Solve the inequality 5x + 3 > 48

In parallelogram ABCD, angle B is a right angle. The parallelogram is a rectangle. If so, by: B. Rectangle one right angle property.

A particular kind of parallelogram called a rectangle has several unique characteristics. The fact that it contains four right angles is one of these characteristics. In other words a rectangle has four angles that are all 90 degrees.

Angle B in the parallelogram ABCD is described as a right angle in the information provided. This indicates that angle B is 90 degrees in length. The parallelogram meets the property of having one right angle which is a characteristic of a rectangle because one of its angles is a right angle.

Therefore the correct option is b.

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Step-by-step explanation:

Use Pythagorean theorem to find the base of the right triangle

221^2 = 195^2 + b^2

b = 104 km

triangle area = 1/2 base * height =  1/2 * 104 * 195 = 10140 km^2

Now multiply by the height to find volume

10140 km^2  * 15 km  = 152100 km^3

The surface area of the rectangular prism is 88 square inches.

Given that:

Length, L = 6 inches

Width, W = 2 inches

Height, H = 4 inches

Let the prism with a length of L, a width of W, and a height of H. Then the surface area of the prism is given as

SA = 2(LW + WH + HL)

SA = 2(6 x 2 + 2 x 4 + 4 x 6)

SA = 2 (12 + 8 + 24)

SA = 2 x 44

SA = 88 square inches

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The kinetic energy of the charged particle after time 't' seconds in a uniform electric field E, neglecting the effect of gravity, is given by the equation KE = (1/2)qEt²/m.

When a charged particle is released from rest in a uniform electric field, it experiences an acceleration due to the electric force acting on it. The equation of motion for the particle in this case is given by Newton's second law, F = ma, where F is the net force on the particle, m is its mass, and a is its acceleration.

In this scenario, the only force acting on the particle is the electric force, given by F = qE, where q is the charge of the particle and E is the electric field strength. Since the particle is released from rest, its initial velocity is zero, and the displacement is given by s = (1/2)at², where s is the distance traveled by the particle and t is the time.

The work done on the particle by the electric force is equal to the change in its kinetic energy. Since the work done is given by the formula W = Fs, and the force F is constant, we have W = qEs. The change in kinetic energy (KE) is equal to the work done, so KE = qEs.

Substituting the expression for displacement, s, we get KE = qE((1/2)at²). Since a = F/m and F = qE, we have a = qE/m. Thus, the equation for kinetic energy becomes KE = (1/2)qEt²/m.

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Answer:

The solution is n=1

Step-by-step explanation:

I hope you mean

4/5n-3/5=1/5n

if so then here's the solution

5n×4/5n-3/5×5n=1/5n×5n

4-3n=1

4-1=3n

3n=3

n=1

The probability is 110/512, which is approximately 0.215, or 21.5% (rounded to one decimal place).

None of the given options match this calculation.

To find the probability that a survey participant chosen at random lives on campus and has a GPA of 2.5 or greater, we need to divide the number of students who live on campus and have a GPA of 2.5 or greater by the total number of students surveyed.

From the given information, we know that:

The total number of students surveyed is 512.

Out of the 512 students surveyed, 279 live on campus.

Among the students who live on campus, 110 have a GPA of 2.5 or greater.

Therefore, the probability can be calculated as follows:

Probability = (Number of students who live on campus and have a GPA of 2.5 or greater) / (Total number of students surveyed)

Probability = 110 / 512

So, the probability is 110/512, which is approximately 0.215, or 21.5% (rounded to one decimal place).

None of the given options match this calculation.

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The integral: S1 0 (-x³ - 2x² - x + 3)dx is -1/12

An integral is a mathematical operation that calculates the area under a curve or the value of a function at a specific point. It is denoted by the symbol ∫ and is used in calculus to find the total amount of change over an interval.

To evaluate the integral:

\($ \int_0^1 (-x^3 - 2x^2 - x + 3)dx $\)

We can integrate each term of the polynomial separately using the power rule of integration, which states that:

\($ \int x^n dx = \frac{x^{n+1}}{n+1} + C $\)

where C is the constant of integration.

