solve -5x-(2x+3)=9 useing pemdas

The number of waffles can be made from 15 eggs are, 20 waffles.

the waffles can be calculates as follows

4 cups of fluor + 6 eggs +2 tbsp oil = 8 waffles

we need 6 eggs to make 8 waffles

So, the waffles can we make from 15 eggs = \(\frac{8}{6} X 15 = 20\) waffles

Hence, the number of waffles can be made from 15 eggs are 20 waffles.

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The slope of a line perpendicular to line E is -(5/3).

Given:

Line E passes through the points (-3, 4) and (2, 7).

Slope of line E =  \(\frac{y_{2}-x_{1} }{x_{2}-x_{1} }\)

                         =  \(\frac{7-4}{2-(-3)}\)

                         =  \(\frac{3}{5}\)

So, the slope of a line perpendicular to line E will be the negative reciprocal of the slope of line E i.e. -(5/3).

Therefore, the slope of a line perpendicular to line E is -(5/3).

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The area of the triangle is approximately 0.968 square meters.

Heron's formula is a mathematical formula used to determine the area of a triangle when the lengths of its sides are given. It was discovered by Hero of Alexandria, a Greek mathematician in the first century AD.

The formula states that the area of a triangle is equal to the square root of the product of its semiperimeter and the difference of each of its semiperimeter sides.

Semiperimeter is a term used to describe half of the triangle's perimeter. In the given triangle having sides of 1m, 2m, and 2m, the semiperimeter is calculated by adding the three sides together and then dividing the sum by two, as follows:

Semiperimeter = (1 + 2 + 2) / 2 = 2.5m Using the Heron's formula,

the area of the triangle can be calculated as shown below:

Area of triangle = sqrt (2.5 (2.5 - 1) (2.5 - 2) (2.5 - 2))

= sqrt (2.5 x 1.5 x 0.5 x 0.5)

= sqrt (0.9375)

= 0.968 m²

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The signal f(t) = cos(6t) + sin(8t) + e(j2t) is not periodic.

To determine if a signal is periodic, we need to check if there exists a fundamental period T₀ such that f(t + T₀) = f(t) for all t.

Let's analyze each component separately:

1. cos(6t): The fundamental period of cos(6t) is 2π/6 = π/3. This means that cos(6t + π/3) = cos(6t) for all t. Therefore, the fundamental frequency ω₀ for cos(6t) is 6.

2. sin(8t): The fundamental period of sin(8t) is 2π/8 = π/4. This implies that sin(8t + π/4) = sin(8t) for all t. Hence, the fundamental frequency ω₀ for sin(8t) is 8.

3. e(j2t): The exponential term e(j2t) has a frequency of ω = 2. However, it does not have a fundamental period since e(j2(t + T₀)) ≠ e(j2t) for any T₀.

Since the three components have different fundamental periods, there is no common fundamental period T₀ that satisfies f(t + T₀) = f(t) for all t. Hence , it is not periodic.

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The equation of the line is y = 2x + 8 that is parallel to the given line y = 2x + 2 and passes through the point (−3, 2)

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation of a straight line is:

y = mx + b

Where m is the rate of change and b is the y intercept.

Two lines are parallel if they have the same slope.

Let us assume that the line is parallel to y = 2x + 2 and passes through the point (−3, 2).

The slope of the line y = 2x + 2 is 2, Since it is parallel, the slope is also 2. hence:

y - y₁ = m(x - x₁)

y - 2 = 2(x - (-3))

y - 2 = 2(x + 3)

y = 2x + 8

The equation of the line is y = 2x + 8

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An equation of the line that is parallel to the given line and passes through the point (−3, 2) is: 4x + 3y = -6.

Mathematically, the slope of any straight line can be calculated by using this formula;

Slope, m = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope, m = (y₂ - y₁)/(x₂ - x₁)

By critically observing the graph (see attachment), we can logically deduce that the line passes through the following points:

Points (x, y) = (3, -1)

Points (x, y) = (0, 3)

Substituting the given parameters into the formula, we have;

Slope, m = (3 + 1)/(0 - 3)

Slope, m = 4/-3

Slope, m = -4/3.

