Which device we have to connect parallel in a circuit. Tell the name of device.​

Answers

Answer 1

Answer:

Explanation:

An ammeter is a measuring device used to measure the electric current in a circuit. A voltmeter is connected in parallel with a device to measure its voltage, while an ammeter is connected in series with a device to measure its current.


Related Questions

Help please

How much work did Mr. Bowen do pushing the elephant in our Edpuzzle?

0J


25J


400J


1,500J

Answers

I think the answer is 25J

An ultrasound machine is being used to try to identify potential kidney stones. The machine is working properly and no kidney stones are found. Which statement best describes this situation? The generated sound wave will not be able to reflect off of the object. The sound wave will not be generated, so there will be no echoes received. The echoes will be made but will not be able to be received by the machine. The machine will not be able to process the received echoes into images.

Answers

Answer:

The generated sound wave will not be able to reflect off of the object.

Explanation:

The statement that best describes this situation is: The generated sound wave will not be able to reflect off of the object.

What is an Ultrasound Machine?

An ultrasound machine is a device that is used to capture images in the human body for review by a medical examiner. The machine gives off sound waves that are reflected off body structures.

So, for the ultrasound machine being described, the absence of kidney stones will cause a non-reflection of the object to be captured.

Since the machine is in good working condition, the sound wave will be generated.

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How much pressure is created when you apply a
50.0N force on a syringe plunger that has a diameter of 0.4​

Answers

Pressure
= Force/Area

Area = π(d^2)/4
= π(0.4^2)/4
=0.126 m2
Pressure
= 50/0.126
= 396.825 Pa

A liquid X at 25°C is poured to a height of 40cm in a thin capillary tube of length 70cm anc diameter of 1cm. Assume that the volume of the capillary tube does not change with temperature. Find the initial volume of the liquid in cm³​

Answers

The level within a capillary tube with a radius of 0.45 mm rises to a height of 3 cm above the water's surface when submerged in it.

What is the capillary pressure equation?

When water saturation decreases, Pnw outside the pore throat is larger than Pw within the pore throat, resulting in a positive pressure (Pc=PnwPw), which is the definition of capillary pressure.

A micron is equal to 0.001 mm in diameter, therefore the capillaries are just big enough for red blood cells to travel through in a single line. Endothelial cells, which also make up the smooth channel surface of the bigger vessels, are the single layer of cells that make up their walls.

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what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

Answers

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.

What is the net force net
on an airplane window of area 1800 cm2
if the pressure inside the cabin is 0.95 atm
and the pressure outside is 0.76 atm
?

Answers

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?

Answers

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

* WILL GIVE BRAINLIEST TO CORRECT ANSWER *
Name a product that people commonly purchase by mass and not by weight.

Answers

I would say food but like they take weight too

please answer-WILL MARK THE BEST ANSWER AS BRAINLIEST (100 POINTS)


What type of movements occur at plate boundaries, and what type of landforms are created at each type of plate boundary?

Claim:

Evidence:

Reasoning:


Complete each section in complete sentences or bullet points.

Answers

Answer:

The Earth’s lithosphere, which includes the crust and upper mantle, is made up of a series of pieces, or tectonic plates, that move slowly over time.

A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth’s mantle to the surface, solidifying to create new oceanic crust. The Mid-Atlantic Ridge and Pacific Ring of Fire are two examples of divergent plate boundaries.

When two plates come together, it is known as a convergent boundary. The impact of the colliding plates can cause the edges of one or both plates to buckle up into a mountain ranges or one of the plates may bend down into a deep seafloor trench. A chain of volcanoes often forms parallel to convergent plate boundaries and powerful earthquakes are common along these boundaries.

At convergent plate boundaries, oceanic crust is often forced down into the mantle where it begins to melt. Magma rises into and through the other plate, solidifying into granite, the rock that makes up the continents. Thus, at convergent boundaries, continental crust is created and oceanic crust is destroyed.

Two plates sliding past each other forms a transform plate boundary. One of the most famous transform plate boundaries occurs at the San Andreas fault zone, which extends underwater. Natural or human-made structures that cross a transform boundary are offset—split into pieces and carried in opposite directions. Rocks that line the boundary are pulverized as the plates grind along, creating a linear fault valley or undersea canyon. Earthquakes are common along these faults. In contrast to convergent and divergent boundaries, crust is cracked and broken at transform margins, but is not created or destroyed.

