Write out the first few terms of the series write out the fis tew terms of the series sum_(i=1)^[infinity] (-1)^n/2^n. What's the series sum?
The first term is _____ (Type an integer or a simplified fraction.)

The value of the Arrow-Debreu security is calculated as the present value of its expected payoff, discounted at the risk-neutral rate. As a result, the premium of the Arrow-Debreu security can be computed using the following formula: \($P_{t}=\frac{1}{(1+R)^{n-t}}\times \pi$,\)

where π=0.4, R=1.05, n=6, and t=2 (expiry node).

By substituting the values, we obtain:

\($P_{2}=\frac{1}{(1+1.05)^{6-2}}\times 0.4 = \frac{0.4}{(1.05)^4} \approx 0.3058$.\)

Therefore, the premium of the Arrow-Debreu security is approximately $0.3058.

Arrow-Debreu securities are typically utilized in financial modeling to simplify the pricing of complex securities. They are named after Kenneth Arrow and Gerard Debreu, who invented them in the 1950s. An Arrow-Debreu security pays $1 if a particular state of the world is realized and $0 otherwise.

They are generally utilized to price derivatives on numerous assets that can be broken down into a set of Arrow-Debreu securities. The value of an Arrow-Debreu security is calculated as the present value of its expected payoff, discounted at the risk-neutral rate. In other words, the expected value of the security is computed using the risk-neutral probability, which is used to discount the value back to the present value.

The formula is expressed as:

\($P_{t}=\frac{1}{(1+R)^{n-t}}\times \pi$\),

where P_t is the price of the Arrow-Debreu security at time t, π is the risk-neutral probability of the security’s payoff, R is the risk-free rate, and n is the total number of time periods.However, Arrow-Debreu securities are not traded in real life. They are used to determine the prices of complex securities, such as options, futures, and swaps, which are constructed from a set of Arrow-Debreu securities.

This process is known as constructing a complete financial market, which allows for a more straightforward pricing of complex securities.

The premium of the Arrow-Debreu security is calculated by multiplying the risk-neutral probability of the security’s payoff by the present value of its expected payoff, discounted at the risk-neutral rate.

The formula is expressed as

\($P_{t}=\frac{1}{(1+R)^{n-t}}\times \pi$,\)

where P_t is the price of the Arrow-Debreu security at time t, π is the risk-neutral probability of the security’s payoff, R is the risk-free rate, and n is the total number of time periods. Arrow-Debreu securities are not traded in real life but are used to price complex securities, such as options, futures, and swaps, by constructing a complete financial market.

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Answer:

12

Step-by-step explanation:

Tree diagram

Heads - 1

           - 2

           - 3

           - 4

           - 5

           - 6

Tails    - 1

           - 2

           - 3

           - 4

           - 5

           - 6

Count all the possibilities, and boom- 12 :)

Sorry if its wrong tho-

we can use the information given about its growth rate and the height after 4.5 years:So, it took 7 years from the time Vlad moved in until the tree was 357 centimeters tall.

Height increase per year = 26 centimeters
Years since Vlad moved in = 4.5 years
Height after 4.5 years = 292 centimeters
To calculate the initial height of the tree, we can multiply the growth rate by the number of years and add it to the starting height:
Initial height = Height after 4.5 years - (Height increase per year x Years since Vlad moved in)
Initial height = 292 - (26 x 4.5)
Initial height = 168 centimeters
Therefore, the tree was 168 centimeters tall when Vlad moved into the house.
To find out how many years passed from the time Vlad moved in until the tree was 357 centimeters tall, we can use the same formula and solve for the number of years:
Height increase per year = 26 centimeters
Initial height = 168 centimeters
Final height = 357 centimeters
To calculate the number of years, we can rearrange the formula as follows:
Years = (Final height - Initial height) / Height increase per year
Years = (357 - 168) / 26
Years = 6.04 years (rounded to two decimal places)
Therefore, it took approximately 6 years and 1 month for the tree to grow from 168 centimeters to 357 centimeters tall.
To determine the height of the oak tree when Vlad moved into the house, we can use the given information. The tree grows by 26 centimeters each year, and it was 292 centimeters tall after 4.5 years.
First, let's find the total growth during the 4.5 years:
26 cm/year * 4.5 years = 117 cm
Now, subtract the total growth from the current height to find the initial height:
292 cm - 117 cm = 175 cm
So, the oak tree was 175 centimeters tall when Vlad moved into the house.
To find out how many years passed until the tree was 357 centimeters tall, we can use the growth rate again:
First, find the difference in height between the target height (357 cm) and the initial height (175 cm):
357 cm - 175 cm = 182 cm
Now, divide the difference in height by the growth rate to find the number of years:
182 cm / 26 cm/year = 7 years

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Answer: are you asking us to answer it or is that the answer?

