Answer:
500j i got it right on a test
Explanation:
The motion of an object at a constant speed along a circular path is known as:
A. Uniform horizontal motion
B. Uniform vertical motion
C. Uniform circular motion
D. Rectilinear motion
Answer:
the motion of an object at a constant speed along a circular path is known as Uniform circular motion
An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.
The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.
To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.
Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.
Using the formula, we can calculate the distance traveled as follows:
d = rt
d = 130 mph × 2.5 hours
Multiplying the rate (130 mph) by the time (2.5 hours) gives us:
d = 325 miles
Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.
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x Methane, has a molar mass of 16.03 grams per mole. How many particles o of methane are present in 120 grams?
In order to determine the number of particles of methane, use the following expression:
number of particles = (mass /molar mass ) x Avogadro's number
in this case, you have:
molar mass = 16.03 grams/mole
mass = 120 grams
Avogadro's number = 6.02*10²³ particles/mol
replace the previos values of the parameters into the formula for the number of particles:
number of particles=(120 grams/ 16.03 grams/ mol)x(6.02*10²³particles/mol)
= (7.46 mol) x (6.02*10²³ particles/mol)
= 4.50*10²⁴ particles
Hence, the number of particles of methane, in 120 grams, is 4.50*10²⁴
A household uses the following electric appliances:
refrigerator of rating 400W for 10 hours each day.
two electric fans of rating 80 W for 6 hours daily.
Six electric tubes of rating 18 W for 6 hours daily.
Calculate the electricity bill for the household for month of June if cost of electricity energy is ₹ 3.00 per unit
The electric bill for the household for the month of June is ₹ 504.72
How do I deterrmine the electric bill for the month of june?We'll begin by obtaining the energy consumed. This is shown below:
For fridge:
Power = 400 WTime = 10 hoursEnergy for fridge =?Energy = power × time
Energy for fridge = 400 × 10
Energy for fridge = 4000 Wh
Divide by 1000 to express in KWh
Energy for fridge = 4000 / 1000
Energy for fridge = 4 kWh
For fan:
Power = 80 WTime = 6 hoursEnergy for fan =?Energy = power × time
Energy for fan = 80 × 6
Energy for fan = 480 Wh
Divide by 1000 to express in KWh
Energy for fan = 480 / 1000
Energy for fan = 0.48 kWh
Energy for 2 fans = 2 × 0.48 = 0.96 kWh
For tube:
Power = 18 WTime = 6 hoursEnergy for tube =?Energy = power × time
Energy for tube = 18 × 6
Energy for tube = 108 Wh
Divide by 1000 to express in KWh
Energy for tube = 108 / 1000
Energy for tube = 0.108 kWh
Energy for 6 tubes = 6 × 0.108 = 0.648 kWh
Total energy consumed per day = 4 + 0.96 + 0.648 = 5.608 kWh
Total energy consumed per month = 30 × 5.608 = 168.24 kWh
Finally, we shall determine the electric bill for the month of june. Details below:
Cost per KWh = ₹ 3.00Total energy (E) = 168.24 KWhElectric bill for June =?Electric bill = energy × Cost per KWh
Electric bill for June= 168.24 × 3
Electric bill for June = ₹ 504.72
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What is the flux through any closed surface surrounding a cylinder with surface charge densityσ = k sin φ , where k is a constant. Its height is H , and its radius is R.
The flux through any closed surface surrounding a cylinder with height H and radius R having surface charge density σ = k sin φ, where k is a constant, is φ₀=2πRLk sin φ/ε₀.
Since the cylinder's surface charge density is given by σ = k sin φ
Therefore, the total charge on the cylinder's curved surface
Q = σ(2πRL)
Where L is the height of the cylinder, Q = 2πRLk sin φ .
From Gauss's Law, the total flux through a closed surface surrounding a cylinder with height H and radius R is given by φ₀=Qε₀ .Here, ε₀ represents the vacuum permittivity. Now, substituting the value of Q, we get
φ₀ = (2πRLk sin φ)/ε₀
Therefore, the flux through any closed surface surrounding a cylinder with height H and radius R having surface charge density σ = k sin φ, where k is a constant, is φ₀=2πRLk sin φ/ε₀.
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A 40W lamp wastes 34 J of energy every second by heating its surroundings.
