Answer:
£800
Step-by-step explanation:
Use the percentage formula: NV = m x OV
NV is New Value;
m is Multiplier;
and OV is Old Value.
£640 in the New value, so now we have to convert 20% to a multiplier and find out the Old value.
Make OV the subject of the formula: OV = NV / m
So 20% decrease would mean: 100 - 20 = 80 * 100 = 0.80
Divide 640 (NV) by 0.80 (m) and it will give you:
£800
And it would make sense that the OV is higher, and it matches the statement -> as the NV is the decrease.
i will mark brain thing help me what is A and B
The average rate of population decline between 2004 and 2014 is 1.45 thousand deer per year. If the population continued to decline at this rate, in which year would the population have reached 225 thousand deer? Explain your reasoning.
Answer:
in 155 years it would reach 225 thousand deer
Step-by-step explanation:
If the cos A= 9/41 , what does the tan A equal?
Answer:
tanA = 40/9
Step-by-step explanation:
Try to construct a right-angled triangle with it's adjacent side=9 and hypotenuse = 41,
By pyth. theorem, we can get the remaining side (opposite side)
= √(41^2 - 9^2)
= 40
tanA = oppside side/ adjacent side
tanA = 40/9
An object has a mass of 225 g and a volume of 15 cm3.
Find the density of the object in g/cm3
Answer:
D=m/v
=225g/15cm^3
=15g/cm^3
Step-by-step explanation:
The formula for calculating density is: density=mass/volume.
after collecting data you will see that all the data is already in the question and there's no need to convert any units. Divide the mass by the volume and you'll have the density in g/cm^3
In a class of 29 students, 19 are female and 14 have an A in the class. There are 8 students who are male and do not have an A in the class. What is t
If In a class of 29 students, 19 are female and 14 have an A in the class then 2 male students have an A in the class.
We can calculate the number of students who are male and have an A in the class by subtracting the given values from the total number of students.
Total students = 29
Female students = 19
Male students = Total students - Female students = 29 - 19 = 10
Students with an A = 14
Male students without an A = 8
To calculate the number of male students with an A, we subtract the number of male students without an A from the total number of male students.
Male students with an A = Male students - Male students without an A = 10 - 8 = 2
Therefore, there are 2 male students who have an A in the class.
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g(x) = -3x - 5, find g(4).
Step-by-step explanation:
putting the value of x in -3x-4 where x is 4 so the ans is -17
7.
Meredith spent $367.80 on tulip mand daffodil bulbs for her
flower bed. A bag of tulip bulbs Meredith spent $367.80 on tulip and daffodil bulbs for her flower bed. A bag of tulip bulbs cost $7.95 and daffodil bulbs cost $6.80 per bag. If she bought three times as many tulips as daffodils, how many bags did she buy of each kind?
tulips as daffodils, how many bags did she buy of each kind?
solve the following system of linear equations. Enter the solution as an ordered pair. For parametric solutions use x=t as the parameter. (If an answer does not exist, enter DNE.) {
−12x−14y=2
−6x−7y=−5
(x,y)=(
The solution to the systems of equations does not exist
Solving the systems of equations graphicallyFrom the question, we have the following parameters that can be used in our computation:
-12x - 14y = 2
-6x - 7y = -5
Next, we plot the graph of the system of the equations
See attachment for the graph
From the graph, we have solution to the system to be the point of intersection of the lines
The lines do not intersect
Hence, the system has no solution
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Under his cell phone plan, Joseph pays a flat cost of $66.50 per month and $5 per gigabyte. He wants to keep his bill at $83.50 per month. Write and solve an equation which can be used to determine gg, the number of gigabytes of data Joseph can use while staying within his budget.
John is saving to buy a new car that will cost him $24,000. John started his savings at the beginning of the school year and has been able to accumulate $1000 after the first month. John plans to continue his savings at a rate proportional to the amount he still needs to save. Determine John's savings amount as function of time Hint: A variable y is said to be proportional to a variable x if y=cx for some constant c.
John's savings amount as a function of time is S(t) = $24,000 / 25. Initially, he needs to save $24,000 for a new car. After the first month, he has saved $1,000. The savings amount is directly proportional to the time elapsed. The constant of proportionality is 1/24. Thus, John's savings amount can be determined based on the remaining amount he needs to save.
John's savings amount can be represented as a function of time and is proportional to the amount he still needs to save. Let's denote the amount John needs to save as N(t) at time t, and his savings amount as S(t) at time t. Initially, John needs to save $24,000, so we have N(0) = $24,000.
We know that John has saved $1,000 after the first month, which means S(1) = $1,000. Since his savings amount is proportional to the amount he still needs to save, we can write the proportionality as:
S(t) = k * N(t)
where k is a constant of proportionality.
We need to find the value of k to determine John's savings amount at any given time.
Using the initial values, we can substitute t = 0 and t = 1 into the equation above:
S(0) = k * N(0) => $1,000 = k * $24,000 => k = 1/24
Now we have the value of k, and we can write John's savings amount as a function of time:
S(t) = (1/24) * N(t)
Since John's savings amount is proportional to the amount he still needs to save, we can express the amount he still needs to save at time t as:
N(t) = $24,000 - S(t)
Substituting the expression for N(t) into the equation for S(t), we get:
S(t) = (1/24) * ($24,000 - S(t))
Simplifying the equation, we have:
24S(t) = $24,000 - S(t)
25S(t) = $24,000
S(t) = $24,000 / 25
Therefore, John's savings amount at any given time t is S(t) = $24,000 / 25.
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Can someone help me please???
Answer:
1. CHECK
2. CHECK
Step-by-step explanation:
i hole it helps
Let x, y, and z represent three rational numbers, such that y is 5/12 times x and z is 50.25 more than x. If y=15.5, what is the value of z?
From the system of linear equations was verified that the value for z is equal to 87.45.
System of Linear EquationsSystem of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.
Rational NumbersThese numbers are represented by a ratio between two integers numbers (\(\frac{a}{b}\)), where b\(\neq\)0. Besides, this ratio can be simplified in decimal form.
For solving this equation, firstly, rewrite the information given:
\(y=\frac{5}{12} x \;(1)\\ \\ z=50.25+x \;(2)\\ \\ y=15.5 \;(3)\)
As the question gives the values for y, you can find x.
\(y=\frac{5}{12} x\\ \\ 15.5=\frac{5}{12} x\\ \\ 5x=12*15.5 \\ \\ x=\frac{186}{5}=37.2\)
Applying x=37.2 in equation (3), you can find z.
\(z=50.25+x \\ \\ z=50.25+37.2\\ \\ z=87.45\)
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A sample of 46 task has been considered and was analyzed. It was found out that the values 35 and 2.9 are obtained for the sample mean and the population standard deviation, respectively. Construct a 95% confidence interval for the population mean. Solve the following questions and express your final answer in 2 decimal places whenever possible.lower confidence interval of the population mean
The lower confidence interval of the population mean is 34.16.
To construct a 95% confidence interval for the population mean, we can use the formula:
CI = sample mean ± (z-score)(standard error)
Where the z-score is determined by the level of confidence and can be found using a z-table or calculator. For a 95% confidence interval, the z-score is 1.96.
The standard error can be calculated using the formula:
standard error = population standard deviation / √(sample size)
Substituting the given values, we get:
standard error = 2.9 / √46 = 0.427
Now we can plug in the values into the formula to get the confidence interval:
CI = 35 ± (1.96)(0.427) = 35 ± 0.837
The lower confidence interval of the population mean is obtained by subtracting the margin of error from the sample mean:
lower confidence interval = 35 - 0.837 = 34.16 (rounded to 2 decimal places)
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find the volume of the cylinder
Step-by-step explanation:
8 volume
The turtle's distance from his starting point is increasing between seconds. The turtle's distance from his starting point is constant between seconds. The turtle's distance from his starting point is decreasing between seconds.
Answer: 10 seconds, decreasing, standing still,
Step-by-step explanation:
A petting zoo gives out large buckets of healthy popcorn snacks for visitors to feed to the animals. what fraction of the snack is left in the bucket after a cow eats 1/3, a goose eats 1/12, and a goat eats 2/9?
Answer:
13/36 is left
Step-by-step explanation:
cow- 1/3 = 12/36
goose- 1/12 = 3/36
goat= 2/9 = 8/36
12 + 3 + 8 = 23/36
23/36 is consumed...
13/36 is left
The fraction of the snack left in the bucket will be 13/36.
What is a fraction?The fraction is defined as the division of the whole part into an equal number of parts.
Given that:
cow- 1/3 = 12/36goose- 1/12 = 3/36goat= 2/9 = 8/36The amount consumed is:-
( 12/ 36 )+ (3 / 36 ) +( 8 / 36 ) = 23/36
So the amount left will be calculated as:-
Amount left = 1 - ( 23 / 36 )
Amount left = ( 36 - 23 ) / 36
Amount left = 13 / 36
Therefore fraction of the snack left in the bucket will be 13/36.
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suppose a clothing store wants to determine the current percentage of customers who are over the age of forty. how many customers should the company survey in order to be 98% confident that the estimated (sample) proportion is within 2 percentage points of the true population proportion of customers who are over the age of forty?
The company survey 307 customers in order to get 98% confidence.
Sample proportion (p) = 0.5 (as no estimate is given)
α = 1 - 92% = 0.08. Therefore, α/2 = 0.08/2 = 0.04
Z(α/2) = Z(0.04) = 1.751
Estimate = 5% = 0.05
Now, E = Z(α/2) * sqrt (p(1-p)/n)
n = (1.751/0.05)2 * 0.5 * (1-0.5)
n = 307
Hence, the company should survey 307 customers in order to be 98% confident that the estimated (sample) proportion is within 2 percentage points of the true population proportion of customers who are over the age of forty.
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pls help reward brainliestt
formula for axis of symmetry is
-b/2a
so
-(-6)/2
= 6/2
= 3
x = 3
5. What values of A, B and C will make the following two planes be parallel? What values will make them be perpendicular? T₁ = 2x - 5y + z-4 = 0 and 2 = Ax+By+ Cz + 10 = 0 [4 marks]
The values of A, B, and C that make the two planes parallel are: A = (5B - C)/2and5B - 3C = |N₁||N₂|/2 and The values of A, B, and C that make the two planes perpendicular are: A = (5B - C)/2and5B - 3C = 0.
Let's have a look at the planes. They are:
T₁ = 2x - 5y + z - 4 = 0 and T₂ = Ax + By + Cz + 10 = 0
Now we will try to solve the question using the concepts of vector and normal to the plane.
The vector and normal to the plane can be defined as follows:
A plane is a 2-dimensional surface that is defined by three points.
A normal is a vector that is perpendicular to the plane.
A vector is a quantity that has both magnitude and direction. Let's calculate the normal to both planes using the coefficients of x, y, and z in the equation of the planes.
The equation of the normal to a plane is given by:
N = ai + bj + ck where a, b, and c are the coefficients of x, y, and z in the equation of the plane.
Let's first find the normal to T₁.
The coefficients of x, y, and z are 2, -5, and 1, respectively.
Therefore, the normal to T₁ is given by:
N₁ = 2i - 5j + k
Now let's find the normal to T₂. The coefficients of x, y, and z are A, B, and C, respectively. Therefore, the normal to T₂ is given by:
N₂ = Ai + Bj + Ck
Now that we have found the normals to the two planes, we can determine if they are parallel or perpendicular based on the dot product of the two normals.
The dot product of two vectors is given by:
A.B = |A||B|cosθwhere A and B are two vectors, |A| and |B| are their magnitudes, and θ is the angle between them.
If the dot product of the two normals is zero, then the planes are perpendicular. If the dot product of the two normals is not zero, then the planes are parallel. In this case, we need to find the values of A, B, and C that make the two planes parallel or perpendicular.
Now let's find the dot product of the two normals:
N₁.N₂ = 2A - 5B + C
If the two planes are parallel, then their normals are parallel, which means that the dot product of the two normals is equal to the product of their magnitudes.
Therefore:
N₁.N₂ = |N₁||N₂|I
f the two planes are perpendicular, then their normals are perpendicular, which means that the dot product of the two normals is zero.
Therefore:
N₁.N₂ = 0
Now let's find the values of A, B, and C that make the two planes parallel or perpendicular. If the two planes are parallel, then their normals are parallel.
Therefore, the dot product of the two normals is equal to the product of their magnitudes.
Therefore:
2A - 5B + C = |N₁||N₂|I
f the two planes are perpendicular, then their normals are perpendicular.
Therefore, the dot product of the two normals is zero.
Therefore:2A - 5B + C = 0
Now let's solve the two equations for A, B, and C.
2A - 5B + C = |N₁||N₂|2A - 5B + C = 0A = (5B - C)/2
Substituting this value of A into the equation 2A - 5B + C = |N₁||N₂|, we get:
5B - 3C = |N₁||N₂|/2
Therefore, the values of A, B, and C that make the two planes parallel are:
A = (5B - C)/2and5B - 3C = |N₁||N₂|/2
The values of A, B, and C that make the two planes perpendicular are:
A = (5B - C)/2and5B - 3C = 0
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Which of the following number lines shows the correct sum of the number above and -5/2?
A.
B.
C.
D.
shirabi spent $208 on a sewing machine to make purses. she spends a total of $10 on thread, fabric, and accessories for each purse and plans to charge $36 for each purse. the equation represents her break-even point, when x represents the number of purses sold. 208 10x
Shirabi needs to sell a minimum of 20 purses in order to reach her break-even point, where her total revenue equals her total costs.
To find the break-even point, we need to determine the number of purses that Shirabi needs to sell in order to cover her costs and not incur any loss. The equation representing her break-even point is given as:
208 + 10x
Here, 208 represents the cost of the sewing machine, and 10x represents the total cost of thread, fabric, and accessories for each purse, multiplied by the number of purses sold.
To find the break-even point, we need to set the equation equal to zero:
208 + 10x = 0
Now, let's solve for x:
10x = -208
x = -208/10
x = -20.8
Since the number of purses sold cannot be negative, we can disregard the negative solution. Therefore, Shirabi's break-even point is when she sells 20 purses.
Shirabi needs to sell a minimum of 20 purses in order to reach her break-even point, where her total revenue equals her total costs. Selling fewer than 20 purses would result in a loss, while selling more than 20 purses would generate a profit.
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Which of the situations below probably does not have a lurking variable operating in some way?Choose the best answer. A. When sales of cold medication go up, sales of ice cream go down. B. Beaches with more sand than rocks tend to be older. O C. Small dogs bite more people than large dogs nationwide, but in both rural areas and urban areas, large dogs are more likely to bite people. D, Neighborhoods with more station wagons tend to have more playgrounds. E Towns that have more teachers have higher sales of floor wax and cat litter.
The situation that probably does not have a lurking variable operating in some way is, option D: Neighborhoods with more station wagons tend to have more playgrounds. So, the correct option is, option D.
This is because it is unlikely that there is a hidden variable that is causing both the presence of station wagons and the presence of playgrounds. It is possible that neighborhoods with more families and children tend to have both more station wagons and more playgrounds, but this is not a hidden variable as it is already known and understood.
In contrast, the other options all involve relationships between variables that could be explained by a hidden variable.
For example, in option A, it is possible that the lurking variable is the weather, which affects both the sales of cold medication and the sales of ice cream.
Similarly, in option E, the lurking variable could be the overall economic health of the town, which affects both the number of teachers and the sales of floor wax and cat litter.
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Solve the following inequality for x. -26+13r+2r greater than 2- 13r
Answer: r > 1
Step-by-step explanation:
Since there is no x in this I'm assuming we are looking for r
Step 1: Simplify both sides
15r - 26 > -13r + 2
Step 2: Add 13r to both sides
15r - 26 + 13r > -13r + 2 + 13r
28 - 26 > 2
Step 3: Add 26 on both sides
28 - 26 + 26 > 2 + 26
28r > 28
Step 4: Divide both sides by 28r / 28 > 28 / 28
r > 1
Hope this helped!
Which factor do 64x2 + 48x + 9 and 64x2 – 9 have in common?
Answer:
They have the factor (8x +3) in common.
Explanation:
Factorize 1
64x² + 48x + 9
64x² + 24x +24x + 9
8x(8x +3) +3(8x +3)
(8x +3)(8x+3)
Factorize 2
64x² – 9
(8x)² – 3²
\(\sf {Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)\)
(8x-3)(8x+3)
Suppose you run a simulation model several times with different order quantities. What can we infer about the quantity that maximizes the output, the company’s profit?
A. This quantity is the optimal order quantity.
B. This quantity might be the optimal order quantity, but we also need to consider the company’s attitude toward risk.
C. This is not necessarily the optimal order quantity, because it may have produced the largest profit by luck.
D. We can’t infer anything.
B. This quantity might be the optimal order quantity, but we also need to consider the company’s attitude toward risk.
How can we say so?Simulation models are useful tools for predicting the outcomes of different scenarios, but they are not always accurate representations of reality. Running a simulation model several times with different order quantities can give an indication of the order quantity that maximizes the output, but it does not guarantee that this is the optimal order quantity.
There are many factors that can affect the outcome of a simulation model, such as the model's assumptions, limitations, and inputs. Additionally, simulation models are subject to randomness and variability, so the results of different runs may vary.
For this reason, it is important to consider other factors, such as the company's attitude toward risk, when making decisions based on the results of a simulation model. The company's attitude toward risk can influence the choice of order quantity and affect the overall outcome of the simulation.
Therefore, while the order quantity that maximizes the output in a simulation model might be a good starting point, it is not necessarily the optimal order quantity. Further analysis and consideration of other factors is necessary to determine the best order quantity for the company.
