what were the 3 constellations that were above the horizon at
9PM on August 31, 2022?

Answer:

sodium ion

Explanation:

And, so if we gots a representation of Na+ , or Cl− , we know that for the sodium ion, while there are 11 charged nuclear particles (how do we know this?), there are 10 charged extranuclear particles, 10 electrons.

brainliest pls

Answer:

KBr+Pb(NO3)2=? is an equation you can use.

Explanation:

Answer:

carbon dioxide

Explanation:

An example of a compound from the given choices is carbon dioxide.

A compound is any substance composed of two or more atoms /elements joined together in a definite grouping .

The minimum volume of 4.00 M KOH required for the reaction to go to completion is 10.94 mL.

The first step is to determine the moles of aluminum foil used in the reaction. We can use the molar mass of aluminum to convert the given mass to moles:

1.1798 g Al / (26.98 g/mol Al) = 0.04375 mol Al

According to the balanced chemical equation, the reaction requires 2 moles of KOH for every mole of Al. Therefore, we need:

0.04375 mol Al x (2 mol KOH / 2 mol Al) = 0.04375 mol KOH

To calculate the minimum volume of 4.00 M KOH required, we can use the equation:

Molarity x Volume = Moles

Rearranging for volume, we get:

Volume = Moles / Molarity

Plugging in the values, we get:

Volume = 0.04375 mol KOH / 4.00 M = 0.01094 L = 10.94 mL

As a result, the minimum volume of 4.00 M KOH required to complete the reaction is 10.94 mL.

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Chlorine is more reactive than bromine because it replaces both bromine and iodine.

Fluorine is the most sensitive while on the other hand, the astatine is the least reactive as compared to other elements. The chlorine displaces both bromine and iodine, and bromine displaces iodine because of its high reactivity. The element that replaces other atom is considered as more reactive.

The order of reactivity is that the chlorine is more reactive than bromine, which indicates that chlorine is more reactive than iodine.

So we can conclude that chlorine is more reactive than bromine due to high reactivity.

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Answer:

Explanation:

Standard enthalpy of combustion (ΔH∘C) is the enthalpy change when 1 mole of a substance burns under standard state conditions;

Answer:

log = ( - 0.51 z 2) / ( 1 + ( / 305)

Explanation:

Answer:

b its will shift left

c yes

Answer:

it can be removed

1. by boiling

Ca(HCO3)2 > CaCO3 + H2O +CO2

2. by treating with calcium hydroxide

Answer: Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

Answer:

Calculate the frequency of light having wavelength of 456 nm.

1.22*10^8nm

Explanation:

In the given question, \(6.58 \times 10^{14}\) Hz is the frequency of the light with a wavelength of 456 nm.

Frequency is a measure of the number of cycles of a periodic wave that occur per unit of time.

The frequency of light can be calculated using the following equation:

frequency = speed of light / wavelength

where the speed of light is a constant equal to \(\rm 3 \times 10^8 \ m/s\).

To use this equation, we need to convert the wavelength from nanometers to meters:

456 nm = \(\rm 456 \times 10^{-9}\ m\)

Now, we can substitute the values into the equation:

frequency =  \(\rm 3 \times 10^8 \ m/s\) / \(\rm 456 \times 10^{-9}\ m\)

=  \(6.58 \times 10^{14}\) Hz

Therefore, the frequency of light with a wavelength of 456 nm is  \(6.58 \times 10^{14}\) Hz.

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The solution for the arithmetic problems are​ is mathematically given as

23.27-72.058=-48.79

0.0853+0.05477+0.0002=0.14

35/0.0622=562.7

3400*0.00800=27.2

(43.1+27.250)*(22.514-18.0)​=317.56

Question Parameter(s):

23.27-72.058

0.0853+0.05477+0.0002

35/0.0622

3400*0.00800

(43.1+27.250)*(22.514-18.0)​

Generally,

23.27-72.058=-48.79

0.0853+0.05477+0.0002=0.14

35/0.0622=562.7

3400*0.00800=27.2

(43.1+27.250)*(22.514-18.0)​=317.56

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Answer:

\(\boxed {\boxed {\sf 2.76 \ mol}}\)

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

\(molarity = \frac {moles}{liters}\)

We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.

