What are 5 tactics that can reduce the likelihood of injury?

The equations of motion can be used to calculate the horizontal and maximum height of a projectile, with the horizontal range being 1003.7 meters and the maximum height being 285.2 meters.

To solve this problem, we can use the equations of motion to find the horizontal range and maximum height of the projectile. We'll start by breaking the initial velocity of the projectile into its horizontal and vertical components:

Initial velocity, v = 150 m/s

Launch angle, θ = 30°

Horizontal component, vx = v cosθ = 150 cos30° ≈ 129.9 m/s

Vertical component, vy = v sinθ = 150 sin30° ≈ 75 m/s

Maximum height:

The formula for the maximum height (hmax) reached by a projectile is given by:

hmax = (v\(y^2\))/(2g)

where g is the acceleration due to gravity, which is approximately 9.81 m/\(s^2\).

Substituting the values we have:

hmax = (\(75^2\))/(2×9.81) ≈ 285.2 meters

Therefore, the maximum height reached by the projectile is approximately 285.2 meters.

Horizontal range:

The formula for the horizontal range (R) of a projectile is given by:

R = (vx×vy)/g

where g is the acceleration due to gravity.

Substituting the values we have:

R = (129.9×75)/9.81 ≈ 1003.7 meters

Therefore, the horizontal range of the projectile is approximately 1003.7 meters.

So, the projectile will travel a horizontal distance of approximately 1003.7 meters and reach a maximum height of approximately 285.2 meters.

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The tension in the cable and the net acceleration of the block B are 291.814 newtons and 0.112 meters per square second, respectively.

Based of the representation seen in the image, an external force moves the block A downwards and the block B moves upwards and with an net acceleration of same magnitude due to the cable. By Newton's laws we construct the free body diagrams for each mass and that can be seen in the image seen below.

The motion equations are described below:

Mass A

250 N - 0.4 · Na - T + (30 kg) · (9.807 m / s²) · sin 30° = (30 kg) · a      (1)

Na - (30 kg) · (9.807 m / s²) · cos 30° = 0     (2)

Mass B

- T + 0.4 · Na + 0.3 · Nb + (15 kg) · (9.807 m / s²) · sin 30° = - (15 kg) · a     (3)

Nb - Na - (15 kg) · (9.807 m / s²) · cos 30° = 0     (4)

By (2):

Na = (30 kg) · (9.807 m / s²) · cos 30°

Na = 254.793 N

By (4):

Nb = 254.793 N + (15 kg) · (9.807 m / s²) · cos 30°

Nb = 382.190 N

Then, we have the following system of linear equations:

T + (30 kg) · a = 250 N - 0.4 · Na + (30 kg) · (9.807 m / s²) · sin 30°

T + 30 · a = 295.188

T - (15 kg) · a = 0.4 · Na + 0.3 · Nb + (15 kg) · (9.807 m / s²) · sin 30°

T - 15 · a = 290.127

The solution of the linear system is T = 291.814 N and a = 0.112 m / s².

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Answer:

Heyaa!! Im Pinky!! and i'm here to inform you that you're answer is....

Explanation:

!!!! The microphone is the part of the telephone the converts sound waves into electrical signals that can be sent through the phone line and then towards the receiver on the other side. The telephone is one of the most important inventions made by man as it allowed communication to speed up through time !!!!

Have a Nice Dayy!!!

~Pinky~

The correct answer is C. Biomedical engineering.

The area of Biomedical engineering is a distinct field that utilizes methods and concepts from engineering to address medical challenges and innovations.

The task involves enhancing healthcare delivery, diagnosis, and treatment via the creation and engineering of diverse medical devices, equipment, and pharmaceuticals.

A vast array of products falls under this area, such as tools for diagnosing medical conditions like magnetic resonance imaging (MRI) and computerized tomography (CT) scanners, medical equipment for treatment purposes such as pacemakers or insulin pumps, medications for various illnesses, and prosthetic limbs designed to aid those with limited mobility.

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Answer:

DDDDDDDD

Explanation:

I THINK...............

Answer:

B. wheel cylinders

Explanation:

Answer:

the vehicle serviced for the same problem more than once

Answer:

Dear [Boss],

I am writing to recommend that our firm pursue a future in designing high-end alternative housing solutions. There is a growing demand for cutting-edge, sustainable housing options, and I believe our firm is well-positioned to meet this demand.

One area of opportunity is the use of recycled and reused materials in these builds. By incorporating materials such as reclaimed wood, recycled steel, and repurposed bricks, we can not only reduce our environmental impact, but also differentiate ourselves from other housing developers.

There are, of course, challenges to using these types of materials. They may require more time and effort to source, and there may be additional costs associated with their use. However, I believe the benefits of using recycled and reused materials far outweigh these challenges. Not only do they reduce waste and decrease our carbon footprint, they also have the potential to add unique character and value to our projects.

In terms of how to move forward, I recommend that we begin by researching and identifying specific recycled and reused materials that align with our design aesthetic and can be incorporated into our projects. We can also consider partnering with organizations or suppliers that specialize in these types of materials.

Overall, I believe that designing high-end alternative housing solutions using recycled and reused materials is a viable and exciting opportunity for our firm. By embracing this trend, we can not only meet the needs of an increasingly environmentally-conscious market, but also differentiate ourselves in a crowded industry.

Sincerely,

[Your Name]

Explanation:

Biomedical engineers may need to dilute solutions for several reasons. One common reason is to adjust the concentration of a particular substance to a desired level for experimental or clinical purposes.

Dilution allows for precise control over the concentration of a solution, enabling researchers or healthcare professionals to study the effects of different concentrations of substances on biological systems.

In biomedical engineering, dilution is often employed when working with drugs or therapeutic agents. By diluting a concentrated drug solution, engineers can create different dosages suitable for specific applications. This is crucial for ensuring patient safety and achieving desired therapeutic outcomes.

Additionally, dilution is necessary for calibration and quality control purposes in biomedical engineering. Diluting stock solutions of known concentrations can generate a range of standard solutions used to calibrate instruments, verify measurement techniques, or assess the accuracy of analytical methods.

Dilution plays a critical role in ensuring accurate and reliable data collection, analysis, and experimentation within the field of biomedical engineering.

In summary, dilution is an essential technique for biomedical engineers as it allows them to control the concentration of substances, customize drug dosages, and maintain accuracy in calibration and quality control processes, all of which are vital for research, development, and healthcare applications.

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Answer:

I believe the correct answer would be Weight.

Weight is a force that gravity exerts on an object.

Hope this helped :))))

2x4 = 8

2x6 = 12

2x8 = 16

2x10 = 20

2x12 = 24

4x4 = 16

The idea that the three pyramids of Giza are the greatest feat of engineering ever is widely accepted among historians and experts.

These majestic structures, built over 4,500 years ago, continue to amaze and baffle people today. Here's why:
1. Monumental size: The pyramids of Giza are colossal structures, with the largest, the Great Pyramid of Khufu, standing at over 450 feet tall.

Constructing such massive structures without modern machinery or technology is a remarkable achievement.
2. Precision and alignment: The pyramids were meticulously built with incredible precision. The sides of the pyramids align almost perfectly with the cardinal points of the compass.

The accuracy of the alignment is a testament to the advanced astronomical knowledge possessed by the ancient Egyptians.
3. Construction techniques: The pyramids were built using immense blocks of limestone, weighing several tons each. The precise cutting and fitting of these massive blocks required advanced engineering skills.

The construction techniques used, such as ramps and pulleys, demonstrate the innovative methods employed by ancient Egyptian engineers.
4. Longevity: Despite being thousands of years old, the pyramids have stood the test of time. They have survived earthquakes, erosion, and countless other natural and human-induced threats.

