A soccer field is viewed from above, while a ball is kicked eastward with an initial speed of 10.0 m/s. The ball experiences a constant eastward acceleration of 0.75 m/s 2 over a distance of 20.0 m. Immediately after this 20.0 m distance, the ball is kicked northward in a manner that does not change its speed at that point, just its direction. The ball is allowed to come to a complete stop. How far north does the ball travel before stopping if the acceleration after this kick is 1.15 m/s 2

Answer:

11.5m/s

Explanation:

v=2.5

a=1.5

t=6s

vf=vi+at

vf=2.5+(1.5)(6)

vf=11.5

The pair-creation or pair-production is a process in which an electron and a positron are created by an incident of a photon on a nucleus. This is a process in which the radiation energy is converted into matter.

Thus in this process, the matter is created.

Therefore the correct answer is option B.

Answer:

A

Explanation:

Answer:

sddww

Explanation:

szsswa

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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There are few points given to us in this question.

A) There are 1.41× 10^16 m in 1.5 light years

B) There are 9.4 × 10^4 AU in 1.5 light years

What is a light year?

Many might confuse it with time because of the presence of term “year” this term is actually used for space objects to measure distance. Light Year is the distance travelled by light in one Earth year.

It’s a term named by German scientist Friedrich Bessel who first used it in 1838.

One light year is about 6 trillion miles or 9.46 trillion kilometers.

To solve part A, we will first multiply V(light) with time (in seconds) in a year and multiply the product with 1.5 light year per light year.

Now let us understand what is Astronomical Unit AU?

AU is also used to measure distance but within our solar system. It is usually the average distance between Sun and Earth. It is about 93 million miles or 150 million kilometers.

To solve part B, we first convert the light year to AU and we do this by using the final value from part A and then convert it in significant figure to obtain a proper value for the answer.

The calculations are shown in the figures below.

Hence,

A) There are 1.41× 10^16 m in 1.5 light years

B) There are 9.4 × 10^4 AU in 1.5 light years

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Answer:

Explanation:

The displacement is the distnce of the shopper from the starting point.

Sum of movement along the vertical = 40-20 = 20m

Movement along the horizontal (x direction) = 15.0m

Displacement will be gotten using the pythagoras theorem.

d = √20²+ 15²

d = √400+225

d = √625

d = 25.0m

Hence the shoppers total displacement is 25.0m

Displacement is the shortest distance between the initial and final points. The total displacement of the shopper is 25 m.

Displacement :

It is the difference between the initial and final point or the shortest distance between the initial and final point.

Given Here,

A shopper moves south = 40m

Shopper took a turn and move = 15 m

Shopper again take a  turn and move  = 20 m

So,

The movement of shopper in Y-axis = 40-20 = 20 m

The movement of shopper in X-axis = 15 m

The displacement can be found using the Pythagoras theorem,

\(\bold{ d = \sqrt{ 20^2+ 15^2}}\\\\\bold {d = \sqrt{ 400+225}}\\\\\bold {d = \sqrt{625}}\\\\\bold {d = 25.0m}\)

Therefore, The total displacement of the shopper is 25 m.

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The superposition principle  used to calculate the electric field's strength at point P, which comes out to be 15 Q/oA.

The superposition principle states that the total electric field at a point is equal to the vector sum of the electric fields due to each individual charge at that point.

In this case, we have five charges, each producing an electric field at point P, so the total electric field at P is:

E = (E1 + E2 + E3 + E4 + E5) = (5Q/εoA + 4Q/εoA + 3Q/εoA + Q/εoA + 2Q/εoA) = (15Q/εoA)

So the magnitude of the electric field at point P is 15 times the magnitude of the electric field due to a single charge.

If the magnitude of the electric field due to one charge is given by

E = Q/εoA,

then the magnitude of the electric field at point P is:

E = 15 * (Q/εoA) = 15Q/εoA

So the magnitude of the electric field at point P is 15Q/εoA.

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Answer:

join my z o o m

Explanation:

Answer:

11,000 kg

(a) 11.2 m/s

(b) 1.6 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)

132,000 kg km/h = 22,000 kg km/h + m (10 km/h)

110,000 kg km/h = m (10 km/h)

m = 11,000 kg

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)

-mv + 10mv = m v₁ + 2m v₂

9mv = m (v₁ + 2 v₂)

9v = v₁ + 2 v₂

Since the collision is elastic, kinetic energy is also conserved.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²

mv² + 50mv² = m v₁² + 2m v₂²

51mv² = m (v₁² + 2 v₂²)

51v² = v₁² + 2 v₂²

We know v = 1.60 m/s.  So the two equations are:

14.4 = v₁ + 2 v₂

130.56 = v₁² + 2 v₂²

Solve the system of equations using substitution.

