Worth 50-100 points. Will mark brainliest to whoever does all the work. Please help! Thank you! Heidi and Madison are using rock-paper-scissors to determine who will be able to choose the song that will be played at the start of the next geometry class. They will go with the winner of two games (in the event of a tie both songs will be played)

(A)Are these 2 events independent or not independent?Why?

(B)Make a tree diagram for the outcome of each game.

(C)What is the total outcome of the two games?

(D)What is the probability of Heidi winning 2 rounds?

Please help I’m at a loss. Time sensitive.

Answer:

8 83/104.

Step-by-step explanation:

4 9/13 * 1 7/8

= 61/13 * 15/8

= 915/104

= 8 83/104.

Answer:

most common, 4, c, 9

Step-by-step explanation:

The mode is the most common number of data sets, The mode in this set of data is 4, To determine the range subtract C from G, and the range will be 9.

A frequency table is a list of objects with the frequency of each item shown in the table.

The frequency of an occurrence or a value is the number of times it happens.

In other words, a frequency table is a table in which we have some data and their frequency.

The mode in the frequency table is the highest repeating element (most common) which is 4 in the given table.

So,

Mode = 4

The range is the complete duration of data from minimum to maximum.

Range = Maximum - Minimum

Range = 11 - 2 = 9

So to determine the range we need to subtract C from G.

Hence "The mode is the most common number of data sets, The mode in this set of data is 4, To determine the range subtract C from G, and the range will be 9".

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Answer:Each person should get 7.5 milliliters  or seven and a half perfume.

Step-by-step explanation:

15/2=7.5

Each person should get 7.5 milliliters or seven and a half perfume.

Unit means 'single entity', the fundamental constructing block. Usually, it is 1 in maths and science.

Thus, unit price of something is price of 1 thing.

Suppose we're taking about price of mangoes, then unit price will denote the price of 1 mango.

WE know that 2 people are evenly sharing 15 milliliters of perfume.

So, one person will share;

15/2

=7.5

Therefore, Each person should get 7.5 milliliters or seven and a half perfume.

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Total money with Kadeem  = $680

Money spent by him on a new bicycle = $470.65

Money left with him after buying a new bicycle = 680 - 470.65 = 209.35

Money spent by him on 2 bicycle reflectors = 7.87*2 = $15.74

Money left with him after buying reflectors = 209.35 - 15.74 = $193.61

Money spent by him on bike gloves = $15.18

Money left with him after buying biking outfits: 193.61 - 15.18 = $178.43

Cost of each outfit = $50.98

Let the number of outfits Kadeem can buy be x, therefore formulating the equation we get:

50.98x< = 178.43

x< = 3.5

So, Kadeem can buy 3 outfits while staying within budget

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Answer:

\(g) \left(5x-2\right)\left(3x+2\right)\)

\(h)2\left(8a-9\right)\left(a-2\right)\)

\(i)3\left(21n^2+42n+16\right)\)

Step-by-step explanation:

Starting with g) \(15^2+4x-4\)

Break the expression into group

\(=\left(15x^2-6x\right)+\left(10x-4\right)\)

Now, Factor out \(3x\) from \(15x^2-6x\) which is now is \(3x(5x-2)\)

Next, Facotr out \(2\) from \(10x-4\) which is now is \(2(5x-2)\)

Thus,

\(=3x\left(5x-2\right)+2\left(5x-2\right)\)

Factor common term 5x -2

\(\left(5x-2\right)\left(3x+2\right)\)

-------------------------------------------------------------------------------------------------------------

Next we have \(h)16a^2-50a+36\)

Factor out common term thus we have \(2(8a^2-25a+18)\)

Factor again: \(8a^2-25a+18\) now turn into \((8a-9)(a-2)\)

\(=2\left(8a-9\right)\left(a-2\right)\)

-------------------------------------------------------------------------------------------------------------

Lastly we have \(i)63n^2+126n+48\)

Rewrite the following:

63 as 3 * 21

126 as 2 * 42

48 as 3 * 16

\(63n^2+126n+48\)

Now cut out common term:

\(=3\left(21n^2+42n+16\right)\)

-------------------------------------------------------------------------------------------------------------

~lenvy~

Answer:

(g)  \((5x-2)(3x+2)\)

(h)  \((16a-18)(a-2)\)

(i)  \(3(21n^2+42n+16)\)

Step-by-step explanation:

To factor a quadratic in the form \(ax^2+bx+c\)

Question (g)

\(15x^2+4x-4\)

\(\implies ac=15 \cdot -4=-60\)

\(\implies d+e=4\)

