when passing another motorist, always remember the following: a.) if both centerlines are solid, no passing is allowed. b.) if one centerline is broken, passing is allowed, but only on the side with the broken line. c.) if both centerlines are broken, passing is allowed on both sides. d.) all of the above

Given input x(t) = 2cos(3t) − 5sin(1000t) The transfer function of a plant G(s) is given as G(s) = (s+2)/(s^2+6s+10).

First, let's solve for the Laplace transform of x(t)Laplace transform of cos(3t) is s / (s^2 + 9)

Laplace transform of sin(1000t) is 1000 / (s^2 + 1000^2) Laplace transform of

x(t) = 2cos(3t) − 5sin(1000t)

is given by

L{2cos(3t) − 5sin(1000t)} = 2L{cos(3t)} - 5L{sin(1000t)}= 2s / (s^2 + 9) - 5(1000 / (s^2 + 1000^2))

Laplace transform of y(t) is given by

Y(s) = G(s)X(s)Where X(s) and Y(s) are the Laplace transform of x(t) and y(t) respectively,

G(s) is the transfer function of a plant.

From the above equation, we can infer the output y(t) of the plant G(s) as follows:

Y(s) = (s+2)/(s^2+6s+10) * (2s / (s^2 + 9) - 5(1000 / (s^2 + 1000^2)))

Multiplying across the numerator and denominator, we obtain:

Y(s) = (2s + 4) / (s^3 + 6s^2 + 10s) - (5000s) / (s^3 + 6s^2 + 10s) - (10000s) / (s^3 + 6s^2 + 10s) = (2s + 4 - 5000s - 10000s) / (s^3 + 6s^2 + 10s) = (-15000s + 4) / (s^3 + 6s^2 + 10s)

Finally, applying inverse Laplace transform on the above equation, we get:

y(t) = L^-1{(−15000s + 4) / (s^3 + 6s^2 + 10s)}

We know that, L^-1{1/(s-a)} = e^at and L^-1{1/(s^2+a^2)} = sin(at) / a

Taking inverse Laplace transform, we get:

y(t) = -2/3 e^-3t + 20/√(999998) sin(999√2t + θ) + 2/3 e^-t sin(t√3)

where θ = arctan(-1000√2/3)T

hus, the output y(t) of the plant G(s), given an input equal to:

x(t) = 2cos(3t) − 5sin(1000t) is:y(t) = -2/3 e^-3t + 20/√(999998) sin(999√2t + θ) + 2/3 e^-t sin(t√3)

where θ = arctan(-1000√2/3).

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The Venn diagram to illustrate the intersections and unions of the events A, B, and C are (a) S = {M1F1, M1F2, M2F1, M2F2},(b) A = {M1F1, M2F1},(c) B = {M1F1, M2F2, M1F2}.

Illustration is the art of creating visual images to represent a concept, idea, or message. It is often used in books, magazines, advertisements, educational materials, and more to help convey a particular message or thought. Illustrations can be created using a range of mediums, from traditional drawings and paintings to digital media such as photography, vector art, and 3D art. Illustration is an important form of communication because it helps to bring an idea to life in a unique and creative way. It can help to engage readers and viewers and provide a more vivid and memorable experience than words alone.

(d) C = {M2F2, M2F1}

(e) A ∩ B = {M1F1}

(f) A U C = {M1F1, M1F2, M2F1, M2F2}

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yes it will

Explanation:

\(V_{F}\) (Volume Fraction) will be 0.14436 and Tensile strength weill be 620.222 MPa.

What is Tensile strength?

Tensile strength is a material's ability to withstand a pulling (tensile) force and refers to a material's breaking strength when a force capable of breaking many strands of the material simultaneously is applied at a constant rate of extension/load. It is typically expressed in units of force per cross-sectional area.

Tensile strength is the amount of load or stress that a material can withstand before stretching and breaking. Tensile strength, as the name implies, is a material's resistance to tension caused by mechanical loads applied to the material. One of the most important and widely measured properties of structural materials is their ability to resist breaking under tensile stress.

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Answer:

Feed Forward

Explanation:

In FEED FORWARD compression design the signal is split at the input, and one signal is used to compress the other slightly delayed split signal.

I hope it helps! Have a great day!

A project that requires using a pleater, a ruffling foot, or a gathering foot is the creation of a dress.

