What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?

Answer:

light is captured through ozone layer.

Explanation:

as its the ozone layer that protects earth from the harmful radiation of the earth and store only the light and energy needed.

Fun Fact - ozone layer can provide light for about 7 minutes so if sun disappears, we won't even realise it for 7 minute straight.

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.

What happens when the thistle funnel is moved upward?

An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.

Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.

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See complete question in the attached image.

Answer:

a) 103.176 m / min

b) 1751.28 meters

Explanation:

Given:-

- Emma's and Lily's velocities ( E(t) and L(t) ) are given as functions respectively:

                         \(E(t) = \frac{7510}{t^2-7t + 80.22} \\\\L ( t ) = 12t^3*e^-^0^.^5^t\)

- Where, E ( t ) and L ( t ) are given in m / min

- Both run for a total time of 15 minutes in the same direction along the straight track defined by the absolute interval:

                         ( 0 ≤ t ≤ 15 ) mins                  

- It is known that Emma is 10 meters ahead of Lily at time t = 0.

Find:-

a) Find the value of \(\frac{1}{6}*\int\limits^8_2 {E(t)} \, dt\) using correct units, interpret the meaning of

b) What is the maximum distance between Emma and Lily over the time interval 0 ≤ t ≤ 15?  

Solution:-

- The average value of a function f ( x ) over an interval [ a , b ] is determined using calculus via the following relation:

                          \(f_a_v_g = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx\)

- The first part of the question is asking us to determine the average velocity of Emma over the time interval of ( 2 , 8 ). Therefore, ( E_avg ) can be determined using the above relation:

                         \(E_a_v_g = \frac{1}{8 - 2}*\int\limits^8_2 {E(t)} \, dt\\\\E_a_v_g = \frac{1}{6}*\int\limits^8_2 {E(t)} \, dt\\\)

- We will evaluate the integral formulation above to determine Emma's average velocity over the 2 ≤ t ≤ 8 minute range:

                         \(E_a_v_g = \frac{1}{6}*\int\limits^8_2 {\frac{7510}{t^2 - 7t + 80.22} } \, dt\\\\E_a_v_g = \frac{1}{6}*37550\int\limits^8_2 {\frac{1}{50t^2 - 350t + 4011} } \, dt\\\\\)

- Complete the square in the denominator:

                          \(E_a_v_g = \frac{1}{6}*37550\int\limits^8_2 {\frac{1}{(5\sqrt{2}*t - \frac{35}{\sqrt{2} })^2 + \frac{6797}{2} } } \, dt\\\\\)

- Use the following substitution:

                          \(u = \frac{5*(2t - 7 )}{\sqrt{6797} } \\\\\frac{du}{dt} = \frac{10}{\sqrt{6797} } \\\\dt = \frac{\sqrt{6797}}{10}.du\)

- Substitute the relations for (u) and (dt) in the above E_avg expression.

                          \(E_a_v_g = \frac{1}{6}*37550\int {\frac{\sqrt{6797} }{5*(6797u^2 + 67997) } } \, du\\\\E_a_v_g = \frac{1}{6}*37550*\frac{1}{5\sqrt{6797}} \int {\frac{1 }{(u^2 + 1) } } \, du\)

- Use the following standard integral:

                          \(arctan(u) = \int {\frac{1}{u^2 + 1} } \, du\)

- Evaluate:

                         \(E_a_v_g = \frac{1}{6}*37550*\frac{1}{5\sqrt{6797}}* arctan ( u ) |\)

- Apply back substitution for ( u ):

                        \(E_a_v_g = \frac{1}{6}*[\frac{75100* arctan ( \frac{5*(16 - 7 )}{\sqrt{6797} } )}{\sqrt{6797} } - \frac{75100* arctan ( \frac{5*(4 - 7 )}{\sqrt{6797} } )}{\sqrt{6797} } ]\\\\\)

- Plug in the limits and find Emma's average velocity:

                        \(E_a_v_g = 151.82037*[arctan (0.54582 ) - arctan ( -0.18194 ) ]\\\\E_a_v_g = 103.176 \frac{m}{min}\)

Answer: Emma's average speed over the interval ( 2 ≤ t ≤ 8 ) is 103.179 meters per minute.

