Where is the north pole of the bar magnet, based on the magnetic field lines
shown?

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

solution

Explanation:

solvent +solute =solution

Answer:

Al2o3 is 101

(nh4)2O IS 52

S8 is 256.56

Ba(oh)2 is 171.35

Cacl2 is 110.98

H2O is 18.01

Explanation:

The diagram shows a picture of a compound.

A compound is a substance that is made up of two or more different elements that are chemically bonded together in a specific ratio.

This means that the elements are combined in a way that creates a new substance with different physical and chemical properties than the individual elements.

Compounds can be formed through a variety of chemical reactions, such as combining elements through a chemical bond or through a reaction between an acid and a base.

So for the given diagram, we can see that it represents two or more elements chemically combined.

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The thinner and denser layer labelled "2" in the diagram represents the marine crust, while the thicker and less dense layer labelled "1" represents the continental crust. Therefore, A. 1; 2 is the right response.

The land on Earth is made up of the continental crust, which is less dense, thicker (between 35 and 70 km), and primarily composed of the rock granite. The majority of the ocean is made up of oceanic crust, which is denser, thinner (5–7 km), and primarily composed of the rock basalt.

With a density of around 2.7 grammes per cubic cm, continental crust has a largely granitic composition and is slightly lighter than Oceanic crust has a density of roughly 2.9 to 3 grammes per cubic centimetre and is composed of basalt, which is richer in iron and magnesium than granite.

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Answer: The equation of the dissociation of the solution is given below:NaCH3COO -----> CH3COO- + Na+HA -----> A- + H+Using the equation of dissociation constant, Ka:Ka = [A-][H+]/[HA][H] = [A-][H+] = 10^-(pH)[H+] = 10^-9.44[H+] = 3.63 × 10^-10 MThus, [A-] = 3.63 × 10^-10 M[HA] = [A-][H+]/Ka[HA] = (3.63 × 10^-10 M)^2 / 1.8 × 10^-5[HA] = 7.32 × 10^-15 M

Therefore, the molarity of the sodium acetate (NaCH3COO) solution is 7.32 × 10^-15 M.

Explanation:

The value of ΔG at 25 °C for the given reaction is: ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol So, the correct answer is -370.4 kJ/mol

To determine the value of ΔG (Gibbs free energy) at 25 °C for the given reaction:

25 (s, rhombic) + 3/2 \(O_2\)(g) → \(2SO_3\)(g)

We can use the equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG is the standard Gibbs free energy change

ΔG° is the standard Gibbs free energy change under standard conditions

R is the gas constant (8.314 J/(mol·K) or 0.008314 kJ/(mol·K))

T is the temperature in Kelvin (25 °C = 298 K)

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants at a given point during the reaction.

Given that ΔG° is -370.4 kJ/mol, we can plug the values into the equation:

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(Q)

Now, we need to determine the value of Q. Since all reactants and products are in their standard states, Q = 1, as their concentrations are taken to be 1.

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(1)

Since ln(1) = 0, the term (0.008314 kJ/(mol·K) * 298 K) * ln(1) becomes 0.

Therefore, the value of ΔG at 25 °C for the given reaction is:

ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol

So, the correct answer is -370.4 kJ/mol.

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Answer:

three half-filled orbitals

Answer:

6p

Explanation:

It can hold a total of 6

The methyl orange indicator will change from red to yellow at the titration's endpoint.

An acid-base indicator called methyl orange changes color between the pH ranges of 3.1 and 4.4. In acidic and basic solutions it is red and yellow, respectively

In this instance, an acid, hydrochloric acid, is being used to titrate the barium hydroxide solution. The pH of the solution will fall as we add the acid since it will neutralize the base. The hue of the methyl orange indicator will vary when the pH ranges from 3.1 to 4.4

All of the barium hydroxide will have interacted with the hydrochloric acid by the time the titration is complete leaving a neutral solution. When the methyl orange indicator becomes yellow the solution's pH is in the basic range.

Therefore, the methyl orange indicator will change from red to yellow at the titration's endpoint.

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Answer:

CH4< CH4I< NaCl

Explanation

NaCl has the boiling point of 1,413°C ( 2,575°F )

CH3I has a boiling point of 42°C ( 107°F )

CH4 has the boiling point of -161.6°C ( -258.9°F )

Answer:

Preventing erosion – Land Reclamation

Protecting nesting areas – Protecting Biodiversity

Preventing littering – Land Reclamation

Preventing habitat disruption – Protecting Biodiversity

Protecting native species – Protecting Biodiversity

Preventing contamination of soil – Land Reclamation

Explanation:

I really hope I'm right! I tried my hardest, please give me brainliest :)

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A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

We want to calculate the mass of CaCO₃ in a 1.60 g supplement. We need to consider the following relationships.

