What is the quotient of 80 divided by 2/3

Answer:

A.) The function is increasing for all real values of x where x < -4

Step-by-step explanation:

On the interval x < -4, all of the x values are increasing. Before x = -4, the line assumes a positive slope because it is heading upwards. After this interval, the function is decreasing because the slope is heading downwards.

On the interval -6 < x < -2, all of the x values are positive because they lie above the x-axis. This does not necessarily mean that all of the values are increasing.

On the interval x < -6 and x > -2, all of the x values are negative because they lie below the x-axis.

What is true about ΔXWZ is that the ratio of its altitude to the corresponding altitude in ΔYWZ is equal to the ratio of the length of XW to the length of YZ.

If ΔYWZ is similar to ΔYXW, it means that these two triangles have corresponding angles that are equal and corresponding sides that are proportional. In this case, we are specifically interested in the altitude of ΔWXZ, which we will denote as h.

Since ΔYWZ is similar to ΔYXW, we can establish the following proportion based on their corresponding sides:

YZ/YX = YW/YW

Let's denote the length of YZ as a and the length of YW as b. We can rewrite the proportion as:

a/YX = b/YW

Now, let's consider ΔXWZ. Since XW is common to both triangles, we can conclude that the altitude of ΔXWZ, which we will denote as k, is also proportional to the altitude of ΔYWZ (h). Therefore, we can express this proportion as:

k/h = XZ/YZ

To establish a relationship between k and h, we need to find a way to relate XZ to YZ. Using the proportion established earlier, we can substitute a for YZ:

k/h = XZ/a

To relate XZ to YZ, we need to find a relationship between XZ and YX. Again, using the similarity of the triangles, we have:

XZ/YZ = XW/YW

Substituting the value of YZ (a) from the earlier proportion, we have:

XZ/a = XW/YW

Now, we can combine the two proportions to find the relationship between k and h:

k/h = (XW/YW) * (YW/a)

Simplifying further, we get:

k/h = (XW/a)

From this equation, we can conclude that the ratio of the altitudes k/h in ΔXWZ and h in ΔYWZ is equal to the ratio of XW to YZ. In other words, the ratio of the altitudes is equal to the ratio of the corresponding sides in the similar triangles.

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Step-by-step explanation:

before tax it would be 6/100×48=$2.88

so therefore before tax = $48-2.88=$45.12

final price after tax =$48+2.88=$50.88

Answer:

24.5 gallons of milk

Step-by-step explanation:

To calculate the total amount of milk needed daily, we need to find the total amount of milk consumed by all the students and convert it into gallons.

For grades 1 through 3, the total amount of milk consumed daily at lunch is:

12 fl. oz. x 212 students = 2,544 fl. oz.

For breakfast:

6 fl. oz. x 48 students = 288 fl. oz.

For kindergarten snack time:

8 fl. oz. x 38 students = 304 fl. oz.

Adding up all these amounts gives us the total amount of milk consumed daily:

2,544 fl. oz. + 288 fl. oz. + 304 fl. oz. = 3,136 fl. oz.

To convert this to gallons, we need to divide by 128 (the number of fluid ounces in a gallon):

3,136 fl. oz. ÷ 128 = 24.5 gallons (rounded to the nearest tenth)

Therefore, Chef needs approximately 24.5 gallons of milk daily to serve all the students.

When we divide the 464 by 60 we get the following remainder in our answer that is 44.

The Remainder is the name for the value that is left behind after division. If an amount (reward) cannot be divided completely with another number, we are left with only a meaning (divisor). The remaining is the name for this amount. For instance, 10 is not precisely divisible by 3. We can calculate 3 x 3 = 9 because that is the closest value.

7.733333333333333

=7 44/60 ⇔ 7 R 44

464 divided by 60

=7 with a remainder of 44

Here, we provide you the outcome of the dividing with remainder, often known as the Euclidean division, along with a brief explanation of the following terms:

464 divide by 60 yields a quotient and residual of 7 R 44.

464 is the dividend & 60 is the divisor; the division (numeric division) of 464/60 is 7; the remainder ("left over") is 44.

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\(\bold{{Answer}}\)

B.2.And30

What is the means of a proportion?

1 : harmonious relation of parts to each other or to the whole : balance, symmetry. 2a : proper or equal share each did her proportion of the work. b : quota, percentage. 3 : the relation of one part to another or to the whole with respect to magnitude, quantity, or degree : ratio.

A proportion is simply a statement that two ratios are equal. It can be written in two ways: as two equal fractions a/b = c/d; or using a colon, a:b = c:d. The following proportion is read as "twenty is to twenty-five as four is to five."

please correct me if im wrong

Answer:

D

Step-by-step explanation:

Given the proportion

\(\frac{a}{b}\) = \(\frac{c}{d}\)

Then a and d are the extremes of the proportion

and b, c are the means of the proportion

Then for

\(\frac{2}{3}\) = \(\frac{20}{30}\)

3 and 20 are the means → D

\(\(\left(\frac{a^{4}}{b^{-3}}\right)^{2}\)\) can be simplified as \(\(a^{8} \cdot {b}^{6}\).\)

First, we'll simplify\(64:\(2^{6} = 64\)\)

So,\(\(\left(64 a^{6}\right)^{\frac{1}{2}} = {(2^{6})}^{\frac{1}{2}} \cdot a^{6 \cdot \frac{1}{2}} = {2}^{3} \cdot a^{3}\)\)

\(\(\left(64 a^{6}\right)^{\frac{1}{2}}\)\)can be simplified as \(\(8a^{3}\).\(\left(x^{4} y^{\frac{1}{2}}\right)^{\frac{1}{4}}\)\)

Using the exponent rule,\(\({\left(x^{4} y^{\frac{1}{2}}\right)}^{\frac{1}{4}} = {x}^{4 \cdot \frac{1}{4}} \cdot {y}^{\frac{1}{2} \cdot \frac{1}{4}} = x\cdot {y}^{\frac{1}{8}}\)\)

\(\(\left(x^{4} y^{\frac{1}{2}}\right)^{\frac{1}{4}}\)\)can be simplified as \(\(x\cdot {y}^{\frac{1}{8}}\).\(\left(\frac{a^{4}}{b^{-3}}\right)^{2}\)\)

Let's apply the quotient of powers rule,\(\(\frac{a^{m}}{a^{n}} = a^{m-n}\)\)

So,\(\(\frac{a^{4}}{b^{-3}} = a^{4} \cdot b^{3}\)\)

Now, we'll apply the exponent rule,\(\({\left({a}^{m}\right)}^{n} = {a}^{mn}\)\)

\(\({\left(\frac{a^{4}}{b^{-3}}\right)}^{2} = {\left(a^{4} \cdot b^{3}\right)}^{2} = {a}^{8} \cdot {b}^{6}\)\)

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Using it's concept, the domain of the function is given as follows:

{x| –2 ≤ x <= 5}

The domain of a function is the set that contains all possible input values for the function, that is, the values for which the function is defined.

The function described in this problem is defined from x = -2 until x = 5 hence the domain of the function is given as follows, by the interval:

{x| –2 ≤ x <= 5}

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Answer:

So I got 64 on my test, but it doesn't let you see what was right and what was wrong, so I guess we will never know☹️☹️☹️☹️.

BTW in was on edge

The algebraic expression that is equivalent to (4x + 12) + 9x is:  C. (4x + 9x) + 12.

Algebraic expressions are equivalent to each other if they have he same value when simplified or evaluated.

Given the expression, (4x + 12) + 9x, we have:

4x + 12 + 9x

Add like terms

13x + 12

Also, simplifying (4x + 9x) + 12, we give us the following:

4x + 9x + 12

13x + 12

Therefore, the algebraic expression that is equivalent to (4x + 12) + 9x is:  C. (4x + 9x) + 12.

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Answer: 3

Step-by-step explanation: I just know

Answer:

5 : 7

Step-by-step explanation:

groom's side: 40

bride's side: 56

ratio groom to bride = 40/56 = 20/28 = 10/14 = 5/7

Answer: 5 : 7

The required manager has 12 fifty-dollar bills as of the given condition.

Let's denote the number of twenty-dollar bills as "x" and the number of fifty-dollar bills as "y".

We know that the convention manager has a total of 48 bills, so:
x + y = 48

We also know that the total amount of money she has is $1320, which can be expressed as:
20x + 50y = 1320

To solve for "y", we can rearrange the first equation to get:
y = 48 - x

Then substitute this expression for "y" in the second equation:

20x + 50(48 - x) = 1320

Expanding the expression and simplifying:
20x + 2400 - 50x = 1320
-30x = -1080
x = 36

So the manager has 36 twenty-dollar bills. To find the number of fifty-dollar bills, we can use the first equation:

x + y = 48

36 + y = 48

y = 12

Therefore, the manager has 12 fifty-dollar bills.