In Geometry, two (2) lines are parallel under the following conditions:

m₁ = m₂ ⇒ -4/3 = -4/3

Note: m represents the slope.

At point (-3, 2), an equation of the other line can be calculated by using the point-slope form:

y - y₁ = m(x - x₁)

Where:

Substituting the given points into the formula, we have;

y - y₁ = m(x - x₁)

y - 2 = -4/3(x - (-3))

y - 2 = -4/3(x + 3)

y - 2 = -4x/3 - 4

y - 2 = -4x/3 - 4 + 2

y = -4x/3 - 2

Multiplying all through by 3, we have:

3y = -4x - 6

Rearranging the equation, we have:

4x + 3y = -6

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It represents a straight line, where the slope indicates the average change per time period, and the intercept is the starting value. This model is ideal for forecasting data with a linear growth pattern.

The linear trend model is appropriate when a time series is expected to grow by a fixed amount each time period. This model assumes that the increase in the variable over time is linear, meaning that it can be represented by a straight line on a graph. The linear trend model can be used to forecast future values of the time series based on its past behavior. In order to fit the linear trend model, at least three data points are required to establish a trend line. This trend line is then used to predict future values of the time series.

If a time series is expected to grow by fixed amounts each time period, the linear trend model is a suitable choice for forecasting future values of the series. When a time series is expected to grow by fixed amounts each time period, the linear trend model should be used. This model is suitable for datasets with a consistent increase or decrease over "three" or more time periods.

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Answer:

11

Step-by-step explanation:

multiply 7 by 2, you will get 14

subtract 3 from 14 you will get 11

so the total answer is 11

The missing lengths are:

AB= 7.211 unit

CD = 5.83 unit

EF = 10.77 unit

GH = 6.088 unit

Using Pythagoras Theorem we get

AB² = 6² + 4²

AB² = 36 + 16

AB² = 52

AB= 7.211

Again, CD²= 5² + 3²

CD² = 25 + 9

CD = 5.83

Again, EF² = 10² + 4²

EF² = 100 + 16

EF² = 116

EF = 10.77

and, GH² = 6² + 1²

GH² = 36 + 1

GH² = 37

GH = √37

GH= 6.088

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When p = 0, the consumer would optimally choose a quantity of q∗ = 40 units (40,000 gallons).

(a) q∗ = 40 units (40,000 gallons)

(b) marginal value at q∗ = $40.00 per 1000 gallons

(c) total benefit = $1,600.00

to illustrate the figure, we can plot the demand curve using the given price equation p = 80 - 2q. the x-axis represents the quantity of water (q) in units of 1000 gallons, and the y-axis represents the price per 1000 gallons ($/1000 g). the demand curve will be a downward-sloping line starting at p = 80 when q = 0, and intersecting the price axis at p = 0 when q = 40.

(a) to determine the optimal quantity (q∗) that the consumer would choose, we set the marginal benefit (mb) equal to the price (p). the marginal benefit is the derivative of the total benefit with respect to quantity. in this case, the marginal benefit is constant and equal to the price, so mb = p. (b) at the optimal quantity q∗, the marginal value received for the last unit of quantity is equal to the price. since the price is given as $80.00 per 1000 gallons, the marginal value at q∗ is $80.00 per 1000 gallons.

(c) the total benefit is calculated by multiplying the price per unit (p) by the quantity (q∗). in this case, when the price offered is $0.00 per 1000 gallons, the total benefit is $80.00 per 1000 gallons multiplied by 40 units (40,000 gallons), resulting in a total benefit of $1,600.00.

note: in this specific case, where the price offered is $0.00 per 1000 gallons, the total benefit, consumer surplus, and total net benefit would all be equal, as there is no payment required.

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The function X(T) = 2cos(2π × 7 × 10' × T) represents a cosine wave with a frequency of 7 × 10' Hz and an amplitude of 2.

In this equation, T represents time. The argument of the cosine function, 2π × 7 × 10' × T, indicates the oscillatory nature of the function. The coefficient 2π × 7 × 10' represents the angular frequency, which determines how quickly the cosine wave completes one full cycle. Multiplying this by T allows for the variation of the function over time.

As T changes, the cosine function will produce values between -2 and 2, resulting in a waveform that oscillates above and below the x-axis. The amplitude of 2 determines the maximum displacement from the x-axis. The frequency of 7 × 10' Hz indicates the number of complete cycles the waveform completes in one second.

Therefore, the function X(T) describes a periodic signal that repeats every 1/f seconds, where f is the frequency.

Overall, the function X(T) generates a periodic cosine wave with a specific frequency and amplitude, providing a mathematical representation of oscillatory behavior over time.

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The number of combination of 11 objects taken 7 at a time is 330

The total objects present = 11

Total objects taken at a time = 7

We need to find the number of combinations of 11 objects taken 7 at a time.

To calculate the number of combinations, the formula used is nCr

Where n represents the total number  and r represents the nymber of items choosen at a single time

nCr = n! / (r! x (n – r)!)

nCr = 11! / (7! x (11 - 7)!)

nCr = 11! / (7! x 4!)

nCr = 330

Therefore, the number of combination of 11 objects taken 7 at a time is 330

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Answer:

The answer to this question is 238 mm^2

Step-by-step explanation:

You are correct!!

good luck on the assignment

Answer:

238 cm²

calculate the area of bigger rectangle:

length * width

11 * (5 + 4 + 5 + 4 )

11 * 18

198 cm²

calculate the area of 2 smaller rectangle:

2 ( length * width )

2 ( 5 * 4 )

2 ( 20 )

40 cm²

total area of both:

40 + 198

238 cm²

Consider the same figure as given above. It is observed that DP/PE = DQ/QF and also in the triangle DEF, the line PQ is parallel to the line EF.

So, ∠P = ∠E and ∠Q = ∠F.

Hence, we can write: DP/DE = DQ/DF= PQ/EF.

The above expression is written as

DP/DE = DQ/DF=BC/EF.

It means that PQ = BC.

Hence, the triangle ABC is congruent to the triangle DPQ.

(i.e) ∆ ABC ≅ ∆ DPQ.

Thus, by using the AAA criterion for similarity of the triangle, we can say that

∠A = ∠D, ∠B = ∠E and ∠C = ∠F.

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Answer:

1

Step-by-step explanation:

Find the rise over run

Rise = 3

Run = 3

3/3 = 1

Slope = 1

Answer:

1

Step-by-step explanation:

First, you take any two points from the line, I put (2,1) and (0,-1). You plug it into the formula y2-y1/x2-x1 which would be -1-1/0-2 which is equal to -2/-2=1

Hope this helps

Answer:

1. 250x12= 3000. So she earned $3000 in that 12 weeks, if you include the 500 then it would be 3500 dollars if not then it would be 3000 dollars.

2. Divide 75 and 12 and you get 6.25 if you want to estimate. Then the answer would be, all of the fields will be harvested in just 6 days.

3. Divide 54 and 3 and you get 18. 18 weeks if they frame the sanem number each week.

4. If you divide 8,000 and 450 you get 17.7777777778. If you want to estimate then the it would be 18. So it would take about 18 days to fill up the 8,000 gallons of water.

5. This graph is y=20x

6. Don't really know, if the 0 is 360 then 10 and 300 are pretty easy because 10=30. so 0, 10, 20 is 360, 300,240 likes the graph and I would think you can solve this

The check for independence in a one- sample is

The population size is further than 10 times the sample size.

The Correct option is D.

What is Z- test?

A Z- test is a statistical thesis test used to determine whether a sample mean significantly differs from a given population mean when the population standard divagation is known.

For a one- sample z- test for a population proportion, the sample is named without relief from a finite population.

In order for the test to be valid, it's necessary to insure that the sample is small relative to the population size.

still, it can be considered large enough to satisfy the independence supposition, If the population size is further than 10 times the sample size. This supposition is necessary for the validity of statistical conclusion in this environment.

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The appropriate measure of variability for the given data is the IQR, and its value is 16.

