ssignment Score: 95.1% Resources Hint Check Answer mestion 30 of 31 > Match each characteristic to the planet it describes. Jupiter Saturn Uranus Neptune Answer Bank largest planet first planet discovered with a telescope least spherical has a me with a dense nitrogen atmosphere most highly inclined rotation artis the four Galilean mcm orbit this planet strongest magnetic field most conspicuous rings has the largest con in the Solar System has the medium sized moon Triton in orbit

Answer:

cause they give u milk

Explanation:

Answer:

Cows are important as they provide humans many things for survival. They provide milk, meat, and leather, all of these are important resources.

Therefore, the answer is (a) 1292 cm is stick has a shadow when held vertical.

Additionally, since light moves in a straight path from its source to an object, the shadow of the object moves with the light source.

Let's use h centimetres to represent the tree's height. We have the following percentage in the problem:

height of tree/length of its shadow = height of meter stick/length of its shadow

or

h / 4200 = 100 / 325

We can solve this proportion for h:

h = 4200 * 100 / 325 = 1292.31 cm

Rounding to the nearest centimeter, we get:

h ≈ 1292 cm

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Answer:

THEY WILL REPEL

Explanation:

THEY'LL MOVE IN OPPOSITE DIRECTIONS

15.8m/s is the final velocity

Deceleration is calculated by dividing the final velocity minus the initial velocity by the time it takes for this velocity to drop. Here the acceleration formula can be used with a negative sign to determine the deceleration value.

The rate of change of the velocity of an object in the time is known as Acceleration . Velocity is defined as the speed of an object in motion by time.

here we know that the initial velocity is 32m/s.

the deceleration is -1.5m/s2 and the time taken is 10.8s

so from the formula

                                       V=U + at

  = 32+-1.5 x10.8

  =15.8m/s          

So the final velocity is 15.8m/s

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The distance the ball was thrown is 52.22m by A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later.

Every motion under constant acceleration is projectile motion

Angle above horizontal Ф = 35°, initial speed v1 = 25m/s , time 2.55s

Substituting value in the below equation

x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²

a= 0 as acceleration in horizontal direction is zero

x= 25*cos(35)*2.55

x=52.22 m

Projectile motion is a form of motion in which object influenced when it is launched into the gravitational force from the surface of Earth along a curved path.

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Apply ohms law

\(\\ \rm\hookrightarrow R=\dfrac{V}{I}\)

\(\\ \rm\hookrightarrow R=\dfrac{5}{25\times 10^{-3}}\)

\(\\ \rm\hookrightarrow R=0.2\times 10^{-3}\)

\(\\ \rm\hookrightarrow R=0.0002\Omega\)

Electrical power can be defined as the product of Voltage and current. Thus, P = IV. Hence, Option D is the correct answer.

Thus, the formula for electric power,

P = IV watt

Where,

P - Power (Watt)

I - Current (Ampere)

V - Voltage (volts)

Electrical power can be defined as the product of Voltage and current. Thus, P = IV. Hence, Option D is the correct answer.

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Weight is best defined as C) the force of gravity on an object.

The change in surface area of Gaussian surface with radius (r) is 8πr.

The electric field experienced by a charge is calculated as follows;

\(E = \frac{Q}{4\pi \varepsilon_o r^2}\)

where;

The electric field reduces by a factor of \(\frac{1}{r^2}\)

The surface area of a sphere is given as;

\(A = 4\pi r^2\)

\(\frac{dA}{dr} = 8\pi r\)

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

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At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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In the large toy car, the acceleration is less as compared to the small toy car which are having greater acceleration. Therefore, the same force experiences by both the toy cars during the collision.

In collision, the change in momentum is same for both the toy cars. Hence, the force exerted on both the cars is same during the collision.

Answer: Mount Nevado Huascarán

Explanation: Mount Nevado Huascarán in Peru has the lowest gravitational acceleration, at 9.7639 m/s2, while the highest is at the surface of the Arctic Ocean, at 9.8337 m/s2

The speed of how fast the birdman should be to hit the bucket is 18.8 m/s

The only force acting on the height at which birdman flies is the gravitational force field.

