Where would a bowling ball and a napkin fall with the same acceleration. Check all that apply. A. Dropped off of the Leaning Tower of Pisa. B. On the moon. C. In a vacuum chamber. D. Anywhere that is not very windy

Answers

Answer 1

On the moon, In a vacuum chamber and anywhere that is not very windy a bowling ball and a napkin fall with the same acceleration.

The correct answer is option B, C, D.

The acceleration of an object in free fall is determined by the gravitational force acting on it. In the absence of other forces, all objects, regardless of their mass, will experience the same acceleration due to gravity. Therefore, both a bowling ball and a napkin would fall with the same acceleration in the following scenarios:

B. On the moon: The moon has a weaker gravitational field compared to Earth. Its acceleration due to gravity is approximately 1/6th of Earth's gravity, but the same for all objects. Hence, both the bowling ball and the napkin would fall with the same acceleration on the moon.

C. In a vacuum chamber: A vacuum chamber eliminates the presence of air, which means there is no air resistance acting on the falling objects. Without air resistance, all objects will experience the same acceleration due to gravity. Therefore, both the bowling ball and the napkin would fall with the same acceleration in a vacuum chamber.

D. Anywhere that is not very windy: Wind or air resistance can affect the motion of objects during free fall. However, if the wind is not very strong, the effect of air resistance becomes negligible. In this case, both the bowling ball and the napkin would experience the same acceleration due to gravity and fall with the same rate.

A. Dropped off of the Leaning Tower of Pisa: This scenario does not guarantee that the bowling ball and napkin will fall with the same acceleration. The presence of air resistance can cause the napkin to experience a greater deceleration compared to the bowling ball due to its larger surface area. However, in the absence of significant air currents, the difference in acceleration may not be noticeable.

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Related Questions

what is the voltage drop on a 120-volt circuit consisting of 12 awg copper wire where the load is 20 amps and the distance from the panel to the load is 100 ft? (use k

Answers

The main answer to your question is that the voltage drop on a 120-volt circuit consisting of 12 AWG copper wire, with a load of 20 amps and a distance of 100 ft from the panel to the load, is 4.8 volts.


To calculate the voltage drop, we can use the formula V_drop = (2 * K * I * L) / cmil, where V_drop is the voltage drop, K is the resistivity of the material (for copper, K = 12.9 ohms per 1000 ft), I is the current (20 amps), L is the distance (100 ft), and cmil is the circular mil area of the wire (for 12 AWG, cmil = 6530).
V_drop = (2 * 12.9 * 20 * 100) / 6530 = 4.8 volts


Summary: In a 120-volt circuit with a 12 AWG copper wire, a 20-amp load, and a 100 ft distance from the panel to the load, the voltage drop is 4.8 volts.

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which of the images below shows the correct resultant vector?

WILL MARK BRAINLIEST

which of the images below shows the correct resultant vector?WILL MARK BRAINLIEST

Answers

Answer:

3 N right.

Explanation:

The vector in red is 5 units long pointing towards right.

it's length represents its magnitude.

Therfore, the red vector's magnitude is 5 and direction is right.

The other one, the one in blue, is pointing towards left, I. e., in a direction opposite to the red one.

It covers 2 units on the graph so we can say ots magnitude is 2 units.

Therefore, the blue Victor's magnitude is 2 and direction is left.

Since, the two vectors are in opposite directions, the magnitude of their resultant will be equal to their difference, and it will be directed towards the vector with larger magnitude.

here, red has larger magnitude and it's direction is right, so the direction of resultant will be right.

magnitude :-

\( \red{5} - \blue{2} \\ = 3 \: units\)

So, we got the resultant vector pointing towards right and magnitude 3.

The mass of the Moon is 7.35 × 1022 kg and its radius is 1738 km. What is the gravitational field strength on the surface of the Moon?

Answers

Answer:

g = 1.62 N/kg

Explanation:

g = GM/r²

  = (6.67 x 10⁻¹¹   x   7.35 x 10²²) / (1738 x 10³)²

  = 1.62 N/kg

Hope this helps!

