Answer: 2x^2 − 9x − 18
Step-by-step explanation:
(2x + 3)(x − 6)
= (2x + 3)(x + −6)
= (2x)(x) + (2x)(−6) + (3)(x) + (3)(−6)
= 2x^2 −12x + 3x − 18
= 2x^2 − 9x − 18
A1=3
An=2(an-1+1)
What's a2 a3 and a4
Answer:
a2 is a3 B is 2 and a4 is -2
Step-by-step explanation:
just math and more math
HELPPP PLEASEEEEEEE!!
Answer:
We would use the explicit formula since the explicit formula is used for finding the nth term in a sequence. The reason why it's not the recursive is because the recursive formula helps you find the next terms using a formula of the preceding term or term before the next term.
Forty percent of passengers with a certain airline prefer a window seat. The probability that exactly two of the next twelve person buying a ticket with this airline will prefer a window seat is about:
The probability that exactly two out of the next twelve passengers buying a ticket with this airline will prefer a window seat is approximately 0.283, or 28.3%.
To calculate the probability that exactly two out of the next twelve passengers buying a ticket with this airline will prefer a window seat, we can use the binomial probability formula.
The formula for calculating the binomial probability is:
P(X = k) = (nCk) * p^k * (1-p)^(n-k)
Where:
P(X = k) is the probability of exactly k successes,
n is the total number of trials,
k is the number of successful outcomes,
p is the probability of success in a single trial, and
(1-p) is the probability of failure in a single trial.
In this case, we have:
n = 12 (total number of trials)
k = 2 (number of successful outcomes)
p = 0.40 (probability of success, which is 40%)
Substituting these values into the formula, we get:
P(X = 2) = (12C2) * (0.40^2) * (1-0.40)^(12-2)
Calculating this expression, we find:
P(X = 2) ≈ 0.283
So, the probability that exactly two out of the next twelve passengers buying a ticket with this airline will prefer a window seat is approximately 0.283, or 28.3%.
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A bakery sells pie slices that are 1/6 of a pie. If they made 18 pies today.How many slices of pie will they have?
Answer:
108 slices
Step-by-step explanation:
One pie is 6 slices so 6*18 is equal to 108
A student takes an exam containing 17 true or false questions. At least 11 correct answers are required to pass. If the student guesses, what is the probability that he will fail
The probability that the student will fail, given that he guesses the answers, is 0.227.
Since there are only two possible outcomes for each question (true or false),
the probability of guessing a correct answer is 1/2 = 0.5.
Likewise, the probability of guessing a wrong answer is also 1/2 = 0.5.
To find the probability of failing the exam,
we need to find the probability of answering less than 11 questions correctly.
Using the binomial probability formula,
the probability of getting k successes (correct answers) in n trials (questions) is given by:
P(k) = (n C k) * p^k * q^(n-k)
where p is the probability of success (getting a correct answer),
q is the probability of failure (getting a wrong answer), and (n C k) is the number of combinations of n things taken k at a time.
In this case,
n = 17, p = 0.5, and
q = 0.5.
The number of ways to get less than 11 correct answers is:
P(X < 11) = P(X = 0) + P(X = 1) + ... + P(X = 10)P(X = k) = (n C k) * p^k * q^(n-k)
Substituting the values:
P(X < 11) = P(X = 0) + P(X = 1) + ... + P(X = 10)
P(X = 0) = (17 C 0) * (0.5)^0 * (0.5)^17 = 0.0015
P(X = 1) = (17 C 1) * (0.5)^1 * (0.5)^16 = 0.0146
P(X = 2) = (17 C 2) * (0.5)^2 * (0.5)^15 = 0.0586
P(X = 3) = (17 C 3) * (0.5)^3 * (0.5)^14 = 0.1558
P(X = 4) = (17 C 4) * (0.5)^4 * (0.5)^13 = 0.268
P(X = 5) = (17 C 5) * (0.5)^5 * (0.5)^12 = 0.327
P(X = 6) = (17 C 6) * (0.5)^6 * (0.5)^11 = 0.2732
P(X = 7) = (17 C 7) * (0.5)^7 * (0.5)^10 = 0.1537
P(X = 8) = (17 C 8) * (0.5)^8 * (0.5)^9 = 0.0573
P(X = 9) = (17 C 9) * (0.5)^9 * (0.5)^8 = 0.013
P(X = 10) = (17 C 10) * (0.5)^10 * (0.5)^7 = 0.0015
Therefore, P(X < 11) = 0.0015 + 0.0146 + 0.0586 + 0.1558 + 0.268 + 0.327 + 0.2732 + 0.1537 + 0.0573 + 0.013 + 0.0015P(X < 11) = 0.8857
Thus, the probability of failing is: P(fail) = P(X < 11) = 0.8857
The probability that the student will fail, given that he guesses the answers, is 0.227 (rounded to three decimal places).