So, we have:

\($ \int_0^1 (-x^3 - 2x^2 - x + 3)dx = \left[-\frac{x^4}{4} - \frac{2x^3}{3} - \frac{x^2}{2} + 3x\right]_0^1 $\)

Now we can substitute the upper limit of integration (1) into the expression, and then subtract the result of substituting the lower limit of integration (0):

\($ \left[-\frac{1^4}{4} - \frac{2(1^3)}{3} - \frac{1^2}{2} + 3(1)\right] - \left[-\frac{0^4}{4} - \frac{2(0^3)}{3} - \frac{0^2}{2} + 3(0)\right] $\)

Simplifying:

\($ = \left[-\frac{1}{4} - \frac{2}{3} - \frac{1}{2} + 3\right] - \left[0\right] $\)

\($ = -\frac{1}{12} $\)

Therefore,

\($ \int_0^1 (-x^3 - 2x^2 - x + 3)dx = -\frac{1}{12} $\)

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The value of the Z-transform at z=3.51 is -3.846.

The definition of the Z-transform for a discrete-time signal x[n] is given by:

\(X(z) = Z{x[n]} = Sum$ {n} =-\infty $ to \infty} (x[n] \times z^{(-n)} )\)

where z is a complex variable.

Using this definition, let's find the Z-transform of the sequence -anu[-n-1]:

\(X(z) = Sum{n=-\infty $ to \infty}(-anu[-n-1] \times z^{(-n)} )\)

\(= Sum{n= 0 $ to $ \infty} (-a\times (n-1)z^{(-n)})\)

\(= -a(z^{(-1)} + 2z^{(-2)} + 3z^{(-3)} + ...)\)

where u[n] is the unit step function, defined as u[n]=1 for n>=0 and u[n]=0 for n<0.

The region of convergence (ROC) for the Z-transform is the set of values of z for which the series converges.

In this case, the series converges for |z| > 0.

Therefore, the ROC is the entire complex plane except for z=0.

Now, let's evaluate X(z) at z=3.51:

\(X(3.51) = -9.49\times (3.51^{(-1)} + 23.51^{(-2)} + 33.51^{(-3)} + ...)\)

\(= -9.49\times (0.2845 + 0.0908 + 0.0289 + ...)\)

\(= -9.49\times (0.4042 + ...)\)

= -3.846.

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The value of the z-transform when z=3.51 is 3.778.

The z-transform is a useful tool in digital signal processing for analyzing and manipulating discrete-time signals.

To find the z-transform of the sequence -anu[-n-1], we can use the definition of the z-transform:

X(z) = ∑n=−∞^∞ x[n]z^-n

where x[n] is the input sequence and X(z) is its z-transform. In this case, the input sequence is -anu[-n-1], where a=9.49 and u[n] is the unit step function.

Substituting the input sequence into the z-transform equation, we get:

X(z) = ∑n=−∞^∞ (-a*u[-n-1])z^-n

We can simplify this expression by changing the limits of the summation and substituting -n-1 with k:

X(z) = ∑k=1^∞ (-a)z^(k-1)

= -a ∑k=0^∞ z^k

= -a/(1-z)

The region of convergence (ROC) for the z-transform is the set of values of z for which the series converges. In this case, the ROC is the exterior of a circle centered at the origin with a radius of 1. This is because the series converges for values of z outside the unit circle, but diverges for values inside the unit circle.

To find the value of the z-transform when z=3.51, we can substitute z=3.51 into the expression for X(z):

X(3.51) = -a/(1-3.51) = -9.49/-2.51 = 3.778

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The sample is the randomly selected customers (Option B).

What is sample?

Now, according to the question, a survey is passed to the customers.

Here, the sample is the customers.

Hence, the sample is customers and the correct choice of options is (C).

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Answer:

randomly selected customers n

Step-by-step explanation:

plato 022

The innovation that was made possible in part because of the Carterfone decision in 1968 is the public Internet. The correct answer is option C

The Carterfone decision was a landmark ruling by the Federal Communications Commission (FCC) that allowed for the interconnection of third-party devices to the telephone network. Prior to this decision, telephone companies had a monopoly on the equipment that could be used on their networks, and customers were not allowed to attach their own devices.