Which of the following is an example of a primary source?

Which of the following is an example of a primary source?

Answers

Answer:

An article written by a scientist .

Explanation:

Primary sources information are those that contain first  hand information probably from the place of the activities or by the original contact of the information (source ) .

So primary information is normally contained in artifact , journals , letter , dissertations manuscripts  , videos and audio recordings .

The fact that the article is written by the scientist means he is the one who has the original information hence he is the first person to access the information , meaning he is the original owner .

HELP HELP HELP NOW PLEASEEEEEEE

how could you increase the kinetic energy of a wagon without increasing its mass?

Answers

Answer:

use newtons gravity of law by launching a watermelon in frot of the wagon

Explanation:

14. If we change how fast an object is going and change its mass then we
have changed its...

Answers

Answer:

Momentum

Explanation:

If we change how fast an object is going and change its mass, then we have changed its momentum.

The momentum of body is the quantity of motion such a body can possess.

It is mathematically expressed as:

   Momentum  = mass x velocity

Therefore, if we vary mass and velocity or either of them, then, the momentum of the object will also change.

Mass and velocity is very crucial to the momentum of a body.

In what way could a random mutation provide an organism with
an advantage?

Answers

Answer:

They are called beneficial mutations. They lead to new versions of proteins that help organisms adapt to changes in their environment. Beneficial mutations are essential for evolution to occur. They increase an organism's changes of surviving or reproducing, so they are likely to become more common over time.

Explanation:

two identical waves of amplitude 5cm meet in a large ripple tank what will be the aplitude of the combined wave at a point where they interfere constructive and where they interfere destructively​

Answers

(a) For constructive interference the two waves will have higher amplitude of 10 cm.

(b) For destructive interference the two waves will have zero amplitude.

Amplitude of the waves for constructive interference

For constructive interference the two waves will have higher amplitude after constructive interference.

Resulting amplitude = 5 cm + 5cm = 10 cm

Amplitude of the waves for destructive interference

For destructive interference the two waves will have zero amplitude after destructive interference.

Resulting amplitude = 5 cm - 5cm = 0

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which of these is not a form of electromagnetic radiation? group of answer choices dc current from your car battery x-rays in the doctor's office light from your camp fire television signals ultraviolet causing a suntan

Answers

Out of the given options, the one that is not a form of electromagnetic radiation is "dc current from your car battery."



Electromagnetic radiation refers to the energy that travels in the form of waves, carrying both electric and magnetic fields. It includes a wide range of wavelengths, from radio waves to gamma rays.

1. DC current from your car battery: Direct current (DC) is the flow of electric charge in one direction, typically used in batteries and electronic devices. 2. X-rays in the doctor's office: X-rays are a form of electromagnetic radiation with a short wavelength and high energy. They are commonly used in medical imaging to visualize bones and internal organs.

3. Light from your campfire: Light is a form of electromagnetic radiation that is visible to the human eye. It has a range of wavelengths, with different colors corresponding to different wavelengths.

4. Television signals: Television signals transmit information through electromagnetic waves. These waves fall within the radio wave portion of the electromagnetic spectrum.

5. Ultraviolet causing a suntan: Ultraviolet (UV) radiation is a form of electromagnetic radiation with shorter wavelengths and higher energy than visible light.

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when a body is fully or partially immersed in a liquid name the forces acting on the body​

Answers

gravitational force (weight) and buoyant

An aquarium has a volume of 2.75 cubic
meters. How many liters of water can the
aquarium hold?

Answers

The aquarium can hold 2750 liters because 1 cubic meter equals 1000 liters.

first to answer gets brainlesit! get it correct.

first to answer gets brainlesit! get it correct.

Answers

Answer:

i believe the answer is c

Find the magnetic field a distance rrr from the center of a long wire that has radius aaa and carries a uniform current per unit area jjj in the positive z direction.

Answers

The magnetic field is \(\vec B = \frac{\mu_0 jR^2}{2r}\hat \theta\).

What is Magnetic Field?

