Prompt the user for a day of the week (e.g., Sunday, Monday, etc.) Display the dates for that day of the week for the next year (see examples below). Do not use any built-in date functions. Don't use anything that we haven't covered in this class. If you do, you will get a zero for the assignment. You can solve this just with lists and loops, etc. If your program is more than 50 lines, you're doing it wrong! (See hint at the bottom.) What to submit: - Your Python program (a .py file) (Only submit one program, not 7!) - Four screen shots of your program working with three different sets of inputs, showing various results. Three of these data sets must match those shown below; the other data set should be one you construct (i.e., you choose a different day of the week).

Answer:

  (a) 100 V

  (b) 60 Hz

  (c) 95.106 V

  (d) 25 V, 75 V

  (e) 23.776 V, 71.329 V

  (f) see attached

Explanation:

The peak value of the sine function is 1, so the peak value of U is ...

  100·1 = 100 V.

__

The argument of the sine function is 2πft, so f = 120πt/(2πt) = 60 Hz.

__

When t=0.020, the voltage is ...

  U = 100sin(120π·0.020) = 100 sin(2.4π) ≈ 95.106 V

__

The resistors are in the ratio of 1 : 3, so divide the source voltage in that ratio.

The peak voltage across the 5Ω resistor is 1/4 of 100 V, or 25 V.

The peak voltage across the 15Ω resistor is 3/4 of 100 V, or 75 V.

__

The same fractions as in (d) apply to the instantaneous voltage.

The voltage on the 5Ω resistor is 1/4·95.106 V ≈ 23.776 V

The voltage on the 15Ω resistor is 3/4·95.106 V ≈ 71.329 V

__

See attached.

Effective communication is essential for engineers in South Africa as it plays a critical role in ensuring that projects are completed successfully.

Engineers must be able to communicate technical information accurately and concisely to stakeholders, including clients, colleagues, and contractors.

Poor communication can lead to misunderstandings, delays, and mistakes that can compromise the safety and quality of a project. Effective communication also helps to build trust and collaboration within teams and fosters a positive relationship with clients.

Therefore, engineers in South Africa need to have strong communication skills to ensure successful project outcomes and professional success.

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Answer:

safety glasses, hearing protection, respirator, work gloves, and work boots.

Explanation:

please give brainliest!! <3

Answer:

2-8

6-8

= -6

-2

= 3

because the minus cancels each other and then 6 divided by 2 is 3

Answer:

A. S0 = 1, S1 = 0, S2 = 0

lines need to send data for the fifth bit in an 8 bit system

d. Test before implementing is not a best practice for firewall changes. It is a best practice to test firewall changes after they have been implemented to ensure that they do not disrupt normal network operations.

What exactly is a Firewall?

A firewall is a network security system that monitors and controls incoming and outgoing network traffic based on predetermined security rules. Firewalls can be implemented as hardware, software, or a combination of both.

They are used to protect networks from unauthorized access, prevent the spread of malware, and enforce security policies. Firewalls can be configured to allow or deny traffic based on a variety of criteria, such as IP address, port number, and protocol.

They are an essential component of any network security strategy and can help protect against a wide range of cyber threats.

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Relationship between two variables.

The experimental research in psychology aims to analyze the relationships between the various variables. There are two variables such s independent and the dependent variable. The independent in the manipulated variable. Depended is measurable.

Thus the two variables are independent and dependent.

Thus the two variables can be recorded by the psychologist.

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When engineers face ethical problems or dilemmas, there are several resources they can use to help them navigate these situations: Codes of Ethics,  Ethical Training and Education,  Ethical Committees, etc.

Personal ethics refers to an individual's own moral principles and values that guide their behavior and decision-making in their personal life. It involves considering what is right or wrong based on one's own beliefs, values, and experiences. Personal ethics are subjective and can vary from person to person.

Professional ethics, on the other hand, refers to the ethical standards and principles that govern the behavior of professionals within their specific field or industry. For engineers, professional ethics encompass the moral obligations and responsibilities they have towards their clients, employers, colleagues, society, and the environment. Professional ethics provide a framework for engineers to ensure that their actions and decisions align with the values and expectations of their profession.

When engineers face ethical problems or dilemmas, there are several resources they can use to help them navigate these situations:

1. Codes of Ethics: Many professional engineering organizations have established codes of ethics that provide guidelines and standards for ethical conduct in the engineering profession. These codes outline the responsibilities and ethical principles that engineers should uphold.

2. Ethical Guidelines and Policies: Companies and organizations often have their own ethical guidelines and policies in place. These documents help engineers understand the ethical expectations within their specific workplace or industry.

3. Ethical Training and Education: Continuous education and training in ethics can equip engineers with the knowledge and skills to identify and address ethical issues. Professional development programs and workshops may focus on ethical decision-making and provide case studies or scenarios to enhance ethical reasoning.