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Find the area of the figure.
Answer:
Area=105
Step-by-step explanation:
If we were to close the rectangle it would be 15ft x 8ft which equals 120ft
but then we'd have to find the area of the small rectangle inside being
3ft x 5ft = 15 ft
So, we'd have to subtract 15 ft from 120 ft giving us the answer of 105 ft
In February 2003,
the Battlefords Chamber of
Commerce in Saskatchewan
placed a cage containing a
64-cubic foot ice cube along
Yellowhead Highway. Local
customers were asked
to predict when the ice cube
would melt enough for a ball
above the ice cube to fall through it. What was
the surface area of the cube?
The side length of the cube is 4 feet. Then the surface area of the cube will be 96 square feet.
What is a volume of a cube?Suppose that: The side length of the considered cube is L units. Then, we get:
The volume of that cube = L³ cubic units.
The surface area of that cube = 6L² square units.
In February 2003, the Battlefords Chamber of Commerce in Saskatchewan placed a cage containing a 64-cubic foot ice cube along Yellowhead Highway. Then the side length of a cube will be
64 = L³
L = ∛64
L = 4 feet
Then the surface area of the cube will be
SA = 6 x 4²
SA = 6 x 16
SA = 96 square feet
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How much force is needed to lift a 10 Newton box with one pulley
Answer:
Assuming an ideal pulley system, the force required to lift a 10 Newton box with one pulley would be 10 Newtons. This is because the force required to lift an object using a pulley system is equal to the weight of the object being lifted. In an ideal pulley system, there is no friction or energy loss, so the force required is equal to the weight of the object. Therefore, if the weight of the box is 10 Newtons, a force of 10 Newtons would be required to lift it with one pulley.
3. Given a nonempty polyhedron P={(x,y)∈Rn×Rk:Ax+By≥b}, let Q denote its projection onto x-space, i.e., Q={x∈Rn:∃y∈Rk,Ax+By≥b}. Prove or disprove the following statements by counterexamples: 1) Suppose that (x^,y^) is an extreme point of P. Is x^ an extreme point of Q ? 2) Suppose that x^ is an extreme point of Q. Does there exist a y^ such that (x^,y^) is an extreme point of P ? 3) Suppose that x^ is an extreme point of Q and P does not contain a line. Does there exist a y^ such that (x^,y^) is an extreme point of P ?
P does not contain a line, it means that for any x in R^n, there exists a unique y in R^k such that Ax + By ≥ b. Therefore, x^ is uniquely determined by y^, and (x^, y^) is an extreme point of P.
1) The statement is true. Suppose (x^,y^) is an extreme point of P. To show that x^ is an extreme point of Q, we need to prove that for any two distinct points x_1, x_2 in Q, the line segment connecting x_1 and x_2 lies entirely in Q. Since Q is the projection of P onto x-space, it means that for any x in Q, there exists y in R^k such that Ax + By ≥ b.
Now, let's assume x_1 and x_2 are two distinct points in Q. Since they belong to Q, there exist corresponding y_1 and y_2 in R^k such that Ax_1 + By_1 ≥ b and Ax_2 + By_2 ≥ b. Since P is a polyhedron, the set of points that satisfy Ax + By ≥ b is a convex set. Therefore, the line segment connecting x_1 and x_2, denoted by [x_1, x_2], lies entirely in P. Since the projection of a convex set onto a subspace is also a convex set, [x_1, x_2] lies entirely in Q. Thus, x^ is an extreme point of Q.