What is ratio?A ratio is a mathematical expression that compares the relative size of two or more values. It is a way of expressing the relationship between two or more quantities in terms of their relative size.
A ratio can be expressed in different ways, such as a fraction, decimal, or percentage. For example, the ratio of 2 to 4 can be expressed as 2/4, 0.5, or 50%.
Ratios are used in many areas of mathematics and science, such as finance, economics, engineering, and physics, to describe and analyze relationships between quantities. For example, in finance, ratios are used to measure a company's financial performance, such as its profitability, liquidity, and debt-to-equity ratios. In engineering, ratios are used to describe the relationship between the size and power of a machine, such as the gear ratio in a car's transmission.
In general, ratios are useful for comparing quantities and understanding the relationships between them, and they play a key role in many aspects of mathematics and science.
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A bag contains twenty $\$1$ bills and five $\$100$ bills. You randomly draw a bill from the bag, set it aside, and then randomly draw another bill from the bag. What is the probability that both bills are $\$1$ bills
The probability that both bills are $1 is 0.76
How to determine the probabilityFollowing the selection of one $1 bill, the remaining number of $1 bills in the bag is reduced to 19.
Based on statistical analysis, there is a high likelihood of selecting a $1 bill on the second attempt, with a confidence level of 95%.
The probability of drawing two $1 bills is mathematically deduced to be zero. The attainment of a numerical outcome of 76 is contingent upon the computation of the product derived from the probability of selecting a $1 bill during the initial endeavor, which stands at 4 out of 5, and the likelihood of selecting another $1 bill in a consequent endeavor, which amounts to 19 out of 20.
In an alternative expression, the probability of two bills being $1 bills simultaneously is 76%.
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Solve the equation { (2n – 1) =
7
12
for n.
n =
WHAT'S THE RANGEE??
Answer:
-2 < y ≤ 10
Step-by-step explanation:
The graph's lowest point is at y = -2, and the graph's highest point is at y = 10, so we know it would start off with -2 and end with 10. The dot at the lowest point is not shaded in, indicating that the graph does not include -2. So, we would represent this exclusion in our inequality with a less than (<) sign. As for the highest point at y = 10, it is shaded in, indicating that the graph does include 10. We would show this in our inequality with a less than or equal to sign (≤)
Here is a partially-completed multiplication table. If you know that a . a = a²= b , a . b = a . a² = a³=c , a⁴ = d, and a₅ = a how would you complete the table? What is a⁹⁹ ? Explain your reasoning.
To complete the table, we used the given information to fill in the missing entries. We then determined the pattern of a to the power of n, where n is greater than or equal to 5. a⁹⁹ falls into the "c" column.
To complete the multiplication table, we can use the given information:
a . a = a² = b
a . b = a . a² = a³ = c
a⁴ = d
a₅ = a
Using this information, we can fill in the missing entries in the table step-by-step:
1. Start with the row and column labeled "a". Since a . a = a² = b, we can fill in the entry as "b".
2. Next, we move to the row labeled "a" and the column labeled "b". Since a . b = a . a² = a³ = c, we can fill in the entry as "c".
3. Continuing in the same manner, we can fill in the remaining entries in the table using the given information. The completed table would look like this:
| a | b | c | d
---------------------------------------
a | b | c | d | a
b | c | d | a | b
c | d | a | b | c
d | a | b | c | d
Now, to find a⁹⁹, we can notice a pattern. From the completed table, we can see that a⁵ = a, a⁶ = a² = b, a⁷ = a³ = c, and so on. We can observe that a to the power of n, where n is greater than or equal to 5, will repeat the pattern of a, b, c, d. Since 99 is not divisible by 4, we know that a⁹⁹ will fall into the "c" column.
Therefore, a⁹⁹ = c.
In summary, to complete the table, we used the given information to fill in the missing entries. We then determined the pattern of a to the power of n, where n is greater than or equal to 5. Using this pattern, we concluded that a⁹⁹ falls into the "c" column.
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An advertisement for a box of crackers says that the new box has 20% more crackers than the original box. If the weight of the original box was 12 ounces, what is the weight of the new box of crackers?
Based on the weight of the old box of crackers, we can infer that the weight of the new box is 14.4 ounces.
The old box weighed 12 ounces and the new box has 20% more than the old box had.
The new box should therefore weigh 20% more than the old box which means that it weighs:
= Weight of old box x ( 1 + increase in new box)
= 12 x (1 + 20%)
= 14.4 ounces
In conclusion, the new box weighs 14.4 ounces.
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