The area in which the force of magnetism works around a magnetic substance or a moving electric charge is known as the magnetic field. a diagram that shows the magnetic field and how a magnetic force is distributed within and outside of a magnetic substance.

a) the magnetic field, B outside the wire

Using ampere law:

\(\int Bdl = \mu_0 I_{net}\)

so:

\(B(2\pi r) = \mu_0 (jA) = \mu_0 j(\pi R^2)\)

\(B = \frac{\mu_0 jR^2}{2r}\\\)

the direction is in\(\hat \theta\)

\(\vec B = \frac{\mu_0 jR^2}{2r}\hat \theta\)

b) the magnetic field, B inside the wire

Using ampere law:

\(\int Bdl = \mu_0 I_{net}\)

so:

\(B(2\pi r) = \mu_0 (jA) = \mu_0 j(\pi r^2)\)

\(B = \frac{\mu_0 jr}{2}\)

the direction is in\(\hat \theta\)

\(\vec B = \frac{\mu_0 jr}{2}\hat \theta\)

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The forces represented by the arrows in the diagrams are applied to the
four objects that are at rest on a table. Which object is most likely to
move to the right?

The forces represented by the arrows in the diagrams are applied to thefour objects that are at rest

Answers

Answer:

Y

Explanation:

the net force on y is 45 +35 = 75 N [right]

the most common type of topographic map is created by the USGS is a 7.5-minute by 7.5-minute quadrangle map (figure 3.18). this means that each side of the map is 7 minutes and 30 seconds. each minute of latitude is 1852 meters and each second of latitude is 31 meters. how many meters does this map cover in a north-south direction?

the most common type of topographic map is created by the USGS is a 7.5-minute by 7.5-minute quadrangle

Answers

Answer: I think it's 13,000 meters

Explanation:

An op-amp is connected in an inverting configuration with R_1 = 1 k ohm and R_2 = 100 k ohm. Find the closed loop gain, G, for the cases when the open loop gain, A, is equal to 10^3, 10^4, 10^5. In each case, determine the percentage error in the magnitude of G relative to the ideal value of R_2/R_1, (obtained if A = infinity). Also determine the voltage that appears at the inverting terminal (v_1) when v_1 = 0. 1 V If A drops by 50% from 100,000 to 50,000, what is the corresponding percentage change in the magnitude of the closed loop gain?

Answers

The closed loop gain, G, for the cases when the open loop gain, A, is equal to \(10^3\) is  \(-10^5\), A is  \(-10^4\) is  \(-10^6\), A is \(10^5\) is \(-10^7\) and the corresponding percentage change in gain is 50%.

The closed loop gain is given by:

G = \(-A*(R_2/R_1)\)

Case 1: A = \(10^3\)

G = \(-10^3*(100k/1k) = -10^5\)

The ideal value of the gain is \(-10^5\), so the percentage error is 0%.

Case 2: A = \(10^4\)

G = \(-10^4*(100k/1k) = -10^6\)

The ideal value of the gain is \(-10^6\), so the percentage error is 0%.

Case 3: A = \(10^5\)

G = \(-10^5*(100k/1k) = -10^7\)

The ideal value of the gain is \(-10^7\), so the percentage error is 0%.

The voltage at the inverting terminal (v_1) when v_1 = 0. 1 V is -0.1 V.

If A drops by 50% from 100,000 to 50,000, the corresponding change in the magnitude of the closed loop gain is a decrease of 50%.

This can be calculated using the equation:

 \(\frac{\Delta G}{G_{initial}} = \frac{A_{initial} - A_{final}}{A_{initial}}\)

In this case, the initial gain is \(-10^5\), and the final gain is \(-5*10^4.\)

Therefore, the percentage change in the magnitude of the closed loop gain is:

\(\frac{\Delta G}{G_{initial}} = \frac{10^5 - 5*10^4}{10^5} = 0.5 = 50\%\)

This means that the magnitude of the closed loop gain decreases by 50%.

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What are the factors that change the pattern observed on a screen during Young’s double-slit experiment?

Answers

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:

1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.

2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.

3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.

4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.

5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.

When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.

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2 questions, brainliest for both correct! please: only answer if you are sure of the answer!! :)

thank you!

2 questions, brainliest for both correct! please: only answer if you are sure of the answer!! :)thank
2 questions, brainliest for both correct! please: only answer if you are sure of the answer!! :)thank

Answers

The main reason why Felix Baumgartner was able to exceed the normal terminal velocity of a person falling to earth is D. There was very little air resistance at the great altitude at which he jumped.

What is Terminal Velocity?

This refers to the constant speed to which an object that is in free fall reaches and he encounters air resistance that prevents further acceleration.

Hence, we can see that the way in which Newton's laws helped in the understanding of the physical world is that A. Scientists can now improve the scientific method.

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what is the launch speed of a projectile that rises vertically above the surface of the earth to an altitude equal to 5 earth radii before momentarily coming to a rest

Answers

The launch speed of the projectile is approximately 11.2 km/s.

What is the initial velocity required for the projectile to reach an altitude of 5 Earth radii?

When a projectile is launched vertically above the surface of the Earth, it follows a parabolic trajectory due to the gravitational force acting on it. To determine the launch speed required for the projectile to reach an altitude equal to 5 Earth radii, we can consider the conservation of mechanical energy.

Initially, the projectile has kinetic energy (½mv²) and gravitational potential energy (mgh), where m is the mass of the projectile, v is its velocity, and h is its height above the surface of the Earth. At the highest point of its trajectory, the projectile comes to rest momentarily, which means its final kinetic energy becomes zero. Therefore, the total mechanical energy at the highest point is equal to the initial mechanical energy.

The gravitational potential energy is given by mgh, where h is the height above the surface of the Earth. At the highest point, the height is equal to 5 Earth radii, which is 5 times the radius of the Earth (R). Therefore, the gravitational potential energy at the highest point is given by mgh = m * g * 5R.

The kinetic energy at the highest point is zero. Thus, the total mechanical energy is equal to the gravitational potential energy alone: mgh = m * g * 5R.

The initial mechanical energy is the sum of the initial kinetic energy and the initial gravitational potential energy, which can be written as ½mv² + mgh. At the highest point, this energy is equal to the gravitational potential energy: ½mv² + mgh = m * g * 5R.

Simplifying the equation, we have ½v² + gh = 5gR.

Since the projectile comes to rest momentarily at the highest point, the final velocity is zero (v = 0). Substituting this into the equation, we have 0 + g * 5R = 5gR.

Simplifying further, we find R = R, which means the equation holds true for any value of R. Therefore, the launch speed of the projectile is independent of the radius of the Earth.

Substituting R = 6,371 km (the average radius of the Earth), we can solve for the launch speed:

0 + 9.8 m/s² * 5 * 6,371 km = v²

v² = 313,979,800 m²/s²

v ≈ 17,718 m/s ≈ 17.7 km/s

Therefore, the launch speed of the projectile required to reach an altitude equal to 5 Earth radii before momentarily coming to a rest is approximately 17.7 km/s.

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A little green moon person stands by the rim of a crater on the Moon, where
the freefall acceleration is 1.62 m/s2 and there is no air resistance. The crater
has vertical walls. To determine the depth of the crater, she drops a rock and
measures the time it takes for it to hit the bottom. If the depth of the crater is
120 m, after what time interval will the rock hit the floor of the crater?

Answers

Answer:

Time:

t = 12 s

Explanation:

Given:

g = 1.62 m/s

H = 120 m

V₀ =0 m/s

__________

t - ?

From the formula:

H = V₀·t + g·t² / 2

H = g·t² / 2

we find the time:

t = √ (2·H / g)

t = √ (2·120 / 1.62) ≈ 12 c

Why should you use the taillights of the vehicle in front of you to guide you in extremely snowy conditions

Answers

Answer:

There are also reasons not to, but usually it keeps you on the road.

Explanation:

If I keep my vehicle straight behind the one in front of me, as long as they are fine I’m fine.
Although, if they make a mistake it’s easy to be too focused on following them than to save yourself.

Using the taillights of the vehicle in front of you to guide you in snowy conditions can help improve your visibility, provide guidance on the road ahead, and keep you centered and safe while driving in challenging conditions.

In extremely snowy conditions, visibility can be severely reduced, making it difficult to see the road ahead and navigate safely. Using the taillights of the vehicle in front of you can help guide you for several reasons:

(1) Contrast: The taillights of a vehicle provide a contrasting light against the white background of the snow, making it easier to see and follow the vehicle in front of you.

(2) Visibility: The taillights are usually positioned higher up on the vehicle than the brake lights, making them more visible above the snow drifts or other obstacles on the road.

(3) Indicators: The taillights provide indicators of the vehicle in front's movements, such as when they are turning or slowing down. By paying attention to these indicators, you can anticipate the actions of the vehicle ahead and react accordingly.

(4) Centering: Following the taillights of the vehicle in front can help keep you centered on the road and prevent you from accidentally veering off course.

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Match the material with its property. Metals
Ceramics
Composites
Polymers Semiconductors - Good electrical and thermal insulators
- Conductivity and weight can be tailored
- Poor electrical and thermal conductivity - The level of conductivity or resistivity can be controlled - low compressive strength

Answers

Metals - Conductivity and weight can be tailored, Ceramics - Good electrical and thermal insulators, Composites - The level of conductivity or resistivity can be controlled, Polymers - Poor electrical and thermal conductivity, Semiconductors - low compressive strength.

Metals: Metals are known for their good electrical and thermal conductivity. They are excellent conductors of electricity and heat, allowing for efficient transfer of these forms of energy.
Ceramics: Ceramics, on the other hand, are good electrical and thermal insulators. They possess high resistivity to the flow of electricity and heat, making them suitable for applications where insulation is required.
Composites: Composites are materials that consist of two or more different constituents, typically combining the properties of both. The conductivity and weight of composites can be tailored based on the specific composition.
Polymers: Polymers are characterized by their low conductivity, both electrical and thermal. They are poor electrical and thermal conductors.
Semiconductors: Semiconductors possess unique properties where their electrical conductivity can be controlled. They have an intermediate level of conductivity between conductors (metals) and insulators (ceramics).

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3. Drinking one liter of pure water is expected to: a) Induce a greater increase in volume of ECF than ICF b) Induce a greater decrease in osmolarity of ECF than ICF c) Induce an increase in urine flow d) Induce a greater increase in volume of plasma than interstitial fluid e) Induce a greater deacrease in osmolarity of plasma than interstitial fluid 3. Drinking one liter of pure water is expected to : a ) Induce a greater increase in volume of ECF than ICF b ) Induce a greater decrease in osmolarity of ECF than ICF c ) Induce an increase in urine flow d ) Induce a greater increase in volume of plasma than interstitial fluid e ) Induce a greater deacrease in osmolarity of plasma than interstitial fluid​

Answers

Answer:

b

Explanation:

Describe a ball's motion as it rolls up a slanted
driveway. It starts with an initial velocity of 1.25 m/s up the ramp. It
travels upward, while slowing down, for 4.22 s, stops for an instant,
and then rolls back down. What are the direction and the magnitude
of the ball's acceleration as it rolls up the driveway?

Answers

The ball will decelerate as it moves upwards.

The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

The given parameters;

initial velocity of the ball, u = 1.25 m/stime of motion of the ball, t = 4.22 s

As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

Thus, the ball decelerate as it moves upwards.

The acceleration of the ball is calculate as;

\(a = \frac{v_f -v_0}{t} \\\\\)

at the highest point on the incline plane, the final velocity \(v_f\) is zero

\(a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2\)

Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

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Two Brothers are playing soccer on the beach. One brother kicks the ball really hard and the ball lands in the water, about 50 meters from the beach. They wonder if the ball will float back to the beach.

Answers

Answer:

Due to wind and waves of water.

Explanation:

They wonder that the ball will float back to the beach because of the wind and the waves of the water. The wind blows towards the beach which moves the water in the form of waves towards the beach so if the ball lands in the water, it will floats on the surface of water and move towards the beach with the help of wind and waves of the sea. The ball floats on the water due to its lighter weight and lower density as compared to water.

A science student investigated how far a spring would stretch when various weights are attached to it. The stretch was measured in millimetres and the weights in grams.
The results are as follows :
MASS IN GRAMS (G) 10. 12. 14. 16. 18. 20. 22. 24
EXTENSION IN
MILLIMTREST (MM). 15. 18. 20. 25. 28. 30 33 40
(iii) Find the equation of the regression line

Answers

Equation of the regression line can be found by using linear regression which is Extension (MM) = a + b * Mass (G)

The equation of the regression line can be found by using linear regression, which is a method of finding the line of best fit that describes the relationship between two variables. In this case, the two variables are the mass in grams (G) and the extension in millimeters (MM).

To find the equation of the regression line, the student could use the method of least squares, which is a method of finding the line that minimizes the sum of the squared errors between the observed data and the predicted data.

Regression line equation is:

Extension (MM) = a + b * Mass (G)

Where "a" is the y-intercept, "b" is the slope of the line, and "Mass (G)" and "Extension (MM)" are the variables.

To find the values of "a" and "b", the student could use the following formulas:

B is equal to (NXY - XY) / (NX2 - (X)XY).

A is equal to (ΣY - bΣX) / N

Where N is the number of data points, ΣX is the sum of the mass values, ΣY is the sum of the extension values, and ΣXY is the sum of the product of the mass and extension values for each data point.

Once the values of "a" and "b" have been found, the equation of the regression line can be substituted into the equation to find the predicted extension for any given mass. This will give the student a model for how the extension of the spring is related to the mass that is attached to it.

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a gymnast does cartwheels along the floor and then launches herself into the air and executes several flips in a tuck while she is airborne. if her moment of inertia when executing the cartwheels is and her spin rate is 0.5 rev/s, how many revolutions does she do in the air if her moment of inertia in the tuck is and she has 2.0 s to do the flips in the air?

Answers

The gymnast completes 10 revolutions in the air.

The law of conservation of angular momentum states that the total angular momentum of a system remains constant if no external torques act on the system. In this case, the gymnast starts with a certain amount of angular momentum while performing the cartwheels on the ground, and this angular momentum is conserved as she launches herself into the air and performs flips.

Let I1 be the moment of inertia of the gymnast while performing the cartwheels, and omega1 be the spin rate. When she launches into the air, she changes her moment of inertia to I2 and starts rotating at a new spin rate, omega2. According to the law of conservation of angular momentum:

I1 * Ω1 = I2 * Ω2

We can rearrange this equation to solve for omega2:

Ω2 = (I1 * Ω1) / I2

Now, we can use the equation for rotational kinematics:

θ  = Ω * t

where theta is the total angle rotated, omega is the spin rate, and t is the time. We can solve for the number of revolutions by converting the angle rotated into revolutions:

revolutions = θ/ (2*pi)

Plugging in the given values, we get:

Ω1 = 0.5 rev/s

I1 = (given)

I2 = (given)

t = 2.0 s

Using the conservation of angular momentum equation, we can solve for omega2:

Ω2 = (I1 * Ω1) / I2

Plugging in the values, we get:

Ω2 = (I1 * 0.5) / I2

Using the equation for rotational kinematics, we can solve for the total angle rotated in radians:

θ = Ω2 * t

Converting this angle to revolutions, we get:

revolutions = θ/ (2*pi)

Plugging in the values, we get:

revolutions = (Ω2 * t) / (2*pi) = 10 revolutions (rounded to the nearest whole number)

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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.

Answers

The correct answer is option C.

Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. The average intensity of Wave 1 is nine times the intensity of Wave 2.

By comparing the two electromagnetic waves, we get:

Maximum Electric Field Strength of Wave(1) = 3 x Maximum Electric Field Strength of Wave (2), i.e.

\(E_{1}\)  = 3 x \(E_{2}\)

Now comparing the average intensities of the two waves. we get \(\frac{I1}{I2}\)

The average intensity of electromagnetic wave 1 can be expressed as:

\(I_{1}\) = \(\frac{1}{2}\) x ε0 x  \(E1^{2}\) x c ------- (1)

Now, the average intensity of the electro-magnetic wave 2 can be expressed as:

\(I_{2}\)  =  \(\frac{1}{2}\) x ε0 x  \(E2^{2}\)  x c -----(2)

Now comparing equations 1 and 2 we get.

\(\frac{I1}{I2}\)  =   \(E1^{2}\) /  \(E2^{2}\)

\(\frac{I1}{I2}\)  =  ( 3 x \(E2)^{2}\)/  \(E2^{2}\)

\(\frac{I1}{I2}\)  = 9

Thus, we can say that the average intensity of Wave 1 is nine times the intensity of Wave 2.

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The complete question is:

Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of Wave 2. How do the average intensities of the waves compare?

a. The average intensity of Wave 1 is three times the intensity of Wave 2.

b. The average intensity of Wave 2 is three times the intensity of Wave 1.

c. The average intensity of Wave 1 is nine times the intensity of Wave 2.

d. The average intensity of Wave 2 is nine times the intensity of Wave 1.

A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is at the 20-yard line; at 3 seconds, he is at the 30-yard line; and at 4 seconds, he is at the 40-yard line. This is evidence that _____

a.) he is accelerating

b.) he is moving with a constant speed (on average)

c.) he is covering a greater distance in each consecutive second

Answers

Answer:

Option (b) he is moving with a constant speed (on average)

Explanation:

To know which option is correct, let us calculate the speed at each time.

Case 1:

Distance = 10 yard

Time = 1 s

Speed =?

Speed = distance / time

Speed = 10 / 1

Speed = 10 yard/s

Case 2:

Distance = 20 yard

Time = 2 s

Speed =?

Speed = distance / time

Speed = 20 / 2

Speed = 10 yard/s

Case 3:

Distance = 30 yard

Time = 3 s

Speed =?

Speed = distance / time

Speed = 30 / 3

Speed = 10 yard/s

Case 4:

Distance = 40 yard

Time = 4 s

Speed =?

Speed = distance / time

Speed = 40 / 4

Speed = 10 yard/s

From the calculations made above, we can see clearly that the speed at each case is the same i.e constant. This is true because he is covering the same distance with respect to time.

This also means that the footballer is not accelerating as his speed remains the same i.e constant.

Thus, option B gives the correct answer to the question.

An object executing simple harmonic motion has a maximum speed of 48 m/s and a maximum acceleration of 0.85 m/s²
Part A
Find the amplitude of this motion.
Express your answer using two significant figures.

Answers

The amplitude of this motion is approximately 2705.37 m, expressed with two significant figures.

To find the amplitude of an object executing simple harmonic motion, we can use the relationship between maximum speed, maximum acceleration, and amplitude.

In simple harmonic motion, the maximum speed (V(max)) occurs when the displacement (x) is zero, and the maximum acceleration (a(max)) occurs when the displacement is at its maximum. The relationship between these quantities is given by:

V(max) = ω * A

a(max) = ω² * A

Where ω represents the angular frequency and A represents the amplitude.

From the given information, V(max) = 48 m/s and a(max) = 0.85 m/s².

Dividing the equation for maximum acceleration by the equation for maximum speed, we get:

a(max) / V(max) = (ω² * A) / (ω * A)

Simplifying, we have:

a(max) / V(max) = ω

Substituting the given values, we have:

0.85 m/s² / 48 m/s = ω

Solving for ω, we find:

ω ≈ 0.0177 rad/s

Now, we can use the equation for maximum speed to find the amplitude:

V(max) = ω * A

Rearranging the equation, we have:

A = V(max) / ω

Substituting the values, we have:

A = 48 m/s / 0.0177 rad/s ≈ 2705.37 m

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