\(1.60gSup \times \frac{37.8gCa}{100gSup} \times \frac{1molCa}{40.08gCa} \times \frac{1molCaCO_3}{1molCa} \times \frac{100.09gCaCO_3}{1molCaCO_3} = 1.51gCaCO_3\)

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

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A 1.60 g calcium supplement contains 37.8% Ca by mass. The calcium is present in the supplement as CaCO₃(s) (molar mass 100.09 g/mol). How many grams of CaCO₃(s) are in the calcium supplement?

Answer:

1 and 2

Explanation:

The given equation is:

        Cl₂  +  H₂   →   2HCl

A coefficient is the variable or number before a chemical specie.

In this reaction Cl₂ and H₂ are the reactants;

  The coefficient of Cl₂ is 1,

                                   H₂ is 1,

                                  HCl is 2

The subscript is the number to the lower power after a chemical specie is denoted.

    For Cl₂, it is 2

A number before a chemical atom or molecule is called a coefficient. The coefficient of chlorine is one (1), and its subscript is two (2).

A subscript is a number or symbol written at the bottom right of the chemical atom or the molecule in a compound.

The balanced chemical reaction is shown as:

\(\rm Cl_{2} + H_{2} \rightarrow 2HCl\)

The coefficient in chlorine is 1, hydrogen is 1, and hydrochloric acid is 2. The subscript in chlorine gas is 2, and hydrogen gas is 2.

Therefore, the coefficient is 1, and the subscript is 2.

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After 1.5 days, only 1.25 mg of technetium-99m will remain out of the original 80 mg that was prepared.

Technetium-99m (99mTc) is a radioactive isotope that is used in medical imaging.

It has a half-life of 6 hours, which means that after 6 hours, half of the original amount of technetium-99m will have decayed.

Therefore, after another 6 hours (12 hours total), half of the remaining technetium-99m will have decayed, leaving only 25% of the original amount.

After another 6 hours (18 hours total), half of the remaining technetium-99m will have decayed again, leaving only 12.5% of the original amount.

After 1.5 days, which is 36 hours total, we can use the formula for radioactive decay to calculate how much technetium-99m will remain: amount remaining = original amount x \((1/2)^{t/h}\) where t is the time elapsed and h is the half-life.

Plugging in the given values, we get: amount remaining = 80 mg x (1/2)^(36/6) amount remaining = 80 mg x \((1/2)^{6}\) amount remaining = 80 mg x 0.015625 amount remaining = 1.25 mg

Therefore, after 1.5 days, only 1.25 mg of technetium-99m will remain out of the original 80 mg that was prepared.

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Answer:

39.119 g

Explanation:

1 mole of S has 32.065 g

=> 1.22 x 32.065 = 39.1193 or 39.119 g

Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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The standard enthalpy change for the reaction 2A+B⇌2C+2D is  664 kJ/mol and The heat that is absorbed when 3.70 mol of A reacts is 2456.8  J

The heat changes that take place as reactants combine to generate a product are measured by the enthalpy of a reaction.

The following formula can be used to determine the enthalpy change of a reaction:

Hess's law states that

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Considering the given reaction: 2A + B ⇌ 2C + 2D  

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Enthalpy of reaction (ΔH°f) = (2 C + 2 D) - (2 * A + B)

Enthalpy of reaction  (ΔH°f)  = {[2(223) + 2(-523)] - [2(-245) + 2(-387)]}

Enthalpy of reaction  (ΔH°f)  = 664 kJ/mol

ΔH = q ÷ n

ΔH = molar enthalpy (heat) of solution

q = amount of energy (heat) released or absorbed

n = moles of solute

so. q = ΔH xn

q = ΔH xn

q = 664 kJ/mol x 3.70 mol

Q= 2456.8  J

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3 sigma and 3 pieee

okok kkk

Answer:

Explanation:

Carbon is the only element listed. Carbon Dioxide consists of Carbon AND Oxygen x2 so this is a compound. As stated earlier, air is a mixture of compounds. Water is another compound consisting of Hydrogen x2 and Oxygen.

Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

See attachment

General Formulas and Concepts:

Reading a Periodic Table

Writing Electron Configurations

Quantum Numbers

Explanation:

Electron Configurations of Zr: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d²

When drawing out the Orbital Diagram, we need to follow Hund's Rule.