Factors of 60:  1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Therefore, the two numbers (d and e) that multiply to -60 and sum to 4 are:

10 and -6

Rewrite \(4x\) as \(+10x-6x\):

\(\implies 15x^2+10x-6x-4\)

Factories first two terms and last two terms separately:

\(\implies 5x(3x+2)-2(3x+2)\)

Factor out common term \((3x+2)\):

\(\implies (5x-2)(3x+2)\)

Question (h)

\(16a^2-50a+36\)

\(\implies ac=16 \cdot 36=576\)

\(\implies d+e=-50\)

Factors of 576:  1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 64, 72, 96, 144, 192, 288, 576

Therefore, the two numbers that multiply to 576 and sum to -50 are:

-32 and -18

Rewrite \(-50a\) as \(-32a-18a\):

\(\implies 16a^2-32a-18a+36\)

Factories first two terms and last two terms separately:

\(\implies 16a(a-2)-18(a-2)\)

Factor out common term \((a-2)\):

\(\implies (16a-18)(a-2)\)

Question (i)

\(63n^2+126n+48\)

Factor out common term 3:

\(\implies 3(21n^2+42n+16)\)

This cannot be factored any further.

Answer:

a) final exam: 90.2 B     b) percent of final grade: 20 F

Step-by-step explanation:

calculator: a)86+81+96+99+89=451/5=90.2

b) 20+15+15+25+25=100/5=20

The  weighted mean of a distribution is the sum of the product of the data elements of the distribution by the proportion of each element.

The weighted mean score of the students is 90.75

To calculate the weighted mean score, we simply multiply the score of each student by the percentage grade.

So, we have:

\(Mean = 86 \times 20\% + 81 \times 15\% + 96 \times 15\% + 99 \times 25\% + 89 \times 25\%\)

This gives:

\(Mean = 17.20 + 12.15 + 14.40 + 24.75 + 22.25\)

\(Mean = 90.75\)

Hence, the weighted mean score of the students is 90.75

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Answer:

C

Step-by-step explanation:

For these types of problems, its important that we focus on the base as well as the lengths of the base and any other given lengths.

Here, the net has a base that forms a square with side lengths of 8mm.

So automatically, we can eliminate choices a and d as both have a base that is a triangle rather than a square.

We've also noticed that the base has a length of 8mm

If we look at B and C closely, we can tell that B has base lengths of 10mm while C has base lengths of 8mm.

So C is the correct answer choice.

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Answer: A

Step-by-step explanation:

270/30

270÷30 = 9

30÷30 = 1

The inequality, -7x ≤ -21, has the solution set as same in the graph.

The inequality is the relationship between two values that are not equal.

The graph shows that the value x ranges from 3 to less than 3 values.

i.e x ≤  3

To solve the inequality, -7x -21, we divide both sides by (-7).

i. e (-7x ≤ -21) / (-7)

x≤ 3

Hence, the inequality suitable for the given graph is -7x ≤ -21

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Answer:

The reduced echelon form of the given matrix B is [ 1 0 0 -5 | 0 ], [ 0 1 0 3 | 0 ], and [ 0 0 1 0 | 0 ]. The parametric description of the set of solutions for the given system of linear equations is { [5x4, -3x4, 0, x4] | x4 ∈ R }.

Step-by-step explanation:

Using row operations to reduce the matrix B to reduced row echelon form, we have:

[ 1 3 -5 4 | 0 ]

[ 1 4 -8 7 | 0 ]

[-3 -7 9 -6 | 0 ]

R2 - R1 -> R2

R3 + 3R1 -> R3

[ 1 3 -5 4 | 0 ]

[ 0 1 -3 3 | 0 ]

[ 0 2 4 6 | 0 ]

R1 - 3R2 -> R1

R3 - 2R2 -> R3

[ 1 0 4 -5 | 0 ]

[ 0 1 -3 3 | 0 ]

[ 0 0 10 0 | 0 ]

R3/10 -> R3

[ 1 0 4 -5 | 0 ]

[ 0 1 -3 3 | 0 ]

[ 0 0 1 0 | 0 ]

R2 + 3R3 -> R2

R1 - 4R3 -> R1

R2 + 3R3 -> R3

[ 1 0 0 -5 | 0 ]

[ 0 1 0 3 | 0 ]

[ 0 0 1 0 | 0 ]

Therefore, the reduced echelon form of the matrix B is:

[ 1 0 0 -5 | 0 ]

[ 0 1 0 3 | 0 ]

[ 0 0 1 0 | 0 ]

asterisk

can you make it step by step easy to understand

Certainly! Here are the steps to find the reduced row echelon form of the matrix B = [1, 3, -5, 4, 1, 4, -8, 7, -3, -7, 9, -6]:

Write the matrix in augmented form, with a vertical line separating the coefficients from the constant terms.

