The candidate that won received 80% of the 260 total votes. How many votes did the non-winning candidate receive?

PLEASE HELP I WILL GET YOU WHATEVER YOU WANT!!

Precession is a phenomenon that refers to the gradual and continuous change in the orientation of the Earth's rotational axis over long periods of time.

This shift in the orientation of the axis of rotation results in changes in the position of the celestial pole with respect to the stars, which causes a shift in the apparent position of stars over time. The precession of the Earth's axis is caused by the gravitational forces of the Sun, Moon, and other planets in the solar system.
Precession is characterized by changes in the magnitude of the angle of tilt, which causes changes in the rate of the Earth's spin. As the axis of rotation moves, it causes the length of the day to change over time. Additionally, deviations in the circularity of the orbit also affect the precession of the Earth's axis.
Precession is a significant phenomenon in astronomy and has been observed for thousands of years. It has important implications for studies of astronomy, geology, and climate change. For instance, precession affects the timing of the seasons and has a significant impact on the Earth's climate. It also affects the orientation of the Earth's magnetic field, which has important implications for navigation and communication systems.
In conclusion, precession is the gradual change in the orientation of the Earth's rotational axis, caused by the gravitational forces of the Sun, Moon, and other planets. It results in changes in the magnitude of the angle of tilt, changes in the rate of Earth's spin, and deviations in the circularity of the orbit. Precession has significant implications for various fields of study, including astronomy, geology, and climate change.

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Answer:

6.5*10^5

Step-by-step explanation:

Basically multiply 6.5 by 100000

1. The prime cost per cleaning is $249,900 / 9,000 = $27.77

2. The conversion cost per cleaning is $243,600 / 9,000 = $27.07

3. The total variable cost per cleaning is $262,500 / 9,000 = $29.17

4. The total service cost per cleaning is $276,900 / 9,000 = $30.77

5. The fixed overhead cost would increase by $900.

1. Prime cost per cleaning:

Prime cost includes direct materials and direct labor.

Prime cost = Direct materials + Direct labor

Prime cost = $18,900 + $231,000

Prime cost = $249,900

Therefore, the prime cost per cleaning is $249,900 / 9,000 = $27.77 (rounded to the nearest cent).

2. Conversion cost per cleaning:

Conversion cost includes direct labor and variable overhead.

Conversion cost = Direct labor + Variable overhead

Conversion cost = $231,000 + $12,600

Conversion cost = $243,600

Therefore, the conversion cost per cleaning is $243,600 / 9,000 = $27.07 (rounded to the nearest cent).

3. Total variable cost per cleaning:

Total variable cost includes direct materials, direct labor, and variable overhead.

Total variable cost = Direct materials + Direct labor + Variable overhead

Total variable cost = $18,900 + $231,000 + $12,600

Total variable cost = $262,500

Therefore, the total variable cost per cleaning is $262,500 / 9,000 = $29.17 (rounded to the nearest cent).

4. Total service cost per cleaning:

Total service cost includes direct materials, direct labor, variable overhead, and fixed overhead.

Total service cost = Direct materials + Direct labor + Variable overhead + Fixed overhead

Total service cost = $18,900 + $231,000 + $12,600 + $14,400

Total service cost = $276,900

Therefore, the total service cost per cleaning is $276,900 / 9,000 = $30.77 (rounded to the nearest cent).

5. If the rent on the office increased by $900, it would affect HHH's fixed overhead cost. The fixed overhead cost would increase by $900. This would lead to an increase in the total service cost per cleaning, as the fixed overhead is a component of the total service cost.

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Answer:

5\(\frac{3}{40}\)

Step-by-step explanation:

Answer: 5 3/40

explanation: did you mean a mixed fraction or nah?

Answer:

6 inches

Step-by-step explanation:

Sqrt 36 =6

The arc length of the given parametric curve is 1/2, obtained through algebraic manipulation and computation of the integral.

To find the arc length, we use the formula for arc length in parametric equations:

L = ∫[a, b] √[(dx/dt)² + (dy/dt)²] dt

In this case, the parametric equations are x = cos(t) + t*sin(t) and y = sin(t) - t*cos(t), where 0 ≤ t ≤ 1.

