Which one of the following conditions would always result in an increase in the internal energy of a system? A) The system loses heat and does work on the surroundings. B) The system gains heat and does work or the surroundings. C) The system loses heat and has work done on it by the surroundings. D) The system gains heat and has work done on it by the surroundings. E) None of the above is correct

Answer:Newton’s first law

Explanation:

Answer: 2M + 3Q2 -----> 2MQ3

Explanation:

2 Ms either side, and 6 Qs either side

Answer:

Zn ,Cd and Hg has low melting points because - These have all their electrons paired.

Explanation:

Hence , the correct option is A (These have all their electrons paired).

If a medicine has a dosage of 20mL, there are 757 doses in a 4 gallon bottle of medicine.

A medicine is a substance or preparation that is used to prevent, treat, or alleviate symptoms of a disease or medical condition.

To calculate the number of doses in a 4 gallon bottle, we first need to know the number of milliliters in 4 gallons.

1 gallon = 3,785.41 milliliters (ml)

Thus, 4 gallons = 4 × 3,785.41 = 15,141.64 ml

Given that 1 dose is 20 ml, the number of doses in a 4 gallon bottle is :

Number of doses = Total volume of medicine / DosageNumber of doses = 15,141.64 / 20

Number of doses = 757.08

Hence, there are 757 doses in a 4 gallon bottle of medicine.

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Answer:

Explanation:

Molecular weight of Al: 27

Molecular weight of O: 16

Percentage composition of Al by weight in Al2O3

= (27*2) / (27*2 + 16*3)

= 0.5294

In 200 grams of Al2O3, there are

= 200*0.5294

= 105.88 grams of Al

77.18 grams of Al was produced in the experiment.

Percent yield for the experiment

= product mass / reactant mass * 100%

= 77.18 / 105.88 * 100%

= 72.89%

Answer:moles or atom. The SI base unit for amount of substance is the mole. 1 mole is equal to 6.0221415E+23 atom. Note that rounding errors may occur, so always check the results.

Explanation:

The element with electronic configuration 2s1, which is lithium, has a violent reaction with cold water.

The most reactive metals in the periodic table are the alkali metals (Li, Na, K, Rb, Cs, and Fr); they all react with cold water violently or even explosively, displacing hydrogen. In the reduction of water to hydrogen gas (H2) and the metal ion hydroxide (OH), Group 1 Metal (M) is oxidised to its metal ions.

The second most reactive metals in the periodic table are the alkaline earth metals (Be, Mg, Ca, Sr, Ba, and Ra), which also exhibit increased reactivity in higher periods like the Group 1 metals. The only alkaline earth metal that does not react with water or steam, even when heated to a high temperature, is beryllium (Be).  Furthermore, beryllium has an exterior oxide layer that is robust, which reduces its reactivity at lower temperatures.

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Answer:

Explanation:

1. Topic: Chemistry

ElementFirst Ionization Energy (kJ/mol) Lithium520Sodium496Rubidium403Cesium376According to the above table, which is most likely to be the first ionization energy for potassium?  

2. Topic: Chemistry, Atom

The correct set of four quantum numbers for the valence electrons of the rubidium atom   (Z=37)  is:  

3. Rubidium and cesium are pyrophoric. Here the term pyrophoric means:

Answer:

Fossil fuels release greenhouse gases and are non renewable

Dimethylhydrazine (CH₃)₂NNH₂ is a fuel used for the Apollo Lunar Descent Module, and N₂O₄ is the oxidant. During the reaction, H₂O, N₂, and CO₂ are produced.

The fuel and oxidizer were stored separately to prevent any accidental reaction before use. Once the engines were ignited, the dimethylhydrazine and N₂O₄ mixed and reacted, producing energy and the products mentioned above.

The fuel used in Apollo Lunar Descent Module was dimethylhydrazine (CH₃)₂NNH₂, whereas the oxidant was N₂O₄. The two substances were stored separately, and the reaction was initiated only when they were mixed. The reaction between the fuel and oxidant produced H₂O, N₂, and CO₂.

The reaction between dimethylhydrazine and nitrogen tetroxide was exothermic and highly energetic.The reason why dimethylhydrazine was chosen as the fuel is that it is highly flammable and can quickly produce large amounts of heat and energy when mixed with an oxidant.

This makes it an ideal fuel for rocket engines, especially those used in space exploration, where high-performance and efficiency are critical.

The reaction between dimethylhydrazine and nitrogen tetroxide is also highly stable and controllable, making it suitable for use in the Apollo Lunar Descent Module.

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A block of ice is first in a solid state when it is placed in a frying pan, which means that the particles are vibrating and moving slowly while being firmly packed together.  

The state of matter will change from a solid to a liquid as the pan's temperature rises, which will increase the thermal energy in the ice cube and cause the particles to slide instead of vibrate.

The ice will have turned into water by then, the water will ultimately transform into water vapor and then into a gas.

Therefore, changes happen when a block of ice is placed in a frying pan the temperature of the pan rises because as the particles heat up, they will travel more quickly and expand.

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Answer:

A) Chemical Change

Explanation:

Chemical changes occur when bonds are broken and formed between molecules or atoms. This means that one substance with a particular set of properties (such as melting point, color, taste, etc.) is turned into a different substance with different properties.

Answer:

The first ionization energy for K is less than Ca because Ca has a larger effective nuclear charge. There is a large increase in the second ionization energy for K compared to Ca because removal of the second electron from K is a core electron that is in a quantum shell closer to the nucleus.

Explanation:

The volume of water that must be add is 20 mL. Volume of water that must add is new volume after dilution minus initial volume.

As per data given:

Initial volume (V1) = 40 mL = 0.040 L

Initial molarity(C1) = 9.0 M

New molarity (C2)= 6.0 M

As we want to know to the new volume of water(V2). We have to use dilution formula where the formula is C1 x V1 = C2 x V2. So, the calculation would be:

9.0 x 0.040 = 6.0 x V2

V2 = 0.06 L

V2 = 60 mL

Since the addition water is the difference between V2 and V1:

Volume add = V2 -V1

Volume add = 60 - 40

Volume add = 20 mL

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Answer:

9

Explanation:

mass number = protons + neutrons

= 4 + 5 = 9

Answer:

People may seem and act normally during the fugue, or they may appear moderately bewildered and draw no notice. When the fugue is over, however, people are thrown into a new scenario with no recall of how they got there or what they were doing.

Explanation:

Answer: ummmm

Explanation:

Answer:

Explanation:

Tums is an over-the-counter (OTC) antacid. It's used to treat heartburn, also known as acid reflux. Tums can also be used to treat other symptoms of indigestion. It's usually safe to drink alcohol when taking Tums

LEAST TO MOST POLAR- hexane,diethyl ether,acetone,n-propanol,water ,methanol

Considering the problem  we can say that the kids are compared to be more polar or smaller molecular weight compounds. The more polar compounds interact with silica more just as the kids bus stopped at every point and reached the destination late. Whereas, the adult bus is compared to be less polar compounds or high molecular weight which interacts less and reaches the destination faster.

Thus more polar compounds reaches the destination late whereas less polar compound reaches first.

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The expression relating the concentration of a gas in \(\mu g/m^-^3 (X)\) with the concentration expressed in ppm (Y) is \(Y = (X/MW) * 10^6 / V\)

To derive an expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y), we can use the ideal gas law. The ideal gas law states that \(PV = nRT\), where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Rearranging the equation, we have \(n = PV/RT\)

To convert the concentration from \(\mu g/m^-^3 (X)\) to moles (n), we divide X by the molecular weight (MW) of the gas. Thus, \(n = X/MW\)

Combining the two equations, we have \(X/MW = PV/RT\)

Since the concentration expressed in ppm (Y) is the same as the number of moles per million parts of air, we can write \(Y = n * 10^6 / V\)

Substituting \(n = X/MW\), we get \(Y = (X/MW) * 10^6 / V\)

Therefore, the expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y) is:

\(Y = (X/MW) * 10^6 / V\)

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Complete question is:

Using the ideal Gas Law, derive an expression relating the concentration of a gas \(\mu_g^-^3 (X)\) with the concentration expressed in ppm (Y). (10 pts) Hint:- Ideal gas law \(PV= nRt -R = 0.0821 atm mol^-^1\)  −MW=X= molecular weight

Answer:

22.75 L CO2

Explanation:

Balance the Equation

C5H12  +  O2 ==>   CO2 + H2O        Balance the Carbons

C5H12  +  O2 ==>   5CO2 + H2O     Now balance the Hydrogens

C5H12  +  O2 ==>   5CO2 + 6H2O   Now count up the oxygens on the right.

5*O2 + 6O ==> 10 O + 6 O ===> 16 Oxygens.

You have 2 on the left. You have to multiply the oxygens by 8

C5H12  +  8O2 ==>   5CO2 + 6 H2O

The equation is now balanced.

Now find out how much oxygen is needed to burn 9.32 L of Pentane

1 Liter Pentane / 8 Liters Oxygen = 9.32 L Pentane / x     Cross multiply

x = 8 * 9.32

x = 74.56

Read this next sentence very carefully. You need 74.56 Liters of oxygen to burn all the pentane you have. There's not that much there. You only have 36.4 Liters of Oxygen. Some of the pentane won't get burned. Consequently there will be a shortage of CO2 as well.

Find out the number of Liters of Pentane that will be burned up.

1 / x =  8 / 36.4               Cross multiply

8x = 36.4                        Divide by 8

8x/8 = 36.4/8

x = 4.55 Liters of Pentane will be  used up.

Find the number of Liters of CO2

For every Liter of Pentane, 5 Liters of CO2 will be produced.

1/5 = 4.55/x                      Cross Multiply

x = 5 * 4.55

x = 22.75

The pH level considered neutral and desired for ice machine or cooling tower applications is 7.0. At this pH, the water is considered neither acidic nor basic, which helps to minimize corrosion and scaling.

Additionally, maintaining a pH of 7.0 in these systems can help to optimize the performance and efficiency of the equipment. However, depending on the specific application and the materials used in the equipment, the recommended pH level may vary slightly.

It is important to regularly monitor and adjust the pH level as needed to ensure proper functioning of the system and to prevent damage or degradation of the equipment.

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The type of bonding present in the compound CH3CH2CH2CH2Li is covalent bonding.

Covalent bonding occurs when atoms share electrons to form a stable molecular structure. In this compound, carbon (C) and hydrogen (H) atoms are bonded together through covalent bonds within the hydrocarbon chain (CH3CH2CH2CH2). The lithium (Li) atom is also bonded to one of the carbon atoms through a covalent bond.

Ionic bonding involves the transfer of electrons between atoms with a large difference in electronegativity, resulting in the formation of ions. Hydrogen bonding is a special type of intermolecular force that occurs between molecules containing hydrogen bonded to a highly electronegative atom (such as oxygen or nitrogen).

Since the compound CH3CH2CH2CH2Li consists of covalent bonds within the hydrocarbon chain and between carbon and lithium, the predominant type of bonding is covalent bonding.

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Explanation:

Observing a chemical and physical change in a substance can provide several benefits, including:

Understanding the nature of the substance: By observing chemical and physical changes, we can understand the properties of a substance and how it behaves under different conditions. This can help us predict how it will react in different situations and can inform decisions about how to handle it safely.

Identifying the presence of impurities: Chemical and physical changes can also indicate the presence of impurities or contaminants in a substance. This can be important in many different fields, including medicine, manufacturing, and environmental science.

Optimizing processes: By understanding the chemical and physical changes that occur in a substance, we can optimize processes to produce the desired results more efficiently. This can lead to cost savings and improved quality control in industries ranging from food and beverage to pharmaceuticals.

Developing new materials: Observing chemical and physical changes can also help scientists and engineers develop new materials with specific properties or characteristics. By manipulating the conditions under which a substance undergoes chemical and physical changes, new materials can be created with improved performance and functionality.

A. Absorption. Both processes are relatod to the way drugs are absorbed into the system.

Answer:

S2I3

I can't type it on the key board but it's S and 2 is small down side

I and the 3 is down side too

To differentiate between the ETC being blocked at the first step and the second step, the compound that can help differentiate between the two steps is cytochrome c. The correct option is c.

If the ETC is blocked at the first step (ubiquinone ⇒ Complex III), cytochrome c would be in its reduced state.

On the other hand, if the ETC is blocked at the second step (Complex III ⇒ cytochrome c), cytochrome c would be in its oxidized state.

Therefore, the correct option is c

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Complete question:

We have established that an inhibitor causing the accumulation of reduced ubiquinone could block the ETC at any of three possible steps.

1. ubiquinone⇒ Complex III

2. Complex III ⇒cytochrome c

3. cytochrome c⇒ Complex IV

What would be different if the ETC were blocked at the first step listed compared with the second step listed? You would find that ubiquinone was reduced in both cases, but there would be a differentiating factor.

You can differentiate between the first step listed and the second step listed by knowing the oxidation state of which compound.

a. Complex III

b. Complex IV

c. ubiquinone

d. Complex I

e. Complex II

f. cytochrome c

When solutions of silver (I) nitrate and hydrochloric acid are mixed, the spectator ions in the resulting reaction are only Ag+ and Cl-.

Explanation :

What is a spectator ion?

An ion that is present in a solution but is not involved in the chemical reaction is known as a spectator ion.

Spectator ions have the same charge and are not affected by the reaction. During the formation of a precipitate, spectator ions are not involved.

They are neither oxidized nor reduced in the course of a reaction.

When solutions of silver(I) nitrate and hydrochloric acid are mixed, the following reaction occurs:

AgNO3 (aq) + HCl (aq) → AgCl (s) + HNO3 (aq)

The equation shows that Ag+ and Cl- ions interact with each other to create solid AgCl.

Nitrate and hydrogen ions are considered spectator ions since they are not involved in the reaction's creation or destruction.Spectator ions can be identified by examining the charges of the ions involved in the reaction.

Any ions that are present on both sides of the chemical equation and have the same charge as the starting elements are considered spectator ions.

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The 85th percentile of blood pressure readings is approximately 137.64. a. To calculate the z-score for a blood pressure reading of 140, we can use the formula:

z = (x - μ) / σ

where x is the value (140 in this case), μ is the mean (121), and σ is the standard deviation (16).

Substituting the values into the formula:

z = (140 - 121) / 16

z ≈ 1.19 (rounded to two decimal places)

b. To find the proportion of Canadians with high blood pressure, we need to calculate the area under the normal distribution curve for values above 140. This can be done by finding the cumulative probability using the z-score.

Using a standard normal distribution table or a calculator, we can find that the cumulative probability corresponding to a z-score of 1.19 is approximately 0.881.

Therefore, the proportion of Canadians with high blood pressure is approximately 0.881 (rounded to four decimal places).

c. To find the proportion of Canadians with systolic blood pressure in the range from 100 to 140, we need to calculate the area under the normal distribution curve between these two values.

Using the z-scores corresponding to 100 and 140, we can find the cumulative probabilities for each value. The cumulative probability for a z-score of -1.25 (corresponding to 100) is approximately 0.105, and the cumulative probability for a z-score of 1.19 (corresponding to 140) is approximately 0.881 (as calculated in part b).

The proportion with systolic blood pressure between 100 and 140 is the difference between these two probabilities:

Proportion = 0.881 - 0.105 ≈ 0.776 (rounded to four decimal places)

d. The 85th percentile represents the value below which 85% of the blood pressure readings fall. To find the 85th percentile, we need to determine the z-score that corresponds to an area of 0.85 under the normal distribution curve.

Using a standard normal distribution table or a calculator, we can find that the z-score corresponding to an area of 0.85 is approximately 1.04.

To find the actual blood pressure reading at the 85th percentile, we can use the z-score formula:

x = μ + (z * σ)

Substituting the values:

x = 121 + (1.04 * 16)

x ≈ 137.64

Therefore, the 85th percentile of blood pressure readings is approximately 137.64.

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Answer:

2 valence electrons.

Explanation:

Valence electrons are the sum total of all the electrons in the highest energy level (principal quantum number n). Most transition metals have an electron configuration that is  

n

s

2

(

n

−

1

)

d

, so those  

n

s

2

electrons are the valence electrons