Which is an example of an applied force?

Answer:

C: H₂

Explanation:

H₂ (Two hydrogen atoms) is a nonpolar bond, also known as a diatomic molecule. They form a nonpolar covalent bond because their difference in electronegativity is 0.

Answer:

A

Explanation:

The correct answer would be the availability of krill.

A limiting factor is a substance or condition whose presence/absence can prevent a population from reaching its potential. Limiting factors can be biotic (living) or abiotic (non-living). Biotic factor includes the presence of competitive organisms in a population while abiotic factor includes food.

In the case of the blue whale, its diet is krill. Hence, its survival is largely dependent on the availability of krill. Otherwise, the blue whale might starve. Therefore, the availability of krill is a limiting factor for the population of whales.

The correct option is A.

Answer:

A. The balloon will be attracted to the cloth.

Explanation:

To oppisites attract.

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

The value of electric flux is 2.45N.m²/C.

A flat sheet of paper of area 0.130 m² is oriented so that the normal to the sheet is at an angle of 56 ∘ to a uniform electric field of magnitude 18 N/C.

The electric flux through the paper is given by;

ϕ=E.A.cosθϕ

= Electric fluxE

= Electric field intensityA

= Area of the surfaceθ

= Angle between electric field intensity and normal to the surface

Given,E = 18 N/C A = 0.130 m² θ = 56°

The electric flux through the paper is :

ϕ=E.A.cosθϕ

= (18 N/C)(0.130 m²)cos56°ϕ

= 2.45 N.m²/C

The electric flux through any closed surface is proportional to the charge enclosed by the surface. The electric flux through an open surface can be calculated by multiplying the electric field intensity with the area of the surface and the cosine of the angle between the electric field intensity and the normal to the surface.

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Complete question:

A flat sheet of paper of area 0.130 m2 is oriented so that the normal to the sheet is at an angle of 56 ∘ to a uniform electric field of magnitude 18 N/C .Find the amount of elctric flux passing through the sheet?

Using the given mass of the compound (0.520 g) and the calculated moles, we can determine the molar mass of the compound.

To find the molar mass of the compound, we can use the formula:

ΔT = Kf * m

where ΔT is the freezing point depression, Kf is the cryoscopic constant (in this case, 3.90 °C/m), and m is the molality of the solution.

First, we need to calculate the molality (m) of the solution:

m = moles of solute / mass of solvent (in kg)

The mass of the solvent (lauric acid) is given as 4.62 g. Since the unknown compound is a solute, we need to convert its mass to moles:

moles = mass / molar mass

Given that the mass of the unknown compound is 0.520 g, we can now calculate the moles of the compound.

Next, we convert the mass of the solvent to kg by dividing by 1000:

mass of solvent (lauric acid) = 4.62 g / 1000 = 0.00462 kg

Now we can calculate the molality:

m = moles of solute / mass of solvent = (moles of the compound) / (mass of solvent)

Finally, we can use the freezing point depression formula to find the molar mass of the compound:

ΔT = Kf * m

Substituting the given values:

4.20 °C = 3.90 °C/m * m

Now solve for m:

m = (4.20 °C) / (3.90 °C/m)

Once we have the molality, we can calculate the moles of the compound:

moles = molality * mass of solvent (in kg)

Finally, we calculate the molar mass:

molar mass = mass of solute / moles of solute

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According to the stoichiometry of the chemical equation, 0.895 moles of aluminium metal is needed to produce 500. g of Iron.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

53.96 g Al gives 111.68 g Fe thus 50 g Fe requires 50×53.96/111.68=24.15 g which is 24.15/26.98 = 0.895 moles.

Thus,  0.895 moles of aluminium metal is needed to produce 500. g of Iron.

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The correct option from the given statements concerning mixtures is (d) more than one correct response.

The statement (a) "The composition of a homogeneous mixture cannot vary" is incorrect as the composition of a homogeneous mixture can vary. For example, a mixture of salt and water is homogeneous and its composition can vary depending on the amount of salt and water mixed in it.

The statement (b) "A homogeneous mixture can have components present in two physical states" is correct. Homogeneous mixtures are mixtures that are uniform throughout their composition, meaning that there is no visible difference between the components of the mixture. For example, a mixture of ethanol and water is homogeneous and its components are present in two physical states (liquid and liquid).

The statement (c) "A heterogeneous mixture containing only one phase is an impossibility" is incorrect. A heterogeneous mixture is a mixture where the components are not evenly distributed and the mixture has different visible regions or phases. However, it is possible for a heterogeneous mixture to contain only one phase. For example, a mixture of oil and water is heterogeneous but can have only one phase.

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Answer:

Graph A

Explanation:

Answer:

A. Graph A

Explanation:

The option that directly contributes to global climate change by releasing carbon dioxide into the atmosphere is generating electricity at a nuclear power plant. Nuclear power plants use nuclear reactions to produce electricity, and in the process, they emit carbon dioxide.