Based on the given stem-and-leaf plot, which represents the scores earned in a flower-growing competition, we can determine the appropriate measure of variability for the data.

The stem-and-leaf plot shows the individual scores, and to measure the spread or variability of the data, we have two commonly used measures: the range and the interquartile range (IQR).

The range is calculated by subtracting the smallest value from the largest value in the dataset. In this case, the smallest value is 20, and the largest value is 65. Therefore, the range is 65 - 20 = 45.

The interquartile range (IQR) is a measure of the spread of the middle 50% of the data. It is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). Looking at the stem-and-leaf plot, we can identify the quartiles. The first quartile (Q1) is 25, and the third quartile (Q3) is 41. Therefore, the IQR is 41 - 25 = 16.

In this case, both the range and the IQR are measures of variability, but the IQR is generally preferred when there are potential outliers in the data. It focuses on the central portion of the dataset and is less affected by extreme values. Therefore, the appropriate measure of variability for the given data is the IQR, and its value is 16.

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Minimum sample size needed  such that mean of the sample is smaller than 35 and sum is 1280 is 37.

To find the minimum sample size, we need to determine the smallest number of elements in a sample that would produce an average less than 35.

To do this, we use the formula for the mean, which is the sum of the elements divided by the number of elements.

If we let x be the minimum sample size, then the sum of the elements in the sample must be smaller than 35x. Since the sum of the elements in the sample is known to be 1280, we can set up an inequality:

1280/x < 35

Solving for x, we get:

x > 1280 / 35 = 36.36

Since x must be a whole number, we round up to the next whole number, which is 37.

However, it's important to note that this is a theoretical minimum and there could be many sets of 37 elements whose sum is 1280 but whose average is less than 35.

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Complete question:

Given a sample having variable size given that sum of the sample is 1280 what is the minimum sample size needed such that mean of the sample is smaller than 35.

a) i.  the probability of two rainy days is 0.2 * 0.85 = 0.17.

   ii. The total probability of having exactly one rainy day is the sum of    these two probabilities is  0.18.

   iii. probability of having At least one dry day is 0.83.

b)i. The probability of having Three rainy days is 0.1447.

ii. The probability of having Exactly one dry day is 0.1881

iii. The probability of having At most two rainy days is 0.35

a) On two consecutive days, the probability of having:

i. Two rainy days: The probability of two rainy days can be found by multiplying the probabilities of rain on each day, given that the previous day was rainy. In this case, the probability of two rainy days is 0.2 * 0.85 = 0.17.

ii. Exactly one rainy day: There are two ways to have exactly one rainy day in two consecutive days: either the first day is rainy and the second day is dry, or the first day is dry and the second day is rainy. The total probability of having exactly one rainy day is the sum of these two probabilities, which can be calculated as:

P(rainy day first) * P(dry day second) + P(dry day first) * P(rainy day second) = 0.2 * 0.9 + 0.8 * 0.1 = 0.18

iii. At least one dry day: To find the probability of at least one dry day, we can subtract the probability of two rainy days from 1, since the only possibility in which there is no dry day is if both days are rainy:

1 - P(two rainy days) = 1 - 0.17 = 0.83

b) On three consecutive days, the probability of having:

i. Three rainy days: The probability of three rainy days can be found by multiplying the probabilities of rain on each day, given that the previous day was rainy. In this case, the probability of three rainy days is 0.2 * 0.85 * 0.85 = 0.1447.

ii. Exactly one dry day: To have exactly one dry day in three consecutive days, we need two rainy days followed by a dry day, or a rainy day followed by two dry days, or two dry days followed by a rainy day. The total probability of having exactly one dry day can be calculated as:

P(rainy day first, rainy day second, dry day third) + P(rainy day first, dry day second, dry day third) + P(dry day first, rainy day second, rainy day third)

= 0.2 * 0.85 * 0.9 + 0.2 * 0.9 * 0.9 + 0.8 * 0.1 * 0.1 = 0.1881

iii. At most two rainy days: To find the probability of at most two rainy days, we need to add up the probabilities of two rainy days and one rainy day.

P(at most two rainy days) = P(two rainy days) + P(one rainy day) = 0.17 + 0.18 = 0.35

So, the probability of having at most two rainy days in three consecutive days is 0.35.

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Answer:

B) (-2,6)

Step-by-step explanation:

Where do the two lines intersect? That is where the solution is.

Hope this helps

Answer:

I believe the answer B ( I think)

Answer:

(Choice B) B It decreases.

Step-by-step explanation:

According to the situation, the solution of the value of the expression is as follows

Let us assume

r         80 -2r

5        80 - 10 = 70

4        80 - 8 = 72

3        80 - 6 = 74

2        80 - 4 = 76

1         80 - 2 = 78

As we can from the above calculation that expression value risen if r value decreased

Therefore the correct option is B.

Answer:

It increases

Step-by-step explanation:

Answer:

The perfect square lockers are the only ones left open.

Step-by-step explanation:

Here is a legit link to an explanation of this old puzzle problem!

https://36university.com/act-math-locker-problem-solution/

Quoting from that page:

Method 2: Who Touches Which Lockers

Identifying which students touch which lockers is a little less of a brute-force approach and would likely have gotten you to the solution a little more quickly.

Here’s what I mean:

Consider locker #1. The only student who touches locker #1 is student #1. Student 1 opens the locker, and since no one else touches it, it will be left open at the end.

Consider locker #2. Student 1 opens the locker, and student 2 closes it. No one else touches the locker, so it will be closed.

Consider locker #10. Students 1 opens the locker. Student 2 closes it. Students 3 and 4 skip right by it. Student 5 opens it. Students 6, 7, 8, and 9 skip right by it. And student 10 closes it. Locker #10 will be closed.

Mental Milestone 1: After looking at several lockers, you should notice that lockers are only changed by student numbers that are factors of the locker number. In other words, locker 12 is changed by students 1, 2, 3, 4, 6, and 12.

Mental Milestone 2: You should also have noticed that factors always come in pairs. This means that for every student who opens a locker, there is another student who closes it. For locker #12, student 1 opens it, but student 12 closes it later. Student 2 opens it, but student 6 closes it later. Student 3 opens it, but student 4 closes it later.

By this logic, every locker would be closed.

But there are exceptions!

Consider locker #25. Student 1 opens it. Student 5 closes it. Student 25 opens it. The locker will be left open, but why? In this case, the factors do not come in pairs. One and 25 are a pair, but five times five is also 25. Five only counts as one factor. This causes the open-close pattern to be thrown off. Locker #25 is left open.

Mental Milestone 3: When factors don’t come in pairs, the locker will be left open. And factors don’t come in pairs when numbers are multiplied by themselves. Perfect squares (1, 4, 9, 16, 25, 36, 49, 64, 81, 100,…) are the only numbers whose factors don’t come in pairs because one set of factors, the square root, is multiplied by itself. This means that only perfect square lockers will be left open.

Locker #s 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100 are left open!

Step-by-step explanation:

the answer is 2y=16x+14

The equations that could be the other equation are y = 8x - 7 and y = -8x + 7.

If the system of equations has no solution, then the other equation must not have the same slope-intercept form as the first equation.

The slope-intercept form of the equation y = 8x + 7 is y = mx + b, where m is the slope and b is the y-intercept. Thus, the slope of the first equation is 8 and the y-intercept is 7.

Now let's check each of the given equations to see which one could be the other equation.

2y = 16x + 14

Rewriting this equation in slope-intercept form, we get y = 8x + 7, which is the same as the first equation. Therefore, this equation cannot be the other equation.

y = 8x – 7

This equation has the same slope as the first equation but a different y-intercept. Therefore, it represents a different line and could be the other equation.

y = –8x + 7

This equation has a slope that is the negative of the slope of the first equation, so it represents a different line. Therefore, it could be the other equation.

2y = −16x − 14

Rewriting this equation in slope-intercept form, we get y = -8x - 7, which has the same slope as the first equation but a different y-intercept. Therefore, it represents a different line and could be the other equation.

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Answer:

Step-by-step explanation:

y=10

(a) Construct confidence intervals are : 90%: [428.95, 444.05], 95%: [427.13, 445.87], 99%: [423.67, 449.33].

(b) The 99% confidence interval has the widest interval.

(a) To construct confidence intervals for the mean breaking strength of the wool fibers, we shall use the given formula:

Confidence interval = sample mean ± (critical value * standard error)

The critical value here will depends on the level of confidence. For a 90% confidence level, the critical value is 1.645 (from the standard normal distribution). For a 95% confidence level, the critical value is 1.96, and for a 99% confidence level, the critical value is 2.576.

Standard error is obtained by dividing the sample standard deviation by the square root of the sample size.

Plugging in the values, we can calculate the confidence intervals:

90% confidence interval:

Lower bound = 436.5 - (1.645 * (11.9 / √20))

Upper bound = 436.5 + (1.645 * (11.9 / √20))

95% confidence interval:

Lower bound = 436.5 - (1.96 * (11.9 / √20))

Upper bound = 436.5 + (1.96 * (11.9 / √20))

99% confidence interval:

Lower bound = 436.5 - (2.576 * (11.9 / √20))

Upper bound = 436.5 + (2.576 * (11.9 / √20))

(b) The width of a confidence interval depends on both the critical value and the standard error. When aiming for a higher level of confidence, the interval becomes wider as it requires a larger critical value. Consequently, it can be concluded that among the given confidence intervals, the one with a 99% confidence level will have the broadest range.

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The magnetic field between the plates is at a distance of 5.00 cm from the center.

To solve this problem, we can use the formulas for the electric field and magnetic field due to a charging capacitor.

(a) The time rate of increase of the electric field between the plates can be found using the formula:

dE/dt = (I / (πε₀R²)),

where dE/dt is the time rate of increase of the electric field, I is the current, ε₀ is the permittivity of free space, and R is the radius of the circular plates.

Given:

I = 0.250 A (current)

R = 10.8 cm = 0.108 m (radius)

Using the formula, we can calculate the time rate of increase of the electric field:

dE/dt = (0.250 A) / (π * ε₀ * (0.108 m)²)

The value of ε₀ is approximately 8.854 × 10^(-12) F/m.

Plugging in the values:

dE/dt = (0.250 A) / (π * (8.854 × 10^(-12) F/m) * (0.108 m)²)

Calculating this expression will give you the time rate of increase of the electric field between the plates.

(b) To calculate the magnetic field between the plates 5.00 cm from the center, we can use Ampere's law:

B = (μ₀I) / (2πr),

where B is the magnetic field, I is the current, μ₀ is the permeability of free space, and r is the distance from the center of the circular plates.

Given:

I = 0.250 A (current)

r = 5.00 cm = 0.05 m (distance from the center)

Using the formula, we can calculate the magnetic field:

B = (μ₀ * 0.250 A) / (2π * 0.05 m)

The value of μ₀ is approximately 4π × 10^(-7) T·m/A.

Plugging in the values:

B = (4π × 10^(-7) T·m/A * 0.250 A) / (2π * 0.05 m)

Calculating this expression will give you the magnetic field between the plates at a distance of 5.00 cm from the center.

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Answer:(35,34)

I’m not entirely sure but for the x axis, you’re adding plus three and for the y axis, you’re adding plus 6.

a. The probability that a failure is due to an induced substance is 0.013487 or 1.35% approximately.

b. Probability of a failure due to disease or infection= 44%.

a. Determine the probability that a failure is due to an induced substance.

The total percentage of heart failures that are caused by outside factors is 19%, of which 73% are due to induced substances.

Therefore, the probability that a failure is due to an induced substance = 73/100*19/100= 0.013487 or 1.35% approximately.

b. Determine the probability that a failure is due to disease or infection.

The total percentage of heart failures that are caused by natural occurrences is 81%, of which disease accounts for 27% and infection (e.g., staph infection) accounts for 17%.

Therefore, the probability that a failure is due to disease or infection = 27/100 + 17/100= 0.44 or 44% approximately.

Probability of a failure due to induced substance= 1.35% (approx.)Probability of a failure due to disease or infection= 44% (approx.)

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