[ 1 3 -5 4 | 0 ]

[ 1 4 -8 7 | 0 ]

[-3 -7 9 -6 | 0 ]

Use row operations to transform the matrix into row echelon form. The goal is to create zeros below the leading entries (the first nonzero element) in each row. Here are the steps:

a. Subtract the first row from the second row, and subtract 3 times the first row from the third row:

[ 1 3 -5 4 | 0 ]

[ 0 1 -3 3 | 0 ]

[ 0 2 4 6 | 0 ]

b. Subtract 3 times the second row from the first row, and subtract 2 times the second row from the third row:

[ 1 0 4 -5 | 0 ]

[ 0 1 -3 3 | 0 ]

[ 0 0 10 0 | 0 ]

c. Divide the third row by 10 to create a leading 1 in the third row:

[ 1 0 4 -5 | 0 ]

[ 0 1 -3 3 | 0 ]

[ 0 0 1 0 | 0 ]

Use row operations to transform the matrix into reduced row echelon form. The goal is to create leading 1's in each row, and zeros above and below the leading 1's. Here are the steps:

a. Subtract 4 times the third row from the first row, and subtract 3 times the third row from the second row:

[ 1 0 0 -5 | 0 ]

[ 0 1 0 3 | 0 ]

[ 0 0 1 0 | 0 ]

The matrix is now in reduced row echelon form. The leftmost nonzero entry in each nonzero row is 1, and each leading 1 is the only nonzero entry in its column. The rows are arranged so that all rows with all zeros are at the bottom of the matrix.

Therefore, the reduced row echelon form of the matrix B is:

[ 1 0 0 -5 | 0 ]

[ 0 1 0 3 | 0 ]

[ 0 0 1 0 | 0 ]

For (b):

From the reduced echelon form obtained in part (a), we can write the system of equations as:

x1 + 0x2 + 4x3 = -5

0x1 + x2 - 3x3 = 3

0x1 + 0x2 + x3 = 0

We can solve for the basic variables (x1, x2, x3) in terms of the free variable(s):

x1 = -5 - 4x3

x2 = 3 + 3x3

x3 = free

Therefore, the general solution to the system of equations is:

x = [-5 - 4x3, 3 + 3x3, x3]

where x3 is any real number, since it is the free variable. This is the parametric description of the set of solutions. We can also write this solution set in set-builder notation as:

{ [-5 - 4x3, 3 + 3x3, x3] | x3 ∈ R }

This means that any vector in the solution set can be obtained by choosing a value for the free variable x3 and plugging it into the expressions for x1, x2, and x3. For example, if we choose x3 = 0, we get the solution (x1, x2, x3) = (-5, 3, 0). If we choose x3 = 1, we get the solution (x1, x2, x3) = (-9, 6, 1), and so on.

Hope this helps! I'm sorry if it doesn't. If you need more help, ask me! :]

Answer:

here hope this helps

Step-by-step explanation:

The equation y = 2/3x - 1 is already in slope-intercept form and matches the general form of a linear equation.

What is Slope of Line?

In mathematics, the slope of a line is a measure of its steepness or inclination. It describes the rate at which the line rises or falls as it moves from left to right. The slope of a line is defined as the ratio of the change in the y-coordinates (vertical change) to the change in the x-coordinates (horizontal change) between any two points on the line.

The slope can be positive, negative, zero, or undefined. A positive slope indicates that the line is rising as it moves from left to right, while a negative slope indicates that the line is falling as it moves from left to right.

Please refer to the graph attached below

The equation y = 2/3x - 1 is already in slope-intercept form, where the slope (m) is the coefficient of x and the y-intercept (b) is the constant term.

So, the slope of the line is 2/3 and the y-intercept is -1.

Comparing this to the general equation y = mx + b, we can see that the slope (m) is the same as before (2/3) and the y-intercept (b) is also the same (-1). Therefore, the equation y = 2/3x - 1 is already in slope-intercept form and matches the general form of a linear equation.

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Answer:

  6.  B. T(n) = -0.411n² +6.5n +27

  7.  C. The zeros, -18 and 18, can be found when 0 = (x +18)(x -18)

Step-by-step explanation:

6. Graphing, or thinking about the data in the table, you see that it is described by a curve that opens downward and has a peak in the vicinity of n=8.