2) The statement is false. Suppose x^ is an extreme point of Q. It does not necessarily imply the existence of a corresponding y^ such that (x^, y^) is an extreme point of P. This is because the projection Q onto x-space may not capture all the extreme points of P. It is possible for multiple points in P to project to the same point in Q, making it impossible to uniquely determine y^.
3) The statement is true. If x^ is an extreme point of Q and P does not contain a line, then there exists a corresponding y^ such that (x^, y^) is an extreme point of P. Since P does not contain a line, it means that for any x in R^n, there exists a unique y in R^k such that Ax + By ≥ b. Therefore, x^ is uniquely determined by y^, and (x^, y^) is an extreme point of P.
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4xy- 72 = 3w solve for y
Answer:
y= \(\frac{3w}{4x}\)+ \(\frac{18}{x}\)
Step-by-step explanation:
Hope this helps. Plz give brainliest.
If x and y are in direct proportion and y is 30 when x is 6,find y when x is 14
Answer:
70
Step-by-step explanation:
If y=30 when x=6, 5x=y (because they are in direct proportion).
So, when x=14 replace x.
5*14=y
y=70
you can prove this because 70/14=30/6=5
so, the proportions are equal
4) A cereal box has dimensions of 7% inches, 12 inches, and 2 inches. A pastry box has dimensions of 3%
inches, 3 % inches, and 2 % inches. What is the difference in volume, in cubic inches, between the two boxes?
Show your work.
The difference in volume between the cereal box and pastry box is 167.991 cubic inches.
What are Dimensions?
Dimensions refer to the measurement of the size or extent of an object or space in a particular direction, such as length, width, and height. In the context of boxes, dimensions are used to describe the length, width, and height of a box, usually given in inches or centimeters.
To find the volume of a rectangular box, we use the formula:
Volume = length x width x height
Let's first find the volume of the cereal box:
Volume of cereal box = 7 inches x 12 inches x 2 inches = 168 cubic inches
Now let's find the volume of the pastry box:
Volume of pastry box = 3% inches x 3% inches x 2% inches = 0.009 cubic inches
Now, to find the difference in volume between the two boxes, we subtract the volume of the pastry box from the volume of the cereal box:
168 cubic inches - 0.009 cubic inches = 167.991 cubic inches
Hence, the difference in volume between the cereal box and pastry box is 167.991 cubic inches.
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The volume of a sphere is 9,198.m3 To the nearest ,meter what is the radius of the sphere? Use 3.14 for .pi
Using the given information, the radius of the sphere to the nearest meter is 13m
Calculating Volume of a sphereFrom the question, we are to determine the radius of the sphere
Using the formula for calculating the volume of a sphere,
\(V = \frac{4}{3} \pi r^{3}\)
Where V is the volume
and r is the radius
From the given information,
V = 9198 m³
Then,
\(9198 = \frac{4}{3} \times \pi r^{3}\)
\(9198 = \frac{4}{3} \times 3.14 \times r^{3}\)
\(4 \times 3.14 \times r^{3} = 9198 \times 3\)
\(4 \times 3.14 \times r^{3} = 27594\)
\(r^{3} = \frac{27594}{4 \times 3.14}\)
\(r = \sqrt[3]{\frac{27594}{4\times 3.14} }\)
r = 12.99995 m
r ≅ 13 m
Hence, the radius of the sphere to the nearest meter is 13m.
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Which of the following shows the extraneous solution to the logarithmic equation below?
2 log Subscript 5 Baseline (x + 1) = 2
x = negative 6
x = negative 4
x = negative 2
x = negative 1
Answer:
A.-6
Step-by-step explanation:
on edg
Answer:
A) -6
Step-by-step explanation:
Solve the equation below for x:
0.25(x - 13) = 7
Answer:
x=41
Step-by-step explanation:
0.25(x-13)=7
We move all terms to the left:
0.25(x-13)-(7)=0
We multiply parentheses
0.25x-3.25-7=0
We add all the numbers together, and all the variables
0.25x-10.25=0
We move all terms containing x to the left, all other terms to the right
0.25x=10.25
x=10.25/0.25
x=41
The solution to the equation; 0.25(x - 13) = 7 as given is; x = 41
According to the question;
We are required to solve for x in the equation; 0.25(x - 13) = 7The solution to the given equation can be evaluated as follows;
0.25(x - 13) = 70.25x - 3.25 = 70.25x = 10.25x = 41.