Suppose the initial velocity (u) is parallel to the ground when the time (t) hits the ground.

Then, we can use the second equation of motion to determine the time (t) when the bird hits the ground.

\(\mathbf{S = ut + \dfrac{1}{2}gt^2}\)

\(\mathbf{78 \ m =(0)t + \dfrac{1}{2}(9.8)t^2}\)

\(\mathbf{78 \ m =4.9 t^2}\)

\(\mathbf{t^2 = \dfrac{78 \ m}{4.9 m/s^2} }\)

\(\mathbf{t^2 = 15.918 \ s^2}\)

\(\mathbf{t =\sqrt{ 15.918 \ s}}\)

\(\mathbf{t =3.989\ s}}\)

Now, the speed of how fast the birdman should be to hit the bucket can be determined using;

\(\mathbf{Speed = \dfrac{Distance}{Time}}\)

\(\mathbf{Speed = \dfrac{75 \ m }{3.989\ s}}\)

\(\mathbf{Speed = 18.8 m/s}\)

Therefore, we can conclude that the speed of how fast the birdman should be to hit the bucket is 18.8 m/s

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Answer:answers A

Explanation:

i) The focal length of the lens can be determined using the lens formula:

1/f = 1/v - 1/u

Where:

f = focal length of the lens

v = image distance from the optical center of the lens (positive for real image)

u = object distance from the optical center of the lens (positive for object on the same side as the incident light)

Given:

Image distance (v) = 60 cm

Object distance (u) = ?

Magnification (m) = -4 (negative because the image is real and inverted)

The magnification is given by the formula:

m = -v/u

Substituting the given values, we have:

-4 = -60/u

Simplifying the equation, we find:

u = 15 cm

Now we can substitute the values of u and v into the lens formula:

1/f = 1/60 - 1/15

Simplifying the equation, we get:

1/f = (1 - 4)/60

1/f = -3/60

1/f = -1/20

Taking the reciprocal of both sides, we find:

f = -20 cm

ii) The distance between the object and its image when they have the same size can be found using the magnification formula:

m = -v/u

Given:

Magnification (m) = 1 (since the object and image are of the same size)

Image distance (v) = ?

Object distance (u) = ?

Substituting the values into the magnification formula, we have:

1 = -v/u

Since the magnification is positive, the image is virtual and upright. Therefore, the image distance (v) is negative.

We know from part (i) that the object distance (u) is 15 cm. Substituting these values into the equation, we find:

1 = -v/15

Rearranging the equation, we have:

v = -15 cm

Therefore, the distance between the object and its image when they have the same size is 15 cm.

To know more about the i) The focal length of the lens can be determined using the lens formula:

1/f = 1/v - 1/u

Where:

f = focal length of the lens

v = image distance from the optical center of the lens (positive for real image)

u = object distance from the optical center of the lens (positive for object on the same side as the incident light)

Given:

Image distance (v) = 60 cm

Object distance (u) = ?

Magnification (m) = -4 (negative because the image is real and inverted)

The magnification is given by the formula:

m = -v/u

Substituting the given values, we have:

-4 = -60/u

Simplifying the equation, we find:

u = 15 cm

Now we can substitute the values of u and v into the lens formula:

1/f = 1/60 - 1/15

Simplifying the equation, we get:

1/f = (1 - 4)/60

1/f = -3/60

1/f = -1/20

Taking the reciprocal of both sides, we find:

f = -20 cm

ii) The distance between the object and its image when they have the same size can be found using the magnification formula:

m = -v/u

Given:

Magnification (m) = 1 (since the object and image are of the same size)

Image distance (v) = ?

Object distance (u) = ?

Substituting the values into the magnification formula, we have:

1 = -v/u

Since the magnification is positive, the image is virtual and upright. Therefore, the image distance (v) is negative.

We know from part (i) that the object distance (u) is 15 cm. Substituting these values into the equation, we find:

1 = -v/15

Rearranging the equation, we have:

v = -15 cm

Therefore, the distance between the object and its image when they have the same size is 15 cm.

