Option B. feelings of i A child's worry caused by a stranger is known as "stranger anxiety."
Answer. Strangers or strange environments are frequently what cause stranger anxiety. Therefore, given that the setting is familiar and there is no perceived threat from outsiders, it is less likely to emerge in a multiple-choice context.
When a stranger approaches, sobbing is a sign of stranger anxiety. It is typical when it begins at around 8 to 9 months of age and typically goes away by age 2. The infant's developmental process of separating the familiar from the unknown is linked to stranger dread. A infant has separation anxiety when they are separated from the person who loves them the most, usually their mother. When: Stranger anxiety
To learn more about stranger anxiety please click on below link
https://brainly.com/question/28317804
#SPJ4
What types of galaxies are these?
Answer:
the first one looks like a spiral galixy
the 2nd one looks like a lenticular galixy ?? (im pretty sure but not 100%)
the 3rd one looks like a elliptical galixy
Explanation:
Answer:
1. Spiral
2. Not sure but i think its irregular.
3. Elliptical
Please Vote Me Brainliest. Thank You.
The image produced by a concave lens is always virtual. Is this true or false?
A medieval instrument used to determine the position of the sun:
Answer: astrolabe
Explanation:
Use the generating function for the associated Laguerre
polynomials to find all six of those that are generated from ₁,
₂, and ₃.
To find the associated Laguerre polynomials generated from ₁, ₂, and ₃, we can use the generating function for the associated Laguerre polynomials. The generating function is given by:
\(G(t, x) = (1 - t)^(-x - 1) * exp(-t) / (1 - t)^x\)
To find the polynomials, we substitute the values of ₁, ₂, and ₃ into the generating function and expand the resulting expression. The coefficients of the expanded terms will give us the associated Laguerre polynomials.
For example:
For ₁, substitute t = x into the generating function and expand to get the associated Laguerre polynomial L₀.
For ₂, substitute t = x into the generating function and expand to get the associated Laguerre polynomial L₁.
For ₃, substitute t = x into the generating function and expand to get the associated Laguerre polynomial L₂.
Repeat the process for the remaining values to obtain the other associated Laguerre polynomials.
Note: The associated Laguerre polynomials are a family of orthogonal polynomials used in various mathematical and physical applications.
To know more about Laguerre refer here:
https://brainly.com/question/33067520#
#SPJ11
The brakes on a car do 110,095J of work as they apply an average force of 8,450N. How far in meters does the car continue before stopping
13.02 meters
Explanation
the work done by the brakes makes the car stops, so the change in energy equals the work done
hence
\(\text{work}=\Delta Ek=\frac{1}{2}mv^2\)also, the work done by a force is given by
\(\text{work}=\text{ force}\cdot dis\tan ce\)then, let
\(\begin{gathered} \text{work}=\text{ 110095 J} \\ \text{Force}=8450\text{ N} \end{gathered}\)replace
\(\begin{gathered} \text{work}=\text{ force}\cdot dis\tan ce \\ 110095\text{ J=8450 N}\cdot distnace \\ \text{divide both sides by 8450 N} \\ \frac{110095\text{ J}}{\text{8450 N}}\text{=}\frac{\text{8450 N}\cdot}{\text{8450 N}}distance \\ 13.02m=\text{distance} \end{gathered}\)therefore, the answer is
13.02 meters
I hope this helps you
Name the following.A subatomic particle that carries a negative charge.
An electron is a subatomic particle that carries a negative charge.
An electron is a subatomic particle that carries a negative electric charge. It is one of the three main subatomic particles that make up an atom, along with protons and neutrons. Electrons have a very small mass compared to protons and neutrons, and are found outside the nucleus of an atom, in the electron cloud or electron shell. The number of electrons in an atom is equal to the number of protons in the nucleus, which means that atoms are electrically neutral.
The behavior of electrons is described by quantum mechanics, and it is responsible for the chemical properties of an atom. The electrons are arranged in energy levels or orbitals around the nucleus. The outermost energy level is called the valence shell, and the number of electrons in this level determines the chemical reactivity of the atom.
In chemical reactions, electrons can be transferred from one atom to another, forming chemical bonds. This is the basis for the formation of molecules and compounds. The movement of electrons also gives rise to electrical phenomena such as electric current and magnetism.
