The mean density of an object is defined as its mass divided by its volume : rho = Mass / Volume. [15 points] a. If a spherical body with mass M has a mean density of rho, derive the equation for the escape velocity of the planet in terms of its density and radius (R). [5 points] b. Sketch a graph of the escape velocity as a function of the radius of a body assuming mean density is constant. Be sure to label your axes. [ 3 points ] c. If a spherical body with mass M has a mean density of rho, derive the equation for the surface gravity of the planet in terms of its density and radius (R). [4 points] d. The dwarf planet Pluto and Saturn's moon Titan have almost identical densities. Titan has an escape velocity that is about 2.2 times higher than Pluto's. How many times larger is Titan's surface gravity than Plutos? Justify your answer using the results you found in the previous parts of the problem. [ 3 points ]

Given the resistance of the copper wire, length of the wire, and area of cross-section, we can calculate the resistivity of copper by the following formula.ρ = RA/L, .

Where: R is the resistance of the copper wireA is the area of cross-section of the copper wireL is the length of the copper wireSubstituting the given values, we haveρ = (2×10-2 ohms)(1.7×10-6 m2)/(2 m)ρ = 1.7×10-8 ohm-m.

Therefore, the resistivity of copper is 1.7×10-8 ohm-m. Given the resistance of the copper wire, length of the wire, and area of cross-section, we can calculate the resistivity of copper by the following formula.ρ = RA/L, .Where: R is the resistance of the copper wireA is the area of cross section of the copper wireL is the length of the copper wire .

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Answer:

Explanation:

Given

Speed v =27m/s

Distance covered after skidding = 41.5m

Acceleration a = ?

Using the equation of motion

v² =u²+2aS

27² = 0²+2a(41.5)

729 = 0+83a

a = 729/83

a = 8.78m/s²

Hence it's acceleration is 8.78m/s²

Answer:

 The state when the two objects have reached the same temperature is known as thermal equilibrium.

Explanation:

where are the statements

Answer:

Socialist

Explanation:

Answer: socialist

Explanation: A socialist form of government is where the goods and services are equally shared, and the political power is distributed among the people.

Answer:

buying and selling goods and services. and exchange account

Explanation:

:)

Answer:

when money is used to intermediate the exchange of goods and services

Answer:

Explanation:

1.

\(\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{0.01223}{1.01}\:\\\mathrm{is}\:0.0121\)

2.

\(\frac{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&\space\space&4&9&10\\ \space\space&\textbf{1}&9&.&8&\linethrough{5}&\linethrough{10}&\linethrough{0}\\ -&\textbf{0}&0&.&0&1&1&3\end{matrix}}{\begin{matrix}\space\space&\textbf{1}&9&.&8&3&8&7\end{matrix}}\\\\=19.8387\)

3.

\(0.1886\times 12\\\\Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer\\1886\times\:12=22632\\\\0.1886\mathrm{\:has\:}4\mathrm{\:decimal\:places}\\12\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}4\mathrm{\:decimal\:places}\\\\=2.2632\)

An atom’s location on the periodic table provides information such as;

1. Atomic number.

2. Number of valence electrons.

3. Atomic weight.

An atom can be defined as the smallest unit which comprises the matter that forms all chemical elements. Thus, atoms are typically the fundamental building blocks of matter and as such determines (defines) the structure of a chemical element.

Generally, atoms are typically made up of three (3) distinct particles and these are;  

Periodic table is an organized tabular array of all the chemical elements arranged in order of increasing atomic number (in rows).

Generally, an atom’s location on the periodic table (the group of elements it belongs to) provides information such as;

1. Atomic number.

2. Number of valence electrons.

3. Atomic weight.

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The size of a neutron star is smaller than any of the given answer choices.

A neutron star is an extremely dense object that is formed from the collapsed core of a massive star that has undergone a supernova explosion. The mass of a neutron star is typically 1.4 times that of our Sun, but its size is only about 20 km in diameter, making it one of the most compact objects in the universe.

To put this into perspective, the diameter of our solar system is about 287 billion km, the diameter of the Sun is about 1.4 million km, and the diameter of the Earth is about 12,742 km. Therefore, a neutron star is much smaller than any of these objects, and its mass is packed into a space that is comparable in size to a medium-sized city.

In conclusion, a neutron star is much smaller than any of the given answer choices, with a diameter of only about 20 km.

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A neutron star is a very compact and incredibly dense object formed from the core of a massive star after a supernova explosion.

1) Our solar system is vast, spanning a distance of over 100 astronomical units (AU), with the distance between the Sun and the outer planets being several billion kilometers.

In contrast, a neutron star typically has a radius of about 10-15 kilometers, which is much smaller than the distance between any two objects in the solar system.

2) The Sun, on the other hand, is much larger than a neutron star, with a radius of about 696,000 kilometers.

The Earth, which is one of the smaller planets in our solar system, has a radius of about 6,371 kilometers.

Therefore, a neutron star is significantly smaller than both the Sun and the Earth.

3) The size of a neutron star is determined by its mass and density, which are both extremely high.

A typical neutron star has a mass of about 1.4 times that of the Sun, but is only about 10-15 kilometers in radius.

This makes it incredibly dense, with a mass-to-volume ratio that is several times higher than that of an atomic nucleus.

In summary, a neutron star is much more massive than the Sun or the Earth, but its size is significantly smaller than both, making it smaller than any of the options given.

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Answer:

i think it is car B because  the greater the speed, the greater the drag force acting on the vehicle

Explanation:

According to the given statement The mass attached to the spring is 3.99 kg.

A spring system with a block hanging from or affixed to the spring's free end is known as a spring-mass system. The spring-mass system is typically used to calculate the duration of any object in a simple harmonic motion.

F = -kx

where k is the spring constant, and

x is the displacement of the spring

The angular frequency of the spring is:

\(\omega=\sqrt{\frac{k}{m}}\)

m is the mass of object attached to the spring

So, frequency:

f = ω/2π = \(\frac{1}{2 \pi} \sqrt{\frac{k}{m}}\)

m = 4π²f² / k

given that f = 0.9 Hz, and

k = 9 N/m

m = (4×π²×0.9²)/8

m = 3.99 kg

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Answer:

v=3.66,h-3.66

Explanation:

vertical = 10sin60 - 10sin 30

horizontal =10cos60 + 10cos 30

v = 10×0.8660-10×0.5

h = 10×0.5 + 10 × 0.8660

v=8.660-5.0 = 3.66

h= 5.0-8.660 = -3.66

Aluminum reacts vigorously and exothermically with copper chloride, the balanced chemical reaction becomes:

2Al + 3CuCl₂ → 2AlCl₃ + 3Cu

Considering that aluminium is a more active metal in the electrochemical series of metals than copper, it displaces copper from the bond. The result is the emission of gaseous hydrogen and red metallic copper. This reaction is quite intense and results in the production of heat.

The reaction between aluminium and copper(II) chloride is highly vigorous, as heat is generated, the reaction mixture becomes very hot, the blue hue owing to the Cu(II) ions fades, the aluminium foil disintegrates, a reddish brown solid emerges, and gas bubbles are released.

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Explanation:

It is given that A body weighs 20gf in air and 18. 0gf in water. Hence, the answer X-3 = 7

Answer:

Due to this EM waves show electric and magnetic field. An electric and magnetic field have no need a medium to show thier effect. Hence in the presence of electric and magnetic field vector which vibrate perpendeculer to each other and get pertervation EM waves travels in vacuum.

In a planetary nebula, the shell of expelled material is glowing intensely due to the UV radiations being emitted from the center of the dying star.

What is a planetary nebula?

Rarefied gas with a density of typically makes up a typical planetary nebula. The highest densities, up to 106 particles per cm3, can be found in young planetary nebulae. The density of nebulae decreases with aging due to their expansion. From 0.1 to 1 solar masses is the mass range of planetary nebulae.

Gases are heated to temperatures of about 10,000 K by radiation from the central star. The temperature of the gas is typically 16,000–25,000 K higher in the central regions than it is in the outermost regions. The area around the central star is frequently filled with a very hot (coronal) gas with a temperature of about 1,000,000 K. Fast stellar wind, a gaseous component, is produced at the central star's surface.

Nebulae can be classified as radiation-bounded or matter-bounded. The visible nebula is fully ionized in the first scenario because there is not enough stuff in the nebula to absorb all of the UV rays released by the star. The latter occurs when the core star's UV photon output is insufficient to completely ionize the surrounding plasma, and an ionization front moves outward into the circumstellar envelope of neutral atoms.

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Answer:

1.439 × 10¹¹ m is the answer.

Explanation:

1 light-second = 2.998 × 10⁸m

480 light-seconds = 480 × 2.998 × 10⁸

= 1439.04 × 10⁸

= 1.439 × 10¹¹

∴ 1.439 × 10¹¹ m is the answer.

The distance converted into the meter will be 1.439×10¹¹ m.In one light second, there are 2.998 ×10⁸ m.

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

The given data in the problem is;

The  distance between the sun and moon is,d= 480 light second

\(\rm d_m\) is the distance in meter

As we know,

\(\rm 1\ light\ second = 2.998 \times 10^8m \\\\ 480\ light\ seconds = 480 \times 2.998 \times 10^8\ m \\\\ d_m= 1439.04 \times 10^8 \\\\ d_m = 1.439 \times 10^{11}\)

Hence the distance converted into the meter will be 1.439×10¹¹ m.

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Answer:

560

Explanation:

56*10=560

hope this helps :3

if it did pls mark brainliest

Answer: 560 cats

Explanation: 56x10 = 560.

The magnification is doubled when 10x oculars are used instead of 5x in our microscope with the same objectives.

When multiple lenses are lined together, the overall magnification can be calculated by multiplying the individual magnifications of each lens.

M = M1 × M2 × M3 × ... × Mn

where M is the overall magnification and M1, M2, M3, ..., Mn are the magnifications of the individual lenses.

Let M be the magnification of the objective, then the overall magnification,

when 5x ocular is used,

M1 = M × 5

M1 = 5M

when 10x ocular is used

M2 =  M × 10

M2 = 10M

Therefore, the magnification is doubled when 10x ocular is used instead of 5x in our microscope with the same objectives.

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The refractive power of the contact lenses required to allow the near-sighted man to focus on very distant objects is approximately +1.67 diopters .

Apologies for the incorrect response in the previous message. Let's correct the calculation:

To determine the refractive power of the contact lenses, we need to calculate the lens power required to correct the near-sightedness of the individual.

The refractive power (P) can be calculated using the formula:

P = 1 / f

where f is the focal length of the lens.

In this case, the near-sighted man has a far-point distance of 60 cm, which means that objects need to be brought closer to him to focus properly.

To calculate the refractive power, we need to find the focal length that brings the far-point distance to infinity. In other words, we need to find the lens power that compensates for the near-sightedness.

Since the far-point distance (f) is 60 cm and we want to correct it to infinity, we can use the formula:

P = 1 / f = 1 / 0.60 = 1.67 D

Therefore, the refractive power of the contact lenses required to allow the near-sighted man to focus on very distant objects is approximately +1.67 diopters or +1.67 \(m^{-1.\) The positive sign indicates that the lenses are converging lenses, which help bring the light rays together to focus correctly on the retina.

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Answer:

Its C

Thank me later

Now bye

Heat loss rate is 1346.29 W per unit length of the pipe. Temperature drops: 295°C across the pipe shell and 0°C across the insulation.

To determine the rate of heat loss from the steam per unit length of the pipe, we need to calculate the thermal resistance and apply the equation for heat transfer rate.

First, let's calculate the thermal resistance of the pipe (\(R_pipe\)):

\(R_pipe\) = ln(D₂/D₁) / (2π\(k_ssL_pipe\))

       = ln(0.055/0.05) / (2π * 15 * 0.05)

       ≈ 0.0216 K/W

Next, let's calculate the thermal resistance of the insulation (\(R_insul\)):

\(R_insul\) = \(\ln\left(\frac{D_2+L_{insul}}{D_2}\right) / (2\pi k_{insul} L_{insul})\)

       = ln((0.055+0.03)/0.055) / (2π * 0.038 * 0.03)

       ≈ 0.1955 K/W

Now, we can calculate the overall thermal resistance (\(R_total\)):

\(R_total = R_pipe + R_insul\)

       ≈ 0.0216 + 0.1955

       ≈ 0.2171 K/W

The rate of heat loss from the steam per unit length of the pipe (W) can be calculated using the equation:

\(W = (T_inside - T_outside) / R_total\)

  = (300 - 5) / 0.2171

  ≈ 1346.29 W

Therefore, the rate of heat loss from the steam per unit length of the pipe is approximately 1346.29 W.