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an insurance company checks police records on 582 accidents selected at random and notes that teenagers were at the wheel in 91 of them. (a) (8 pts) find the 95% confidence interval for , the true proportion of all auto accidents that involve teenage drivers. (note: for full credit, show all your work. no credit
The 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).
To find the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers, we can use the formula for the confidence interval for a proportion.
The formula for the confidence interval is:
CI = p1 ± Z * √((p1 * (1 - p1)) / n)
Where:
CI is the confidence interval,
p1 is the sample proportion (proportion of accidents involving teenage drivers),
Z is the Z-score corresponding to the desired confidence level (95% confidence level corresponds to Z ≈ 1.96),
n is the sample size (number of accidents checked).
Given:
Number of accidents checked (sample size), n = 582
Number of accidents involving teenage drivers, x = 91
First, we calculate the sample proportion:
p1 = x / n = 91 / 582 ≈ 0.1566
Now we can calculate the confidence interval:
CI = 0.1566 ± 1.96 * √((0.1566 * (1 - 0.1566)) / 582)
Calculating the standard error of the proportion:
SE = √((p1 * (1 - p1)) / n) = √((0.1566 * (1 - 0.1566)) / 582) ≈ 0.0184
Substituting the values into the formula:
CI = 0.1566 ± 1.96 * 0.0184
Calculating the values:
CI = 0.1566 ± 0.0361
Finally, we can simplify the confidence interval:
CI = (0.1205, 0.1927)
Therefore, the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).
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problem 1: consider the following bivariate pdf: fx,y (x, y) = { 2 x y ≤ 1 , 0 < x < 1 , 0 < y < 1 0 otherwise find the probability p(x > 0.5)
According to question, the probability that x > 0.5 is 1/4.
To find the probability P(x > 0.5), we need to integrate the given PDF over the range where x > 0.5:
P(x > 0.5) = ∫∫(x > 0.5) fx,y (x, y) dxdy
= ∫∫(x > 0.5) 2xy dxdy, where the limits of integration are 0 to 1 for y and 0.5 to 1 for x.
= ∫0^1 ∫0.5^1 2xy dxdy
= 1/4
what is probability?
The probability of an event is the measure of the likelihood of that event occurring. It is a number between 0 and 1, inclusive, where 0 indicates that the event is impossible and 1 indicates that the event is certain to occur. If the probability of an event is p, then the probability of the complement of that event (i.e., the event not occurring) is 1-p.
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What does it mean when a set is closed under addition?
Answer: I don't know
Step-by-step explanation:
You and your pen pal record the weather in your respective countries on weekend days over the summer. Complete parts a through b.
We have the following response after answering the given question: As a equation result, Country A saw more erratic weather throughout the summer, with a 6°C difference in temperatures.
What is equation?In a mathematical equation, the equals sign (=), which connects two claims and denotes equality, is utilised. In algebra, an equation is a mathematical statement that proves the equality of two mathematical expressions. For instance, in the equation 3x + 5 = 14, the equal sign separates the numbers by a space. Mathematical expressions can be used to describe the relationship between the two sentences on either side of a letter. The logo and the particular piece of software frequently correspond. like, for instance, 2x - 4 = 2.
Which nation experienced the hottest summer?
We may examine the average temperature for each nation throughout the observed weekends to determine which nation experienced the hottest summer.
Country A: (21.4°C) (18+20+22+23+24)/5
(24+26+28+29+27)/5 = 26.8°C for Country B.
The summer was therefore hotter in Country B, with an average temperature of 26.8°C.
b) Over the summer, which nation saw more erratic weather?
We may examine the temperature ranges recorded for each nation to determine which experienced more erratic weather during the summer.
24°C - 18°C equals 6°C in Country A.
29°C - 24°C equals 5°C in country B.
As a result, Country A saw more erratic weather throughout the summer, with a 6°C difference in temperatures.
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A box is to be made out of a 10 cm by 20 cm piece of cardboard. Squares of side length cm will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top. (a) Express the volume V of the box as a function of x. V = cm^3 (b) Give the domain of V in interval notation. (Use the fact that length and volume must be positive.) = ? (c) Find the length L , width W, and height H of the resulting box that maximizes the volume. (Assume that W < or = to L ) L= ?cm W= ?cm H= ? cm (d) The maximum volume of the box is ? cm^3.
