Working as a seismologist, you find the epicenter of many earthquakes in a region. What features of earth's crust would you expect to find in this region?

Answers

Answer 1

Answer:

Explanation:

As a seismologist studying earthquakes in a particular region, you might expect to find certain features of the earth's crust in that region that are indicative of tectonic activity. Some examples of these features include:

Fault lines: These are fractures in the earth's crust where two tectonic plates have moved relative to each other, often resulting in earthquakes when the movement is sudden and violent.

Folded mountain ranges: When tectonic plates collide, the resulting pressure can cause the earth's crust to fold and form mountain ranges.

Volcanoes: Many earthquakes occur in regions with volcanic activity, as the movement of magma beneath the earth's surface can cause the ground to shake.

Plate boundaries: The boundary between two tectonic plates is often a zone of high seismic activity, as the plates grind against each other and cause earthquakes.

Seismic gaps: Some areas along a fault line may have experienced few or no earthquakes in recent history, and are therefore considered "seismic gaps." These areas may be more prone to earthquakes in the future as the pressure builds up.

By studying these and other features of the earth's crust, you can gain a better understanding of the underlying tectonic processes that contribute to earthquakes in the region.


Related Questions

Critically discuss why the environment in most communities continue to be dirty amidst the existence of local government structures​

Answers

Explanation:

# Unmanaged population distribution

# lack of sanitation programs

# lack of awareness programs

# lack of implementation of policies and rules

# carelessness of people and government

# Unmanaged waste disposal

A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg•m2. if the arms are pulled in so the moment of inertia decreases to 1.80 kg•m2, what is the final angular speed?
A) 2.25 rad/s
B) 6.25 rad /s
C) 0.81 rad/s
D) 4.60 rad/s

Answers

Refer to the photo taken.
Answer: B) 6.25 rad/s
A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kgm2. if the

How are clouds made. plz halp

Answers

Answer:

A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud. As long as the cloud and the air that its made of is warmer than the outside air around it, it floats!

Explanation:

A cloud is made up op liquid and water droplets.

Answer:

How are clouds made

Explanation:

When sunlight hits water it evaporates into the air and makes water droplets that we see as white fluufly clouds

A car weighing 10000 Newton on one foot of Area 200 meter^2 . How much Pressure is exerted on the Ground ?​

Answers

Question :-

A car weighing 10000 Newton on one foot of Area 200 meter² . How much Pressure is exerted on the Ground ?

Answer :-

Pressure exerted on the ground is 50 Pascals .

\( \rule {180pt} {2pt} \)

Given :-

Force = 10000 NArea = 200 m²

To Find :-

Pressure = ?

Solution :-

As per the provided information in the given question, we have been given that Force is 10000 Newton , Area is given 200 meter² . And, we have been asked to calculate the Pressure exerted on the Ground .

For calculating the Pressure , we will use the Formula :-

Pressure = Force / Area

Therefore , by Substituting the given values in the above Formula :-

⇒ Pressure = Force / Area

⇒ Pressure = 10000 / 200

⇒ Pressure = 50

Hence :-

Pressure = 50 Pascals .

\( \underline {\rule {180pt} {4pt}} \)

Answer:

50 Pa

Explanation:

Here,

→Force(F)=10000N

→Area(A)=200m²

As we have,

→Pressure=Force/Area

→Pressure=10000N/200m²

→Pressure=50 Pa

when three 20-ohm resisters are wired in poarallel and connected to a 10-volt source the total resistance of the circuit will be

Answers

Total resistance = R + 0Total resistance = 0.15 ohms The total resistance of the circuit when three 20-ohm resistors are wired in parallel and connected to a 10-volt source is 0.15 ohms.

When three 20-ohm resistors are wired in parallel and connected to a 10-volt source, the total resistance of the circuit will be 6.67 ohms (rounded to two decimal places).

When resistors are connected in parallel, their resistances are added reciprocally.

Therefore, the total resistance (R) of three resistors in parallel can be calculated as follows

                     :R = (1/R1) + (1/R2) + (1/R3)where R1, R2, and R3 are the resistances of the three resistors. To calculate the total resistance of the circuit, we need to substitute the values we know into the formula

. In this case, the resistance of each resistor is 20 ohms.

Therefore, we can write:R = (1/20) + (1/20) + (1/20)R = 3/20

Simplifying the fraction gives:  R = 0.15 ohms

Now we can calculate the total resistance of the circuit by adding the resistance of the three parallel resistors to the resistance of the source (which is negligible compared to the resistors).

Therefore: Total resistance = R + 0Total resistance = 0.15 ohms The total resistance of the circuit when three 20-ohm resistors are wired in parallel and connected to a 10-volt source is 0.15 ohms.

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Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?

Answers

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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explain why the average rate per square meter at which solar energy reaches earth is one-fourth of the solar constant

Answers

The average rate per square meter at which solar energy reaches Earth is one-fourth of the solar constant because of the scattering and absorption of solar radiation in the Earth's atmosphere.

Solar radiation from the Sun consists of electromagnetic waves that travel through space. However, when these waves reach Earth's atmosphere, they encounter various particles, molecules, and gases. These atmospheric constituents interact with the solar radiation in two main ways: scattering and absorption.

Scattering occurs when the solar radiation encounters particles or molecules in the atmosphere. These particles scatter the radiation in different directions, causing it to spread out. As a result, not all the solar radiation that reaches Earth's atmosphere directly reaches the surface, leading to a reduction in the amount of solar energy per square meter.

Absorption happens when certain gases in the atmosphere, such as water vapor, carbon dioxide, and ozone, absorb specific wavelengths of solar radiation. These absorbed wavelengths are then converted into heat energy, which contributes to the warming of the atmosphere. Again, this reduces the amount of solar energy that reaches the Earth's surface.

Both scattering and absorption processes collectively lead to a decrease in the amount of solar energy reaching Earth's surface. Consequently, the average rate per square meter at which solar energy reaches Earth is one-fourth of the solar constant, which is the amount of solar energy that would reach Earth's outer atmosphere on a surface perpendicular to the Sun's rays.

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the process of converting food into energy is called

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The process of converting food into energy is called cellular respiration. This process occurs in the mitochondria of cells and involves.

the breakdown of glucose and other organic molecules in the presence of oxygen to produce ATP, the primary source of energy for cellular activities. Cellular respiration is a complex series of biochemical reactions that involves several stages, including glycolysis, the Krebs cycle, and oxidative phosphorylation. These stages involve the transfer of electrons and protons between different molecules and the production of ATP through a process called chemiosmosis. The overall reaction of cellular respiration can be summarized as: glucose + oxygen → carbon dioxide + water + ATP.

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I need the answer of question (6) with explanation.​

 I need the answer of question (6) with explanation.

Answers

Grounding a Negatively Charged Object

If it is to have its charge removed, then it will have to lose its excess electrons. Once the excess electrons are removed from the object, there will be equal numbers of protons and electrons within the object and it will have a balance of charge.
The answer could either be:
A or D
Hope this helps!
Please give Brainliest!


How many times faster are plates moving at
7.3 cm/year than those moving at 1.3 cm/year?

Answers

Plates moving at 7.3 cm/year are approximately 5.615 times faster than those moving at 1.3 cm/year.

The speed at which plates move is determined by the relative motion between tectonic plates along their boundaries. To compare the speeds of plates moving at different rates, we can calculate the ratio between their velocities.Let's consider plates moving at 7.3 cm/year and 1.3 cm/year. To find the factor by which the faster plates are moving compared to the slower plates, we divide their velocities:

7.3 cm/year / 1.3 cm/year = 5.615

In other words, for every unit of time, the faster plates cover approximately 5.615 times the distance covered by the slower plates. This difference in speed can have significant implications for geological processes such as the accumulation of strain along plate boundaries, the occurrence of earthquakes, and the formation of mountain ranges. It highlights the dynamic nature of tectonic plate movements and their influence on Earth's geology and surface features.

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In the the table there is 20 kj of coal, how much energy in joules is 1g of coal?

Answers

Answer:

what do u meN by this i really don't know

a 0.5 kg ball is moving horizontally with a speed of 6 m/s to the right when it strikes a vertical wall. the ball rebounds with a speed of 4 m/s. what is the magnitude of the change in linear momentum of the ball

Answers

The magnitude of the change in linear momentum of the ball is 2 kg•m/s to the left.

When the ball strikes the wall, it experiences a sudden change in momentum due to the impulse provided by the wall. Since the wall is vertical, it does not move and therefore does not exert any horizontal force on the ball.

This means that the horizontal component of the ball's momentum is conserved, and the only change in momentum is in the vertical direction.