- The displacement S ( E ) of Emma from time t = 0 till time ( t ) over the absolute interval of  0≤t≤15 is given by the relation:

                    \(S (E) = S_o + \int\limits^t_0 {E(t)} \, dt\\\\S ( E ) = 10 + \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } |_0^t\\\\S ( E ) = 10 + [ \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } - \frac{75100*arctan( \frac{5*(0 - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } ]\\\\S ( E ) = \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } + 375.71098\\\)

- The displacement S ( L ) of Lily from time t = 0 till time ( t ) over the absolute interval of  0 ≤ t ≤ 15 is given by the relation:

                    \(S (L) = \int\limits^t_0 {L(t)} \, dt\\\\S (L) = \int\limits^t_0 ({12t^3 *e^-^0^.^5^t } )\, .dt\\\)

 Apply integration by parts:

  \(S ( L ) = 24t^3*e^-^0^.^5^t - 64*\int\limits^t_0 ({e^-^0^.^5^t*t^2} \,) dt\\\)

 Re-apply integration by parts 2 more times:

 \(S ( L ) = -24t^3*e^-^0^.^5^t + 64*[ -2t^2*e^-^0^.^5^t - 2\int\limits^t_0 ({e^-^0^.^5^t*t} \,) dt ]\\\)             \(S ( L ) = -24t^3*e^-^0^.^5^t + 64*[ -2t^2*e^-^0^.^5^t - 2*( -2t*e^-^0^.^5^t - (4e^-^0^.^5^t - 4 ) ]\\\\\)    

\(S ( L ) = e^-^0^.^5^t* ( -24t^3 -128t^2+ 256t + 512) - 512 \\\)

- The distance between Emma and Lily over the time interval 0 < t < 15 mins can be determined by subtracting S ( L )  from S ( E ):

                    \(S = S ( E ) - S ( L )\\\\S = \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } - e^-^0^.^5^t* ( -24t^3 -128t^2+ 256t + 512) + 887.71098\\\)

- The maximum distance ( S ) between Emma and Lily is governed by the critical value of S ( t ) for which function takes either a minima or maxima.

- To determine the critical values of the function S ( t ) we will take the first derivative of the function S with respect to t and set it to zero:

              \(\frac{dS}{dt} = \frac{d [ S(E) - S(L)]}{dt} \\\\\frac{dS}{dt} = E(t) - L(t) \\\\\frac{dS}{dt} = \frac{7510}{t^2 - 7t+80.22} - 12t^3*e^-^0^.^5^t = 0\\\\( 12t^5 - 84t^4 + 962.64t^3) *e^-^0^.^5^t - 7510 = 0\\\\t = 4.233 , 11.671\)

- We will plug in each value of t and evaluate the displacement function S(t) for each critical value:

Answer:

partecls

Explanation:

because they are to small to see with plain eyes

The first few terms of the Maclaurin series for each of the following functions f(x) = 1 + x + 2x² + 3x³ + 5x⁴ + 8x⁵ + ...

To find the Maclaurin series for the function f(x) = 1/(1+x+x² ), we can use the formula for the geometric series:

1/(1-r) = 1 + r + r² + r³ + ...

If we let r = x + x² , then we have:

f(x) = 1/(1+x+x² ) = 1/(1 - (x+x² ))

Using the formula for the geometric series, we can expand this as:

f(x) = 1 + (x+x² ) + (x+x² )²  + (x+x² )³ + ...

Expanding the terms, we have:

f(x) = 1 + x + 2x²  + 3x³ + 5x⁴ + 8x⁵ + ...

We can check our answer using a computer program, such as Python.

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A key challenge with renewable energy is that the energy must be transported to the place where it's needed batteries or devices .

Option A is correct.

Renewable energy sources such as solar, wind, and hydroelectric power are often located far away from the areas where the energy is needed. This makes it necessary to transport the energy over long distances, which can be expensive and lead to losses due to transmission and distribution. In addition, renewable energy sources are often intermittent, meaning they don't produce a constant supply of energy.

To address this, energy storage devices are needed to store excess energy produced during peak times for use during times of low energy production. However, the current technology for energy storage is not yet efficient or cost-effective enough to meet the growing demand for renewable energy. Developing more effective energy storage devices is therefore an important area of research and development in the field of renewable energy.

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Question incomplete:

A key challenge with renewable energy is that the energy must be transported to the place where it's needed _ or devices that store the energy needed improvement.

A. batteries

B. refineries

C. solar panels

D. wind turbines

Answer:

batteries

Explanation:

For the graph of Annual cray fish caught in Lambert Bay for the last 20 years, the axes are as follows:

Y-axis: amount of fish caught

X-axis: year

A graph is a pictorial illustration of data.

There are different types of graphs such as

A graph has the vertical axis, known as the Y-axis, and the horizontal axis known as the X-axis.

For the graph of Annual cray fish caught in Lambert Bay for the last 20 years, the axis can be labelled as follows:

Y-axis: amount of fish caught

X-axis : year

In conclusion, in a graph, the vertical axis is known as the Y-axis while  the horizontal axis is known as the X-axis.

