Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes to an A-note at 440 Hz while the Boston Symphony Orchestra tunes to 442 Hz. If the speed of sound is constant at 343 m/s, find the magnitude of difference between the wavelengths of these two different A-notes. (Enter your answer in m.)

Answers

Answer 1

Answer:

Δλ = 3*10⁻³ m.

Explanation:

At any wave, there exists a fixed relationship between the speed of  the wave, the wavelength, and the frequency, as follows:

       \(v = \lambda* f (1)\)

       where v is the speed, λ is the wavelength and f is the frequency.

Rearranging terms, we can get λ from the other two parameters, as follows:

       \(\lambda = \frac{v}{f} (2)\)

Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:

        \(\lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m (3)\)

        \(\lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m (4)\)

The difference between both wavelengths, is just the difference between (3) and (4):

       \(\Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)\)

       ⇒ Δλ = 3*10⁻³ m.


Related Questions

A potentiometer wire is 10 m long and has a resistance of `18Omega`. It is connected to a battery of emf 5 V and internal resistance `2Omega`. Calculate the potential gradient along the wire.

Answers

The potential gradient along the wire is 0.208Vm⁻¹

We are given that,

Resistance of wire = R = 20Ω

Internal resistance = r = 18Ω

length of wire = L = 10m

E.M.F = ∈ =5V

Thus to find the value of potential gradient of the wire, we can use the equation,

i =  (∈)/(R+r)

i = 5v/ (20Ω +18Ω)

i = 0.104 A

Vr = iR =(0.104 A)(20Ω) =

Vr = 2.08 volt

Thus the potential gradient of the wire is given as,

potential gradient = V/L =  (2.08volt)/(10m)

potential gradient = 0.208Vm⁻¹

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A student is using two circuits to investigate power consumption. She connects two identical light bulbs in series in one circuit and in parallel in the second circuit. What should she measure to calculate which configuration uses more power?
Responses
A The resistance of the bulbs and the potential difference of the battery.The resistance of the bulbs and the potential difference of the battery.
B The current flowing into each bulb and the potential difference across each bulb.The current flowing into each bulb and the potential difference across each bulb.
C The current flowing out of the battery and the resistance of each bulb.The current flowing out of the battery and the resistance of each bulb.
D The potential difference of the battery and the resistance of the battery.

Answers

The potential difference across the each bulb and the current entering each bulb.

What occurs if you connect two light bulbs in series?

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

When are two identical bulbs linked in both series and parallel?

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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i need help with this pls

i need help with this pls

Answers

Answer:

C = (7 + 8) i + (5 - 1) j     adding vectors

C = 15 i + 4 j

theta = arctan (4 / 15) = 14.9 deg

Note that this is the same as adding x and y components

what is mass over density ?​

Answers

Mass over density is a mathematical expression that represents the ratio of mass to density. It is calculated by dividing the mass of an object or substance by its density. Mathematically, it can be represented as:

The equation relating mass (m) and density (ρ) is given by:

m = ρ * V

where:

m is the mass of the object or substance,

ρ is the density of the object or substance, and

V is the volume of the object or substance.

This equation states that the mass of an object is equal to the product of its density and volume. It shows that mass is directly proportional to density and volume.

A boat is traveling at an initial velocity of 2.7 meters per second in the positive direction. It accelerates at a rate of 0.15 meters per second squared for 12 seconds. What is the final velocity of the boat? ​

Answers

Answer:

\(\boxed {\boxed {\sf 4.5 \ m/s \ in \ the \ positive \ direction}}\)

Explanation:

We are asked to find the final velocity of the boat.

We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.

\(v_f= v_i + at\)

The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.

\(v_i\)= 2.7 m/s a= 0.15 m/s²t= 12 s

Substitute the values into the formula.

\(v_f = 2.7 \ m/s + (0.15 \ m/s^2)(12 \ s)\)

Multiply the numbers in parentheses.

\(v_f= 2.7 \ m/s + (0.15 \ m/s/s * 12 \ s)\)

\(v_f = 2.7 \ m/s + (0.15 \ m/s *12)\)

\(\v_f=2.7 \ m/s + (1.8 \ m/s)\)\(v_f=2.7 \ m/s + (1.8 \ m/s)\)

Add.