Using the principle of conservation of momentum, the initial momentum of the ball in the horizontal direction is:

p₁ = m₁v₁ = (0.5 kg)(6 m/s) = 3 kg•m/s

The final momentum in the horizontal direction is the same as the initial momentum, since there are no external forces acting in that direction.

In the vertical direction, the initial momentum is:

p₁ = m₁v₁ = (0.5 kg)(6 m/s) = 3 kg•m/s

After rebounding, the ball is moving in the opposite direction, so its velocity is -4 m/s. Therefore, the final momentum in the vertical direction is:

p₂ = m₁v₂ = (0.5 kg)(-4 m/s) = -2 kg•m/s

The change in momentum is the difference between the final and initial momentum in the vertical direction:

Δp = p₂ - p₁ = (-2 kg•m/s) - (3 kg•m/s) = -5 kg•m/s

Since the question asks for the magnitude of the change in momentum, we take the absolute value, which gives:

|Δp| = |-5 kg•m/s| = 5 kg•m/s

However, the question asks for the direction of the change in momentum as well. Since the final momentum is in the opposite direction of the initial momentum, the change in momentum is to the left.

Therefore, change in linear momentum is 2 kg•m/s to the left.

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Could you please help me with this question

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\(\begin{gathered} mass_{}ofthecablecar=m_c=2500\operatorname{kg} \\ massofthepeople=m_P=80(70\operatorname{kg})=5600\text{ kg} \\ g=9.81m/s^2 \\ h=950\text{ m} \\ t=\text{ }6\text{ minutes= 6(60s)=360 s} \\ A) \\ For\text{ total gain gravitational potential energy for the car} \\ P_C=\text{ }m_cgh \\ P_C=\text{ (}2500\operatorname{kg}\text{)(}9.81m/s^2\text{)(}950\text{ m)} \\ P_C=\text{ 23,298,750 J} \\ \text{The total gain gravitational potential energy for the car is 23,298,750 J} \\ \\ For\text{ total gain gravitational potential energy for the people} \\ P_P=\text{ }m_Pgh \\ P_P=\text{ (}5600\text{ kg)(}9.81m/s^2\text{)(}950\text{ m)} \\ P_P=\text{ 52,189,200 J} \\ \text{The total gain gravitational potential energy for the people is 52,189,200 J} \\ \\ B)\text{ } \\ \text{The total work is the sum of gain gravitational potential energy for the} \\ \text{car and people} \\ W_T=\text{23,298,750 }J+\text{52,189,200 J} \\ W_T=75,487,950\text{ J} \\ \text{The total work done by the motor }is\text{ }75,487,950\text{ J} \\ \\ C) \\ For\text{ the minimun power} \\ \text{Powe}=\frac{W_T}{t}=\frac{75,487,950\text{ J}}{\text{360 s}}=209,688.75\text{ W} \\ \text{The minimun power is }209,688.75\text{ W} \end{gathered}\)

Suppose that white light strikes a surface of flint glass at an angle of 60 degrees. The index of refraction of this dense glass for red light is 1.710, for green light is 1.723, and for blue light is 1.735. What is the order of colors you would see in the refracted light

Answers

The order of colors seen in the refracted light will be VIBGYOR, with blue light being refracted the most and red light being refracted the least.

When white light enters a medium with varying refractive indices, it undergoes dispersion, which means that different colors of the light will be refracted at slightly different angles. The extent of this separation depends on the difference in the refractive indices of the medium for different colors of light. This phenomenon is responsible for the rainbow colors we see in prisms and raindrops.

In this case, white light entering a surface of flint glass at an angle of 60 degrees will be refracted and separated into its component colors. The order in which these colors appear can be determined by calculating the angle of refraction for each color using Snell's law.

Assuming that the incident angle is measured from the normal to the surface, the angle of incidence, in this case, is 30 degrees (since the incident angle is 60 degrees). Using Snell's law, we can calculate the angle of refraction for each color:

For red light: angle of refraction = \($\arcsin\left(\frac{\sin(30)}{1.710}\right)$\) = 17.5 degrees

For green light: angle of refraction = \($\arcsin\left(\frac{\sin(30)}{1.723}\right)$\) = 17.1 degrees

For blue light: angle of refraction = \($\arcsin\left(\frac{\sin(30)}{1.735}\right)$\) = 16.7 degrees

Since blue light is refracted the most and red light is refracted the least, the order of colors in the refracted light will be violet, blue, green, yellow, orange, and red. This sequence of colors is commonly referred to as VIBGYOR.