130.56 = (14.4 − 2 v₂)² + 2 v₂²

130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²

0 = 6 v₂² − 57.6 v₂ + 76.8

0 = v₂² − 9.6 v₂ + 12.8

v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)

v₂ = 1.6 or 8

If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.

If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.

We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision.  Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.

Answer:

Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.

Explanation:

Answer: Colonialism is a big topic, but it can only be understood by looking at human experiences. Formal colonialism first came to the region we today call Ghana in 1874, and British rule spread through the region into the early twentieth century. The British called the territory the “Gold Coast Colony”.

Explanation: hey, hope this hlps! oh, btw you picked the wrong subject for this question it should have been history insteat of phiscics!

Answer:

C

Explanation:

I think buh were is the question

The weight of the cylinder in pounds is 26.45 lbs.

To determine the weight of the cylinder in pounds, we first need to calculate its volume. The volume of a cylinder is given by :

V = πr²h

where,

r = the radius

h = the height (or length) of the cylinder.

Given the radius and length, we can substitute these values into the formula to get:

V = π * (0.04 m)² * (0.11 m) = 0.001539 m³

Since the mass density of steel is 7850 kg/m3, we can multiply the volume by the mass density to find the mass of the cylinder:

mass = 7850 kg/m³ * 0.001539 m³

mass = 12 kg

To convert this mass to pounds, we can multiply it by 2.20462 (1kg = 2.20462 lbs)

12 kg * 2.20462 = 26.45 lbs

Hence, the weight of the cylinder in pounds is 26.45 lbs.

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It promotes enjoyable experiences for both guests and hosts; It lessens the negative effects of tourism on the environment; It increases local residents' access to work and financial prospects; It promotes conservation by offering financial advantages in its direction.

The World Tourism Organization defines ecotourism as all forms of nature-based travel in which visitors' primary interests are in observing and appreciating the environment as well as the local cultures that are still practiced in natural settings.

Here are a few instances of ecotourism:

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Answer:

i dont know

Explanation:

sorry i cant answer this question

Answer:

\(v_{2'}=8.1\:\mathrm{m/s}\)

Explanation:

In a perfectly elastic collision, the total kinetic energy of the system is maintained. Therefore, we can set up the following equation:

\(\frac{1}{2}m_1{v_1}^2+\frac{1}{2}m_2{v_2}^2=\frac{1}{2}m_1{v_{1'}}^2+\frac{1}{2}m_2{v_{2'}}^2\)

Since the second block was initially at rest, \(\frac{1}{2}m_2{v_2}^2=0\).

Plugging in all given values, we have:

\(\frac{1}{2}m_1{v_1}^2=\frac{1}{2}m_1{v_{1'}}^2+\frac{1}{2}m_2{v_{2'}}^2,\\\\\frac{1}{2}\cdot4.4\cdot8.4^2=\frac{1}{2}\cdot 4.4 \cdot (-2.5)^2+\frac{1}{2}\cdot 4.4\cdot {v_{2'}}^2,\\\\{v_{2'}}=\sqrt{64.31},\\\\{v_{2'}}\approx\fbox{$8.1\:\mathrm{m/s}$}\)..

No, the potential of a non-uniformly charged sphere cannot be the same as that of a point charge.

The potential of a charged sphere depends on the distribution of charge throughout the sphere, whereas the potential of a point charge depends only on its own charge and the distance from it. A non-uniformly charged sphere has different charges distributed at different distances from a point in space, so the potential at that point will vary depending on the distribution.

In contrast, a point charge has all its charge concentrated at a single point, so the potential at any given distance will be the same regardless of the distribution of charge in the surrounding space. Therefore, the potential of a non-uniformly charged sphere cannot be the same as that of a point charge.

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Answer:

The two methods will yield different results as one is subject to experimental errors that us the Archimedes method of measurement, the the density measurement method will be more accurate

Explanation:

This is because the density method using the calculated volume will huve room for less errors that's occur in practical method i.e Archimedes method due to human error

The force that acts on a projectile in the horizontal direction is Gravitational force.

A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.

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Given,

The radius of the ball, r=0.101 m

The mass of the ball, m=0.400 kg

The angular speed of the ball, ω=93 rad/s

a.