What is the efficiency of the lamp?
С
18%
D
85%
A
0.15%
15%
B
Answer:
\(15\%\).
Explanation:
The efficiency of a machine is the percentage of energy input that was turned into useful energy.
The power rating of this lamp is \(40\; \rm W\) (same as \(40\; \rm J \cdot s^{-1}\),) meaning that \(40\; \rm J\) of energy is supplied to this lamp every second.
The question states that \(34\; \rm J\) out of that \(40\; \rm J\) of energy input would be turned into heat, which is not useful energy output in this scenario. Assuming that all other forms of energy loss is negligible. The rest of the \((40\; \rm J - 34\; \rm J) = 6\; \rm J\) of energy supplied to this lamp would be turned into useful energy output.
Thus, every second, this lamp would receive \(40\; \rm J\) of energy input and would outputs \(6\; \rm J\) of useful work. The efficiency of this lamp would be:
\(\begin{aligned}& \text{Efficiency} \\ =\; & \frac{\text{Useful energy out}}{\text{Total energy in}} \times 100\% \\ =\; & \frac{6\; \rm J}{40\; \rm J} \times 100\%\\ =\; &15\% \end{aligned}\).
define steam distillation
Answer:
Steam distillation is a separation process which consists in distilling water together with other volatile and non-volatile components.
1.What happens to the Angle of Refraction as the medium becomes denser? Explain why.
Answer:
Explanation:
If angle of incidence and angle of refraction be i and r respectively ,
sini / sinr = μ ( refractive index )
sin r = sin i / μ
If angle of incidence i be constant and medium becomes denser that means μ becomes higher in value , the value of sin r will be low ( because of increase in value of denominator )
As sin r decreases , r also decreases also.
Hence when medium becomes denser , angle of refraction becomes less .
compound name: for C3N6
Answer:
C3N6 is also known as propene(Meythlethylene)
Explanation:
Propene has 3 Carbon molecules and 6 nitrogen molecules. This makes the new substance a non-metal.
a mouse of mass 27.0 g falls 200 m down a vertical mine shaft and lands at the bottom with a speed of 8.1 m/s. during its fall, how much work (in j) is done on the mouse by air resistance?
Work is done on the mouse by air resistance 25.574 Joule.
Work is done every time a force moves something over a displacement. you can calculate the electricity transferred, or paintings done, by using multiplying the force via the gap moved in the course of the force. strength transferred = work achieved = pressure x distance moved within the direction of the pressure.
Work to be accomplished, a force must be exerted and there must be motion or displacement in the route of the pressure. The work done by way of a force appearing on an object is the same as the significance of the pressure accelerated by way of the space moved within the route of the force.
given,
mass = 27.0 g = 0.027 kg
Height H = 200 m
initial speed u = 0 m/s
final speed V = 8.1 m/s
force = mg
= 0.027 × 9.8
= 0.2646 N
1/2mu² + mgh = mgh + 1/2mv²
0 + 0.027×9.8 ×100 = 0 + 1/2×0.027× (8.1)² + air reesistance
initial energy = 26.46 J
final energy = 0.886 J
air resistance = 26.46 J - 0.886 J
= 25.574 Joule
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After Sophia eats her body breaks down the food to use as an engery source when she runs this is an example of which type of engery conversion
Answer:
cannibalism
Explanation:
because she is eating her body!
GIVING BRAINLIEST
In addition to having a blue color, what other characteristic do Neptune and Uranus share?
no rings
27 moons
no axis tilt
cold temperatures
Answer:
Cold temps. . .
Explanation:
Hope it helps!
(Table 310-15(a)(16)): What size conductor is required to feed a 16 ampere load when the conductors are in an ambient temperature of 100F? The circuit is protected with a 20-ampere overcurrent protection device.
To determine the size of the conductor required to feed a 16 ampere load with a 20-ampere overcurrent protection device, we need to use the National Electric Code (NEC) ampacity tables.
For conductors in an ambient temperature of 100°F, we need to use the 90°C column of the tables. Based on NEC Table 310.16, a 14 AWG copper conductor can handle up to 20 amperes at 90°C. Therefore, a 14 AWG copper conductor would be sufficient to feed the 16 ampere load and protect the circuit with a 20-ampere overcurrent protection device.
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Full Question: What size conductor is required to feed a 16 ampere load when the conductors are in an ambient temperature of 100F? The circuit is protected with a 20-ampere overcurrent protection device.
A 140-Hz sound travels through pure carbon dioxide. The wavelength of the sound is measured to be 1.92 m. What is the speed of sound in carbon dioxide?
Answer:
V = 268.8 m/s
Explanation:
The speed of a wave in general is given by the following formula:
V = fλ
where,
V = Speed of that wave
f = Frequency of the wave
λ = wavelength of the wave
In this case we have a sound wave, travelling across carbon dioxide. The properties of sound wave are as follows:
V = Speed of Sound in Carbon dioxide = ?
f = frequency of sound wave = 140 Hz
λ = wavelength of sound wave = 1.92 m
Therefore,
V = (140 Hz)(1.92 m)
V = 268.8 m/s
A weight lifter benches a bar a vertical distance of 1.5m. What is the work done on the weights if the lifter exerts a constant force of 1000N?
Answer: 1500 Joules
Explanation: To calculate the work done by the weight lifter, we can use the formula:
Work = Force x Distance x cos(theta)
where "Force" is the force applied by the weight lifter, "Distance" is the vertical distance that the weight is lifted, and "theta" is the angle between the direction of the force and the direction of the displacement.
In this case, the force applied by the weight lifter is 1000N and the vertical distance lifted is 1.5m. Since the force is applied vertically upwards and the displacement is also vertical, the angle between the direction of the force and the direction of the displacement is 0 degrees (cos(0) = 1).
Therefore, the work done by the weight lifter is:
Work = 1000N x 1.5m x cos(0) = 1500 Joules
So the work done by the weight lifter on the weights is 1500 Joules.
1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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why are star clusters almost ideal "laboratories" for stellar studies?
Overall, star clusters provide a unique opportunity to study the properties and evolution of stars in a controlled and relatively simple environment, which can help us better understand the processes that govern the life cycles of stars.
Star clusters are almost ideal "laboratories" for stellar studies for several reasons:
Stellar populations: Star clusters are made up of stars that formed around the same time and from the same cloud of gas and dust. This means that the stars in a cluster have similar ages and compositions, which makes it easier to study their properties and evolution.
Distance: Star clusters are relatively close to Earth, which makes them easier to observe and study in detail. This is because the stars in a cluster are all at roughly the same distance from us, which eliminates distance-related uncertainties and allows us to accurately measure their properties.
Large numbers: Star clusters contain a large number of stars packed into a relatively small region of space. This means that we can observe and study many stars at once, which allows us to gather statistical data on the properties of stars and their evolution.
Interactions: Star clusters are dynamic environments, and the gravitational interactions between stars can affect their evolution. Studying star clusters allows us to observe and understand the effects of interactions between stars, such as binary star systems, stellar collisions, and gravitational interactions between stars.
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can anyone help me with this , thank you
Answer:
1.) A
2.) B
4.) A
17.) B
Explanation:
Im sure tama ako nasagot kona
to ehh
which of the following telescope is the best option if visible radiation is blocked? a ultraviolet telescope b. lnfrared telescope cradio telescope o ray telescope
The telescope that is the best option if visible radiation is blocked is b. infrared telescope
If visible light is obscured, an infrared telescope is generally used. Since infrared radiation has longer wavelengths than visible light, infrared telescopes are made to detect and study this type of electromagnetic energy. They may also view various celestial things and phenomena that mostly emit infrared light thanks to this.
While radio telescopes are employed to determine and study radio waves, X-ray telescopes are used to watch X-rays, and UV telescopes are utilized to observe ultraviolet light. None of these alternatives is intended to deal with the situation where visible radiation is blocked. However, in these circumstances, infrared telescopes can still deliver useful observations.
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Complete Question:
Which of the following telescope is the best option if visible radiation is blocked?
a. ultraviolet telescope
b. lnfrared telescope
c. radio telescope
d. ray telescope
Determine the maximum constant speed at which the pilot can travel around the vertical curve having a radius of curvature p = 800 m, so that he experiences a maximum acceleration an = 8g = 78.5 m/s2. If he has a mass of 70 kg, determine the normal force he exerts on the seat of the airplane when the plane is traveling at this speed and is at its lowest point.
The maximum constant speed at which the pilot can travel around the vertical curve with a radius of curvature of
p = 800 m so that he experiences a maximum acceleration of
an = 8g = 78.5 m/s2 is 89.4 m/s.
Given data:
Radius of curvature p = 800 m
Maximum acceleration an = 8g = 78.5 m/s²
Mass of the pilot m = 70 kg
Maximum speed v for the plane is given as follows:
an = (v²) / pm
g = (v²) / p78.5 m/s²
= (v²) / (800 m)
where v is the velocity and an is the maximum acceleration Let's solve the above equation for v to determine the maximum constant speed:
v² = 78.5 m/s² × 800
mv² = 62800
v = √62800
v = 250.96 m/s
The pilot can travel at a maximum speed of 250.96 m/s
to experience a maximum acceleration of 8g if we consider the theory of relativistic mass increasing with speed.
So we need to lower the speed to achieve 8g.
For a safe speed, let's take 80% of the maximum speed; 80% of 250.96 m/s = 200.768 m/s
Therefore, the maximum constant speed that the pilot can travel around the vertical curve having a radius of curvature p = 800 m,
so that he experiences a maximum acceleration an = 8g = 78.5 m/s2, is 200.768 m/s.
When the plane is traveling at this speed and is at its lowest point, the normal force he exerts on the seat of the airplane is;
N = m(g + an)
Here, m = 70 kg, g = 9.81 m/s²,
and an = 78.5 m/s²
N = (70 kg)(9.81 m/s² + 78.5 m/s²)
N = 5662.7 N (approx)
Therefore, the normal force the pilot exerts on the seat of the airplane when the plane is traveling at the maximum constant speed and is at its lowest point is 5662.7 N.
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Korbel pushes a 15 kg chair for a distance of 30 meters. How much
work did he do?
The work that has been done by the Korbel is 4.41kJ.
What is the work done?We have to note that we define work in physics as the product of the force and the distance. In the case of the chair in the question, we have been told that Korbel pushes a 15 kg chair for a distance of 30 meters.
The force in this case would be the weight of the chair that we have and we can write that;
W = mgh
m = mass
g = acceleration due to gravity
h = height
Thus
W = 15 * 9.8 * 30
W = 4.41kJ
Thus a work of about 4.41kJ is done.
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A fly undergoes a displacement of -5. 80 m while accelerating at -1. 33 m/s for 4. 22 s what was the initial velocity of the fly.
The fly has an average velocity of
v[ave] = ∆x/∆t = (-5.80 m) / (4.22 s) ≈ -1.37 m/s
If its acceleration is constant, then its average velocity is also equal to the average of its initial and final velocities,
v[ave] = (v[initial] + v[final]) / 2
which tells us that
v[initial] ≈ -1.37 m/s - 1/2 v[final]
The fly's final velocity after some time t is given by
v[final] = v[initial] + (-1.33 m/s²) t
so that after 4.22 s, we have
v[final] ≈ v[initial] - 5.61 m/s
Substitute this into the equation for v[initial] :
v[initial] ≈ -1.37 m/s - 1/2 (v[initial] - 5.61 m/s)
Solve for v[initial] :
3/2 v[initial] ≈ -1.37 m/s + 1/2 (5.61 m/s)
⇒ v[initial] ≈ 0.955 m/s
7) Your Grandma is following behind you on the trip to Dallas, but she refuses to drive
faster than 60 miles per hour. If she drives at that speed for the entire trip, how much
later will she arrive in Dallas
Answer:
Grandma will arive \(\frac{1}{2}\)hr later
Explanation:
\(s=20\\d=210 mi|\\ s=70 mi|h \\ \\ \frac{60}{1} =\frac{210}{+} = 3.5 hrs\)
Adam is studying forces in the lab. If he applies an unbalanced force to an object, what could happen?
A. Only the object's speed can change.
B. Only the object's direction can change.
C. Neither the object's speed nor direction can change.
D. The object's speed, direction, or both can change.
Neither the object's speed nor direction can change
Answer:
D. The object's speed, direction, or both can change.
Explanation:
If Adam applies an unbalanced force to an object, the object's speed, direction, or both can change. This is because an unbalanced force causes an acceleration, which can result in changes in both speed and direction.
Let's consider some examples to better understand this concept. Imagine Adam pushes a book on a table with a greater force in one direction. If the force is greater than the friction between the book and the table, the book will start moving in the direction of the force. This change in direction is caused by the unbalanced force applied by Adam.
Now, let's say Adam applies a constant force to a ball on the ground. If the force is greater than the friction between the ball and the ground, the ball will start rolling and its speed will increase. Again, this change in speed is due to the unbalanced force applied by Adam.
In summary, when an unbalanced force is applied to an object, it can cause changes in the object's speed, direction, or both. So, the correct answer is D: The object's speed, direction, or both can change.
Calculate the speed of an 6.4 × 104
kg airliner
with a kinetic energy of 1.1 × 109
J.
If a 6.4 × 10^4 kg airliner with a kinetic energy of 1.1 × 10^9J, then the speed of the airliner is 131.17 meters per second.
To calculate the speed of an airliner with a given kinetic energy, we can use the formula for kinetic energy:
Kinetic energy (KE) = (1/2) * mass * velocity^2
Given:
Mass of the airliner (m) = 6.4 × 10^4 kg
Kinetic energy (KE) = 1.1 × 10^9 J
We can rearrange the formula to solve for velocity (v):
KE = (1/2) * m * v^2
Multiply both sides of the equation by 2:
2 * KE = m * v^2
Divide both sides of the equation by m:
(2 * KE) / m = v^2
Take the square root of both sides to solve for v:
v = √((2 * KE) / m)
Substituting the given values into the equation:
v = √((2 * (1.1 × 10^9 J)) / (6.4 × 10^4 kg))
Calculating the expression:
v ≈ √(1.71875 × 10^4 m^2/s^2)
v ≈ 131.17 m/s
Therefore, the speed of the airliner is approximately 131.17 meters per second.
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a 1000 kg rhinoceros running at its top speed of 15 m/s has a kinetic energy of a.bc X 10^ J. What are the values of a.b.c. and d?
Answer:
K.E = 1.13 × 10^5 J
When compared to;
K.E = a.bc X 10^d J
We can observe that;
a = 1
b = 1
c = 3
d = 5
Explanation:
Given;
Mass of rhinoceros m = 1000kg
Velocity v = 15m/s
The kinetic energy of the body at this speed is;
K.E = 0.5×mv^2 ........1
Substituting the values of m and v into equation 1;
K.E = 0.5×1000×15^2
K.E = 112500 J
K.E = 1.13 × 10^5 J
When compared to;
K.E = a.bc X 10^d J
We can observe that;
a = 1
b = 1
c = 3
d = 5
A student performed an investigation into the refraction of light in a transparent material.
The results are shown below:
The angle of refraction of the refracted ray through the material shown is 32o .
Use this information to calculate the critical angle of the transparent material
The critical angle of the transparent material is 35.3 degrees.
What is the critical angle?The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:
sin(critical angle) = sin(90 degrees) / sin(angle of refraction)
sin(critical angle) = 1 / sin(32 degrees)
sin(critical angle) = 0.574
critical angle = arcsin(0.574)
critical angle = 35.3 degrees
Therefore, the critical angle of the transparent material is 35.3 degrees.
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This sentence contains two errors in grammar usage. read the sentence and the question that follows.
after finishing dinner, the table was cleared by kim, and mark washed the dishes.
which version of the sentence has been edited correctly for grammar usage?
The correct sentence would be: "After finishing dinner, Kim cleared the table, and Mark washed the dishes."
The original sentence contains a misplaced modifier. To correct this, the sentence should be rewritten to indicate who performed each action.
This above version correctly indicates that Kim cleared the table and Mark washed the dishes. The original sentence suggests that the table cleared itself, which is a grammatical error. Additionally, the sentence should use past tense to indicate that the actions have already occurred.
By using "was cleared" and "washed," the original sentence is using a combination of past and present tense, which is also a grammatical error.
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What change happens when matter
changes states?
What specific type of tide has the smallest difference between high and low tide?
Answer: Neap tides
Explanation: Neap tides are tides that have the smallest tidal range, and they occur when the Earth the Moon, and the Sun form a 90o angle. They occur exactly halfway between the spring tides when the Moon is at first or last quarter.