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D.Nitrogen oxides

Explanation:

In large quantity it can be very poisonous that can cut the follow of hemoglobin which can result to death.

Answer:

n=15 moles H2O

1:2

x:15

x=7.5 moles of O2

The Combined Gas Law, which emphasizes the following, can be used to address the issue:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where:

P₁ = Initial pressure

V₁ = Initial volume (unknown in this case)

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Let's plug in the given values:

P₁ = 60.0 atm

V₁ = unknown

T₁ = 115K

P₂ = 30.0 atm

V₂ = 29 liters

T₂ = 225K

We can rearrange the combined gas law equation to solve for V1 as follows:

V₁ = (P₁ * V₂ * T₁) / (P₂ * T₂)

Plugging in the values:

V₁ = (60.0 atm * 29 L * 115K) / (30.0 atm * 225K)

Simplifying the equation:

V₁ = (60.0 * 29 * 115) / (30.0 * 225)

V₁ ≈ 57.7 liters

Therefore, you initially started with approximately 57.7 liters of gas.

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Answer:c

Explanation:

The resonance structure of benzene can be depicted by drawing two possible arrangements of the double bonds. The electron flow arrows show the movement of pi electrons from the double bond to the single bond. Both structures are equivalent and contribute equally to the resonance hybrid of benzene.

Benzene is a cyclic compound that contains six carbon atoms and six hydrogen atoms. It has a planar structure with alternating double and single bonds between the carbon atoms. The resonance structure of benzene can be depicted by drawing two possible arrangements of the double bonds. One structure has the double bonds between the adjacent carbon atoms, while the other has the double bonds between alternate carbon atoms. Both structures are equivalent and contribute equally to the resonance hybrid of benzene.
To depict the electron flow in the resonance structure of benzene, we use curved arrows to show the movement of electrons. The arrows represent the movement of pi electrons in the molecule. The curved arrow starts from a bond or an atom where electrons are located and points towards the location where electrons will move to.
In benzene, the electron flow arrows move from the double bond to the single bond. The double bond between two carbon atoms in the first structure is shown by two parallel lines, which represents the sharing of four pi electrons between the two carbon atoms. The curved arrow starts from one carbon atom and points towards the adjacent carbon atom, indicating the movement of two pi electrons to form a double bond. This creates a negative charge on the first carbon atom and a positive charge on the adjacent carbon atom. Similarly, the second curved arrow moves from the second carbon atom to the third carbon atom to create another double bond and so on until it reaches the sixth carbon atom.
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The limiting reactant would be Cu and the excess reactant would be S.

From the equation:

     2Cu + S → Cu2S

Mole ratio of Cu to S = 2:1

Mole of 40.2 g Cu = 40.2/63.55

                                 = 0.63 moles

Mole of 14.1 g of S = 14.1/32.07

                                     = 0.44 moles

Equivalent mole of Cu = 0.44 x 2 = 0.88 moles

Thus, Cu is limiting while S is in excess.

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Answer:

The first two are 0.633 and 0.440

The answer for the next sentence is Copper and Sulfur

Answer:

Explanation:

You can see from the equation P = I² × R that for a given resistance the power depends on the current squared, so doubling the current will give 4 times the power.

Answer:

1-state what the lab is about, that is, what scientific concept (theory, principle, procedure, etc.) you are supposed to be learning about by doing the lab. You should do this briefly, in a sentence or two. If you are having trouble writing the opening sentence of the report, you can try something like: "This laboratory experiment focuses on X…"; "This lab is designed to help students learn about, observe, or investigate, X…." Or begin with a definition of the scientific concept: "X is a theory that…."                        2-give the necessary background for the scientific concept by telling what you know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab). In relatively simple labs you can do this in a paragraph following the initial statement of the learning context. But in more complex labs, the background may require more paragraphs.

Explanation:

Answer: the correct answer is A

Explanation:

Explanation:

GOLGI BODY - transportation of lipids and steroids.

LYSOSOME - destruction of malfunctioning or worn out cell organelles.

MITOCHONDRIA - oxides glucose to give energy to the cell in a form of cellular respiration.

VACUOLE - FOOD VACUOLE for storage of food while WATER VACUOLE eliminates excess water by a process called OSMOREGULATION.

CELL WALL - provides rigidity for the plant cell.

