What if the experiment is repeated 1,000 times, then how many times could you expect to draw Ella's name?

Answer:

15

Step-by-step explanation:

Answer:

It is #3

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

Answer C.

Step-by-step explanation:

If x= -5 and y= 0.25

Equation A : 4 * 0.25 - 3 * -5 =  16

Equation B: -(-5) -8*0.25=3

These are only coordinates that satisfy the equation.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given coordinates: (-5, 0.25)

Equation A: 4y - 3x= 16

So, 4(0.25)- 3 (-5)

= 1+ 15

= 16

and, Equation B: -x -8y= 3

So, -(-5) -8 (0.25)

=  5 - 2

= 3

Hence, these are only coordinates that satisfy the equation.

Learn more about equation here:

https://brainly.com/question/10413253

#SPJ2

Answer:

jhv

Step-by-step explanation:

kjbb

D) a reflection across the x-axis (y=0)

Answer:

15.25 km

Step-by-step explanation:

I remember I did this one but I don't exactly remember the answer

I hope it is right!

Have a good day :)!

Answer: 12.56km

Step-by-step explanation:

it just is

Part A: To calculate the measures of center, we can find the median and the mean for each school.

For Bay Side School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 25, so the median class size is 25.

To find the mean class size for Bay Side School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 12 + 12 + 12 + 14 + 15 + 15 + 16 + 16 + 18 + 18 + 20 + 20 + 23 + 25 + 25 = 243. There are 15 classes, so the mean class size is 243/15 ≈ 16.2.

For Seaside School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 15, so the median class size is 15.

To find the mean class size for Seaside School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 10 + 10 + 10 + 11 + 12 + 15 + 15 + 16 + 17 + 17Part A (continued):

18 + 18 + 20 + 20 + 25 = 222. There are 14 classes, so the mean class size is 222/14 ≈ 15.9.

Therefore, the measures of center for Bay Side School are: median = 25, mean ≈ 16.2.

The measures of center for Seaside School are: median = 15, mean ≈ 15.9.

Part B: To calculate the measures of variability, we can find the range and the interquartile range (IQR) for each school.

For Bay Side School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 12, so the range is 25 - 12 = 13.

To find the IQR for Bay Side School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 15 and Q3 is 20. Therefore, the IQR is 20 - 15 = 5.

For Seaside School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 10, so the range is 25 - 10 = 15.

To find the IQRPart B (continued): for Seaside School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 12 and Q3 is 18. Therefore, the IQR is 18 - 12 = 6.

Therefore, the measures of variability for Bay Side School are: range = 13, IQR = 5.

The measures of variability for Seaside School are: range = 15, IQR = 6.

Part C: If you are interested in a smaller class size, Seaside School is a better choice because its measures of center are lower than those of Bay Side School, indicating that its class sizes tend to be smaller on average. Additionally, Seaside School has a smaller range and IQR, indicating less variability in class size. Therefore, there is less chance of encountering very large classes at Seaside School compared to Bay Side School.

Answer:

I believe the answer is d. 17%, 0.175, 2/11, 1/5

Step-by-step explanation:

if you convet them all to decimels it comes out to:

17%= .17

.175= .175

2/11= .18

1/5= .2

Answer:

c

Step-by-step explanation:

if you change them to decimals yo get the answer

This is one slight annoyance when it comes to sig figs, in my opinion anyway. You did the steps correct. The 639 bumps up to 640, so 6396 rounds to 6400 when rounding to 3 sig figs.

Normally the trailing zeros, ie zeros on the right, are not significant. So 6400 shows only 2 sig figs. What we need to do is draw a horizontal line over the first zero to show that it is significant (while the other zero is not significant)

So you'll write it like this \(64\overline{0}0\)

This notation can be problematic when it comes to decimals because it could be easily mixed up with the repeating decimal notation.

When you convert \(64\overline{0}0\) to scientific notation, you would get \(6.40 \times 10^3\).

In short: \(64\overline{0}0 = 6.40 \times 10^3\)

Here the zero is significant because the zero is present in the scientific notation result. Writing \(6.4 \times 10^3\) shows 2 sig figs while \(6.40 \times 10^3\) has 3 sig figs.

It's similar to how the number \(5.7\) has 2 sig figs while \(5.70\) has 3 sig figs. While the zero is trailing, having it after a decimal point indicates to the reader that you achieved this level of accuracy.

Answer:

This is one slight annoyance when it comes to sig figs, in my opinion anyway. You did the steps correctly. The 639 bumps up to 640, so 6396 rounds to 6400 when rounding to 3 sig figs.

Normally the trailing zeros, ie zeros on the right, are not significant. So 6400 shows only 2 sig figs. What we need to do is draw a horizontal line over the first zero to show that it is significant (while the other zero is not significant)

So you'll write it like this  

This notation can be problematic when it comes to decimals because it could be easily mixed up with the repeating decimal notation.

When you convert  to scientific notation, you would get .

In short:  

Here the zero is significant because the zero is present in the scientific notation result. Writing  shows 2 sig figs while  has 3 sig figs.

It's similar to how the number  has 2 sig figs while  has 3 sig figs. While the zero is trailing, having it after a decimal point indicates to the reader that you achieved this level of accuracy.