(a) The volume V of the box as a function of x is V = 4x^3-60x^2+200x
(b) The domain of V in interval notation is 0<x<5,
(c) The length L , width W, and height H of the resulting box that maximizes the volume is H = 2.113, W = 5.773, L= 15.773
(d) The maximum volume of the box is 192.421 cm^2.
In the given question,
A box is to be made out of a 10 cm by 20 cm piece of cardboard. Squares of side length cm will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top.
(a) We have to express the volume V of the box as a function of x.
If we cut out the squares, we'll have a length and width of 10-2x, 20-2x respectively and height of x.
So V = x(10-2x) (20-2x)
V = x(10(20-2x)-2x(20-2x))
V = x(200-20x-40x+4x^2)
V = x ( 200 - 60 x + 4x^2)
V = 4x^3-60x^2+200x
(b) Now we have to give the domain of V in interval notation.
Since the lengths must all be positive,
10-2x > 0 ≥ x < 5 and x> 0
So 0 < x < 5
(c) Now we have to find the length L , width W, and height H of the resulting box that maximizes the volume.
We take the derivative of V:
V'(x) = 12x^2-120x+200
Taking V'(x)=0
0 = 4 (3x^2-30x+50)
3x^2-30x+50=0
Now using the quadratic formula:
x=\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
From the equationl a=3, b=-30, c=50
Putting the value
x=\(\frac{30\pm\sqrt{(-30)^2-4\times3\times50}}{2\times3}\)
x= \(\frac{30\pm\sqrt{900-600}}{6}\)
x= \(\frac{30\pm\sqrt{300}}{6}\)
x= \(\frac{30\pm17.321}{6}\)
Since x<5,
So x= \(\frac{30-17.321}{6}\)
x= 2.113
So H = 2.113, W = 5.773, L= 15.773.
d) Now we have to find the maximum volume of the box.
V = HWL
V= 2.113*5.773*15.773
V = 192.421 cm^3
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In each of problems 5 through 11, find the general solution of the given differential equation
The complete question is
"Find the general solution of the given differential equation
y''-y=0, y1(t)=e^t , y2(t)=cosht
The function \(y(t)=e^t\) is the solution of the given differential equation.
The function y(t)=cosht is the solution of given differential equation.
What is a function?
The function is a type of relation, or rule, that maps one input to specific single output.
Given;
\(y_1(t) = e^t\)
Given differential equations are,
y''-y = 0
So that,
\(y' (t) = e^t, y'' (t) = e^t\)
Substitute values in the given differential equation.
\(e^t -e^t=0\)
Therefore, the function \(y(t)=e^t\) is the solution of the given differential equation.
Another function;
\(y(t)=cosht\)
So that,
\(y"(t)=sinht\\\\y"(t)=cosht\)
Hence, function y(t)=cosht is solution of given differential equation.
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Look at the picture........... need it done ASAP
Answer:
(-8,5)
Step-by-step explanation:
The answer explained step by step on the picture.
Solve the dual of the following problem, and then find its optimal solution from the solution of the dual. Does the solution of the dual offer computational advantages over solving the primal directly? Minimize z = 50xı + 60x2 + 30x3 subject to 5x + 5x2 + 3x3 = 50 X1+X2+X3 = 207x1 + 6x2 9x3 = 30 5x1 + 5x2 + 5x3 35 2xy + 4x2 15x3 = 10 12x + 10x2 90 X2 - 10x3 = 20 X1, X2, X3 =0
Yes, the solution of the dual offer computational advantages over solving the primal directly
Let us consider the given primal problem:
Minimize z = 50x₁ + 60x₂ + 30x₃
subject to
5x₁ + 5x₂ + 3x₃ ≥ 50
x₂- x₃ ≥ 20
7x₁ + 6x₂ - 9x₃ ≥ 30
5x₁ + 5x₂ + 5x₃ ≥ 35
2x₁ + 4x₂ + 15x₃ ≥ 10
12x₁ +10x₂ ≥ 90
x₂ - 10x₃ ≥ 20
x₁, x₂, x₃ ≥ 0
We will now form the dual problem by introducing the dual variables y₁, y₂, y₃, y₄, y₅, y₆, y₇, and the objective function of the dual problem is to maximize the sum of the right-hand side coefficients of the primal constraints multiplied by the dual variables.
