Median can described as -
the middle observation when the data values are arranged in ascending order; the second quartile; and 50th percentile all.
Hence the correct option is (D).
Median of a data observations set is the middle point or middle value of the data set arranged in ascending or descending order.
Hence point (A) is correct.
50th percentile means the middle observation or the observation, after or before which equal number of observations lie.
So the point (B) is also correct.
A quartile means = 25 percentile
second quartile stands for = 25*2 = 50 percentile.
Hence point (C) is also correct.
Hence the best suited option is (D) all of the above.
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The question is incomplete. The complete question will be -
Write 6.51 x 10-8 in standard form
Please help :)
There are seven "0"s between the decimal point and the digit "6".
======================================================
Explanation:
The number \(6.51 \times 10^{-8}\) is in scientific notation.
The exponent -8 tells us to move the decimal point exactly 8 spots to the left to get the answer 0.0000000651
In other words, we'll move the decimal point one spot to the left to go from 6.51 to 0.651
Then we move it another seven spots to the left to arrive at 0.0000000651
This is why there are seven "0"s between the decimal point and the digit "6".
A snow globe is made out of regular right triangular prism that is inscribed in hemisphere with radius 12cm. help a designer to find the dimensions of maximum volume prison. state the exact answer.
Note: Find the dimensions of the prism for the case when the triangular base is on the grand circle of the hemisphere.
The maximum volume of the prism is 1728 cubic centimeters.
To find the dimensions of the prism with maximum volume, we need to consider the relationship between the volume of the prism and its dimensions.
Let's assume the base of the right triangular prism is an isosceles right triangle with legs of length 'a'. The height of the prism will be 'h'. The prism is inscribed in a hemisphere with a radius of 12 cm.
First, let's determine the relationship between 'a' and 'h'. Since the base of the prism is on the great circle of the hemisphere, the hypotenuse of the triangular base is equal to the diameter of the hemisphere, which is twice the radius. Therefore, the hypotenuse of the base is 2 * 12 = 24 cm.
By using the Pythagorean theorem, we can find 'a':
a^2 + a^2 = 24^2
2a^2 = 576
a^2 = 288
a = √288
Now, let's find the height 'h' of the prism. The height 'h' is equal to the radius of the hemisphere, which is 12 cm.
Therefore, the dimensions of the prism for maximum volume are:
Base length (a) = √288 cm
Height (h) = 12 cm
To find the maximum volume, we can use the formula for the volume of a right triangular prism:
Volume = (1/2) * a^2 * h
Substituting the values, we get:
Volume = (1/2) * (√288)^2 * 12
= (1/2) * 288 * 12
= 1728
Hence, the maximum volume of the prism is 1728 cubic centimeters.
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1. Use the slope to find the speed of the object in the graph below.252015-distance (miles)105-150(1.39, 11.6)23time (hour)
Notice that the slope of the line is equal to the speed
\(\text{Slope (speed) = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{20\text{ -10}}{4\text{ - 2}}\text{ =}\frac{10}{2}=5\text{miles / hour}\)hence, the speed = 5 miles / hour
The coordinates (1, 1), (1, 3), (3, 3), and (x, y) form a square when graphed on a coordinate plane. Which ordered pair would be the fourth vertex of the square? A (3, 1) B (1,3) C (3,5) D (3, 0
)
Answer:
3,1
....................................
when processing an invoice what account is debited
a. cash
b. accounts payable
c. accounts receivable
d. the answer depends on the transaction
Answer:
D
Step-by-step explanation:
Because the account that gets debited depends on the specific transaction
Maya wants to put fencing around her
rectangular backyard. The width of the yard
is 55 feet and the length is 75 feet. How
many feet of fencing does Maya need?
3) 260
7) 130
6) 3,905
9) 4,125
Answer:
3) 260 ft
Step-by-step explanation:
You want the perimeter of a rectangle 55 ft by 75 ft.
PerimeterThe equation for the perimeter of a rectangle is ...
P = 2(L +W)
ApplicationFor the given rectangle, the perimeter is ...
P = 2(75 ft +55 ft) = 2(130 ft) = 260 ft
Maya needs 260 feet of fencing to put fence around her rectangular yard.
Find the slope of the line that passes through the
points (-3,5) and (3, 1).
Answer:
Slope = -2/3
Step-by-step explanation:
Slope = change in y / change in x OR the rise/run
Slope = (5 - 1)/(-3 -3)
Slope = 4/-6
Slope = -2/3
Hope this helped!
Solution :
As we know that,
\( \boxed{\red{\bf{Slope \: (m) \: = \: \dfrac{y_{2} \: - \: y_{1} }{x_{2} \: - \:x_{1}} }}} \: \bigstar\)We have :
\(\sf{x_1 \: = \: -3}\)\(\sf{y_1 \: = \: 5}\)\(\sf{x_2 \: = \: 3}\)\(\sf{y_2 \: = \: 1}\)Substituting the values :
\( \longmapsto \: \sf{Slope \: (m) \: = \: \dfrac{1 \: - \: 5 }{3 \: - \: ( - 3)} } \\ \\ \longmapsto \: \sf{Slope \: (m) \: = \: \dfrac{1 \: - \: 5 }{3 \: + \: 3} } \\ \\ \longmapsto \: \sf{Slope \: (m) \: = \: \dfrac{ - 4}{6} } \\ \\ \longmapsto \: \sf{Slope \: (m) \: = \: \cancel\dfrac{ - 4}{6} } \\ \\ \longmapsto \: \bf{ \orange{Slope \: (m) \: = \: \dfrac{ - 2}{3} }}\)
does this interval give convincing evidence of a difference between the population proportions? justify your answer. no. because the interval does not contain 0, there is not convincing evidence that the true proportion of men who can identify egypt on the map is different than the true proportion of women that can identify egypt on a map. yes. because the interval does not contain 0, there is convincing evidence that the true proportion of men who can identify egypt on the map is different than the true proportion of women that can identify egypt on a map. no. because the interval does not contain negative numbers, there is not convincing evidence that the true proportion of men who can identify egypt on the map is different than the true proportion of women that can identify egypt on a map. yes. because the interval does not contain negative numbers, there is convincing evidence that the true proportion of men who can identify egypt on the map is different than the true proportion of women that can identify egypt on a map. no. because the conditions were not met, we cannot use this interval to conclude that there is convincing evidence that the true proportion of men who can identify egypt on the map is different from the true proportion of women that can identify egypt on a map.
The answer to the question is no, there is not convincing evidence of a difference between the population proportions.
Confidence intervals are used to estimate the range of possible values of an unknown population parameter based on a sample. If the confidence interval does not contain 0, it means that the difference between the sample proportions is statistically significant, which suggests that the difference between the population proportions may also be statistically significant. However, to conclude that there is convincing evidence of a difference between the population proportions, it is important to make sure that the conditions for performing the hypothesis test have been met, such as the independence of the sample and the normality of the population.
In this case, it seems that the conditions have not been met, so we cannot use this interval to conclude that there is convincing evidence that the true proportion of men who can identify Egypt on the map is different from the true proportion of women that can identify Egypt on a map.
Therefore, the answer to the question is no, there is no convincing evidence of a difference between the population proportions.
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The answer to the question is no, there is not convincing evidence of a difference between the population proportions.
Confidence intervals are used to estimate the range of possible values of an unknown population parameter based on a sample. If the confidence interval does not contain 0, it means that the difference between the sample proportions is statistically significant, which suggests that the difference between the population proportions may also be statistically significant. However, to conclude that there is convincing evidence of a difference between the population proportions, it is important to make sure that the conditions for performing the hypothesis test have been met, such as the independence of the sample and the normality of the population.
In this case, it seems that the conditions have not been met, so we cannot use this interval to conclude that there is convincing evidence that the true proportion of men who can identify Egypt on the map is different from the true proportion of women that can identify Egypt on a map.
Therefore, the answer to the question is no, there is no convincing evidence of a difference between the population proportions.
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a(q-8)=23
solve for q
help appreciated!
Answer:
q= (23+8a)/a
Step-by-step explanation:
a(q-8)=23
or, aq-8a = 23
or, aq = 23+8a
or, q = (23+8a)/a
(I’m not sure if the A is part of the question or if A is what question you’re answering but I’ll work o for both)
A(q - 8) = 23
Multiply everything inside the brackets by A:
aq- 8a = 23
Divide both sides by a to isolate q - 8a:
q - 8a = 23 / a
Add 8a to both sides to isolate q:
q = 23 + 8a² / a
Without the A:
q - 8 = 23
Add 8 to both sides to isolate q:
q = 31
Sorry if I misunderstood but I hope I helped you, have a great day!!
if p(x)=3x^2+5x-8 then find p(-2)
P(x) = P(-2)
P(-2) = 3(-2)^2 + 5(-2)-8
= 3(4) + (-10) - 8
= 12 + (-10 -8)
= 12 + (-18)
= 12 - 18
= - 6
P(-2) = -6
(divided on both sides by -2)
Answer:
P = 3
(btw i am not sure if this is the answer you are looking for. Please clarify ths objective of this equation. What are we looking for? Are we solving for "P" ?)
need help asap
* Calculate the reciprocal (Inverse or Indirect quote) from following. \( \rightarrow \) USO/DKK \( 6.4270 / \mathrm{H} 350 \) \( \rightarrow \) GBP/NZD 2.0397/0700 \( \rightarrow \) USO/INR \( 44.333
The reciprocal (inverse or indirect quote) for the given exchange rates is as follows:
USO/DKK: The reciprocal exchange rate is 0.1557 DKK/USO.
GBP/NZD: The reciprocal exchange rate is 0.4898 NZD/GBP.
USO/INR: The reciprocal exchange rate is 0.0226 INR/USO.
To calculate the reciprocal quote, we take the reciprocal of the given exchange rate. For example, for USO/DKK with an exchange rate of 6.4270 DKK per USO, the reciprocal is 1 divided by 6.4270, which equals 0.1557 DKK per USO.
Similarly, for GBP/NZD with an exchange rate of 2.0397 NZD per GBP, the reciprocal is 1 divided by 2.0397, which equals 0.4898 NZD per GBP.
Finally, for USO/INR with an exchange rate of 44.333 INR per USO, the reciprocal is 1 divided by 44.333, which equals 0.0226 INR per USO.
These reciprocal quotes represent the inverse of the original exchange rates.
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Complete question: Calculate the reciprocal (inverse or indirect quote) for the following currency pairs:
1. USO/DKK: 1/6.4270 or DKK/USO: 1/350
2. GBP/NZD: 1/2.0397 or NZD/GBP: 1/0.7000
3. USO/INR: 1/44.333 or INR/USO: 1/44.333
Find the percent increase. Round to the nearest percent. From 82 books to 144 books The percent increase is
Answer:
Step-by-step explanation:
56%
Plzzzzzzzzzzz helppppppppppp
Step-by-step explanation:
It’s in step one.
Ling subtracted 6.2 to get rid of it on both side but instead they subtracted it from the right side but added it to the left side when Ling was supposed to subtract from both sides.
what is the measure (in radians) of the angle formed by the hands of a clock at each time? write your answers in terms of π . a. 1:30 p.m.
The measure (in radians) of the angle formed by the hands of a clock at 1.30 PM is 3π/4 radians.
The given time is 1:30 PM.
Time is used to quantify, measure, or compare the duration of events or the intervals between them, and even, sequence events.
The angle between hour hand and minute hand is 135°.
In radians = 135° ×π/180°
= 9π/12
= 3π/4
Therefore, the measure (in radians) of the angle formed by the hands of a clock at 1.30 PM is 3π/4 radians.
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provide numerical measures of individuals. the measures can be added or​ subtracted, and provide meaningful results.
Quantitative variables provide numerical measures of individuals. The measurements yield useful results and can be added to or removed from.
A quantitative variable is one for which the data display amounts (e.g. height, weight, or age). A categorical variable is one where the data indicate categories. As was discussed in the chapter's section on variables, quantitative variables are those that are measured on a numeric scale.
Height, weight, reaction speed, subjective pain rating, temperature, and exam score are a few examples of quantitative variables.
A quantitative study works with numbers and data, whereas a qualitative study concentrates on words and meanings. Variables can be quantified, and hypotheses can be tested quantitatively. You can go more deeply into concepts and experiences by using qualitative research methods.
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John is interested in purchasing a multi-office building containing five offices. The current owner provides the following probability distribution indicating the probability that the given number of offices will be leased each year.
Number of Lease Offices 0 1 2 3 4 5
Probability 10/33 1/33 7/33 1/11 4/33 8/33
If each yearly lease is $12,000, how much could John expect to collect in yearly leases for the whole building in a given year?(in dollars)
a) E(X) = $29,130.91
b) E(X) = $29,090.91
c) E(X) = $29,170.91
d) E(X) = $29,070.91
e) E(X) = $29,100.91
AE(X) = $23,333.33 could John expect to collect in yearly leases for the whole building in a given year.
What is probability ?
The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a proposition is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.
The given table is:
Number of Lease Offices : 0 1 2 3 4 5
Probability : 5/18 1/4 1/9 1/18 2/9 1/12
The expected probability is
Expected probability \($=\sum_{i=0}^5 x_i p\left(x_i\right)$\)
Expected probability \($=0 p(0)+1 P(1)+2 P(2)+3 P(3)+4 P(4)+5 P(5)$\)
Expected probability \($=0 \cdot\left(\frac{5}{18}\right)+1 \cdot\left(\frac{1}{4}\right)+2 \cdot\left(\frac{1}{9}\right)+3 \cdot\left(\frac{1}{18}\right)+4 \cdot\left(\frac{2}{9}\right)+5 \cdot\left(\frac{1}{12}\right)=\frac{35}{18}$\)
It is given that the yearly lease \($=\$ 12,000$\).
The yearly leases for the whole building in a given year is
Yearly leases \($=\frac{35}{18} \times 12000=23333.3333333 \approx 23333.33$\)
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What is the answer? 7 = -5(n – 4) – 3.
You have to evaluate
3³+11-10÷2×4=w
Answer:
18
Brainliest, please!
Step-by-step explanation:
3^3 + 11 - 10 / 2 x 4 = w
27 + 11 - 10 / 2 x 4 = w
27 + 11 - 5 x 4 = w
27 + 11 - 20 = w
38 - 20 = w
w = 18
how do you write 4:2:2 in simplest form
ratio
Answer:
2:1:1
Step-by-step explanation:
Divide the whole ratio by the greatest common factor. That GCF is two.
how many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 if each digit can be used only once?
Answer:
180
Step-by-step explanation:
A 3-digit number cannot start with 0, so the leftmost digit is a choice of 6 digits out of the 7. The middle digit can be chosen from all 7 digits minus the one already used, so there are 6 choices. The right digit can be chosen from 5.
6 × 6 × 5 = .180
The number of three-digit numbers that can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 is 180.
This can be calculated by finding the number of element availabe at first place which is 6 excluding 0 than for second position 6 as first number is excluded and 0 is added and for the last positon the number of possibe combination is 5 as 2 digits are already used.
The final answer is 6*6*5 = 180
so count of 3 digit numbers that can be formed by the given set of digit without repetetion allowed is 180
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uppose v,w∈r3are orthogonal unit vectors. let u=v×w. show that w=u×v and v=w×u.
To show that w = u × v and v = w × u, we need to demonstrate that the cross product of vectors u and v yields the same result as the cross product of vectors w and u.
Given that u = v × w, let's calculate the cross product of w and u:
w × u = (u × v) × u
Since the cross product is not associative, we need to use the vector triple product identity:
w × u = u × (v × u) - (u · u) v
Since u is orthogonal to v, the dot product (u · v) is zero. Therefore, we can simplify the equation:
w × u = u × (v × u)
Next, let's calculate the cross product of v and u:
v × u = (u × v) × v
Using the vector triple product identity:
v × u = v × (u × v) + (v · v) u
Again, since u is orthogonal to v, the dot product (v · v) is zero:
v × u = v × (u × v)
Thus, we have shown that w = u × v and v = w × u, indicating that the cross products are equivalent in both directions.
In summary, when u, v, and w are orthogonal unit vectors, the cross product of u and v yields the same result as the cross product of w and u, as well as the cross product of v and w.
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what's the answer to this amthswatxh qu
The equation of the line is y=3x+1 when the line is on the graph of the given picture.
Given that,
In the picture we have a graph.
We have to find the equation of the line.
We know that,
From the graph we can see the points,
(1,4) and (0,1)
We know that the equation of the line is y=mx +b
The y and x value are from the points and the m is the slope that is rise by run and b is the y intercept.
m is rise/run
m= 1-4/0-1
m=-3/-1
m=3
b is 4=3(1)+b
4=3+b
b=4-3
b=1
The equation of the line is y=3x+1
Therefore, The equation of the line is y=3x+1 when the line is on the graph of the given picture.
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The weight of meteorite A is 7 times the weight of meteorite B. If the sum of their weights is 144 tons, find the weight of each.
Taking into account the definition of a system of linear equations, the weight of meteorite A and meteorite B is 126 tons and 18 tons respectively.
System of linear equationsA system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.
Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is, they must give the solution proposed in both equations.
Weight of each meteoriteIn this case, a system of linear equations must be proposed taking into account that:
"A" is the weight of meteorite A."B" is the weight of meteorite B.You know:
The weight of meteorite A is 7 times the weight of meteorite B. The sum of their weights is 144 tons.The system of equations to be solved is
\(\left \{ {{A=7B} \atop {A+B=144}} \right.\)
It is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.
In this case, substituting the first equation in the second one you get:
7B + B= 144
Solving:
8B= 144
B= 144÷8
B= 18 tons
Remembering that A= 7B, the value of A is calculated as:
A= 7×18
A= 126 tons
Finally, the weight of meteorite A and meteorite B is 126 tons and 18 tons respectively.