\(1.2 \ mol/liter= \frac {x}{2.3 \ liters}\)

Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.

\(2.3 \ liters *1.2 \ mol/liter= \frac {x}{2.3 \ liters}* 2.3 \ liters\\2.3 *1.2 \ mol= x\\2.76 \ mol =x\)

In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.

Answer:  Jean Baptiste de Lamarck is a famous biologist known for his theory of evolution. While he is known for his theory of inheritance of acquired characteristics, he also proposed a theory of needs to explain the evolutionary process.

According to Lamarck's theory of needs, animals have specific needs that arise due to changes in their environment. For example, if an animal lives in an area with tall trees, it may need to stretch its neck to reach the leaves for food. Over time, Lamarck believed that this need would cause the animal's neck to lengthen, and this acquired trait would be passed down to its offspring.

One example of Lamarck's theory of needs can be seen in the evolution of the giraffe. Lamarck proposed that the giraffe's long neck evolved due to a need to reach high branches for food. According to his theory, over time, the giraffe's neck lengthened as a result of this need, and this acquired trait was passed down to future generations, eventually resulting in the long-necked giraffes we see today.

However, it is important to note that Lamarck's theory of needs has been largely discredited in modern evolutionary theory, which relies on the principles of natural selection and genetic mutation to explain the process of evolution.

Explanation: i would reallyyyyyyy apreciate brainliest

Answer:

Explanation:

i dont kow

The complete ionic equation and the net ionic equation for the reaction of aqueous ammonia and aluminum nitrate is written as follows:

\(Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)\)

\(Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)\)

In an ionic equation all the ions are charges are balanced to the proper stoichiometric ratio. The states of each species have to be written in the brackets.

The reaction of aluminum nitrate and aqueous ammonia is written as follows:

\(Al(NO_{3})_{3}(aq) + 3NH_{4}OH(aq)\rightarrow Al(OH)_{3}(s) +3NH_{4}NO_{3}(aq)\)

The complete ionic equation is written below:

\(Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)\)

From this complete ionic equation the net ionic equation can be written by cancelling same species from both side as below:

\(Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)\)

Therefore, the net product aluminum hydroxide is precipitated and the net ionic equation is written as above.

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Answer:

Robert Delaunay's Homage to Blériot (1914) was inspired by the first flight across the English channel.

The  low-spin octahedral complex [Co(CN)6]¯, is known to be one that all the 6 cyanide ligands that are said to be placed in an octahedral geometry and the 6 electrons from cyanide ligands that will tend to pair up with the 6 electrons from cobalt's 3d orbitals. So no unpaired electrons is seen this complex.

The complex [Co(CN)6]¯ is one that takes in a coordination number of 6, and cyanide (CN¯) may be a solid field ligand. Thus, the complex may be a low-spin octahedral complex.

The electronic arrangement of Co(II) particle is 3d⁷.

So, Cyanide (CN¯) could be a solid field ligand, which suggests it'll cause the 3d orbitals to match up some time recently moving onto the 4d orbitals, coming about within the arrangement of a low-spin complex.

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A higher density water will be obtained in lower temperature water.

Density is the fluid property that describes the amount of solutes that dissolves in a given volume of the fluid.

Density of a fluid is calculated by taking the ratio of mass to volume of the fluid.

\(\rho = \frac{m}{v}\)

When the temperature of the water is low, more mass of the water is obtained while a high temperature evaporates the liquid.

Thus, a higher density water will be obtained in lower temperature water.

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The compound above is a cyclic (ring) compound.

Organic compounds are compounds which contains carbon and hydrogen.

Some classes of organic compounds include the following:

So therefore, the compound above is a cyclic (ring) compound.

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ANSWER

99 grams of bromine gas will give us 27.75L

STEP-BY-STEP EXPLANATION:

What to find? Volume of bromine

Given parameters

• The mass of bromine = 99 grams

• Molar mass of bromine = 79.904 g/mol

Firstly, we need to find the mole of bromine

Note that, 1 mole = 22.4L at STP

Hence, 99 grams of bromine gas will give us 27.75L

Answer:

CO2 AND H20 I THINK IM 99 PERCENT SURE

According to the claim, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303. (orange is 1.303 times more effused than blue).Relative rate of effusion for the orange to blue spheres = 1.531.