Step-by-step explanation:

Answer: Um, I don't understand how did you post your question with the ones that are linear relationship to its algebraic model in slope-intercept form.

Step-by-step explanation:

Answer:

\(A = 52\), \(B = 38\)

Step-by-step explanation:

The sum of two complementary angles is always \(90\)°

\(A + B = 90\)

\(A = B + 14\)

substitute \(A\) for \(B = 14\)

\((B + 14)+ B = 90\)

\(2B + 14 = 90\)

\(2B = 76\)

\(B = 38\)

input this into the original equation

\(A + 38 = 90\)

\(A = 52\)

plz mark me brainliest ;)

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

\(\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx \)

Here 5 is a constant so it can come out . So that,

\(\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx \)

Now we can write √x as ,

\(\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx \)

Simplify ,

\(\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx \)

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

\(\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) \)

On simplifying we will get ,

\(\longrightarrow \underline{\underline{ I = 2 }}\)

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\( \displaystyle \int_{0} ^{1} 5x \sqrt{x} dx\)

use constant integration rule which yields:

\( \displaystyle 5\int_{0} ^{1} x \sqrt{x} dx\)

notice that we can rewrite √x using Law of exponent therefore we obtain:

\( \displaystyle 5\int_{0} ^{1} x \cdot {x}^{1/2} dx\)

once again use law of exponent which yields:

\( \displaystyle 5\int_{0} ^{1} {x}^{ \frac{3}{2} } dx\)

use exponent integration rule which yields;

\( \displaystyle 5 \left( \frac{{x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \right) \bigg| _{0} ^{1} \)

simplify which yields:

\( \displaystyle 2 {x}^{2} \sqrt{x} \bigg| _{0} ^{1} \)

recall fundamental theorem:

\( \displaystyle 2 ( {1}^{2}) (\sqrt{1} ) - 2( {0}^{2} )( \sqrt{0)} \)

simplify:

\( \displaystyle 2 \)

hence

our answer is A

The budgets of Hong Kong, the United States of America, and Korea differ in contents, formats, advantages, and disadvantages. While each budget has its strengths and weaknesses, they all aim to provide a clear and transparent financial plan for their respective countries.

A budget is a financial plan that estimates expected income and expenditure for a specific period. It may include income, expenses, debts, and savings. Budgets may vary from country to country and can be analyzed by comparing their contents, formats, advantages, and disadvantages. Here are the budgets of Hong Kong, the United States of America, and Korea:

United States Budget:

Korean Budget:

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Step-by-step explanation:

I don't know if I got that right

Answer:

Five less than the number than....... 8/n - 5 +7

Eight more than the product........ 8 +7n - 2

Five times the sum..... 5(n+7)

Twice the difference.... 2 (8-n)

Answer:

Blue:

\( \frac{8}{n} - 5 + 7\)

Green:

\(8 + 7n - 2\)

Orange:

\(5(n + 7)\)

Purple:

\(2(8 - n)\)

The rate at which Ms. Sanchez's students can write lines of code can be expressed as 12 lines of code per hour. This means that, on average, each student is able to write 12 lines of code within a one-hour time period.

The rate at which Ms. Sanchez's students can write lines of code can be calculated as follows:
In 20 minutes, each student can write an average of 4 lines of code.
To find the rate per hour, we need to convert the time from minutes to hours. Since there are 60 minutes in an hour, we divide the number of minutes by 60:
20 minutes ÷ 60 minutes/hour = 1/3 hour

Now, we can calculate the rate per hour by multiplying the rate per 20 minutes by the number of 20-minute intervals in an hour:
4 lines of code/20 minutes × 3 intervals/hour = 12 lines of code/hour

Therefore, the rate at which each of Ms. Sanchez's students can write lines of code is 12 lines of code per hour.

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Answer: 105

Step-by-step explanation:

Given

The ratio of men to women working for a company is 4:7

There are total of 165 employees

Suppose, there is  4x men and 7x women such that the ratio remains constant

\(\therefore 4x+7x=165\\\Rightarrow 11x=165\\\Rightarrow x=15\)

\(\text{Men= }4\times 15=60\\\text{Women= }7\times 15=105\)

Answer:

I believe the answer you chose is correct. D

Step-by-step explanation:

The correct answer is

60 miles

4 gallons

The size for a TV is determined as the diagonal length of the Television.

The Televisions that we see in our daily life are mostly of the rectangular shape.

A rectangular shape is a shape that has 4 sides in it, the opposite sides of the rectangular are parallel and equal. Two pairs of equal sides are formed in this type of shape.

If we connect the vertices that are directly opposite to each other than it is known as the diagonal of the rectangle . Often we see that the TV is of 32'' or 64''. This only means that the diagonal length of the TV is 32'' or 64''. This is how we measure the size of the TV.

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The perimeter of the quadrilateral is 46 units, so the correct option is d.

The perimeter is equal to the sum of the lengths of all the sides of the quadrilateral.

Remember that the length of a segment whose endpoints are (x₁, y₁) and (x₂, y₂) is:

L = √( (x₁ - x₂)^2 + (y₁ - y₂)^2)

The length between the first two vertices: (−6, −2), (0, −10)

L₁ = √( (-6 - 0)^2 + (-2 + 10)^2) = 10

The length between the second two vertices:  (0, −10), (5, 2)

L₂ = √( (0 - 5)^2 + (-10 - 2)^2) = 13

The length between the third two vertices:  (5, 2), (−1, 10)

L₃ = √( (5 + 1)^2 + (2 - 10)^2) = 10

The length between the fourth two vertices:  (−1, 10), (−6, −2)

L₄ = √( (-1 + 6)^2 + (10 + 2)^2) = 13

Then the perimeter is:

P = 10 + 13 + 10 + 13 = 46

The correct option is D.

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Answer:

x=-2

Step-by-step explanation:

\(\huge\text{Hey there!}\)

\(\large\boxed{\mathbf{\boxed{\textsf{EQUATION }\rightarrow \mathbf{[?]}} \times 22 = 22,000}}\)

\(\large\textbf{Lets solve the choices into the equation to see which}\\\large\textbf{one will fit with the answer (22,000)}\)

\(\large\boxed{\boxed{\bf 10^3}\times\bf 22}\\\large\boxed{= \boxed{\bf 10\times10\times10}\times\bf 22}\\\large\boxed{= \boxed{\bf 100\times10}\times\bf 22}\\\large\boxed{= \boxed{1\bf ,000}\times\bf 22}\\\large\boxed{= \bf 22,000}\\\\\\\\\large\boxed{\mathbf{22,000 = 22,000}}\\\large\text{Thus, this means Option A. could possibly be your answer.}\)

\(\large\boxed{\boxed{\bf 10^5}\times\bf22}\\\large\boxed{= \boxed{\bf 10\times10\times10\times10\times10}\times\bf 22}\\\large\boxed{=\boxed{\bf 100\times100\times10}\times\bf 22}\\\large\boxed{= \boxed{\bf 10,000\times10}\times\bf 22}\\\large\boxed{= \boxed{\bf 100,000}\times\bf 22}\\\large\boxed{ = \bf 2,200,000}\\\\\\\\\large\boxed{\bf 2,200,000 \neq 22,000}\\\large\text{Thus, this means Option B. isn't your answer}\)

\(\large\boxed{\mathbf{\boxed{\mathbf{10^2}} \times 22}}\\\large\boxed{= \boxed{\bf 10\times10} \times \bf 22}\\\large\boxed{= \boxed{\bf 100}\times \bf 22}\\\large\boxed{\mathbf{= 2,200}}\\\\\\\\\large\boxed{\mathbf{2,220 \neq 22,000}}\\\large\text{Thus, this means Option C isn't your answer}\)

\(\large\boxed{\boxed{\bf 10^4}\times\bf 22}\\\large\boxed{= \boxed{\bf 10\times10\times10\times10}\times\bf 22}\\\large\boxed{= \boxed{\bf 100\times100}\times\bf 22}\\\large\boxed{= \boxed{\bf 10,000}\times \bf 22}\\\large\boxed{= \bf 220,000}\\\\\\\\\large\boxed{\bf 220,000\neq 22,000}}\\\large\text{Thus, this means Option D. isn't your answer}\)

\(\huge\boxed{\text{Therefore, your answer is: \boxed{\mathsf{10^3}}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

The fee charged for the R 2, 500 withdrawal from TownBank would be R 33. 30.

To find the total fee charged to withdraw the sum of R 2, 500 from TownBank, the formula is :

= 3. 30 + R 1, 20 per R 100

The amount withdrawn was R 2, 500 so the total fee charged would be :

= 3. 30 + 1, 20 x ( 2, 500 / 100 )

= 3. 30 + 1. 20 x 25

= 3. 30 + 30

= 33. 30

= R 33. 30

In conclusion, the total fee charged was R 33. 30.

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First part of the question :

The TownBank current account charges R3,30 plus R1,20 per R100 or part thereof for a cash withdrawal from a TownBank ATM. The first five withdrawals in a month are free. Determine the bank charges for a withdrawal of:

Answer:

he equation given in the exercise  is:

Observe that highest exponent of the variable "x" is 2. Therefore, it is a Quadratic equation.