Learn more about subatomic particles here: brainly.com/question/29765133?
#SPJ4
Complete question:
The subatomic particle that carries negative charge
A. Electron
B. Proton
C. Neutron
D. None of these
What is benford's law.
Answer:
Known variously as the Newcomb–Benford law, the law of anomalous numbers, or the first-digit law, Benford's Law is the observation that the first digit in many real-world collections of numerical data will be tiny, as shown by the example of the first-digit law.
Explanation:
Hope it helps:)
What is 8 degrees Celsius in Fahrenheit?
8 degrees Celsius is equal to 46.4 degrees Fahrenheit when converting temperatures from degrees Celsius to Fahrenheit.
Is a refrigerator safe at 8 degrees Celsius?Between 32 degrees Centigrade and 41 degrees Fahrenheit, or 0 degrees Celcius with 5 degrees Celcius, should be the temperature of the refrigerator's coldest portion. To determine whether food has been kept warmed (above 63 degrees Celsius) or cold (below 8 degrees Celsius), you might use a probe thermometer.
How cold can a person tolerate?The most susceptible body parts to frostbite are the fingertips, nose, ears, toes, cheeks, and chin, so use as much protection as you can. How cold is too cold? When the windchill drops below 0 degrees Celsius or the temperature drops below zero, experts generally advise staying inside.
To know more about Celsius visit :
https://brainly.com/question/14767047
#SPJ4
A 5.0 kg objects suspended on a spring oscillates such that its position x a function of time t is given by the equation x(t) = Acos(ωt), where A = 0.80 m and ω = 2.0 rad/s. What is the magnitude of the maximum net force on the object during the motion?
The 5.0 kg object suspended on a spring oscillates such that its position x a function of time t is given by the equation x(t) = Acos(ωt), where A = 0.80 m and ω = 2.0 rad/s. The magnitude of the maximum net force on the object is 19.6 N.
The formula for the net force acting on an object undergoing simple harmonic motion is F_net = -kx, where k is the spring constant and x is the displacement from the equilibrium position.
The maximum displacement in this case is A = 0.80 m.
The spring constant can be found using the formula k = mω^2, where m is the mass of the object and ω is the angular frequency.
Plugging in the given values, we get k = (5.0 kg)(2.0 rad/s)^2 = 20 N/m.
To find the maximum net force, we plug in the maximum displacement into the formula: F_net = -kx = -(20 N/m)(0.80 m) = -16 N.
However, we need the magnitude of the force, so we take the absolute value, giving us 16 N.
But since the force is changing direction, we need to double this value to get the maximum magnitude, giving us 2(16 N) = 32 N.
Therefore, the magnitude of the maximum net force on the object during the motion is 19.6 N (rounded to one significant figure).
Learn more about force here:
https://brainly.com/question/13543451
#SPJ11
Calculate the current through the resistor in the circuit shown below.
Answer:
0.6amp or I= 0.6
Explanation:
V=IR
12V=I(20)
12/20=I
0.6=I
Answer:
0.6amp
Explanation:
Explain how energy is transferred in an impact situation such as a car crash.
I PROMISE TO MARK YOU BRAINLIEST I JUST NEED A THOROUGH ANSWER!!
THANKS IN ADVANCE BESTIES
why do black holes have a large gravitational pull that even light cannot escape from
Answer:
Because matter has been squeezed into a tiny space.
Explanation:
According to NASA, this can happen when a star is dying.
A black hole has no more gravity than the same amount of matter in any other form.
But remember that the gravitational forces are stronger as you get closer to the center of the body. The mass of a black hole is packed into such a small size (theoretically zero !) that you can get very close to its center. THAT'S where its gravity is hugely strong.
all white dwarfs have masses in a small range—from about 0.5 to almost 1.4 malchemist sun symbol. why? (select all that apply.)
A white dwarf cannot support its own weight by its degenerate pressure if its mass is greater than 1.4 solar masses.
What are white dwarfs?
White dwarfs are stellar core remnant composed mostly of electron-degenerate matter.
White dwarf is very dense due to its large mass and smaller volume.
Reasons for comparable mass of white dwarfs and SunStars with main sequence masses less than about 0.5 solar masses cannot ignite the helium fusion required to become white dwarfs.A white dwarf cannot support its own weight by its degenerate pressure if its mass is greater than 1.4 solar masses.Learn more about white dwarfs here: https://brainly.com/question/24873876
#SPJ11
In a vehicle traveling at 20 miles per hour, the force of your car impacting a surface is ______ times as great as at 10 MPH. Two Four Six Twelve
At 20 miles per hour, the force of your car impacting a surface is four times as great as at 10 MPH.
Impact surface means a surface that either moves or comes in contact with a moveable surface and is subject to damage by repeated sudden force, impact, or contact, such as doors and windows with certain parts of their frames.
The term “impact surface” means an interior or exterior surface that is subject to damage by repeated impacts. an impinging or striking especially of one body against another. : a forceful contact or onset. also : the impetus communicated in or as if in such a contact. : the force of impression of one thing on another .
For such more questions on force of impact:
brainly.com/question/12912354
#SPJ11
attractive forces that are involved in this selective adsorption are the same forces that cause attractive interactions between any two molecules:
The attractive forces that are involved in selective adsorption can vary depending on the nature of the molecules and the adsorbent material. While some of the attractive forces involved in selective adsorption can be similar to the forces that cause attractive interactions between any two molecules, there can also be specific interactions that are unique to the adsorption process.
Here are some of the common attractive forces involved in selective adsorption:
1. Hydrogen bonding: Hydrogen bonding occurs when a hydrogen atom is bonded to a highly electronegative atom (such as nitrogen, oxygen, or fluorine) and forms an electrostatic interaction with another electronegative atom.
2. Electrostatic interactions: Electrostatic forces occur between charged particles or polar molecules. In selective adsorption, these interactions can play a role when the adsorbent material has a charged surface or when the adsorbing molecule has a net charge or a polar group.
To know more about attractive force:
https://brainly.com/question/14521784
#SPJ4
FILL IN THE BLANK. Accurate radiometric dating is possible only if a rock contains a measurable amount of ________.
Accurate radiometric dating is possible only if a rock contains a measurable amount of a radioactive isotope.
Radiometric dating is a method used to determine the age of rocks and other geological materials based on the decay of radioactive isotopes. Radioactive isotopes are unstable forms of elements that undergo radioactive decay, meaning they spontaneously break down over time and transform into stable isotopes or other elements.
The process of radiometric dating relies on the fact that radioactive isotopes decay at a known rate called the half-life. The half-life is the time it takes for half of the parent radioactive isotope to decay into the daughter isotope. By measuring the ratio of parent to daughter isotopes in a rock sample and knowing the half-life of the radioactive isotope, scientists can calculate the age of the rock.
To perform radiometric dating, it is crucial that the rock contains a measurable amount of the radioactive isotope. If the rock does not have any detectable amount of the radioactive isotope, it becomes challenging or impossible to accurately determine its age using radiometric dating methods.
The presence of a measurable amount of the radioactive isotope allows scientists to measure the ratio of parent to daughter isotopes and calculate the elapsed time since the rock formed or underwent a specific event, such as a volcanic eruption or the deposition of sediment.
The accuracy of radiometric dating depends on several factors, including the precision of the measurement techniques and the assumptions made about the initial concentrations of parent and daughter isotopes. Additionally, different isotopes have different half-lives, making them suitable for dating materials of different ages. Commonly used isotopes for radiometric dating include uranium-238, potassium-40, carbon-14, and many others.
To know more about radioactive isotope refer here
https://brainly.com/question/28039996#
#SPJ11
7. A 100 kg log is dragged across a horizontal siand of concrete. 7.1 Show by calculation that the weight of the log is 980 N. Use the equation w = mg in which g = 9,8 m.s-2. (Refer back to Unit 6 on page 30.)
The weight of the log is 980N
What is the Weight of an object?
The force of gravity acting on an object is its weight, which is equal to its mass times the acceleration of gravity, or w = mg. The newton is the SI unit for weight since it is a force.
The weight of a 100 kg log can be calculated using the equation w = mg,
where m is the mass of the log (100 kg) and g is the acceleration due to gravity (9.8 m/s^2).
So, w = (100 kg)(9.8 m/s^2) = 980 N.
Read more about mass and weight here:
https://brainly.com/question/1100162
#SPJ1
Compared to the nucleus 5626Fe, what is the radius of the nucleus 112 48Cd?
Compared to the nucleus , what is the radius of the nucleus ?
the same
11256=2 times as large
4826=2 times as large
2?=1.41 times as large
2?3=1.26 times as large
To determine the relative size of nuclei, you can use a simple relationship known as the "semi-empirical mass formula" or the "liquid drop model." According to this model, the radius of a nucleus is proportional to the cube root of its mass number (A).
Let's compare the nuclei:
For the nucleus 56^26Fe, the mass number (A) is 56.
For the nucleus 112^48Cd, the mass number (A) is 112.
To find the relative size of the nuclei, we can compare the cube roots of their mass numbers.
For the nucleus 56^26Fe:
Cube root of 56 = ∛56 ≈ 3.78
For the nucleus 112^48Cd:
Cube root of 112 = ∛112 ≈ 4.83
Comparing the cube roots, we find that the cube root of 112^48Cd is approximately 1.28 times larger than the cube root of 56^26Fe. Therefore, the radius of the nucleus 112^48Cd is about 1.28 times larger than the radius of the nucleus 56^26Fe.
learn more about radius here:
https://brainly.com/question/20188113
#SPJ11
a.) Using Earth's estimated cratering rate of Ncum (D > 22.6 km) = 1.8 x 10-15 craters/km2/yr, and a power law exponent b = 1.8 (see your class notes), compute the size of the largest crater likely to have formed in Sweden (area ≈ 450,000 km2) since the formation of its surface rocks ~2000 Myr ago. How does this compare to the size of the putative Uppland structure?
b.) Calculate the probability that a crater as large as Uppland would have formed in the past 2000 Myr. Note that the largest confirmed crater in Sweden is the 55 km-diameter Siljan structure
a) The size of the largest crater likely to have formed in Sweden since the formation of its surface rocks is approximately 63 km in diameter.
b) The probability that a crater as large as Uppland would have formed in the past 2000 Myr is very low, likely less than 0.01%.
a) Using the given equation N(D) = Ncum(Dref) * (D/Dref)^-b, where Dref = 22.6 km and Ncum = 1.8 x 10^-15 craters/km^2/yr, we can calculate that the expected number of craters with diameter > 63 km in Sweden since the formation of its surface rocks is approximately 0.0005.
Assuming that only one such crater would form, the maximum size of the largest crater is around 63 km in diameter.
b) The probability that a crater as large as Uppland would have formed in the past 2000 Myr can be estimated using the Poisson distribution. Based on the expected number of craters with diameter > 55 km in Sweden (0.002), the probability of at least one such crater forming in 2000 Myr is very low, likely less than 0.01%.
Therefore, the Uppland structure is likely not a meteorite impact crater.
For more questions like Probability click the link below:
https://brainly.com/question/30034780
#SPJ11
Problem Solving: Solve for the number of book stacks needed to satisfy given Reverberation Time (R.) in a closed room library. Find intensity in Decibel Scale. The library's floor area with a radius of 60 feet and 10 feet high. The library has two (2) glass doors with a dimension of 3 feet wide and 7 feet height. The absorption coefficient of the following materials (A.) are as follows: Glass at 0.025; Plywood ceiling at 0.033; Stack wood without books at 0.17; Stack of books with books at 0.40. The reverberation time is 0.05 seconds. As Floor Tile is 0.03. As for Concrete Wall is 0.04.
Required: Solve for the number of Book stack. and Take note that a Book Stack is actually a book shelves.
Hints. To Solve for the number of Book stack you will be needing these sets of formulas to decode the problem.
Formulas: R₁ = 0.049 V/A,, English system
A₁ = (Number of Book Stacks) (Maintenance Factor)
Note: Get the ratio of the A, Stack with books and A, Stack without books .This will serve as a multiplying Factor (MF).
A, Ratio Stack = A, Stack with Book / A, Stack without Book
Note: The Stack or Book Shelves is 5 feet high. Discard the Width of the Book Shelve it is open ended front till back. It only has base to carry the books. It has no partitions or shelves but it has boards that carries the individual level of books.
Approximately 47,415 book stacks are needed to satisfy the given Reverberation Time (R) in the closed room library.
To solve for the number of book stacks needed to satisfy the given Reverberation Time (R) in the closed room library, we will use the following formulas:
1. A₁ = (Number of Book Stacks) × (Maintenance Factor)
2. A, Ratio Stack = A, Stack with Books / A, Stack without Books
3. R₁ = 0.049 × (Volume of the room) / A
First, let's calculate the volume of the room:
Volume = floor area × height
Volume = π × (60 ft)^2 × 10 ft
Volume ≈ 113,097 ft³
Now, let's calculate the absorption coefficient for the different materials:
A, Stack without Books = 0.17
A, Stack with Books = 0.40
A, Ratio Stack = 0.40 / 0.17
A, Ratio Stack ≈ 2.35
Next, we can calculate the required absorption coefficient (A₁) using the reverberation time formula:
R₁ = 0.049 × Volume / A₁
Given that R₁ = 0.05 seconds, we can rearrange the formula to solve for A₁:
A₁ = 0.049 × Volume / R₁
A₁ ≈ 0.049 × 113,097 ft³ / 0.05 s
A₁ ≈ 111,288 ft²·s
Now, we can calculate the number of book stacks needed (Number of Book Stacks):
Number of Book Stacks = A₁ / (A, Ratio Stack)
Number of Book Stacks ≈ 111,288 ft²·s / 2.35
Number of Book Stacks ≈ 47,415
Therefore, approximately 47,415 book stacks are needed to satisfy the given Reverberation Time (R) in the closed room library.
To find the intensity in the decibel scale, we would need additional information such as the source power or sound pressure levels. The given information does not allow us to calculate the decibel scale intensity.
To know more about Reverberation Time visit:
https://brainly.com/question/28029112
#SPJ11
does an object in motion stay in motion
Estamos bajando dos cajas de madera con frutos menores (una encima de la otra) por una rampa con una inclinación de 30 grados con la horizontal. La caja inferior tiene una masa de 80kg y su coeficiente de fricción con el suelo es de 0.3, y la caja superior tiene una masa de 30kg con un coeficiente de fricción con la caja inferior de 0.8. Calcula la fuerza que tenemos que ejercer para que ambas cajas bajen con velocidad constante de 0.5m/s.
La situación planteada se muestra a continuación:
(El diagrama mostrado es para la caja inferior). A continuación mostramos el diagrama para la caja superior:
Si consideramos el sistema de dos cajas como uno solo tenemos el siguiente sistemas de ecuaciones:
\(\begin{gathered} F+F_f-W_x=0 \\ N-W_y=0 \end{gathered}\)De donde:
\(\begin{gathered} F=W_x-F_f \\ F=W_x-\mu N \\ F=W_x-\mu W_y \\ F=(80)(9.81)\sin 30-(0.3)(80)(9.81)\cos 30 \\ F=188.5 \end{gathered}\)Ahora debemos determinar si la caja de arriba no se resbala al aplicar esta fuerza, para esto debemos recordar que la fricción es máxima con el coeficiente de fricción estático.
Entonces tenemos que la fricción es máxima para el bloque de arriba cuando:
\(F_f=(0.8)(30)(9.81)\cos 30=203.89\)Dado que la fuerza que debemos aplicar no es mayor a la fricción máxima concluimos que ambas cajas bajaran al mismo tiempo. Por lo tanto la fuerza que debemos aplicar es de 188.5 N.
If a police car drives at a constant speed of 30 km/h, how long will it take to travel a distance of 96 km??
Answer:
3.2 hours
Explanation:
96÷30=3.2
so it should take 3.2 hours
8)
in a 4 period battle, the girls were able to overcome the in Tug-of-War. Ten boys each pulled with a force of 30 N. Six girls
were able to pull the rope toward them with a net force of 60 N. What was the minimum amount of force each of the six
giris applied to the rope?
Answer: The answer would be 10
Explanation:
(A) What is the magnitude of the net electric force on charge A in the figure? Assume that q1=0.70nC and q2=4.0nC(B) What is the direction of the net electric force on charge A?
The net electromagnetic force acting on charge A has a magnitude of 1.9 * 10⁻⁵ N and is acting in a leftward direction.
How is electric force produced?When two charges interact with one another, electrical forces are created. When there are three or so more charges present, the electric force exerted on a wireless charger is just the sum of the effects of each charge's interactions with the other charges.
(A). F = Kq1 *q1/(1cm)² - Kq1*q2/(2cm)²
F = 9 * 10⁹ * (0.7 * 10⁻⁹)²/(10⁻²)² - 9 * 10⁹ * 0.7 *4 * 10⁻¹⁸/(2*10⁻²)²
F = 4.41 * 10⁻⁵ - 6.3 * 10⁻⁵
F = -1.89 * 10⁻⁵
\(F_{A}\) = 1.9 * 10⁻⁵ N
(B). The net positive charge acting on charging A is coming from the left.
To know more about Electric force visit;
https://brainly.com/question/19817118
#SPJ4
Exam
You push on a shovel then the
shovel pushes on dirt. The force
you apply to the shovel is the
input force. The shovel then
pushing on the dirt is known as
what?
A. Output work
B. Input work
C. Input force
D. Output force
7. From the choices below, select ALL that are results of radioactive decay.
-the nuclear ejection of electrons
-nuclear fission
-radiation emission
-the nuclear capture of electrons
-nuclear fusion
please help!!!!
What are the mass and weight of a 50 kg stone on planet Earth?
Answer:
500 Newtons
Explanation:
Mass of the stone = 50 kg
Acceleration caused due to gravity on Earth (g) = 9.81 m/s^2 = 10 m/s^2
We know that,
F=ma
Hence,
W=mg
So,
The weight of the stone on Earth = 50 * 10 = 500 Newtons
You want to have a subject exercise at 125 Watts with an RPM of
60 for 3 minutes. What resistance (in SI units) do you set the
cycle ergometer to (include your units
To determine the resistance in SI units that you need to set the cycle ergometer to, given that you want to have a subject exercise at 125 watts with an RPM of 60 for 3 minutes, follow the steps below:
Step 1: Determine the energy used in Joules during the 3 minutes at 125 watts.
P = W / tWhere:
P = power (125 watts)t = time (3 minutes converted to seconds
= 3 × 60 = 180 seconds)
W = energy used in Joules (to be determined)
Substituting the given values:
P = W / t125
= W / 180W
= 125 × 180W
= 22,500 Joules
Step 2: Determine the work done (in Joules) per revolution (360 degrees).
Work done per revolution = energy used in Joules / number of revolutions per minute / 60
Where:number of revolutions per minute = RPM / 60
Substituting the given values:
Work done per revolution = 22,500 / (60 / 60) / 360
Work done per revolution = 22,500 / 1 / 360
Work done per revolution = 22,500 × 360
Work done per revolution = 8,100,000 Joules
Step 3: Determine the torque needed to perform one revolution (360 degrees) of the pedals in SI units (N-m).Torque = work done per revolution / (2 × π)
Where:
2 × π = 6.2832
Substituting the given values:Torque = 8,100,000 / 6.2832
Torque = 1,288,684.08 N-m
Step 4:
Determine the resistance (force) needed at the pedals in Newtons (N) to produce the required torque.Resistance = Torque / pedal radius
Where:pedal radius = 0.175 m (average for a cycle ergometer)
Substituting the given values:
Resistance = 1,288,684.08 / 0.175
Resistance = 7,358,971.89 N (Newtons)
Therefore, you would need to set the resistance to 7,358,971.89 N (Newtons) on the cycle ergometer to achieve the desired subject exercise at 125 Watts with an RPM of 60 for 3 minutes.
To know more about ,resistance visit;
https://brainly.com/question/17563681
#SPJ11
Which best describes reflection and refraction?
In both reflection and refraction, rays pass through a boundary.
In both reflection and refraction, rays bounce off a boundary.
In reflection, rays bounce off a boundary, and in refraction, rays pass through a boundary.
In refraction, rays bounce off a boundary, and in reflection, rays pass through a boundary.
Answer:
The correct answer is the third option
Explanation:
To reflect means to bounce off. When an incoming ray (called incident ray) gets to a boundary and bounces off the boundary, that is referred to as reflection. However, when an incident ray passes through the boundary and it causes a change in the direction of propagation of the wave, that is referred to as refraction. Thus, the correct option, as explained above, is; In reflection, rays bounce off a boundary, and in refraction, rays pass through a boundary.
Answer:
c
Explanation:
on edge 2020