This is because the construction and maintenance of nuclear power plants require the use of fossil fuels, which are burned to produce the necessary energy. This, in turn, releases carbon dioxide into the atmosphere. The other options, such as using foams and packing materials that contain chlorofluorocarbons, transporting products from one continent to another on a cargo ship, and growing fast-growing crops in open fields, contribute to global climate change indirectly, through processes such as deforestation, which releases carbon dioxide, or the use of fossil fuels in transportation. In conclusion, generating electricity at a nuclear power plant directly contributes to global climate change through the direct release of carbon dioxide into the atmosphere.

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The number of dilutions required to reach 2.5% as the final concentration would be 2.

Any dilution in which the concentration is reduced by the same amount in each subsequent stage is referred to as a serial dilution.

In serial dilutions, the original volume divided by the final amount is known as the dilution factor.

\(DF = \frac{V_i}{V_f}\)

Now we are given that we must do 50% serial dilution, which indicates that the concentration must be reduced to half of its starting value after each dilution.

∴ \(DF=\frac{10}{50}\) × \(100\)

DF = 2

This indicates that starting with a 10% concentration, a single dilution would result in a 5% concentration. And again diluting this 5% concentration would result in a 2.5% concentration.

Hence, the number of dilutions required to reach 2.5% as the final concentration would be 2.

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Answer:

Explanation:

Repeated tests help determine whether the hypothesis is always true in different circumstances. Repeatedly testing a hypothesis qualifies it to be accepted as a theory.

0.15l to one significant figure 0.1L.When we express a measurement to one significant figure, we round the value to the nearest number that has only one non-zero digit.

When we say "0.15L to one significant figure," what we mean is that we want to express the quantity 0.15L to the nearest order of magnitude. In other words, we want to round the value to a single significant digit. To do this, we look at the first non-zero digit in the number, which in this case is "1." We keep this digit and drop all the rest. Since the next digit after "1" is "5," which is greater than or equal to 5, we round up. Therefore, 0.15L to one significant figure is 0.1L. It's important to note that expressing a quantity to one significant figure means that we're sacrificing precision for simplicity. We're essentially saying that the exact value doesn't matter as much as the order of magnitude, and that the value is likely to be within a certain range of values rather than an exact value.

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The correct option is C. Erosion is the process by which the earth surface get worn down. It involves the removal of soil, rocks or dissolved material from one location and its transportation to another location.

Therefore, the molarity of the solution is 0.8 M when 20.2 g of potassium nitrate (KNO3) is dissolved in 250.0 ml of water.

To calculate the molarity of the solution, we need to first find the number of moles of potassium nitrate present in the solution. The molarity of a solution is defined as the number of moles of solute present per liter of solution.
The molar mass of potassium nitrate (KNO3) is 101.1 g/mol.
First, we need to convert the volume of water from milliliters to liters.
250.0 mL of water = 0.250 L of water
Next, we can calculate the number of moles of potassium nitrate present in the solution:
moles of KNO3 = mass of KNO3 / molar mass of KNO3
moles of KNO3 = 20.2 g / 101.1 g/mol
moles of KNO3 = 0.2 moles
Now that we know the number of moles of potassium nitrate present in the solution, we can calculate the molarity:
Molarity = moles of solute / liters of solution
Molarity = 0.2 moles / 0.250 L
Molarity = 0.8 M
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The maximum amount of strong base that can be added to the buffer without significantly changing the pH is 0.35 mol.

Sodium carbonate is a white, odorless powder that is commonly used in various applications such as in the manufacture of glass, soaps and detergents, water softening, and as a food additive. It is an ionic compound made up of sodium cations (Na+) and carbonate anions ( 2-). It is also known as washing soda, soda ash, or sal soda.

According to given data, Number of moles of NaH = 0.35 mol. To calculate the initial pH of the buffer, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant of the weak acid in the buffer (in this case, carbonic acid, ), [A-] is the concentration of the conjugate base (in this case, bicarbonate ion, H-), and [HA] is the concentration of the weak acid (in this case, carbonic acid, ).

The pKa of carbonic acid is 6.35, and the concentrations of H- and  can be calculated using the initial amounts of NaH  and Na2and the stoichiometry of the reaction:

[H-] = [NaH] = 0.35 mol / (0.35 mol + 0.50 mol) = 0.411 M

[NaH] - [H-] = 0.35 M - 0.411 M = -0.061 M

substituting these values into the Henderson-Hasselbalch equation, we get:

pH = 6.35 + log(0.411 / (-0.061))

pH = 9.17

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Answer:

C Tympanic membrane

Explanation:

due to the nerved gathered inside the membrane can cause a nauseous feeling.

Aerobes are organisms that require oxygen to grow and survive. The correct answer is: aerobes.

They have metabolic pathways that depend on the presence of oxygen for efficient energy production through aerobic respiration. Without oxygen, aerobes cannot carry out their metabolic processes effectively.

Facultative anaerobes, on the other hand, can grow and survive in the presence or absence of oxygen. They have the ability to switch between aerobic and anaerobic metabolic pathways depending on the availability of oxygen. In the presence of oxygen, facultative anaerobes can utilize aerobic respiration, and in the absence of oxygen, they can switch to anaerobic fermentation.

Anaerobes are organisms that do not require oxygen for growth and can even be inhibited or killed by its presence. They have metabolic pathways that allow them to carry out fermentation or other anaerobic processes for energy production.

Therefore, the correct answer is aerobes, as they specifically require oxygen to grow.

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The fact is, the cheap fruit has probably already been picked when it comes to finding new mineral wealth.

According to a group of specialists, the present high production rate will cause some finite metals, including gold, to run out limited are our gold holdings  Scientists have determined when the rare metal will vanish, and it will happen in just 27 years, in 2050.

Deep ocean mines, essentially level the planet's surface to collect resources, cause numerous environmental issues. The loss of natural land has the most immediate effects at mining sites.

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Enthalpy change of Pentane (C5H12)  that burns is -3,270.5  kJ

Enthalpy change is defined as the difference in enthalpy of total products and reactants, each multiplied by the respective moles. It is expressed as ΔH°rxn

The formula for calculating the enthalpy change of a reaction is:

ΔH°rxn =∑[n x ΔH°f(product) - ∑[n x ΔH°f(reactant)]

The equilibrium reactions are:

C₅H₁₂(l) + 8O₂(g) ⇒ 5CO₂(g) +6H₂O(g)

ΔH°f(CO₂)(g) = -393.5 kJ/mol

ΔH°f(H₂O)(g) = - 241.8 kJ/mol

ΔH°f(C₅H₁₂)(l) = -146.8 kJ/mol

ΔH°f(O₂)(g) = 0 kJ/mol

The equation for the enthalpy change for the above reaction is:

ΔH°rxn =∑[n x ΔH°f(product) - ∑[n x ΔH°f(reactant)]

ΔH°rxn =∑[(n(CO₂) x ΔH°f(CO₂)) + (n(H₂O) x ΔH°f(H₂O)) ]- ∑[(n x ΔH°f(C₅H₁₂)) + (n x ΔH°f(O₂))]

ΔH°rxn =[( 5 x -393.5) + (6 x - 241.8 ) ]- [(1 x -147.8) + (8 x O₂)]

ΔH°rxn = -3,418.3 -(-147.8)

ΔH°rxn = -3,270.5  kJ

Therefore, the enthalpy of burning 1 mole of pentane is -3,270.5  kJ

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Answer:

See explanation

Explanation:

In Rutherford's experiment, a gold foil was bombarded with positively charged alpha particles. A zinc sulphide screen was used to observe the movement of the alpha particles during the experiment.

A few particles passed through without deflection while some particles were deflected through large angles.  This observation led Rutherford to the conclusion that the atom was made up of a dense positively charged nucleus where most of its mass was concentrated.

Answer:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Best regards!

The first step in this calculation is to know how many liters is equal to 1 gallon, and the value is 3.785 liters, so now we have to make the following calculation:

1 gal = 3.785 Liters

30.0 gal = x Liters

x = 3.785 * 30.0

x = 114 Liters

Answer:

Lithium has two naturally occurring isotopes. Lithium-6 has an atomic mass of 6.015 amu. Lithium-7 has an atomic mass of 7.016 amu. The average atomic mass of lithium is 6.941 amu.

Explanation:

The heat capacity of the object is 5.67 × 10² J/°C. This means that it requires 5.67 × 10² J of heat energy to raise the temperature of the object by one degree Celsius.

The heat capacity of an object is defined as the amount of heat energy required to raise the temperature of the object by one degree Celsius (or one Kelvin). It is usually denoted by the symbol "C" and has the unit joules per degree Celsius (J/°C) or joules per Kelvin (J/K).

In this case, we are given that an object absorbs 1.70 × 10⁴ J of heat and its temperature increases from 45.0°C to 75.0°C. To find the heat capacity of the object, we can use the formula:

Heat Capacity (C) = Heat Absorbed (Q) / Temperature Change (ΔT)

ΔT = T_final - T_initial

Plugging in the given values:

Q = 1.70 × 10⁴ J

ΔT = 75.0°C - 45.0°C = 30.0°C

Using the formula, we can calculate the heat capacity:

C = Q / ΔT = (1.70 × 10⁴ J) / (30.0°C) = 5.67 × 10² J/°C

Therefore, the heat capacity of the object is 5.67 × 10² J/°C. This means that it requires 5.67 × 10² J of heat energy to raise the temperature of the object by one degree Celsius.

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