We differentiate x and y with respect to t to find dx/dt and dy/dt:

dx/dt = -sin(t) + sin(t) + t*cos(t) = t*cos(t)
dy/dt = cos(t) - cos(t) - t*sin(t) = -t*sin(t)

Substituting these derivatives into the arc length formula:

L = ∫[0, 1] √[(t*cos(t))² + (-t*sin(t))²] dt
  = ∫[0, 1] √[t²*cos²(t) + t²*sin²(t)] dt
  = ∫[0, 1] t dt

Integrating with respect to t:

L = [t²/2] from 0 to 1
  = 1/2

Therefore, the arc length of the given parametric curve is 1/2.

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The length of SR will be 15 units, using Pythagoras' theorem

What is Pythagoras' theorem?

The hypotenuse's square is equal to the sum of the squares of the other two sides if a triangle has a straight angle (90 degrees), according to the Pythagoras theorem. Remember that BC2 = AB2 + AC2 in the triangle ABC signifies this. Base AB, height AC, and hypotenuse BC are all used in this equation. The longest side of a right-angled triangle is its hypotenuse, it should be emphasized.

Triangle SRT and triangle TRQ can be compared using the image. Since both triangles have equal sides and right angles (T), they are both triangles (RT)

Using Pythagoras theorem,  

RQ² = TQ² + TR²

20² = TR² + 16²

TR = 12

SR/RQ = TR/TQ

SR / 20 = 12 / 16

SR = 15 units

Hence the length of SR will be 15 units.

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Answer:

x = 51.3°

Step-by-step explanation:

Hope this helped!

Answer:

Hey there!

Angela will have 7+2, or 9 cups of rice.

Let me know if this helps :)

Answer:

7/2

Step-by-step explanation:

Answer:

X-axis

Step-by-step explanation:

Maybe

The use of a 3-into-2 exhaust manifold configuration in a six-cylinder engine can better eliminate exhaust interference by strategically managing the exhaust pulses and optimizing exhaust flow.

In a six-cylinder engine, the exhaust manifolds play a crucial role in managing the flow of exhaust gases from each cylinder into the exhaust system. The primary objective of an exhaust manifold is to collect and direct the exhaust gases away from the engine cylinders.

To minimize exhaust interference in a six-cylinder engine, a commonly used configuration is a "3-into-2" exhaust manifold design. This design groups the cylinders into two sets, typically cylinders 1-3 and cylinders 4-6, and each set has its own dedicated exhaust manifold. This arrangement helps to reduce exhaust interference by separating the exhaust pulses from adjacent cylinders.

The reason for this design choice lies in the firing order of a six-cylinder engine. A typical firing order for a six-cylinder engine is 1-5-3-6-2-4. By pairing cylinders that fire in sequence but are separated by other cylinders, the exhaust pulses can be better staggered, reducing the likelihood of interference.

By employing separate exhaust manifolds for each set of cylinders, the exhaust gases from cylinders that fire in close succession are kept separate until they merge further downstream in the exhaust system. This configuration allows for more efficient flow and can help to mitigate the negative effects of exhaust interference, such as backpressure and power loss.

Therefore, the use of a 3-into-2 exhaust manifold configuration in a six-cylinder engine can better eliminate exhaust interference by strategically managing the exhaust pulses and optimizing exhaust flow.

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The three angles are 44, 54, and 82 degrees. Since two angles (44 and 44 degrees) have the same measure, the triangle is isosceles.

If the measures of the three angles of a triangle are x, x + 10, and 2x - 6, the triangle must be isosceles.

In a triangle, the sum of the angles is always 180 degrees. Therefore, we can set up the equation:

x + (x + 10) + (2x - 6) = 180

Combine the terms:

4x + 4 = 180

Subtract 4 from both sides:

4x = 176

Divide by 4:

x = 44

Now, we can find the measures of the other two angles:

x + 10 = 44 + 10 = 54
2x - 6 = 2(44) - 6 = 88 - 6 = 82

The three angles are 44, 54, and 82 degrees. Since two angles (44 and 44 degrees) have the same measure, the triangle is isosceles.

