Resonance A mass of one slug is hanging at rest on a spring whose constant is 12 lb/ft. At time = 0 an external force of f(t) =16 cos o t lb is applied to the system. (a)What is the frequency of the forcing function that is in resonance with the system? (b)Find the equation of motion of the mass with resonance.

Answers

Answer 1

a. The frequency of the forcing function that is in resonance with the system is 3.46 rad/s. b. The equation of motion of the mass with resonance is: m[d²x/dt²] + 12x = 16cos(3.46t)

(a) The frequency of the forcing function that is in resonance with the system is the same as the natural frequency of the system, which is:

ω = \(\sqrt{k}\) / m

where m is the mass of the object (in slugs) and k is the spring constant (in pounds per foot).

ω = 3.46 rad/s

Therefore, the frequency of the forcing function that is in resonance with the system is 3.46 rad/s.

(b)The equation of motion of the mass is given by the differential equation:

m[d²x/dt²] + kx = f(t)

where x is the displacement of the mass, m is the mass of the object, k is the spring constant, and f(t) is the external force applied to the system.

We substitute the values given in the problem:

m[d²x/dt²] + 12x = 16cos(ωt)

To find the equation of motion of the mass with resonance, we assume that the forcing function is in resonance with the system.

This means that the frequency of the forcing function is the same as the natural frequency of the system.

ω = \(\sqrt{k}\)/m = 3.46 rad/s

Substituting this value in the equation of motion, we get:

m[d²x/dt²] + 12x = 16cos(3.46t)

We can solve this differential equation to get the equation of motion of the mass with resonance.

However, since the question only asks for the equation of motion, we can stop here. The equation of motion of the mass with resonance is:

m[d²x/dt²] + 12x = 16cos(3.46t)

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Related Questions

True or false. A high gear ratio = more speed = more force.

Answers

Answer:

False

Explanation:

I took the test  and true was incorrect so the answer is false

hope this helps

Answer:

False

Explanation:

False. A high gear ratio = less speed = more force

Comment on the speed changes as it follows its parabolic arc. do they make sense physically?

Answers

(a) Duration of the ball's flight is 2.5S

(b) Angle of its velocity is 16.1

(c) Speed of the ball is 22.53 m/s

(a). To determine the duration of the ball's flight in

We calculate the whole time when the ball touches the ground, thus we enter y=0 and all other specified values in the equation.

\(25sin30t-1/210t^{2} = 0\)

\(t = 2.5 s\)

(b) After it has been in the air for one-fourth of this period, determine the angle of its velocity with respect to the ground.

t1=1/4 t = 2.5/4 = 0.625 s

\(v_{x} = 25\sqrt{3} /2 m/s\)

\(v_{y} = 25/2 - 2.5/2 = 12.5/2 m/s\)

∅= 16.1

(c) To determine speed of the ball for time \(t_{1} ,t_{2} , t_{3}\)

\(v=\sqrt{v} ^{2}{x} + \sqrt{v} ^{2} y_{}\)

vt1 = 22.53 m/s

vt2 = 21.65 m/s

vt3 = 22.53 m/s

What is the speed change on its parabolic arc?  

The turning point on the corresponding parabolic curve is where the speed is at its lowest in the xx direction. Physically speaking, the shift in speed does make sense. The ball's initial motion against gravity causes its speed to decrease, but after it reaches the turning point, its speed begins to increase as it descends.

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A bat with a mass of 0.35 kg travels at a rate of 15 m/s. What is the animal's momentum?

Answers

Answer:

momentum= mass x velocity = 0.35x15= 5.25kgm/s

Please help

Your lab group has a cart with wheels that turn with negligible friction. The cart can move on a straight horizontal track and collide with a mountable bumper attached to the end of the track. Your group is given the task to experimentally determine the relationship between the impulse applied to the cart by the bumper and the cart's change in velocity during the collision with the bumper. Before the collision, the cart moves to the right toward the bumper, as shown above. After the collision, the cart moves to the left.

A) In the table below, list the quantities that would be measured in your experiment. Define a symbol to represent each quantity and list the equipment that would be used to measure each quantity. Assume equipment usually found in a high school physics laboratory is available. You do not need to fill in every row. If you need additional rows, you may add them to the space just below the table.
Quantity to| symbol | equipment
Be |for /for
Measured. |quantity |measume


B) Describe the overall procedure to be followed to collect data that could be used to find the relationship between impulse and change in velocity. Provide enough detail so that another student could replicate the experiment. As needed, use the symbols defined in the table. If needed, you may include a simple diagram of the setup with your procedure.

C) Explain how you can determine the impulse applied to the cart by the bumper and the cart’s change in velocity using the quantities you indicated in the table in part (a

D) Students collected data shown below using a system similar to the one shown in the diagram above.  Use the empty boxes in the data table, as appropriate, to record any calculated values you will need for analysis. Label each column and include appropriate units. You do not need to fill in every column. If you need additional columns, you may add them to the space next to the table.

E) Indicate below which quantities should be graphed to determine the relationship between the magnitudes of the impulse and the change in velocity.
Vertical axis:        ____________
Horizontal axis:   ____________
 
F) Using graph paper or graphing tool, plot the data for the quantities indicated in part

(e). Clearly scale and label all axes including units. Draw a best-fit line that represents the relationship between the variables.
(if you can tell me equation ill just graph it)

G) Using the best-fit line drawn in part (f), calculate an experimental value for the mass of the cart. Explicitly indicate the principles used in your calculation.

Please help Your lab group has a cart with wheels that turn with negligible friction. The cart can move

Answers

The quantities that would be measured in your experiment will be:

Quantity to be Measured Symbol Equipment to Measure

Mass of Cart                    m Electronic Balance

Initial Velocity of Cart    v_i Motion Detector

Final Velocity of Cart     v_f Motion Detector

Time of Collision           Δt Photogates/Timer

Impulse Applied by Bumper J Force Sensor/Photogates and Mass

How to explain the experiment

The overall procedure to be followed to collect data that could be used to find the relationship between impulse and change in velocity.

Set up the experiment by placing the cart at the beginning of the track and attaching the bumper to the end of the track.Measure and record the mass of the cart using an electronic balance.Set up a motion detector to measure the initial velocity of the cart and record it as v_i.Start the cart moving and allow it to collide with the bumper. Record the time of the collision using photogates or a timer as Δt.Use the motion detector to measure the final velocity of the cart as it moves in the opposite direction and record it as v_f.Repeat steps 3-5 several times to obtain multiple data points for velocity and time of collision.To determine the impulse applied by the bumper, use a force sensor or photogates and mass to measure the force and time of collision during each trial. Multiply the force by the time of collision to obtain the impulse for each trial.Repeat steps 3-7 for different initial velocities of the cart to obtain additional data points.

The impulse applied to the cart by the bumper can be determined using the formula:

J = Δp = m(vf - vi)

where m is the mass of the cart, vf is the final velocity of the cart, and vi is the initial velocity of the cart.

The change in velocity of the cart can be determined using the formula:

Δv = vf - vi

where vf is the final velocity of the cart and vi is the initial velocity of the cart.

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what is the process of a blue giant star?
they didn't have astronomy on here so I just choose something related to the sorts.

Answers

The process of the blue giant start includes stellar Formation, main Sequence Phase, expansion and Cooling, helium Fusion, variable Behavior, and supernova.

What is the process of a blue giant star?

The stage in the formation of a star just before nuclear reactions ignite. After a massive red giant star ejects its outer layers, its hot inner core is exposed, and it becomes a blue giant star.

During the process of a blue giant star,  once a star consumes all its hydrogen, the core superheats and pushes its surface layers far out into space.

The process of the blue giant start includes;

Stellar FormationMain Sequence PhaseExpansion and CoolingHelium FusionVariable BehaviorSupernova or Stellar Evolution

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Question 4 of 10
When you go along with a group because you don't want to cause trouble, it is
called:
A. informational social influence.
B. normative social influence.
C. attribution
.
D. fundamental social influence.

Answers

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

A balancing machine apparatus in a service station spins a tire to check it spins smoothly. The tire starts from rest and turns through 4.73 revin 1.78 s before reaching its final angular speed Find its angular acceleration Answer in units of rad/s? Answer in units of rad/s2 1. 40.104726 2. 331914518 3. 31.14749 4. 196.894956 5. 18.759921 6. 32 366038 7. 309.070405 8.35 882879 9. 84381621 10. 17.866388

Answers

The correct option is option 3.

To find the angular acceleration of the tire, we can use the formula:

angular acceleration (α) = (final angular speed - initial angular speed) / time

Given:

Number of revolutions (n) = 4.73 rev

Time (t) = 1.78 s

First, let's convert the number of revolutions to radians:

Angle (θ) = n * 2π

Substituting the values:

θ = (4.73 rev) * (2π rad/rev)

Now, we can calculate the initial angular speed (ω_initial) using the formula:

ω_initial = 0 rad/s (as the tire starts from rest)

Next, let's calculate the final angular speed (ω_final) using the formula:

ω_final = θ / t

Now, we can calculate the angular acceleration (α) using the formula:

α = (ω_final - ω_initial) / t

Substituting the values:

α = (ω_final - 0 rad/s) / t

Now, let's calculate the angular acceleration:

α = ω_final / t

Substituting the values:

α = (θ / t) / t

Calculating the result:

α ≈ 31.14749 rad/s²

Therefore, the angular acceleration of the tire is approximately 31.14749 rad/s².

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if you walk at 1 km/h down the aisle toward the front of a train that moves at 60 km/h, what is your speed relative to the ground?

Answers

If you walk at 1 km/h down the aisle towards the front of a train that moves at 60 km/h, your speed relative to the ground would be 61 km/h.

This is because we add the velocity of the person to the velocity of the train to determine their combined velocity relative to the ground. If the person were to walk in the opposite direction of the train, their speed relative to the ground would be 59 km/h since we would subtract their velocity from that of the train. The same concept applies to any situation where two objects are moving relative to each other.

For example, let's say that two cars are driving in the same direction on a highway. Car A is driving at 70 km/h and Car B is driving at 90 km/h.

The relative velocity of Car A with respect to Car B would be 20 km/h (90 km/h - 70 km/h) while the relative velocity of Car B with respect to Car A would be -20 km/h (70 km/h - 90 km/h).

So therefore if you walk at 1 km/h down the aisle towards the front of a train that moves at 60 km/h, your speed relative to the ground would be 61 km/h.

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look at it 500 points for all of it 200+ if you get it right

Answers

Work is said to be done when force applied moves a distance in the direction of the force.

The questions here relate to motion and i will try to answer each one.

1) The graph as shown represents a constant negative acceleration.

2) Given that even at constant velocity, an acceleration occurs in circular motion because the direction of motion changes hence as the carousel moves, there is acceleration; change in velocity.

3) From the diagram shown, we can see that a simple machine makes a task easier.

4) The average speed for each lap decreases. This is an example of a(n) inverse relationship.

5) When a stack of books is carried at waist level across a room, work is not being done.

6) The reason why the tortoise won is that, the tortoise moved at a constant velocity throughout the race; the hare stopped to rest periodically.

7) Work is only said to be done when the force applied moves a distance hence, work is not done because, the object has not moved.

8) The truth about the movement of the car is that the car travels at constant velocity.

9) The mechanical advantage is defined as the ratio of load to effort. Hence the mechanical advantage = 600 Ibs/150 Ibs = 4

10) The lowest gear has the greatest mechanical advantage because it requires the least work to climb the hill.

11) A pulley helps you do work because it decreases the amount of applied force.

12) The pedals on a bicycle give a mechanical advantage by allowing you to turn the pedals a short distance to turn the larger circumference of the wheels.

13) The car is traveling with a constant velocity due to the flat line of the graph.

14) The statement Mary traveled 70 miles/hour due north is velocity.

15) speed = distance/time

time = distance/speed

time = 9 m/ 2m/s = 4.5 s

16) The force needed to push the mass to the top of the ramp can be decreased by decreasing the length of the ramp.

17) The acceleration of the car is negative when the velocity of a car reduced from 50 km/h to 35 km/h over one minute.

18) Average velocity = Distance covered in a specific direction/ time

= 25 Km due east/4 hours = 6.25 km/hr due east

19) Work done = Force × distance

Distance = Work done/Force

Distance = 96 J/16 N = 6 meters

20) The most work is done when Jeremy pushed a car up a steep hill.

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An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms-2 in the downward direction. Calculate ----- Its speed just before it hits the ground. What is its average velocity during 0.5 s? Calculate the height of the branch of the tree from the ground?

Answers

Given that,

Time = 0.5 s

Acceleration = 10 m/s²

(I). We need to calculate the speed of apple

Using equation of motion

\(v=u+at\)

Where, v = speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

\(v=0+10\times0.5\)

\(v=5\ m/s\)

(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

\(s=ut+\dfrac{1}{2}gt^2\)

Put the value into the formula

\(s=0+\dfrac{1}{2}\times10\times(0.5)^2\)

\(s=1.25\ m\)

(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

\(v_{avg}=\dfrac{\Delta x}{\Delta t}\)

\(v_{avg}=\dfrac{x_{f}-x_{i}}{t_{f}-t_{0}}\)

Where, \(x_{f}\)= final position

\(x_{i}\) = initial position

Put the value into the formula

\(v_{avg}=\dfrac{1.25+0}{0.5}\)

\(v_{avg}=2.5\ m/s\)

Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

(III). The height of the branch of the tree from the ground is 1.25 m.

During a classroom lab activity, students built each of the circuits shown below and measured the current and resistance in each circuit. Each circuit contains a 1. 5-volt battery and each bulb has a resistance of 50 Ω.
When the switch is closed, in which circuit would resistance be the highest and current be lowest?

Answers

Circuit 2 would have the highest resistance and lowest current when the switch is closed.

This is because Circuit 2 has two bulbs in series, meaning that the current must pass through both bulbs to complete the circuit. This increases the overall resistance of the circuit, resulting in a lower current.

Note: This assumes that the other conditions, such as the size and quality of the bulbs and the battery, are the same in all of the circuits. If these conditions change, the resistance and current in the circuits may also change.

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why is an iceberg more dense than a ship?

Answers

Answer:

icebergs float on water because ice is less dense than water. The same is true for a boat: a boat floats on water because, overall, it is less dense than the water.

Explanation:

I need help on this question

I need help on this question

Answers

Answer:

at rest because time is passing and speed is still at 0

Explanation:

The measure the activity of a rock thought to be radioactive, a physicist puts the rock beside a detector and counts 225 particles in 10 minutes. To check for background, she removes the rock and then records 90 particles in 6 minutes. She converts both these answers into rates, in particles per hour, and takes their difference to give the activity of the rock alone. What is the final answer, in particles per hour, and what is its uncertainty

Answers

The activity of the rock alone is 12,600 ± 963 particles/hour.

To find the activity of the rock alone, we need to subtract the background count from the total count. Let's first convert both counts to rates in particles per hour:

Total count rate = (225 particles / 10 minutes) * (60 minutes / 1 hour) = 13,500 particles/hourBackground count rate = (90 particles / 6 minutes) * (60 minutes / 1 hour) = 900 particles/hour

Activity of rock alone = Total count rate - Background count rate = 13,500 particles/hour - 900 particles/hour = 12,600 particles/hour

To find the uncertainty in the activity, we can use the formula for the propagation of uncertainty:

δQ = sqrt((δA)^2 + (δB)^2)

where δQ is the uncertainty in the final quantity (activity), δA is the uncertainty in the first quantity (total count rate), and δB is the uncertainty in the second quantity (background count rate).

The uncertainties in the count rates are proportional to the square root of the number of counts, so we have:

δA = sqrt(225) * (13,500 particles/hour / 225) = 900 particles/hourδB = sqrt(90) * (900 particles/hour / 90) = 300 particles/hour

Substituting these values into the formula for δQ, we get:

δQ = sqrt((900 particles/hour)^2 + (300 particles/hour)^2) = 963 particles/hour.

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pweese help one more timeeee

pweese look at the image below

pweese help one more timeeeepweese look at the image below

Answers

Answer:

increasing; speeding up is my answer

That answer is B increasing

A V = 82-V source is connected in series with an R = 1.9-kΩ resistor and an L = 34-H inductor and the current is allowed to reach maximum. At time t = 0 a switch is thrown that disconnects the voltage source, but leaves the resistor and the inductor connected in their own circuit. After the current decreases to 51 % of its maximum value, the battery is reconnected into the circuit by reversing the switch.
Part (a) At what value of the time t, in milliseconds, does the current reach 78 % of its maximum?
Part (b) How much energy, in millijoules, is supplied in total by the battery, both in initially bringing the current to maximum and in bringing the current back to the 78 % level from 51 %? Ignore energy dissipated in the resistor during those processes.

Answers

By following these calculations, we can determine the value of time when the current reaches 78% of its maximum and the total energy supplied by the battery.

To solve this problem, we need to consider the behavior of an RL circuit and the relationships between current, time, and energy.

Given:

Voltage of the source (V) = 82 V

Resistance (R) = 1.9 kΩ = 1900 Ω

Inductance (L) = 34 H

Current at maximum (I_max) = maximum value of current

Current at 51% of maximum (I_51) = 0.51 * I_max

Current at 78% of maximum (I_78) = 0.78 * I_max

Part (a) To find the value of time (t) when the current reaches 78% of its maximum (I_78), we can use the formula for the current in an RL circuit:

I(t) = I_max * (1 - e^(-t / τ))

Where:

I(t) is the current at time t,

I_max is the maximum current,

e is the base of the natural logarithm,

t is the time,

τ = L / R is the time constant of the RL circuit.

We can rearrange the formula to solve for time:

t = -τ * ln(1 - (I(t) / I_max))

Substituting the values:

t = - (L / R) * ln(1 - (I_78 / I_max))

Now we can calculate the time t.

Part (b) To find the energy supplied by the battery, we need to consider the total energy consumed in bringing the current to its maximum and in bringing it back to the 78% level from the 51% level.

The energy stored in an inductor is given by the formula:

E = (1/2) * L * I^2

The energy supplied by the battery is equal to the total energy consumed in the circuit. Therefore, we can calculate the energy supplied by the battery by finding the difference between the energy at maximum current and the energy at the 78% level:

E_total = (1/2) * L * (I_max^2 - I_78^2)

To convert the energy to millijoules, we need to multiply the result by 1000.

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If c1=c2=4. 00μf and c4=8. 00μf, what must the capacitance c3 be if the network is to store 2. 70×10−3 j of electrical energy?

Answers

To store 2.70x10^-3 J of electrical energy, capacitance c3 in the network must be 2.67μF. This can be calculated using the formula for energy stored in a capacitor network.

A network of capacitors is a collection of capacitors wired into a circuit. The capacitors store electrical energy as an electric field between their plates when a voltage is applied across the network. The formula E = 1/2 * C * V2 may be used to determine the total energy held in a capacitor network, where E is the energy held, C is the network's total capacitance, and V is the applied voltage. The capacitances of c1, c2, and c4 in this instance are specified as 4.00 F, 4.00 F, and 8.00 F, respectively. It is possible to determine that the capacitance c3 has to be 2.67 F to store 2.70 x 10-3 J of electrical energy by rearranging the formula and inserting the numbers.

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The fastest crossing of the Atlantic Ocean by an ocean
linger was made in July of 1952. The ship, the S.S. United States, traveled 4727 km east by northeast in 3 days, 15 hours, and 20 minutes. Assume that the ship had traveled the same speed, but directly east. What would the velocity of the S.S United States be in km/h?

Answers

That’s insane!!23456

real electronic signal data from a particle accelerator subsystems for machine learning anomaly detection

Answers

Using real electronic signal data from particle accelerator subsystems for machine-learning anomaly detection can help improve the safety and efficiency of the accelerator system.

Real electronic signal data from particle accelerator subsystems can be used for machine-learning anomaly detection. This involves using machine learning algorithms to analyze the signals and identify any abnormal patterns or behaviors.

To accomplish this, the following steps can be followed:

1. Data Collection: Gather real electronic signal data from the particle accelerator subsystems. This data should include a variety of normal and abnormal signals to train the machine-learning model effectively.

2. Data Preprocessing: Clean and prepare the data for analysis. This may involve removing noise, normalizing the signals, and dividing the data into training and testing sets.

3. Feature Extraction: Extract relevant features from the signal data. This can involve techniques such as Fourier transforms, wavelet transforms, or statistical measures to capture important characteristics of the signals.

4. Model Training: Train a machine learning model using the labeled data. This can include techniques such as supervised learning, unsupervised learning, or a combination of both.

5. Anomaly Detection: Apply the trained model to new, unseen data and identify any anomalous patterns or behaviors. The model should be able to distinguish between normal and abnormal signals based on the patterns it learned during training.

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Complete Question: Where can I find real electronic signal data from particle accelerator subsystems that can be used for machine learning anomaly detection?

An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

Answers

When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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If no other forms of energy besides kinetic and gravitational potential energy are present, then mechanical energy is represented by the equation __________.
A) PEg = E + KE
B) ME = 1/2 (KE)(PEg)2
C) PEg = mgh
D) E = KE + PEg

Answers

If no other forms of energy besides kinetic and gravitational potential energy are present, then mechanical energy is represented by the equation  E = KE + PEg. So option D is correct.

Mechanical energy refers to the sum of potential energy (stored energy by virtue of position) and kinetic energy (the energy of motion). In other words, it is the energy that is due to the position and motion of an object.Mechanical energy, E, is equal to the sum of the kinetic energy, KE, and potential energy, PEg. Thus, it is given by the equation:E = KE + PEg  .Therefore, if no other forms of energy apart from kinetic and gravitational potential energy are present, the mechanical energy of a system is equal to the sum of its kinetic energy and gravitational potential energy, as shown in the equation above.Option D is the correct equation for mechanical energy.

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016 (part 1 of 2) 10.0 points
A neutron in a reactor makes an elastic headon collision with the nucleus of an atom initially at rest.
Assume: The mass of the atomic nucleus is
about 11.1 the mass of the neutron.
What fraction of the neutron’s kinetic energy is transferred to the atomic nucleus?
017 (part 2 of 2) 10.0 points
If the initial kinetic energy of the neutron is
4.2 × 10−13 J, find its final kinetic energy.
Answer in units of J.
No Rounding

Answers

(a) The fraction of neutron's kinetic energy transferred to the atomic nucleus is 0.09.

(b) The final kinetic energy of the neutron is 3.82 x 10⁻¹³ J.

What is the final velocity of the atom?

The final velocity of the atom is calculated by applying the principle of conservation of linear momentum as follows;

initial momentum of the neutron = final momentum of the atom

m₁u₁  = m₂u₂

where;

m₁ is the mass of the neutronu₁ is the initial velocity of the neutronm₂ is the mass of the atomic nucleus u₂ is the final velocity of the atomic nucleus

The mass of the atomic nucleus = 11.1 m₁

u₂  = m₁u₁ / m₂

u₂  = m₁u₁ / (11.1 m₁)

u₂  = 0.09u₁

The initial kinetic energy of the neutron is calculated as;

K.Ei = ¹/₂m₁u₁²

The final kinetic energy of the atomic nucleus is calculated as;

K.Ef =  ¹/₂m₂u₂²

K.Ef =  ¹/₂(11.1 m₁)(0.09u₁)²

K.Ef = 0.09 (¹/₂m₁u₁²)

K.Ef = 0.09 (K.Ei)

The fraction of neutron's kinetic energy transferred to the atomic nucleus is calculated as;

= 0.09 (K.Ei) / K.Ei

= 0.09

= 9 %

The final kinetic energy of the neutron is calculated as follows;

K.E.f (neutron) = (1 - 0.09) x (4.2 x 10⁻¹³ J)

K.E.f (neutron) = 3.82 x 10⁻¹³ J

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(01. 03 MC)
An object i moving 10 m/ to the outh. After one minute, it moving at a rate of 15 m/. Explain what type of motion thi i decribing. Then explain
whether thi repreent a calar or vector quantity

Answers

The motion being described is linear motion, and since it has direction, it is a vector quantity.

What type of motion is linear?

A linear motion is a style of motion in which the object's movement is inversely proportional to its speed and duration of motion.

This type of motion also happens in a straight line.

The following is the formula for final velocity in a linear type of motion:

v = u + at

where;

V is the object's final speed or moving rate.

u is an object's initial speed, and a represents its acceleration.

t is the object's motion in time.

Our equation is formed by the supplied statement as follows:

v = u + at

15 m/s = 10 m/s + 60a

Thus, the final velocity formula, which is a vector quantity, is shown by the equation above.

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In a calorimetry experiment, it was determined that the heat change of the surroundings (qsurroundings) was 4482 j. what is the heat change of the system (qsystem)?

Answers

The heat of the surroundings is  - 4482 J.

What is the heat change of the system (qsystem)?

A calorimeter is a device in which that is no exchange of heat between the device and the environment. In other words, there could only be exchange of heat when the a substance has been put inside the calorimeter.

We know that in a calorimeter;

Heat of the surrounding =  Heat of the system

That implies that they are of the same magnitude but of opposite direction hence the heat of the system is - 4482 J.

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As the name states, the cars of a roller coaster really do coast along the tracks. A motor pulls the cars up a high hill at the beginning of the ride. After the hill, however, the motion of the car is a result of gravity and inertia. As the cars roll down the hill, they must pick up the speed that they need to whiz through the rest of the curves, loops, twists, and bumps in the track. To learn more about designing roller coasters, read the interview with Steve Okamoto.
How did you become a roller coaster designer?
I have been fascinated with roller coasters ever since my first ride on one. I remember going to Disneyland as a kid. My mother was always upset with me because I kept looking over the sides of the rides, trying to figure out how they worked. My interest in finding out how things worked led me to study mechanical engineering. What sort of training do you have I earned a degree in product design. For this degree, I studied mechanical engineering and studio art. Product designers consider an object's form as well as its function.They also take into account the interests and abilities of the
product's consumer. Most rides and parks have some kind of theme, so I must consider marketing goals and concerns in my designs.
What is the nature of your work?
To design a roller coaster, I study site maps of the location. Then, I go to the amusement park to look at the actual site.Because most rides I design are for older parks (few parks are built from scratch), fitting a coaster around, above, and in
between existing rides and buildings is one of my biggest challenges. I also have to design how the parts of the ride will work together. The towers and structures that support the ride have to be strong enough to hold up a track and speeding cars that are full of people. The cars themselves need special wheels to keep them locked onto the track andseat belts or bars to keep the passengers safely inside. It's
like putting together a puzzle, except the pieces haven't
been cut out yet.
What advice do you have for a student who is interested in designing
roller coasters?
Studying math and science is very important. To design a successtulcoaster, I have to understand how energy is converted from one form to another as the cars move along the track. I have to calculate speeds and accelerations of the cars on each part of the
track. They have to go fast enough to make it up the next hill! I rely on my knowledge of geometry and physics to create the roller coaster's curves.loops, and dips. Sammrazie in two paragraphs

Answers

The summary of the interview with Steve Okamoto a roller coaster designer highlighted how he developed a fascination for rollercoasters and how he successfully learned how to build them.

What is the summary of the interview with Steve Okamoto?

The summary of the interview with Steve Okamoto is given below.

In an interview with Steve Okamoto, a roller coaster designer, he explained that his fascination with roller coasters began at a young age, and his interest in finding out how they worked led him to study mechanical engineering and product design. As a roller coaster designer, Okamoto's work involves studying site maps, designing how the parts of the ride will work together, and fitting coasters around existing rides and buildings. He also has to consider marketing goals and concerns in his designs, as most parks have some kind of theme. Okamoto recommends that students interested in designing roller coasters should focus on studying math and science, and understanding how energy is converted from one form to another as the cars move along the track.

Overall, Okamoto's work as a roller coaster designer involves a combination of mechanical engineering, product design, and consideration for marketing goals and existing park infrastructure. To design a successful roller coaster, he relies on his knowledge of math, science, geometry, and physics to calculate speeds, accelerations, and the coaster's curves, loops, and dips. His advice for students interested in designing roller coasters is to focus on studying math and science, and understanding how energy is converted throughout the coaster's track.

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A tall tree has more chance to break during the storm, why?​

Answers

because the top part become weaker

Explanation:

Unfortunately, all trees have some potential to fail during heavy winds or other harsh elements, such as snow and ice. ... In these incidences, the tree trunk acts as a lever and the force applied to the roots and trunk increases with height and mass. Taller trees are more susceptible to windthrow.

"Windthrow" is a phenomenon that uproots a tree because the trunk acts as a lever applying force to the roots. ... Trees are more likely to uproot during strong winds especially if the tree is top-heavy which can also result in tearing, splitting and limb breakage

3. Label the parts of each wave.
Please help me!!!

3. Label the parts of each wave.Please help me!!!

Answers

Answer:

D is the wavelength

A is the crest

C is amplitude

B is trough

G is wavelength

H is compression

I is rarefaction

what is 2 plus 2 and 1 plus 1​

Answers

Answer: 6

Explanation:

Have an awesome amazing day

Answer:

2 plus 2 = 4 AND 1 plus 1 = 2

Explanation:

I guess combine both equations if your detailed instructions allow.

please help me out with this. ​

please help me out with this.

Answers

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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what heat transfer mechanisms (conduction, convection, or radiation) are involved when heat flows through a glass windowpane? explain.

Answers

When heat flows through a glass windowpane, the primary heat transfer mechanisms involved are conduction and radiation.

Conduction occurs as heat moves through the solid glass material, with molecules transferring energy to their neighbors. Radiation is the emission of infrared energy from the warm side of the glass to the cooler side, transferring heat in the form of electromagnetic waves without the need for direct contact or a medium. Convection is less significant in this context since it involves the transfer of heat through fluid motion, which doesn't occur within the solid glass windowpane.

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