what are triglycerides?

Answer:

The average force of wind on the building is 4.728 x 10¹² N

Explanation:

Given;

speed of the air wind, v = 124 km/h

dimension of the building, 42 m wide by 73 m high

density of the air, ρ = 1.3 kg/cm³ =

speed of the air in m/s = 124/3.6 = 34.44 m/s

Area of the building, A = 42 m x 73 m = 3066 m²

density of the air in (k.g/m³);

\(\rho = \frac{1.3 \ kg}{cm^3} *(\frac{100\ cm}{1 \ m} )^3\\\\\rho = \frac{1.3 \ kg}{cm^3} *\frac{10^6\ cm^3}{1 \ m^3} = \frac{1.3*10^6 \ kg}{m^3}\)

The average force of wind on the building;

F = mass flow rate x velocity

F = (ρvA) x V

F = ρAv²

F = 1.3 x 10⁶ x 3066  x (34.44)²

F = 4.728 x 10¹² N

Therefore, the average force of wind on the building is 4.728 x 10¹² N

The focal length is the sum of the focal lengths of the front and back surfaces, which equals 70 cm.

The complete question is,

A narrow plano-convex lens' focal length should be determined. This lens's back surface is curved at a radius of R 2R 2 = approximately 35 cm, while its front surface is flat. Let's say the lens has an index of refraction of 1.5.      

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Answer:

By making the object sharp pointed

The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].

The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.

The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.

To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]

Y = 4.95sin[π(3.80x - 1180t - 0.206)]

The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.

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-- The given question is incomplete, the complete question is

"Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]

Y2 : 4.95sin[π(3.80x-1180t-0.250)]

Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --

When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.

Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.

What exactly does the Law of Gravitation apply to  According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.

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When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.

Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.

What exactly does the Law of Gravitation apply to  According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.

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The unstretched length of the bungee cord is  29.4 m.

Simple harmonic motion is a type of periodic motion in which the displacement of an object from its equilibrium position is directly proportional to the force acting on it and is always directed towards the equilibrium position. It is characterized by a sinusoidal pattern of motion and has many real-world applications, including in oscillations of springs and pendulums.

We can solve this problem by applying the principles of simple harmonic motion (SHM) to the bungee jumper's oscillations.

Let's begin by finding the period of oscillation, T. The time it takes for the bungee jumper to reach the lowest point and return to the same point is one period of oscillation. From the problem, we know that the bungee jumper completes 6 cycles (5 low points plus the initial jump) in 28.0 s. Therefore, the period of oscillation is:

T = 28.0 s / 6 = 4.67 s

Next, we can use the formula for the period of an object undergoing SHM to find the spring constant, k, of the bungee cord:

T = 2π √(m/k)

where m is the mass of the bungee jumper. Rearranging this formula to solve for k, we get:

k = (4π²m) / T²

Substituting the given values, we get:

k = (4π² × 50.0 kg) / (4.67 s)² = 360 N/m

So the spring constant of the bungee cord is approximately 360 N/m.

To find the unstretched length of the bungee cord, we can use the fact that the bungee jumper comes to rest 27.0 m below the level of the bridge. At this point, all of the potential energy from the initial jump has been converted into elastic potential energy stored in the bungee cord. Therefore, the total energy of the system is:

E = mgh = (1/2)kx²

where h is the height from which the bungee jumper initially jumped (we assume that there is no air resistance), and x is the unstretched length of the bungee cord.

Substituting the given values, we get:

(50.0 kg)(9.81 m/s²)(27.0 m) = (1/2)kx²

Solving for x, we get:

x = √[(2mgh)/k] = √[(2 × 50.0 kg × 9.81 m/s² × 27.0 m) / 360 N/m] ≈ 29.4 m

Hence, the unstretched length of the bungee cord is approximately 29.4 m.

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When a mass m particle is released onto a smooth inclined plane (where the frictional force F=0), it will glide down the slope.

We resolve in the direction of motion in order to get the particle's sliding acceleration.

F=ma, 

mg cos(90∘−θ)=ma, 

g cos(90∘−θ)=a, 

g sin(θ)=a.

How many Newtons is the net force while the block is travelling at a constant speed?

Zero. Newton's first law of motion states that any object travelling at a constant speed experiences no net external forces, hence the total amount of forces acting on the object must be zero. The mathematical expression for an item being under no net external force is Fnet=0 or F=0.

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The time the wheel would take for the disk with twice the radius and twice the mass to come to a stop would be 480 seconds.

This is because the moment of inertia, which is the measure of an object's resistance to changes in its rotation rate, depends on both the mass and the radius of the disk. Specifically, the moment of inertia of a solid disk is given by

I = 1/2 * mass * radius^2.

Since the disk in question has twice the mass and twice the radius, its moment of inertia will be 8 times greater than the original disk. This means that it will take 8 times longer for the disk to come to a stop under the same frictional force.

Therefore, the time it would take for the disk with twice the radius and twice the mass to come to a stop is 8 * 60 seconds = 480 seconds.

Therefore, the time the wheel would take to come to a stop from the same initial rotational speed If the disk had twice the radius and twice the mass is 480 seconds.

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b. Perspiration dries on a person's skin.

Vaporization, conversion of a substance from the liquid or solid phase into the gaseous phase.

Evaporation is a phase transition from the liquid phase to vapor (a state of substance below critical temperature) that occurs at temperatures below the boiling temperature at a given pressure.

When we are sweating:

Some of sweat has to evaporate off of your skin for this process to actually work. That's because cooling your body via sweating relies on a principle of physics called "heat of vaporization."

It takes energy to evaporate sweat off of your skin, and that energy is heat. As your excess body heat is used to convert beads of sweat into vapor, you start to cool down.

When the sweat hits the air, the air makes it evaporate (this means it turns from a liquid to a vapor.

As the sweat evaporates off your skin, you cool down.

Sweat is a great cooling system, but if you're sweating a lot on a hot day or after playing hard you could be losing too much water through your skin.

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Answer:

Option (a)

Explanation:

Given that,

Mass of a car, m = 1200 kg

Force exerted by the engine, F = 600 N

Noe force,F = ma

a is the acceleration of the engine

\(a=\dfrac{F}{m}\\\\a=\dfrac{600\ N}{1200\ kg}\\\\a=0.5\ m/s^2\)

So, the acceleration of the car is 0.5 m/s².

Answer:

0.5 m/s^2

Hope it works!

Explanation:

The time taken to fire the rocket at the given thrust is 1,382.3 seconds.

The centripetal acceleration of the wheel is calculated by applying the following formula.

F = ma

where;

a = F / m

a = (100 N) / (5 x 10⁵)

a = 2 x 10⁻⁴ m/s²

The velocity of the wheel is calculated as follows;

a = v²/r

where;

v² = ar

v = √ (ar)

v = √ (2 x 10⁻⁴ x 11 )

v = 0.05 m/s

The time of motion of the motion of the rockets at the given speed is calculated as;

v = 2πr / T

T = 2πr / v

T = (2π x 11) / (0.05)

T = 1,382.3 seconds

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It is female (XO).A karyotype can be used to diagnose a chromosomal disorder by examining the number and arrangement of a person's chromosomes.

Chromosomes are thread-like structures located in the nucleus of cells that carry genetic information in the form of genes. They are composed of DNA and proteins and are responsible for directing the development and functioning of cells. In humans, chromosomes come in pairs of 23, with one copy of each pair inherited from each parent.

For example, Down Syndrome is caused by an extra chromosome 21, Klinefelter Syndrome is caused by an extra X chromosome in males (XXY), and Turner Syndrome is caused by a single X chromosome in females (XO).

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Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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The researcher did not find strong evidence to support the idea that job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

It sounds like the researcher conducted an experiment to investigate whether job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

Based on the information provided, the researcher found that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level.

The factors that play an important role in the hiring process for a job:

(1) Qualifications and experience: Employers typically look for candidates who possess the necessary qualifications and experience for the job. This includes education, training, certifications, and work experience.

(2) Skills and abilities: Employers also consider a candidate's skills and abilities related to the job. These may include technical, interpersonal, communication, and problem-solving skills.

(3) Personal characteristics: Personal characteristics, such as motivation, work ethic, and adaptability, can also play a role in the hiring process. Employers may look for candidates who demonstrate a positive attitude, a willingness to learn, and the ability to work well with others.

(4) Fit with company culture: Companies may also consider whether a candidate fits with their company culture, values, and mission. This can include factors such as teamwork, creativity, and innovation.