4. Professional Networks and Support: Engaging with professional networks, such as engineering associations and societies, can provide engineers with opportunities to discuss ethical challenges with peers and seek advice or guidance from experienced professionals.

5. Ethical Committees and Advisors: Some organizations have dedicated ethics committees or advisors who can provide guidance and assistance when engineers encounter ethical problems. These committees may offer confidential consultations and help engineers navigate complex ethical issues.

6. Legal and Regulatory Resources: Laws and regulations play a crucial role in defining ethical boundaries and providing legal frameworks. Engineers can consult legal resources, regulations, and guidelines to ensure compliance with legal and ethical requirements.

7. Ethical Decision-Making Frameworks: Engineers can utilize ethical decision-making frameworks, such as the Ethical Decision-Making Model or the SAD Formula (Scrutinize, Analyze, and Decide), to systematically evaluate ethical dilemmas and arrive at well-considered decisions.

By utilizing these resources, engineers can enhance their understanding of ethics, address ethical challenges effectively, and uphold the highest standards of professional conduct.

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Answer:

can be found in the service manual for the specific vehicle being serviced.

Answer:

The relation between the discharge volume flow rate and the inlet volume flow rate is \(\frac{1}{5}\).

Explanation:

No matter if fluid is compressible or not, mass throughout compressor, a device that works at steady state, must be conserved according to Principle of Mass Conservation:

\(\dot m_{in}-\dot m_{out} = 0\) (Eq. 1)

Where \(\dot m_{in}\) and \(\dot m_{out}\) are mass flows at inlet and outlet, measured in kilograms per second.

After applying Dimensional analysis, we expand the equation above as follows:

\(\rho_{in}\cdot \dot V_{in} - \rho_{out}\cdot \dot V_{out} = 0\) (Eq. 2)

Where:

\(\rho_{in}\), \(\rho_{out}\) - Fluid densities at inlet and outlet, measured in kilograms per cubic meter.

\(\dot V_{in}\), \(\dot V_{out}\) - Volume flow rates at inlet and outlet, measured in cubic meters per second.

After some algebraic handling, we find the following relationship:

\(\rho_{out}\cdot \dot V_{out} = \rho_{in}\cdot \dot V_{in}\)

\(\frac{\dot V_{out}}{V_{in}} = \frac{\rho_{in}}{\rho_{out}}\) (Eq. 3)

If we know that \(\rho_{in} = 1\,\frac{kg}{m^{3}}\) and \(\rho_{out} = 5\,\frac{kg}{m^{3}}\), then the relation between the discharge volume flow rate and the inlet volume flow rate is:

\(\frac{\dot V_{out}}{\dot V_{in}} = \frac{1\,\frac{kg}{m^{2}} }{5\,\frac{kg}{m^{3}} }\)

\(\frac{\dot V_{out}}{\dot V_{in}} = \frac{1}{5}\)

The relation between the discharge volume flow rate and the inlet volume flow rate is \(\frac{1}{5}\).

The equation in the Laplace transform domain is obtained without rearranging terms yet, using 'y' for the Laplace transform of y(t) (not y(s)).

When performing the Laplace transform on a given equation, we represent the unknown function y(t) as 'y' in the Laplace transform domain.

The equation is written without rearranging terms, maintaining the original form of the equation. This approach allows us to analyze and manipulate the equation algebraically using properties and rules of the Laplace transform.

It simplifies the process of solving differential equations and finding solutions in the Laplace domain before inverse transforming back to the time domain.

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The following Unified Endpoint Management (UEM) features can help an IT administrator manage and administer IT assets: software deployment, remote management, user provisioning, and license management.

These features allow administrators to efficiently deploy software, remotely manage devices, provision user accounts, and manage software licenses.

Unified Endpoint Management (UEM) is a solution that enables IT administrators to manage and secure a wide range of devices and endpoints from a single console. Among the given features, software deployment is a key UEM capability that allows administrators to distribute and install applications across multiple devices simultaneously. This feature streamlines the deployment process and ensures that all devices are equipped with the necessary software.

Remote management is another important UEM feature that enables administrators to monitor and control endpoints from a centralized location. It provides administrators with the ability to troubleshoot issues, perform updates, and enforce security policies remotely, saving time and resources.

User provisioning is a UEM feature that simplifies the process of creating and managing user accounts on various devices and platforms. Administrators can provision user profiles, set access permissions, and manage user roles and groups, ensuring efficient user management across the organization.

License management is a crucial UEM feature that allows administrators to track and manage software licenses effectively. It helps ensure compliance with licensing agreements, prevents unauthorized software usage, and optimizes license allocation and utilization.

