the original amount leaving you moles.

To find the concentration of the unknown oxalic acid solution, we need to use the balanced chemical equation for the reaction:NaOH + H₂C₂O → H₂O + Na₂C₂O₁

From the equation, we can see that the mole ratio between sodium hydroxide (NaOH) and oxalic acid (H₂C₂O) is 1:1. First, we need to determine the number of moles of NaOH used in the titration. The molar mass of NaOH is 22.99 + 16.00 + 1.01 = 40.00 g/mol. Therefore, the number of moles of NaOH is:moles of NaOH = mass of NaOH / molar mass of NaOH

= 22 g / 40 g/mol

= 0.55 mol

Since the mole ratio between NaOH and H₂C₂O is 1:1, the number of moles of H₂C₂O is also 0.55 mol.Now, we can determine the concentration of the oxalic acid solution using the volume of the acid used in the titration. The volume is given as 14.9 mL, which is equivalent to 0.0149 L. concentration of oxalic acid (C) = moles of H₂C₂O / volume of H₂C₂O

= 0.55 mol / 0.0149 L

≈ 36.91 mol/L.Therefore, the concentration of the unknown oxalic acid solution is approximately 36.91 mol/L.

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Option B is supported by the mass of 2.75 104 moles of NaOH, which is 1.1 102 g.

To find the mass of \(2.75 x 10^-^4\) moles of NaOH, we need to use the formula:
mass = moles x molar mass

The molar mass of \(NaOH\) is 40.00 g/mol (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H).
So, the mass of \(NaOH\) is:

mass =\(2.75 x 10^-^4\) mol x 40.00 g/mol
mass = 0.011 g

Converting this to scientific notation, we get:
mass \(= 1.1 x 10^-^2 g\)

Therefore, the answer is option b)\(1.10 x 10^-^2 g NaOH.\)

To find the mass of \(NaOH\), we need to use the formula:
mass = moles × molar mass

The molar mass of \(NaOH\) (sodium hydroxide) is approximately 40 g/mol (23 g/mol for Na, 16 g/mol for O, and 1 g/mol for H).

Given, moles of \(NaOH\) = 2.75 × 10⁻⁴
Now, let's calculate the mass:
mass = (2.75 × 10⁻⁴ moles) × (40 g/mol) = 1.1 × 10⁻² g

So, the mass of 2.75 × 10⁻⁴ moles of \(NaOH\) is 1.1 × 10⁻² g, which corresponds to option B.

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The energy needed is the energy that changes. The electron in a hydrogen atom is initially assumed to be in the ground state with n=1. The energy of the electron in its ground state is therefore 13.6 eV.

As a result, 12.75eV of the energy is needed to transfer electrons from the ground state to the third excited state. The 4th and 5th ionisation the energies differ significantly from one another. The fourth electron is attracted to the nucleus atom considerably less strongly than the fifth electron because it is in an inner main shell that is closer to the nucleus.

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The volume of hydrogen gas produced is 0.266 L, from 50.0 mL of 0.214 M H₂SO₄ and 0.300 g of Al.

To solve this problem, we need to use stoichiometry to determine how much H₂ gas will be produced from the given amounts of H₂SO₄ and Al, and then use the ideal gas law to calculate the volume of H₂ gas at the given conditions.

Balanced chemical equation for the reaction;

2Al (s) + 3H₂SO₄ (aq) → Al₂(SO₄)₃ (aq) + 3H₂ (g)

From the equation, we can see that 3 moles of H₂ are produced for every 2 moles of Al. We can use this ratio to calculate the number of moles of H₂ produced from the given mass of Al

0.300 g Al × (1 mol Al / 26.98 g) × (3 mol H₂ / 2 mol Al) = 0.0329 mol H₂

Next, let's use the volume and concentration of H₂SO₄ to calculate the number of moles of H₂SO₄ used in the reaction;

50.0 ml H₂SO₄ × (1 L / 1000 ml) × (0.214 mol / L) = 0.0107 mol H₂SO₄

Since the reaction requires 3 moles of H₂SO₄ for every 2 moles of Al, we can see that the amount of H₂SO₄ is limiting the amount of H₂ that can be produced. Therefore, we can conclude that 0.0107 mol of H₂ will be produced.

Now, we can use the ideal gas law to calculate the volume of H₂ gas produced at the given conditions;

PV = nRT

P = 750. mmHg = 0.987 atm (converting to atm)

V = unknown

n = 0.0107 mol

R = 0.0821 L atm / (mol K)

T = 25 + 273 = 298 K

Solving for V, we get;

V = nRT / P = (0.0107 mol)(0.0821 L atm / (mol K))(298 K) / 0.987 atm

= 0.266 L

Therefore, the volume of H₂ gas produced is 0.266 L.

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447.81830943999995. that's the mass

Approximately 24.55 cm^3 of oxalic acid must be added to sufficient water to give a 1.500 liter solution with a formal concentration of 0.300 F.

To find the volume of oxalic acid needed to make a 1.500 liter solution with a formal concentration of 0.300 F, we need to use the equation:

Formal concentration (F) = (moles of solute) / (volume of solution in liters)

First, we need to calculate the moles of oxalic acid required. The formal concentration (F) is given as 0.300, so:

0.300 = (moles of oxalic acid) / 1.500

Rearranging the equation, we find:

moles of oxalic acid = 0.300 * 1.500

moles of oxalic acid = 0.450

Next, we can calculate the mass of oxalic acid needed using its molecular mass:

mass of oxalic acid = moles of oxalic acid * molecular mass

mass of oxalic acid = 0.450 * 90.03

mass of oxalic acid = 40.5145 g

Finally, we can calculate the volume of oxalic acid needed using its density:

volume of oxalic acid = mass of oxalic acid / density

volume of oxalic acid = 40.5145 g / 1.65 g/cm^3

volume of oxalic acid = 24.55 cm^3

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To determine the number of H+(aq) ions present in the given solution of sulfuric acid (H₂SO₄), we need to use the molarity (M) and volume (V) of the solution.

The given information is:

Molarity (M) = 0.722 M

Volume (V) = 65.5 mL = 65.5 cm³

To find the number of H+(aq) ions, we need to consider the dissociation of sulfuric acid in water:

H₂SO₄ → 2H⁺(aq) + SO₄²⁻(aq)

From the balanced equation, we can see that for every 1 mole of sulfuric acid (H₂SO₄), it dissociates into 2 moles of H⁺(aq) ions.

First, let's convert the volume from milliliters (mL) to liters (L):

V(L) = V(mL) / 1000

V(L) = 65.5 mL / 1000 = 0.0655 L

Next, we can calculate the number of moles of sulfuric acid (H₂SO₄) in the solution using the formula:

moles = Molarity * Volume

moles(H₂SO₄) = 0.722 M * 0.0655 L

Now, we know that for every 1 mole of sulfuric acid (H₂SO₄), it dissociates into 2 moles of H⁺(aq) ions. Therefore, the number of H⁺(aq) ions can be calculated as:

moles(H⁺) = 2 * moles(H₂SO₄)

Finally, we can convert the moles of H⁺(aq) ions into the number of ions using Avogadro's number (6.022 × 10²³ ions/mol).

Number of H⁺(aq) ions = moles(H⁺) * Avogadro's number

By performing these calculations, we can determine the number of H⁺(aq) ions present in 65.5 mL of 0.722 M sulfuric acid.

Number of H⁺(aq) ions = 0.094722 moles * 6.022 × 10²³ ions/mol

Number of H⁺(aq) ions ≈ 5.701 × 10²² ions

Therefore, approximately 5.701 × 10²² H⁺(aq) ions are present in 65.5 mL of 0.722 M sulfuric acid.

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The percent yield of MgCl2 is calculated as follows: (35.8 g/45.56 g) * 100% = 78.58% per mass. The actual yield od MgCl2 is 35.8 g.

The chemical formula of magnesium chloride, or MgCl2, is one magnesium & two chloride ions. It is a salt (compound). MgCl2(H2O)x is the formula for its different hydrates. As an alloying agent and for catharsis.

MgCl2, a solid white substance. The direct mixing of dry chlorine and magnesium results in the unknown hydrate (hexagon shaped; r.d. 2.32; p.p.m. 714°C; b.p. 1412°C): Mg(s)+Cl2(g) = MgCl2 (s) As a component of carnallite (KCl), the substance also naturally exists.

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There are 3 important numbers.All digits in significant figures that are not zeros.

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Answer:

# protones: 22

# neutrones: 26

# electrones: 22

Explanation:

El número atómico del titanio es 22. Este número atómico representa la cantidad de protones del átomo en cuestión. Así:

# protones: 22.

El número másico se define como la suma de protones y neutrones, así:

48 = 22 + # neutrones

26 = # neutrones

Un átomo es neutro, esto quiere decir que sus cargas positivas y negativas son iguales (Protones: cargas positivas; Electrones: Cargas negativas).

Así, el # protones = # electrones = 22

the energy an object has because of its position rather than its motion.

Answer:

The number is mostly related to the mass or the weight of the element.

Explanation:

Answer:

Atomic mass i believe..

To identify whether the solution contains Cr3+ or Ni2+ ions, a single reagent can be used. A solution of 1,10-phenanthroline in ethanol can be added to the unknown solution.

To identify whether the solution contains Cr3+ or Ni2+ ions, a single reagent can be used. A solution of 1,10-phenanthroline in ethanol can be added to the unknown solution. If Cr3+ is present, a red complex ion will form, [Cr(phen)3]3+, due to the reaction between Cr3+ and the 1,10-phenanthroline. On the other hand, if Ni2+ is present, a green complex ion will form, [Ni(phen)3]2+, due to the reaction between Ni2+ and the 1,10-phenanthroline. The color change of the solution will indicate the presence of either Cr3+ or Ni2+ ion. This reaction is known as a complexation reaction, where a ligand (1,10-phenanthroline) binds to a metal ion (Cr3+ or Ni2+) to form a complex ion with a characteristic color.

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Answer: The answer is  Ernest Rutherford.

Explanation:

The atom economy of method 1 is 17%

Titanium is a valuable and expensive metal with some unique properties that make it suitable for special purposes.

Titanium is the perfect material for marine and aerospace applications because it has high corrosion resistance, especially in saltwater settings. Additionally biocompatible, titanium does not react with living tissue.

We know that the formula for atom economy is;

Atom economy(%) = Mass of desired product/Mass of reactants * 100/1

Mass of desired product = 48 g

Mass of reactants = 80 + 142 + 12 + 48 = 282 g

Atom economy (%) = 48/282 * 100/1

= 17%

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Answer: A decomposition reaction occurs when one reactant breaks down into two or more products.

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When the tree species was preserved as a fossil in the Arizona desert, the environment was likely different compared to the present. Based on the fact that the tree species is now extinct, infer that the conditions that supported its existence have significantly changed.

In the past, the environment where the tree lived may have had different climatic conditions, such as temperature, precipitation patterns, and humidity levels. It may have been part of a specific ecosystem or habitat that provided suitable resources for the tree's growth and survival. The tree species may have had adaptations that allowed it to thrive in that particular environment.

The extinction of the tree species may have had cascading effects on other living things that were associated with it. For example, other plant species that relied on the tree for shade or as a host for epiphytic growth might have also suffered or disappeared. Similarly, animals that depended on the tree for food, shelter, or nesting sites could have been affected by its extinction.

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6.9 cause argon is a proactive system that can be sick

The species would be an anuran (an amphibian)

We need to answer this in English.

Here we want to find "A species that mates on the surface and then deposits its eggs in the water to be surrounded by sperm"

This would be known as a species of amphibian called an anuran, specifically a frog or toad.

Frogs and toads belong to the order Anura and have a characteristic reproductive cycle that involves external fertilization. During reproduction, the male releases his sperm into the water, and the female deposits her eggs in the water as well. The eggs are externally fertilized by sperm that swim around them. This process is known as external or external fertilization.

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Answer:

heat transfer is when you transfer heat from one thing to another and heat transformation is when heat is transforming into something else hope it helps

Explanation:

Answer:

35.8.540 its korrect now