\(v_f=4.5 \ m/s\)

The final velocity of the boat is 4.5 meters per second in the positive direction.

A 2.0 kg block slides on a frictionless 15° inclined plane. A force parallel to the inclined plane is applied to the block. The acceleration of the block is 1.5 m/s? downhill. What is the applied force?

Answers

The applied force on the block sliding on the frictionless inclined plane is 1.9 N.

What is friction?

Friction is the force that opposes the sliding or rolling motion of one body relative to another. For example, when you want to stop or slow down, you use your car's brakes because the friction created between the brakes and the wheels slows down or stops the car.

The unevenness of the two contact surfaces creates friction. When an object rides on another object, the surface irregularities become entangled and friction occurs. The rougher the surface, the more irregularities there are, and the greater the friction.

Equation of motion along an inclined plane:

Fₙ = (m×g×sinθ) - (m×a)

Where, Fₙ = applied force

m = mass of the block (2.0 kg)

g = gravitational acceleration (9.8 m/s²)

a = acceleration (1.5 m/s²)

θ = inclination of plane (15°)

Fₙ = (2 × 9.8 × sin15) - (2 × 1.5)

Fₙ = (19.6 × 0.25) - 3

Fₙ = 4.9 - 3

Fₙ = 1.9 N

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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Two positive point charges are 4.9cm apart. If the electric potential energy is 70.0 μJ, what is the magnitude of the force between the two charges?

Answers

Hi there!

Recall the following:

\(V \text{ (Electric Potential Energy) } = \frac{kq_1q_2}{r}\\\\F_E = \frac{kq_1q_2}{r^2}\)

k = Coulomb's Constant (Jm/C²)

q = Charge (C)
r = distance between charges (m)

To calculate the electric force between the two charges, we can simply divide by another 'r' (distance):

\(F_E = \frac{70}{0.049} = \boxed{1428.57 \mu J}\)

Why is Rome warmer than New York in January

Answers

Answer:

The basic answer is sea flows. On the off chance that the air making a trip to New York moves via land, it will be cooler than the air and flows that reach, for instance, San Francisco. Along these lines, Rome is hotter than New York because of flows, topography and air development designs.

Explanation:

Brainliest?

Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 5.00 m above the ground and measure that it hits the ground 0.804 s later. Part APart complete What is the acceleration of gravity near the surface of this planet

Answers

Answer:

g = 15.5 m/s²

Explanation:

In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:

h = Vi t + (0.5)gt²

where,

h = height covered by the wrench = 5 m

Vi = Initial Velocity = 0 m/s

t = Time Taken to hit the ground = 0.804 s

g = acceleration due to gravity near the surface of the planet = ?

Therefore,

5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²

g = (5 m)/(0.3232 s²)

g = 15.5 m/s²

Need ASAP! Please Provide the Answer. I do not need an explanation. Thank you.

An iguana runs back and forth along the ground. The horizontal position of the iguana in meters over time is shown below.

Need ASAP! Please Provide the Answer. I do not need an explanation. Thank you.An iguana runs back and

Answers

The displacement of the iguana between 0 and 5 seconds is 6 m and the distance is 15 m.

What is displacement?

The displacement of an object is the change in the position of the object.

Displacement = change in position of the iguana

Displacement = position (5 seconds) - Position (0 seconds)

Displacement = 6 m - 0 m = 6 m

Distance traveled by the iguana

This the total path covered by iguana in the first 5 seconds.

Distance = speed x time

speed = (6 - 0) / (3 - 1) = 3 m/s

Distance traveled by 0 and 5 seconds = 5 x 3 m/s = 15 m

Thus, the displacement of the iguana between 0 and 5 seconds is 6 m and the distance is 15 m.

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uses of atmospheric pressure​

Answers

Atmospheric pressure is an indicator of weather. When a low-pressure system moves into an area, it usually leads to cloudiness, wind, and precipitation.

explain why the length of the pendulum is measured from the lower part of the wooden clamp

Answers

The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.

The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.

The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.

As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.

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In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O is

Answers

The point through which this ray will pass, after refraction by the lens is point D.

What is refraction of light?