Therefore, making an exponent 1 instead of the exponent 2 would turn the given equation into a Linear function.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

the order of letter should resemble the same shape

To prove that the set a = {0, 1} is numerically equivalent to r (the set of real numbers), we need to find a bijective function that maps each element of a to a unique element in r.

One way to do this is to use the binary representation of real numbers. Specifically, we can define the function f: a -> r as follows:

- For any x in a, we map it to the real number f(x) = 0.x_1 x_2 x_3 ..., where x_i is the i-th digit of the binary representation of x. In other words, we take the binary representation of x and interpret it as a binary fraction in [0, 1).

For example, f(0) = 0.000..., which corresponds to the real number 0. f(1) = 0.111..., which corresponds to the real number 0.999..., the largest number less than 1 in binary.

We can see that f is a bijection, since every binary fraction in [0, 1) has a unique binary representation, and hence corresponds to a unique element in a. Also, every element in a corresponds to a unique binary fraction in [0, 1), which is mapped by f to a unique real number.

Therefore, we have proven that a is numerically equivalent to r, since we have found a bijection between the two sets.

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By Euclid's axioms we proved that AC=BD

Things which are equal to the same thing are also equal to one another.

If equals be added to equals, the wholes are equal.

If equals be subtracted from equals, the remainders are equal.

Things which coincide with one another are equal to one another.

The whole is greater than the part.

given that , B is in between A and C

and C is between B and D

and also given that AB=CD

let AC=AB+BC .......(1)

    BD=BC+CD ........(2)

   subtract 1-2

we get, AC-BD=AB+BC-BC-CD

  AC-BD=AB-CD

we know AB=CD so we get

  AC-BD=0

 AC=BD

Hence, Proved

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Answer:

We established that AC=BD using Euclid's axioms.

Step-by-step explanation:

Things that are equivalent to one another are also equivalent to the same object.

The wholes are equal if equals are added to equals.

The remainders are equal when equals are subtracted from equals.

Things are equivalent to one another if they occur simultaneously.

A component cannot possibly equal the whole.

given that , B is in between A and C

and C is between B and D

and also given that AB=CD

let AC=AB+BC .......(1)

   BD=BC+CD ........(2)

  subtract 1-2

we get, AC-BD=AB+BC-BC-CD

 AC-BD=AB-CD

we know AB=CD so we get

 AC-BD=0

 AC=BD

Hence, Proved

Answer:

the mouse

Step-by-step explanation:

there I Got it

Answer:

800

Step-by-step explanation:

\(15 \div 100 \times x = 120 \\ 0.15x = 120 \\ x = 120 \div 0.15 \\ x = 800\)

To determine if, x, x2, and x4 are linearly independent, we need to see if there exists a non-trivial linear combination of these vectors that equals the zero vector.

Let's suppose there are scalars a, b, and c such that a*x + b*x2 + c*x4 = 0.
We can rewrite this as:
a*x + b*x^2 + c*x^4 = 0*x + 0*x^2 + 0*x^4
This gives us a system of equations:
a = 0
b = 0
c = 0
Since the only solution to this system is a = b = c = 0, we can conclude that ,x, x2, and x4 are linearly independent.

Therefore, there is no non-trivial linear combination of these vectors that equals the zero vector.

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Answer:

20km is in 12.5miles

Step-by-step explanation:

5miles= 8km

12.5miles=xkm

12.5÷5miles=2.5miles

2.5miles/km

2.5×8km=20km

Answer:

A

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

x is 738

Step-by-step explanation:

Answer:

9 dollars

Step-by-step explanation:

let x be per mile

the equation for solving this would be 0.5x + 3(flat fee)=amount you have to pay

The x is 12 since you have to go 12 miles

0.5(12)+3=amount you have to pay

6+3=amount you have to pay

$9=mount you have to pay

such pair of equation that have only one pair of solutions which satisfy both equation is linear equation

Step-by-step explanation:

the ans is 19 a6 x5 y3

93-12-62×a2xy×a2x×a2x3y2

ans. 19 a6 x5 y3 add all the spuare and cube

Answer:

\(31a^2x(3y-4-2x^2y^2)\)

Step-by-step explanation:

So the given equation is : 93a²xy - 124a²x - 62a²x³y². In this form you'll notice they all have a, and specifically a^2, and they also have x, but we only factor out x^1 since the first variable only has a degree of 1. So this gives us the equation: \(a^2x(93y-124-62x^2y^2)\). Now if we look at the coefficients you'll notice that they have a GCF of 31. So we can factor that out to. This gives you the equation: \(31a^2x(3y-4-2x^2y^2)\) Which is your completely factored equation. You could also technically group 2xy^2 and 3y to get: \(31a^2x(y(3-2xy)-4)\), although I'm not sure if that's considered "simplifying it"