A pleater, a ruffling foot, and a gathering foot are all accessories for sewing machines or machines themselves that help fashion designers to give the fabric a different shape or texture, and therefore create unique pieces.

All of the tools can be used in the creation of a dress, for example, a pleater can be used in the top section of the dress to give it a nice texture and make it different from the skirt. In the same way, others such as the ruffling foot or the gathering foot can be used in the sleeves of the dress.

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Answer:

Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang

Answer:

  SPL is best represented using a logarithmic scale

Explanation:

Microbars would be a linear scale. deciBels is a logarithmic scale, so is able to express a wide range of sound pressures more easily.

Answer:

The City can grant higher budgets to emergency services like the Fire Department, so a higher budget will allow engineers & scientists to innovate new technology and add more fire stations across the city.

Explanation:

Answer:

They moved fresh water around their vast empire with aqueducts and canals.

Explanation:

Answer:

how will i draw diagram

Explanation:

Answer:

At eutectic there are 3phases present.

Explanation:

In three-phase motors, each phase is 120 degrees out of phase symmetrical with the other phases. Three-phase motors are a type of electric motor that employs three-phase electrical power.

The voltage of each phase is shifted by 120 degrees or one-third of a cycle from that of the other phases. The current in each phase is also shifted by one-third of a cycle from that of the other phases. This arrangement allows for a smooth, steady flow of power to the motor, resulting in less vibration and noise than single-phase motors. Three-phase power is used in a variety of industrial and commercial applications, including pumps, compressors, fans, and conveyor belts. In addition, three-phase motors are used in appliances such as washing machines, refrigerators, and air conditioners. Three-phase motors are typically more efficient and reliable than single-phase motors. They are also more expensive and require more complex wiring. However, the benefits of three-phase power make it a popular choice for high-power applications.

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Answer:

\(N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb\)

Explanation:

Na and Nb are the vertical reactions on each of the two legs at A and at B

For the horizontal forces:

\(Fcos(30)-0.5N_a-0.5N_b=0\\0.5N_a+0.5N_b= Fcos(30)\\N_a+N_b= 2Fcos(30)\)

For the vertical forces:

\(N_a+N_b-Fsin(30)-75=0\\N_a+N_b=Fsin(30)+80\)

Therefore equating both equations:

\(2Fcos(30)=Fsin(30)+80\\F(2cos(30)-sin(30))=80\\F=\frac{80}{2cos(30)-sin(30)} =64.93N\)

After the desk star to slide:

sum of all vertical force = ma , therefore:

\(N_a+N_b-64.93sin(30)-80=0\\N_a+N_b=64.93sin(30)+80\)

sum of all horizontal force = ma

\(64.93cos(30)-0.2N_a-0.2N_b=\frac{80lb}{32.2ft/s^2}a\\ 0.2(N_a+N_b)=64.93cos(30)-\frac{80lb}{32.2ft/s^2}a\\N_a+N_b=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}a}{0.2}=324.65-12.42a\)

equating both equations:

\(324.65-12.42a=64.93sin(30)+80\\12.42a=324.65-64.93sin(30)-80\\12.42a=212.185\\a=17.08ft/s^2\)

From the moment equation:

\(4N_b-80(2)-64.93(3)=\frac{-80}{32.2} (17.08)(2)\\N_b=67.48lb\)

\(N_a=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}(17.08)}{0.2}-67.48 = 45.04lb\)

For each leg: \(N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb\)

Answer:

a.) I = 7.8 × 10^-4 A

b.) V(20) = 9.3 × 10^-43 V

Explanation:

Given that the

R1 = 20 kΩ,

R2 = 12 kΩ,

C = 10 µ F, and

ε = 25 V.

R1 and R2 are in series with each other.