Explanation:

well I'm not 100% sure but I studied a little bit with rocks and crystals I've noticed that the hotter the temperature are it does not matter if it is Obsidian the hotter it is the more shinier it will become so the texture of it has to be a right temperature to be able to create a different texture such as a diamond and a diamond has to be compressed so hard that it will turn into diamond this is just an explanation please do not take this as a real answer I hope this help you though

Answer:

88 gram is the answer in 2 significant digits

One mole of octane gives 9 moles of water. Then, 3.43 g or 0.03 moles of octane will give 0.27 moles of water that is 4.86 g of water can be produced.

Combustion is a type of chemical reaction in which a gas reacts with oxygen to give carbon dioxide and water.

The combustion reaction of octane is given as follows:

\(\rm C_{8}H_{18} + \frac{25}{2}O_{2} \rightarrow 8CO_{2} + 9 H_{2}O\)

As per this balanced chemical equation, one mole or 114 g of octane gives 9 moles of water.

no.of moles in 3.4 g of octane = 3.4 g/114 g = 0.03 moles.

no.of moles of water produced from 0.03 moles of octane :

= (0.03 × 9) = 0.27 moles.

Molar mass of water = 18 g/mol

then, mass of 0.27 moles = 0.27 × 18 =4.86 g.

Therefore, the maximum mass of water that could be produced here is 4.86 g.

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The mass (in grams) of chlorine gas is needed to react with 251 grams of iron is 479 grams. Option C.

To determine the mass of chlorine gas needed to react with 251 grams of iron, we need to use the stoichiometry of the balanced chemical equation:

2Fe + 3Cl2 → 2FeCl3

From the balanced equation, we can see that 2 moles of iron (Fe) react with 3 moles of chlorine gas (Cl2) to produce 2 moles of iron(III) chloride (FeCl3).

To calculate the mass of chlorine gas, we can follow these steps:

Step 1: Convert the given mass of iron (Fe) to moles.

Using the molar mass of iron (Fe), which is approximately 55.85 g/mol, we can calculate the number of moles of iron:

moles of Fe = mass of Fe / molar mass of Fe

moles of Fe = 251 g / 55.85 g/mol

moles of Fe ≈ 4.5 mol (rounded to one decimal place)

Step 2: Use the mole ratio from the balanced equation to find the moles of chlorine gas (Cl2) needed.

From the balanced equation, we know that 2 moles of Fe react with 3 moles of Cl2. Therefore, the moles of Cl2 can be calculated as:

moles of Cl2 = (moles of Fe / 2) * 3

moles of Cl2 = (4.5 mol / 2) * 3

moles of Cl2 ≈ 6.75 mol (rounded to two decimal places)

Step 3: Convert the moles of chlorine gas to grams.

Using the molar mass of chlorine gas (Cl2), which is approximately 70.90 g/mol, we can calculate the mass of chlorine gas:

mass of Cl2 = moles of Cl2 * molar mass of Cl2

mass of Cl2 = 6.75 mol * 70.90 g/mol

mass of Cl2 ≈ 479 grams (rounded to the nearest whole number) Option C is correct.

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Answer:

4 protons, 5 neutrons, 4 electrons to have the neutral Be atom

the only way to make a negative Be is to have more than 4 electrons

Explanation:

Make a neutral Beryllium atom by adding protons, neutrons and electrons. Now, what would you do to make a

beryllium atom with a negative charge?

Be has an atomic number of 4, an atomic mass 9

its atomic number tells us it has 4 protons, with a +4 charge

its atomic mass = neutrons + protons, so it has 5 neutrons with no charge

its neutral atom will have 4 electrons each with a negative charge to balance the +4 total proton harge.

so

4 protons, 5 neutrons, 4 electrons to have the neutral Be atom

to make a negative Be species, it still must have an atomic number of 4,

or it is not Beryllium

so the only way to make a negative Be is to have more than 4 electrons

Answer:

If it loses 2 electrons, the net charge on the atom will be 2+

If the atom instead gains 4 electrons, the net charge will be 4-

Explanation:

It is based on adding and subtracting charges. Protons are +1 and electrons are -1

If the atom has 9 protons and 9 electrons, the net charge is +9 + (-9) = 0. The +9 is the 9 protons and the -9 is from the 9 electrons.

If two electrons are taken away, there would be 9-2 or 7 electrons with 9 protons. The net charge would then be +9 + (-7) = +2. +9 comes from the 9 electrons and -7 is from the 7 electrons.

So, if two electrons are taken away, the net charge is +2.

Similarly, if the atom gains 4 electrons, there will be 9+4 or 12 electrons and 9 protons. The net charge would then be +9 + (-12) = -4. +9 comes from the 9 protons and -12 comes from the 12 electrons.

So, if 4 electrons are added, the net charge is -4.