when a transition metal atom formas an ion which electrons are lost first

Answer:

To indicate short quotations (four typed lines or fewer of prose or three lines of verse) in your text, enclose the quotation within double quotation marks.

Answer: about 29.4 Earth years

Orbit and Rotation

One day on Saturn takes only 10.7 hours (the time it takes for Saturn to rotate or spin around once), and Saturn makes a complete orbit around the Sun (a year in Saturnian time) in about 29.4 Earth years (10,756 Earth days).

Answer:

v_kyle = 0.5 m/s

v_jennies = 0.333 m/s

Kyle's Rabbit was the fastest

Explanation:

For the velocity of Kyle's Rabbit:

d = distance covered = 40 m

t = time taken = (1 min)(60s/1 min) + 20 s = 80 s

\(v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}\)

v_kyle = 0.5 m/s

For the velocity of Jennies Rabbit:

d = distance covered = 30 m

t = time taken = (1 min)(60s/1 min) + 30 s = 90 s

\(v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}\)

v_jennies = 0.333 m/s

It is clear from the results that:

Kyle's Rabbit was the fastest

The speed of sound is typically measured in units of distance per time, such as meters per second or feet per second, rather than miles per hour (mph).

In physics, speed is the measure of how fast an object is moving. It is defined as the distance traveled per unit time, usually expressed in meters per second (m/s) or kilometers per hour (km/h). Speed can be calculated by dividing the distance traveled by the time it takes to travel that distance. For example, if a car travels 60 kilometers in one hour, its speed is 60 kilometers per hour (60 km/h). Speed can be further classified into different types based on the direction of motion or the changes in speed over time. For instance, if the speed of an object remains constant over time, it is called constant speed. If the speed of an object changes over time, it is called acceleration. The rate of change of speed is called the acceleration of an object. Speed is an important concept in many fields of science, including physics, engineering, and astronomy. It plays a crucial role in describing the motion of objects and helps in predicting and understanding the behavior of physical systems.

Here,

The speed of sound varies depending on the medium through which it travels, such as air, water, or solids, as well as the temperature and humidity of the medium.

At sea level and a temperature of 68°F (20°C), the speed of sound in dry air is approximately 1,125 feet per second (343 meters per second) or about 768 miles per hour (1,236 kilometers per hour). However, this speed can vary by several hundred feet per second depending on the exact conditions.

It's important to note that the speed of sound is not a constant value and can vary depending on the conditions. Additionally, the term "mph" is typically used to measure the speed of objects in relation to the ground, rather than the speed of sound in a medium.

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Answer:

Explanation:

The frequency equation is

\(f=\frac{v}{\lambda}\) where f is frequency measured in Hz, v is velocity of sound measured in m/s and \(\lambda\) is wavelength measured in meters. Filling in our given info:

\(512=\frac{340}{\lambda}\) and

\(\lambda=\frac{340}{512}\) so

\(\lambda=.664 m\) (That is the incorrect number of sig dig's by the way. It should only be 2 since the number 340 only has 2 sig dig's)

The parallax of stars, as viewed from the orbit of Jupiter, would be about twenty five times larger, since Jupiter's orbit around the Sun is about five times larger than that of Earth.

Parallax distances would be easier to measure from Jupiter's orbit—for the same accuracy, one could measure distances about twenty five times farther than we can from Earth.

Parallax distance is the measuring of how nearby object appears to move against the background of more distant objects.

The principle of parallax., is used by astronomers to measure large distances, such as the distance of a planet or a star from Earth.

The term parallax is the semi-angle of inclination between two sight-lines to the star, as observed when Earth is on opposite sides of the Sun in its orbit.

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The density of the lead will be equal to 11.3 gram per centimeter cube such that the volume of the bottle remains the same in all the cases.

Density of a material is defined as mass per volume that means how many grams are confined in a certain amount of volume density depending on temperature and changes with temperature.

Volume is a measure of occupied three-dimensional space. It is often quantified numerically using SI derived units or by various imperial units. The definition of length is interrelated with volume.

Given:

Mass of relative density bottle = 25.8g.

Mass of relative density bottle with lead shots only = 69.3 u

Mass of relative density bottle filled with water = 75.8g

Mass of relative density of bottle filled with lead and water =115.1g

Using the relationship between mass , density and volume

i.e. mass = density × volume

25.8 = 115.1× volume

volume = 0.27 u

Using the mass density equation for the volume we get,

Volume of the bottle with the lead=69.3/0.27 Volume of the bottle with the lead =260 u

Finally the density of the lead = \(\frac{260 \times 10}{69.3 + 115}\)

Finally the density of the lead = 11.3 u

Therefore, The density of the lead will be equal to 11.3 gram per centimeter cube such that the volume of the bottle remains the same in all the cases.

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Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

\(Ro = m/V\)

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

\(V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]\)

And the mass m = 4 [gramm] = 0.004 [kg]

\(Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]\)

The period of oscillation is dependent on the square root of the ratio of the mass (m) and the spring constant (k).

Since m and k are unchanged, doubling the amplitude of oscillation will not affect the period. Therefore, the period remains the same. Expressing this answer to two significant figures, the period is equal to the original period with appropriate units.
When the oscillation amplitude is doubled while mass (m) and spring constant (k) are unchanged, we first need to understand the relationship between period, amplitude, mass, and spring constant.

The period (T) of an oscillation is determined by the formula T = 2π√(m/k), where m is the mass and k is the spring constant. Amplitude, on the other hand, is the maximum displacement of the oscillating object from its equilibrium position. Notice that amplitude is not present in the formula for the period.
Thus, when the amplitude is doubled, it does not affect the period of oscillation. The period remains the same, as it depends only on the mass and spring constant. To express your answer to two significant figures, we would need the numerical values of mass and spring constant. However, since these values are not provided, we cannot calculate the exact period value in this case.
In conclusion, the period remains unchanged when the oscillation amplitude is doubled while m and k are unchanged.

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A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.

In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

Therefore, A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

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Answer:

2.5 kg

Explanation:

Answer:

c

Explanation:

would be the BEST way to add about 30 percent more aerobic activity to her week, She is interested in losing a little weight, so she would like higher than average aerobic activity, 250 minutes of moderate activity weekly would be the BEST way to add about 30 percent more aerobic activity to her week

Weight can be defined as the force at which the gravitational field pulls the object towards the earth’s surface which is the center of gravity which has a specific force attracts objects towards it.

The SI unit of weight of kg/mt/sq sq. is  Newton (N),

W = 1 kg (mass) X 1 mtr/sec sq (force of gravity), Unit of Weight is calculated as the product of mass, distance, and time.

Dimensional Unit of weight (W) = Mass (M) X Distance (L) X Time (t sq) CGS unit of Weight is represented as Dyne,  in terms of the product of centimeter gram and seconds.

The Basic Unit of Weight has the same value as that of the SI unit of weight and other units of weights also used includes gram, slug, pound-force, etc.

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Answer: loss of hair cells

Explanation:

The hair cells in the ear canal create the essential vibrations needed for both the ear and brain to process the sound, without them, vibrations cannot be fully developed.

Answer: Loss of hair cells

Explanation: I got it right on the quiz

The fundamental resonance frequency of a 1 m long tube open at both ends is 172 Hz. If the tube has one end open and the other end closed the fundamental resonance frequency is 86 Hz.

There are two kind of tube, there are  a tube that opens at both ends and a tube that one end open and the other end closed. In problems didn't gave the information what kind of tube.

The formula for a tube that opens at both ends

\(f_n = \frac{nv}{2L}\)

\(f_1 = \frac{1 \times 344}{2 \times 1}\)

\(f_1 = \frac{344}{2}\)

f₁ = 172 Hz

The formula for a tube that one end open and the other end closed

\(f_n = \frac{(2n - 1) \: v}{4L}\)

\(f_1 = \frac{1 \times 344}{4 \times 1}\)

\(f_1 = \frac{344}{4}\)

f₁ = 86 Hz

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a) The velocity function v(t) is given by v(t) = -100 + 10t, b) The acceleration function a(t) is given by a(t) = 10, c) The velocity is v(3) = -70 fps, and the acceleration is a(3) = 10 feet per second squared.

a) To find the velocity function, we take the derivative of the distance function s(t) with respect to time t. The derivative of s(t) = 80 - 100t + 5t^2 is v(t) = s'(t) = -100 + 10t. The units of velocity are feet per second.

b) The acceleration function is obtained by taking the derivative of the velocity function v(t). Since v(t) = -100 + 10t, the derivative of v(t) is a(t) = s"(t) = 10. The units of acceleration are feet per second squared.

c) To find the velocity and acceleration when t = 3 seconds, we substitute t = 3 into the respective functions. For velocity, v(3) = -100 + 10(3) = -70 feet per second. For acceleration, a(3) = 10 feet per second squared.

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The Earth's atmosphere is divided into several layers, each with different characteristics that affect the types of wavelengths that are reflected, absorbed, or allowed to pass through to Earth's surface.

The first layer closest to Earth's surface is the troposphere, which contains most of the Earth's weather. This layer is characterized by decreasing temperature with altitude and contains water vapor, carbon dioxide, and other greenhouse gases. These gases absorb and re-emit certain wavelengths of radiation, such as infrared radiation, which are trapped within the atmosphere, leading to the greenhouse effect. This helps to keep the Earth warm, but too much of this effect can lead to global warming and climate change.

The next layer is the stratosphere, which contains the ozone layer. Ozone absorbs harmful ultraviolet radiation from the sun, preventing it from reaching the Earth's surface. This layer allows visible light and some infrared radiation to pass through.

Above the stratosphere is the mesosphere, where most meteoroids burn up upon entering the Earth's atmosphere. This layer absorbs most of the incoming radiation and reflects some of it back into space.

Finally, the thermosphere is the outermost layer of the Earth's atmosphere, where the temperature increases with altitude due to the absorption of high-energy solar radiation. The ionosphere, a sub-layer of the thermosphere, contains ions and free electrons that can reflect and scatter radio waves, making long-range communication possible.

Overall, the characteristics of each atmospheric layer affect the types of wavelengths that are reflected, absorbed, or allowed to pass through to the Earth's surface. The amount of radiation absorbed or reflected by each layer can also affect the Earth's climate and weather patterns.

Answer:D

Explanation:

The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

The correct answer to the magnesium nominal corrosion potential is option B, which is -1.05V. The corrosion potential is a measure of the relative tendency of a metal to corrode in a given environment. It is the voltage difference between a metal and a reference electrode, and it provides information on the metal's susceptibility to corrosion.

The Magnesium is a reactive metal that is commonly used in various industries due to its lightweight and high strength-to-weight ratio. However, it is also prone to corrosion in many environments, especially in the presence of water and salt. Understanding the magnesium nominal corrosion potential is crucial in designing and selecting materials for different applications. The magnesium nominal corrosion potential is affected by many factors, including the chemical composition of the environment, temperature, and ph. Therefore, it is essential to consider these factors when selecting a suitable material for a particular application. In conclusion, the magnesium nominal corrosion potential is an important parameter that provides information on the metal's susceptibility to corrosion. The correct answer to the question of the magnesium nominal corrosion potential is -1.05V, which is option B. Understanding this parameter is crucial in selecting and designing materials for different applications and in implementing proper maintenance and protection strategies.

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Answer:

A

Explanation:

The length of the spring when a 200 g mass is hung will be 410 cm.

To determine the new length of the spring when a 200 g mass is hung instead of a 100 g mass, we can use Hooke's Law , which states that the elongation of a spring is directly proportional to the applied force.

Let's denote the initial length of the spring as L1 (10 cm) and the final length when the 100 g mass is hung as L2 (12 cm). We can calculate the spring constant (k) using the formula:

k = (m * g) / ΔL

where m is the mass (in kg), g is the acceleration due to gravity (approximately 9.8 m/s²), and ΔL is the change in length.

For the 100 g mass:

k = (0.1 kg * 9.8 m/s²) / (0.12 m - 0.1 m) = 0.49 kg/s²

Now, we can use the spring constant to find the new length (L3) when a 200 g mass is hung:

L3 = L1 + (m * g) / k

= 10 cm + (0.2 kg * 9.8 m/s²) / (0.49 kg/s²)

= 10 cm + 4 m

= 410 cm

Therefore, the length of the spring when a 200 g mass is hung will be 410 cm.

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Answer:

10 million joules or 10,000 KJ

Explanation:

Work= Force x Displacement

convert 5km into meters -5km=5000m

W= 2000N x 5000m

w=10,000,000 Joules

or 10,000KJ

Answer:

hertz

Explanation: play piano

Heat energy is also called thermal energy.

Answer:

constant speed

Explanation:

this is because it does not increase nor decrease

The fraction of light from the Sun intercepted and reflected by the Earth is approximately 4.26 x 10⁻⁵.

To calculate the fraction of light from the Sun intercepted and reflected by the Earth, we need to compare the cross-section of the Earth to the area of a sphere centered on the Sun with a radius equal to the radius of Earth's orbit.

The cross-section of the Earth can be calculated as the area of a circle with radius REarth, which is option (c) R Earth.

The area of a sphere centered on the Sun with a radius r is given by 4πr², where r is the radius of the Earth's orbit. Therefore, the area of the sphere centered on the Sun with a radius equal to the radius of Earth's orbit is 4π(149.6 x 10⁶ km)²= 2.83 x 10²³ m².

The ratio of the cross-section of the Earth to the area of the sphere is A1/A2 = πREarth² / 4πr² = (REarth/r)². Using the radius of Earth's orbit in meters, r = 149.6 x 10⁹ m, and the radius of Earth, REarth = 6,371 km = 6.371 x 10⁶ m, we get A1/A2 = (6.371 x 10⁶ m / 149.6 x 10⁹ m)² = 4.26 x 10⁻⁵.

Therefore, by calculating we can say that the fraction of light is approximately 4.26 x 10⁻⁵.

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