The durability of the pyramids is a testament to the engineering prowess of the ancient Egyptians.
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Answer:

to find a solution to a problem.

Explanation:

The engineering design process, by definition, is a series of steps that engineers use to find a solution to a problem. These steps include: defining the problem, brainstorming solutions, designing and building a prototype of the solution, testing the solution, and improving it.

Based on the concept of engineering lessons, making a paper airplane relates to STEM in many ways as it develops students to have key scientific concepts like aerodynamics, velocity, thrust, speed, and other scientific forces.

STEM is an acronym word for Science technology, engineering, and mathematics combined as various academic disciplines.

Generally, the term STEM is commonly used to cover an education policy or curriculum choices in schools. It has significance for workforce development, national security concerns, and immigration policy.

Given that making a paper airplane has many engineering principles, it is concluded that it relates to the STEM discipline in many ways.

Therefore, making and playing with paper planes among the students can lead to conversations about aerodynamics (the forces that impact plane flight): thrust, lift, drag, and gravity/weight.

In some cases, like high school children, it is expected that they can learn about plane movements like roll, yaw, and pitch all of which were established based on the principle of STEM

Hence, in this case, it is concluded that making the paper plane is related to STEM in many ways.

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Answer:

onii-san?

Explanation:

Answer:

onii-san 0.o

Explanation:

It means older brother

Answer:

false

Explanation:

this is false because electronics are the only thing that is technology

The statement made by Technician A is inaccurate. The hybrid car's electric propulsion system does not boost the idle speed of the internal combustion engine.

Rather than idling the engine, the electric motor is usually able to supply power when the vehicle is at a standstill or moving at a slow pace, thus resulting in reduced or eliminated engine idle needs.

The accuracy of Technician B's statement is somewhat accurate. Hybrid cars' regenerative braking systems efficiently accumulate the energy released during deceleration, converting it into electrical energy and storing it in the battery.

The system's responsibility of reducing the vehicle's speed can actually diminish the wear on usual brake components, rather than intensifying it. The reason for this is that the vehicle requires lower levels of friction when the regenerative braking is actively assisting in decelerating.

Both Technician A and Technician B are partly erroneous in their assertions.

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Answer:

Did you need help answering this?

Explanation:

Answer:

Pseudocode is an artificial and informal language that helps programmers develop algorithms. Pseudocode is a "text-based" detail (algorithmic) design tool. The rules of Pseudocode are reasonably straightforward. All statements showing "dependency" are to be indented. These include while, do, for, if, switch.

Answer:

One reason why stripping tool designed for use with solid wire cannot be used on stranded wire is that the diameter of a stranded wire is larger than the diameter of a solid wire of the same gauge.

Therefore, a tool for stripping a 8-gauge solid wire cannot be used for stripping a 8-gauge stranded wire as the diameter of an American Wire Gauge, AWG 8-guage solid  wire (0.129 inches in diameter) is smaller than the diameter of an AWG 8-gauge stranded wire (0.152 inches in diameter)

Explanation:

The Answers for the given question are as follow:

a. The model speed is approximately 31.62 rev/min.

b. The scale ratio is approximately 0.0417.

c. The estimated volume flow rate through the model is approximately 943.44 m^3/s.

d. The bearing thrust of the model is approximately 9.72 kN.

To calculate the required values for the water turbine model, we can utilize the concept of dynamic similarity.

a. To find the model speed, we can use the principle of geometric similarity, which states that the ratio of speeds is equal to the ratio of the square roots of the head. Thus:

  Model speed = (√(Model head))/(√(Full-size head)) * Full-size speed

              = (√4.9/√16.5) * 93.7 rev/min

              = 31.62 rev/min

b. The scale ratio can be determined using the equation:

  Scale ratio = (√(Model power))/(√(Full-size power))

             = (√37.5kW)/(√27MW)

             ≈ 0.0417

c. To estimate the volume flow rate through the model, we can use the power equation:

  Model power = (Model efficiency) * (Volume flow rate) * (Model head) * (Gravity)

  37.5kW = 0.88 * (Volume flow rate) * 4.9m * (9.81m/s^2)

  Solving for the volume flow rate:

  Volume flow rate = 37.5kW / (0.88 * 4.9m * 9.81m/s^2)

                   ≈ 943.44 m^3/s

d. To calculate the bearing thrust of the model, we can use the principle of force similarity:

  Bearing thrust model = (Model power / Full-size power) * Full-size bearing thrust

                      = (37.5kW / 27MW) * 7.0GN

                      ≈ 9.72kN

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As per the data given in the question, the perimeter of rectangle ABCDA is 14 units.

To find the perimeter of the rectangle ABCDA, we need to calculate the sum of the lengths of all four sides.

The coordinates of the vertices are as follows:

A(2, -6)

B(5, -6)

C(5, -2)

D(2, -2)

Let's calculate the length of each side:

Side AB: Distance between points A and B

AB = sqrt\(((5 - 2)^2 + (-6 - (-6))^2)\)

  = \(sqrt(3^2 + 0^2)\)

  = sqrt(9)

  = 3

Side BC: Distance between points B and C

BC = sqrt\(((5 - 5)^2 + (-2 - (-6))^2)\)

  = sqrt\((0^2 + 4^2)\)

  = sqrt(16)

  = 4

Side CD: Distance between points C and D

CD = sqrt\(((2 - 5)^2 + (-2 - (-2))^2)\)

  = sqrt\(((-3)^2 + 0^2)\)

  = sqrt(9)

  = 3

Side DA: Distance between points D and A

DA = sqrt\(((2 - 2)^2 + (-2 - (-6))^2)\)

  = sqrt\((0^2 + 4^2)\)

  = sqrt(16)

  = 4

Now, let's calculate the perimeter by adding the lengths of all four sides:

Perimeter = AB + BC + CD + DA

         = 3 + 4 + 3 + 4

         = 14

Therefore, the perimeter of rectangle ABCDA is 14 units.

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Answer:

The most important thing is to try and inspire people so that they can be great in whatever they want to do. Everything negative - pressure, challenges - is all an opportunity for me to rise. If you're afraid to fail, then you're probably going to fail.

Answer:

C

Explanation:

because it is more professional then what the other answers are.

Answer:

B.  It can add to an engineer’s credentials and qualifications.

Explanation:

Answer:

B. It can add to an Engineer's credentials and qualifications.

Explanation:

Answer:

a) A suspended floor is a ground floor with a void underneath the structure. The floor can be formed in various ways, using timber joists, precast concrete panels, block and beam system or cast in-situ with reinforced concrete. However, the floor structure is supported by external and internal walls.

b) Soil exploration consists of determining the profile of the natural soil deposits at the site, taking the soil samples and determining the engineering properties of soils using laboratory tests as well as in-situ testing methods

c) Bulking in sand Occurs When dry sand interacts with the atmospheric moisture. Presence of moisture content forms a thin layer around sand particles. This layer generates the force which makes particles to move aside to each other. This results in the increase of the volume of sand.

d) In a nutshell, bearing capacity is the capacity of soil to support the loads that are applied to the ground above. It depends primarily on the type of soil, its shear strength and its density. It also depends on the depth of embedment of the load – the deeper it is founded, the greater the bearing capacity.

Explanation:

Answer:

C) deployment engineer, software engineer, test engineer, technical writer, trainer

Explanation:

Answer:

c

Explanation:

i took the mf test

Answer:

1. Always Start by calculating reactions at supports.

2. Make a slice through the members you wish to solve.

3. Treat the half structure as its own static truss.

4. Solve the truss by taking the sum of forces = 0.

5. Take the moment about a node of more than one unknown member.