The constraints of the dual problem are formed by the coefficients of the primal objective function.
Maximize w = 50y₁ + 20y₂ + 30y₃ + 35y₄ + 10y₅ + 90y₆ + 20y₇
subject to
5y₁ + y₂ + 7y₃ + 5y₄ + 2y₅ + 12y₆ ≥ 50
5y₁ + 5y₂ + 6y₃ + 5y₄ + 4y₅ + 10y₆ - 10y₇ ≥ 60
3y₁ - y₂ - 9y₃ + 5y₄ + 15y₅ ≥ 30
Now, we can solve this dual problem using the simplex method or any other optimization technique.
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Complete Question:
Solve the dual of the following problem, and then find its optimal solution from the solution of the dual. Does the solution of the dual offer computational advantages over solving the primal directly?
Minimize z = 50x₁ + 60x₂ + 30x₃
subject to
5x₁ + 5x₂ + 3x₃ ≥ 50
x₂- x₃ ≥ 20
7x₁ + 6x₂ - 9x₃ ≥ 30
5x₁ + 5x₂ + 5x₃ ≥ 35
2x₁ + 4x₂ + 15x₃ ≥ 10
12x₁ +10x₂ ≥ 90
x₂ - 10x₃ ≥ 20
x₁, x₂, x₃ ≥ 0
Solve for s based on the information in the figure below and given that line f is the perpendicular bisector of MN.
The value of s is 8
How to determine the valueFirst, we need to know that perpendicular bisectors are lines that divides into equal parts
From the diagram shown, we have that;
Line NO is equal to Line MO
This is represented as;
NO = 3s + 12
MO = 36
Equate the expressions, we get;
3s + 12 = 36
collect the like terms, we have;
3s = 36 - 12
subtract the value, we have;
3s = 24
Divide both sides by the coefficient of s in the equation;
s = 24/3
Divide the values
s = 8
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The hanger below represents a balanced equation find the Value of n that makes the equation true n=
Answer: where is the diagram ?
Step-by-step explanation:
The triangle below is isosceles. Find the length of side
x to the nearest tenth.
Answer:
x=2.3
Step-by-step explanation:
Isosceles triangle means both sides are the same length, triangle is also right meaning you can plug values into Pythagorean theorem (\(a^2+b^2=c^2\))
\(x^2+x^2=\sqrt{11}^2 \\2x^2=11\\x=\sqrt{\frac{11}{2} } \\x=2.345...\\x=2.3\)
Assuming all my math is right, this is your answer
Given the following acceleration function of an object moving along a line, find the position function with the given initial velocity and position. a(t)=−38;v(0)=24,s(0)=0 s(t)= (Type an expression using t as the variable.)
According to the question the position function with the given initial velocity and position is \(\[s(t) = -19t^2 + 24t.\]\)
To find the position function, we need to integrate the acceleration function twice.
First, integrate the acceleration function to find the velocity function:
\(\[v(t) = \int a(t) dt = \int -38 dt = -38t + C_1.\]\)
Next, integrate the velocity function to find the position function:
\(\[s(t) = \int v(t) dt = \int (-38t + C_1) dt = -19t^2 + C_1t + C_2.\]\)
Using the given initial conditions v(0) = 24 and s(0) = 0, we can find the constants:
\(\[v(0) = -38(0) + C_1 = 24 \implies C_1 = 24,\]\)
\(\[s(0) = -19(0)^2 + 24(0) + C_2 = 0 \implies C_2 = 0.\]\)
Therefore, the position function is:
\(\[s(t) = -19t^2 + 24t.\]\)
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58 x 64 is the same as:
(64 x 50) + (64 x )
What number goes in the space?
help please
Rachel covered a single lap of 1,210 m in 55 s. Calculate her speed in m/s
Answer:
22 m/s
Step-by-step explanation:
Take the distance and divide by the time
1210 m/55s
22 m/s
Answer:
22m/sStep-by-step explanation:
\(speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} \)
Find the value of x.
Answer:
X=23
Step-by-step explanation: