Which software license allows a user to download it, modify it, and then upload the software program with a different name? O GNU Open Left License O Copyright O GNU General Public License O Open Source License​

Answer:

They protect the entire hand from abrasion and punctures, and are a dependable, comfortable glove for a wide variety of jobs. Drivers' gloves are available in various types of leathers and can be unlined or lined for cold weather. Leather palm gloves provide maximum protection against abrasive and puncture hazards.

Gloves with leather palms offer the best defense against abrasive and puncture risks. They have leather palms and fingers and are constructed of dependable cotton or canvas.

Abrasive is defined as a substance, sometimes a mineral, used to shape or polish a product by rubbing, which causes some of the workpiece to be removed due to friction. Abrasives are a particular kind of extremely hard material that are utilized in a variety of residential, industrial, and technological applications. A portion of the work piece is worn away when the abrasive is rubbed against it.

These leather gloves each offer particular levels of comfort, protection, and durability. Some of these leather gloves are suitable for use by those handling dangerous chemicals and sparks. Some can provide cut protection to an extreme degree. For workers who handle heat and water, certain types of leather gloves are recommended.

Thus, gloves with leather palms offer the best defense against abrasive and puncture risks. They have leather palms and fingers and are constructed of dependable cotton or canvas.

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In a basketball game, point guard A intends the speed as 47.76 ft/sec, and the launch angle will be 41.084°.

The projectile motion is given as the motion of the object in the curved path near the earth's surface. The throwing of the ball will follow the projectile motion.

The missing image is attached below.

The given game situation consists of:

Velocity of shooting guard (vs) = 12 ft/sec.

Distance from B to C (sc) = 20 ft

Final height to catch the ball, 7 ft

The total distance to cover from B to C = 60 ft

Time is taken to reach B to C = Distance/Speed

Time to reach B to C = 20ft/12ft/sec

Time to reach B to C = 1.667 sec.

The time taken to cover the horizontal distance:

Distance = Velocity * Time

60³ = v₀cosθ * distance/time

60³ =  v₀cosθ * 20/12

v₀cosθ  = 36 ft/sec

The vertical movement can be given where, g = 32.2 ft/sec²:

s = s₀ + v₀sinθ * time + 1/2 -g time²

7 = s + v₀sinθ * 20/12 - 1/2 32.2 ft/sec² * (20/12)²

v₀sinθ = 31.3875 ft/sec

\(\rm v_0 =\sqrt{v_0sin\theta^2\;+\;v_ocos\theta^2}\)

Substituting the values:

v₀ = 47.76 ft/sec

The launch angle for the ball will be:

tanθ = v₀sinθ/v₀cosθ

tanθ = 31.3875/36

tanθ = 0.871

θ = 41.084°

Thus, the speed v₀ of the ball will be 47.76 ft/sec, and the launch angle will be 41.084°.

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Answer: Tl = - 13.3°C

the lowest outdoor temperature is - 13.3°C

Explanation:

Given that;

Temperature of Th = 21°C = 21 + 273 = 294 K

the rate at which heat lost is Qh = 5400 kJ/h°C

the power input to heat pump Wnet = 6 kw

The COP of a reversible heat pump depends on the temperature limits in the cycle only, and is determined by;

COPhp = Th/(Th - Tl)

COPhp = Qh/Wnet

Qh/Wnet = Th/(Th -Tl)

the amount of heat loss is expressed as

Qh = 5400/3600(294 - Tl)

the temperature of sink

( 5400/3600(294 - Tl)) / 6 = 294 / ( 294 - Tl)

now solving the equation

Tl = 259.7 - 273

Tl = - 13.3°C

so the lowest outdoor temperature is - 13.3°C

For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about one.

A particular disk is activated by mounting software, which makes its contents accessible to the computer's file system. A partition is created in the computer's file system for the mounted device when it is mounted.

A framework or foundation that supports or supports something else. Mounting is another word for support.

The procedure through which the operating system of a computer makes the files and directories on a storage device (such as a hard drive, CD-ROM, or network share) accessible to users via the computer's file system is known as mounting.

For surface-mounted and pendant-hung luminaires, mounting rods should be placed so that they develop about one.

