Sienna plays a game of chess and a game of pool.
Work out the probability that she does not win either of the two games.
Give your answer as a fraction in its simplest form.
Chess
10
32
10
FE
Win
Lose
Draw
1/3
|w/ w/~/
2
1
3
/2/3 1/3)
23
Pool
Win
Lose
Win
Lose
Win
Lose

Answer:

From home it looks like it took her 2  hours and 30 minutes

Step-by-step explanation:

If you look when she started, 10 A.M, and look when she first arrived at the campground, 12:30 P.M, you can see it took her 2 and a half hours.

a) , 36 : '22 in its simplest form is 18 : 11., d) the mean is 301.25.

a) To express 36 : '22 in its simplest form, we need to find the greatest common divisor (GCD) of 36 and 22. The GCD of 36 and 22 is 2. Divide both numbers by the GCD to simplify the fraction. 36 ÷ 2 = 18 and 22 ÷ 2 = 11. So, 36 : '22 in its simplest form is 18 : 11.

b) To express the fractions x 3 2 and I in equivalent fractions with a denominator of 20, we need to multiply the numerator and denominator by the same number. For x 3 2, multiply both the numerator and denominator by 10. This gives us x 3 2 = 10 x 3 2 ÷ 2 10 ÷ 2 = 15 1. For I, multiply both the numerator and denominator by 20. This gives us I = 1 x 20 2 x 20 = 20 40.

c) To evaluate Workout;+;—§, substitute the values into the expression: 2 + 5 - 4 ÷ 2. Start by performing the division: 4 ÷ 2 = 2. Then, perform the addition: 2 + 5 = 7. Finally, perform the subtraction: 7 - 2 = 5.

d) To find the mean of the dataset: 301, 285, 21, 351, 35, 2135, 311, 25, 45, 310, 301, 305, add up all the numbers and divide by the total number of values. Adding all the numbers together gives us 3615. Since there are 12 numbers in the dataset, the mean is 3615 ÷ 12 = 301.25. Rounded to two decimal places, the mean is 301.25.

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34% of the data in a normal distribution is more than 1 standard deviation above the mean.

In a normal distribution, about 68% of the data falls within one standard deviation above or below the mean. This means that roughly 34% of the data falls one standard deviation above the mean.

To be more precise, we can use the empirical rule or the 68-95-99.7 rule, which states that:

Approximately 68% of the data falls within one standard deviation of the mean.

Approximately 95% of the data falls within two standard deviations of the mean.

Approximately 99.7% of the data falls within three standard deviations of the mean.

Therefore, if we assume that the normal distribution is perfectly symmetrical, we can estimate that roughly 34% of the data falls more than one standard deviation above the mean.

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The distance from the point to the given plane is 16/7 units.

To find the distance from a point to a given plane, we can use the formula:

distance = |ax + by + cz - d| / √(a^2 + b^2 + c^2)

where (x, y, z) are the coordinates of the point, and a, b, c, and d are the coefficients of the plane equation.

In this case, the point is (1, -3, 4) and the plane equation is 3x + 2y + 6z = 5.

Let's plug in the values:

distance = |(3*1) + (2*(-3)) + (6*4) - 5| / √(3^2 + 2^2 + 6^2)

Simplifying:

distance = |3 - 6 + 24 - 5| / √(9 + 4 + 36)
distance = |16| / √49
distance = 16 / 7

Therefore, the distance from the point (1, -3, 4) to the plane 3x + 2y + 6z = 5 is 16/7 units.

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The sum of the series when evaluated are ∑aₙ² + 1 = 45, ∑bₙ² - 1 = 35, ∑(2aₙ + bₙ) = 0, ∑(aₙ + 3bₙ) = 0, ∑(aₙ/bₙ)² = 2, ∑(aₙ/bₙ)³ = -2, ∑aₙ² + ∑bₙ² = 80 and ∑aₙ² - ∑bₙ² = 0

Series 61

This series represents the summation of aₙ² + 1 from n = 1 to 5

From the graph, we have

a₁ = -4; a₂ = -2; a₃ = 0; a₄ = 2 and a₅ = 4

So, we have

∑aₙ² + 1 = (-4)² + 1 + (-2)² + 1 + (0)² + 1 + (2)² + 1 + (4)² + 1

∑aₙ² + 1 = 45

Series 62

This series represents the summation of bₙ² - 1 from n = 1 to 5

From the graph, we have

b₁ = 4; b₂ = 2; b₃ = 0; b₄ = -2 and b₅ = -4

So, we have

∑bₙ² - 1 = (4)² - 1 + (2)² - 1 + (0)² - 1 + (-2)² - 1 + (-4)² - 1

∑bₙ² - 1 = 35

Using the above formats, the sum of the remaining series is

Series 63

∑(2aₙ + bₙ) = (2 * 4 - 4) + (2 * 2 - 2) + (2 * 0 - 0) + (2 * -2 + 2) + (2 * -4 + 4)