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What is the answer for the first part of a? In kN

What is the answer for the first part of a? In kN

Answers

We are asked to determine the magnitude of the force that acts parallel to the nail. To do that we will add the torque that acts on the point of contact. First, we draw a free-body diagram of the situation:

We have decomposed the force of the nail into its horizontal and vertical components. The horizontal component does no torque since there is no distance parallel to the force to the point of contact.

Now, we add the torques. We consider counterclockwise as positive:

\(\Sigma T=-(30cm)F+(5cm)(R_y)\)

Since we consider the moment before there is no angular acceleration the sum of torques adds up to zero:

\(-(30cm)F+(5cm)(R_y)=0\)

Now, we determine the value of Ry as a function of "R" using the trigonometric function cosine:

\(\cos \theta=\frac{R_y}{R}\)

Now, we multiply both sides by "R":

\(R\cos \theta=R_y\)

Now, we substitute in the sum of torques:

\(-(30cm)F+(5cm)(R\cos \theta_{})=0\)

Now, we solve for "R". First, we add "30F" to both sides:

\((5cm)(R\cos \theta)=(30cm)F\)

Now, we divide both sides by 5cm:

\((R\cos \theta)=\frac{(30cm)F}{5cm}\)

Now, we divide both sides by cosine:

\(R=\frac{(30cm)F}{5cm\cos \theta}\)

Now, we substitute the values:

\(R=\frac{(30cm)(155N)}{(5cm)\cos 26.9}\)

Solving the operations:

\(R=1042.8N\)

Therefore, the force on the nail is 1042.8 Newtons.

What is the answer for the first part of a? In kN

Which term names the cone-shaped underwater volcanic mountains?.

Answers

Answer:

Is this multiple choice answers?? Or fill in the blank??

Explanation:

Please help, it’s the last question and I’m bad at Physics

Please help, its the last question and Im bad at Physics

Answers

Answer:

The end velocity of the sculpture is 7.00 m/s²

Explanation

The equation needed here is v = √(2gh).  Let's do it:

v = √(2 × 9.8m/s² × 2.5m)

v = √(49.0 m²/s²)

v = 7.0m/s

Funny enough the numbers given don't have the accuracy demanded.  We're given is 2.5m which is only accurate to the tenths, and 30kg which is only accurate to the nearest integer.  Also, presumably the acceleration due to Earth gravity that's provided is only 9.8m/s², so that's still only the nearest tenth.  So taking those and asking to find the answer to the nearest hundredth is pointless.

But whatever.  The given answer is correct to the nearest hundredth.  7.00m/s²  To be sure, I plugged it into a form on a physics page that does exactly that, and the answer they gave was 7.0023745972349, so we have it rounded correctly.

Use a 10 mH inductor to design a low-pass passive filter with a cutoff frequency of 1600 rad/sec. 1) Find the cutoff frequency in hertz. i1 Calculate the value of the filter resistor. iii) Assume the cutoff frequency cannot decrease by more than 10%. Find the smallest value of load resistance that can be connected across the output terminals of the filter. iv) If the resistor found in (in) is connected across the output terminals, determine the magnitude of H(jo) when o = 0. [15 Marks]

Answers

The cutoff frequency i) in hertz is approximately 254.65 Hz, ii) The value of the filter resistor is 12.56 Ω, iii) the output terminals of the filter is approximately 125.65 Ω, iv) The magnitude of H(jω) when ω = 0 is 1.

What is  cutoff frequency?

Cutoff frequency refers to a specific frequency at which a system, such as an electronic circuit or a filter, begins to significantly attenuate or block the transmission of signals or the passage of certain frequencies.

The cutoff frequency is an important parameter in signal processing and communications systems, as it defines the range of frequencies that are allowed or blocked. It depends on factors such as the components used in the system, the design of the filter, and the intended application.

i) To find the cutoff frequency in hertz, we can use the formula: f_c = ω_c / (2π),

where f_c is the cutoff frequency in hertz and ω_c is the cutoff frequency in radians per second. Given that the cutoff frequency is 1600 rad/sec, we can substitute this value into the formula: f_c = 1600 rad/sec / (2π) ≈ 254.65 Hz.

ii) To calculate the value of the filter resistor, we can use the formula for the cutoff frequency of a passive RC filter: f_c = 1 / (2π * R * C),

where R is the resistance and C is the capacitance. In this case, we have an inductor (L) instead of a capacitor. We can use the relationship between inductance and capacitance: L = 1 / (2π * f_c * C), to find the value of the resistor: R = L / (2π * f_c) ≈ 12.56 Ω.

iii) To determine the smallest value of load resistance that can be connected across the output terminals, we need to consider the 10% decrease in cutoff frequency. We can calculate the new cutoff frequency: f_new = 0.9 * f_c ≈ 229.18 Hz.

Using the same formula as before, we can solve for the new load resistance: R_load = L / (2π * f_new) ≈ 125.65 Ω.

iv) Finally, when ω = 0, the magnitude of H(jω) is equal to 1, indicating that there is no attenuation at DC (zero frequency).

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what would be the weight of the following items in newtons? 2.5 kg of lead = . 0.7 kg of gold = . 430 g of copper = . 2,570 ml of water =

Answers

The weight of the items in Newton are:

2.5 kg of lead= 24.5 N0.7 kg of gold= 6.86 N430 g of copper= 4.214 N2570 mL of water=  25.186 N

What is the weight of an object?

The weight of an object is the force exerted on it by gravity. In the SI system, weight is measured in newtons (N). To calculate the weight of an object in newtons, you can use the formula W = m*g, where W is the weight in newtons, m is the mass in kilograms, and g is the acceleration due to gravity (9.8 m/s²).

For the first item, 2.5 kg of lead, the weight in newtons would be:

W = 2.5 kg * 9.8 m/s² = 24.5 N

For the second item, 0.7 kg of gold, the weight in newtons would be:

W = 0.7 kg * 9.8 m/s² = 6.86 N

For the third item, 430 g of copper, we first need to convert the mass from grams to kilograms:

430 g = 0.43 kg

Then, we can calculate the weight in newtons:

W = 0.43 kg * 9.8 m/s² = 4.214 N

For the fourth item, 2,570 ml of water, we first need to convert the volume from milliliters to liters, and then from liters to kilograms (since 1 liter of water has a mass of 1 kg):

2,570 ml = 2.57 L = 2.57 kg

Then, we can calculate the weight in newtons:

W = 2.57 kg * 9.8 m/s² = 25.186 N

So, the weight of the items in newtons are 24.5N, 6.86 N, 4.214 N, and 25.186 N respectively.

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If a body moves along acurved path then what is the ratio between its average speed and average velocity

Answers

If a body moves along a curved path, the ratio between its average speed and average velocity depends on the characteristics of the path. Average speed is defined as the total distance traveled divided by the total time taken, while average velocity is the displacement divided by the total time taken.

In the case of a curved path, the body may experience changes in direction, resulting in a non-zero displacement even if the starting and ending points are the same. This means that the average velocity will take into account the direction of motion and the change in position.

On the other hand, average speed does not consider the direction of motion, only the total distance traveled. It is a scalar quantity that measures how fast an object is moving without regard to the direction.

Therefore, in general, when a body moves along a curved path, the average speed will be greater than or equal to the average velocity. The average speed will represent the total distance covered over the total time taken, while the average velocity will indicate the displacement over the total time taken, considering the direction.

However, there are cases where the average speed and average velocity can be equal. This happens when the body moves along a straight path without changing its direction. In such a scenario, the displacement and the distance traveled will be the same, resulting in equal average speed and average velocity.

In summary, the ratio between the average speed and average velocity of a body moving along a curved path depends on the specific characteristics of the motion. In general, the average speed will be greater than or equal to the average velocity, but there are cases where they can be equal, such as when the motion occurs along a straight path.

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Determined by the Direction and Position of the electron's movement within its sublevel
A)Energy levels
B)Sublevels
C)Orbitals
D)Valances​

Answers

C orbitals
I am sure this is right, try it out

40 POINTS AND RLLY EASY

Which option that best describes the planet Jupiter?

Select one:

a.
-largest and most massive planet in the solar system
- has a huge permanent storm that looks like a red spot in images
- has at least 61 moons orbiting it, some of which are very large
- located closer to the sun than Kuiper Belt

b.
-has highest surface temperature of any planet in the solar system
- roughly the same size as Earth
- has a thick carbon dioxide atmosphere
-orbits the sun

C.
- has landforms made by flowing liquid water
- has many huge on its surface
- gets its red color from iron oxide present in soil and rocks on surface
- reflects light from sun
d. -inside of the planet shrunk, forming large cliffs on the surface
- heavily cratered
- no atmosphere
- has mass

Answers

A. Jupiter largest and most massive planet in the solar system

Jupiter has a huge permanent storm that looks like a red spot in images

Jupiter has at least 61 moons orbiting it, some of which are very large

Jupiter located closer to the sun than Kuiper Belt

Which option that best describes the planet Jupiter?

Jupiter came on fifth number from the sun and the Jupiter is the massive planet present in our solar system. It contains the big storms like great red spot. The surface of the Jupiter is gas made giant but the surface of the Jupiter is not solid, but it may have a solid inner core about the size of Earth.

The Jupiter contain at least 61 moons which orbiting the Jupiter . The life on the Jupiter is impossible because the Jupiter contain very much pressure, it has volatile surface and the temperature of the Jupiter is very hot than that of the earth.

So we can conclude that option A is the right answer.

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4) A basketball is launched at a velocity of 25 m/s in a direction making an angle of 50° upward with the
horizontal. What is the maximum height reached by the object?

Answers

Answer:

As Per Provided Information

Velocity of projection u is 25m/sAngle made by ball is 50°

We have been asked to determine the maximum height reached by the object .

here we will take acceleration due to gravity g is 9.8 m/.

For calculating the maximum height attained by the object we will use the following formula .

\( \boxed{\bf \:H_{(max)} \: = \cfrac{u {}^{2} {sin}^{2} \theta }{2g}}\)

Substituting all the value in above equation we obtain

\(\sf \qquad \: \longrightarrow\:H_{(max)} \: = \cfrac{ {25}^{2} {sin}^{2} {50}^{ \circ} }{2 \times 9.8} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cfrac{625 \times(0.766) {}^{2} }{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cfrac{625 \times 0.586756}{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cfrac{366.7225}{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} = \cancel \cfrac{366.7225}{19.6} \\ \\ \\ \sf \qquad \: \longrightarrow\:H_{(max)} =18.71 \: m\)

Therefore,

Maximum height reached by the object is 18.71 meters.

When an arrow is shot from a bow, it has kinetic energy in it. From where does it get its kinetic energy?

Answers

An arrow shot from a bow gets its kinetic energy from the potential energy stored in the bowstring and limbs. When the bowstring is pulled back, it stores energy in the limbs as elastic potential energy.

What is kinetic energy?

Kinetic energy is defined as the energy an object has due to its motion. When an arrow is shot from a bow, it is set in motion and therefore has kinetic energy. The kinetic energy of the arrow depends on its mass and speed. The heavier the arrow, the more kinetic energy it has, and the faster the arrow, the more kinetic energy it has.

The energy stored in the bow is transferred to the arrow when the string is released and the limbs snap back to their original position. This causes the arrow to be propelled forward with a significant amount of kinetic energy.

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Scientists have detected an asteroid that is 700,000,000 km from Earth. About how many astronomical units is that? 0. 5 AU 1 AU 3. 5 AU 4. 5 AU.

Answers

Answer:

it is 4.67921098559 astronomical units

Explanation:

An asteroid that is 700,000,000 km is equivalent to 4.67 AU.

Option D is the correct answer.

How do you convert KM into AU?

Given that an asteroid that is 700,000,000 km from Earth.

We know that 1 AU is equal to 149597870.691 KM. The expression can be given below.

\(1 \;\rm AU = 149597870.691\;\rm KM\)

\(1 \;\rm KM = \dfrac {1}{149597870.691} \;\rm AU\)

\(700,000,000 \;\rm KM = \dfrac {1}{149597870.691} \times 700,000,000 \;\rm AU\)

\(700,000,000 \;\rm KM = 4.67 \;\rm AU\)

Hence we can conclude that 700,000,000 km is equivalent to 4.67 AU. Option D is the correct answer.

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You have a wooden statue hanging from the ceiling using a 10 m spring m the gym. You know the spring constant of the spring is 2 N/m. The statue's 10 kg mass causes the spring to stretch 3 m. What is the potential energy of the spring while it holds up the statue?

Answers

9 joules are the spring's potential energy when supporting the statue.

How to calculate potential energy?

The potential energy of a spring can be calculated using the formula:

PE = 1/2 kx²,

where k = spring constant and x = displacement of the spring from its equilibrium position.

In this problem, the spring has a constant of 2 N/m and a displacement of 3 m due to the statue's mass of 10 kg.