The area of a piston of a force pump is 8 X 10⁴m². What force must be
applied to the piston to raise oil (d = 780 Kg/mº) to a height of 6.0 m? Assume
the upper end of the oil is open to the atmosphere.​

Answers

Answer:

Force of \(37.44 * 10^{8}\) Kgm/s^2 must be  applied to the piston to raise oil to a height of 6.0 m

Explanation:

As we know,

Pressure is the force per unit area

Or \(P = \frac{F}{A}\)

Force \(= P * A\)

Pressure is the product of density, gravitational constant and height

\(P = 780 * 10 * 6\)

Force

\(= P * A\\= 780 * 10*6*8*10^4\\= 37.44 * 10^{8}\)Kgm/s^2

The force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N. Force is defined as the ratio of presure and area. Its unit is Newton.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The given data in the problem is;

A is the area of a piston = 8 X 10⁴m².

F is the force=?

h is the height = 6.0 m

Force is defined as the ratio of presure and area. Its unit is Newton.

\(\rm P = \frac{F}{A} \\\\ \rm F = P \times A \\\\ \rm F = 780 \times 10^6 \times 8 \times 10^4 \\\\ \rm F = 37.44 \times 10^8\)

Hence the force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N.

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if i have the equation mgh1=mgh2+1/2mv^2 do the m values cancel out? is the equation h1=h2+1/2v^2

Answers

The equation is of conservation of energy

\(h_1=h_2+ \frac{1}{2g}v^2\)

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. Following work, energy is transmitted to the item, which causes it to move at a new, constant speed. An object can store energy as the result of its position is potential energy.

Conservation of energy equation  

\(mgh_1=mgh_2+1/2mv^2\)

\(h_1=h_2+ \frac{1}{2g}v^2\)

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6. Find the fundamental units involved in the following derived units.
(i) Newton(N)
(ii) Watt (W)
(iii) Joule (1)
(iv) Pascal (Pa)
(v) Cubic metre​

Answers

Answer:

I. force

II. electricity.

III. energy.

iv. pressure.

v. volume.

Solubility Curve Practice Problems Worksheet 1
Directions: Find the mass of solute will dissolve in 100mL of water at the following temperatures?
150
1. KCl at 70°C =
140
2. Ce,(SO.), at 100°C=
130
120
3. NH.Cl at 90°C=
4. Which of the above three substances is most
110
100
NaNO3
soluble in water at 15°C. =
90
KNO3
Grams of solute
per 100 g H,0
80
70
60
NH3
NHACI
50
KCI
40
Naci
30
20
KCIO
10
Ce2(SO4)3
0
10 20 30 40 50 60 70 80 90 100
Temperature (°C)

Answers

I don’t understand can you please explain your question thank u

According to the solubility curve, KCl is soluble in water at a rate of about 40 grammes per 100 g. Given that we have 100 mL, or 100 grammes, of water, the mass of KCl that will dissolve is similarly 40 grammes.

\(Ce_2(SO_4)_3\) is soluble in water at a rate of around 30 grammes per 100 grammes at 100 °C. \(Ce_2(SO_4)_3\) will therefore dissolve in 100 mL of water at a mass of 30 grammes.

\(NH_4Cl\) dissolves in water at a rate of around 90 grammes per 100 grammes at 90 °C. The mass of \(NH_4Cl\) that will dissolve in 100 mL of water is similarly 90 grammes.

We must ascertain the solubilities of the abovementioned chemicals at 15°C in order to ascertain which substance is most soluble at that temperature.

\(NaNO_3\) has the highest solubility at 15°C, as seen by the solubility curve. At 15°C, \(NaNO_3\) dissolves in water at a rate of about 80 grammes per 100 g.

Therefore, at 15°C, NaNO3 is the most soluble substance among the three given substances.

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Plz help!! WILL MARK BRAINLIEST :)
Which forces are easier to anticipate and
design for, internal or external? Why do
you think this is so?

Answers

Answer:

The external forces such as wind, water and the vibration of the earth when an earthquake happens create internal forces within a structure. Internal forces such as shear, tension and compression can destroy the inner framework of a building or a bridge even though it is made of super strong steel and concrete.

I Hope This Will Help You ...

A 75.0-kg man is riding an escalator in a shopping mall. The escalator moves the man at
a constant velocity from ground level to the floor above, a vertical height of 4.60 m. What
is the work done on the man by (a) the gravitational force and (b) the escalator?

Answers

The negative sign indicates that the work done by the escalator is in the opposite direction of the displacement, which is downward. So, the escalator is doing negative work on the man.

The gravitational force is doing positive work on the man because it is in the same direction as the displacement.

Steps

We need to use the formulas for work and gravitational potential energy:

work = force x distance x cos(theta)

gravitational potential energy = mgh

(a) The work done on the man by the gravitational force is given by:

work_gravity = mgh = (75.0 kg)(9.8 m/s^2)(4.60 m) = 3,301 J

The gravitational force is doing positive work on the man because it is in the same direction as the displacement.

(b) The work done on the man by the escalator is given by:

work_escalator = force_escalator x distance x cos(0) = force_escalator x distance

The escalator is moving the man at a constant velocity, so the net force on the man is zero (since the man is not accelerating). Therefore, the force of the escalator must be equal in magnitude and opposite in direction to the gravitational force:

force_escalator = -mg = -(75.0 kg)(9.8 m/s^2) = -735 N

Substituting this value and the distance (4.60 m) into the formula for work, we get:

work_escalator = (-735 N)(4.60 m) = -3,381 J

The negative sign indicates that the work done by the escalator is in the opposite direction of the displacement, which is downward. So, the escalator is doing negative work on the man.

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Hi please answer the question labeled d

If Q1 is 5 times larger than Q2 the force that Q1 exerts on Q2 is?
(greater than, smaller than, or exactly the same as) the force that Q2 exerts on Q1.

Hi please answer the question labeled dIf Q1 is 5 times larger than Q2 the force that Q1 exerts on Q2

Answers

part a) If Q increases by 5 times its original value, the electrostatic force (F) will increase5 times as well.

part b) If r is halved (reduced by 2), the force will become four times stronger (since 2² = 4).

part c) If Q1 is positive and Q2 is negative, the charges will attract each other.

part d) If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same.

What is electrostatic force?

The electrostatic force is described as the force of attraction or repulsion between two charged particles.

With regards to Coulomb's Law, we have that the electrostatic force between two charges separated by a distance is :

Force = k * (Q1 * Q2) / r²

Where:

F_ =  electrostatic force

k = electrostatic constant

Q1 and Q2 =  magnitudes of the charges

r = distance

for case a:

If one of the charges, Q1 or Q2, increases by 5 times then the electrostatic force  will also increase by 5 times.

case b)

If the distance between the charges, r, is halved, the electrostatic force   will become four times stronger because (1/r²).

for case c.

if Q1 is positive and Q2 is negative, the charges will attract each other because of magnetic laws.

for case d.)

If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same as there is a resulting stronger gravitational or electromagnetic force.

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What is the average acceleration of a me
that reaches 24 m/s in 5.5 seconds?
F 0.20 m/s2
G 2.5 m/s
H 10 m/s2
J 208 m/s

What is the average acceleration of a methat reaches 24 m/s in 5.5 seconds?F 0.20 m/s2G 2.5 m/sH 10 m/s2J

Answers

Answer:

See below

Explanation:

Assuming starting from zero velocity

vfinal = at

24   = a (5.5)

a = 4.36  m/s^2        I think part of your question is missing....what was the initial velocity?

A radio is rated as 50 W. Calculate the energy transferred in Joules by the radio when it has been switched on for 2 minutes?

Answers

The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.

Energy transfer

Power is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:

Power = Energy transferred / Time

Rearranging the equation to solve for energy transferred, we get:

Energy transferred = Power x Time

We are given:

Power = 50 W

Time = 2 minutes = 120 seconds

Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:

Energy transferred = Power x Time = 50 W x 120 s = 6000 J

In other words, the energy transferred by the radio is 6000 Joules.

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Which common characteristic of planets do Saturn and Earth share?

They have rings.
They have moons.
They are made of rock.
They have thick atmospheres.

Answers

i believe it’s
“they have thick atmospheres”
i hope i’m right and this helped you

The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

What is moons of planets?

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

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How much work is done by the force if the object moves from x = 0.15 m to x = 0.60 m ?

Answers

The work done by the force if the object moves from x = 0.15 m to x = 0.60 m is 0.24 J

What is work done by a force?

The work done by a force is defined as the product of force and distance traveled.

Work done = force * distance

Work done between 0.15 m to 0.25 m = 0.6 * (0.25 - 0.15)

Work done between 0.15 m to 0.25 m = 0.6 * (0.10)

Work done between 0.15 m to 0.25 m = 0.06 J

Work done between 0.25 m to 0.50 m = 0.4 * (0.50 - 0.25)

Work done between 0.25 m to 0.50 m = 0.4 * (0.25)

Work done between 0.25 m to 0.50 m = 0.1 J

Work done between 0.50 m to 0.60 m = 0.8 * (0.60 - 0.50)

Work done between 0.50 m to 0.60 m = 0.8 * (0.10)

Work done between 0.50 m to 0.60 m = 0.08 J

Total work done = 0.06 + 0.08 + 0.1

Total work done = 0.24 J

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How much work is done by the force if the object moves from x = 0.15 m to x = 0.60 m ?

12. The distortion of the Earth's crustal plates is an example of shear on a large scale. A particular crustal rock has a shear modulus of 1.5 x 10¹0 Pa What shear stress is involved when a 10-km layer of this rock is sheared through a distance of 5.0 m? (2) Figure 4: Road destroyed by shear flow/stress​

Answers

The shear stress involved when a 10-km layer of this rock is sheared through a distance of 5.0 m is 7.5 x 10⁶ Pa.

How the shear stress is calculated

To calculate the shear stress, we can use the equation:

τ = G × γ

where τ is the shear stress, G is the shear modulus, and γ is the shear strain.

First, let's calculate the shear strain:

γ = Δx / h

where Δx is the distance the layer is sheared through (5.0 m), and h is the thickness of the layer (10,000 m).

γ = 5.0 m / 10,000 m = 5.0 x 10^-4

Now we can calculate the shear stress:

τ = G × γ

τ = (1.5 x 10^10 Pa) × (5.0 x 10^-4)

τ = 7.5 x 10^6 Pa

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First to answer gets brainliest

First to answer gets brainliest

Answers

Answer:

has a charge

Explanation:

Answer:

gain electrons

Explanation:

I looked it up and that was what I found

side note: ions do have a charge

What is meant by electricity and magnetism

Answers

Electricity is just the flow of electrons or charges from a point of production through a conductor, to another point where it can be utilized or converted to another form of energy.

Magnetism is the force exerted by magnets when they attract or repel each other. Magnetism is caused by the motion of electric charges from two or more magnetic substances.

Answer:

By Electricity.. We mean the Flow of electrical power or Charge.

While Magnetism is a phenomenon that occurs from or by the Motion of Charges

Why do total solar eclipses not happen every month when there is a new moon?

Answers

Answer: Eclipses do not happen at every new moon, of course. This is because the moon's orbit is tilted just over 5 degrees relative to Earth's orbit around the sun. For this reason, the moon's shadow usually passes either above or below Earth, so a solar eclipse doesn't occur.

Explanation:   :>

A fast train has a speed of 181 km/hr. Because its wheels have a limited grip to the railway, the train must not accelerate at more than 0.058g (where g = 9.81 m/s2) while turning, or it will derail. What is the smallest radius of curvature for the track that the train can tolerate? If there is a curve of radius 1.100 km, what speed must the train mantain to keep the acceleration at the limit?

Answers

a. The the smallest radius of curvature for the track that the train can tolerate is 4.44 km

b. The speed must the train mantain to keep the acceleration at the limit is 25 m/s

a. What is the smallest radius of curvature for the track that the train can tolerate?

Using the equation for centripetal acceleration, we find the radius of the circle the train can tolerate.

So, centripetal acceleration a = v²/r where

v = speed of train and r = radius of curvature of track.

What is the radius of curvature of the track?

Making r subject of the formula, we have

r = v²/a

Given that the train has a speed of 181 km/hr and its acceleration must not exceed 0.058g, we have that

v = 181 km/hr = 181 × 1000 m/3600 s = 50.28 m/s and a = 0.058g = 0.058 × 9.81 m/s² = 0.569 m/s²

So, substituting the values of the variables into the equation for r,we have

r ≥ v²/a

r ≥ (50.28 m/s)²/0.569 m/s²

r ≥ 2528.0784 m²/s²/0.569 m/s²

r ≥ 4443.02 m

r ≥ 4.44 km

So, the the smallest radius of curvature for the track that the train can tolerate is 4.44 km

b. If there is a curve of radius 1.100 km, what speed must the train mantain to keep the acceleration at the limit?

Using the equation for centripetal acceleration, we find the radius of the circle the train can tolerate.

So, centripetal acceleration a = v²/r where

v = speed of train and r = radius of curvature of track.What is the speed of the train?

Making v subject of the formula, we have

v = √ar

Given that there is a curve of radius 1.100 km and its acceleration must not exceed 0.058g, we have that

r = 1.100 km = 1100 m and a = 0.058g = 0.058 × 9.81 m/s² = 0.569 m/s²

So, substituting the values of the variables into the equation for r,we have

v = √ar

v = √(0.569 m/s² × 1100 m)

v = √(625.9 m²/s²)

v = 25.02 m/s

v ≅ 25 m/s

So, the speed must the train mantain to keep the acceleration at the limit is 25 m/s

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Please help me on these four question

Please help me on these four question

Answers

Answer:

Q4 : False

Q5: False

Explanation:

Those acts are morally praiseworthy that are done out of a sense of duty rather than for the consequences that are expected, particularly the consequences to self.  

What is the force required to accelerate a 500 kg object at a rate of 10 m/s^2?

Answers

Answer:

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

Explanation:

The force required to accelerate an object can be calculated using the formula:

force = mass x acceleration

where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.

In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:

force = mass x acceleration

force = 500 kg x 10 m/s^2

force = 5000 N

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

A 65 kg-mass person stands at the end of a diving board, 1.5 m from the board's pivot point. Determine the torque the person is exerting on the board with respect to the pivot point. Show your work.

Answers

Answer:

Explanation:

The torque is given by the formula:

τ = F × r × sin(θ)

where τ is the torque, F is the force applied, r is the distance between the force and the pivot point, and θ is the angle between the force and the lever arm.

In this case, the person's weight is the force being applied, and it can be calculated as:

F = m × g

where m is the mass of the person and g is the acceleration due to gravity (9.81 m/s^2).

F = 65 kg × 9.81 m/s^2 = 637.65 N

The distance between the person and the pivot point is 1.5 m, so r = 1.5 m.

The angle between the person's weight and the lever arm is 90 degrees, so sin(θ) = 1.

Therefore, the torque the person is exerting on the board is:

τ = F × r × sin(θ) = 637.65 N × 1.5 m × 1 = 956.475 N·m

So the person is exerting a torque of 956.475 N·m on the diving board with respect to the pivot point.

Three different scientific institutions provide data about how much the annual global temperature has deviated from the norm in the years 1880 to 2014. The nort is
based on the temperatures of a base period, from 1951 to 1980
Institution A's data show that the annual global temperature deviated from the norm by 0.75°C in 2010
Institution B's data show that the annual global temperature deviated from the norm by 0.72°C in 2010
Institution C's data show that the annual global temperature deviated from the norm by 0.77°C in 2010.
Which are accurate statements about this data? Select the two correct answers
(1 point)

Answers

Based on the findings above, the accurate statements are:

B. The institutions have not yet gathered enough data for scientists to draw a conclusion about whether the annual global temperature is gradually increasing.C. The data gathered by each institution is very similar to the data gathered by the other institutions.

What are the accurate statements?

The information that all three institutions gathered is quite similar with their results showing a range of annual temperature deviation of 0.05°C in 2010.

However, this data is not enough to say that temperatures are rising gradually because there is no information on temperatures from the previous years.

Find out more on annual temperatures at https://brainly.com/question/27043563.

short note on how to measure with Metre rule Micrometre screw gauge Vernier Caliper ​

Answers

Hold the measurement target between the screw gauge's anvil and spindle while applying light pressure. the main size reading of the a circular scale just before zero.

How are a vernier caliper and screw gauge used?

Vernier calipers can be used for alike external and internal measurements, while screw gauges can only be used for external measurements. A vernier caliper has a minimum count of 0.001 cm while a screw gauge has a minimum count of 0.01 cm.

What is the purpose of a metre ruler?

This metre ruler, commonly known as a metre stick, is used to measure short distances and lengths up with one metre. It is a measuring tool used to determine distances and rule straight lines in engineering drawings, geometry, engineering, printing, and construction.

To know more about circular scale visit:

https://brainly.com/question/23849016

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