Operating system deployment, although not mentioned in the summary, is not a UEM feature. It typically falls under the domain of Mobile Device Management (MDM) or PC lifecycle management solutions, which focus on deploying and managing operating systems on devices. UEM solutions may integrate with MDM or PC lifecycle management tools to provide comprehensive endpoint management capabilities.

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Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

Answer:

  40 ft

Explanation:

Assuming no loss of energy in the system of pulleys, the work done is the same whether you move the load directly or through the pulleys.

  W = Fd . . . . . . . . work is the product of force and distance

  F(10 ft) = (0.25F)(d) . . . . . where d is the distance we want to find

  d = 10F/(0.25F) = 40

The rope will need to move 40 feet.

Answer:

Relative density = 0.7 or 70%

Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

Pd min = 1.54 mg/mg³

We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

= 0.649350 - 0.581395 / 0.649350 - 0.552486

= 0.067955/0.096864

= 0.7015

= 0.7

The relative density is Therefore 0.7 or 70% when converted to percentage

Answer:

what are the options available?

✅C) Avoid having to use a net ✅

IamSugarBee

A SELECT command pulls zero or more rows from one or more database tables or views. SELECT is the most often used data manipulation language (DML) command in most applications. See the statement required below.

SELECT VendorName, InvoiceNumber, InvoiceDate,

InvoiceTotal - PaymentTotal - CreditTotal AS Balance

FROM Vendors JOIN Invoices

ON Vendors.VendorID = Invoices.VendorID

WHERE InvoiceTotal - PaymentTotal - CreditTotal > 0

ORDER BY VendorName;

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In the situation that you create a sound data engineering architecture, Azure Data Factory is a good offering. We get support from Azure Data Factory for data integration, transformation, and mobility.

A major change in form or aspect is called a metamorphose. An important event, such as acquiring your driver's license, starting college, or getting married, may cause your life to transform. A transformation is a major, immediate change.

A fundamental change in the nature or value of the sacred as a source of meaning in life, as well as a radical shift in the paths that a people travel to access the sacred, are what is meant by spiritual transformation.

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Note that the force on the disc is 38700 Nand the torque required to maintain the disc in the vertical position is 65550 N m.

Force = mass * acceleration due to gravity

= (volume * density) * acceleration due to gravity

= (πr² * height * density) * acceleration due to gravity

= (π * (3/2 m)² * 4 m * 1000 kg/m³) * 9.8 m/s²

Force = 38700 N

Torque = force * distance

= 38700 N * (3/2 m)

Torque = 65550 N m

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The thermal efficiency of the diesel cycle is 0.551 (approx) as a decimal to three decimal places.

We have given:

Compression ratio = r = 10

Cut off ratio = ρ = 3

Air-standard and constant specific heats = 450 K

Thermal efficiency of the diesel cycle is given by: ηth= 1 - 1/r^γ-1(ρ^(γ-1) - 1/ r^γ-1)

Here, γ is the ratio of specific heats, which is evaluated at 450 K.

The value of γ for air at 450 K can be calculated using the following formula,γ= cp/cv, where, cp = specific heat at constant pressure

cv = specific heat at constant volume

The specific heats of air at constant pressure and constant volume can be taken as, cp = 1005 J/kg.

Kcv = 717 J/kg.K

So,γ = 1005/717 = 1.4

Using the values of r, ρ, and γ in the above formula,ηth= 1 - 1/r^γ-1(ρ^(γ-1) - 1/ r^γ-1)

ηth= 1 - 1/10^(1.4-1)(3^(1.4-1) - 1/10^(1.4-1))

On calculation,ηth= 0.551 (approx)Hence, the thermal efficiency of the diesel cycle is 0.551 (approx) as a decimal to three decimal places.

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Answer:

2.25V

Explanation:

In the above question, we are given an npn transistor.

It's VB = Biased voltage = 2.95V

We are asked to calculate the DC emitter voltage.

DC emitter voltage = VB - VBE

Where:

VBE = Voltage between the base and emitter of a bipolar junction transistor

VBE has a set standard voltage of 0.7V

Hence,

DC emitter voltage = 2.95V - 0.7V

= 2.25V

In this exercise we have to use the knowledge of voltage to calculate the difference, like this:

\(2.25V\)

Knowing that the initial voltage is given by 2.95V and we want to find the voltage difference we have:

\(DC = VB - VBE\)

Where, VBE = Voltage between the base and emitter of a bipolar junction transistor is equal to 0.7 V, this way:

\(DC = 2.95V - 0.7V = 2.25V\)

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Answer:

Find explanation below.

Explanation:

Seed drills make it possible for seeds to be planted at equal spacing or distances.