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Now, in the Tracker tool, add kinetic energy, KE, and potential energy, PE, to your table. (Click on Table, then check KE and PE in the Table Columns dialog.) Also, adapt the two graphs to show kinetic energy and potential energy vs. time. (Click on the vertical axis labels; from the pop-up menu, select KE or PE.) Step forward through the video a frame at a time, tracking the process in the table and on the two graphs. Based on your observations, what can you say about your predictions in Part A and Part B concerning the potential and kinetic energy?

Answers

It appears that kinetic energy and potential energy have been added to the table, and the two graphs have been modified to display kinetic energy and potential energy.

How does potential energy become kinetic energy?

The charged particles start to work, though, as soon as the battery is pressed, converting the potential energy into kinetic energy. Similar to this, whenever you turn on a light, potential energy passes through your wiring and is converted into kinetic energy, which manifests as heat and light.

What connection exists between kinetic and potential energy and speed?

Potential energy is released, and thus releases kinetic energy in addition to other catalysts like gravity or elastic forces. Motion is created by kinetic energy.

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In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue).
The top of a pool table is a height ℎ=2.75 ft from the floor. If a player's ball lands a distance =16.50 ft from the table edge, what is her break shot speed 0?

In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players

Answers

The break shot speed of the player is determined as 96.5 ft/s.

Time of motion of the player

use the following kinematic equation to determine the time of motion of the player.

h = vt + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 2.75/32.17)

t = 0.171 s

break shot speed

vx = x/t

vx = 16.5 ft / 0.171 s

vx = 96.5 ft/s

Thus, the break shot speed of the player is determined as 96.5 ft/s.

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An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the two objects stick together. If the momentum is conserved, what is the new velocity of the combined object? Round to the nearest hundredth.

Answers

Answer:

18.60  m/s

Explanation:

Original momentum = mv = 4000        with m = 115    

after collision   m = 115 + 100 = 215 kg

  but the total momentum is still the same (conserved)

          4000 = 215 v      shows v = 18.60 m/s

Answer:

18.60

Explanation:

calculate the net force acting on the box in the following. refer to the screenshot below.

calculate the net force acting on the box in the following. refer to the screenshot below.

Answers

The net force acting on the box is 5N , and it is unbalanced.

since the forces acting on the system is 7N and 2N which is opposite direction.

Explanation:The sum of all forces acting on an object is known as net force. Newton's second law, which states that F = ma, where F is the net force, can be used to calculate the net force. m is the object's mass. a represents acceleration.When two forces act in the same direction on an object, the net force equals the sum of the two forces.In general, when opposing forces act on an object, such as the book on the table, the net force equals the difference between the two forces. In other words, the net force is calculated by subtracting one force from the other. The net force is zero if the opposing forces are equal or balanced.

here given two forces ,

        f1 = 7N

        f2 = 2N

since both forces are in opposite direction ,

     Net force = f1 - f2

                      = 7N - 2N

                      = 5N

so the net force that act on the given box is 5N and unbalanced .

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Work is done on a wooden crate by pushing it across a floor. The work done is equal to the force applied parallel to the floor multiplied by the

A. force of friction
B. distance moved
C. mass of the crate
D. crate's direction

Answers

The work done is equal to the force applied parallel to the floor multiplied by the distance moves. Hence, option B is correct.

When a wooden crate is pushed across a floor, the work done on it is given by the product of the force applied parallel to the floor and the distance moved by the crate.

This is because work is defined as the product of force and displacement in the direction of the force, which in this case is the distance moved by the crate. The force of friction and the mass of the crate are not relevant to the calculation of work done in this scenario

It is important to understand the concept of work and the factors that influence it, as it is a fundamental concept in physics and is used in many real-world applications.

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3. A bald eagle in level flight at a height of 135m drops the fish it caught. If the eagle's
speed is 25.0 m/s how far from the drop point will the fish land?

Answers

The horizontal distance travelled by the fish when dropped is 131.25 m.

What is the time of motion of the fish?

The time of motion of the fish from the given height is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

v is the initial vertical velocity = 0t is the time of motion'g is acceleration due to gravity

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 135 / 9.8 )

t = 5.25 seconds

The horizontal distance travelled by the fish when dropped is calculated as;

X = vt

X = 25 m/s  x  5.25 s

X = 131.25 m

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Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge

Answers

The force between two charges can be calculated using Coulomb's law, which states that the force (F) between two charges (q1 and q2) is proportional to the product of their charges and inversely proportional to the square of the distance (r) between them:

F = k * (q1 * q2) / r^2

where k is Coulomb's constant (9 x 10^9 N m^2 C^-2).