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Answer:

0.66secs

Explanation:

Given the following

Initial speed u = 24.2m/s

Height H = 18m

Required

Time t

Using the equation of motion:

H = ut+1/2gt²

18 = 24.2t+1/2(9.8)t²

18 = 24.2t+0.5(9.8)t²

18 = 24.2t+4.9t²

Rearrange

4.9t²+24.2t -18 = 0

Using the general formula

t = -24.2±√24.2²-4(4.9)(-18)/2(4.9)

t = -24.2±√585.64+352.8/9.8

t = -24.2±√938.44/9.8

t=-24.2+30.63/9.8

t= 6.43/9.8

t = 0.66secs

The ball will be at the same height after 0.66secs

Answer:

I = ΔVA[1 - α (T₀ - T)]/Lρ₀

Explanation:

We have the following data:

ΔV = Battery Terminal Voltage

I = Current through wire

L = Length of wire

A = Cross-sectional area of wire

T = Temperature of wire, when connected across battery

T₀ = Reference temperature

ρ = Resistivity of wire at temperature T

ρ₀ = Resistivity of wire at reference temperature

α = Temperature Coefficient of Resistance

From OHM'S LAW we know that;

ΔV = IR

I = ΔV/R

but,  R = ρL/A   (For Wire)

Therefore,

I = ΔV/(ρL/A)

I = ΔVA/ρL

but,   ρ = ρ₀[1 + α (T₀ - T)]

Therefore,

I = ΔVA/Lρ₀[1 + α (T₀ - T)]

I = [ΔVA/Lρ₀] [1 + α (T₀ - T)]⁻¹

using Binomial Theorem:

(1 +x)⁻¹ = 1 - x + x² - x³ + ...

In case of [1 + α (T₀ - T)]⁻¹, x = α (T₀ - T).

Since, α generally has very low value. Thus, its higher powers can easily be neglected.

Therefore, using this Binomial Approximation, we can write:

[1 + α (T₀ - T)]⁻¹ = [1 - α (T₀ - T)]

Thus, the equation becomes:

I = ΔVA[1 - α (T₀ - T)]/Lρ₀

Answer:

d=91m

Explanation:

Answer:

720W

Explanation:

PLEASE MARK ME AS BRAINLIEST AND HAVE A NICE DAY

Answer:

a) The magnitude of the friction force is 55.851 newtons, b) The speed of the crate when it reaches the bottom of the ramp is 2.526 meters per second.

Explanation:

a) This situation can be modelled by the Principle of Energy Conservation and the Work-Energy Theorem, where friction represents the only non-conservative force exerting on the crate in motion. Let consider the bottom of the straight ramp as the zero point. The energy equation for the crate is:

\(U_{g,1}+K_{1} = U_{g,2}+K_{2}+ W_{fr}\)

Where:

\(U_{g,1}\), \(U_{g,2}\) - Initial and final gravitational potential energy, measured in joules.

\(K_{1}\), \(K_{2}\) - Initial and final translational kinetic energy, measured in joules.

\(W_{fr}\) - Work losses due to friction, measured in joules.

By applying the defintions of translational kinetic and gravitational potential energies and work, this expression is now expanded:

\(m\cdot g \cdot y_{1} + \frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot y_{2} + \frac{1}{2}\cdot m\cdot v_{2}^{2} + \mu_{k}\cdot m \cdot g \cdot \cos \theta\)

Where:

\(m\) - Mass of the crate, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(y_{1}\), \(y_{2}\) - Initial and final height of the crate, measured in meters.

\(v_{1}\), \(v_{2}\) - Initial and final speeds of the crate, measured in meters per second.

\(\mu_{k}\) - Kinetic coefficient of friction, dimensionless.

\(\theta\) - Ramp inclination, measured in sexagesimal degrees.

The equation is now simplified and the coefficient of friction is consequently cleared:

\(y_{1}-y_{2}+\frac{1}{2\cdot g}\cdot (v_{1}^{2}-v_{2}^{2}) = \mu_{k}\cdot \cos \theta\)

\(\mu_{k} = \frac{1}{\cos \theta} \cdot \left[y_{1}-y_{2}+\frac{1}{2\cdot g}\cdot (v_{1}^{2}-v_{2}^{2}) \right]\)

The final height of the crate is:

\(y_{2} = (1.6\,m)\cdot \sin 30^{\circ}\)

\(y_{2} = 0.8\,m\)

If \(\theta = 30^{\circ}\), \(y_{1} = 0\,m\), \(y_{2} = 0.8\,m\), \(g = 9.807\,\frac{m}{s^{2}}\), \(v_{1} = 5\,\frac{m}{s}\) and \(v_{2} = 0\,\frac{m}{s}\), the coefficient of friction is:

\(\mu_{k} = \frac{1}{\cos 30^{\circ}}\cdot \left\{0\,m-0.8\,m+\frac{1}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\cdot \left[\left(5\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right] \right\}\)

\(\mu_{k} \approx 0.548\)

Then, the magnitude of the friction force is:

\(f =\mu_{k}\cdot m\cdot g \cdot \cos \theta\)

If \(\mu_{k} \approx 0.548\), \(m = 12\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(\theta = 30^{\circ}\), the magnitude of the force of friction is:

\(f = (0.548)\cdot (12\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \cos 30^{\circ}\)

\(f = 55.851\,N\)

The magnitude of the force of friction is 55.851 newtons.

b) The energy equation of the situation is:

\(m\cdot g \cdot y_{1} + \frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot y_{2} + \frac{1}{2}\cdot m\cdot v_{2}^{2} + \mu_{k}\cdot m \cdot g \cdot \cos \theta\)

\(y_{1}+\frac{1}{2\cdot g}\cdot v_{1}^{2} =y_{2} + \frac{1}{2\cdot g}\cdot v_{2}^{2} + \mu_{k}\cdot \cos \theta\)

Now, the final speed is cleared:

\(y_{1}-y_{2}+ \frac{1}{2\cdot g}\cdot v_{1}^{2} -\mu_{k}\cdot \cos \theta= \frac{1}{2\cdot g}\cdot v_{2}^{2}\)

\(2\cdot g \cdot (y_{1}-y_{2}-\mu_{k}\cdot \cos \theta) + v_{1}^{2} = v_{2}^{2}\)

\(v_{2} = \sqrt{2\cdot g \cdot (y_{1}-y_{2}-\mu_{k}\cdot \cos \theta)+v_{1}^{2}}\)

Given that \(g = 9.807\,\frac{m}{s^{2}}\), \(y_{1} = 0.8\,m\), \(y_{2} = 0\,m\), \(\mu_{k} \approx 0.548\), \(\theta = 30^{\circ}\) and \(v_{1} = 0\,\frac{m}{s}\), the speed of the crate at the bottom of the ramp is:

\(v_{2}=\sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot [0.8\,m-0\,m-(0.548)\cdot \cos 30^{\circ}]+\left(0\,\frac{m}{s} \right)^{2}}\)

\(v_{2}\approx 2.526\,\frac{m}{s}\)

The speed of the crate when it reaches the bottom of the ramp is 2.526 meters per second.

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a)  Let us assume the depth be h

As we know that

\(Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h\)

After solving this,  

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

b)

Given that  

height of the extra fluid is

\(h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}\)

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

\(Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000\)

Pb' = 122 KPa

(A)  The depth of the fluid is 2.14 m.

(B)  The new pressure at the bottom of container is 121972 Pa.

Given data:

The cross-sectional area of the container is, \(A =66.2 \;\rm cm^{2}=66.2 \times 10^{-4} \;\rm m^{2}\).

The density of fluid is, \(\rho = 856 \;\rm kg/m^{3}\).

The container pressure at bottom is, \(P=119 \;\rm kPa=119 \times 10^{3} \;\rm Pa\).

The atmospheric pressure is, \(P_{at}=101 \;\rm kPa=101 \times 10^{3}\;\rm Pa\).

(A)

The given problem is based on the net pressure on the container, which is equal to the difference between the pressure at the bottom and the atmospheric pressure. Then the expression is,

\(P_{net} = P-P_{at}\\\\\rho \times g \times h= P-P_{at}\)

Here, h is the depth of fluid.

Solving as,

\(856\times 9.8 \times h= (119-101) \times 10^{3}\\\\h=\dfrac{ (119-101) \times 10^{3}}{856\times 9.8}\\\\h= 2.14 \;\rm m\)

Thus, the depth of the fluid is 2.14 m.

(B)

For an additional volume of \(2.35 \times 10^{-3} \;\rm m^{3}\) to the liquid, the new depth is,

\(V=A \times h'\\\\h'=\dfrac{2.35 \times 10^{-3}}{66.2 \times 10^{-4}}\\\\h'=0.36 \;\rm m\)

Now, calculate the new pressure at the bottom of the container as,

\(P'-P_{at}= \rho \times g \times (h+h')\\\\\P'-(101 \times 10^{3})= 856 \times 9.8 \times (2.14+0.36)\\\\P'=121972 \;\rm Pa\)

Thus, we can conclude that the new pressure at the bottom of container is 121972 Pa.

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Answer:

jnfal4u4ryhfsbjls5

Explanation:

duehdakjweyedufkbshegygfr

To remove an ice plug from a production pipe, you can follow these general steps:

Safety precautions: Ensure you are wearing appropriate personal protective equipment (PPE) such as gloves and eye protection. Ice removal procedures can involve using sharp tools or applying pressure, so safety is paramount.

Identify the location of the ice plug: Determine the exact location of the ice plug in the production pipe. This information will help you plan the removal procedure effectively.