Let us first find the equivalent resistance R

R = R1 + R2

R = 20 + 12 = 32 kΩ

At t = 0, V = 25v

From ohms law, V = IR

Make current I the subject of formula

I = V/R

I = 25/32 × 10^3

I = 7.8 × 10^-4 A

b.) The voltage across R1 after a long time can be achieved by using the formula

V(t) = Voe^- (t/RC)

V(t) = 25e^- t/20000 × 10×10^-6

V(t) = 25e^- t/0.2

After a very long time. Let assume t = 20s. Then

V(20) = 25e^- 20/0.2

V(20) = 25e^-100

V(20) = 25 × 3.72 × 10^-44

V(20) = 9.3 × 10^-43 V

\(\boxed{ℒ_t[f(t)] =\frac{30}{{s}^{4} } - \frac{9}{s} + \frac{6}{s + 5} + \frac{1}{s - 3}} \)

This holds true because:

\(\lim_{s\to\infty} [\frac{30}{{s}^{4} } - \frac{9}{s} + \frac{6}{s + 5} + \frac{1}{s - 3}] =0 \)

[The answer is throughly verified, hence you can trust this :)]

Rigid schedule 80 pvc shall have a minimum burial depth of 18 inches.

Rigid schedule 80 PVC is a type of polyvinyl chloride pipe commonly used in various applications, including underground installations. The minimum burial depth refers to the depth at which the pipe should be buried to ensure proper protection and structural integrity.

The required minimum burial depth for rigid schedule 80 PVC is determined by factors such as the type of soil, traffic loads, and environmental conditions. It is essential to follow local building codes and regulations, as they may specify specific requirements for burial depths. Generally, the recommended minimum burial depth for rigid schedule 80 PVC ranges from 18 to 24 inches.

Proper burial depth helps protect the PVC pipe from external stresses, such as vehicle traffic or ground movement. It also safeguards the pipe from potential damage caused by temperature fluctuations or exposure to sunlight. By burying the pipe at the appropriate depth, the risk of accidental damage and potential leaks or breaks is significantly reduced.

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Answer:

(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ

Explanation:

Solution

Recall that:

A 10 gr of air is compressed isentropically

The initial air is at = 27 °C, 110 kPa

After compression air is at = a450 °C

For air,  R=287 J/kg.K

cv = 716.5 J/kg.K

y = 1.4

Now,

(a) W efind the pressure on [MPa]

Thus,

T₂/T₁ = (p₂/p₁)^r-1/r

=(450 + 273)/27 + 273) =

=(p₂/110) ^0.4/1.4

p₂ becomes  2390.3 kPa

So, p₂ = 2.39 MPa

(b) For the increase in total internal energy, is given below:

ΔU = mCv (T₂ - T₁)

=(10/100) (716.5) (450 -27)

ΔU =3030 J

ΔU =3.03 kJ

(c) The next step is to find the total work needed in kJ

ΔW = mR ( (T₂ - T₁) / k- 1

(10/100) (287) (450 -27)/1.4 -1

ΔW = 3035 J

Hence, the total work required is = 3.035 kJ

Answer:

Technician B is correct.

Explanation:

Answer:

C - oil filters.

Explanation:

You must crush or drain oil filters for a minimum of 12 hours for recycling because used motor oil is hazardous waste and can affect the environment if disposed of properly so the government has created strict rules for proper disposal.

When a wye-delta transformer bank is fully loaded, the line current on the primary side is equal to the phase current. the line current at full-load on the primary side of a wye-delta transformer bank can be calculated by dividing the total rated VA of the transformer bank by the square root of 3 times the rated primary voltage.

On the other hand, the line current on the secondary side is equal to the phase current multiplied by the square root of 3. Therefore, the line current (rms value) at full-load on the secondary side of a wye-delta transformer bank can be calculated by dividing the total rated VA of the transformer bank by the rated secondary voltage multiplied by the square root of 3.To determine the line current (rms value) at full-load on both the primary and secondary sides of a wye-delta connected transformer bank, you'll need to know the transformer's power rating and voltage levels on both sides. Keep in mind that the primary and secondary currents will differ depending on the transformer's voltage ratio.

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Answer:The two-second rule is a rule of thumb by which a driver may maintain a safe trailing distance at any speed. The rule is that a driver should ideally stay at least two seconds behind any vehicle that is directly in front of his or her vehicle.

Explanation:

Answer:

do u speak english

Explanation:

The statement that is not true of ISO 9000 is b. The American National Standards Institute guarantees continued ISO 9000 certification for all the ISO-certified American companies. Here's why:  ISO 9000 is a set of international standards for quality management and quality assurance.

It is designed to help companies achieve consistency in their products and services while also improving customer satisfaction. ISO 9000 is a five-part series of standards that includes ISO 9001, ISO 9002, ISO 9003, ISO 9004, and ISO 19011.

