The volume of a cone is 75 and the radius is 5 . What is the height

Answer:

180 p

Step-by-step explanation:your welcome

Answer:

The answer is C

Step-by-step explanation:

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A parabola has a maximum value of 4 at x= -1, a y-intercept of 3, and an x-intercept of 1. The x-intercepts are -3 and 1. So, The second graph is the right one.

We have given that,

A parabola has a maximum value of 4 at x = -1,

A y-intercept of 3, and an x-intercept of 1.

The maximum value of a graph refers to the point on the graph where the y-coordinate has the largest value.

A maximum graph is one that represents the largest value of the y-coordinate on the graph.

So, The second graph is the right one.

Note that when x = 1, y (the maximum) is 4,

and that, The x-intercepts are -3 and 1.

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Considering the graphs given here between the scatter plot, its line of best fit and residual plot; linear regression equation is more appropriate for the data because it help to determine a regression correlation in two variables.

In statistics, a regression equation is used to determine whether there is any link between two sets of data. A variable's value can be predicted using linear regression analysis based on the value of another variable.

The Linear Regression equation can be understandable by following justification:

Y= mX +b

Given, Y = { 2,4,6,8,10,12}

           X = {9, 2,1,12,25,48}

         ∵  y = 3.93x - 11.33

          ∵ r = 0.8241

∴ Value of Y = 3

∴ Value of X = {0.8241 + 11.33r} ÷ {0.93}

Thus for the scatter plot dots more understandable with linear equation and for residual plot dots depicts non-linear equation. The two variables X and Y.

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Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.

To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:

OCF = Year 1 Revenues - Year 1 Costs

OCF = $192,000 - $125,000

OCF = $67,000

To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.

The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:

Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues

Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.

The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:

ATSV = Salvage Value percentage * Initial Cost

ATSV = 28% * $390,000

ATSV = $109,200

To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.

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The complete question is:

Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000  7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.

Answer: 4q-4

Step-by-step explanation:

2(q+q-2) = 2(2q-2) = 4q-4

Answer:

The volume of the cylinder is \(300\pi\) cubic feet.

Step-by-step explanation:

From Geometry we remember that volumes of a cone and a cylinder with the same radius (\(R\)), measured in feet, and height (\(h\)), measured in feet, are defined by the following equations:

Cone

\(V_{co} = \frac{1}{3}\pi\cdot R^{2}\cdot h\) (1)

Cylinder

\(V_{cy} = \pi\cdot R^{2}\cdot h\) (2)

The ratio of the volume of the cylinder to the volume of the cone is:

\(\frac{V_{cy}}{V_{co}} = 3\) (3)

If we know that \(V_{co} = 100\pi\,ft^{3}\), then the volume of the cylinder is:

\(V_{cy} = 3\cdot V_{co}\)

\(V_{cy} = 300\pi\,ft^{3}\)

The volume of the cylinder is \(300\pi\) cubic feet.

Answer:

i dont know spanish soryy.

Step-by-step explanation:

To determine the sign of the sum of two integers when one integer is positive and the other is negative, we can follow a simple rule based on their magnitudes.

If the magnitude of the positive integer is greater than the magnitude of the negative integer, the sum will be positive. This is because the positive integer outweighs the negative integer, resulting in a positive value.

On the other hand, if the magnitude of the negative integer is greater than the magnitude of the positive integer, the sum will be negative. In this case, the negative integer dominates and determines the sign of the sum.

In both scenarios, the sign of the larger magnitude integer takes precedence and determines the sign of the sum. It is important to note that the sum will always have the sign of the integer with the larger magnitude, regardless of the specific values of the integers involved.

By considering the magnitudes of the integers, we can easily determine the sign of their sum when one integer is positive and the other is negative.

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Answer:

k

Step-by-step explanation:

The simplified version of (sec a - cosec a) / (sec a + cosec a)  is cosec 2a(cosec 2a - 2) / (sec²a - cosec²a).

The study of correlations between triangles' side lengths and angles is known as trigonometry. The field was created in the Hellenistic era in the third century BC as a result of the use of geometry in astronomical research.

Given:

(sec a - cosec a) / (sec a + cosec a)

Multiply the numerator and denominator by (sec a - cosec a)

(sec a - cosec a) / (sec a + cosec a)  × (sec a - cosec a)

(sec²a + cosec²a -2sec a cosec a) / (sec²a - cosec²a)

As we know,

\(sec^2a + cosec^2a = sec^2a \ cosec^2a\)

sec² a cosec² a - 2sec a cosec a /  (sec²a - cosec²a)

sec a cosec a (sec a cosec a - 2) / (sec²a - cosec²a)

cosec 2a(cosec 2a - 2) / (sec²a - cosec²a)

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Answer:

a.) 135 degrees

b.) 45 degrees

c.) 45 degrees

Step-by-step explanation:

Use this link to see a visual representation on how to solve for these types of angles, it lets you click on any type of angle and see how it corresponds to other angles within the parallel line and traversal, give it a try!

https://www.mathsisfun.com/geometry/alternate-exterior-angles.html

So the minimal transportation cost is $8,700, and it can be achieved by renting 6 buses and 27 vans.

Let's start by defining our variables. Let b be the number of buses and v be the number of vans to be rented. We want to minimize the transportation costs, so our objective function is:

C = 1400b + 100v

We also have two constraints:

The total number of students that can be transported cannot be less than 720:

72b + 9v ≥ 720

The total number of chaperones cannot be more than 45:

3b + v ≤ 45

Now we can solve for b and v. Let's solve the second constraint for v:

v ≤ 45 - 3b

Substituting this inequality into the first constraint, we get:

72b + 9(45 - 3b) ≥ 720

Simplifying and solving for b, we get:

b ≥ 6

So we know that we need to rent at least 6 buses. Since we cannot rent a fraction of a bus or van, b must be an integer. Let's try b = 6 and see if it satisfies the second constraint:

3(6) + v ≤ 45

v ≤ 27

Since v must also be an integer, the largest integer that satisfies this inequality is v = 27. Now we can calculate the total cost:

C = 1400(6) + 100(27) = 8700

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Answer:

B. No, Hannah should have used the ratio \( \frac{adjacent}{opposite} \)

Step-by-step explanation:

✍️The formula for calculating cotangent of an angle is given as:

\( cot = \frac{adjacent}{opposite} \).

The ratio, \( \frac{opposite}{adjacent} \), used by Hannah is the formula for calculating tangent of an angle.

Therefore, Hannah did not calculate the cotangent of the angle correctly.

She should have used, the ratio, \( \frac{adjacent}{opposite} \) instead.

Equivalent expressions are expressions that have the same value

The equivalent expression of \((4 +7i)(3 +4i)\) is \(-16+37i\)

The expression is given as:

\((4 +7i)(3 +4i)\)

Expand the equation

\((4 +7i)(3 +4i) = 4(3 +4i) +7i(3 +4i)\)

Distribute the equation, as follows:

\((4 +7i)(3 +4i) = 12 +16i +21i +28i^2\)

In complex numbers,

\(i^2 = -1\)

So, we have:

\((4 +7i)(3 +4i) = 12 +16i +21i +28(-1)\)

Evaluate the product

\((4 +7i)(3 +4i) = 12 +16i +21i -28\)

Combine like terms

\((4 +7i)(3 +4i) = 12-28+16i +21i\)

Evaluate like terms

\((4 +7i)(3 +4i) = -16+37i\)

Hence, the equivalent expression of \((4 +7i)(3 +4i)\) is \(-16+37i\)

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Answer:

The answer would be

A. x + 2y + 10

A constant term is considered any term that does not change or have a variable with it. 10 is the only displayed constant term.

Answer:

\(\\ \sf\longmapsto x^2+y\)

Step-by-step explanation:

Trinomial means the expression has 3 roots.

In the last one

Total 3 roots

The price for 1 scoop of ice cream and the price for 1 topping is $1.20 and $0.35 respectively.  

Suppose the price for 1 scoop of ice cream = x

The price for 1 topping = y

An equation of the form ax+by+c=0 is called a linear equation where a, b and c are real numbers.

According to the question

3x+y=3.95.......(1)

2x+2y=3.10.......(2)

Multiply equation (1) by 2 on both sides

6x+2y=7.90.....(3)

Subtracting the equation (2) from equation(3)

4x=4.80

x=1.20

So, y = 0.35

So, the price for 1 scoop of ice cream =$1.20

The price for 1 topping = $0.35

Hence, the price for 1 scoop of ice cream and price for 1 topping is $1.20 and $0.35 respectively.  

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Answer:

B

Step-by-step explanation:

Answer:

Step-by-step explanation:

3444

Answer- The rabbit population decreased in 2013 and 2015 in some areas of up to 80%

The value or measure of ∠PQR in the given circle where PQ & RQ are tangents from same external point Q is  52°, found by applying theorem in circle C and considering quadrilateral CPQR.

The word "tangent" refers or means "to touch". The Latin word for the same is "tangere". The line that intersects the circle exactly at one point on its circumference or boundary of circle and never enters the circle's interior is a tangent. A circle can have many  or infinite tangents. They are always perpendicular to the radius. A tangent of a circle is straight line that touches or intersects externally the circle at only one point without entering the interior of circle.

Consider the circle C, Given that

∠PCR=128°

QP & RQ are tangents from same point Q, which means

QP= QR {tangents from same external point are equal in length}

CP & CR are radius from the centre C & also perpendicular to the tangents, which means:

CP ⟂ QP

CR ⟂ QR

∠CPQ=90°

∠CRQ=90°

Consider the Quadrilateral CPQR,

∠C + ∠P + ∠Q + ∠R = 360°  {angle sum property of quadrilateral}

128 + 90 + ∠Q + 90 = 360

128 + 180 +∠Q = 360°  

∠Q = 360° - 180 - 128

∠Q = 360° - 308

∠Q = 52°

Therefore the measure of ∠PQR is  52°.

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The distance between train station C and train station B is 75.02095678 miles, using the law of cosines.

In the question, we are given that a train leaves train station A and heads due west for 105 miles to reach train station B. Another train leaves train station A at the same time and travels 85 miles to train station C in a direction 45 north of west from station A.

We are asked to calculate the distance between train station C and train station B.

The given scenario can be shown by the attached diagram in the form of a triangle, where A depicts train station A, B depicts train station B, and C depicts train station C, with the angle between them being 45°.

The distance between train station A and train station B can be shown as AB = c = 105 miles.

The distance between train station A and train station C can be shown as AC = b = 85 miles.

The distance between train station B and train station C can be shown as BC = a = x miles.

By the law of cosines, in the triangle ABC, we can say that:

a² = b² + c² - 2bc cos A,

or, x² = 85² + 105² - 2(85)(105) cos 45°),

or, x² = 7225 + 11025 - 17850(0.707106781),

or, x² = 18250 - 12621.85604,

or, x² = 5628.143956,

or, x = √5628.143956 = 75.02095678.

Thus, the distance between train station C and train station B is 75.02095678 miles, using the law of cosines.

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Answer:

1/3

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

Each angle on a square road sign measures 90 degrees.

A square is a quadrilateral with four equal sides and four right angles. In a square, all angles are congruent, meaning they have the same measure. Since a square has four angles, each angle is equal to the total sum of the interior angles of a square divided by four.
The total sum of the interior angles of a square can be calculated using the formula (n - 2) * 180 degrees, where n is the number of sides. For a square, n = 4, so the total sum of the interior angles is (4 - 2) * 180 = 2 * 180 = 360 degrees.
To find the measure of each angle, we divide the total sum of the interior angles by the number of angles, which is 4 in the case of a square:
360 degrees / 4 angles = 90 degrees.
Therefore, each angle on a square road sign measures 90 degrees.

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Answer:

Hi, there!

23

Step-by-step explanation:

The value of (23) is equal to twenty three.

23

I hope it's helps you

Step by step explanation

Without knowing the transfer function and the arrangement of poles and zeros, it is not possible to determine the frequency at which the gradient is -40 dB/decade in a Bode plot.

In a Bode plot, the gradient represents the slope of the line that connects two consecutive asymptotes. Each asymptote corresponds to a pole or zero in the transfer function.

Therefore, to determine when the gradient is equal to -40, we need to find the frequency at which two consecutive asymptotes have a 40 dB difference in magnitude.

In general, the magnitude of the transfer function for a system with a single pole or zero can be expressed as:

|H(jω)| = K / |1 + jω/ωp| (for a pole)

or

|H(jω)| = K |1 + jω/ωz| (for a zero)

where K is the system gain, ωp is the pole frequency, and ωz is the zero frequency.

When there are multiple poles and zeros, the magnitude is the product of the individual magnitudes. The phase angle also depends on the number and type of poles and zeros.

For a single pole, the magnitude asymptote has a slope of -20 dB/decade (i.e., a decrease of 20 dB for each increase in frequency by a factor of 10). Therefore, two consecutive poles will have a 40 dB difference in magnitude when the frequency is such that the first pole's magnitude asymptote intersects the second pole's magnitude asymptote. This occurs when the frequency is one decade below the second pole's frequency.

For a single zero, the magnitude asymptote has a slope of +20 dB/decade (i.e., an increase of 20 dB for each increase in frequency by a factor of 10).

Therefore, two consecutive zeros will have a 40 dB difference in magnitude when the frequency is such that the first zero's magnitude asymptote intersects the second zero's magnitude asymptote. This occurs when the frequency is one decade above the second zero's frequency.

In general, when there are multiple poles and zeros, the frequency at which two consecutive asymptotes have a 40 dB difference in magnitude will depend on the specific values and arrangement of the poles and zeros.

Your question seems incomplete. I could not find the exact question details online so I answered in general.

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The shape A is the enlargement of shape C.

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered. There is no effect of dilation on the angle.

An enlargement of a shape is a transformation that results in a larger or smaller version of the original shape while keeping the shape's angles the same. The process involves multiplying the length, width, and height of the original shape by a common scale factor.

From the graph, the shape A is the enlargement of shape C.

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Answer:

32 units

Step-by-step explanation:

∠LON = 2(∠LMN) = 2(60°) = 120°

120°/360° = 1/3

length of minor arc LN = (1/3)(96) = 32 units

Answer:

\(b = \frac{3v}{h} \)

Answer:

Step-by-step explanation:

First you multiple both sides by 3

3v=Bh

Than divide by h

You get

3v/h=B

1. The he intersection points A and B are:

A(-2, -1) and B(6, 7)

2. Midpoint is (7, -1)

3. length of AB is 4√5

To find the intersection points A and B, set y = x + 1 and y = x² - 3x - 11 equal to each other:

x + 1 = x² - 3x - 11

Now, rearrange the equation to set it equal to zero:

x² - 4x - 12 = 0

Factor the quadratic equation:

(x - 6)(x + 2) = 0

Solve for x:

x = 6, x = -2

Now plug the x-values back into the equation of either line (y = x + 1) to find the corresponding y-values:

For x = 6: y = 6 + 1 = 7

For x = -2: y = -2 + 1 = -1

So the intersection points A and B are:

A(-2, -1) and B(6, 7)

a) To find the midpoint of A(5,-5) and B(9,3), use the midpoint formula:

Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Midpoint = ((5 + 9)/2, (-5 + 3)/2) = (14/2, -2/2) = (7, -1)

b) To find the length of AB, use the distance formula:

Distance = √((x2 - x1)² + (y2 - y1)²)

Distance = √((9 - 5)² + (3 - (-5))²) = √(4² + 8²) = √(16 + 64) = √80

Length of AB = 4√5 (simplified

a) To find the length of AB, use the distance formula:

Distance = √((x2 - x1)² + (y2 - y1)²)

Distance = √((9 - 5)² + (-1 - 7)²) = √(4² + (-8)²) = √(16 + 64) = √80

Length of AB = 4√5 (simplified)

b) To find the equation of the line AB, first find the slope:

m = (y2 - y1)/(x2 - x1) = (-1 - 7)/(9 - 5) = (-8)/4 = -2

Next, use the point-slope form with one of the points (A or B), say A(5,7):

y - y1 = m(x - x1)

y - 7 = -2(x - 5)

Now, convert the equation to the slope-intercept form (y = mx + c):

y = -2x + 10 + 7

y = -2x + 17

To find the gradient of the line that is perpendicular to 3y = 4x - 5, first find the gradient of the given line:

3y = 4x - 5 => y = (4/3)x - 5/3

The gradient of the given line is 4/3. To find the gradient of the perpendicular line, find the negative reciprocal:

m_perpendicular = -1/(4/3) = -3/4

i) To find the midpoint M of A(1,5) and B(3,9), use the midpoint formula:

Midpoint = ((x1 + x2)/2, (y1 + y2)/

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\(\displaystyle -5(2-5(-3))^2=-5(17)^2=-1445\)