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The discharge rate of the supply of water to the roof top is;

V' = 9.8641 L/s

The conditions given to us are;

- Water goes in atmosphere and so; p₂ = p_atm

- Velocity at point 1 is very small and so; V₁ ≈ 0

- Reference level is point 1

- Difference between pressures p₁ and p₂ is gauge pressure;

p_gauge = p₁ - p_atm

- There is no turbine and pump

From the conditions above, we can say that the Velocity V₂ can be gotten from the expression;

(p₁ - p_atm)/(ρg) + 0 + 0 + 0 = (V₂²/2g) + h + 0 + h_L

Making V₂ the subject gives us;

V₂ = √[(2p₁_gauge)/ρ - 2g(h + h_L)]

We are given;

p₁_gauge(air pressure in the tank)  = 300 KPa = 300000 Pa

ρ(density of water) = 1000 kg/m³

h (height above the water tank level) = 8 m

h_L(head loss) = 2 m

Thus;

V₂ = √[(2 * 300000/1000) - 2(9.8)(8 + 2)]

V₂ = 20.095 m/s

The discharge rate of the supply of water to the roof top is given by the formula;

V' = A₂ * V₂

Where A₂ is cross sectional area of pipe = πr² = π * (2.5/200)² = 4.90874 * 10⁻⁴ m²

Thus;

V' = 20.95 * 4.90874 * 10⁻⁴

V' = 9.8641 L/s

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Sodium hydroxide, NaOH, is a very useful compound in the chemical industry. Sodium hydroxide is used to make soap, detergent, paper, and many other products. It is also used to clean drains, dissolve grease, and other materials.

For commercial convenience, one form of sodium hydroxide that is sold commercially is the saturated solution. This solution is M, which is approximately by mass sodium hydroxide.

To prepare L of M solution, we must first find the number of moles of NaOH that will be required.

Then we will find the volume of the saturated solution that is required to make this solution.
To find the number of moles of NaOH that will be required, we will use the formula:

\(N = C x V\)Where, N = number of moles of NaOH, C = concentration of the solution, and V = volume of the solution.

In this case, C = M, which is the concentration of the solution that we want to make. And V = L, which is the volume of the solution that we want to make.

So,

\(N = M x LV = N / MC = 40% = 40 / 100 = 0.4 M\)

Volume of the saturated solution required to prepare the M solution:

\(V = N / MV = 4.69 L\)

We will require approximately \(4.69 L\)of the saturated solution to prepare L of M solution.

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Answer: I have 2 suggestions: one, maybe, maybe, use some of that metal tape that you get at hardware places, and: two, buy a new pipe (or pipes), two be sure that it won't happen again. Have a good day, and thanks for asking the brain!

Explanation:

A caisson is a watertight enclosure that can be pumped dry so that construction activities, such as the construction of piers can take place. A caisson is a watertight structure or chamber, usually made of wood, metal, or concrete, that is sunk to the bed of a river, lake, or ocean to provide a foundation or support for a bridge, building, or other structure.

A caisson is constructed onshore and then floated to the location where it is to be sunk into the water. Once in place, water is pumped out of the caisson, and construction workers enter the dry chamber to begin work on the foundation or support structure. The use of caissons has been an important development in the construction of bridges and other structures in areas with deep water or unstable soils.

A foundation called a caisson is used in construction on soft or deep water. It involves filling a series of large, watertight cylinders with concrete and sinking them into the ground. The base serves as a solid foundation for any subsequent structures. The construction of large structures like bridges, docks, and caissons is common.

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Answer:

final temperature = 26.5°

Explanation:

Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)

Initial temperature of water = 20° C

Density of water = 1000 kg/\(m^{3}\)

volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)

Initial temperature of copper block = 100° C

Density of copper = 8960 kg/\(m^{3}\)

Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)

Assumptions:

mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg

specific heat capacity of water c = 4186 J/K-kg

heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules

mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg

specific heat capacity of copper is 385 J/K-kg

heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules

total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules

this heat will be distributed in the entire system

heat energy of water within the system = mcT

where T is the final temperature

= 903 x 4186 x T = 3779958T

for copper, heat will be

mcT = 869.12 x 385 = 334611.2T

these component heats will sum up to the final heat of the system, i.e

3779958T + 334611.2T = 109.05 x \(10^{6}\)

4114569.2T = 109.05 x \(10^{6}\)

final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°

Answer:

Used to recall the direction a standard screw

The MMC of the hole diameter is 10.10 mm. The least material condition (LMC) is the smallest size limit of a part that is acceptable for use.  LMC is the smallest allowable size limit that will still allow the part to function as intended. In this case, we will calculate the LMC for a part with a length of \(35.00 ± 0.15 mm.\)

To calculate the LMC, we must subtract the tolerance from the nominal value. The nominal value is the target value of the part dimension. In this case, the nominal value is 35.00 mm.

LMC = Nominal Value - Tolerance LMC = \(35.00 - 0.15LMC = 34.85 mm\)

Therefore, the LMC for the given part is 34.85 mm.

The Maximum Material Condition (MMC) is the largest size limit of a part that is acceptable for use. In other words, MMC is the largest allowable size limit that will still allow the part to function as intended. In this case, we will calculate the MMC of the hole diameter with dimension \(10.0 ± 0.10 mm\).

To calculate the MMC, we must add the tolerance to the nominal value. The nominal value is the target value of the part dimension. In this case, the nominal value is 10.0 mm.

MMC = Nominal Value + Tolerance MMC = \(10.0 + 0.10MMC = 10.10 mm.\)

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Answer:

do the wam wam

Explanation:

The heat flux is =1038kW/m² , the heat lost per hour is =259.5 kW, the heat lost per hour using a sheet of soda- lime glass.

The thickness of steel( t) = 10mm = 10× 10^-³m

The temperature difference on both sides = 300-100

∆T = 200°C

But the formula for heat flux = q = k∆T/t

Where K = thermal conductivity for steel = 51.9W/mK.

Substitute the variables into the formula for heat flux;

q = 51.9 × 200/10 × 10-³

q = 10380 × 10³/10

q = 10380000/10

q = 1038000 W/m² = 1038kW/m²

To calculate the heat lost per hour if the cross sectional area is = 0.25 m2 use the formula q × A

= 1038kW/m² × 0.25 m2

= 259.5 kW.

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Answer:

The final velocity of the rocket is 450 m/s.

Explanation:

Given;

initial velocity of the rocket, u = 0

constant upward acceleration of the rocket, a = 18 m/s²

time of motion of the rocket, t = 25 s

The final velocity of the rocket is calculated with the following kinematic equation;

v = u + at

where;

v is the final velocity of the rocket after 25 s

Substitute the given values in the equation above;

v = 0 + 18 x 25

v = 450 m/s

Therefore, the final velocity of the rocket is 450 m/s.

Note that given the above , the optimal lot size is 63,246 and the total cost is $242,663

(a) This is a quantity discount model and the decision is to identify the optimal order quantity in the presence of discounts. We evaluate the order quantities at different unit prices using the econonmic order quantity equation as shown below:

For, price = Sl.00 per unit

Q = EOQ = √(2(20000)(400))/ (0.2 x 1)
= 30,984

Since Q > 19,999

We select Q = 20,000 (break point) and evaluate the corresponding total cost, which includes purchase cost + holding cost + order cost

Total Cost = (20,000) (12) (0.98) + (20000/2) (0.2) (0.98) + (20000) (12)/(20000) (400)
= $241, 960


Similarly we evaluate the EOQs at prices of p = 0.98 (Q = 31298) and p = 0.96 (Q = 31623)

which is not in the range so use Q = 40001).

The correspond total costs are S241,334 and $236,640

So, the optimal value of Q = 40001 and the total cost is S236,640

The cycle inventory is Q/2 = 40001/2 = 2000.5

(b) If the manufacturer did not offer a quantity discount but sold all plywood at 0.96 per square foot then Q = 31,623 and the total cost is    $ 233,436

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When parking uphill without a curb, turn your wheels to the right (towards the side of the road) to prevent your vehicle from rolling into traffic. Refer to local laws and your vehicle's manual for specific instructions.

When parking uphill without a curb, you should turn your vehicle's wheels to the right (towards the side of the road). Here's a general guideline to follow:

1. Bring your vehicle to a complete stop and engage the parking brake.

2. Turn the steering wheel completely to the right, which means turning it towards the side of the road.

3. If there is a roadway slope, position your vehicle's wheels against the edge of the road to prevent it from rolling.

By turning the wheels to the right, you create a safety measure that helps prevent your vehicle from rolling downhill into traffic if the parking brake were to fail. This way, the curb serves as a substitute for a curb, and the wheels are turned in the opposite direction to the one used when parking downhill.

However, it's essential to consult and follow the specific local laws and regulations regarding parking, as they may vary depending on your location. Additionally, always refer to your vehicle's owner's manual for any specific instructions related to parking or wheel positioning.

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Answer:

Explanation:

Enforcing OSHA, Occupational Safety and Health Administration, standards is not a job for electricians, lawmakers or tax collectors. The right answer is safety inspectors.

Answer:

Bluetooth is a slow wireless technology used to connect devices within a radius of about 30 feet. While Bluetooth technology is amazing, there are lots of bugs involved with Bluetooth devices, and there is still lots to be discovered in this area of tech.

You get a result immediately from Euler's formula:

e ^(i π/2) = cos(π/2) + i sin(π/2) = 0 + i * 1 = i

It is accurate to say that site engineering does not require particular consideration for soils with low percolation rates.

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Answer:

The City can grant higher budgets to emergency services like the Fire Department, so a higher budget will allow engineers & scientists to innovate new technology and add more fire stations across the city.

Explanation:

The probability that one will win back at least the cost of three tickets is approximately 0.31744. This is solved using Binomial Distribution Model.

The Binomial Distribution Model is a mathematical model of probability that allows one to decipher the probability of success of a group of possibilities within a range of specifically repeated processes.

