What element has the following electron configuration? 1s 22s 22p 63s 23p 64s 2

Answer: I believe the answer is B. Sorry if i'm wrong

Explanation:

Explanation:

Moles of Carbon used

= 48g / (12g/mol) = 4.0mol.

Moles of Oxygen used

= 128g / (32g/mol) = 4.0mol.

C + O2 => CO2

Therefore 4.0mol of CO2 is produced, which is equal to 91.2dm³ or 176g. (depending on gas or solid)

The rate of CO2 increase is in the last few hundred years is 10 times more with the rate of increase (or decrease, for that matter) in the preceding 400,000 years.

There are many possible reasons for this cause , some primary factors are listed below:

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Answer:

When a molecule has just has one carboxylic acid group, it is defined as a monocarboxylic acid.

Explanation:

hope it will help ^_^

Answer:

sksksk

Explanation:

anna oop

Answer:

Try putting Dd okkkkkkkk

The cultures of prehistoric humans are primarily known through the excavation of stone tools and other durable artifacts, such as the Oldowan and Acheulian tool traditions.

Stone tools and imperishable artifacts serve as key archaeological evidence for understanding prehistoric cultures. Through meticulous excavation and analysis, archaeologists have been able to piece together the lifestyles, technological advancements, and social behaviors of early human societies. The term "paleolithic" refers to the Old Stone Age, a time when humans relied on stone tools as their primary implements.

The Oldowan tool tradition is considered the earliest stone tool industry, dating back around 2.6 million years ago. It is characterized by simple tools, such as choppers and scrapers, which were crafted by flaking off pieces from larger stones. These tools were primarily used for basic activities like butchering and processing animal carcasses.

Later, the Acheulian tool tradition emerged around 1.76 million years ago, representing an advancement in stone tool technology. Acheulian tools, such as handaxes and cleavers, were more refined and standardized, showcasing an increased level of sophistication in tool-making techniques. These tools served a wide range of purposes, including hunting, woodworking, and shaping raw materials.

By studying the Oldowan and Acheulian tool traditions, researchers gain valuable insights into the cognitive abilities, cultural development, and technological progress of early humans. The examination of these artifacts provides evidence of their adaptability, problem-solving skills, and the gradual refinement of their tool-making techniques over time.

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The correct statement is Net ionic equations only show the species that actually change during the reaction. (C)

This means that the net ionic equation only includes the ions or molecules that participate in the reaction, excluding any spectator ions that do not undergo any chemical change. The complete ionic equation, on the other hand, shows all the ions present in the reaction, including the spectator ions. (C)

Strong electrolytes are written as ions in both molecular and complete ionic equations, while weak electrolytes are only partially dissociated into ions in the complete ionic equation. Therefore, statement A and B are incorrect, and statement D is only partially correct.

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The number of particles in 2.38 g ammonium phosphate are \(\rm \bold{9.0345\;\times\;10^2^1}\).

The number of particles in a mole of sample is given by Avogadro law. The number of particles in a mole of a sample is equivalent to \(\rm 6.023\;\times\;10^2^3\).

The given mass of ammonium phosphate is 2.38 g.

The molar mass of ammonium phosphate is 149 g/mol

The moles of the sample is given as:

\(\rm Moles=\dfrac{Mass}{Molar\;mass} \\\\Moles\;(NH_4)_3PO_4=\dfrac{2.38\;g}{149\;g/mol}\\\\ Moles\;(NH_4)_3PO_4=0.015\;mol\)

The available moles of ammonium phosphate is 0.015 mol.

According to Avogadro's law, the number of particles in the sample is given as:

\(\rm 1\;mol=6.023\;\times\;10^2^3\;particles\\\\0..015\;mol=\dfrac{6.023\;\times\;10^2^3\;particles}{1\;mol}\;\times\;0.015\;mol\\\\ 0.015\;mol=9.0345\;\times\;10^2^1\;particles\)

The number of particles in 2.38 g ammonium phosphate are \(\rm \bold{9.0345\;\times\;10^2^1}\).

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To contain five electrons with three of them unpaired, we need five degenerate orbitals.

Orbitals within the same energy level in an atom or molecule that have the same energy are called degenerate orbitals. This implies that electrons in these orbitals have the same amount of energy and are therefore indistinguishable from each other.

If there are multiple orbitals with the same energy level, then they are said to be degenerate orbitals.

This is because each degenerate orbital can hold a maximum of two electrons with opposite spins. Since three of the five electrons need to be unpaired, we need three separate degenerate orbitals to hold these unpaired electrons. The remaining two electrons can be paired in the other two degenerate orbitals.

Therefore, we need five degenerate orbitals in total to contain the five electrons with three of them unpaired.

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Answer:

1- ions

Explanation:

Non-metals in group 17 on the periodic table most commonly forms -1 ions with other chemical species.

This is because of their atomic structure

Group 17 is made up of halogens which are fluorine, chlorine, bromine, iodine and astatine.

Because each of the elements has seven electrons in the outer shells of their atoms which implies that they lack one electron to become an octet, the elements are all univalent and also acceptors of electrons.

The balanced reaction equation for the bromination of stilbene using pyridinium tribromide is: C14H12 + Br2 → C14H10Br2 In this reaction, stilbene (C14H12) reacts with bromine (Br2) to form dibromostilbene (C14H10Br2).

The balanced reaction equation for the bromination of stilbene using pyridinium tri-bromide is: Stilbene + 3 Br2 + Pyridinium tribromide → 2,3,4,5-tetrabromostilbene + Pyridinium bromide In the given procedure, the amount of stilbene is not mentioned, so we cannot determine the limiting reagent directly.

To find the limiting reagent in a given procedure, you will need to compare the stoichiometric ratios of the reactants to determine which one will be completely consumed first during the reaction.

To do this, you'll need the amounts (usually in moles or grams) of both stilbene and pyridinium tribromide used in the procedure.

However, we can assume that the amount of pyridinium tri-bromide is in excess, and the limiting reagent will be the reactant that is completely consumed first.

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The steps to perform vacuum filtration is given below.

Vacuum filtration, in contrast to gravity filtering, is used to separate a solid suspended in a solvent when the desired component of the mixture is a solid. As in the process of recrystallization to obtain crystals. Because the air and dissolve are pushed through the filter paper by applying vacuum, vacuum filtration is faster than gravity filtration.

Here are the step-wise instructions to perform a vacuum filtration:

Note: It's essential to wear appropriate personal protective equipment (PPE) such as gloves, safety glasses, and a lab coat while performing vacuum filtration to ensure safety.

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The shape of an electron cloud is primarily determined by the electron's energy sublevel, which is a function of its principal quantum number. Option A

Electrons occupy different energy sublevels within an atom's electronic configuration, and these sublevels have different shapes, orientations, and energies. The shapes of these sublevels are determined by the probability distribution of the electrons in that sublevel, which is a mathematical function that describes the likelihood of finding the electron at any given point in space.

The probability distribution is determined by the quantum mechanical properties of the electrons, which are described by their wave functions. The shapes of the energy sublevels are characterized by different types of orbitals, such as s, p, d, and f orbitals, each with a distinct shape and orientation.

The position and speed of the electron also play a role in determining its energy and behavior, but they do not directly determine the shape of the electron cloud. Option A

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Answer:

1. Jacques Charles

2. Temperature

3. Volume

4. Pressure

5. \( \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)

Explanation:

Jacques Alexandre-César Charles was a French mathematician, scientist, inventor, balloonist, aeronaut, and physicist who was born on the 12th of November, 1746 in Beaugency, France and died on the 7th of April, 1823 in Paris, France. He was famously known for his invention of the first hydrogen balloon in 1783 and the discovery of Charles Law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles' law is given by the formula;

\( VT = K\)

\( \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)

Where;

Heat is the result of the movement of kinetic energy within a material or an item, or by a source of energy to a material or an object.

Energy that is transported from a region of greater temperature to one of lower temperature is known as heat.Joule is the SI unit (J).Heat is another factor that causes the phase transition.

heat is the energy that moves through one body to the other when temperatures are different.Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.

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7.296 x 102 in scientific notation 23x1011 is obtained by dividing by 3.6 x 109.

Very big or very low numbers can be written using scientific notation. Once a number within 1 and 10 has been multiplied by such a power of 10, it is then expressed in scientific notation. For instance, the scientific notation for 650,000,000 is 6.5 108.

A system of symbols and signs is used in notation to represent words, numbers, sentences, etc. The efficient communication of words, figures, and other objects is greatly aided by notation, which is frequently created for a specific purpose. Music notation is a prime example of notation.

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The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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A substituted phenol compound that has both ortho and meta substitution is 2-nitrophenol.

Phenol (also known as carbolic acid) is a C6H5OH aromatic organic compound. It's a volatile white crystalline solid. A phenyl group (C6H5) is bonded to the a hydroxy group (OH) in the molecule. It is mildly acidic and must be handled with caution since it may cause chemical burns.

Phenol was originally extracted from coal tar but is now produced on either a large scale (approximately 7 billion kg/year) from oil feedstocks. As a forerunner to too many materials but instead useful compounds, it is a valuable industrial commodity.

The nitro group (-NO2) is an activating and ortho/para-directing substituent, which will direct the electrophile to the ortho and para positions. The nitro group is also a meta-directing substituent, which will direct the electrophile to the meta position.

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Answer:

chemical formula

Explanation:

(a) Predict the product and provide a step-by-step mechanism for the following reaction. Show complete arrow pushing to indicate electron flow in each of these steps and specify what intermediates and products clearly.

The given reaction is shown below:

Step 1: The benzene ring is an electron-rich molecule and it acts as a nucleophile to attack the carbonyl carbon.

Step 2: The lone pair of electrons on the oxygen atom of water is used to attack the protonated carbonyl carbon.

Step 3: The lone pair of electrons on the oxygen atom is used to attack the protonated carbonyl carbon.

Step 4: The lone pair of electrons on the oxygen atom of water is used to attack the protonated carbonyl carbon.