Answer:

22 14/35

soo 22 as a whole number and the fraction 14/35

I’m pretty sure the answer should be 1,710 if not i’m sorry

Answer:

1710 fish

Step-by-step explanation:

Let the number of fish in the lake last year be 'x'

The equation becomes-
x + 15x/100=6210     (This is because 15% of x is added in x to become    
6210... hope you understand)

x + 15x/100 = 6210
115x/100 = 6210
23x/20 = 6210
x = 6210 * 20/23
x = 270 * 20
x = 5400

Therefore- The number of fish last year = 5400


Now, let the number of fish in the lake 2 years ago be 'y'

The equation becomes-
y + 20y/100 = 5400     (Same logic as last time)

y + 20y/100 = 5400
120y/100 = 5400
24y/20 = 5400
6y/5 = 5400
y = 5400 * 5/6
y = 900 * 5
y = 4500

Therefore- Fish in the lake two years ago = 4500 fish

Difference between current and two years ago = 6210-4500
                                                                               = 1710 fish

Hope you understood the answer and I hope it helps you :)

Answ

Step-by-step explanation:

Answer:

Step-by-step explanation:

Its 0.122 Can i get my coffee now please i need to do my hw!

Answer:

Step-by-step explanation:

Well the answer is 40 cause you count by 20 so if you in 20 t o times then you would get 40 percent

Answer:

0.32 (rounded to the nearest hundredth)

Step-by-step explanation:

If you have any questions ask me please! :)

Answer:

0.32 km

Step-by-step explanation:

Using the formula r = c / (2 * π), where c = 2 kilometers and π = 3.14, we can calculate the radius as:

r = 2 km / (2 * 3.14)

r = 2 km / 6.28

r = 0.31847133758 km

Rounding this to the nearest hundredth gives:r ≈ 0.32 km

Therefore, the approximate radius of the circle is 0.32 kilometers.

Answer:

9 4/5

Step-by-step explanation:

You can rewrite them into decimal. It would be 3.5 times 2.8 and you get 9.8 or 9 4/5

Answer:

49 /5  = 9.8

Step-by-step explanation:

Answer:14

Step-by-step explanation:

\(3 \times (4 + 6) - 16 = \)

\(3 \times (10) - 16 = \)

\(3 \times 10 - 16 = \)

\((3 \times 10) - 16 = \)

\(30 - 16 = \)

\(14\)

1. Start the search among 2-digit numbers. A dropdown number (DDN) with 2 digits is a number \(ab\) such that

\(\dfrac{a+b}2 = a \implies a + b = 2a \implies b = a\)

or

\(\dfrac{a+b}2 = b \implies a+b = 2b \implies a=b\)

but both of these solutions violate the requirement that the digits are distinct, so there are no 2-digit DDNs.

A 3-digit DDN \(abc\) is such that

\(\dfrac{a+b+c}3 = a \implies a+b+c = 3a \implies b+c = 2a\)

or \(a+c=2b\) if the average is \(b\), or \(a+b=2c\) if the average is \(c\). The smallest possible value for \(a\) is 1 since we require 3 digits. Then \(b+c=2\), and we can pick \(b=0\) and \(c=2\) to get the smallest DDN, 102.

2. In a 4-digit DDN \(abcd\), we have

\(\dfrac{a+b+c+d}4 = a \implies a + b + c + d = 4a \implies b+c+d=3a\)

or \(a+c+d=3b\) or \(a+b+d=3c\) or \(a+b+c=3d\).

We're free to fix \(a=1\) and \(b=0\) to try to get the smallest DDN. This leaves us with \(c+d=3\) or \(c+d=-1\) or \(1+d=3c\) or \(c=3d\).

The first two cases are impossible - the only choices for \(c,d\) such that \(c+d=3\) are 1 and 2, and the sum of two positive integers must be positive. The smallest possible value of \(c\) is 2; this leaves us with \(1+d=6\) or \(2=3d\), but the latter case is impossible because 3 does not divide 2. So \(d=5\), and the smallest 4-digit DDN is 1025.

To find the largest DDN, start with the largest possible values for \(a\) and \(b\). Let \(a=9\) and \(b=8\). Then \(c+d=19\) or \(c+d=15\) or \(17+d=3c\) or \(17+c=3d\). At most, we can have \(c+d=13\) with 7 and 6, so the first two cases are impossible. If we maximize \(c=7\), then either \(17+d=21\implies d=4\) or \(24=3d\implies d=8\) (which we don't want). So the largest 3-digit DDN is 9874.

3. I don't have an analytical solution to this, but using brute force (program) the total count is 112.

4. It is possible; consider 1249 and 1250, with digital averages

\(\dfrac{1+2+4+9}4=4 \text{ and } \dfrac{1+2+5+0}4=2\)

which happens to be the smallest pair. (Also found with brute force.)

Answer:

The answer is B, 38.75

Step-by-step explanation:

The mean, you add up all the numbers and divided it by how much numbers are there.

1) 20 + 22 + 25 + 31 + 33 + 34 + 41 + 41 + 45 + 50 + 56 + 67 = 465

2) Count. How many numbers are there? There are 12 numbers.

3) 465/12 is 38.75

The answer is B, 38.75

Hope this helps :)

Answer:

3/8

Step-by-step explanation:

So 1 pizza was already eat right and 1/8 was eating I'm assuming it 1/8 then 1/2 is 4/8 so add that witch is 5/8 so 5/8 - 8/8= 3/8

Answer:

There were 3/8s left

Step-by-step explanation:

1 1/8 + 1/2 = 1 5/8

2- 1 5/8= 3/8

Answer:

solve for Q-  -7cQ/10=8.2

solve for C- -82/7Q+10/7

Step-by-step explanation:

oop

Answer:

solve for Q-  -7cQ/10=8.2

solve for C- -82/7Q+10/7

Step-by-step explanation:

trust me its right