What is the solution for -3w-4=w+4

Answer:

Step-by-step explanation:

There are 25 numbers between and including 1-25, so there are 25 possibilities. The possible outcomes are:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

Answer:

3,4

Step-by-step explanation:

this is g mail ok dont do enything messed up ok :)

Without the standard deviation, we cannot calculate the standard error or the 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B.

To calculate a 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B, we can use the least squares means estimates provided in the JMP output.

According to the JMP output, the estimate for the mean time required to stabilize emergency condition 4 using display panel B is 10.375000.

To calculate the confidence interval, we need to find the margin of error. The margin of error can be calculated using the formula:

Margin of Error = Critical Value * Standard Error

In this case, we need to find the critical value for a 95 percent confidence interval. Since we have a sample size of 24 (as mentioned in the question), we can use the t-distribution with (24-1) degrees of freedom to find the critical value.

Looking up the critical value in the t-distribution table, with (24-1) degrees of freedom and a confidence level of 95 percent, we find that the critical value is approximately 2.064.

The standard error can be calculated using the formula:

Standard Error = Standard Deviation / √(sample size)

The standard deviation is not provided in the given information. Therefore, we cannot calculate the standard error or the confidence interval without this information.

In summary, without the standard deviation, we cannot calculate the standard error or the 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B.

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Answer:

If 43=x, this means that x is 43

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

x is the number of days worked

y is the total amount earned

m is the amount earned per day

so y = mx

Answer:

Is and proportional

Step-by-step explanation:

1. Correctly stated hypothesis testing problem: H0: μ = 25, H1: μ ≠ 25 (two-tailed test).

2. Incorrectly stated hypothesis testing problem: H0: μ > 10, H1: μ = 10 (null hypothesis should have an equal sign).

3. Correctly stated hypothesis testing problem: H0: x = 50, H1: x ≠ 50 (two-tailed test).

4. Correctly stated hypothesis testing problem: H0: p = 0.1, H1: p = 0.5 (two-tailed test).

5. Correctly stated hypothesis testing problem: H0: μ = 30, H1: μ > 30 (one-tailed test).

1. H0: μ = 25, H1: μ ≠ 25

This is a correctly stated hypothesis testing problem. H0 represents the null hypothesis, which states that the population mean (μ) is equal to 25. H1 represents the alternative hypothesis, which states that the population mean is not equal to 25.

The use of the symbol "≠" indicates a two-tailed test, where we are interested in determining whether the population mean is significantly different from 25 in either direction.

2. H0: μ > 10, H1: μ = 10

This is not a correctly stated hypothesis testing problem. The null hypothesis (H0) should always represent the hypothesis of no effect or no difference, while the alternative hypothesis (H1) should represent the hypothesis we are trying to establish.

In this case, the null hypothesis suggests that the population mean (μ) is greater than 10, while the alternative hypothesis states that the population mean is equal to 10. This formulation is incorrect because the null hypothesis should always have an equal sign (e.g., =, ≤, or ≥) and the alternative hypothesis should have an inequality sign (e.g., ≠, <, or >).

3. H0: x = 50, H1: x ≠ 50

This is a correctly stated hypothesis testing problem. Here, H0 represents the null hypothesis that the sample mean (x) is equal to 50. H1 represents the alternative hypothesis, stating that the sample mean is not equal to 50.

The symbol "≠" indicates a two-tailed test, where we are interested in determining whether the sample mean is significantly different from 50 in either direction.

4. H0: p = 0.1, H1: p = 0.5

This is a correctly stated hypothesis testing problem. H0 represents the null hypothesis that the population proportion (p) is equal to 0.1. H1 represents the alternative hypothesis, stating that the population proportion is equal to 0.5.

The use of the equal sign (=) in both hypotheses indicates that this is a two-tailed test, seeking to determine whether the population proportion significantly differs from 0.1 in either direction.

5. H0: μ = 30, H1: μ > 30

This is a correctly stated hypothesis testing problem. H0 represents the null hypothesis that the population mean (μ) is equal to 30. H1 represents the alternative hypothesis, stating that the population mean is greater than 30. The symbol ">" indicates a one-tailed test, where we are interested in determining whether the population mean is significantly larger than 30.

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The rate is the angle between the line and the water changing when there are 25 feet of line out is 3 rad/sec

we can form the given  situation  in the form of a right-angle triangle with a constant height of 15 feet(4.572 m)  and a hypotenuse which is the fishing line, shrinking at a rate of 1 f/s = 0.3048 m/s .Here we consider θ to be the angle between the hypotenuse and water and r to be the length of the hypotenuse. we know that: sinθ = 4.572 / r

differentiating both sides with respect to t:

=>cosθ dθ/dt = (-4.572/r2) dr/dt

=>dθ/dt = (1/cosθ)(-4.572/r2) dr/dt

here dr/dt = -  0.3048 m/s, the negative sign is because the length r  is shrinking. So, When the line is 25 feet( 7.62) out, r = 7.62

cosθ = √(1 - sin2θ) = √[1 - (4.572/r)2] = √[1 - (4.572/7.62)2] ≅ 0.8

so the rate of the angle changing  is :

dθ/dt = (1/0.8) [-4.572/(7.62^2)] (-0.3048) rad/sec = 3 rad/sec

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The area between y=x² +9 and y = x for x in the interval (0,8) is (x²+9-x) dx [2] 8(x-x²-9) dx [4] 8(x-x² +9) dx none of these √=+1+v==√x+1-VI, The answer to the question is B. False.

The given options [1], [2], [3], and [4] do not correctly represent the area between the curves y = x² + 9 and y = x for x in the interval (0,8). The correct expression for the area between these curves can be found by integrating the difference between the curves over the given interval.

To calculate the area, we need to find the points of intersection between the curves. Setting x² + 9 = x and solving for x gives us x = 3. Thus, the interval of integration is (0, 3).

Now, we can find the area by integrating the difference between the curves:

Area = ∫[(x² + 9) - x] dx from 0 to 3

Therefore, the correct expression for the area between the curves is not provided in the given options. The area is 31.5 square units.

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Period of the functions: The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ). The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.

We know that cos (t) is periodic and has a period of 2π.∴ b = 2π∴ The period of the function f(t) =

(7 cos t)² = 2π/b = 2π/2π = 1.

The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ) Hence, the period of the function f(t) =

cos (2φt²/m) is √(4πm/φ).

The function f(t) = (7 cos t)² is a trigonometric function and it is periodic. The period of the function is given by 2π/b where b is the period of cos t. As cos (t) is periodic and has a period of 2π, the period of the function f(t) = (7 cos t)² is 2π/2π = 1. Hence, the period of the function f(t) = (7 cos t)² is 1.The function f(t) = cos (2φt²/m) is also a trigonometric function and is periodic. The period of this function is given by T = √(4πm/φ). Therefore, the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).

The period of the function f(t) = (7 cos t)² is 1, and the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).

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Answer:

18

Step-by-step explanation:

Intersecting Secants Theorem:

6(x + 6) = 8(8 + 10)

6x + 36 = 8(18)

6x + 36 = 144

6x = 144 - 36

6x = 108

x = 18

   Value of \(10^x\) will be between 1 and 10.

 Given in the question,

If we have to find the range of the value of the number, substitute x = 0 and 1

\(10^0=1\)

\(10^1=10\)

  Therefore, value of \(10^x\) will vary between 1 and 10.

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Answer:

Acute

Step-by-step explanation:

Acute is defined as an angle less than 90°. All of those angles are less the 90°.

Answer:

right triangle

Step-by-step explanation:

To test for a right triangle, use the Pythagorean theorem.

Let the legs, a and b, be the two shorter sides, and let the hypotenuse, c, be the longest side.

a² + b² = c²

a² + b² = 7.2² + 9.6² = 51.84 + 92.16 = 144

c² = 12² = 144

Since a² + b² = c², the triangle is a right triangle.

Answer:

x^2 +2x + 3

Step-by-step explanation:

x^3 - x -6 / x-2

Step one - FACTOR x^3:

(x-2)(x^2+2x+3) / x-2

Step two - CANCEL the common factor of x-2

x^2+2x+3

Answer:

5

Step-by-step explanation:

a. Based on the exterior angle theorem, m∠1 = 122°

b. Based on the triangle sum theorem, t = 9

c. m∠RQS = 110°

d. ΔPQT is not similar to ΔRST.

The angle that is formed by an extended side of a triangle is called the exterior angle, according to the exterior angle theorem, the measure of the exterior angle is equal to the sum of the remote angles of the triangle.

a. m∠1 = 52 + 70 [exterior angle theorem]

m∠1 = 122°

b. 4t + 6t + 90 = 180 [triangle sum theorem]

10t = 180 - 90

10t = 90

10t/10 = 90/10

t = 9

c. ∠RQS and ∠RQN are a linear pair, therefore:

m∠RQS + m∠RQN = 180

Substitute

m∠RQS + 70 = 180

m∠RQS = 180 - 70

m∠RQS = 110°

d. The corresponding angles of triangles PQT and RST are not congruent to each other, which is one of the criteria for proving that two triangles are similar. Therefore:

ΔPQT is not similar to ΔRST.

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a. The payback period for the equipment purchase is 8 years.

b. The discounted payback period for the equipment purchase is greater than 8 years.

c. The Benefits Cost ratio for the equipment purchase is 1.39.

d. The Net Future Worth (NFW) of this investment is positive.

a. To calculate the payback period, we need to determine the time it takes for the cumulative cash inflows to equal or exceed the initial cost. In this case, the initial cost is $1,000,000, and the annual cash inflows are $100,000 for the first year, increasing by $50,000 every year for the next 6 years. We calculate the cumulative cash inflows as follows:

Year 1: $100,000

Year 2: $100,000 + $50,000 = $150,000

Year 3: $100,000 + $50,000 + $50,000 = $200,000

Year 4: $100,000 + $50,000 + $50,000 + $50,000 = $250,000

Year 5: $100,000 + $50,000 + $50,000 + $50,000 + $50,000 = $300,000

Year 6: $100,000 + $50,000 + $50,000 + $50,000 + $50,000 + $50,000 = $350,000

Year 7: $100,000 + $50,000 + $50,000 + $50,000 + $50,000 + $50,000 + $50,000 = $400,000

The payback period is the time it takes for the cumulative cash inflows to reach or exceed the initial cost. In this case, it takes 8 years to reach $400,000, which is greater than the initial cost of $1,000,000.

b. The discounted payback period considers the time it takes for the cumulative discounted cash inflows to equal or exceeds the initial cost. We need to discount the cash inflows using the MARR (10%). The discounted cash inflows are as follows:

Year 1: $100,000 / (1 + 0.10)^1 = $90,909.09

Year 2: $50,000 / (1 + 0.10)^2 = $41,322.31

Year 3: $50,000 / (1 + 0.10)^3 = $37,566.64

Year 4: $50,000 / (1 + 0.10)^4 = $34,151.49

Year 5: $50,000 / (1 + 0.10)^5 = $31,046.81

Year 6: $50,000 / (1 + 0.10)^6 = $28,223.46

Year 7: $50,000 / (1 + 0.10)^7 = $25,645.87

The cumulative discounted cash inflows are calculated as follows:

Year 1: $90,909.09

Year 2: $90,909.09 + $41,322.31 = $132,231.40

Year 3: $132,231.40 + $37,566.64 = $169,798.04

Year 4: $169,798.04 + $34,151.49 = $203,949.53

Year 5: $203,949.53 + $31,046.81 = $235,996.34

Year 6: $235,996.34 + $28,223.46 = $264,219.80

Year 7: $264,219.80 + $25,645.87 = $289,865.67

The discounted payback period is the time it takes for the cumulative discounted cash inflows to reach or exceed the initial cost. In this case, it takes more than 8 years to reach $289,865.67, which is greater than the initial cost of $1,000,000.

c. The Benefits Cost ratio is calculated by dividing the cumulative cash inflows by the initial cost. In this case, the cumulative cash inflows over 7 years are $400,000, and the initial cost is $1,000,000. Therefore, the Benefits Cost ratio is 0.4 (400,000/1,000,000).

d. The Net Future Worth (NFW) is calculated by subtracting the initial cost from the cumulative cash inflows, considering the time value of money. We discount the cash inflows using the MARR (10%) before subtracting the initial cost. The discounted cash inflows are as follows:

Year 1: $100,000 / (1 + 0.10)^1 = $90,909.09

Year 2: $50,000 / (1 + 0.10)^2 = $41,322.31

Year 3: $50,000 / (1 + 0.10)^3 = $37,566.64

Year 4: $50,000 / (1 + 0.10)^4 = $34,151.49

Year 5: $50,000 / (1 + 0.10)^5 = $31,046.81

Year 6: $50,000 / (1 + 0.10)^6 = $28,223.46

Year 7: $50,000 / (1 + 0.10)^7 = $25,645.87

The cumulative discounted cash inflows are calculated as follows:

Year 1: $90,909.09

Year 2: $90,909.09 + $41,322.31 = $132,231.40

Year 3: $132,231.40 + $37,566.64 = $169,798.04

Year 4: $169,798.04 + $34,151.49 = $203,949.53

Year 5: $203,949.53 + $31,046.81 = $235,996.34

Year 6: $235,996.34 + $28,223.46 = $264,219.80

Year 7: $264,219.80 + $25,645.87 = $289,865.67

The NFW is calculated as the cumulative discounted cash inflows minus the initial cost:

NFW = $289,865.67 - $1,000,000 = -$710,134.33

The NFW of this investment is negative, indicating that the investment does not yield positive net benefits considering the MARR (10%).

Problem 2:

a. The AB/AC ratio for the first increment (C-D) is not provided in the given information and cannot be calculated without additional data.

b. The AB/AC ratio for the second increment (B-C) is not provided in the given information and cannot be calculated without additional data.

c. The AB/AC ratio for the third increment (A-B) is not provided in the given information and cannot be calculated without additional data.

d. The best alternative using B/C ratio analysis cannot be determined without the AB/AC ratios for each increment.

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Answer: r=0

It’s very easy to do and make sure to simplify

Answer:

the answer would be she would drive 192 miles

Answer:

affixwritersgmaicom

APP 447520635495

Answer: 12 donuts are glazed

Step-by-step explanation:

1/3 of 18 = 6

2/3 o 18 = 12

The value for the hotspots of the similar triangles ∆ABC and ∆PWR are:

(1). angle B = 68°

(2). PQ = 5cm

(3). BC = 19.5cm

(4). area of ∆PQR = 30cm²

Similar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.

(1). angle B = 180 - (22 + 90) {sum of interior angles of a triangle}

angle B = 68°

Given that the triangle ∆ABC is similar to the triangle ∆PQR.

(2). PQ/7.5cm = 12cm/18cm

PQ = (12cm × 7.5cm)/18cm {cross multiplication}

PQ = 5cm

(3). 13cm/BC = 12cm/18cm

BC = (13cm × 18cm)/12cm {cross multiplication}

BC = 19.5cm

(4). area of ∆PQR = 1/2 × 12cm × 5cm

area of ∆PQR = 6cm × 5cm

area of ∆PQR = 30cm²

Therefore, the value for the hotspots of the similar triangles ∆ABC and ∆PWR are:

(1). angle B = 68°

(2). PQ = 5cm

(3). BC = 19.5cm

(4). area of ∆PQR = 30cm²

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The length of line segment K′N′ from the trapezoid KLMN cannot be determined based on the given information. More information is needed to answer this question accurately.

The length of line segment K′N′ will be the same as the length of line segment KN in the original trapezoid KLMN. This is because a reflection across the x- or y-axis does not change the length of any line segments, it only changes their position.

To find the length of line segment KN, we can use the distance formula:

KN = √((x2 - x1)² + (y2 - y1)²)

Where x1 and y1 are the coordinates of point K, and x2 and y2 are the coordinates of point N.

Without knowing the coordinates of points K and N, it is not possible to determine the length of line segment KN or K′N′. Therefore, more information is needed to answer this question accurately.

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The standard form of the equation of f(x) is f(x) = x2 - 4x + 12.

Since the vertex of the parabola is at (2, 16), we can write the equation of the parabola in vertex form as:

f(x) = a(x - 2)2 + 16

where "a" is a constant.

To determine the value of "a", we can use one of the points on the parabola, such as (0, 12). Substituting these values into the equation gives:

12 = a(0 - 2)2 + 16

Simplifying this equation yields:

-4 = -4a

Therefore, a = 1. Substituting this value of "a" into the equation gives:

f(x) = (x - 2)2 + 16

Expanding and simplifying this equation gives:

f(x) = x2 - 4x + 12

Therefore, the standard form of the equation of f(x) is f(x) = x2 - 4x + 12. Answer: (B)

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Answer:

113.04

Step-by-step explanation:

Enter the area of the circle, in square centimeters. Round your answer to the nearest hundredth. 1.

Answer:

C

Step-by-step explanation:

x - 3 < -9

simplifies to x < -6, which is to the left with an open circle

x + 5> 12

simplifies to x > 7, which is to the right a closed circle

Answer:

Substitute y and x

(2)2 + (1)3+7

then multiply 2 * 2

4+ (1)3+7

then multiply 1* 3

4+ 3+7

add those numbers

14 ang iyong sagot, tandaan kapag nakikita ang panaklong tulad ng nakikita mo dito nangangahulugang dumami

Answer:

The product of (x + 1)(x² + 2x + 2) is

x³ + 3x² + 2x + 4

Step-by-step explanation:

The product of (x + 1)(x² + 2x + 2) is Given in the steps below.

(x + 1)(x² + 2x + 2) = x(x² + 2x + 2) + x² + 2x + 2

= x³ + 2x² + 2 + x² + 2x + 2

= x³ + 3x² + 2x + 4

The value stored in the variable x after the execution of the following code snippet will be b) 2.

The right-click context menu option or a combination of hotkeys can be used to add code snippets, which are compact chunks of reusable code, to a code file. Although try-finally and if-else blocks, for example, are frequently used code blocks found in code snippets, you can also use them to add whole classes or methods.

Learn more about using the templates tool to create reusable emails. Applications and web pages use snippets. Snippets are made to be reusable and to add functionality, like connecting various parts of a program.

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Answer:

x = 5 , y = 15

Step-by-step explanation:

Since the figures are congruent then corresponding sides and angles are congruent , that is

WG = DG ( substitute values )

3x - 5 = 10 ( add 5 to both sides )

3x = 15 ( divide both sides by 3 )

x = 5

and

∠ WGF = ∠ DGF , that is

15x + y = 90 ( substitute x = 5 )

15(5) + y = 90

75 + y = 90 ( subtract 75 from both sides )

y = 15