CHLOROPLAST - pigmented organelle of the plant which functions to manufacture food by a phenomenon known as PHOTOSYNTHESIS.

RIBOSOME - synthesizes protein and enzymes.

ENDOPLASMIC RETICULUM - The ROUGH ENDOPLASMIC RETICULUM has RIBOSOMES attached to it while the SMOOTH ENDOPLASMIC RETICULUM has nothing attached, they transport proteins and enzymes

According to the statement Na+ have 3 mol and PO43- have 1 mol.

A fixed amount of atoms are measured in a mole. Mole conversions are possible for quantities like grams and milligrams. However, because a mole is the sum of all the atoms, it does not have a gram or milligram equivalent. Any element or compound has an Avogadro number of atoms or 6.0221023 atoms, in 1 mole. A pure element's atomic mass in atomic mass (amu) or grams per mole (g/mol) is proportional to the weight of one mole of its atoms in grams.

Na3PO4 --------------> 3 Na+ + PO43-

1 mol Na3PO4 --------------> 3 mol Na+ + 1 mol PO43-

Therefore,

Na+ = 3 mol

PO43- = 1 mol

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Answer:

sketching a diagram of a new medical device (b)

Explanation:

its on edge technical design not d i got that one wrong

Answer:

the answer is b

Explanation: i took the test edge 2021

The theoretical standard cell potential for the given electrochemical cell is 1.05 V.

To calculate the theoretical standard cell potential for the electrochemical cell, we need to use the given standard reduction potentials of the half-reactions and apply them to the overall cell reaction.

The cell reaction is:

Mn+Pb²⁺ → Mn²⁺ + Pb

To determine the cell potential, we need to subtract the reduction potential of the anode (oxidation) from the reduction potential of the cathode (reduction). Since the given potentials are reduction potentials, we need to flip the sign of the anode potential.

The reduction potential for the reduction half-reaction:

Mn²⁺ + 2e⁻→ Mn

E°(Mn²⁺/Mn) = -1.18 V

The reduction potential for the reduction half-reaction:

Pb²⁺ + 2e⁻ → Pb

E°(Pb²⁺/Pb) = -0.13 V

Now, we can calculate the standard cell potential:

E°(cell) = E°(cathode) - E°(anode)

= E°(Pb²⁺/Pb) - E°(Mn²⁺/Mn)

= (-0.13 V) - (-1.18 V)

= 1.05 V

Therefore, the theoretical standard cell potential for the given electrochemical cell is 1.05 V.

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--The question is incomplete, the given complete question is:

"Calculate the theoretical standard cell potential for the electrochemical cell that includes the reaction. Mn+Pb²⁺→Mn²⁺+Pb The standard reduction potentials for each half reaction are given Mn²⁺+2e−→Mn -1.18 V Pb²⁺+2e−→Pb -0.13 V"--

answer✅☑️✔️️

1.0×10^-11

Answer:

when it comes to adding or subtracting numbers, his final answer should have the same number of decimal places as the least precise value.

For example if you add 2 numbers; 10.443 + 3.5 , 10.443 has 3 decimal places and 3.5 has only one decimal place.

Therefore 3.5 is the less precise value.

So when adding these 2 values the final answer should have only one decimal place.

after adding we get 13.943 but it can have upto one decimal place. then the second decimal place is less than 5 so the answer should be rounded off to 13.9.

the answer is the same number of decimal places as the least precise value

Explanation:

I think this is the answer I'm not sure

Answer: the same number of decimal places as the least precise value

Explanation:

                 Answer:

                     ⬇️

There are 1.9926 * 10 ^24 atoms.


M ( Mg ) = 80.45 g

We can find the molar mass of magnesium in the Periodic table:M ( Mg ) =              24.31 g / molen = 80.45 g :

                                     24.31 g/mole = 3.31 molesN a ( Avogadro`s constant ) = 6.02 * 10 ^23N = Na * n = 6.02 * 10 ^24 * 3.31 = 19.926 * 10 ^24

Answer:

d. The electron-pair geometry is tetrahedral, the molecular geometry is tetrahedral.

Explanation:

According to Valence Shell Electron Pair Repulsion Theory, the shape of a molecule depends on the number of electrons pairs surrounding the valence shell of the central atom in the molecule.

In CH3Cl, the central atom is carbon. Carbon has four regions of electron density surrounding it and no lone pairs. Lone pairs cause molecules to deviate from the expected geometry.

Since CH3Cl has no lone pairs on the carbon central atom, both the molecular and electron pair geometries are tetrahedral.

In CH₃Cl, the electron-pair geometry is trigonal-planar, and the molecular geometry is bent. Therefore, option C is correct.

According to VSEPR (Valence Shell Electron Pair Repulsion) theory, the electron pairs around the central atom in CH₃Cl will arrange themselves to minimize repulsion, resulting in a specific geometry.

In CH₃Cl, the central atom is carbon (C), and it is surrounded by three hydrogen atoms (H) and one chlorine atom (Cl).

The electron-pair geometry is determined by the arrangement of these electron pairs.

Molecular geometry considers only the atoms around the central atom, not the lone pairs.

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Answer:

7 C7H6O2 + 12 O2 → 14 CO2 + 6 H2O

Explanation:

To balance this equation, you need to make sure that the number of atoms of each element on both sides of the equation are equal. In this equation, the number of carbon atoms (7) and hydrogen atoms (12) on the left side must be equal to the number of carbon atoms (1) and hydrogen atoms (2) on the right side. To balance this equation, you need to add coefficients of 7, 12, 2, and 14, respectively, in front of the compounds C7H6O2, O2, CO2, and H2O. This results in the equation: 7 C7H6O2 + 12 O2 → 14 CO2 + 6 H2O

Answer:

D. The table pushes up on the vase with the same amount of force as gravity pulling it down

Explanation:

The balanced oxidation half equation is given below:

Oxidation reactions are reactions in which the oxidation of the species increases.

Oxidation reactions can involve addition of oxygen or electronegative elements to a substance or the removal of hydrogen or electropositive elements from a substance.

The balanced half-reaction for the oxidation of solid manganese dioxide to permanganate ion in acidic aqueous solution is given below:

MnO₂ + H₂O → MnO₄⁻ + H⁺ + 3 e⁻

In conclusion, the balanced oxidation half equation shows that three electrons were lost by the manganese (iv) ion to form manganese (vii) ion.

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Answer:

Coefficient = 1.58

Exponent = - 5

Explanation:

pH = 2.95

Molar concentration = 0.0796M

Ka = [H+]^2 / [HA]

Ka = [H+]^2 / 0.0796

Therefore ;

[H+] = 10^-2.95

[H+] = 0.0011220 = 1.122 × 10^-3

Ka = [H+] / molar concentration

Ka = [1.122 × 10^-3]^2 / 0.0796

Ka = (1.258884 × 10^-6) / 0.0796

Ka = 15.815 × 10^-6

Ka = 1.58 × 10^-5

Coefficient = 1.58

Exponent = - 5

\(E=hc/ \lambda\) is the equation for calculating the energy and wavelength of electron transitions in a one-electron system.

E = hv is the formula for calculating the energy of a single photon. It takes into account the energy in SI units of J, Planck's constant (h = 6.626 x 10-34 J s), and the frequency of the radiation in SI units of s-1 or Hertz, Hz. Wavelength and frequency are connected by the formula c/, where c is the speed of light, which is 2.998 x 108 m s-1.

The energy of the photon increases as the wavelength of light decreases. By dividing the aforementioned equation by Avogadro's number, one can determine the energy of a mole of photons with the wavelength

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The Environmental Protection Agency (EPA) is responsible for protecting human health and the environment.

Here are six things that the EPA does in order to accomplish its mission:

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Step 1

The reaction involved here:

3 FeO + 2 Al => 3 Fe + AI2O3 (Don't forget to completed it and balance it)

---------------

Step 2

Data provided:

125 grams of FeO react with 25.0 grams of AI

--

Data needed:

The molar masses of:

FeO) 71.8 g/mol

Al) 27.0 g/mol

Fe) 55.8 g/mol

---------------

Step 3

The limiting reactant:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

3 x 71.8 g FeO ----- 2 x 27.0 g Al

125 g FeO ----- X

X = 125 g FeO x 2 x 27.0 g Al/3 x 71.8 g FeO

X = 31.3 g Al

For 125 g of FeO, 31.3 g of Al is needed, but there is 25.0 g of Al, so the limiting reactant is Al.

-------------

Step 4

The amount of Fe produced:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

2 x 27.0 g Al ---- 3 x 55.8 g Fe

25.0 g Al --- X = 77.5 g Fe

Answer: 77.6 g Fe (the closest value)

2 physical changes:

1. Pounding it into a block

2. Melting it into liquid

2 chemical changes:

1. Combining it with another metal to find a metallic alloy

2. Testing the flammibility of the metal

Answer:

Explanation:

To identify the unknown metal, the industrial chemist can change its physical and chemical properties. Here are two ways the metal can be changed physically:

1. Changing the shape or form: The chemist can melt the metal and cast it into different shapes, such as rods, sheets, or wires. By observing how the metal behaves during melting and casting, the chemist can gather information about its melting point, malleability, and ductility. These physical properties can help narrow down the possible identity of the metal.

2. Changing the size or surface area: The chemist can grind or cut the metal into smaller pieces or increase its surface area by creating a powder or filing it down. Changing the size or surface area exposes more of the metal's surface to react with other substances. This can provide insights into the metal's reactivity and susceptibility to corrosion.

Now, let's explore two ways the metal can be changed chemically:

1. Reacting with acids: The chemist can test the metal's reactivity by exposing it to different acids, such as hydrochloric acid or sulfuric acid. By observing any chemical reactions, such as effervescence (formation of gas bubbles) or the production of salts, the chemist can gain information about the metal's reactivity and its position in the reactivity series.

2. Oxidation-reduction reactions: The chemist can subject the metal to oxidation-reduction reactions. For example, they can react the metal with oxygen to form an oxide or with another compound to displace a less reactive metal. These reactions can provide valuable clues about the metal's reactivity and its ability to gain or lose electrons.

It's important to note that these are just a few methods the industrial chemist could use to identify the unknown metal. Other techniques, such as spectroscopy or x-ray diffraction, may also be employed depending on the specific circumstances.

Answer:

explanations below

Explanation:

The alkaline earth metals are the 6 chemical elements that can be found in group two of the periodic table. These elements have a lot of properties in common, in the sense that they are generally shiny, reactive at standard temperature and pressure and they are also silvery-white. The elements are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra)

These metals have two electrons at their orbits, which can be easily lost to form cations (with charge +2, and an oxidation state of +2)  

Below are some of their details

Name: Beryllium  

Number of Protons/Electrons: 4  

Number of Neutrons: 5  

Name: Magnesium  

Number of Protons/Electrons: 12  

Number of Neutrons: 12  

Name: Calcium  

Number of Protons/Electrons: 20  

Number of Neutrons: 20  

Name: Strontium  

Number of Protons/Electrons: 38  

Number of Neutrons: 50  

Name: Barium  

Number of Protons/Electrons: 56  

Number of Neutrons: 81  

Name: Radium  

Number of Protons/Electrons: 88  

Number of Neutrons: 138  

Answer:

Thomson--atoms cotain electron

Ernest Rutherford--atoms have a positive nucleus

R.A Millikan--electrons have Q=-1

Dalton--atoms are indivisible

Millikan---> Electrons have a charge of -1

Rutherford ---> Atoms have a positive nucleus

Thomson -----> Atoms contain electrons

Dalton --------> Atoms are indivisible

The atomic theory went through several modifications and different scientists proposed various models of the atom until our present conception of the atom was developed.

The atom was first defined as the smallest indivisible particle of a substance. This idea of "indivisibility" of the atom stems from Dalton's theory.

The fact that atoms were composed of negatively charged electrons was proven by the experiments of J.J Thompson using the cathode ray tube. Millikan's charge to mass experiment showed that the electron has a charge of -1.

Rutherford, in his famous gold foil experiment showed that atoms were composed of a positively charged nucleus.

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As per the aleks data tab the chemical species can be given as per the following: Ag<Zn<Mg<Na

This is not a redox reaction. None of the species are reduced and none are oxidized.

The decreasing power will be greater the lower the reduction potential.

A chemical reaction known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances. An oxidation-reduction reaction is any chemical process in which a molecule, atom, or ion experiences a change in its oxidation number as a result of gaining or losing an electron.

Redox reactions are those in which one chemical is reduced and another is oxidized. Here, oxygen is being introduced, which causes C to oxidize into CO, and oxygen is being removed, which causes ZnO to decrease to Zn. It is a redox reaction as a result.

Redox reactions are those in which there is a change in the oxidation number, with both an increase and a drop in number.

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