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tres fosas marinas tienen una profundidad de -5534m, -6524m, -4321m, respectivamente.
¿cual de las 3 fosas marinas tiene mayor profundidad?
For the given depth of the trenches the deeper sea seals is with measure -6524m and shallower sea seals is with measure -4,321m.
Measure of the depth of the three trenches is equal to :
-5,534m, -6,524m and -4,321m.
Now consider sea is the origin and above sea it is positive axis of the number line .And deeper of the sea it is representing negative axis of the number line.After origin 'Zero ' first points towards negative side is -4,321m.After -4,321m it is -5,534m.At the end it is -6,524m.Deeper is -6,524m and shallower is -4,321m.Therefore, the from the depth of the trenches the deeper one is -6524m and shallower sea seals is -4,321m.
The above question is incomplete, the complete question is:
Three trenches have a depth of
-5,534m, -6,524m and -4,321m, respectively. Which of the three
sea seals is deeper and which is shallower?
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Doug i a aleperon in a retail tore and earn $75 per week plu 15% of hi weekly ale. If Doug make $555 one week, what are hi ale that week?
Group of anwer choice
Doug made sales worth A. $3,200 in the last week.
What is the percentage?
A percentage is a value divided by a hundredth. By dividing the percentage value by a hundred, you can convert it to decimals and fractions.
Given, Doug is a salesperson in a retail store and earns $75 per week,
Plus 15% of his weekly sales.
Doug makes $555 one week,
∴ He made $(555 - 75) = $480.
So, $480 is 15% of his weekly sales, Assuming he made sales worth $x.
∴ 15% of x is $480.
(15/100)×x = 480.
0.15x = 480.
x = 480/0.15.
x = 3200.
Doug made sales worth A. $3,200 in the last week.
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consider the quadratic function y equals short dash x squared plus 6 x minus 5. what do we know about the graph of this quadratic equation, based on its formula?
Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.
Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.
First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.
Next, we can find the vertex using the formula:
Vertex = (-b/2a, f(-b/2a))
where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:
Vertex = (-b/2a, f(-b/2a))
= (-6/(2*-1), f(6/(2*-1)))
= (3, -14)
So the vertex of the parabola is at the point (3,-14).
Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.
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Write the following as an inequality.
5 is greater than or equal to w, and -5 is less than or equal to w
use w only once in your inequality
Answer:
\(-5\leq w\leq 5\)
\(\huge\underline\mathtt\red{Answer:}\)
−5 ≤ w ≤ 5
no one wants to help me..someone please help!!
in a recent football game, the orange team defeated the blue team by a score of 44 to 24. the total points scored came from a combination of touchdowns (worth 6 points), extra-point kicks (worth 1 point), and field goals (worth 3 points). the numbers of touchdowns was equal to the number of extra-point kicks. there were twice as many touchdowns as field goals. find the number of touchdowns, extra-point kicks, and field goals scored.
The required number of touchdowns are 8, number of extra- point kicks are 8 and number of field goals are 4 can be obtained from the system of equations.
The orange team scores 44 points and the blue team scores 24 points.
The touchdowns are worth 6 points.
The extra- point kicks are worth 1 point.
The field goals are worth 3 points.
Let the number of touchdowns, extra- point kicks and field goals be x, y and z respectively.
According to the question, the numbers of touchdowns was equal to the number of extra-point kicks.
That is, x= y
Also according to the question, there are twice as many touchdowns as field goals.
That is, x= 2z
From the above two equations we can say that,
x= y= 2z
⇒y= 2z
We can state the total score by the two teams by the following equations as,
6x+ 1y+ 3z = 44+24
⇒ 6(2z)+ 1(2z)+ 3(z) = 68
⇒ 17z = 68
⇒ z= 68/17
⇒ z= 4
Hence, x= 2z = 2(4) = 8
and y= x= 8
Hence the number of touchdowns, extra- point kicks and field goals are 8, 8 and 4 respectively.
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Solve the equation: (3)/(7)-(2)/(5)x=5
Answer:
x = - \(\frac{80}{7}\)
Step-by-step explanation:
Given
\(\frac{3}{7}\) - \(\frac{2}{5}\) x = 5
Multiply through by 35 ( the lcm of 7 and 5 ) to clear the fractions
15 - 14x = 175 ( subtract 15 from both sides )
- 14x = 160 ( divide both sides by - 14 )
x = \(\frac{160}{-14}\) = - \(\frac{80}{7}\)