Of the choices offered, the only ones that describe a downward-opening curve are the ones with a negative leading coefficient, B and C. Of those two, Choice C has a peak at n=0, leaving choice B as the only viable one.

This is confirmed by software that computes the regression formula for you. (see attached)

__

7. You know that "the difference of squares" has a special factored form:

  a² -b² = (a +b)(a -b)

This suggests that the function you have might be considered in terms of the difference of squares:

  h(x) = x² -324 = x² -18²

So, its factoring would be ...

  h(x) = (x +18)(x -18)

The zeros of the function are those values of x such that h(x) = 0. Hence, the zeros can be found when ...

  0 = (x +18)(x -18)

Those values of x are -18 and 18, matching choice C.

Step-by-step explanation:

The ONE  solution to this system of two lines is the point where the two lines cross   at   (1,4)

The type of model that best fits the situation of a $500 raise in salary each year is a linear model.

In a linear model, the dependent variable changes a constant amount for constant increments of the independent variable.

In the given case, the dependent variable is the salary and the independent variable is the year.

You may build a table to show that for increments of 1 year the increments of the salary is $500:

Year         Salary        Change in year         Change in salary

2010           A                           -                                       -

2011           A + 500     2011 - 2010 = 1          A + 500 - 500 = 500

2012          A + 1,000   2012 - 2011 = 1          A + 1,000 - (A + 500) = 500

So, you can see that every year the salary increases the same amount ($500).

In general, a linear model is represented by the general equation y = mx + b, where x is the change of y per unit change of x, and b is the initial value (y-intercept).              

In this case, m = $500 and b is the starting salary: y = 500x + b.

Answer:

The third option.

Step-by-step explanation:

Lets write the length as L and the width as W.

Given, L = W - 4

or L - W = - 4

Perimeter of a rectangle = 2( L + W)

44 = 2 (L + W)

L + W = 22

L - W = -4

2L = 18 (adding the two equations)

L = 9

W = 13

So, the answer is the third option.

Cheers

Answer:

C. 20

Step-by-step explanation:

\( \frac{y}{ {x}^{2} } = 10 \\ \\ y = 10 {x}^{2} \\ \\ differentiating \: w.r.t. \: x \: on \: both \: sides \\ \\ \frac{dy}{dx} = 10 \frac{d}{dx} {x}^{2} \\ \\ \frac{dy}{dx} = 10 \times 2{x} \\ \\ \frac{dy}{dx} = 20{x} \\ \\ differentiating \: again\: w.r.t. \: x \: on \: both \: sides \\ \\ \frac{d}{dx} \bigg(\frac{dy}{dx} \bigg)= 20\frac{d}{dx} {x} \\ \\ \frac{ {d}^{2} y}{d {x}^{2} } = 20 \times 1 \\ \\ \huge \purple {\frac{ {d}^{2} y}{d {x}^{2} } } \red{= } \orange{20}\)

Answer:

Joel had 120 dimes and 80 quarters.

Step-by-step explanation:

Given that Joel had 200 coins, which were dimes and quarters, and the total value was $ 32, to determine how many coins of each type he had, the following calculation must be performed:

0.25 - 0.10 = 0.15

200 x 0.10 = 20

32 - 20 = 12

12 / 0.15 = 80

200 - 80 = 120

(80 x 0.25) + (120 x 0.1) = X

20 + 12 = X

32 = X

Thus, Joel had 120 dimes and 80 quarters.

Answer:

x-40%-16%

Step-by-step explanation:

D. Angle Division

1) Examining that figure, we can take line segment QR and TS as parallel ones, and those line segments TN and NS as transversal ones.

2) In addition to this, since ∡QTS and ∡RST are right angles, then we have a rectangle. And since ∡NTS and ∡NST are congruent

3) Then we can say that NT bisects ∡QTS and NS bisects ∡RST

So, angle Division is the answer

The area of the original figure is 1/9 times the area of the new figure

The perimeter of the original figure is 1/2 times the perimeter of the new figure

From the question, we have the following parameters that can be used in our computation:

The figures

The areas of the new figures is calculated as

Area = Old area * scale factor

So, we have

Area Figure 1 = (1 * 3) * 3

Area Figure 1 = 9

The perimeter of the new figures is calculated as

Perimeter = Old Perimeter * scale factor

So, we have

Perimeter Figure 2 = (4 * 4 + 4 * (2 + 3)) * 1/2

Perimeter Figure 2 = 18

See attachment for the dilates figures

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Part a; compounded semiannually (n = 2); CI =  $6,390.

Part b: compounded quarterly ( n = 4) ; CI =  $6,425

Part c: compounded monthly (n = 12): CI =  $6,450

Part d: compounded continuously; CI =  $6,467.

The compound interest is calumniated by formula.

A = P(1 + r/100n)∧nt

In which,

A  = amount after compounding

P = principal amount  ($20,000 )

n = number of time principal amount compounded in a year.

t = total time in years (7 years)

r= rate of interest (4%)

Part a; compounded semiannually (n = 2)

A = P(1 + r/100n)∧nt

A = 20,000(1 + 4/200)∧(2x7)

A = 26390

CI = A - P

CI =  26,390 -  20,000

CI =  $6,390.

Part b: compounded quarterly ( n = 4)

A = 20,000(1 + 4/400)∧(4x7)

A = 26425

CI = A - P

CI =  26,425 -  20,000

CI =  $6,425

Part c: compounded monthly (n = 12)

A = 20,000(1 + 4/1200)∧(12x7)

A = 26450

CI = A - P

CI =  26,450-  20,000

CI =  $6,450

Part d: compounded continuously.

P = P₀e∧rt

P = (20,000)(2.72)∧(0.04 x 7)

P = 20,000 x 1.32

P = 26,467

CI =  26,467 - 20, 000

CI =  $6,467.

Thus, the for compounded continuously is $6,467.

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Answer: -4/3

Step-by-step explanation:

\(\csc \theta=\frac{1}{\sin \theta}=\frac{1}{-3/4}=-4/3\)

Answer:

$159.99

Step-by-step explanation:

Answer:

1500 millimeters is your answer

The solution is Option A.

The coordinate of the triangle after the translation is given by A' ( 0 , -3 ) with 4 units right and 4 units down

A translation moves a shape up, down, or from side to side, but it has no effect on its appearance. A transformation is an example of translation. A transformation is a method of changing a shape's size or position. Every point in the shape is translated in the same direction by the same amount.

Given data ,

Let the coordinate of the triangle be represented as A

Now , the coordinate A = A ( -4 , 1 )

Now , the coordinate of the triangle after translation is A' ( 0 , -3 )

when there is a translation of the coordinate A by 4 units to the right , we get

A to 4 units right = A ( -4 + 4 , 1 )

The new coordinate of A = A ( 0 ,  1 )

Now , A to 4 units down , we get

The coordinate of A' = A' ( 0 , 1 - 4 )

The coordinate of A' = A' ( 0 , -3 )

Hence , the translated coordinate is A' ( 0 , -3 )

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(a) To meet the desired 20g protein and 80g carbohydrate intake, prepare 4 servings of Pork & Beans and combine with 15 slices of "lite" rye bread.

(b) Bread: A/4 slices, Beans: B/21 - (A/4) * (12/21) servings.

(a) To prepare a meal of "beans-on-toast" that supplies 20 grams of protein and 80 grams of carbohydrates, you can use the following combination:

- Servings of Campbell's Pork & Beans: 4 servings.

- Slices of "lite" rye bread: 15 slices.

By using 4 servings of Campbell's Pork & Beans, you will obtain a total of 20 grams of protein (5 grams per serving) and 84 grams of carbohydrates (21 grams per serving).

Combining this with 15 slices of "lite" rye bread will contribute an additional 60 grams of carbohydrates (12 grams per slice) and 4 grams of protein (4 grams per slice). Thus, your meal will meet the desired nutritional requirements of 20 grams of protein and 80 grams of carbohydrates.

(b) The formula to determine the number of slices of bread and servings of Pork & Beans needed to meet specific protein and carbohydrate requirements is as follows:

- Number of slices of bread (Bread): A divided by 4.

- Number of servings of Pork & Beans (Beans): (B divided by 21) minus ((A divided by 4) multiplied by (12 divided by 21)).

Using this formula, you can calculate the appropriate quantities of bread and beans based on the desired protein (A) and carbohydrate (B) values.

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Sally's average annual percentage gain is approximately 5.26%.

To calculate Sally's average annual percentage gain, we can use the formula:

Average Annual Percentage Gain = (Profit / Initial Investment) * (1 / Time) * 100

Profit = $2500

Initial Investment = $19000

Time = 2.5 years

Substituting the values into the formula:

Average Annual Percentage Gain = (2500 / 19000) * (1 / 2.5) * 100

= (0.1316) * (0.4) * 100

= 5.26

Therefore, Sally's average annual percentage gain is approximately 5.26%.

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Answer:

4

Step-by-step explanation:

36 divided by 9 = 4

4 x 9 = 36