This decision paved the way for the development of the public Internet by allowing for the interconnection of third-party devices to the telephone network, which enabled the creation of new technologies, such as modems. Without the Carterfone decision, the public Internet as we know it today may not have been possible.

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Answer:

Equal

Step-by-step explanation:

3 tens can be left alone. 30 ones will be rounded to 3 tens since 10 ones = 1 ten so there for they are equal.

Answer:

3Y=3/4X +6

Step-by-step explanation:

3Y=3/4X +6 is parallel to Y=1/4X-3

Answer:

son2: 5

son1: 10

Step-by-step explanation:

2x (son1) + x (son2) + 35 (mother) + 3 (years)*3 (people) = 59

3x = 15

x = 5

The age of each boy at present will be 2 years and 3 years.

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Let the age of the sons will be x and y.

A mother who is 35 years old has two sons, one of whom is twice as old as the other. Then the equation will be

x = 2y

In 3 years, the sum of all their ages will be 59 years. Then the equation will be

x + y + x + 1 + y + 1 + x + 2 + y + 2 + 35 = 59

Simplify the equation, we have

3x + 3y + 41 = 59

      6y + 3y = 59 – 41

              9y = 18

                y = 2

Then the value of x will be

x = 2y

x = 2(2)

x = 4

Thus, the age of each boy at present will be 2 years and 3 years.

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The is used as a measure of to overcome the range is influenced too much by .

?

are then selected as 3 points such that

they create four groups in the data, each groups approximately possessing 25% of the data.

(inter quartile range) is defined as the between third and first quartile.

Since, range is used as a measure of to overcome the difficult of the range.

The interquartile range can be affected by , so the IQR (interquartile range) is used as a better of the range.

Hence, The interquartile range is used as a measure of variability to overcome the range is influenced too much by

Learn more about here:

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#

The interquartile range is used to overcome the difficulty of range as a measure of variability which is affected by outliers.

The range is a measure of variability which is determined by calculating the difference between the highest and lowest values in a dataset. However, this measure of variability can be affected by outliers - values that are unusually high or low. For example, if a dataset includes one value that is much higher than the rest, then the range will be much higher than it would be without the outlier. The interquartile range is used to overcome this difficulty by ignoring the outliers when calculating the range. It is calculated by dividing the data into quartiles and then subtracting the lower quartile from the upper quartile. This gives a more reliable measure of variability as it ignores the outliers and is not affected by them.

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Answer:

Step-by-step explanation:

side NO=x

49/16=x/27

1323/16=x

x=82.7

Answer:

The pool holds 660,000 gallons of water.

Step-by-step explanation:

63/100 = 415,800/x

cross multiply so 415,000 * 100 = 41,500,000

41,500,000 / 63 = 660,000

Answer:

25

Step-by-step explanation:

25

Answer: how many more means subtract so subtract and it will be 25 LLaps

Answer:

B, 2I + 3 = 39

Step-by-step explanation:

work backwards first, so 39 minus 3 is 36, divided by two is 13.

Answer:

Hi, I know you won’t see this til morning but I have a random question I want to ask you whenever you wake up lol

Goodnight

Step-by-step explanation:

Answer:

349r49

Step-by-step explanation:

hey its vikki this is my new acct

\(8^{3} \cdot 8^{-7} =8^{-4}=\boxed{\frac{1}{8^4}}\)

10/75=13.333333334 so around 66 people

you can also just divide 500 by 75 then take it times 10 :)

The distance from (x, y) to (1, -3) is at least 13.

To prove that the distance from (x, y) to (1, -3) is at least 13, we will use the distance formula between two points in a coordinate plane. Let's denote the distance as d.

The distance formula between two points (x1, y1) and (x2, y2) is given by:

d = √[(x2 - x1)^2 + (y2 - y1)^2]

In this case, we have the points (x, y) and (1, -3), so we can substitute the coordinates into the distance formula:

d = √[(1 - x)^2 + (-3 - y)^2]

Now, we need to prove that the distance is at least 13.

Given the conditions x ≤ -11 and y ≥ 2, we can make some observations:

If x ≤ -11, then (1 - x) ≥ 12, since subtracting a negative number gives a positive value.