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Answer:

1:26

Step-by-step explanation:

You can divide both sides by 2.

A4 = [1 32/27 32/27 81]. To compute A4, we first need to find A. From the given equation A = PDP-1, we can substitute the values of P and D to get:

A = [1 2 2 3] [1 0 0 3]^-1

To find the inverse of D, we can simply take the reciprocal of each non-zero element on the main diagonal. In this case, the inverse of D is:

D^-1 = [1 0 0 1/3]

Substituting this value into the equation for A, we get:

A = [1 2 2 3] [1 0 0 1/3]
 = [1 2/3 2/3 3]

Now that we have A, we can easily compute A4 by raising A to the fourth power. That is:

A4 = A x A x A x A
  = [1 2/3 2/3 3] x [1 2/3 2/3 3] x [1 2/3 2/3 3] x [1 2/3 2/3 3]
  = [1 32/27 32/27 81]

Therefore, A4 = [1 32/27 32/27 81].

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Answer:

Two angles whose sum in 90 degrees

Step-by-step explanation:

The number of miles that Jamel drove the car on his vacation was 97 miles.

Let the number of miles that he traveled be represented by x.

Based in the information given, the equation to solve the question will be:

50 + (0.75 × x) = 122.75

50 + 0.75x = 122.75

Collect like terms

0.75x = 122.75 - 50

0.75x = 72.75

Divide both side by 0.75

0.75x/0.75 = 72.75/0.75

x = 97

Therefore, Jamel drove the car for 97 miles.

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There are several different sampling methods that could be employed for this study, including:

Simple random sampling: This method involves randomly selecting a certain number of students from each campus and measuring the distance between their hometowns and their campuses.

Stratified random sampling: This method involves dividing the student population at each campus into different strata (e.g. by major or year in school) and then randomly selecting a certain number of students from each stratum.

Cluster sampling: This method involves randomly selecting a certain number of campuses and then measuring the distance between the hometowns of all students at those campuses and their respective campuses.

Multi-stage sampling: This method involves using a combination of the above methods, such as first using cluster sampling to select a certain number of campuses and then using stratified random sampling to select a certain number of students from each campus.

This study would be an enumerative study because it seeks to measure the characteristics of a population, in this case, the average distance between the hometowns of students and their campuses, by counting and measuring them.

It is not an analytic study because it doesn't involve testing a hypothesis or making causal inferences.

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Answer:

p and m or A. and D.

Step-by-step explanation:

The equation which gives solutions, x=0 and y=-6.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

y=-x-6............................(1)

x+3y=-18.........................(2)

now, solving both equation we get

x+3y=-18

x + 3(-x-6) = -18

x - 3x - 18 = -18

-2x = 0

x= 0

and, y= -0 -6 = -6

Hence, the solution is x=0 and y=-6.

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Answer:

9

Step-by-step explanation:

You take the amount of money that the gym membership cost, $55, and you divide that into, the amount of money he has, $495, and then that will leave you with 9 months.

Hope this helps :)))

Answer:

$6.80

Step-by-step explanation:

1.79 x 3.8 = 6.802

So $6.80

Answer:

X = 4.47  Y = 8.94

Step-by-step explanation:

2\(\sqrt{5}\)= 2.23606798

2.23606798 x 2 = 4.47213596

-------

4.47213596

4.47213596^2 + 4.47213596^2 = 8.94427192^2

8.94427192^2 = 80

Square root of 80 is 8.94

To calculate the probabilities, we need to use the concept of binomial probability.

For a fair coin being tossed 5 times:

(a) Probability of getting five heads:

The probability of getting a head in a single toss is 1/2.

Since each toss is independent, we multiply the probabilities together.

P(Head) = 1/2

P(Tails) = 1/2

P(Five Heads) = P(Head) * P(Head) * P(Head) * P(Head) * P(Head) = \((1/2)^5\) = 1/32 ≈ 0.03125

So, the probability of obtaining five heads is approximately 0.03125 or 3.125%.

(b) Probability of getting four heads:

There are five possible positions for the four heads.