∑(2aₙ + bₙ) = 0

Series 64

∑(aₙ + 3bₙ) = (4 - 3 * 4) + (2 - 3 * 2) + (0 - 3 * 0) + (-2 + 3 * 2) + (-4 + 3 * 4)

∑(aₙ + 3bₙ) = 0

Series 65

∑(aₙ/bₙ)² = (2/-2)² + (4/-4)²

∑(aₙ/bₙ)² = 2

Series 66

∑(aₙ/bₙ)³ = (2/-2)³ + (4/-4)³

∑(aₙ/bₙ)³ = -2

Series 67

∑aₙ² + ∑bₙ² = (-4)² + (4)² + (-2)² + (2)² + (0)² + (0)² + (2)² + (-2)² + (4)² + (-4)²

∑aₙ² + ∑bₙ² = 80

Series 68

∑aₙ² - ∑bₙ² = (-4)² - (4)² + (-2)² - (2)² + (0)² - (0)² + (2)² - (-2)² + (4)² - (-4)²

∑aₙ² - ∑bₙ² = 0

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a) Given the triangle ABC, you have to do a counterclockwise 90º rotation of the figure.

To make said rotation you have to invert the coordinates of each point of the figure and invert the sign of the x-coordinate of the image point.

In general:

Preimage point; Image point

P(x,y) → P'(-y,x)

The y-coordinate turns into the x-coordinate and the x-coordinate turns into the y-coordinate.

The x-coordinate of the image point must have the opposite sing as the original one.

So for triangle ABC:

A to A'

(3,-2) → (-(-2),3)= (2,3)

B to B'

(3,-6) → (-(-6),3)= (6,3)

C to C'

(9,-2) → (-(-2),9)= (2,9)

The coordinates for the 90º counterclockwise rotation are A'(2,3), B'(6,3) and C(2,9)

b) Triange A'B'C' was translated a certain number of units, its new position is given as triangle A''B''C'':

A''(-3,-4)

B''(1,-4)

C''(-3,2)

To determine what kind of translation was done, first step is to draw triangle A''B''C'' and compare it to triangle A'B'C':

As you can see in the graphic, triangle A'B'C' was translated horizontally to the left a k number of units and vertically downwards a m number of units.

Horizontal translation

These translations are made over the x-axis, the translation factor k is added (movement to the rigth) or subtracted (movement to the left) from the x-coordinate of each point:

In this case the translation was made to the left, so:

Preimage point; Image point

P(x,y) → P'(x-k,y)

Vertical translation

These translations are made over the y-axis, this means that the translation factor m will be added (↑up) or subtracted (↓down) from the y-coordinates of each point.

For the example, the movement was downwards so we can express it as:

Preimage point; Image point

P(x,y) → P'(x,y-m)

You can unite both movements in the same expression as:

Preimage point; Image point

P(x,y) → P'(x-k,y-m)

Going a little further you can determine the amount of units the figure was translated by comparing a set of points from the preimage and image:

Given A'(2,3) and A''(-3,-4)

For the horizontal movement compare the x-coordinates. We know that to determine the x-coordinate of A'', k units were subtacted from the x-coordinate of A', so:

2-k=-3

-k=-3-2

-k=-5

k=5

For the vertical movement, compare the y-coordinates of both point. We know that m units were subtracted from the y-coordinate of A' to determine the y-coordinate of A'', so:

3-m=-4

-m=-4-3

-m=-7

m=7

This means that the translation rule for A'B'C' → A''B''C'' is (x-5,y-7)

Jim purchased notebooks. they were dollars each. Therefore, the equation to represent the total cost that Jim paid is:y = x dollars.

The amount or equivalent paid or charged for something : price. The average cost of a college education has gone up dramatically.

the outlay or expenditure (as of effort or sacrifice) made to achieve an object. He achieved fame, but at the cost of losing several friends.

Given that Jim purchased notebooks which were x dollars each, we can write an equation to represent the total cost that Jim paid as follows:

Let the total cost Jim paid be y.

Then, since he purchased x notebooks, the equation that represents the total cost that Jim paid is:

y = x dollars

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-1/7, since parallel lines have equal slopes.

He may be paid less each week if no work is available, option D is correct.

Chris being an hourly employee suggests that he is paid based on the number of hours he works.

He may be paid less each week if no work is available reflects a common practice for hourly employees where their pay may vary depending on the availability of work.

If there is no work available, Chris may receive less pay for that week.

Hence, He may be paid less each week if no work is available, option D is correct.

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Answer:

parallel i think

Step-by-step explanation:

parallel because it's a unknown error

Answer:

Choice B

Step-by-step explanation:

The best way to compare two lines is to solve for y.

The first equation:

For \(20y-24x=-20\) the first thing we should do is add the 24x on both sides which will cancel out itself on the left side \(20y=24x-20\). Now all we have to do is divide the 20 on both sides to leave us with \(y=\frac{6}{5}-1\).

The second equation:

For \(5y-6x=-5\) the first thing we should do is add the 6x on both side which will cancel itself on the left side \(5y=6x-5\). Now all we have to do is divide the 5 on both sides to leave us with \(y=\frac{6}{5}x-1\).

Now for the comparison:

They are the same exact line. If you were to graph them they would overlap each other.

Answer:

no

Step-by-step explanation:

0.06 = \(\frac{6}{100}\) ← that is 6 books out of 100

she requires to have 60 out of 100 , that is

\(\frac{60}{100}\) = 0.6

Answer: 0.75

Step-by-step explanation: took the same question

Answer:

0.75

Step-by-step explanation:

Answer:

y= -25

Step-by-step explanation:

Hope this helps!!

Absolute value equation that has the solutions x=2 and x=9 is |x - 5.5| = 3.5

absolute value equation is |x - 5.5| = 3.5

Generalizations of the absolute cost for actual numbers arise in a huge form of mathematical settings. as an example, an absolute value is likewise defined for the complicated numbers, the quaternions, ordered jewelry, fields and vector spaces. absolutely the price is closely associated with the notions of value, distance, and norm in numerous mathematical and bodily contexts.

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Step-by-step explanation:

Let's call the number of girls in the school "g". We know that there are 1000 boys, so the total number of students is 1000 + g.

The problem states that 48% of the total number of students were successful in the examination. Therefore, we can write an equation:

0.48(1000 + g) = 0.5(1000) + 0.4(g)

Simplifying and solving for g:

480 + 0.48g = 500 + 0.4g

0.08g = 20

g = 250

Therefore, the number of girls in the school is 250.

Answer:

250

Step-by-step explanation:

Hi dear,

Firstly, let the girls be G

1000 + G = Total number of students

50% of boy = 1000 × 0.5 = 500

40% of girls = G × 0.4 = 0.4G

0.48 • (1000 + G) = 480 + 0.48G

480 + 0.48G = 500 + 0.4G

Collect Like Terms

0.48G - 0.4G = 500 - 480

0.08G = 20

G = 20/0.08

G = 250

Therefore, the girls are 250( two hundred and fifty)in the school

Answer:

Arithmetic

Step-by-step explanation:

It is arithmetic because it keeps adding 6.

\(9+6=15\)

\(15+6=21\)

\(21+6=27\)

\(27+6=33\)

therefore, being Arithmetic.

Hope this helped!

brainliest please!

Answer:

Arithmetic

Step-by-step explanation:

#1) KEEP IN MIND: Arithmetic-add Geometric-multiply

#2) KEEP IN MIND: For checking do the opposite: arithmetic-subtract geometric-divide

Geometric check:

33/27=1.23

27/21=1.28

This is not geometric because it would have the same answer.

Arithmetic check:

33-27=6

27-21=6

This is arithmetic because it has the same answer.

The expressions (7x - 6y) and (3x - 5y) added together result in 10x - 11y.

Area is the entire amount of space occupied by a flat (2-D) surface or an object's shape.

On a sheet of paper, draw a square using a pencil. It has two dimensions. The area of a shape on paper is the area that it occupies.

Consider your square as being composed of smaller unit squares.

The number of unit squares necessary to completely cover the surface area of a specific 2-D shape is used to calculate the area of a figure. Some typical units for measuring area are square cms, square feet, square inches, square meters, etc.

Draw unit squares with 1-centimeter sides in order to calculate the area of the square figures shown below. The shape will therefore be measured.

According to our question-

(7x – 6y) and (3x – 5y

Then the sum of the expressions will be

(7x – 6y) + (3x – 5y)

7x – 6y + 3x – 5y

10x – 11y

Hence, The expressions (7x - 6y) and (3x - 5y) added together result in 10x - 11y.

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(a) Using a first-order method, we can approximate f"(1) as:

f"(1) ≈ [f(x-2h) - 2f(x) + f(x+3h)] / (5\(h^2\))

(b) The exact value of f"(1) is -1, so the approximation error for each of the above calculations is:

Error = |1.6 - (-1)| ≈ 2.6

(a) Using a first-order method, we can approximate f"(1) as:

f"(1) ≈ [f(x-2h) - 2f(x) + f(x+3h)] / (5\(h^2\))

(b) Using the three-point centered difference formula for the second derivative, we have:

f"(x) ≈ [f(x-h) - 2f(x) + f(x+h)] / \(h^2\)

For f(x) = 1-5 and x = 1, we have:

f(0.9) = 1-4.97 = -3.97

f(1) = 1-5 = -4

f(1.1) = 1-5.03 = -4.03

For h = 0.1, we have:

f"(1) ≈ [-3.97 - 2(-4) + (-4.03)] / (\(0.1^2\)) ≈ 1.6

For h = 0.01, we have:

f"(1) ≈ [-3.997 - 2(-4) + (-4.003)] / (\(0.01^2\)) ≈ 1.6

For h = 0.001, we have:

f"(1) ≈ [-3.9997 - 2(-4) + (-4.0003)] / (0.00\(1^2\)) ≈ 1.6

The exact value of f"(1) is -1, so the approximation error for each of the above calculations is:

Error = |1.6 - (-1)| ≈ 2.6

Therefore, the first-order method and three-point centered difference formula provide an approximation to f"(1), but the approximation error is relatively large.

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we are asked to develop a first-order method for approximating the second derivative of a function f(1), using data points f(x-2h), f(x), and f(x+3h). A first-order method uses only one term in the approximation formula, which in this case is the point-centred difference formula.

This formula uses three data points and approximates the derivative using the difference between the central point and its neighboring points. For part (b) of the question, we are asked to use the three-point centred difference formula to approximate the second derivative of a function f(x)=1-5, for different values of h. The approximation error is the difference between the true value of the derivative and its approximation, and it gives us an idea of how accurate our approximation is. (a) To develop a first-order method for approximating f''(1) using the data f(x-2h), f(x), and f(x+3h), we can use finite differences. The formula can be derived as follows: f''(1) ≈ (f(1-2h) - 2f(1) + f(1+3h))/(h^2) (b) For f(x) = 1-5x, the second derivative f''(x) is a constant -10. Using the three-point centered difference formula for the second derivative: f''(x) ≈ (f(x-h) - 2f(x) + f(x+h))/(h^2) For h = 0.1, 0.01, and 0.001, calculate f''(1) using the formula above, and then determine the approximation error by comparing with the exact value of -10. Note that the approximation error is expected to decrease as h decreases, and the final answers for derivative values should be reported to 6 decimal digits.

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Answer:

Slope of the graphed line, using 2 points (-1, 3) and (0, 0):

Slope of the line containing the points (-6, 2) and (-9, 5):

The difference in number between the slopes:

The difference in slopes:

Answer:

i like to know this answer

List and appraise a piece of music base on timbre

Step-by-step explanation:

x = number of years after 2007.

x = 0 for 2007.

PC(x) is a function that calculates how many pounds of chicken the average adult will eat every year (x) after 2007 (up to 2012).

PC(x) = 0.8x + 52

0 <= x <= 5

in 2007 (x = 0) the average adult ate 52 pounds.

in every year after 2007 until 2012 0.8 pounds get added to the amount of the previous year.

so, in 2012 (x = 5) the average adult will eat

PC(5) = 0.8×5 + 52 = 4 + 52 = 56 pounds of chicken.

The politician's claim may be justified because the interval contains 0, indicating no difference in population proportions, but the presence of both positive and negative values within the interval suggests that there could still be a difference in support for the new traffic law between the two political parties.

Based on the given information, the politician's claim may be justified because the 95 percent confidence interval for the difference in population proportions (-0.010, 0.110) contains 0, indicating no difference in the population proportions. However, it is important to note that the interval also contains both positive and negative values, which suggests that there could potentially be a difference in the proportions of party members who support the new traffic law.

While the interval contains 0, which supports the politician's claim, the presence of positive and negative values suggests uncertainty. This means that it is possible for there to be a difference in support between the two political parties. Without further information or analysis, it is difficult to definitively conclude whether the claim is justified or not.

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Answer:

Tax amount = $36.25

Step-by-step explanation:

The tax rate is 7.25%.

We need to find the tax be on a $500 TV.

It can be calculated as follows :

\(C=500\times 7.25\%\\\\=500\times \dfrac{7.25}{100}\\\\=\$36.25\)

So, the required tax on $500 TV is $36.25.

The 90% confidence interval for the difference in the population means is -2.51 to 0.31

From the question, we have the following parameters that can be used in our computation:

xˉ₁ = −17.1

s₁² = 8.4

n₁ = 22

​xˉ₂ = −16.0

s₂² = 8.7

n₂ = 24

Calculate the pooled variance using

P = (df₁ * s₁² + df₂ * s₂²)/df

Where

df₁ = 22 - 1 = 21

df₂ = 24 - 1 = 23

df = 22 + 24 - 2 = 44

So, we have

P = (21 * 8.4 + 23 * 8.7)/44

P = 8.56

Also, we have the standard error to be

SE = √(P/n₁ + P/n₂)

So, we have

SE = √(8.56/22 + 8.56/24)

SE = 0.86

The z score at 90% CI is 1.645, and the CI is calculated as

CI =  (x₁ - x₂) ± z * SE

So, we have

CI = (-17.1 + 16.0) ± 1.645 * 0.86

This gives

CI = -1.1 ± 1.41

Expand and evaluate

CI = (-2.51, 0.31)

Hence, the confidence interval is -2.51 to 0.31

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Answer:

24

Step-by-step explanation:

12*4/2

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Davis wants to pour 5 gallons of punch into ½ gallon jugs How many jugs will he need?

A. 2½

B. 5½

C. 10

D. 15

Answer:

Number of jugs = 10

Davis will need 10 jugs to pour 5 gallons of punch into ½ gallon jugs.

Step-by-step explanation:

David has 5 gallons of punch that he wants to pour into jugs.

The capacity of 1 jug is ½ gallon.

The required number of jugs may be found as

Number of jugs = gallons of punch/capacity of jug

For the given case, we have

Gallons of punch = 5

capacity of jug (in gallons) = ½ = 0.5

So, the required number of jugs is,

Number of jugs = 5/½

Number of jugs = 5/0.5

Number of jugs = 10

Therefore, Davis will need 10 jugs to pour 5 gallons of punch into ½ gallon jugs.

As the interest rate increases from 10 percent to 11 percent, the present value of the bond decreases from $1,074.47 to $1,058.31. Conversely, when the interest rate decreases to 9 percent, the present value increases to $1,091.19. This is because the discount rate used to calculate the present value is inversely related to the interest rate, meaning that as the interest rate increases, the present value decreases, and vice versa.

To compute the present value of a five-year, 10 percent coupon bond with a face value of $1,000, we need to discount the future cash flows (coupon payments and face value) by the appropriate interest rate.

Step 1: Calculate the present value of each coupon payment.
Since the bond has a 10 percent coupon rate, it pays $100 (10% of $1,000) annually. To calculate the present value of each coupon payment, we need to discount it by the interest rate.

Using the formula: PV = C / (1+r)^n
Where PV is the present value,

C is the cash flow,

r is the interest rate, and

n is the number of periods.

At an interest rate of 10 percent, the present value of each coupon payment is:
PV1 = $100 / (1+0.10)^1 = $90.91

Step 2: Calculate the present value of the face value.
The face value of the bond is $1,000, which will be received at the end of the fifth year. We need to discount it to its present value using the interest rate.

At an interest rate of 10 percent, the present value of the face value is:
PV2 = $1,000 / (1+0.10)^5 = $620.92

Step 3: Calculate the total present value.
To find the present value of the bond, we need to sum up the present values of each coupon payment and the present value of the face value.
Total present value at an interest rate of 10 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,074.47

When the interest rate goes to 11 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 11 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,058.31

When the interest rate goes to 9 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 9 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,091.19

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Answer:

positive

Step-by-step explanation:

assuming what you mean is subtracting a negative number, this will be positive.

subtracting a negative number will make the number positive, for example

8 - (-3) is the same as 8 + 3

The number of unemployed people in Apexico in February 2008 was 10,080,000. So, correct option is A.

To calculate the number of unemployed people in Apexico in February 2008, we can use the following formula:

Number of Unemployed = Total Population x Unemployment Rate

Substituting the given values:

Number of Unemployed = 168,000,000 x 0.06 = 10,080,000

Option A is the correct answer.

This calculation is based on the assumption that the unemployment rate is constant across the entire population of Apexico.

This calculation provides a rough estimate of the number of unemployed people in Apexico in February 2008, but it should be interpreted with caution.

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