If y ≥ 2, then (-3 - y) ≤ -5, since subtracting a positive number gives a negative value.

Substituting these observations into the distance formula:

d = √[(1 - x)^2 + (-3 - y)^2]

≥ √[12^2 + (-5)^2]

= √[144 + 25]

= √169

= 13

Therefore, we have shown that the distance from (x, y) to (1, -3) is at least 13.

The proof demonstrates that for any real numbers x and y satisfying x ≤ -11 and y ≥ 2, the distance from the point (x, y) to the point (1, -3) is at least 13.

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Answer: -5/3

Step-by-step explanation:

Answer: m = -4/3

Step-by-step explanation:

If you're given two different coordinates, and you want to find the slope, the general rule is that you subtract the first coordinates from the first. The formula for these kinds of problems is \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\) .

The critical point of f at z = 1 is a local minimum.

To find the critical points of the function f(z, 3) = 4z^2 - 8z + 1, we need to find the values of z where the first partial derivatives with respect to z are equal to zero. Let's solve it step by step.

Take the partial derivative of f with respect to z:

∂f/∂z = 8z - 8

Set the derivative equal to zero and solve for z:

8z - 8 = 0

8z = 8

z = 1

The critical point of f occurs when z = 1.

To determine whether the critical point is a local minimum, local maximum, or a saddle point, we can use the second partial derivative test. We need to calculate the second partial derivative ∂²f/∂z² and evaluate it at the critical point (z = 1).

Taking the second partial derivative of f with respect to z:

∂²f/∂z² = 8

Evaluate the second derivative at the critical point:

∂²f/∂z² at z = 1 is 8.

Analyzing the second derivative:

Since the second derivative ∂²f/∂z² = 8 is positive, the critical point (z = 1) corresponds to a local minimum.

Therefore, the critical point of f at z = 1 is a local minimum.

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Answer:

shift the graph up 1 unit

Step-by-step explanation:

d is the vertical shift

+1 means we shift the graph up 1 unit

Answer:

The first one, the opposite of any negative number is the same number but positive...and vise versa.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

im doing the test rn

Answer:

3^x -1

hopefully i helped :)

Answer:

x=0

Step by step explanation:

cos (a+b) = cos(a) cos(b) -sin (a) sin (b)

Same identity forms in question.

L.H.S -cos (x+60)

Now write it in the form of sin .

sin [90-(60+x)]

Equal to RHS

R.H.S - 30

90-(60+x)=30

30-x=30

x=0

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The answer to the equation cos195°cos285° is -1/4.

An equation is a mathematical statement that asserts the equality of two expressions. Equations are used to describe relationships between different quantities and can be used to solve for unknown values. Equations are typically written as symbols, but can also be written in words. Simple equations might involve addition, subtraction, multiplication, and division, while more complex equations may involve exponents, logarithms, and trigonometric functions. Equations can be used to model and understand real-world phenomena, such as calculating projectile motion, or predicting the behavior of a chemical reaction.

This is derived from the trigonometric identity cos{60°−x}cosx – sin(60°−x)sinx. This identity states that the cosine of the sum of two angles is equal to the product of the cosines of each angle minus the product of the sines of each angle.

By substituting the angles 195° and 285° into the identity, we get cos{60°−195°}cos195° – sin(60°−195°)sinx. When we use the values of the angles, we get cos{-135°}cos195° – sin(135°)sinx. We can then simplify this to -1/4cos195° – 0sinx. As the sine of the angle is 0, this simplifies to –1/4cos195°. As the cosine of 195° is -1/4, the answer to the equation cos195°cos285° is -1/4.

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Population will be 43,160 in 76 years if a town doubles its size every 38 years if the current population is 6,790.

Since the town doubles in size every 38 years, we can use the formula:

P = P0 * 2^(t/T)

where P0 is the initial population, P is the population after time t, and T is the doubling time (38 years in this case).

We know that the current population is P0 = 6,790, and we want to find the population in 76 years, which is t = 76. Plugging these values into the formula, we get:

P = 6,790 * 2^(76/38)

P = 6,790 * 2^2

P = 6,790 * 4

P = 27,160

Therefore, the population of the town will be 27,160 in 76 years.

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