P(Four Heads) = (5C4) * P(Head) * P(Head) * P(Head) * P(Head) * P(Tails) = 5 * \((1/2)^4\) * (1/2) = 5/32 ≈ 0.15625

So, the probability of obtaining four heads is approximately 0.15625 or 15.625%.

(c) Probability of getting one head:

There are five possible positions for the one head.

P(One Head) = (5C1) * P(Head) * P(Tails) * P(Tails) * P(Tails) * P(Tails) = 5 * (1/2) * \((1/2)^4\) = 5/32 ≈ 0.15625

So, the probability of obtaining one head is approximately 0.15625 or 15.625%.

For a fair die being thrown eight times:

(a) Probability of a 6 occurring six times:

The probability of rolling a 6 on a fair die is 1/6.

Since each roll is independent, we multiply the probabilities together.

P(6) = 1/6

P(Not 6) = 1 - P(6) = 5/6

P(Six 6s) = P(6) * P(6) * P(6) * P(6) * P(6) * P(6) * P(Not 6) * P(Not 6) = \((1/6)^6 * (5/6)^2\) ≈ 0.000021433

So, the probability of rolling a 6 six times is approximately 0.000021433 or 0.0021433%.

(b) Probability of a 6 never happening:

P(No 6) = P(Not 6) * P(Not 6) * P(Not 6) * P(Not 6) * P(Not 6) * P(Not 6) * P(Not 6) * P(Not 6) = \((5/6)^8\) ≈ 0.23256

So, the probability of not rolling a 6 at all is approximately 0.23256 or 23.256%.

(c) Probability of an odd number of 6s:

To have an odd number of 6s, we can either have 1, 3, 5, or 7 6s.

P(Odd 6s) = P(One 6) + P(Three 6s) + P(Five 6s) + P(Seven 6s)

\(P(One 6) = (8C1) * P(6) * P(Not 6)^7 = 8 * (1/6) * (5/6)^7P(Three 6s) = (8C3) * P(6)^3 * P(Not 6)^5 = 56 * (1/6)^3 * (5/6)^5P(Five 6s) = (8C5) * P(6)^5 * P(Not 6)^3 = 56 * (1/6)^5 * (5/6)^3P(Seven 6s) = (8C7) * P(6)^7 * P(Not 6) = 8 * (1/6)^7 * (5/6)\)

P(Odd 6s) = P(One 6) + P(Three 6s) + P(Five 6s) + P(Seven 6s)

Calculate each term and sum them up to find the final probability.

After performing the calculations, we find that P(Odd 6s) is approximately 0.28806 or 28.806%.

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Answer:

A=63.585 cm²

Step-by-step explanation:

Note : It is not given what to find so i am finding are of the circle.

D=9cm

r=D/2

r=9/2

r=4.5

Area of the circle :

A=πr²

A=π4.5²

A=63.585 cm²

The length of the rectangle is 19 cm.

The formula for the area of a rectangle,

Area = Length x Width

Given that the area is 336 cm squared.

So, we can set up an equation,

⇒ 336 = (w + 5)w

where w represents the width of the rectangle.

Expanding this equation,

⇒ 336 = w² + 5w

Moving all terms to one side:

⇒ w² + 5w - 336 = 0

This is a quadratic equation that we can solve using the quadratic formula,

⇒ w = (-5 ± √(5² - 4(1)(-336))) / (2(1))

⇒ w = (-5 ± 23) / 2

We'll take the positive value,

⇒ w = 14

So, the width of the rectangle is 14 cm.

We also know that the length is 5 cm more than the width,

Therefore,

⇒ l = w + 5

⇒ l = 14 + 5

⇒ l = 19

Therefore, the length of the rectangle is 19 cm.

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The inequality can be written as

So, the water can continue to overflow till m minutes.

We approximated the 37.96 minutes to 38 minutes.

So, near to 38 minutes the water can flow.

Answer:

C = 5.50S + 9L

.............

The equation that relates the cost, Cin dollars with the number of small toy cars, S, and the number of large cars, L is  C = 5.50S + 9L.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

A hobby shop sells small and large toy cars. A small toy car is $5.50, and a large toy car is $9.

Let S be the number of a small toy car and L be the number of a large toy car.

The equation can be made:

Total cost:

C = 5.50S + 9L

Thus, the equation that relates the cost, Cin dollars with the number of small toy cars, S, and the number of large cars, L is  C = 5.50S + 9L.

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