Step 5: The lone pair of electrons on the oxygen atom of water is used to attack the protonated carbonyl carbon. The final product is 2,4-pentane dione.

(b) Predict the product and provide a step-by-step mechanism for the following reaction. Show complete arrow pushing to indicate electron flow in each of these steps and specify what intermediates and products clearly. The given reaction is shown below:

Step 1: The nitrogen atom of hydrazine acts as a nucleophile and attacks the carbonyl carbon.

Step 2: The lone pair of electrons on the oxygen atom of acetic acid is used to attack the nitrogen atom of hydrazine.

Step 3: The nitrogen atom of hydrazine is again used as a nucleophile to attack the carbonyl carbon. The final product is N-acetyl hydrazine.

(c) Predict the product and provide a step-by-step mechanism for the following reaction. Show complete arrow pushing to indicate electron flow in each of these steps and specify what intermediates and products clearly. The given reaction is shown below:

Step 1: The lone pair of electrons on the nitrogen atom of amide is used to attack the carbonyl carbon of acetic anhydride.

Step 2: The oxygen atom of the second molecule of acetic anhydride is used to attack the nitrogen atom of the amide. The final product is N, N-dimethylacetamide.

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Pieces of a whole object of solid matter can add up to more than one whole object through the process of fragmentation or division.

When a solid object is broken or divided into smaller pieces, each piece retains its own individual identity and properties. Although the individual pieces may not be equivalent to the original whole object in terms of size or shape, collectively they still possess the same amount of matter or substance.

For example, if a solid object is broken into two equal pieces, each piece will have half the mass and volume of the original object. Therefore, when you add up the masses and volumes of the two pieces, it will be greater than the mass and volume of the original object. This principle applies to larger divisions as well, where the total mass and volume of the individual pieces will always be equal to or greater than the mass and volume of the original whole object.

In summary, when a solid object is fragmented or divided into smaller pieces, the total amount of matter or substance remains the same. Each piece retains its own individual identity and properties, and collectively, the sum of the masses and volumes of the pieces can add up to more than one whole object. This is due to the conservation of mass and volume.

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The oxidation reduction reaction are given below.

Oxidation half reaction:

Zn° →Zn² + 2e-

Reduction half reaction:

2Mn^5 +4e^- → 2Mn^2+

Belo w are the oxidation and reduction reaction of the common alkaline batteries to produce electricity.

Oxidation half reaction:

Zn° →Zn² + 2e-

Reduction half reaction:

2Mn^5 +4e^- → 2Mn^2+

To balance the overall reaction, we need to multiply each half reaction by appropriate coefficients to ensure that the electrons cancel out.

Here is the balance overall reaction.
2Zn° + 2Mn^5 → 2Zn² + 2Mn²+

The balanced equation shows that in alkaline batteries, zinc metal is oxidized to form zinc ion, while manganese ions are reduced to manganese(II) ions. The oxidation reduction reaction    generate an electric current as a result of the flow of electrons.

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Balancing the equation :

KOH(aq) + HBr(aq) --> KBr(aq) + H2O(l)

This is the balanced chemical reaction because it follows the following ionic reaction:

H ^(aq)+ + Br^(aq)- + K^+(aq) + OH ^- (aq) → K^+(aq) + Br^-(aq) + H2O (l)

Red blood cells

[•] More in numbers.

[•] No antibodies present in these cells.

White blood cells

[•] Less in numbers

[•] Antibodies are present in these cells.

The pH of the solution containing 8.4×10⁻⁶ M H⁺ is 5.08

This is simply a measure of the acidity / alkalinity of a solution.

The pH measures the hydrogen ion concentration while the pOH measures the hydroxide ion concentration

The pH scale is a scale that gives an understanding of the variation of the acidity / alkalinity of a solution.

The scale ranges from 0 to 14 indicating:

pH = –Log H⁺

Where

With the above formula, we can determine the pH of the solution. Detail below:

From the question given above, the following data were obtained:

The pH of the solution can be obtained as illustrated below:

pH = –Log H⁺

pH = –Log 8.4×10⁻⁶

pH = 5.08

Thus, the pH of the solution is 5.08

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No, Yvonne cannot classify this mixture as a true solution because a true solution is a homogenous mixture where the solute is completely dissolved in the solvent, resulting in a clear solution.

In this case, the solid did not dissolve and the mixture is cloudy, indicating that the solid particles are still present in the mixture. This mixture is known as a suspension, which is a type of heterogenous mixture where the solid particles are not dissolved but are instead suspended in the solvent. Therefore, Yvonne's mixture cannot be considered a true solution because it does not meet the criteria for a homogenous mixture where the solute is completely dissolved in the solvent.
Yvonne cannot classify the mixture as a true solution. A true solution is a homogeneous mixture with a uniform composition throughout. In this case, the solid does not dissolve in water, resulting in a cloudy appearance. This indicates that the mixture is not homogeneous, and it is instead a suspension. Suspensions consist of solid particles dispersed in a liquid, and the particles are large enough to settle or be filtered out. Since the mixture is not uniform and the solid particles do not dissolve, it cannot be considered a true solution.

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