Utilize a spring scale to apply pressure to the block. Calculate the block's acceleration and the applied force.
The puck is subject to equal amounts of gravitational and normal forces, but there is no frictional force acting on it. A satellite in a circular orbit moves closer to the object it is circling at a speed equal to the gravitational acceleration at the radius of the orbit. Objects in orbit are constantly falling free, just like in a falling elevator. Actually, lift and drag are two parts of a single aerodynamic force that acts on the ball. Lift acts perpendicular to the motion, while drag occurs in the opposite direction. On earth, gravity pulls things downward and toward the ground.
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Due to our ozone layer, ultraviolet astronomy must be done from space, true or false?
True, due to the protective nature of the ozone layer and the absorption of UV radiation, conducting ultraviolet astronomy from space is necessary to gather accurate and detailed data about celestial objects and phenomena emitting UV light.
The ozone layer plays a crucial role in protecting the Earth's surface from harmful ultraviolet (UV) radiation. It absorbs a significant portion of the Sun's UV rays, preventing them from reaching the surface and potentially causing damage to living organisms.
As a result, to observe and study ultraviolet astronomy, which involves the detection and analysis of celestial objects and phenomena emitting UV radiation, observations must be conducted from space. By observing from space, astronomers can bypass the Earth's atmosphere, including the ozone layer, and directly capture the UV light from celestial sources.
UV astronomy satellites and telescopes, such as the Hubble Space Telescope and the International Ultraviolet Explorer (IUE), have been specifically designed and deployed to conduct observations in the ultraviolet spectrum. These instruments are situated above the Earth's atmosphere, enabling them to capture and analyze UV radiation without interference from atmospheric absorption.
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Use the reaction to answer the question.
HCl + H2O → Cl–+ H3O+
Which statement about the reaction is correct?
(1 point)
HCl is an acid, and Cl– is its conjugate base.
HCl is an acid, and H3O+ is its conjugate base.
H2O is an acid, and Cl– is its conjugate base.
H2O is an acid, and H3O+ is its conjugate base.
Answer:
I think HCl is an acid and Cl-is its conjugate base
For the given equation HCl + H2O → Cl– + H3O+ the statement that is true is that HCl is an acid, and Cl – is its conjugate base, therefore the correct answer is option A .
What is a Chemical compound?A chemical compound is a combination of two or more either similar or dissimilar chemical elements.
For example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.
As given in the problem we have to find Which statement about the reaction is correct for the given chemical reaction,
HCl + H2O → Cl–+ H3O +
For the given equation HCl + H2O → Cl–+ H3O+ the statement that is true is that HCl is an acid, and Cl– is its conjugate base .
Thus, the correct answer is option A .
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the microwaves in a certain microwave oven have a wavelength of 12.2 cm. how wide must this oven be so that it will contain five antinodal planes of the electric field along its width in the standing wave pattern?
The frequency of the antinodal planes is f = 3 × \(10^1^1\) hz
Given, the wavelength is 12.2 cm = 0.122 m
The number of antinodal planes of the given electric field considered is given to be n = 5
The width can be mathematically represented as ;
l = nλ/ 2
l = 5 X 0.122/ 2
l = 0.305 m
The frequency of the errors made is mathematically represented as:
f = c / k
λk = wavelength of the microwave
this is equal to 0.122 X 0.02/ 5/2
λk = wavelength of the microwave = 0.122 X 0.02/ 5/2
so thus f = 3 X 10^8/ 0.000976
f = 3 × \(10^1^1\) hz
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What is the mean of 4, 6, 8, 20, 12?
10
00
5
Answer:
mean= sum of all values/ total no. of values
values given= 4,6,8,20,12
= 4+6+8+20+12/5
=50/5=10
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How long should a spring be stretched for it to store 45 J of energy? The force constant of the spring is
540N/m?
Answer:
x = 0.4 m
Explanation:
When a spring is stretched from its equilibrium position. Some energy is stored in the spring. This energy is called the elastic potential energy of the spring. The formula used to calculate the magnitude of this stored energy is given as follows:
P.E = (1/2)kx²
where,
P.E = Elastic Potential Energy Stored in the spring = 45 J
k = Spring Constant = 540 N/m
x = amount of stretching = ?
Therefore,
45 J = (1/2)(540 N/m)x²
x² = (45 J)(2)/(540 N/m)
x = √(0.167 m²)
x = 0.4 m
A toy rocket expels gas at the rate of 3kg/s. What is the initial force exerted on the rocket if it moves with the speed of 300 m/s?
Answer:
the initial force exerted on the rocket is 900 N
Explanation:
The computation of the initial force exterted on the rocket is shown below:
Force exerter = Rate of change of momentum
= 300 m/s × 3kg/s
= 900 N
hence, the initial force exerted on the rocket is 900 N
we simply multiplied the rate with its speed so that the force could come
A wooden block of 16N is placed on a rough surface. If the coefficient of friction between both surface is 0.25,the least horizontal force required to move the block is?
The least horizontal force required to move the block is 4.0 N.
What is static friction?A force that holds an object at rest is called static friction.
The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.
Weight of the block = 16 N
The coefficient of friction between both surface is 0.25,
Hence, the least horizontal force required to move the block is = frictional resistance force
= 0.25 × 16 N
= 4 N.
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Which of the following conditions must be met to have electric current flow through
a circuit?
The circuit must be a closed loop.
The circuit must have a source of electric charges (energy).
A potential difference through the circuit must exist.
All of the above conditions are necessary for electric current flow.
Answer:
all of the above conditions are necessary for electric current to flow
Explanation:
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A rolling ball has 3,276) of energy, what is it's mass when it is rolling at a velocity of 53m/s? what is the mass
Initial velocity U = 0
Final velocity V = 32.23 m/s
Explanation:
Given that a coin is dropped from the top of the Tower of Pisa, 53m above the ground.
What is the coin's initial velocity ?
Since the coin is dropped from the tower, the initial velocity U will be equal to zero.
Therefore, U = 0
But the final velocity V will be calculated by using the formula
V^2 = U^2 + 2gH
V^2 = 0 + 2 × 9.8 × 53
V^2 = 1038.8
V = sqrt ( 1038.8)
V = 32.23 m/s
sorry if did not help :(
POSSIBLE 1. Which of the following are examples of a physical reactions: (1) ice melting, (2) pencil breaking, (3) iron rusting, (4) wood burning? a. 1.4 b. 3,4 c. 2.3 d. 1,2
Answer:
D) 1 & 2
Explanation:
Ice melting can be refrozen and although the pencil breaks, it doesn't change the chemical formula of the pencil
what is the domain of
I am made of many cells. My cells have
An organized nucleus.
I mostly have two parents, but
sometimes one. I make my own food
who am i?
Answer:
Eukarya
Explanation:
Only organisms of domain eukarya have an organized nucleus
A bullet of mass 0.5 kg is moving horizontally with a speed of 50 m/s when it hits a block
of mass 3 kg that is at rest on a horizontal surface with a coefficient of friction of 0.2.
After the collision the bullet becomes embedded in the block.
A) What is the net momentum of the bullet-block system before the collision?
B) Find the total energy of the bullet-block system before the collision?
C) What is the speed of the bullet-block system after the collision?
D) *Find the total energy of the bullet-block system after the collision?
E) *How much work must be done to stop the bullet-block system?
F) *Find the maximum traveled distance of the bullet-block after the collision?
Answer:
a) The net momentum of the bullet-block system before the collision is 25 kilogram-meters per second.
b) The initial translational kinetic energy of the bullet before the collision is 625 joules.
c) The final speed of the bullet-block system after the collision is 7.143 meters per second.
d) The total energy of the bullet-block system after the collision is 89.289 joules.
e) 89.289 joules must be done to stop the bullet-block system.
f) The bullet-block system will travel 13.007 meters before stopping.
Explanation:
a) Since no external forces are applied on the system defined by the bullet and the block, then the net momentum is conserved and can be calculated by the initial momentum of the bullet:
\(p = m\cdot v_{o}\) (1)
Where:
\(p\) - Net momentum, in kilogram-meters per second.
\(m\) - Mass of the bullet, in kilograms.
\(v_{o}\) - Initial speed of the bullet, in meters per second.
If we know that \(m = 0.5\,kg\) and \(v_{o} = 50\,\frac{m}{s}\), then the net momentum of the bullet-block system before the collision is:
\(p = (0.5\,kg)\cdot \left(50\,\frac{m}{s} \right)\)
\(p = 25\,\frac{kg\cdot m}{s}\)
The net momentum of the bullet-block system before the collision is 25 kilogram-meters per second.
b) The total energy of the bullet before the collision is its initial translational kinetic energy (\(K\)), in joules:
\(K = \frac{1}{2}\cdot m \cdot v_{o}^{2}\) (2)
\(K = \frac{1}{2}\cdot (0.5\,kg)\cdot \left(50\,\frac{m}{s} \right)^{2}\)
\(K = 625\,J\)
The initial translational kinetic energy of the bullet before the collision is 625 joules.
c) Both the bullet and the block experiments a complete inelastic collision, then the final speed of the bullet-block system is calculated solely by the Principle of Momentum Conservation:
\(v_{f} = \frac{m\cdot v_{o}}{m+M}\) (3)
Where:
\(v_{f}\) - Final speed, in meters per second.
\(M\) - Mass of the block, in kilograms.
If we know that \(m = 0.5\,kg\), \(v_{o} = 50\,\frac{m}{s}\) and \(M = 3\,kg\), then the final speed of the bullet-block system is:
\(v_{f} = \left(\frac{0.5\,kg}{0.5\,kg + 3\,kg} \right)\cdot \left(50\,\frac{m}{s} \right)\)
\(v_{f} = 7.143\,\frac{m}{s}\)
The final speed of the bullet-block system after the collision is 7.143 meters per second.
d) The total energy of the bullet-block system after the collision is the translational kinetic energy of the system (\(K\)), in joules, is:
\(K = \frac{1}{2}\cdot (m + M)\cdot v_{f}^{2}\) (4)
\(K = \frac{1}{2}\cdot (0.5\,kg + 3\,kg)\cdot \left(7.143\,\frac{m}{s} \right)^{2}\)
\(K = 89.289\,J\)
The total energy of the bullet-block system after the collision is 89.289 joules.
e) By Work-Energy Theorem, magnitude of the work done by friction must be equal to the magnitude of the translational kinetic energy of the system. Hence, 89.289 joules must be done to stop the bullet-block system.
f) The maximum travelled distance of the bullet-block after the collision can be determined by means of Work-Energy Theorem and definition of work:
\(W = \mu_{k}\cdot (m+M)\cdot g\cdot s\) (5)
Where:
\(W\) - Work done by friction, in joules.
\(g\) - Gravitational acceleration, in meters per square second.
\(s\) - Travelled distance, in meters.
\(\mu_{k}\) - Kinetic coefficient of friction, no unit.
If we know that \(m = 0.5\,kg\), \(M = 3\,kg\), \(\mu_{k} = 0.2\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(W = 89.289\,J\), then the travelled distance of the bullet-block system is:
\(s = \frac{W}{\mu_{k}\cdot (m+M)\cdot g}\)
\(s = \frac{89.289\,J}{0.2\cdot (0.5\,kg + 3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)
\(s = 13.007\,m\)
The bullet-block system will travel 13.007 meters before stopping.
use the result for the energy levels of the hydrogen atom to calculate the wavelengths of the first 5 lines of the balmer series. in what part of the electromagnetic spectrum do these lines fall?
The magnitude of the momentum of the 12,500-kg truck can be calculated using the formula:
Momentum = mass x velocity
So, Momentum = 12,500 kg x 16.5 m/s = 206,250 kg*m/s.
a. To find the speed of the 2250-kg SUV required to have the same momentum, we can use the same formula:
Momentum of SUV = mass of SUV x velocity of SUV
We know the momentum is the same, so we can set the two equations equal to each other:
12,500 kg x 16.5 m/s = 2250 kg x velocity of SUV
Solving for the velocity of SUV, we get:
Velocity of SUV = (12,500 kg x 16.5 m/s) / 2250 kg = 91.67 m/s
So, the SUV would need to be moving at a speed of 91.67 m/s to have the same momentum as the 12,500-kg truck.
b. To find the speed of the SUV required to have the same kinetic energy as the truck, we can use the formula:
Kinetic Energy = (1/2) x mass x velocity^2
We know the mass of the SUV and the kinetic energy is the same as the truck, so we can set the two equations equal to each other:
(1/2) x 12,500 kg x (16.5 m/s)^2 = (1/2) x 2250 kg x velocity^2
Solving for the velocity of SUV, we get:
Velocity of SUV = sqrt[(12,500 kg x (16.5 m/s)^2) / (2250 kg)] = 33.57 m/s
So, the SUV would need to be moving at a speed of 33.57 m/s to have the same kinetic energy as the 12,500-kg truck.
Friction was not used in the calculations, as it was not mentioned in the question.
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a particle is projected horizontally at 10m/s from the top of a tower 20m high.
calculate the horizontal distance travelled by the particle.( g=10m/s^2)
What factors do Presidents consider when choosing a Supreme Court Justice?
Answer:
Presidents use the same criteria: legal expertise, party affiliation, philosophy, an da sense of the acceptability to the Senate. Define majority opinion, concurring opinion, and dissenting opinion.
Explanation:
If a runner exerts 457 j of work to make 321 w of power then how long did it take the runner to do the work
The time taken by the runner to do the work is 1.42 seconds.
Given the data in the question;
Work done; \(W = 457J\)Power; \(P = 321W\)Time elapsed; \(t = \ ?\)PowerPower can be simply referred to as the quantity of energy transferred per unit time.
It is expressed as;
\(P = \frac{W}{t}\)
Where W is work done and t is time elapsed.
To determine the time it took the runner to do the work, we substitute our given values into the expression above.
\(P = \frac{W}{t} \\\\t = \frac{W}{P} \\\\t = \frac{457J}{321W} \\\\t = \frac{457 kgm^2/s^2}{321 kgm^2/s^3}\\\\t = 1.42s\)
Therefore, the time taken by the runner to do the work is 1.42 seconds.
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A mass-spring system can oscillate once every 2.5s when a 750 grammass is attached to it. What must the spring constant be to allow thisvibrational period?
Answer:
4.737 N/m
Explanation:
The period of a mass-spring system is calculated as
\(T=2\pi\sqrt{\frac{m}{k}}\)Where m is the mass and k is the spring constant. Solving for k, we get
\(\begin{gathered} \frac{T}{2\pi}=\sqrt{\frac{m}{k}} \\ \\ (\frac{T}{2\pi})^2=\frac{m}{k} \\ \\ \frac{T^2}{4\pi^2}\cdot k=m \\ \\ T^2\cdot k=m(4\pi^2) \\ \\ k=\frac{m(4\pi^2)}{T^2} \end{gathered}\)Then, replacing m = 750 g = 0.75 kg and T = 2.5s, we get:
\(k=\frac{0.75\text{ kg }\cdot4\cdot\pi^2}{(2.5\text{ s\rparen}^2}=4.737\text{ N/m}\)Therefore, the spring constant must be 4.737 N/m
The 200-mm test tube also contained some water (besides the metal) that was subsequently added to the calorimeter (in Part A.4.). Considering a higher specific heat for water, will the temperature change in the calorimeter be higher, lower, or unaffected by this technique error?
Answer:
The temperature change in the calorimeter will be lower
Explanation:
Water is an example of a molecular substance. They have relatively low melting points and boiling points usually below 300° C . Water reacts with metals to a degree varying with their position in the electrochemical series.
The specific heat of water is 4179.6 Joules which is relatively high . This typically implies that water absorbs a larger amount of heat but the increase in temperature of its boiling points is relatively low. Thus; in the 200-mm test tube that contains water and was subsequently added to the calorimeter , the heat present was initially absorbed by the water and that does not result to an increase in the temperature change in the calorimeter. Thus the temperature change in the calorimeter will be lower.
An object is placed 19 cm to the left of a converging lens of focal length 30 cm. A diverging lens of focal length 9 cm is 25 cm to the right of the converging lens. Find the position and magnification of the final image.
The final image will be real and obtained at infinity is the position and magnification of the final image.
What are convergent and divergent lenses?A converging lens brings together parallel light rays that are moving in their direction. A diverging lens does just that as parallel light rays approach it. It creates the true image. The virtual image is created. A converging lens is also known as a convex lens.
Is a convex lens also a converging lens?Since the rays converge after passing through the convex lens, convex lenses are also known as converging lenses. Since the rays diverge after striking the concave lens, it is known as a diverging lens.
For converging lens,
\(\frac{1}{f} =\frac{1}{v} -\frac{1}{u}\)
\(\frac{1}{30} =\frac{1}{v} -\frac{1}{-19}\)
\(\frac{1}{v} =\frac{1}{30} -\frac{1}{19}\)
\(v=11m\)
The final image will be real and obtained at infinity.
For diverging lens,
\(\frac{1}{f} =\frac{1}{v} -\frac{1}{u}\)
\(\frac{1}{9} =\frac{1}{v} -\frac{1}{-30-25}\)
\(\frac{1}{v} =\frac{1}{9} -\frac{1}{55}\)
\(v=46m\)
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A tsunami can travel over 970 kilometers in an hour. If it’s been 3 hours since the tsunami was created, how far has it traveled?
Answer:
2910
Explanation:
970 × 3. 970 in one hour × 3 hrs. 2910 kilometers
· A car moves at 12 m/s and coasts up a hill with a
uniform acceleration of -1.6 m/s2.
a. What is its displacement after 6.0 s?
b. What is its displacement after 9.0 s?
Explanation:
Given that,
Initial speed of a car, u = 12 m/s
Aceleration, a = -1.6 m/s²
(a) The displacement of car after 6 seconds is :
\(d=ut+\dfrac{1}{2}at^2\\\\d=12\times 6+\dfrac{1}{2}\times (-1.6)\times 6^2\\\\d=43.2\ m\)
(b) The displacement of the car after 9 seconds is :
\(d=ut+\dfrac{1}{2}at^2\\\\d=12\times 9+\dfrac{1}{2}\times (-1.6)\times 9^2\\\\d=43.2\ m\)
Hence, this is the required solution.
does height of image in plane mirror change as you move farther away
The picture position travels away from the mirror as the object approaches it, and the image size increases (but the image is still inverted).
In terms of physics, how do objects move?A force pushing or pulling an object will cause it to move in that direction. The acceleration increases as the force and object weight increase. Moreover, it can cause something to shift pace, direction, or tempo.
What factors are at work?The primary forces that produce motion are gravity and friction. The motion of an object will change if one, both, or both forces are changed. The force that draws two objects together is called gravity. The amount of "stuff" in an object, or its mass, is the same for everything.
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What would be the acceleration in a body moving with uniform velocity and why?
Explanation:
The derivative of a constant term is always 0. So the acceleration of the body would be zero. Hence, the acceleration of a body moving with uniform velocity will always be zero.
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You have a 6-m-long copper wire. You want to make an N-turn current loop that generates a 4.085 mT magnetic field at the center when the current is 1.513 A. You must use the entire wire. What will be the diameter, in cm, of your coil?
ANSWER:
2.98 cm
STEP-BY-STEP EXPLANATION:
Given:
Length wire (L) = 6 m
Current (i) = 1.513 A
magnetic field (β) = 4.085 mT = 4.085 x 10^-3 T
Magnetic field at the center of circular coil is given for the following formula:
\(\beta=\frac{\mu_0\cdot N\cdot i}{2R}=\frac{\mu_0\cdot N\cdot\imaginaryI}{d}\)The total length of wire in the coil is given by:
\(\begin{gathered} L=\pi\cdot d\cdot N \\ \\ N=\frac{L}{\pi d} \end{gathered}\)We replacing:
\(\begin{gathered} \beta=\frac{\mu_0\cdot\frac{L}{\pi d}\cdot\imaginaryI}{d} \\ \\ \beta=\frac{\mu_0\cdot L\cdot\imaginaryI}{\pi\cdot d^2} \\ \\ d^2=\frac{\mu_0\cdot L\cdot\imaginaryI}{\pi\beta} \\ \\ d=\sqrt{\frac{\mu_0L\imaginaryI}{\pi\beta}} \\ \\ \text{ Therefore:} \\ \\ d=\sqrt{\frac{4\pi\cdot10^{-7}\cdot6\cdot1.513}{\pi\cdot4.085\cdot10^{-3}}} \\ \\ d=0.0298\text{ m}=2.98\text{ cm} \end{gathered}\)Therefore, the diameter in centimeters is equal to 2.98 cm
A red cart has a mass of 4 kg and a velocity of 5 m/s. There is a 2-kg blue cart that is parked and not moving, thus its velocity is 0 m/s.
The red cart hits the blue cart.
The blue cart starts to move forward with a velocity of 6 m/s. The red cart bounces off of the blue cart and moves backwards, at a velocity of 2 m/s.
Name the TYPE of collision that occurred.
Calculate the BEFORE momentum of the red cart. Use correct units.
Calculate the BEFORE momentum of the blue cart. Use correct units.
Calculate the AFTER momentum of the red cart. Use correct units.
Calculate the AFTER momentum of the blue cart. Use correct units.
Calculate the SYSTEM’S TOTAL MOMENTUM before the collision. Use correct units.
Calculate the SYSTEM’S TOTAL MOMENTUM after the collision. Use correct units.
EXPLAIN how this example supports the Law of Conservation of Momentum. Use the evidence to support your answer of how this example supports the Law of Conservation of Momentum. Use correct units. Be specific.
Answer:dam hold up
Explanation:
Write a set of turtle instructions to draw an AND gate.
The turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
To draw an AND gate using turtle graphics, you can use the following set of instructions:
Set up the turtle:
a. Set the turtle's initial position.
b. Set the turtle's pen color and size.
Draw the first input line:
a. Move the turtle forward to the starting point of the line.
b. Draw a straight line segment to represent the first input.
Draw the second input line:
a. Move the turtle to the starting point of the second line.
b. Draw a straight line segment to represent the second input.
Draw the output line:
a. Move the turtle to the starting point of the output line.
b. Draw a straight line segment to represent the output.
Draw the logic gate shape:
a. Move the turtle to the starting point of the gate.
b. Draw a rectangle to represent the gate.
c. Add any necessary labels or symbols to indicate it as an AND gate.
Add connections between lines and gate:
a. Move the turtle to the intersection point of the first input line and the gate.
b. Draw a small line segment to connect the input line to the gate.
c. Repeat the above step for the second input line and the gate.
d. Draw a small line segment to connect the output line to the gate.
Repeat the above steps as necessary to draw multiple AND gates or any additional components.
Remember to adjust the turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
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HELPPPP I HAVE A TEST TODAY AND I LITERALLY CAN'T WITH THIS
In a children’s soccer game, one of the children kicks the ball from the ground, giving it an initial velocity of 22 m/s at an angle of 62° to the horizontal. Determine the initial vertical and horizontal velocity components.
If you post links I will report u so I suggest u don't
The horizontal component of velocity is
(22 m/s) • cosine(62°).
The vertical component of velocity is
(22 m/s) • sine(62°).
These are the original components, right after the kick. As time goes on, the horizontal one doesn't change. But the vertical one gets bigger and bigger, because gravity is accelerating the ball downward.
That's the complete story of projectile motion.
What happens when thermal energy is removed from a substance?(1 point) Responses All substances will freeze. All substances will freeze. The substance loses potential energy. The substance loses potential energy. The substance’s atoms lose kinetic energy. The substance’s atoms lose kinetic energy. The substance’s particles speed up
does fire have ways to protect itself from changes in the environment
Answer:
I think no because the critical properties distinguishing life is adaptation to changing environment and self replication of the information encoding the life process. Fire does not change its process to adapt to its environment, e.g. moving toward more fuel or storing and conserving fuel when it is in short supply.
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Given a parallel runtime of 20s on eight cores and a serial runtime of 80s, what is the runtime in seconds on 16 cores assuming the same efficiency (do not include any units in the answer)?
If we assume the same efficiency, then we can use Amdahl's Law to calculate the new runtime on 16 cores.
Amdahl's Law states that the speedup of a parallel program is limited by the portion of the program that must be executed sequentially. In this case, the portion that must be executed sequentially is (80-20)/80 = 0.75 or 75%. This means that only 25% of the program can be parallelized. Therefore, the speedup we can expect from doubling the number of cores is limited to 1/((1-0.25) + 0.25/8) = 1.85.
Using this speedup, we can calculate the new runtime on 16 cores as 20/1.85 = 10.81 seconds.
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