What is the slope of the line that passes through the points (-4,5) and (-7,8) ? write your answr in the simplest form

The Probability density Function of Z is given by:
\(f_Z(z)\) = { 2z, 0 ≤ z ≤ 1   , 0  otherwise. }

To find the CDF of Z = |X - Y|, we need to consider two cases:
Case 1: z < 0

If z < 0, then P(Z < z) = 0 since Z is always non-negative.

Case 2: z ≥ 0
If z ≥ 0, then we can express the event {Z < z} in terms of X and Y as follows:
{Z < z} = {(X,Y) : |X - Y| < z}
This event corresponds to a square region in the unit square with vertices at (0,0), (1-z, z), (z,1-z), and (1,1).
The area of this square is \(1 - (1-z)^2 = 2z - z^2.\)
Since X and Y are independent and uniformly distributed in [0,1], the joint PDF of (X,Y) is fXY(x,y) = 1 for 0 ≤ x,y ≤ 1, and zero elsewhere.

Therefore, the probability of the event {Z < z} is given by the double integral:

P(Z < z) = ∫\(\int {Z < z} f_{XY}(x,y) dxdy\)

= ∫∫|x-y| < z 1 dxdy

\(= 2 \int z^0 y^z 1 dxdy\)

= 2∫\(z^0\)(z-y) dy

= z^2.

Thus, the CDF of Z is given by:

FZ(z) = P(Z ≤ z)

= 0, if z < 0

= z², if 0 ≤ z ≤ 1

= 1, if z > 1.

To find the PDF of Z, we can differentiate the CDF:

fZ(z) = d/dz FZ(z)

= 2z, if 0 ≤ z ≤ 1

= 0, otherwise.

Therefore, the PDF of Z is given by:

\(f_Z(z)\) = { 2z, 0 ≤ z ≤ 1

0, otherwise. }

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Answer:

16x-24 -3x is less than 10x

Hey there!

8(2x - 4) - 3x > 5x + 6 - x

DISTRIBUTE 8 WITHIN the PARENTHESES

8(2x) + 8(-4) - 3x > 5x + 6 - x

16x - 32 - 3x > 5x + 6 - 1x

13x - 32 > 4x + 6

SUBTRACT 4x to BOTH SIDES

13x - 32 - 4x > 4x + 6 - 4x

SIMPLIFY IT!

9x - 32 > 6

ADD 32 to BOTH SIDES

9x - 32 + 32 > 6 + 32

CANCEL out: -32 + 32 because it gives you 1

KEEP: 6 + 32 because it helps solve for the x-value

NEW EQUATION: 9x > 6 + 32

SIMPLIFY IT!

9x > 38

DIVIDE 9 to BOTH SIDES

9x/9 > 38/9

CANCEL out: 9/9 because it gives you 1

KEEP: 38/9 because it helps solve for the x-value

NEW EQUATION:

x > 38/9 ≈ x > 4.222222222222222

SIMPLIFY IT!

Therefore, your answer is: x > 38/9

(IT IS AN OPEN CIRCLE SHADED TO THE RIGHT)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

ummm

Step-by-step explanation:

Answer:

29.50

Step-by-step explanation:

Question 1The demand function for a specific good is p = 10 - 1000q. The question is to calculate the price elasticity of demand at q = 1000. We are to interpret the answer as well.

The formula for the price elasticity of demand is given as\(:$$\varepsilon_{d}=\frac{\%\,\text{change}\,\text{in}\,\text{quantity}\,\text{demanded}}{\%\,\text{change}\,\text{in}\,\text{price}}$$\)Now, we can calculate the price elasticity of demand using the given formula:\($$\varepsilon_{d}=\frac{d\,\ln\,q}{d\,\ln\,p}=-\frac{d\,q}{d\,p}\cdot\frac{p}{q}$$\)Now, we can plug in the values for p and q to calculate the price elasticity of demand at\(q = 1000.$$p=10-1000(1000)=-999990\ \ \ \text{and}\ \ \ q=1000$$$$\varepsilon_{d}=-\frac{d\,q}{d\,p}\cdot\frac{p}{q}=\frac{1000}{999990}\cdot\frac{-999990}{1000}=-1$$Interpretation: As $\varepsilon_{d}$\) is negative, we can say that the given good has inelastic demand. Question 2We are given the cost function C(q) = 7000 + 2q.

The total revenue function is given as:\($$R(q)=q\cdot p=q(10-1000q)=10q-1000q^{2}$$\)The profit function is given as:\($$P(q)=R(q)-C(q)$$\)Now, we can calculate the derivative of P(q) w.r.t. q and set it equal to zero to find the quantity that maximizes profit.(a) Calculation of quantity that maximizes profit\(:$$P(q)=R(q)-C(q)=10q-1000q^{2}-7000-2q=-1000q^{2}+8q-7000$$Therefore,$$P'(q)=-2000q+8=0$$$$\Right Arrow q=4/1000=0.004$$\)Now, to verify that this value of q maximizes the profit, we can check the second derivative of P(q) w.r.t. q\(.$$P''(q)=-2000<0$$As $P''(q)<0$,\)we can say that the value of q = 0.004 is the maximum point for P(q).

(b) Calculation of maximum profit:\($$P(q)=R(q)-C(q)=10q-1000q^{2}-7000-2q=-1000q^{2}+8q-7000$$$$\text{At}\ \ q=0.004,\ \ \ \ P(q)=10(0.004)-1000(0.004)^{2}-7000=-26.8$$\)Therefore, the maximum profit is $26.8.The quantity that maximizes the profit is 0.004, and the maximum profit is 26.8.

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In linear equation , A tree that is 50m tall and is transpiring roughly 90liters of water each day. So  0 calorie will the tree use to transpire this quantity of water .

What is linear equation explain with example?

What makes an equation linear?

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The ratio by mass of copper to zinc in the alloy is 3:1.

To find the ratio by mass of copper to zinc in the alloy, we need to first calculate the total mass of the alloy. We can do this by adding the mass of copper and zinc:

Total mass of alloy = 13.5 g + 4.5 g = 18 g

Now we can find the ratio of copper to zinc by dividing the mass of copper by the mass of zinc:

Ratio of copper to zinc = 13.5 g / 4.5 g = 3:1

Therefore, the ratio by mass of copper to zinc in the alloy is 3:1.

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The chances of both drinks being ginger ales is 0.35

There are a total of 30 sodas in the cooler.

The probability is the ratio of number of favorable outcomes to the total number of outcomes

If one drink is selected at random, the probability of selecting a ginger ale is 18/30, or 3/5.

Since the first drink is not replaced, there are now 17 ginger ales left out of a total of 29 sodas. So, the probability of selecting another ginger ale is 17/29.

To find the probability of both drinks being ginger ales,

We multiply the probabilities of each event:

(3/5) × (17/29) = 51/145

= 0.35

Therefore, the probability is 0.35

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Answer:hope this helps

Step-by-step explanation:

It’s on the imagen

Answer:

Y= 3x/4+5                             X= 4y/3-20/3

Step-by-step explanation:

For Y divide each term by 5 and simplify.

For X solve for x by simplifying both sides of the equation, then isolating the variable.

The solution to the given wave equation with the specified boundary and initial conditions is u(x, t) = ∑[(nπ*A_n*cos(nπλt) + nπ*B_n*sin(nπλt))]*sin(nπx), where the sum is over all positive integers n.

The given equation is a partial differential equation known as the wave equation. It describes the behavior of waves propagating through a medium. The boundary conditions specify that the solution should be zero at both ends of the interval [0, 1], indicating that the wave is confined within this region. The initial condition u(x,0) = sin(ntx) represents the initial displacement of the wave at time t = 0.

To solve this problem, we can separate variables by assuming a solution of the form u(x, t) = X(x)T(t). Substituting this into the wave equation, we obtain X''(x)T(t) - X(x)T''(t) = 0. Rearranging and dividing by X(x)T(t), we have X''(x)/X(x) = T''(t)/T(t). Since the left-hand side depends only on x and the right-hand side depends only on t, both sides must be equal to a constant, say -λ².This leads to two ordinary differential equations: X''(x) + λ²X(x) = 0 and T''(t) + λ²T(t) = 0. The boundary conditions for X(x) imply that the solutions are of the form X(x) = sin(nπx), where n is a positive integer. Plugging this into the equation for T(t), we find T''(t) + λ²T(t) = -(nπ)²T(t). The solutions for T(t) are T(t) = A*cos(nπλt) + B*sin(nπλt), where A and B are constants.

Combining the solutions for X(x) and T(t), we obtain u(x, t) = Σ[A_n*cos(nπλt) + B_n*sin(nπλt)]*sin(nπx), where the sum is taken over all positive integers n. Finally, the constants A_n and B_n can be determined using the initial condition u(x,0) = sin(ntx). By matching the coefficients of sin(nπx) on both sides of the equation, we can find the values of A_n and B_n. The resulting solution is u(x, t) = Σ[(nπ*A_n*cos(nπλt) + nπ*B_n*sin(nπλt))]*sin(nπx), where the sum is taken over all positive integers n.

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After the British conquest of Bengal, Calcutta (now Kolkata) experienced significant growth, transforming from a small village to a bustling city.

The colonial period brought about notable changes in the city's culture, architecture, and the lives of both Europeans and Indians. During the colonial period in Calcutta, the city became a vibrant center of British influence in India. European culture, customs, and architectural styles left a lasting impact on the cityscape. British architectural elements, such as neoclassical facades, grand buildings, and wide boulevards, started to dominate the urban landscape. Calcutta became known for its grand colonial buildings, including the Victoria Memorial, St. Paul's Cathedral, and the Raj Bhavan.

The colonial presence in Calcutta led to a blending of cultures, as British and Indian traditions intertwined. European social norms and lifestyles became prominent among the elite class, with clubs, balls, and social gatherings being part of the European social fabric. Meanwhile, Indian culture continued to thrive in the city, with festivals, music, art, and literature playing a vital role in the lives of the Indian population. The city became a melting pot of diverse cultures, languages, and traditions.

However, it is important to note that the colonial period also brought about significant disparities and challenges for the Indian population. British policies and administration often favored the interests of the colonial rulers, leading to economic exploitation and social inequality. The indigenous population faced restrictions and limitations in various aspects of life, including access to education, employment opportunities, and political representation. Nevertheless, the colonial period in Calcutta shaped the city's identity and laid the groundwork for its development as a cultural, intellectual, and commercial hub in India.

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Answer:

C.

Step-by-step explanation:

the ratio is 1:2

so,

\(4*2=8\\7*2=14\\1*2=2\)

the only shape with those numbers is C

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!

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The answer is: A) r=0.04; R=0.96 B) 8% C) 92.16%.

The Hardy-Weinberg equilibrium is a method for determining the frequency of certain genetic traits in a population. The following are the frequencies of the red hair (r) and non-red hair (R) alleles in the Norwegian population, according to the question: A) The total frequency of alleles is 1. If red hair (r) is found in approximately 4% of the people in Norway, then the frequency of the R allele must be 0.96 or 96%. R = 0.96 r = 0.04 B) The frequency of hetero zygotes in a population can be determined by multiplying the frequency of the R allele by the frequency of the r allele and then multiplying that number by 2.

Heterogeneous genotype = 2pq Here, p represents the frequency of the R allele, and q represents the frequency of the r allele. p = R = 0.96 q = r = 0.04 Therefore, 2pq = 2(0.96 x 0.04) = 0.077, or approximately 8%. C) In order for a child to have red hair, both parents must carry the r allele. If both parents are homozygous for the R allele, there is no chance that their child will have red hair. This means that the proportion of matings that cannot result in a child with red hair is (0.96 x 0.96) = 0.9216 or 92.16%.

Therefore, the answer is: A) r=0.04; R=0.96 B) 8% C) 92.16%.

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A very small P-value indicates that the null hypothesis is highly inconsistent with the collected data. That is, the lower the p-value, the higher the statistical significance of the observed data.

P-value is a statistical measure used to test a hypothesis against observed data. The p-value measures the probability of getting the observed result given that the null hypothesis is true. A p-value > 0.05 is interpreted by many as "not statistically significant". This means that there is insufficient evidence to reject the null hypothesis. A small p-value indicates that the difference is unlikely to be due to sampling error. In other words, very small p-values suggest rejecting the null hypothesis and using the alternative hypothesis instead accept.

How to calculated p-Value ?

P-values are typically obtained using p-value tables or spreadsheet/statistical software. These calculations are based on assumptions or known probability distributions of the particular statistic being tested. A p-value of 0.05 or less is generally considered statistically significant.

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The required mean of the values 20 and 40 is 30.

The total of all numbers multiplied by the total number of values yields the mean (also known as the arithmetic mean, which varies from the scaling factor) of a dataset.

The term "average" is frequently used to describe this central trend measurement.

So, we have the values:

20, 40

Mean formula: Sum of terms / Number of terms

Obtain mean using the formula as follows:

Mean: Sum of terms / Number of terms

Mean: 60/2

Mean: 30

Therefore, the required mean of the values 20 and 40 is 30.

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The probability that the mean weight of 20 randomly picked fruit will be between 752 grams and 766 grams can be calculated using the Central Limit Theorem. According to the Central Limit Theorem, if the sample size is large enough, the sampling distribution of the mean will be approximately normally distributed regardless of the shape of the population distribution.

In this case, the mean weight of the fruit is normally distributed with a mean of 744 grams and a standard deviation of 37 grams.

To find the probability, we need to standardize the values of 752 grams and 766 grams using the formula z = (x - μ) / (σ / √n), where z is the standard score, x is the value, μ is the mean, σ is the standard deviation, and n is the sample size.

For 752 grams:
z1 = (752 - 744) / (37 / √20) = 0.589

For 766 grams:
z2 = (766 - 744) / (37 / √20) = 1.573

Now, we can use a standard normal distribution table or a calculator to find the probability between these two z-scores.

Using the standard normal distribution table, the probability between z1 = 0.589 and z2 = 1.573 is approximately 0.1398 or 13.98%.

Therefore, the probability that the mean weight of 20 randomly picked fruit will be between 752 grams and 766 grams is approximately 0.1398 or 13.98%.

Please note that the calculation assumes the weights of the fruit are independent and identically distributed.

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The solution to the compound inequality in interval notation is (-∞, -5] or (2, ∞).

To solve the compound inequality, we need to consider the two individual inequalities separately and then combine their solutions. Let's break it down step by step.

Inequality 1: 2(x + 3) > 6

First, distribute the 2 on the left side: 2x + 6 > 6

Then, subtract 6 from both sides: 2x > 0

Divide both sides by 2: x > 0

Inequality 2: 2x - 3 ≤ -7

Add 3 to both sides: 2x ≤ -4

Divide both sides by 2: x ≤ -2

Now, we combine the solutions of the two inequalities:

For the first inequality, x > 0, we use parentheses to indicate that 0 is not included in the solution set. Therefore, the solution is (0, ∞).

For the second inequality, x ≤ -2, we use brackets to indicate that -2 is included in the solution set. Therefore, the solution is [-∞, -2].

Finally, we combine the solutions of both inequalities. Since we are dealing with the logical "or" (represented by the symbol ∨), we take the union of the two solution sets. Hence, the solution to the compound inequality is (-∞, -5] or (2, ∞).

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Answer:

x>2

Step-by-step explanation:

Answer:   \(x \ge 2\)

The x part is already taken care of, so you'll fill the rest into the box.

On a keyboard you could type x >= 2 to mean \(x \ge 2\)

=====================================================

Explanation:

We have a closed or filled in circle at x = 2. This means 2 is included in the shaded region solution set. So we'll have "or equal to" as part of the inequality.

We'll also have "greater than" because how the shading is to the right of the closed circle.

So put together that's why the graph represents \(x \ge 2\)

Something like x = 5 is a solution because \(5 \ge 2\) is true

Something like x = 0 is not a solution because \(0 \ge 2\) is false

Answer:

7^1/3 * y^1/3

Step-by-step explanation:

(7y) ^ 1/3

We know that (ab) ^c = a^c * b^c

7^1/3 * y^1/3

Answer:

7^1/3 * y^1/3

Step-by-step explanation:

7^1/3 * y^1/3

There are 2 students who used none of the above-mentioned means of transportation.

There were 2 students who used none of the above-mentioned means of transportation.

A poll was conducted on 100 students at a commuter campus to determine how they got to school.

The following are the results: 36 people drove alone.

34 people carpooled.30 people used public transportation.

5 people used both carpools and public transportation.8 people used both a carpool and their own car.

7 people used buses and their own cars.

4 people used all three modes of transportation.

Now, let us calculate the number of students who didn't use any of the above means of transportation:

Number of students who drove alone = 36

Number of students who carpooled = 34

Number of students who used public transport = 30

Number of students who used carpool and public transport = 5

Number of students who used carpool and their own car = 8

Number of students who used buses and their own car = 7

Number of students who used all three modes of transportation = 4

Thus, the total number of students who used one or more means of transportation =36+34+30+5+8+7+4 = 124

Now, subtracting the number of students who used one or more means of transportation from the total number of students polled will give us the number of students who used none of the means of transportation.

100 - 124 = -24

But, negative values are meaningless in this context.

Hence, the answer is 2.

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Answer:

-34.

Step-by-step explanation:

This is an arithmetic sequence with first term a1  and common difference -2.

nth term = a1 + d(n - 1)

23rd term = 10 - 2(23-1)

= 10 - 44

= -34.

Answer:

-34

Step-by-step explanation:

The sequence starts with 10. Each subsequent term is 2 less than the previous term.

The common difference is -2.

The second term is 10 + (-2) × 1

The third term is 10 + (-2) × 2

The fourth term is 10 + (-2) × 3

Each term you subtract a multiple of -2 from 10. The multiple is 1 less than the number of the term multiplied by -2.

For term n, you get 10 + (-2) × (n - 1).

The 23rd term is:

10 + (-2) × (23 - 1) = 10 - 2 × 22 = 10 - 44 = -34

The percent decrease in the travel time after getting a new job is 36%.

Percentage is defined as part of a whole expressed in hundredths or out of 100. It is usually written with the symbol "%".

First, determine the decrease in travel time after getting a new job by subtracting the new travel time of 30.72 minutes from the initial travel time of 48 minutes.

decrease in time = 48 - 30.72

decrease in time = 17.28

Then, determine the percent decrease by dividing the decrease in time of 17.28 minutes by the initial travel time of 48 minutes and multiply by 100.

percent decrease = (17.28 / 48) x 100

percent decrease = 36%

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Answer: Two strong parties that win most elections.

Step-by-step explanation: “ The modern two-party system consists of the "Democratic" Party and the "Republican" Party. ... These two parties have won every United States presidential election since 1852 and have controlled the United States Congress since at least 1856.”

This means that the two strong parties are Democrats and the Republicans, those of which who wins most/all elections.

Answer:

B. Two strong parties that win most elections

Step-by-step explanation:

The dimensions of a Norman window of maximum area if the total perimeter is 22 feet are: Width of the rectangular part = 11/(4π) feet, Height = 11/(4π) feet and Radius of the semicircle part = (22 - 11/π) / π feet

To find the dimensions of the Norman window of maximum area, we need to use optimization techniques. Let's first define some variables:

- Let's call the width of the rectangular part of the window "w".
- Let's call the height of the rectangular part of the window "h".
- Let's call the radius of the semicircle "r".

From the problem, we know that the total perimeter of the window is 22 feet. That means:

- The perimeter of the rectangular part of the window is 2w + 2h.
- The perimeter of the semicircle part of the window is half the circumference of a circle with radius "r", which is πr.

So we can write an equation for the total perimeter:

2w + 2h + πr = 22

We also know that the area of the window is given by:

A = wh + 1/2π\(r^2\)

Our goal is to maximize A. To do that, we need to express A in terms of just one variable, so we can take the derivative and find the maximum. We can use the equation for the perimeter to solve for one of the variables in terms of the others. For example, we can solve for "r":

r = (22 - 2w - 2h) / π

Now we can substitute this expression for "r" into the equation for the area:

A = wh + 1/2π [(22 - 2w - 2h) / π\(]^2\)

Simplifying this equation, we get:

A = wh + 1/2π (484 - 44w - 44h + 4wh)

To find the maximum of this function, we need to take the partial derivatives with respect to "w" and "h" and set them equal to zero:

∂A/∂w = h - 22/(2π) + 2wh/(2π) = 0
∂A/∂h = w - 22/(2π) + 2wh/(2π) = 0

Solving these equations simultaneously, we get:

w = h = 11/(4π)

Now we can substitute these values into the equation for "r" to find the radius of the semicircle:

r = (22 - 2w - 2h) / π = (22 - 11/π) / π

Therefore, the dimensions of the Norman window of maximum area are:

- Width of the rectangular part: w = h = 11/(4π) feet
- Height of the rectangular part: w = h = 11/(4π) feet
- Radius of the semicircle part: r = (22 - 11/π) / π feet

Note that we could also have used the equation for "r" to solve for "w" or "h" instead, and we would have gotten the same result.

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The student covers a total distance of 22.05 kilometers in a week's time, walking between the park and the house each day.

To find the total distance covered by the student in a week's time, we need to calculate the distance covered in one round trip (from the house to the park and back) and then multiply it by the number of round trips in a week.

Given that the difference between the park and house is 1 kilometer and 575 meters, we can convert it to a total distance of 1.575 kilometers.

In a round trip, the student covers twice the distance between the park and the house, which is 1.575 kilometers * 2 = 3.15 kilometers.

Now, we need to determine how many round trips the student makes in a week. Let's assume the student makes one round trip each day.

Since there are 7 days in a week, the total distance covered by the student in a week's time is 3.15 kilometers * 7 = 22.05 kilometers.

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After the boys from Barack Academy travel to Hillary High and then return with a combination of boys and girls, Hillary High will have more boys on campus compared to the number of girls at Barack Academy.

Based on the given information, we can determine that both schools initially have the same number of students. The boys from Barack Academy board the bus and travel to Hillary High for a dance. Afterward, the bus is filled with a combination of boys and girls and they travel back to Barack Academy for another dance.

Since all the boys from Barack Academy initially leave the school and then return with a combination of boys and girls, it can be inferred that the number of boys on campus at Barack Academy remains the same or increases (if some boys from Hillary High join them).

On the other hand, at Hillary High, the girls who stay at the school are joined by a combination of boys and girls from the other school. Therefore, it can be inferred that the number of boys on campus at Hillary High increases.

Based on this analysis, it can be concluded that after the events described, Hillary High would have more boys on campus than Barack Academy would have girls on campus.

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In case (a), y = x^4 + 1 with x = -1 and delta-x = dx = 0.01, we need to calculate delta-y and dy. In case (b), y = x - 2x^3 with x = 3 and delta-x = dx = 0.001, we also need to find delta-y and dy. Therefore, delta-y is approximately -1.039404. Therefore, delta-y is approximately 54.001.

(a) For case (a), let's calculate delta-y and dy.

Given x = -1, delta-x = dx = 0.01, and the function y = x^4 + 1, we can find:

y = (-1)^4 + 1 = 1 + 1 = 2.

Now, let's calculate delta-y:

delta-y = y(x + delta-x) - y(x)

       = y(-1 + 0.01) - y(-1)

       = y(-0.99) - y(-1)

       = (-0.99)^4 + 1 - 2

       ≈ 0.960596 - 2

       ≈ -1.039404.

Therefore, delta-y is approximately -1.039404.

(b) For case (b), let's find delta-y and dy.

Given x = 3, delta-x = dx = 0.001, and the function y = x - 2x^3, we can calculate:

y = 3 - 2(3)^3 = 3 - 54 = -51.

Now, let's find delta-y:

delta-y = y(x + delta-x) - y(x)

       = y(3 + 0.001) - y(3)

       = y(3.001) - y(3)

       = 3.001 - (-51)

       ≈ 54.001.

Therefore, delta-y is approximately 54.001.

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The answer is: A) The data support the researchers' belief that night owls have better dream recall than early birds. B) we can be 92% confident that the true difference in mean number of dreams recalled per week between night owls and early birds is between 1.87 and 2.63.

A) These are the alternative and null hypotheses:

H0: μE = μN (the mean number of dreams recalled each week is the same for early birds and night owls) (the mean number of dreams recalled per week is the same for early birds and night owls)

Ha: μE < μN (the mean number of dreams recalled each week is smaller for early birds than for night owls) (the mean number of dreams recalled per week is lower for early birds than for night owls)

Using the following formula, we can run a two-sample t-test with unequal variances:

t = [(sN2 / nN) + (sE2 / nE)] / sqrt[(xN - xE)]

where nN and nE are the sample sizes for night owls and early birds, respectively, and xN and sN and xE and sE are the sample means and standard deviations for night owls and early birds, respectively.

When we enter the values, we obtain:

t = (9.55 - 7.26) / sqrt[(5.88^2 / 100) + (6.94^2 / 100)] = 5.01

The data are consistent with the researchers' hypothesis that night owls are more capable of remembering their dreams than early birds.

B) We can use the following formula to determine the confidence interval:

CI is equal to (xN - xE) t/2 * sqrt[(sN / nN) + (sE / nE)].

where t/2 is the t-value for the required level of confidence and degrees of freedom, and xN, xE, sN, sE, nN, and nE are the same as previously (198 in this case).

With a t-value of 1.75 and a 92% confidence level (from a t-distribution with 198 degrees of freedom), we get:

CI is equal to (9.55 - 7.26) 1.75 * sqrt[(5.88 - + 6.94 / 100)] = (1.87, 2.63) (1.87, 2.63)

The genuine difference between night owls and early birds in terms of the average number of dreams recalled per week is therefore between 1.87 and 2.63, with a 92% confidence interval.

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Answer:

Would the answer be 9?

Step-by-step explanation:

Use PEMDAS.
3/1/3=1
9-1-8
8+1=9

\(9 - 3 \div \frac{1}{3} + 1\)

you can follow the PEDMAS rule where,

P= Parenthesis

E= Exponents

D= Division

M= Multiplication

A= Addition

S= Subtraction

\(3 \div \frac{1}{3} = 1\)

\(9 - 8 = 1\)

\(8 + 1 = 9\)

Answer:

Scalene Triangle

Step-by-step explanation:

Measure the side and if the none of the sides are equal then it will be a scalene triangle