Plugging in the given values into the formula:

PE = 1/2 (2 N/m) (3 m)²

PE = 1/2 (2 N/m) (9 m²)

PE = 9 J

Therefore, the potential energy of the spring while holding up the statue is 9 joules.

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PLEASE DO THIS FOR ME Use the words in the table to fill in the blanks. the answers underlined and bolded are already answered.

PLEASE DO THIS FOR ME Use the words in the table to fill in the blanks. the answers underlined and bolded

Answers

Note that the sentences with the blank spaces are completed as follows;

A "formula" tells what elements make up a compound and the ratios of the atoms of those elements.A compound that is composed of only two elements is a "binary compound".An atom with a negative charge is an "anion".A metal and non-metal tend to form an "ionic" bond.A "bond" is formed when atoms gain, lose, or share electrons.Two non-metal atoms tend to form a "covalent" bond. A "bond" is formed when atoms gain, lose, or share electrons.An "ionic" ion forms when a compound contains both an ionic bond and a covalent bond."Periods" on the periodic table are the rows of elements, and have the same number of valence electrons."Groups" or "families" on the periodic table are the columns of elements and have similar properties.The electrons in the outermost shell of an atom are known as the "valence" electrons and are responsible for the element's chemical activity.

What is a periodic table?

The periodic table, commonly known as the periodic table of elements, is an arrangement of chemical elements in rows and columns. It is frequently utilized in chemistry, physics, and other disciplines, and is widely regarded as a chemical icon. Because of the arrangement of the elements, it is known as the periodic table.

The periodic table is important because it is arranged to give a wealth of information on elements and their relationships to one another in a single reference.

The table may be used to forecast the characteristics of all elements, even those yet to be found.

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awnser these pls they r for middle schoolers lol

awnser these pls they r for middle schoolers lol
awnser these pls they r for middle schoolers lol
awnser these pls they r for middle schoolers lol

Answers

Answer:

Find the set of value of x Find the set of value of x which satisfy the inequality 2r2- 5x 2 18which satisfy the inequality 2r2- Find the set of value of x which satisfy the inequality 2r2- 5x 2 185x 2 18

near earth's surface is the weight of an object in newtons about 10 times it's mass in kilograms?

Answers

Answer:

Weight varies with location depending upon the acceleration due to gravity eg. for a mass m = 10kg on Earth it`s weight is W = mg = 10 x 10 = 100N.

Explanation:

Near Earth's surface, the weight of an object in newtons is  10 times its mass in kilograms. This relationship of the acceleration is due to gravity on Earth, which is 9.81 m/s².

Mathematically, it can be expressed as:

Weight (in newtons) = Mass (in kilograms) × Acceleration due to gravity

So, an object with a mass of, for example, 5 kg, its weight near the Earth's surface would be:

Weight = 5 kg × 9.81 m/s² = 49.05 N

The weight in newtons is roughly 10 times the mass in kilograms of objects near the Earth's surface. The given statement is correct.

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a 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. a 70 kg construction worker stands at the far end of the beam.

Answers

The magnitude of the torque about the bolt due to the worker and the weight of the beam is 13,798.4 Nm

What is the magnitude of the torque?

The length of the steel = \(r_{2}\) = 4.4 m

The mass of the steel= \(m_{1}\) = 500 kg

The mass of the worker = \(m_{2}\) = 70 kg

Let , the total torque = \(\tau_{t}\)

The centre of gravity = \(r_{1}\)

                                   =4.4/2

                                   = 2.2

\(\tau_{t} = \tau_{1} +\tau_{2}\\\\\tau_{t} = F_{1}r_{1} + F_{2}r_{2} \\\\\text{We know that},F = mg \\\\\tau_{t} = m_{1}gr_{1} + m_{2}gr_{2}\\\\\tau_{t} = (500* 9.8* 2.2) +(70*9.8* 4.4)\\\\\tau_{t} = 13,798.4 Nm\)

The magnitude of the torque about the bolt due to the worker and the weight of the beam is 13,798.4 Nm.

What is torque?The force that may twist an item about its axis is measured as torque. Torque is what causes an object to acquire angular acceleration, just as force is what causes an object to accelerate in linear kinematics. Torque is a vector quantity.Torque is a twisting or turning force that frequently results in rotation around an axis, which may be a fixed point or the centre of mass. The ability of something rotating, such as a gear or a shaft, to overcome turning resistance is another way to think of torque.

The complete question is:

A 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70 kg construction worker stands at the far end of the beam. What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?

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