Given that non-losing tickets (n) is: 5

Tickets gotten with non-losing probability p = 2/5 = 0.4

Note that probability here is given as:

Pr [X ≥ 3] = \(\sum_{x=3}^{5}.\)\(\binom{n}{x}\) pˣ (1-p)ⁿ⁻ˣ

→ \(\sum_{x=3}^{5}.\)\(\binom{n}{x}\) (0.4)ˣ (0.6)⁵⁻ˣ

= 992/3125

= 0.31744

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Answer:

B- Fluorinated gas

Explanation:

Answer:

B.) fluorinated gas

Explanation:

The radial load in bearing b when the motor is stopped with zero tension in the chain is 300 lb. It is logical that the load in the bearing is higher when the motor is stopped than when it is running and putting tension in the chain due to the principle of statics.

Here's why:When the motor is running, the chain is stretched due to the tension force applied to it. This tension force counteracts the radial load on the bearings, which is why the load is lower in this scenario.On the other hand, when the motor is stopped with zero tension in the chain, the weight of the load is entirely supported by the bearings.

The radial load on the bearing is given by the formula:Radial load on bearing = (Weight of load / Number of bearings) + Axial load due to belt tensionTherefore, when the motor is stopped with zero tension in the chain, the radial load on bearing b can be calculated as follows:Radial load on bearing b = (300 lb / 2) + 0Radial load on bearing b = 150 lbHence, the radial load in bearing b when the motor is stopped with zero tension in the chain is 150 lb.

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Answer:

Air is a gas

Explanation:

i think. beavuse it cant be a liqued or a solid. i dont think a plasma. i would answer gas

6.25×10⁻¹⁸ electrons will flow through a copper wire.

Electrons can be defined as the sum of atomic particles that is the career of negative charge, they are responsible for the chemical property of an element, the electrons are present in the shell.

Use formula ( I = ne/t )

Here,

number of electron

electron =1.6 x 10¯¹9 C

We have a relation between charge and current as

Charge = Current×time i.e

Q = i×t.

Now we have current = 10 amp & time = 10sec from given data.

Therefore charge Q = 10×1 = 100 coulombs.

Again we have a relation between charge and no of electrons

I.e no of electrons= total charge / 1.6×10⁻¹⁹

So, no of electrons = ( 100C/1.6×10⁻¹⁸ )

= 6.25×10⁻¹⁸ electrons.

Therefore, 6.25×10⁻¹⁸ electrons will flow through a copper wire carrying 10 amps current for 10 sec

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Answer:

10.5

Explanation:

Measuring a Brake Drum, the Brake Micrometer is set to a Base Drum Diameter of 10 Inches plus four notches, and the dial reads 22.  Diameter of the drum is 10.5.

Any straight line segment that cuts through the center of a circle and has ends that are on the circle is considered a circle's diameter in geometry. It is also known as the circle's longest chord.

The diameter of a sphere can be defined using either of the two methods. In more recent usage, the diameter can also refer to a diameter's length, or displaystyle d.

As opposed to a diameter, which refers to the line segment itself, one uses the term "diameter" in this context since all diameters of a circle or sphere have the same length, which is equal to twice the radius "displaystyle r.

Therefore, Measuring a Brake Drum, the Brake Micrometer is set to a Base Drum Diameter of 10 Inches plus four notches, and the dial reads 22.  Diameter of the drum is 10.5.

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Answer:

class helloSarah {

public static void main(String [] args) {

Name = "Hello Sarah";

System.out.print(Name);

}

}

Explanation:

The question seem incomplete; However, since the program is incorrect, I'll assume the question is to correct the given code;

The program segment was written in Java and the correct program is in the answer section

See bold texts for line by line explanation

This line declares the class name

class helloSarah {

This line declares the main method of the program

public static void main(String [] args) {

This line initializes string variable Name

String Name = "Hello Sarah";

This line prints the initialized variable

System.out.print(Name);

}

}

Answer:

class helloSarah {

public static void main(String [] args) {

Name = "Hello Sarah";

System.out.print(Name);

]

Explanation:

The correct answer is The correct answer is d. EVJ cable type is available in sizes ranging from 18 AWG to 500 kcmil and is rated for extra hard usage.

Additionally, it has thermoset insulation, which provides excellent resistance to high temperatures and chemicals. The thermoset insulation ensures that the cable can withstand the harsh environments of electric vehicle applications, where exposure to heat and chemicals is common.EVJ cable type is commonly used in electric vehicle charging stations, battery management systems, and other applications where high power is required. The range of sizes available makes it a versatile cable that can accommodate different power requirements. The extra hard usage rating ensures that the cable can withstand the rough handling that is typical in electric vehicle charging stations.

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Answer:

Cross pattern, according to the internet