Seed drills are important because they allow seeds to be planted at specific depths and distances. This allows for increased crop yield. They also help to curb the growth of weeds.

The correct SI Form of the following combinations of Units are given as follows:

A) kN/μs = GN/s

B) Mg/mN; = Gg/N

C) MN/(kg.ms)  = GN/(kg.s)

The International System of Units, abbreviated SI in all languages and often pleonastically as the SI system, is the current version of the metric system and the world's most extensively used measuring system.

The System of Units, often known as the metric system, is frequently shortened as SI, which originates from the original French word, Système international d'unités.

A) kN/μs  = (10) ³N/ (10) ⁻6s

= (10)⁹ N/s

= GN/s

B) Mg/mN = (10⁶)g/10⁻³/N

= Gg/N

C) MN/ (kg.ms) = 10⁶N/kg * (10⁻³)s

= 10⁹ (N/kg · s)

= GN/Kg · S)

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Full Question:

Represent Each Of The Following Combinations Of Units In The Correct Si Form Using An Appropriate Prefix:

A) kN/μs

B) Mg/mN; and

MN/(kg.ms)

Answer:

rain

Explanation:

evaoration causes clouds

clouds condense and rain

Answer:

rain

Explanation:

Answer:

The chip will operate below a maximum allowable temperature of 85°C

Explanation:

Given data:

8-mm-thick aluminum

0.02 mm-thick epoxy joint

chip and substrate = 10 mm on a side

temperature = 25°C

attached below is a detailed solution

Tc = 75.3 ° c   which is less than 85°c . hence the chip will operate below a maximum allowable temperature of 85°C

Moral creativity and innovation are based on original discoveries,  whereas immoral innovation is based on unscrupulous actions.

Innovation refers to the practices aimed at developing new products and services for the well-being of society.

Moral innovation is an expression generally used to describe technological advancements based on intellectual property rights.

In conclusion, moral creativity and innovation are based on original discoveries,  whereas immoral innovation is based on unscrupulous actions.

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Answer:

d= 2.80inch

Explanation:

Given:

Axial force= 30kip

d= 1inch

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

A) The average normal stress in the concrete and in each bar are; σ_st = 15.52 kpi ; σ_con = 2.25 kpi

B) The required diameter of each bar so that 60% of the axial force is carried by concrete is; 0.94 inches

We are told that;

Column has eight A992 steel reinforcing bars.

Column is subjected to an axial force of 200 kip.

A) Diameter of each bar is 1 inch.

Using equations of equilibrium, we have;

∑fy = 0;

8P_st + P_con = 200      ------(eq 1)

Using compatibility concept, we know from the image attached that;

δ_st = δ_con

where δ_st is change in length of steel and δ_con is change in length of concrete.

Thus;

δ_st = (P_st * L)/(A_st * E_st)

where;

P_st is tensile force of steel

L is length of steel = 3 ft = 36 inches

A_st is area of steel = π/4 * 1² = 0.7854 in²

E_st is young's modulus of steel = 29000 ksi

Similarly;

δ_con = (P_con * L)/(A_con * E_con)

where;

P_con is tensile force of concrete

L is length of concrete = 3 ft = 36 inches

E_con is young's modulus of concrete = 4200 ksi

A_con is area of concrete with diameter of 8 inches = (π/4 * 8²) - 6(π/4 * 1²) = 45.5531 in²

Thus;

From δ_st = δ_con;

(P_st * 36)/(0.7854 * 29000) = (P_con * 36)/(45.5531 * 4200)

Solving this gives;

P_st = 0.119P_con    -----(eq 2)

Put 0.119P_con for P_st in eq 1 to get;

8(0.119P_con) + P_con = 200  

1.952P_con = 200

P_con = 102.459 kip

Thus; P_st = 12.193 kip

Thus, average normal stress is;

Steel; σ_st = P_st/A_st

σ_st = 12.193/0.7854

σ_st = 15.52 kpi

Concrete; σ_con = P_con/A_con

σ_con = 102.459/45.5531

σ_con = 2.25 kpi

B) Since 60% of the axial force is carried by the concrete. Then it means that 40% will be carried by the steel.

Thus;

P_con = 60% * 200 = 120 kip

P_st = 40% * 200 = 80 kip

Using compatibility again;

δ_st = δ_con

Thus;

(P_st * L)/(A_st * E_st) = (P_con * L)/(A_con * E_con)

6(π/4 * d²)) = (80 * ((π/4 * 8²) - 6(π/4 * d²)) * 4200)/(120 * 29000)

⇒ 4.712d² = 0.09655(50.2655 - 4.712d²)

⇒ 4.712d²/0.09655 = 50.2655 - 4.712d²

⇒ 48.8037d² = 50.2655 - 4.712d²

Solving this gives;

d = 0.94 inches

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