The ISO 9000 certification process involves an accredited third-party certification body reviewing a company's quality management system to ensure that it meets the requirements of the ISO 9001 standard. Once a company has been certified, the certification body will issue an ISO 9000 certificate that the company can use in its advertising and publications.

Continued ISO 9000 certification is not guaranteed. To maintain certification, a company must undergo regular surveillance audits to ensure that its quality management system continues to meet the requirements of the ISO 9001 standard. If a company fails to meet these requirements, it can lose its certification.

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Answer:

The answer is "evaluating outcomes ".

Explanation:

The assessment of the results shows that maybe a program has achieved its goals. The assessment with results measures the results of the program and decides whether intended results were achieved. Its results allow you to achieve people by the measurable changes made through participating in your project by students enrolled. It is a form of assessment that examines if changes occur for students enrolled or if these adjustments are related to a program.

Answer:

A

Explanation:

Primary radial system

In a lever system, the effort required to lift a load can be calculated using the principle of torque. The effort needed to lift the load on the lever is 275 Newtons.

Torque is the product of force and the perpendicular distance from the force to the pivot point. In this case, the effort arm of the lever is 10 meters long, and the resistance arm is 5.5 meters long.

To calculate the effort needed, we can use the equation:

Effort × Effort Arm = Load × Load Arm

Let's substitute the given values into the equation:

Effort × 10 = 50 × 5.5

Simplifying the equation, we have:

Effort × 10 = 275

Dividing both sides of the equation by 10, we find:

Effort = 275/10 = 27.5 Newtons

Therefore, the effort needed to lift the load on the lever is 275 Newtons.

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To determine the velocity of piston C, we need to use the concept of instantaneous center of zero velocity.

At the instant shown, point B is the instantaneous center of zero velocity for the connecting rod BC. Therefore, the velocity of point C is perpendicular to line BC and passes through point B.

Let's draw a diagram to better visualize the problem:

     A (50mm)

     o

      \

       \

        \

         o B (-175mm)

           \

            \

             \

              o C (50mm)

From the given information, we know that the angular velocity of crank AB is 2000 RPM. Let's convert this to radians per second:

2000 RPM * (2π radians/revolution) * (1/60 seconds/minute) = 209.44 radians/second

The velocity of point B is equal to the velocity of point A, which is perpendicular to line AB and passes through point A. The velocity of point A can be calculated as:

VA = ω * rA

where ω is the angular velocity in radians per second and rA is the distance from point A to the center of rotation (which is point O in this case). Since rA = 50mm, we have:

VA = 209.44 radians/second * 0.05 meters = 10.47 meters/second

The velocity of point C can be calculated as:

VC = VB + BC

where VB is the velocity of point B and BC is the velocity of point C relative to point B. Since point B is the instantaneous center of zero velocity, we know that the velocity of point B is zero. Therefore:

VB = 0

To calculate the velocity of point C relative to point B, we can use the formula:

BC = rBC * ωBC

where rBC is the length of the connecting rod BC and ωBC is the angular velocity of BC relative to AB. Let's first calculate the length of BC using the Pythagorean theorem:

BC^2 = AB^2 + AC^2 - 2 * AB * AC * cos(θ)

where θ is the angle between AB and AC. From the diagram, we can see that θ is equal to:

θ = 180° - φ

where φ is the angle between AB and the horizontal axis. Since AB is horizontal, we have:

θ = 180° - (-90°) = 270°

Using the law of cosines, we can calculate the length of BC as:

BC^2 = 175^2 + 50^2 - 2 * 175 * 50 * cos(270°) = 32725

BC = sqrt(32725) = 181.05 mm

To calculate ωBC, we can use the formula:

ωBC = (ωAB * sin(θ)) / sin(φ)

where ωAB is the angular velocity of AB and φ is the angle between AB and the line passing through points A and B. From the diagram, we can see that φ is equal to:

φ = 180° - θ

φ = 180° - 270° = 90°

Therefore:

ωBC = (209.44 radians/second * sin(270°)) / sin(90°) = -209.44 radians/second

(Note that the negative sign indicates that BC is rotating in the opposite direction to AB.)

Now we can calculate the velocity of point C as:

VC = VB + BC = 0 + 181.05 mm * (-209.44 radians/second) = -37.94 meters/second

Therefore, the velocity of piston C at the instant shown is -37

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Answer:

C. Signal-to-quantization-noise ratio

Explanation: