20 points + Brainliest. Please help!

A piston consists of a closed cylinder with a moveable top. When a chemical reaction heats the gas inside the piston, the gas expands and lifts the top. For the thermodynamic system of the piston, are the values of heat Q and work W positive, zero, or negative?

A. Both Q and W are positive
B. Q is positive, W is negative
C. Both Q and W are negative
D. Q is positive, W is zero

The transfer of warmth (heat) from one item to another is known as heat conduction. Therefore, we can witness heat or thermal conduction when two things with differing temperatures come into touch.

Thus, The heat transfers from the hotter (the cup) to the colder (our hands) object when we contact the hot cup. When we added hot water to the cup that was at normal temperature, thermal conduction also took place.

The object's temperature is actually a measurement of how quickly its atoms are moving. The total energy produced by the atoms' vibrations is measured by the heat.

As a result, the atoms inside it begin to travel more quickly, which inevitably raises the likelihood that they will collide and conduction. It also relies on the density of the material we are working with how much they will clash.

Thus, The transfer of warmth (heat) from one item to another is known as heat conduction. Therefore, we can witness heat or thermal conduction when two things with differing temperatures come into touch.

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Answer:

Chemical energy is energy stored in the bonds of atoms and molecules. ...

Mechanical energy is energy stored in objects by tension. ...

Nuclear energy is energy stored in the nucleus of an atom—the energy that holds the nucleus together. ...

Gravitational energy is energy stored in an object's height.

Answer:

Nuclear power

Electricity

Mechanic

Gravity

Explanation:

The formula for calculating a percentage markup is (sticker price - invoice price)/invoice price × 100, markup percentage: markup price × 100

The price (or income) of a thing is its gross profit minus the cost to produce it or acquire it for resale. The gross profit is divided by the item's cost to calculate the markup percentage.

A Reliable Markup Ratio Although there isn't a set "ideal" markup percentage, the majority of businesses settle for a markup of 50%. A price that is 50% more than the value of the good or service is referred to as a "keystone" markup.

percentage of markup The price (or income) of a thing is its gross profit minus the cost to produce it or acquire it for resale. The gross profit is divided by the item's cost to calculate the markup percentage. To convert the value to percentage points, multiply by 100.

(sticker price - invoice price)/invoice price × 100

Where,

The difference between the sticker price and the invoice price is known as the cost of goods.

The dealer's profit over their cost is known as markup price. The formula is as follows:

(Selling price - Cost Price) / Cost Price is the markup price.

Markup proportion: pricing markup of 100

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Vegetation, noise barriers, and buffer zones all help reduce highway noise for nearby homes by absorbing, reflecting, or allowing sound waves to dissipate. The impact on drivers' noise experience varies, with the least change occurring with the use of buffer zones.

Each method impacts the acoustics of traffic noise differently.
1. Vegetation: Planting trees and shrubs helps to absorb and scatter sound waves, reducing the intensity of noise heard in nearby homes. The vegetation also creates a psychological buffer, making the noise seem less intrusive. However, the impact on the driver's noise experience would be minimal, as the vegetation is not directly between the highway and the driver.

2. Noise barriers: These structures, which can be dirt mounds or high vertical walls, block and reflect sound waves away from nearby homes. By physically obstructing the direct path of the sound, noise barriers significantly reduce the noise levels experienced by residents. For drivers on the highway, noise may be slightly reduced as some sound waves are reflected back towards the road; however, this effect is generally less significant than the noise reduction for nearby homes.

3. Buffer zones: A large open space between the highway and homes allows sound waves to dissipate and lose energy over distance, reducing the overall noise level experienced by residents. This method has the least direct impact on the acoustics of traffic noise but is still effective in lowering the noise levels in nearby homes. For drivers, the noise impact would be virtually unchanged as the buffer zone does not directly interact with the sound waves.

In summary, vegetation, noise barriers, and buffer zones all help reduce highway noise for nearby homes by absorbing, reflecting, or allowing sound waves to dissipate. The impact on drivers' noise experience varies, with the least change occurring with the use of buffer zones.

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Isolate the variable by dividing each side by factors that don't contain the variable.

m

=

32.021

¯

3

s

Vega has an apparent magnitude of 0.03 and an absolute magnitude of 0.58. It it was moved twice as far from Earth as it is now, its absolute magnitude number would increase This statement is. True.

Vega is a star, and its apparent magnitude of 0.03 indicates that it is one of the brightest stars visible from Earth. Its absolute magnitude of 0.58 is a measure of its intrinsic brightness, or how bright it would appear if it were located at a standard distance of 10 parsecs from Earth. If Vega were moved twice as far away from Earth, its distance from Earth would be four times greater, and its absolute magnitude would increase because its brightness would be spread out over a larger area. Therefore, it is true that if Vega were moved twice as far from Earth as it is now, its absolute magnitude number would increase.

Vega's apparent magnitude of 0.03 and absolute magnitude of 0.58 are indications of its brightness and intrinsic brightness, respectively. If Vega were moved twice as far from Earth as it is now, its absolute magnitude number would increase. This is because the distance from Earth would be four times greater, and the brightness of Vega would be spread out over a larger area. Therefore, Vega's intrinsic brightness would appear to decrease, resulting in a higher absolute magnitude.

Therefore, the statement that Vega's absolute magnitude number would increase if it were moved twice as far from Earth as it is now is true.

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Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

                        400 N                                          300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

x = 2 cm

Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

In the event of an accident or a car crash, road safety barriers and fences prevent automobiles from running off the road.

Newton's Three Laws of Physics can help explain what these safety barriers are and how they help to save lives during car accidents :

I.  Unless acted upon by an imbalanced force, an object at rest will remain at rest, and an object at constant velocity will remain at constant velocity.

II.  If an imbalanced force occurs, a mass will experience acceleration proportional to its magnitude.

III.  When you apply a force to an object, you will feel a force that is equal    in magnitude but opposite in direction.

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The total work done by Happy Hogan is 0 joules because the package is being carried at a constant velocity and there is no change in kinetic energy. This is because work done is the product of force and displacement of an object in the direction of the force.

Hence, if there is no force applied or the object is not displaced in the direction of force then no work is done. The formula for work done is given as follows:

Work done = Force × displacement × cosθHere, cosθ = 1 because the force is applied in the direction of displacement. But in this case, there is no force applied to the package. Happy Hogan is just carrying the package at a constant velocity, hence, there is no change in the kinetic energy of the package.

Therefore, the total work done by Happy Hogan while carrying the package at a constant velocity across the room for 12 seconds is zero joules.

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Answer:

mirrors bounce back light but lenses absorbs light

Mirrors and lenses compare in their interaction with light is that Mirrors bounce light from their surfaces; lenses do not. Hence option B is correct.

Reflection is the change of direction of the wave at the interface which separates two media. it get incident on the other media and get return to the same media is called as reflection. Common examples include the reflection of light, sound and water waves.

Mirror is a type of glass to which a silver layer is coated on the back side and on the silver layer any type of paint is painted.

We can see that in the dark room when we incident light on the mirror, the direction of the light changes at the point of the incidence. in the scientific language we can say that light has reflected from the surface of the mirror. in this case  angle of incidence is always equal to angle of reflection. Light get bounce off from the mirror into same medium as it was incident.

convex lens focuses all the light falling on it to a focus of the lens and concave lens diverges all the light, it do not bounce back the light.

Hence option B is correct.

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The disappearance of the reactant and not the appearance of the product in this experiment is flipping the sign-on rates for reactants.

The reaction rate is a measure of the change in concentration of the disappearance of a reactant or the change in concentration of the appearance of a product per unit of time. The vanishing rate value is always negative because the reactant concentration is consumed in the reaction. The product is formed in a reaction, so the rate of occurrence value is always positive.

The rate of reaction is defined as the rate of disappearance of reactants and the rate of appearance of products, and the rate constant is the constant of proportionality between reaction rate and concentration conditions. The rate of a chemical reaction can be measured as the rate of appearance of one of the products or the rate of disappearance of one of the reactants. If the reactant concentration decreases, use the negative sign to represent the rate of reaction for the reactant.

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Explanation:

t=2s

u=10

v=5

a=?

v=u+at

5=10+2a

2a=-5

a=-2.5

The current flowing in the 30 W lightbulb is 0.25 A.

The current flowing in the 60 W lightbulb is 0.5 A.

The current in each lightbulb is different since the lightbulbs are connect in parallel.

The current flowing in each lightbulb is determined by applying Ohm's law as shown below;

P = IV

where;

The current flowing in the 30 W lightbulb is calculated as;

P = IV

I = P/V

I = 30 / 120

I = 0.25 A

The current flowing in the 60 W lightbulb is calculated as;

P = IV

I = P/V

I = 60 / 120

I = 0.5 A

Thus, the current in each lightbulb is a function of power of the lightbulb and the voltage supplied to the lightbulb.

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The complete question is below:

two lightbulbs use 30 w and 60 w, respectively, when connected in parallel to a 120-v source. find the current in each lightbulb.

If you quadruple the temperature of a blackbody without changing its size, the total energy emitted increases by a factor of 256.

The total energy emitted by a blackbody is given by the Stefan-Boltzmann law, which states that the power radiated per unit area is proportional to the fourth power of the temperature (T^4).

Mathematically, we can express this relationship as:

P ∝ T^4

Where P is the power radiated per unit area and T is the temperature.

Now, let's consider the situation where we quadruple the temperature of the blackbody. In other words, if the initial temperature is T, the new temperature will be 4T.

Substituting this value into the Stefan-Boltzmann law, we have:

P ∝ (4T)^4
P ∝ 256T^4

So, when we quadruple the temperature of the blackbody, the total energy emitted increases by a factor of 256. This means that the power radiated per unit area will be 256 times greater than before.

It's important to note that this calculation assumes the size of the blackbody remains constant. If the size of the blackbody were to change, it would affect the total energy emitted differently. However, in the given scenario, where the size is not mentioned, we can conclude that quadrupling the temperature leads to a 256-fold increase in the total energy emitted.

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Answer: Green line

Explanation:

When an object is moving at constant velocity or speed rather, the line on a graph will be represented by a straight line.

They would be maintaining the same speed over a period of time so on a graph with time like the above, their journey would appear to be horizontal which would make the green line correct.

Answer:

Hope this helps!!!

Explanation:

Answer:

The answer to your problem is, C. In the same direction the wind blows

Explanation:

We know the if an object is light enough and there are gusts of winds then we can conclude that the light object will move toward the wind is faced.

Such in this case sand will move with the direction of wind. Look at the diagram down below \/ \/ \/ \/

-------------->      . ----->

/\ Wind           /\ sand

The sand will move with the wind flow.

Thus, the answer to your problem is, C. In the same direction the wind blows

a. The amplitude of the wave is 0.14 meters.

b. The frequency of oscillation of the wave is 17.7 Hz.

In the given expression, the amplitude of the wave is determined by the coefficient in front of the sine function, which is 0.14. The amplitude represents the maximum displacement of the wave from its equilibrium position.

The frequency of oscillation of the wave is determined by the coefficient of t in the argument of the sine function, which is 17.7. The frequency represents the number of complete oscillations of the wave that occur per unit time, in this case, per second (Hz).

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Answer:

4N

Explanation:

Given parameters:

Weight of stone when immersed in water  = 18N

Weight of water displaced  = 4N

Unknown:

Weight of the stone in air  = ?

Solution:

To solve this problem, we employ the Archimedes' principles.

It states that the upward buoyant force on a body is equal to the weight of the fluid displaced.

The weight of the water displaced is equal to the weight of the body.

So, the weight of the stone in air  = 4N

Answer:

all of the above?

Explanation:

I think that is

Answer:

Explanation:

where is the question

Answer:

Average speed = 541.67 mph

Explanation:

Answer:

shirt is little attached to the body, it can come off and fly away

Explanation:

In electrostatics, charges of different signs attract and charges of the same sign repel.

In this case, when a negative charge is placed on it, both the inventor and the shirt are charged, therefore there is a repulsive force, also there is an attraction between the positive charge of the roof attracts the negative charge, such as the shirt. of weak the two forces not greater than the resistance of the walk.

As the shirt is little attached to the body, it can come off and fly away

The answers to the questions of the object thrown off a cliff with a horizontal speed of 10 m/s and that reach the ground which is 30 m below after 3 seconds, are:

a. We know:

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity and the total horizontal distance traveled by the object, we need to use the following equations:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

\( v_{i_{x}} = \frac{x}{t} \)  (2)

d. The initial vertical velocity and the horizontal distance traveled by the object are 4.72 m/s and 30 m, respectively.

a. From the statement, we know:

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity we can use the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

Where:

\( y_{f}\): is the final height = 0 m  

\( y_{i}\): is the initial height = 30 m  

\( v_{i_{y}}\): is the initial vertical velocity =?  

g: is the acceleration due to gravity = 9.81 m/s²

t: is the time = 3 s  

And, to find the horizontal distance traveled by the object we need to use the equation:

\( v_{i_{x}} = \frac{x}{t} \)   (2)

Where:

\(v_{i_{x}} \): is the initial horizontal velocity = 10 m/s

x: is the horizontal distance =?

d. The solution to this problem is the following.

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)  

\( 0 = 30 m + v_{i_{y}}*3 s - \frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} \)

Solving for \(v_{i_{y}}\)

\( v_{i_{y}} = \frac{\frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} - 30 m}{3 s} = 4.72 m/s \)

Hence, the initial vertical velocity is 4.72 m/s.  

\( v_{i_{x}} = \frac{x}{t} \)

\( 10 m/s = \frac{x}{3 s} \)

\( x = 10 m/s*3 s = 30 m \)

Therefore, the horizontal distance traveled by the object is 30 m.

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The approximate distance to the galaxy is 78.7 million light-years.

The shift in the absorption line wavelength can be attributed to the Doppler effect, specifically the redshift caused by the expansion of the universe. We can use Hubble's law to estimate the distance to the galaxy. Hubble's law states that the recessional velocity of a galaxy is proportional to its distance from us. The equation is v = H0 * d, where v is the recessional velocity, H0 is the Hubble constant, and d is the distance. Rearranging the equation, we have d = v / H0. The redshift of the absorption line corresponds to the recessional velocity of the galaxy. By knowing the redshift and the Hubble constant, we can calculate the approximate distance. Considering the redshift from the given wavelength shift and using a Hubble constant of 70 km/s/Mpc, we find that the approximate distance to the galaxy is 78.7 million light-years.

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The resultant velocity of the parachute is 3.4 m/s.

The term resultant velocity refers to the effective velocity  with which the parachute moves. We know that velocity is a vector quantity. Recall that a vector is known to have both magnitude and direction.

Given that the magnitude of the resultant vector can only be obtained geometrically we have;

Vertical component =   3.0 m/s

Horizontal component = 1.6 m/s

Resultant velocity = √(3)^2 + (1.6)^2

= 3.4 m/s

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a man has a mass of 70kg. then calculated weight on earth where Gravity strength is 10N/kg is 700N

Gravity, which derives from the Latin word gravitas, which means "weight"[1], is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between things and governs the motion of planets, stars, galaxies, and even light.

Weight W = mg = 70*10 =  700 N

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Answer:

the elephant would hit first

Explanation:

the elephant would hit first because it has a greater mass than the feather does

If the mass of a glider in an oscillatory system is doubled while assuming no damping, the period of oscillation would remain unchanged.

The period of oscillation (T) is the time taken for one complete cycle of oscillation, which is independent of the mass of the object in simple harmonic motion. The period is determined by other factors such as the stiffness of the system and the restoring force acting on the object.

In a simple harmonic oscillator, the period is given by the equation:

T = 2π * √(m/k)

Where m is the mass of the object and k is the spring constant or the stiffness of the system.

Doubling the mass of the glider would increase the numerator of the equation by a factor of 2, but it would also increase the denominator by the same factor since the spring constant remains constant. As a result, the ratio of mass to stiffness remains the same, and the square root of that ratio (which represents the period) also remains the same.

Therefore, doubling the mass of the glider would not affect the period of oscillation, and it would remain unchanged.

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