Thawing the ice plug: There are several methods to thaw the ice plug, depending on the circumstances and available resources. Here are a few commonly used techniques:

a. Heat application: Use a heat source such as a heat gun or an electric heat blanket to warm the pipe and melt the ice. Be cautious not to apply excessive heat, as it could damage the pipe or create safety hazards.

b. Hot water circulation: If possible, circulate hot water through the pipe to gradually melt the ice plug. This method is often used when dealing with larger ice blockages.

c. Steam injection: Injecting steam into the pipe can provide efficient heat transfer and accelerate the melting process. However, this method requires specialized equipment and should be performed by trained personnel.

d. Chemical agents: In some cases, specific chemicals may be used to lower the freezing point of the ice or promote melting. However, this method should be used cautiously, considering the potential environmental impact and the compatibility of chemicals with the pipe material.

Monitor progress: As you apply the thawing method, periodically check the pipe to monitor the progress. Be patient and avoid using excessive force, as sudden releases of pressure can be hazardous.

Assist the melting process: To expedite the melting of the ice plug, you can gently tap the pipe or use non-abrasive tools to break up any loose ice. This can help facilitate the flow of water and aid the thawing process.

Maintain a controlled environment: If possible, create a controlled environment around the affected pipe section. Insulating the pipe or providing external heat sources can help maintain a higher temperature and prevent further freezing.

Resume production: Once the ice plug has completely melted, inspect the pipe for any damage or residual ice fragments. Ensure the pipe is clear before resuming production.

It is important to note that the specific procedure may vary depending on the size and material of the production pipe, as well as the available resources and safety protocols. When dealing with critical systems or complex ice plug situations, it is advisable to consult with experts or professionals with experience in ice plug removal.

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Answer:

A5 A20 A32 5G A1 G A20 5G T mOBIL

Answer:

Change its velocity by 10 m/s in 1s

Explanation:

It will take the airplane approximately 15,116 seconds, or about 4.2 hours, to travel 10,924 km to Rome, Italy.

To find the time it takes for the airplane to travel 10,924 km, we can use the formula:

time = distance / speed

where distance is 10,924 km and speed is 988 km/hr.

First, we need to convert the airplane's weight of 41,000 kg to Newtons, the unit of force used in physics:

force = mass x acceleration due to gravity

force = 41,000 kg x 9.8 m/s^2 = 401,800 N

Now, we can use Newton's second law of motion, which states that force equals mass times acceleration, to find the acceleration of the airplane:

force = mass x acceleration

401,800 N = 41,000 kg x acceleration

acceleration = 9.8 m/s^2

we can use the kinematic equation

distance = (1/2) x acceleration x time^2 + initial velocity x time

Since the airplane starts from rest, the initial velocity is 0, so we can simplify the equation to

distance = (1/2) x acceleration x time^2

Solving for time,

time = square root(2 x distance / acceleration)

Plugging in the values ,

time = square root(2 x 10,924,000 m / 9.8 m/s^2 x 1000) = 15,116 seconds

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At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

1/f1 = 1/v - 1/u1

1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)

1/f1 = 0 - 4

1/f1 = -4

f1 = -1/4

f1 = -0.25 meters

The initial lens power (P1) is the reciprocal of the focal length:

P1 = 1/f1

P1 = 1/-0.25

P1 = -4 diopters

Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:

1/f2 = 1/v2 - 1/u1

1/f2 = 1/0.40 - 1/0.25

1/f2 = 2.5 - 4

1/f2 = -1.5

f2 = -1/1.5

f2 = -0.67 meters

The final lens power (P2) is the reciprocal of the focal length:

P2 = 1/f2

P2 = 1/-0.67

P2 ≈ -1.49 diopters

Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

Read  more on power of lenses here https://brainly.com/question/30995178

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Answer:

44M 64M

Explanation:

Answer:

Object C has the most potential energy.

Between A and B, we do not know which has more potential energy.

Explanation:

We know the object with the most potential energy and this is the object at C.

Potential energy is the energy due to the position of a body above the ground surface.

The higher a body is above ground, the more its potential energy.

 Potential energy  = mass x acceleration due to gravity x height

So;

 Object C has the most potential energy.

Between A and B, we do not know which has more potential energy.

This is because, the height and mass of the objects are not quantified using numbers.

Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.

Answer:

Third parties may also help voter turnout by bringing more people to the polls. Third party candidates at the top of the ticket can help to draw attention to other party candidates down the ballot, helping them to win local or state office.

Answer:

IM answering so you can give the other guy brain cuz he smart.

Explanation: