We know, acceleration is the rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.
Describe acceleration. What are the factors on which acceleration is dependent?
Acceleration (m/s) = force (N) / mass (kg)
so the answer is mass
A point or an object moving in a straight line is accelerated if it speeds up or slows down. Motion on a circle is accelerated even if the speed is constant, because the direction is continually changing. For all other kinds of motion, both effects contribute to the acceleration.
Unit of acceleration is : metre per second per second
The three types of acceleration are
1) Change in velocity
2) Change in direction
3) Both change in velocity and directio
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The distance between two successive crests or two successive troughs on a transverse wave is known asA. PitchB. LoudnessC. WavelengthD. Rarefaction
Explanation:
That would be the definition of WAVELENGTH
Two people are pulling the same 12 kg box along a flat, frictionless surface. One
pulls up and to the right with a 30 N force at 20°, the second pulls up and to the left
with a 45 N force at 50°. What is the acceleration of the box?
3.00 m/s^2
09.80 m/s^2
O 1.474 m/s^2
0.474 m/s^2
Answer:
The acceleration is 0.062 m/s^2.
Explanation:
mass = 12 kg
F = 30 N at 20° right
F' = 45 N at 50° left
Let the acceleration is a.
The net force is
F'' = F' cos 50° - F cos 20°
F'' = 45 x 0.643 - 30 x 0.94 = 28.94 - 28.2 = 0.74 N
According to the Newton's second law
0.74 = 12 x a
a = 0.062 m/s^2
Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.
Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)
a) Two other forces that act on thee sled are the weight of the daughter and the drag force
b) The drag force slows down the sled while the weight presses it down.
What is motion?We know that motion is the result of the action of unbalanced forces. From the Newton's third law, we know that if the forces that are acting on an object are balanced that the object is not going to move from its state of rest.
In this case, we are told that a father pushes his daughter and son on a sled down a hill. The fact that the led is moving is due to the fact that there are forces that are acting on the sled.
The forces that are acting on the sled apart from the force that was applied in pushing the sled is the drag force and the weight of the son.
The drag force would determine how fast that the sled would move because it acts in opposition to the forward force and tries to slow down the sled as it is moving. The weight of the son does press the sled downwards.
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what are types of dooing used to control conductivity in semi
conductors and their effects on fermi level
The two types of doping used to control conductivity in semiconductors are N-type and P-type doping. The effects on the Fermi level differ between the two types of doping.
In semiconductors, doping refers to the intentional introduction of impurities to control conductivity. N-type doping is accomplished by introducing impurities into the semiconductor that have more valence electrons than the semiconductor's atoms. Phosphorus or arsenic, for example, are commonly used as doping agents in silicon.
When these impurities are introduced, they create extra electrons in the conduction band, resulting in n-type doping. The Fermi level is shifted closer to the conduction band as a result of the additional electrons. P-type doping, on the other hand, involves introducing impurities into the semiconductor that have fewer valence electrons than the semiconductor's atoms. Boron, for example, is a common p-type dopant for silicon. When boron is introduced, it creates holes in the valence band, resulting in p-type doping. As a result of the additional holes, the Fermi level is shifted closer to the valence band.
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based on what you learned about atoms, select all of the correct statements from the following list.1)Protons are positively charged.2)Doppler shifts in spectral lines give clues to the motions of stars.3)The Lyman and Paschen series of the hydrogen spectrum are not visible.4)Stellar spectra are absorption spectra.5)Spectra can reveal the chemical composition of stars.6)Electrons surround the nucleus.7)The number of neutrons determines the isotope of an atom.8)Neutral atoms have the same number of protons as electrons.
Neutral atoms contain the same amount of protons and electrons, protons are electrostatic attraction, stellar spectra are absorbance spectra, and spectra may show the chemical makeup of stars.
What do stellar spectra refer to?Information about a star's temperature, chemical make-up, and inherent brightness may be found in its spectrum. A series of photographs taken at various wavelengths of the split in the star's light make up spectrograms produced by slit spectrographs.
What processes result in stellar spectra?The transitions of electrons inside atoms or ions form spectral lines, which are typically dark absorbing lines but may also be dazzling emission lines in some things.
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Can someone give me an example of a machine that uses a pulley ramp system?
Multiple examples would be appreciated :)
bicycle wheels
roller skates
doorknob
A wheel that has a rope wrapped around it
show how three identical 6 resistors must be connected tho have the following effective resistance values 9 and 4 ohms
Answer:
connect two 9 ohms resistance in series now it becomes 18 ohm
according to the big bang theory the entire universe began as a
According to the Big Bang theory, the entire universe began as a singularity - an extremely hot and dense point in space-time. About 13.8 billion years ago, this singularity began to rapidly expand, creating all matter and energy in the universe and eventually leading to the formation of galaxies, stars, and planets.
The Big Bang theory posits that the universe began as a singularity, a point of infinite density and temperature. This singularity rapidly expanded, causing a rapid cooling and the formation of particles like protons, neutrons, and electrons. As the universe continued to expand and cool, these particles began to form atoms, eventually leading to the formation of stars and galaxies. The Big Bang theory has been supported by a range of scientific observations and experiments, from the cosmic microwave background radiation to the relative abundance of light elements. Despite ongoing debate and refinement, it remains the prevailing scientific explanation for the origin and evolution of the universe.
In conclusion, the Big Bang theory suggests that the universe began as a singularity that rapidly expanded and eventually led to the formation of all matter and energy. This theory has been supported by a wealth of scientific evidence and remains the prevailing explanation for the origins and evolution of the universe.
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how is stratospheric ozone created?
A. Radiant energy from the sun breaks apart oxygen molecules freeing single oxygen atoms that recombine into ozone
B. When ultraviolet radiation passes through a depleted ozone layer it acts on oxygen at ground levels creating ozone
C. Ozone is formed in when sulfur and nitrogen oxides combine with water in the atmosphere
D. Ozone created from NOx and VOC gases rise from low altitudes into the stratosphere and form the ozone layer
Answer:
Its actually D
Explanation:
I hope you get it right^^, Have a nice day!
What is the purpose of Rheostat in an electric circuit
Answer:
to dim lights, or to control speed in a engine
Explanation:
The freezing point of an aqueous 0.050 m cacl2solution is −0.27 °c. what is the van’t hoff factor (i) for cacl2at this concentration? how does it compare to the expected value of i?
Then the answer is 2.9
\($\begin{aligned} \Delta T_{f} &=i \times m \times k_{f} \\ i &=\frac{\Delta T_{f}}{m \times k_{f}} \end{aligned}$\)
\(=\frac{0.27^{\circ} \AC}{0.050 \times \frac{1.86^{\circ} \mathrm{C}}{\mathrm{m}}}\)
\(\therefore i^{2}=2.9\)
Using van’t hoff factor the answer has no unit, as, expected since i is a ratio. The magnitude is about right since it is close to the value ace would expect upon the complete dissociation \($\mathrm{CaCl}_{2}$\).
What is Van't Hoff factor?
The Van't Hoff factor is always positive and can never be negative. When the solute remains completely undissociated in solution, the Van't Hoff factor is one; it is greater than one for salts and acids and less than one for the solute that associates when dissolved to form a solution.The van't Hoff factor is defined as the ratio of the observed colligative property produced by a given concentration of electrolyte solution to the observed colligative property produced by the same concentration of non-electrolyte solution.To learn more about van't Hoff factor visit: https://brainly.com/question/24598605
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can someone help me and give me the right answer
Answer:
C. sedimentary
Explanation:
Answer:
Sedimentary
Explanation:
Igneous rock- A rock that's formed through the cooling and solidification of magma or lava.
Metamorphic rock- A rock that starts out as another rock and often has a striped appearance.
Volcanic rock- A rock that's formed from lava that erupted from a volcano.
Sedimentary is the only right answer. A Sedimentary rock is a rock thats made from the deposition of lots of pieces of eroded rock particles.
In a ballistics test at the police station an officer
shoots a 6.0g bullet at 350m/s into a wooden block. If
it takes 1.8ms for the bullet to stop, what is the
average force acting on the bullet as it stops? (Hint:
ms stands for milliseconds.)
Explain how inductive reasoning is inferior to deductive reasoning in establishing theory.
Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.
Explanation: No explanation lol. But I hope this is helpful!
The position-time graph of a pedestrian is given below. what is his displacement after 2.5 s?
Answer:
The displacement of the pedestrian after 2.5 seconds is -10 meters.
Explanation:
Let \(x(t)\) and \(t\) be position, measured in meters, and time, measured in seconds, respectively. From definition of displacement, we get that:
\(d = x(2.5\,s)-x(0\,s)\)
Where:
\(x(0\,s)\) - Position of the pedestrian at 0 seconds, measured in meters.
\(x(2.5\,s)\) - Position of the pedestrian at 2.5 seconds, measured in meters.
If \(x(0\,s) = 10\,m\) and \(x(2.5\,s) = 0\,m\), then the displacement of the pedestrian after 2.5 seconds is:
\(d = 0\,m-10\,m\)
\(d = -10\,m\)
The displacement of the pedestrian after 2.5 seconds is -10 meters.
What 2 factors impact gravitational pull?
mass and distance
matter and energy
size and shape
speed and direction
Answer:
When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them
What is the maximum speed at which a car can safely travel around a circular track of radius 142 meters if the coefficient of friction between the tires and the road is 1.07? Include units in your answer. Answer must be in 3 significant digits.
Given that the radius of the circular path is r = 142 m and the coefficient of the friction is
\(\mu=1.07\)The condition for the car to travel safely is
Frictional force = centrifugal force
\(\mu mg=\frac{mv^2}{r}\)Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
\(\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}\)a milling machine processes a part with t0=15 mins and sigma0=3mins. the mean time to failure 750 mins and the mean time to repair is 200 muns. the coefficient of varuation for the repair time is 1.2. the product of the milling machine is feeding the downstream turning machine. the turning maching had the same t0 and sigma0, but the mean time to failure and mean time to replair are 110 muns and 38 muns. (cv=1.2).Assuming the arrival to the milling machine is 1.2 parts/hrwith an arrival Cv =1. find the cycle time of the entire line.
The cycle time of the entire line is 30.00528 minutes per part.
To calculate the cycle time of the entire line, we need to consider the processing times, failures, and repairs of both the milling machine and the turning machine.
For the milling machine:
Mean processing time (t0) = 15 mins
Standard deviation of processing time (sigma0) = 3 mins
Mean time to failure (MTTF) = 750 mins
Mean time to repair (MTTR) = 200 mins
For the turning machine:
Mean processing time (t0) = 15 mins
Standard deviation of processing time (sigma0) = 3 mins
Mean time to failure (MTTF) = 110 mins
Mean time to repair (MTTR) = 38 mins
We also know that the arrival rate to the milling machine is 1.2 parts/hr, with a coefficient of variation (CV) of 1.
To calculate the cycle time, we can use the following formula:
Cycle time = Processing time + Failure time + Repair time
Processing time:
The processing time is the sum of the mean processing times of the milling machine and the turning machine:
Processing time = t0 (milling machine) + t0 (turning machine) = 15 mins + 15 mins = 30 mins
Failure time:
The failure time is the inverse of the MTTF, considering the arrival rate:
Failure time = 1 / (MTTF * Arrival rate) = 1 / (750 mins * (1.2 parts/60 mins)) = 0.00111 parts/min
Repair time:
The repair time is the inverse of the MTTR, considering the coefficient of variation (CV):
Repair time = 1 / (MTTR * CV) = 1 / (200 mins * 1.2) = 0.00417 parts/min
Cycle time:
Cycle time = Processing time + Failure time + Repair time = 30 mins + 0.00111 parts/min + 0.00417 parts/min
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When 50 g of a certain material at 100°C is mixed with 100 g of water at 0°C, the final temperature is 40°C. What is the specific heat of the material? The specific heat of water is 1.00 kcal/kg • C°.
we can equate the two quantities of heat to find c: m_water * c_water * ΔT = m_material * c * ΔT, c = (m_water * c_water * ΔT) / (m_material * ΔT)
the above expression yields c = 0.20 kcal/kg * C°.
The formula for calculating the specific heat (c) of a material is:
ΔQ = m * c * ΔT
c = ΔQ / (m * ΔT)
ΔT = 100°C - 40°C = 60°C
m_water = 100 gΔQ = m_water * c_water * ΔT = 100 g * 1.00 kcal/kg * ΔT
m_material = 50 g
ΔT = 40°C - 0°C = 40°C
ΔQ = m_material * c * ΔT
So, we can equate the two quantities of heat to find c:
m_water * c_water * ΔT = m_material * c * ΔT
c = (m_water * c_water * ΔT) / (m_material * ΔT)
the above expression yields temperature c = 0.20 kcal/kg * C°.
How is mixing temperature determined?The first container's mass and temperature are multiplied together, and the result is added to the second container's mass and temperature to determine the mixture's water temperature. Finally, divide that outcome by the combined water masses in each container.
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HELP PLSSS
What is the momentum of A 200 kg shark swimming at 15 m/s? |
Answer:
3000 Kg.m/s
Explanation:
From the question given above, the following data were obtained:
Mass (m) of shark = 200 Kg.
Velocity (v) of shark = 15 m/s.
Momentum of shark =..?
The momentum of an object is simply defined as the product of the mass and velocity of the object. Mathematically, it is expressed as:
Momentum = mass (m) × velocity (v)
With the above formula, we can obtain the momentum of the shark as follow:
Mass (m) of shark = 200 Kg.
Velocity (v) of shark = 15 m/s.
Momentum of shark =..?
Momentum = mass (m) × velocity (v)
Momentum of shark = 200 × 15
Momentum of shark = 3000 Kg.m/s
Therefore, the momentum of the shark is 3000 Kg.m/s.
A football player threw a football with a velocity of (3.0 m/s x + 5.0m/s y). How far did it travel horizontally?
The horizontal distance travelled by the football is 3.1 m.
What is the angle of projection of the ball?
The angle of projection of the football is calculated as follows;
tan ( θ ) = Vy / Vx
where;
Vy is the velocity of the ball in the vertical directionVx is the velocity of the ball in the horizontal directiontan ( θ ) = 5 / 3
tan ( θ ) = 1.667
θ = arc tan (1.667)
θ = 59⁰
The resultant velocity of the ball is calculated as follows;
v = √ (Vx² + Vy²)
v = √ (3² + 5²)
v = 5.83 m/s
The horizontal distance travelled by the football is calculated as follows;
x = v² sin(2θ) /g
where;
v is the resultant velocityg is acceleration due to gravityθ is the angle of projection of the ballx = [ (5.83)² sin(2 x 59) /9.8 ]
x = 3.1 m
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Tech A says that total resistance goes up as more parallel paths are added. Tech B says that total amperage goes up as more parallel paths are added. Who is correct
Answer: Tech B says that total amperage goes up as more parallel paths are added. Who is correct
Explanation: Tech B is correct, because amperage has been known to go up through when more parallel paths are added to a circuit. this is so because when more resistors are introduced in parallel to a circuit, the resulting resistance of the circuit would decrease, this increases the total current of the circuit. as a result, when more resistors are added in parallel what you get is a change in the direction of flow which is equal to providing more branches which charge can flow through.
A car travels a distance of 150 m in the direction of a constant force of 50 N. The work done on the car is
Answer:
the work done on the car is 7,500 J.
Explanation:
Given;
distance traveled by the car, d = 150 m
applied force, F = 50 N
The work done on the car is calculated as;
W = F x d
W = 50 N x 150 m
W = 7,500 J
Therefore, the work done on the car is 7,500 J.
1. Label the parts of the chicken wing in the black wing diagram below
if earth's mass decreased to one-half its original mass with no change in radius, then your weight would
Answer:
Because of symmetry the gravitational field of the earth acts as though all of the mass of the earth were centered at the center of the earth - so g = G M / R^2 and W = m g weight of an individual
If the mass (M) had 1/2 of its value the weight would also be halved.
If these two objects roll up the slope without slipping, which reaches the greater maximum height? The cylindrical shell The solid disk Both reach the same maximum height More information about the objects' mass and diameter is needed.
Both the cylindrical shell and the solid disk will reach the same maximum height.
When objects roll up a slope without slipping, their maximum height depends on their initial kinetic energy (KE) and rotational kinetic energy (KE_rot). If an object reaches a greater maximum height, it means it has more total energy.
For a cylindrical shell and a solid disk with the same mass and diameter, their moments of inertia (I) will differ due to their different distributions of mass. However, the kinetic energy and rotational kinetic energy equations for rolling objects are the same:
KE = (1/2) * mv^2,
KE_rot = (1/2) * I * ω^2,
where m is the mass, v is the linear velocity, I is the moment of inertia, and ω is the angular velocity.
Since both objects are rolling without slipping, their linear velocity and angular velocity are related by the equation:
v = ω * r,
where r is the radius of the object.
If we compare the kinetic energy and rotational kinetic energy of the cylindrical shell and the solid disk, we find that their total energies are the same:
KE_total = KE + KE_rot = (1/2) * mv^2 + (1/2) * I * ω^2.
Since the total energies are equal, both objects will reach the same maximum height because they possess the same amount of energy to overcome the gravitational potential energy at the top of the slope.
Both the cylindrical shell and the solid disk, when rolling up a slope without slipping, will reach the same maximum height. This is due to the conservation of energy, where their total energies, comprising both kinetic and rotational kinetic energy, are equal. The mass and diameter of the objects are not needed to determine their relative maximum heights in this scenario.
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Please!!! I need some help!!! I will give Brainliest To anyone who truly helps.
Determine the net force charge acting at q1 (+ 2.0 × 10-5C), caused by q2 (-4.0 × 10-5 C) and q3 (-4.0 × 10-5 C). Be sure to include a free body diagram representing the force acting at q1 in your solution. Determine the net electric field acting at q1.
Answer:
Please INCLUDE a picture.
Explanation:
You did not include a picture, so there is no way to tell how the charges will interact with each other.
Please INCLUDE a picture.
The net force acting on q1 is 3.2 N to the right.
The force on q₁ due to q₂ is:
F1 = k * q₁ * q₂ / r²
where:
k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C⁻²
q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C
q₂ is the charge of q₂, which is -4.0 × 10⁻⁵ C
r is the distance between q₁ and q₂, which is 0.1 m
Plugging in the values, we get:
F₁ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.1 m)²
= 6.4 N
The force on q₁ due to q₃ is:
F₂ = k * q₁ * q₃ / r²
where:
k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C²
q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C
q₃ is the charge of q₃, which is -4.0 × 10⁻⁵ C
r is the distance between q₁ and q₃, which is 0.2 m
Plugging in the values, we get:
F₂ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.2 m)²
= 16 N
The net force on q₁ is the sum of F₁ and F₂:
Fnet = F₁ + F₂
= 6.4 N + 16 N
= 22 N
The net force on q1 is to the right because both F₁ and F₂ are to the right.
Net electric field
The net electric field acting on q1 is 3.2 N/C to the right.
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Which of the following has the smallest mass? O a. 10.0 mol of F2 O b. 5.50 x 1024 atoms of 12 O c. 3.50 x 1024 molecules of 12 O d. 255. g of Cl2 O e. 0.020 kg of Br2
The option with the smallest mass is e. 0.020 kg of Br2.Option E
To determine which option has the smallest mass, we need to compare the masses of each given quantity.
a. 10.0 mol of F2:
To find the mass, we can use the molar mass of F2, which is 38.0 g/mol. Therefore, the mass of 10.0 mol of F2 is:
10.0 mol * 38.0 g/mol = 380 g
b. 5.50 x 10^24 atoms of 12O:
To find the mass, we need to know the molar mass of 12O. However, the given molar mass is for F2, not for 12O. Therefore, we cannot determine the mass of this option.
c. 3.50 x 10^24 molecules of 12O:
Similarly, without the molar mass of 12O, we cannot determine the mass of this option.
d. 255 g of Cl2:
Since the molar mass of Cl2 is 70.9 g/mol, the number of moles in 255 g can be calculated as:
255 g / 70.9 g/mol = 3.59 mol
e. 0.020 kg of Br2:
The molar mass of Br2 is 159.8 g/mol. To convert 0.020 kg to grams, we multiply by 1000:
0.020 kg * 1000 g/kg = 20 g
Now we can determine the number of moles:
20 g / 159.8 g/mol ≈ 0.125 mol
Comparing the number of moles, we find that option d (255 g of Cl2) has the largest number of moles, indicating a larger mass compared to the other options. Among the remaining options, option e (0.020 kg of Br2) has the smallest mass. Option e
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The magnitude of F is 301 newtons and it points at 225o measured counterclockwise from the positive x-axis. What is the x component (in newtons) of F
The x-component of the force F is approximately -212.907 newtons, calculated using the magnitude of the force (301 newtons) and the angle (225 degrees).
To find the x-component of a force given its magnitude and angle, we can use trigonometry. The x-component of a force can be determined by multiplying the force magnitude by the cosine of the angle.
To find the x-component:
x-component of F = Magnitude of F * cos(\(\theta\))
Using the given values:
x-component of F = 301 newtons * cos(225°)
Calculating the cosine of 225°:
cos(225°) ≈ -0.707
Substituting the values:
x-component of F ≈ 301 newtons * (-0.707)
x-component of F ≈ -212.907 newtons
Therefore, the x-component of the force F is approximately -212.907 newtons.
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A football thrown by a professional quarterback goes farther than one thrown by a 10-year old. What Newton Law is this?
Answer:
2nd law of motion
Explanation:
Answer:
Newton's 2nd Law of Motion
Explanation:
The amount of force needed to make an object change its acceleration depends on the mass of the object. In other words, the amount of force thrown by a professional quarter-back has more acceleration from his mass.