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Answer:

v= 18.5 m/s

Explanation:

       \(F_{cent} = F_{g} - F_{n} (1)\)

       \(F_{cent} = m*\frac{v^{2}}{r} (2)\)

       \(F_{n} = F_{g} - m*\frac{v^{2}}{r} (3)\)      

        \(0.9*F_{g} = F_{g} - m*\frac{v^{2}}{r} (4)\)

The velocity the occupants of the car appear to weigh 10% less than their normal weight is 18.52 m/s.

The given parameters:

Apply the principle of conservation of energy to determine the velocity the occupants of the car appear to weigh 10% less than their normal weight;

\(F_c = mg\\\\\frac{mv^2}{r} = mg\\\\v^2 = gr\\\\v = \sqrt{gr} \\\\v = \sqrt{0.1 \times 9.8 \times 350}\\\\v = 18.52 \ m/s\)

Thus, the velocity the occupants of the car appear to weigh 10% less than their normal weight is 18.52 m/s.

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The circuit in which lamps Q and R light but not lamp P when switch S is open is circuit B.

An electric circuit is a path for transmitting electric current.

Given the circuits below, when switch S is open, we want to determine the circuit in which lamps Q and R light but not lamp P.

To determine the circuit, we proceed as follows.

To determine the circuit in which lamps Q and R light but not lamp P, it must satisfy this condition

Looking at all the circuits, the circuit which satisfy these condition is circuit B

So, the circuit in which lamps Q and R light but not lamp P is circuit B.

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The height above the ground in which the vase is raised is 51.02 m.

The height above the ground in which the vase is raised is calculated by applying the formula for gravitational potential energy.

Gravitational potential energy of an object is the energy possessed by the object due to the object's position above the ground.

Mathematically, the formula for gravitational potential energy is given as;

P.E = mgh

where;

The given parameters include;

mass of the vase = 0.2 kg

potential energy of the vase = 100 J

acceleration due to gravity = 9.8 m/s²

h = P.E / mg

h = (100) / (0.2 x 9.8)

h = 51.02 m

Thus, the height of the vase is a function of the potential energy and mass of the vase.

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The complete question is below:

a 0.2 kg vase has a potential energy of 100j. What is the height of the vase?

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

Answer:

Explanation:

The electric flux through a surface is given by the equation:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

We are given Φ = 4.44 N⋅m2/C, A = 6.66×10−4 m2, and θ = 60.0∘. Substituting these values into the equation above and solving for E, we get:

E = Φ / (Acos(θ))

= 4.44 N⋅m2/C / (6.66×10−4 m2cos(60.0∘))

= 1.62×10^4 N/C

Therefore, the magnitude of the electric field is 1.62×10^4 N/C.

The magnitude of the electric field is 13,320 N/C.

The electric flux through a surface is defined as the product of the electric field and the area of the surface projected perpendicular to the electric field. Mathematically, we can write:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

Here in the Question,

We are given the electric flux Φ = 4.44 N·m^2/C, the area A = 6.66×10^-4 m^2, and the angle θ = 60.0°. We can solve for the magnitude of the electric field E by rearranging the equation as follows:

E = Φ / (A*cos(θ))

Substituting the given values, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*cos(60.0°))

Simplifying the denominator, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*0.5)

E = 13,320 N/C

Therefore, 13,320 N/C is the magnitude of the electric field.

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With a horizontal velocity of 3.04 m/s and a horizontal displacement of 1.68 m from the end of the diving board, the swimmer enters the water 1.70 metres below the diving board.

The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.

We can use the kinematic equations of motion to solve this issue.

Use the swimmer's horizontal travel distance as the displacement in the x-direction. Given that the swimmer enters the water 1.68 metres from the board's end, the following is the answer:

x=1.68 m and v0x=3.04 m/s

Δx = v0x * t

calculating t:

t = 1.68 m / 3.04 m/s because x / v0x.

t = 0.5526 s

Thus, the swimmer enters the water in 0.5526 seconds.

"y" equals "v0y*t" plus "(1/2)*a*t2"

replacing the values with:

Δy = 0 + (1/2) * (-9.81 m/s²) * (0.5526 s)²

Δy = -1.70 m

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Answer:

The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.

Answer:

1500 m/s

Explanation:

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

1/f1 = 1/v - 1/u1

1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)

1/f1 = 0 - 4

1/f1 = -4

f1 = -1/4

f1 = -0.25 meters

The initial lens power (P1) is the reciprocal of the focal length:

P1 = 1/f1

P1 = 1/-0.25

P1 = -4 diopters

Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:

1/f2 = 1/v2 - 1/u1

1/f2 = 1/0.40 - 1/0.25

1/f2 = 2.5 - 4

1/f2 = -1.5

f2 = -1/1.5

f2 = -0.67 meters

The final lens power (P2) is the reciprocal of the focal length:

P2 = 1/f2

P2 = 1/-0.67

P2 ≈ -1.49 diopters

Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.

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In a case whereby the lowest pitch that the average human can hear has a frequency of 28.0 Hz sound with this frequency travels through air with a speed of 331M/S  the wave length is

Frequency refers to the number of vibrations measured each second. A wave is a collection of vibrations known as energy. The top node is referred to as the trough, and the bottom node as the crest.

λ = wave velocity/frequency

λ = 331 m/s / 28 Hz

λ = 11.82 m

As a result, the lowest pitch that a typical person can hear is at a frequency of 29 Hz. The wavelength of sound at this frequency is 11.82 m as it moves through air at a speed of 331 m/s.

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Answer: Delta T = - 14.4 kJ

Explanation:

Firstly the initial momentum of the satellite is;

H0 = L0*W0

L0 is the momentum of inertia of the satellite about its longer axis (1000 kg.m^2) and Wo is the initial angular velocity of the satellite ( 6 rad/s)

now we substitute

H0 = 1000 kg.m^2 * 6 rad/s

H0 = 6000 kg.m^2

Now the initial rotational kinetic energy of the satellite is;

0o = 1/2L0W0^2

we substitute

T0 = 1/2 * (1000 kg.m^2) * (6 rad/s)^2

T0 = 18000

Next is the final angular momentum of the satellite;

H = IW

I is the moment of inertia of the satellite about its transverse axes through center of mass (5000 kgm^2)

we know that the law of conservation angular momentum, the total initial angular momentum of the satellite is equal to the total final angular momentum of the satellite.

simply put H = H0

we know that our H0 = 6000 kgm^2

so we substitute

H0 = IW

6000 kg.m^2 = 5000 kgm^2 * W

W = 1.2 rad/s

The final rotational kinetic energy of the satellite is;

T = 1/2IW^2

T = 1/2 * 5000 kgm^2 * 1.2^2

T = 3600 J

so the change in rotational kinetic energy of the satellite is;

Delta T = T - T0

Delta T = 3600 - 18000

DeltaT = - 14400 J

Delta T = - 14.4 kJ

Answer:

Endurance, or aerobic

Strength, or resistance training

Balance

Flexibility

Explanation:

Answer:

Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).

Answer:

37.4m/s

Explanation:

since the car doesn't accelerate, we can use the formula v=ωr where v is linear speed, ω is angular speed (rads/second) and r is radius. Substitute values for equation:

v=55*0.68

v=37.40

Answer:

We can write   S = v * t    where S is the distance traveled in time t

S = .12 rad/sec * 30 sec = 3.6 rad     distance traveled

Also 2 * pi * N = S   since there are 2 * pi rad / revolution

So 2 * pi * N = 3.6

N = 3.6 / (2 * pi) = .573 revolutions

Answers:

No, They will attract each other, B, and neither direction

Explanation:

Since the two already presented particles in the diagram represent both opposing charges due to the direction of the arrows (the arrows facing away from the particle shows a positive charge and the particles facing towards the particle show a negative charge), not only because of this but as the arrows between the particles show an attracting magnetic field, then it can be concluded that the particles will attract to each other and if another particle was introduced into the diagram of a positive charge, then it would attract to the negatively charged particle. If you have any questions or need further explanation, please comment below. E2021, have a great day.

Answer:

No, They Will Attract Each Other, B, and Neither Direction

Explanation: Im an edge student

We can now see that 120 g of KNO3 (potassium nitrate) can not dissolve in 100 mL of water at 60°C.

Solubility is the ability of a substance, called the solute, to dissolve in a solvent to form a hom--ogeneous mixture called a solution.

The saturated solution of potassium nitrate will hold about 110 g of dissolved salt per 100 mL of water at 60∘C . Thus we can say that the solubility of the KNO3 at 60°C is 110g of the salt per  100 g of water.

Solubility is an important concept in chemistry and is used in various applications such as in the preparation of solutions.

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Answer:

I think its the electromagnetic spectrum

Answer:

\(\mu=41.5\textdegree\)

Explanation:

From the question we are told that:

Water index of refraction \(i_w=1.33\)

Glass index of refraction \(i_g=1.50\)

Generally the equation for Brewster's law is mathematically given by

 \(\theta=tan^{-1}(\frac{i_g}{i_w})\)

 \(\theta=tan^{-1}(\frac{1.50}{1.33})\)

 \(\theta=48.44 \textdegree\)

Therefore Angle of incident to plane  \mu (normal at 90 degree to the surface)

 \(\mu=90\textdegree-\theta\)

 \(\mu=90\textdegree-48.44\textdegree\)

 \(\mu=41.5\textdegree\)

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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