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Answer:

144

Step-by-step explanation:

Using the rule of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\)

Given

4\(\sqrt{2}\) × 6\(\sqrt{18}\)

= 4 × 6 × \(\sqrt{2}\) × \(\sqrt{18}\)

= 24 × \(\sqrt{36}\)

= 24 × 6

= 144

Answer:

probably D

Step-by-step explanation:

a. This is a voluntary response sampling strategy. Bias may occur because only those with strong opinions are likely to respond, which may not represent the views of all parents.

b. This is cluster sampling. Bias may occur if the selected school is not representative of the entire city's school system.

c. This is a census. Bias may occur if some parents do not return the survey, leading to nonresponse bias.

d. This is stratified random sampling. Bias may be minimized as each school is fairly represented, but nonresponse bias could still occur if some parents do not return the survey or respond to the phone call.

e. This is a voluntary response sampling strategy. Bias may occur as only those watching the news and with strong opinions are likely to participate, which may not represent the views of all parents.

f. This is convenience sampling. Bias may occur because only those attending the PTA meetings will have their opinions counted, which may not represent the views of all parents.

g. This is cluster sampling. Bias may occur if the selected classes are not representative of the entire city's school system.

h. This is systematic random sampling. Bias may be minimized as the sample is spread evenly throughout the enrollment records, but nonresponse bias could still occur if some parents are not available for the interview.

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Answer: 44.4

Step-by-step explanation:

We are asked to find angle V, so we are going to use our trig ratios to explain this one. They have given us the side opposite of angle v and the hypotunse. angle v. so we are going to be using sine. . SOHCAHTOA.  

First, let use the ratio for sine \(\frac{opp}{hypo\\}\) which equal to \(\frac{7}{10}\)

then we are to take the arcsine or the sine inverse because we are trying to the angle measure not side length. (\(sin^{-1}\)(7/10) which gives us 44.4

A plasmid used in both yeast and bacteria requires two different selection markers because the same selection may not work for both hosts and bacteria and yeast recognize different promoters.

When using a plasmid in both yeast and bacteria, it is important to have two different selection markers for several reasons. First, the same selection, such as the presence of an antibiotic, may not be effective in both hosts. Different organisms have varying sensitivities to antibiotics, so a marker that works in bacteria may not work in yeast or vice versa. Therefore, two different selection markers are needed to ensure successful selection in both hosts.

Additionally, bacteria and yeast recognize different promoters, which are DNA sequences that control the initiation of gene expression. Promoters are specific to each organism and play a crucial role in regulating gene expression. By incorporating two different selection markers into the plasmid, each marker can be driven by a promoter recognized specifically by the corresponding host. This ensures that the selection marker is effectively expressed in the appropriate host organism, enabling accurate selection and maintenance of the plasmid.

In summary, using two different selection markers in a plasmid intended for both yeast and bacteria is necessary because the same selection may not be effective in both hosts, and different promoters are recognized by bacteria and yeast. This approach allows for successful selection and maintenance of the plasmid in both organisms.

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Answer:

The transformed function is

g(x)=2*|x-4|-6

Step-by-step explanation:

First, you would have to stretch it vertically which is g(x)=2*f(x)

Then you would have to move it 6 units down and 4 units to the right which is g(x)=2*f(x-4)-6

resulting in the actual function

g(x)=2*|x-4|-6

Just type that function into the DESMOS calculator and you should be good

Answer:

C: 12/45

Step-by-step explanation:

You have to divide the numerator and the denominator by the same number, and if once you divide it you get the fraction then it's the right answer. So lets take 12/45 and try it.

12/3 =4

45/3 =15

4/15

Answer:

the answer is x=+/- 3 sqrt 2

Answer:

I may be wrong but im about 80% sure its E i am deeply sorry if i am wrong and please do tell me if i am.

Step-by-step explanation:

The common sum is 18.

What is a common sum?

The following item in an arithmetic sequence is obtained by adding or subtracting a specified amount (the common sum). To find the common sum in an arithmetic sequence, add the first term from the second term.

Here,

We have a number on a vertex.

It will be counted in 3 different faces since any vertex is the intersection of three edges.

Therefore, each number 1, 2, .... 7,8 will be added to the total sum 3 times.  

Our total sum is 3(1+2+....+8) = 108.

since there are 6 faces in a cube, we get

our common sum is :

= 108/6

= 18

Hence, the common sum is 18.

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Answer:

2.25km

Step-by-step explanation:

Calculate the total distance:

9km/ 0.80 x 100% = 11.25km

The walker has travelled 9km, so

11.25km - 9km = 2.25km left

F(x) = \(\sqrt x\)  and  G(x) \(= 3x + 2\) forms the composite function G(F(x)).  

When F(x) = \(\sqrt x\) and G(x) \(= 3x + 2\) , the composite function G(F(x)) is given as follows:

G(F(x)) = G(\(\sqrt x\))

           = \(3(\sqrt x) + 2\)

           = \(3\sqrt x + 2\)

\(\therefore\) B is the correct Option.

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A firm experiences increasing returns to scale if inputs are doubled and output more than doubles.

When the firm's output grows at a faster rate than the growth in inputs, increasing returns to scale result. In this case, the company experiences economies of scale, which makes it more effective as it grows its production.

The firm is able to boost productivity and efficiency as it expands its scale of operations if inputs are doubled and output more than doubles.

This can be ascribed to a number of things, including specialisation, labour division, the use of capital-intensive technology, discounts for bulk purchases, and spreading fixed costs over a higher output. Lower average costs per unit of output result in higher profitability and competitiveness for the company.

The firm gains a number of benefits from growing returns to scale. First off, it lets the company to benefit from cost savings brought about by economies of scale, allowing it to manufacture goods or services for less money per unit. This may enable more competitive pricing on the market or result in larger profit margins.

Second, raising returns to scale can result in better operational effectiveness and resource utilisation. As the company grows in size, it will be able to use resources more wisely and profit from production volume-related synergies.market prices that are competitive.

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The required average velocity both conditions are -2 mm/s and -1/2 mm/s.

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

To find the average velocity over the interval 1 < t < 3 for the position function s(t) = 12t - t^2, we need to find the derivative of the position function and then evaluate it at the limits of the interval. The derivative of the position function s(t) = 12t - t^2 is given by:

s'(t) = 12 - 2t

The average velocity over the interval 1 < t < 3 is given by:

v_avg = (s'(3) - s'(1)) / (3 - 1) = (12 - 23 - (12 - 21)) / (3 - 1) = -2

Therefore, the average velocity over the interval 1 < t < 3 for the position function s(t) = 12t - t^2 is -2 mm/s.

For the position function s(t) = ln(t), the derivative of the position function is given by:

s'(t) = 1/t

The average velocity over the interval 1 < t < 3 is given by:

v_avg = (s'(3) - s'(1)) / (3 - 1) = (1/3 - 1) / (3 - 1) = -1/2

Therefore, the average velocity over the interval 1 < t < 3 for the position function s(t) = ln(t) is -1/2 mm/s.

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Answer:

Step-by-step explanation:

Use Newton's Law of Cooling here:

\(T(t)=T_s+(T_0-T_s)^{-kt\)

where T(t) is the temp of something after a certain amount of time, t, has gone by; Ts is the surrounding temp, and T0 is the initial temp. k is the constant of cooling. We need to first solve for this using the information given. Filling in what we know:

\(53=35+(73-35)^{-35k\) which can simplify a bit to

\(53=35+(38)^{-35k\) and \(18=38^{-35k\)

Take the natural log of both sides:

\(ln(18)=ln(38)^{-35k\)

Taking the natural log allows us to pull that exponent down out front:

\(ln(18)=-35k*ln(38)\)

and now we can divide both sides by ln(38) to get

-35k = .794585 so

k = -.023

Now that have the value for k, we can go on to solve the rest of the problem which is asking us the temp of the soda after 70 minutes. Filling in using the k value and the new time of 70 minutes:

\(T(t)=35+(38)^{70(-.023)\) and

\(T(t)=35+(38)^{-1.61\) and

\(T(t)=35+.0028612013\) and

T(t) = 35 F, basically the temp of the fridge, which is not surprising!

a. The probability that the current component has been in operation for at least 50 hours is 0.5

b. The probability that the current component will last for at least 50 more hours is also 0.5.

(a) The probability that the current component has been in operation for at least 50 hours is given by the cumulative distribution function (CDF) of the uniform distribution on [100, 200] evaluated at 50.

The CDF of a uniform distribution on [a, b] is given by:

F(x) = (x - a) / (b - a) for a <= x <= b

F(x) = 0 for x < a

F(x) = 1 for x > b

Therefore, in this case, the CDF is:

F(x) = (x - 100) / 100 for 100 <= x <= 200

F(x) = 0 for x < 100

F(x) = 1 for x > 200

So the probability that the current component has been in operation for at least 50 hours is:

P(ti >= 50) = 1 - F(50) = 1 - ((50 - 100) / 100) = 0.5

(b) The probability that the current component will last for at least 50 more hours is also given by the CDF of the uniform distribution on [100, 200], but evaluated at 150 instead of 50.

That is,

P(ti >= 150) = F(150) = (150 - 100) / 100 = 0.5.

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