To determine the temperature drops across the pipe shell and the insulation, we need to consider the temperature difference between the inside and outside of each layer.

Temperature drop across the pipe shell (Δ\(T_shell\)):

Δ\(T_shell = T_inside - T_outside\)

         = 300 - 5

         = 295°C

Temperature drop across the insulation (Δ\(T_insul\)):

Δ\(T_insul = T_outside - T_surr\)

         = 5 - 5

         = 0°C

Therefore, the temperature drop across the pipe shell is 295°C and there is no temperature drop across the insulation (0°C).

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Answer:

Direction - Downwards

Acceleration - Upwards

Explanation:

Terminal velocity means the net force was 0, so when the parachute is introduced the parachutist will feel an unbalanced force upwards thus being accelerated upwards. Still the motion is still going down as although there is an Acceleration upwards, it will take some time for it to accelerate enough to make the velocity 0

The work done by the force is approximately 1.42 × 10⁵ J.

Pushing force = 10,000 NAngle = 25.0°

Distance = 15.0 mWe can use the formula to find the work done by the force, Work done = force × displacement × cos(θ)

where,θ = angle between force and displacement

Let's put the given values in the above formula,

Work done = 10000 × 15 × cos(25.0°) ≈ 1.42 × 10⁵ J

Therefore, the work done by the force is approximately 1.42 × 10⁵ J.

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Cause: Energy transferred over time Effect: Power When energy is transferred over time, it results in the generation of power. Power is the rate at which work is done or energy is transferred, per unit of time.

The more energy that is transferred over time, the greater the power generated. Cause: Force applied to an object to change its position. Effect: Motion

When a force is applied to an object, it causes the object to move. Motion is a change in an object's position over time. The greater the force applied to the object, the greater the acceleration produced, and the faster the object will move.

Cause: Force moving an object over a distance

Effect: Work

When a force moves an object over a distance, it results in the generation of work. Work is the energy transferred to or from an object when a force is applied over a distance. The more force that is applied over a distance, the more work is done.

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Cause:-Energy transferred over time,Force applied to an object to change its position,Force moving an object over a distance

Effect:Power,Work,Motion

The Explanation are given as follows :-

Power is the rate at which work is done, or the amount of energy transferred over time. When energy is transferred over time, it can be used to perform work at a certain rate, which is power.

Work is the energy transferred when a force is applied to an object to change its position. When a force is applied to an object, work is done to move the object over a certain distance.

Motion is the change in position of an object over time due to a force moving it over a certain distance. When a force is applied to an object and work is done to move it, the object undergoes motion.

Work, power, and energy are related concepts in physics, but they are different in terms of their definitions and units of measurement.

Work is the transfer of energy that occurs when a force is applied to an object and the object is moved through a distance. The amount of work done is equal to the force applied multiplied by the distance over which the force is applied. The unit of work is joules (J).

Power is the rate at which work is done or energy is transferred. It is equal to the amount of work done divided by the time taken to do the work. The unit of power is watts (W).

Energy is the capacity to do work, or the ability to cause change. It is a scalar quantity that comes in different forms, such as kinetic energy (energy of motion), potential energy (energy stored in an object due to its position or state), thermal energy (energy associated with the temperature of a system), etc. The unit of energy is also joules (J).

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When an object attached to a horizontal spring oscillates, its kinetic energy is maximum at the midpoint between points A and B, as it has the highest speed at this position. Answer is option C). Midway between A and B.

At points A and B, the kinetic energy is minimum since the object momentarily comes to a stop before changing direction. The object attached to the horizontal spring oscillates between points A and B, which means it moves back and forth. Kinetic energy is the energy of motion, so the object will have its maximum kinetic energy when it is at the midpoint between A and B. This is because at this point, the object has the highest speed, and thus the highest kinetic energy. Therefore, the answer is C) midway between A and B.

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