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Answer:

Play tennis, nothing can train you better for the sport than the sport itself. However, tennis is one of those unique sports that combine nearly all components of fitness including power, agility, speed, flexibility, reaction time, balance, coordination, cardiovascular endurance and muscular endurance.

Explanation:

a) The main advantages of an epicyclic gearbox are:

b) i) Using the formula for the gear ratio of an epicyclic gear train:

T4/T3 = (t2/t1) x (t5/t2) x (t4/t5)

T4/30 = (1/2) x (60/20) x (40/60)

T4 = 40 Nm

ii) From the law of gearing for an epicyclic gear train:

w21 = (t3/t2) x (t5/t4) x w31 - (t3/t2) x w2

Substituting the given values:

w21 = (30/20) x (60/40) x 200 - (30/20) x 100

w21 = 150 rad/s

iii) The fixing couple that must be applied to wheel 5 can be found from the power transmitted by the gear train:

P = w3 x T3 = w2 x T2 = w1 x T1

Substituting the given values:

9 kW = 200 rad/s x 30 Nm = w2 x T2 = w2 x 20 Nm

w2 = 450 rad/s

T2 = (9 kW) / (450 rad/s) = 20 Nm

The fixing couple that must be applied to wheel 5 is equal in magnitude and opposite in direction to T2, so it is -20 Nm.

iv) The tangential force at the pitch point between wheels 3 and 4 can be found from the formula:

Ft = (2 x Pd) / (m x z3)

where Pd is the diametral pitch, m is the module, and z3 is the number of teeth on wheel 3.

Substituting the given values:

Pd = 25.4 / 5 = 5.08 teeth/inch

z3 = t3 / m = 30 / 5 = 6 teeth

Ft = (2 x 5.08) / (5 x 6) = 0.846 N

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The size of the smallest human feature that can be seen is  1.28 * 10^-4 m.

We know that ultrasound is used in the observation of the human tissues. In most cases, the ultrasound can be used to "see" the fetus that is still in the womb in addition to a lot of other things that the ultra sound can be used to do in the human system.

Given that;

v = λf

v = speed of the wave

λ = wavelength of the wave

f = frequency of the wave

Thus;

λ = v/f

λ = 1540/12 * 10^6 Hz

λ = 1.28 * 10^-4 m

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Sentences 20, 21, 22, and 23 can be completed as follows:

20. B. Ultraviolet is used to observe star birth and far away galaxies.

21.  D. Radio waves is used to observe the depths of the Milky Way galaxy.

22. C. Gamma rays are used to observe supernova explosions and radioactive decay.

23. C. Wernher von Braun developed the V-2 rocket.

Rays are beams of light and radiation that can be harmful when used wrongly or advantageous for scientific purposes.

As scientists study extraterrestrial bodies, they often have to use rays for their findings. Gamma rays are known for their use in observing supernova explosions. Also, Wernher Braun is attributed to the development of the V-2 rocket.

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Answer:

average velocity = \(\bf 900 \space\ km/h\)

Explanation:

We can find the average velocity using the following equation:

\(\boxed{average \space\ velocity = \frac{total \space\ distance \space\ travelled}{ \space\ time \space\ taken}}\) .

In this case:

• total distance travelled = 450 km

• time taken = 30 min = 0.5 h

Substituting these values into the equation:

\(average \space\ velocity = \frac{450 \space\ km }{ 0.5 \space\ h}\)

                          ⇒ \(\bf 900 \space\ km/h\)

Answer:

due to inertia of motion

Answer:

The maximum speed of the stone without breaking the rope is 4.33 m/s.

Explanation:

Given;

maximum tension the rope can withstand, T = 75 N

mass of the rock, m = 6 kg

radius of the circle, r = 1.5 m

As the stone spin in a vertical circle, it performs circular motion with centripetal acceleration directed inwards. The maximum centripetal force during this motion will be equal to maximum tension on the rope.