In this problem, we have two equal and opposite charges, so we can assume that q1 = -q2 = q. The distance between them is 40 mm, which is 0.04 m. We are given that the force between them is 0.5 N. Therefore, we can set up an equation:

0.5 N = k * (q * q) / (0.04 m)^2

Simplifying and solving for q:

q^2 = (0.5 N * (0.04 m)^2) / k
q^2 = (0.5 N * (0.04 m)^2) / (9 x 10^9 N m^2 C^-2)
q^2 = 8.88 x 10^-12 C^2
q = sqrt(8.88 x 10^-12 C^2)
q = 2.98 x 10^-6 C

Therefore, the magnitude of each charge is 2.98 x 10^-6 C.

A small car moving at 20 m/sec collides head on with an oncoming large truck moving at 25 m/sec. Which vehicle undergoes the largest change in its momentum

Answers

Answer:

The truck will undergo the largest change in momentum if it has a greater mass than the small car.

Explanation:

The change in momentum of an object can be calculated using the equation:

Δp = m * Δv

where Δp represents the change in momentum, m represents the mass of the object, and Δv represents the change in velocity.

Since we are comparing the change in momentum of the car and the truck, we need to consider the masses of both vehicles.

Let's assume the mass of the car is represented by m_car, and the mass of the truck is represented by m_truck.

Since both vehicles collide head-on, the change in velocity (Δv) will be the difference between their initial velocities, considering that they are moving in opposite directions:

Δv = v_truck - v_car

Now, let's compare the change in momentum for the car and the truck:

For the car:

Δp_car = m_car * Δv

For the truck:

Δp_truck = m_truck * Δv

Comparing the magnitudes of the change in momentum, we can neglect the negative sign:

|Δp_car| = |m_car * Δv|

|Δp_truck| = |m_truck * Δv|

Since both Δv and Δp are positive values, we can conclude that the vehicle with the greater mass will undergo the largest change in its momentum.

Therefore, if the mass of the truck (m_truck) is greater than the mass of the car (m_car), then the truck will undergo the largest change in its momentum. Conversely, if the mass of the car is greater, then the car will undergo the largest change in its momentum.

The energy stored in a wood log is transformed when the log is burned. Which of the following explanations best describes how the
chemical energy stored in the log compares to the heat and light energy produced by burning?
O A The chemical energy is equal to the amount of heat, light, and other applicable energies.
O B The chemical energy is less than the amount of heat, light, and other applicable energies.
OCThe chemical energy is more than the amount of heat, light, and other applicable energies.
D. The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies.

Answers

Answer:

D. The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies.

Hope this helps!

The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies. Thus option D is correct.

What is chemical energy ?

Energy is the ability to do work It can be movement of a body to do some physical activity.

If the energy is stored in the form of chemical bonds of a complex molecule then the energy is called as chemical energy.

The energy released in the chemical reaction and produced as as a by-product, that process is known as an exothermic reaction.

For instance,  chemical energy sored in biomass, batteries, natural gas, petroleum, and coal.

Dry wood also the storage of chemical energy, as it burns the chemical energy is released and converted into light energy and thermal energy

The food we eat is also an example of chemical energy storage as it is liberated during digestion process.  

Thus option D is correct.

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Please show work for number 1! I will give brainliest

Please show work for number 1! I will give brainliest

Answers

The value of angle of reflection of the ray is determined as 70⁰.

option B.

What is the angle of reflection?

Angle of reflection is the angle between a reflected ray and the perpendicular to a reflecting surface drawn at the point of contact.

Based on the definition of angle of reflection, we can determine the value of angle of reflection from the ray diagram as follows;

The incident angle (angle between the incoming arrow and the normal) = 70 degrees

The reflected angle (angle between the out going arrow and the normal) = 70 degrees

Thus, the value of angle of reflection of the ray is determined as 70⁰.

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The angle of reflection for the light ray shown in the diagram given in the question is 70° (option B)

How do i determine the angle of reflection?