The linear velocity of the ball is given by,

The translational kinetic energy is given by,

On substituting the known values,

hus the translational kinetic energy of the ball is 17.6 J

b.

The moment of inertia of the ball is given by,

The rotational kinetic energy of the ball is given by.

On substituting the known values,

hus the trotational kinetic energy of the ball is 11.8 J

.

From the law of conservation of energy, the energy can neither be created nor be destroyed but can be converted from one form to another.

When ball rolls up the hill the ball will lose its translational and rotational kinetic energy. But the lost kinetic energy will be converted into its gravitational potential energy.

Therefore, the gravitational potential energy of the ball when it is up the hill is equal to the sum of its translational and rotational kinetic energy.

Thus,

Where g is the acceleration due to gravity and h is the height that the ball will reach before coming to rest.

On rearranging the above equation,

On substituting the known values,

herefore the ball will treach a height of 7.5 m before coming to rest.

Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.

The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.

They are being affected by the kinetic frictional force, which is caused by:

f = μk * N

Therefore,

fB = μk * N = μk * mB * g

Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,

fC = μk * N = μk * mC * g

where mC is the mass of Car C.

For Car A, the x-component of the tangential acceleration is given by:

aA = (fB - fC) / mA

where mA is the mass of Car A.

We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:

aA = (μk * mB * g - μk * mC * g) / mA

aA = μk * g * (mB - mC) / mA

Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:

aA = (mB - mC) * 9.81 / mA

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Time it takes energy to pass through radiative zone is :  A) 8 minutes

Energy generated in the core of the Sun takes about 8 minutes to pass through radiative zone and reach the top of convective zone. The radiative zone is a layer of the Sun that lies just outside the core and it is characterized by high density and high temperature.

In this zone, energy is transported by photons that bounce around between atoms and ions that make up the plasma of the Sun. This process is known as radiative diffusion and is relatively slow compared to convective transport of energy that takes place in the outer layers of Sun.

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Answer:

Classic 5 Day Split

Day 1 – Chest

Day 2 – Legs

Day 3 – Rest

Day 4 – Back

Day 5 – Arms

Day 6 – Shoulders

Day 7 – Rest  

Upper Lower Push Pull Legs

Day 1 – Upper

Day 2 – Lower

Day 3 – Rest

Day 4 – Push

Day 5 – Pull

Day 6 – Legs

Day 7 – Rest  

5 Day Split Variation

Day 1 – Chest

Day 2 – Legs & Shoulders

Day 3 – Back

Day 4 – Biceps & Triceps

Day 5 – Core & Cardio

Day 6 – Rest

Day 7 – Rest

Explanation:

Answer:

Push or pull of an object is considered a force. Push and pull come from the objects interacting with one another. Terms like stretch and squeeze can also be used to denote force.

In Physics, force is defined as:

The push or pull on an object with mass that causes it to change its velocity.

Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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The period of the wave from the calculation can be seen to be 10 s

When we talk about the period of the wave what we mean is the inverse of the frequency of the wave. Thus the period and the the frequency of the wave are actually the opposites of each other as we know in physics.

Given f = 0.10 Hz

T = 1/f = 1/0.10

T = 10 seconds

In the study of wave motion, the period of a wave is a crucial variable that is employed in many fields, such as optics, seismology, and communication systems.

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Answer:

Well If the unknown is one of four possible compounds which melt at 102, 104, 106, and 108° C, it is most likely that which melts at 108° C. To summarize, an impure solid melts over a wide range and at a temperature lower than that of the pure solid.

Explanation:

I have known this since grade school

Answer: 0.09 J

Explanation: K = 200 N/m , 1/2 X 200 N/m X (0.03 M)^2 = 0.09 J

You push on a box with net force of 5 N and it accelerates. If you exert  same net force on an object that has half the mass, then :The object will accelerate twice as much.

Newton's second law of motion states that : acceleration of object is directly proportional to net force acting on it and inversely proportional to  mass. Therefore, if net force acting on object is constant, and mass is reduced by factor of 2, then its acceleration will be twice as much.

In this case, if you exert net force of 5 N on object with mass M, and it accelerates with acceleration A, then :

F = M*A; F is the net force applied.

If you exert same net force of 5 N on an object that has half the mass of the previous object, i.e., its mass is M/2, then its acceleration would be:

A' = F/(M/2) = 2F/M = 2A;  A' is the new acceleration of the object.

Object will accelerate twice as much if you exert the same net force on an object that has half the mass.

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