\(F_c,_m_a_x = T = \frac{MV_m_a_x^{2} }{r}\\\\V_m_a_x^{2} = \frac{Tr}{M}\\\\V_m_a_x = \sqrt{\frac{75*1.5}{6}}\\\\V_m_a_x = 4.33 \ m/s\)

Therefore, the maximum speed of the stone without breaking the rope is 4.33 m/s.

We can confirm that the clothes are sticking together due to static forces created by the heat and friction of the dryer.

The clothes are stuck together due to static forces that arise when these materials are heated and the friction from the dryer cycle. Adding a light spray of water can help with this situation given that water is a strong conductor of electricity, which will help to dispel the charges that hold the clothes together.

Therefore, we can confirm that clothes are sticking together due to static forces created by the heat and friction of the dryer, which a light spray of water can help to dispel and separate the clothes.

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Here according to the momentum of both balls before and after collision is constant. Therefore, the angle of bouncing after collision will be   20.77°.

The momentum of an object is the product of its mass and velocity. During collision between two objects, the total momentum is conserved .

Given, mass of cue ball = 0.6 kg

velocity = 2 m/s

initial momentum of the eight balls is zero since they were at rest.

then total initial momentum = 0.6 kg × 2 m/s = 1.2 kg m/s.

Final velocity of both balls = 0.8 m/s

then,

1.2 kg m/s = (0.8 m/s cos 20 × 0.6 kg ) + (0.8 m/s cos θ × 0.6 kg )

(0.8 m/s cos θ × 0.6 kg )  = 0.449 kg m/s

cos θ = 0.935

then θ = 20.77°.

Therefore, the angle at which the eight ball travel after collision is 20.77°.

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Answer:

1470J

Explanation:

Given parameters:

Height of stairs  = 2.5m

Time taken  = 4.25s

Mass of Bart  = 60kg

Unknown:

Work done by Bart  = ?

Solution:

Work done is a function of the force acting to move a body through a distance.

    Work done  = Weight  x height

  Work done  = mass x acceleration due to gravity x height

Work done  = 60 x 9.8 x 2.5  = 1470J

Answer:

The stars at the center bulge are bigger and brighter than the stars in the arms.

Explanation:

The difference between the stars at the center bulge and the stars in the arms is that the stars at the center bulge are bigger and brighter than the stars in the arms.

A collection of the stars, gases and dust is known as a galaxy.

The Milky Way is a galaxy to which our solar system belongs.

Also, The shape of the milky way is spiral.

There are stars located in the center bulge of the Milky Way and the spiral arms of the Milky Way.

It is known that in a galaxy which has a spiral shape, the gases, dust, and stars are organized in such a way that they form a bulge or a disk in the center with spiral arms surrounding it.

Therefore, the structure of the milky way is best described by the statement a core with spiral arms.

The difference between the stars at the center bulge and the stars in the arms is that the stars at the center bulge are bigger and brighter than the stars in the arms.

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Answer and Explaination:

To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.

1. Gravitational force:

The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.

2. Force exerted by the spring:

The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Given:

Mass (m) = 5.0 kg

Compression of the spring (x) = 20.0 cm = 0.20 m

Angle of the inclined plane (θ) = 30°

First, let's find the force exerted by the spring (F_spring):

F_spring = -kx

To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.

Next, let's calculate the gravitational force components:

Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ

Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ

Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.

At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).

Therefore, we have:

F_perpendicular = F_spring

mg * cosθ = -kx

Now, let's substitute the known values and solve for k:

(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m

49.0 N * 0.866 = -k * 0.20 m

42.426 N = -0.20 k

k = -42.426 N / (-0.20 m)

k = 212.13 N/m

Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:

PE_spring = (1/2) * k * x^2

PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2

PE_spring = 4.243 J

The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.

KE_max = PE_spring = 4.243 J

Next, we can calculate the height (h) the mass reaches on the inclined plane:

KE_max = m * g * h

4.243 J = 5.0 kg * 9.8 m/s^2 * h

h = 4.243 J / (5.0 kg * 9.8 m/s^2)

h = 0.086 m

The height the mass reaches on the inclined plane is 0.086 m.

Now, we can calculate the distance traveled.

A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.

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1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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