To determine the angle of reflection, we must bear in mind the laws of reflection. This is given below:

The first law of reflection states that the incident ray, the reflected ray, and the normal at the point of incidence, all lies in the same plane. The second law of reflection states that the angle of reflection is equal to the angle of incidence i.e Angle of reflection = Angle of incidence

From the above law, we can obtain the angle of reflection. This is illustrated below:

Angle of incidence = 70°Angle of reflection =?

Angle of reflection = Angle of incidence

= 70°

Thus, we can conclude that the angle of reflection is 70° (option B)

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What is the period of an objects motion?

Answers

The time for an object to complete one full cycle. Can have a long period or short period.


Brainliest?

URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally insulated chamber. For water L = 3.33 x 105 J/kg. The specific heat of ice is 2090 J/(kg°C) and of water 4186 J/(kg°C). How much does the ice heat up in order to bring the water down to 0°C?


A. 0.04°C


B. 0.4°C


C. 4°C


D. 10°C


E. 20°C

Answers

Answer:

Explanation:

heat lost by water will be used to increase the temperature of  ice

heat gained by ice

= mass x specific heat  x rise in temperature

1 x 2090 x t

heat lost by water in cooling to 0° C

= mcΔt  where m is mass of water , s is specific heat of water and Δt is fall in temperature .

= 1 x 2 x 4186  

8372

heat lost = heat gained

1 x 2090 x t  = 8372

t = 4°C

There will be a rise of  4 degree in the temperature of ice.  

 

The increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.

The given parameters;

mass of the ice, m₁ = 1 kgtemperature of the ice, t₁ = -20°Cmass of the water, m₂ =  1 kgtemperature of the water, t₂ = 2 °C

Apply the principle of conservation of energy to determine the increase in the temperature of the ice to bring the water to 0 °C.

Heat absorbed by the ice = Heat lost by water

\(Q_{ice} = Q_{w}\\\\mc\Delta t_{ice} = mc \Delta t_{w}\\\\1 \times 2090 \times \Delta t = 1 \times 4186 \times (2-0)\\\\2090\Delta t = 8372\\\\\Delta t = \frac{8372}{2090} \\\\\Delta t = 4 \ ^0C\)

Thus, the increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.

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what would the mass be of an object that was moving at a velocity of 35 m/s and has a kinetic energy of 500j be?

Answers

Answer:

0.816 kg

Explanation:

\(E_k=\frac{1}{2}mv^{2}\\\)

so \(m=\frac{2E_k}{v^2}=\frac{2\times500}{35^2}=0.816 kg\)

A thin film with an index of refraction of 1.60 is placed in one of the beams of a Michelson interferometer. If this causes a shift of 8 bright fringes in the pattern produced by light of wavelength 580 nm, what is the thickness of the film

Answers

Answer:

3.867 μm

Explanation:

The index of refraction, μ = 1.6

Wavelength of the light, λ = 580 nm

N2 - N1 = (2L / λ) (n2 - n1), Making L subject of formula, we have

(N2 - N1) λ = 2L (n2 - n1)

L = [(N2 - N1) * λ] / 2(n2 - n1)

L = (8 * 580) / 2(1.6 - 1.0)

L = 4640 nm / 1.2

L = 3867 nm or 3.867 μm

Therefore we can come to the conclusion that the thickness of the film is 3.867 nm

The students brought the cart back to the starting point one more time. The cart sits motionless on the sidewalk as they plan their next investigation. What could they infer about the cart as it sits on sidewalk?

A. The forces acting on the cart are balanced. B. Gravity is the only force acting on the cart.
C. The cart has too much mass to be acted on by forces.
D. The cart moves only when acted on by a pulling force.​

Answers

The forces acting on the cart are balanced. this  they infer about the cart as it sits on sidewalk. Hence option A is correct.

The most plausible conclusion the students may draw about the cart, which is immobile on the sidewalk, is that the forces pulling on it are balanced based on the facts provided. Accordingly, there is no net force exerted on the cart, and forces operating in opposing directions cancel one another out to bring about equilibrium. The cart's inertia suggests that no unbalanced force is pressing on it, supporting the conclusion that the forces pushing the cart are also balanced. The most logical conclusion the students may draw is option A.

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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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