The process of effusion is when a gas escapes from a container through a hole that is significantly smaller in diameter than the molecules' mean free path.

Gas molecules flow through a small opening in one container and into another by effusion. Graham's law allows rates of effusion to be compared at the same temperature. Diffusion is the random molecular motion-based movement of gas molecules through one or more other types of gas.

Rate of effusion of Orange / Rate of effusion of blue

= [Mblue / Morange]^1/2

Vrms = sqrt [(3RT/M)]

Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue

= 565/ 369

= 1.531

Thus,  Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303.

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The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group

Answer & Explanation:

The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.

Answer:

The first image = double replacement

Second = single replacement

Third = Decomposition

Fourth = Combination

Explanation:

1. a color from each pair is being swapped and replacing each other so there is a double replacement

2. only the blue and the red are changing places so it is single replacement

3. the pair is being separated (decomposed)

4. the red and green are coming together (combined)

Answer:

Brass is an alloy, and either a "solid solution".

Alloys in general may be solid solutions or they simply be mixtures

Explanation:

The volume of methanol is 54.72 ml, m/m% of solution is 29% and mass of NaCl present is 73.76g

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

1. v/v% = 17.1 %

This means that 17.1 ml of methanol is present in 100 ml of water.

so, 320 ml of water has 0.171 × 320 = 54.72 ml

2. Mass of NaCl = 8.5 lbs

Mass of water = 29.3 lbs

mass of NaCl in 1 lbs = 8.5 / 29.3 = 0.29 lbs

m/m% = 29%

3. Volume of NaCl = 194 ml

Concentration of NaCl = 6.5 M

Moles of NaCl = 0.194 × 6.5 = 1.261 moles

Mass of NaCl = 1.261 × 58.5 = 73.76g

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Answer:

The pressure in mmHg is 59.

Explanation:

Given data:

Pressure of air inside balloon = 0.78 atm

Pressure in mmHg = ?

Solution:

mmHg:

mmHg is referred as manometric unit of pressure. It is define as the pressure exerted by mercury column at height of one millimeter.

Symbol:

"mmHg"

Atmosphere (atm)

atm is unit of pressure. It is used as a standard unit. It is equal to the 101325 Pa.

1 atm = 760 mmHg

Inorder to convert the atm into mmHg we will multiply the given atm value with 760.

0.78 atm × 760 mmHg / 1 atm = 592.8 mmHg

59 mmHg or 59

Answer: During diffusion, molecules flow down their concentration gradient.

Explanation:

They're flowing from an area of high concentration to an area of low concentration. Molecules flowing down a concentration gradient is a natural process and does not require energy.

The empirical formula of the compound is C₂H₁₆S₂N₃O.

The moles of each element is as follows::

For CO₂:

Carbon (C) has a molar mass of 12.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of C in CO₂ = 2.08 g / 12.01 g/mol = 0.173 moles

Moles of O in CO₂ = 2.08 g / 16.00 g/mol = 0.130 moles

For H₂O:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in H₂O = 1.28 g / 1.01 g/mol = 1.27 moles

Moles of O in H₂O = 1.28 g / 16.00 g/mol = 0.080 moles

For SO₃:

Sulfur (S) has a molar mass of 32.06 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of S in SO₃ = 4.77 g / 32.06 g/mol = 0.149 moles

Moles of O in SO₃ = 4.77 g / 16.00 g/mol = 0.298 moles

For HNO₃:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Nitrogen (N) has a molar mass of 14.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in HNO₃ = 3.48 g / 1.01 g/mol = 3.45 moles

Moles of N in HNO₃ = 3.48 g / 14.01 g/mol = 0.248 moles

Moles of O in HNO₃ = 3.48 g / 16.00 g/mol = 0.217 moles

The simplest whole-number ratio of the elements will be:

Carbon: 0.173 moles / 0.080 moles ≈ 2.16

Hydrogen: 1.27 moles / 0.080 moles ≈ 15.88

Sulfur: 0.149 moles / 0.080 moles ≈ 1.86

Nitrogen: 0.248 moles / 0.080 moles ≈ 3.10

Oxygen: 0.080 moles / 0.080 moles = 1

Therefore, the empirical formula is C₂H₁₆S₂N₃O.

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