Name:
Mellisayang
Kinematics practice problems #1
1
A high school athlete runs 1.00 x 10 m in 12.20 s. What is the velocity in m/s and km/h?
Answer:
\(velocity = \frac{distance}{time} \\ velocity = \frac{10}{12.20} \\ velocity = \frac{50}{61} \\ multiply \: by \: 3.6u \: can \: convert \: to \: km \: per \: hour \\ velocity = \frac{50}{61} \times 3.6 \\ v = \frac{180}{61} \\ v = 2.95 \frac{km}{h} \\ thank \: you\)
Make a tree diagram based on the topic motion which includes all the concept like uniform & non uniform motion accelerated motion equation of motion motion etc
I think it is a education tips
Explain how motion is relative
Answer:
it's always relative because it's measured or observed with respect to another thing
Explanation:
do you understand?
A 47 kg gymnast hangs vertically from a pair of parallel rings.
If the ropes supporting the rings are attached to the ceiling directly above, what is the tension in each rope?
The tension is in each rope will be 230.535 N .
Tension also known as tensile force is the force developed in a rope, string, or cable when it is stretched by an applied force.
Formula for the tension is T = mg.Mass of the gymnast = m = 47 kg
Acceleration due to gravity = g = 9.81 \(m/s^{2}\)
T = m*g
T = 47 * 9.81
T = 461.07 N
Since there are two parallel ropes attached to the ceiling, therefore tension will be equally divided into each rope respectively.
Tension in each rope = t
t = \(\frac{T}{2}\)
t = \(\frac{461.07}{2}\)
t = 230.535 N
The tension in each rope will be 230.535 N, when both the ropes are attached to the ceiling directly above the gymnast.
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Not far from the mirror showcase (the figure shows a top view) there is a person (indicated by point H in the figure), and closer to the showcase there is a lamppost (point C). By building, find the positions at which the observer (points H, which are indicated for example and are not the answer) will see in the window: a person to the left of the pillar; the person to the right of the pillar; a pole blocking a person
The observer (point H) must be positioned to the right of the person and to the left of the lamppost, to the left of the person and to the right of the lamppost, or behind the lamppost to see the person obstructed by it.
To determine the possible positions of the observer (point H) relative to the mirror showcase, we need to consider the given information about the position of the person and the lamppost.
If the person is to the left of the lamppost (point C) as seen in the window, then the observer (point H) must be positioned to the right of the person and to the left of the lamppost. This is because the mirror will reflect the image of the person to the right, and the observer must be positioned to the right of the reflected image to see it.
If the person is to the right of the lamppost (point C) as seen in the window, then the observer (point H) must be positioned to the left of the person and to the right of the lamppost. This is because the mirror will reflect the image of the person to the left, and the observer must be positioned to the left of the reflected image to see it.
If the lamppost (point C) obstructs the view of the person as seen in the window, then the observer (point H) must be positioned behind the lamppost, either to the left or to the right of it. This is because the mirror will not be able to reflect the image of the person due to the obstruction caused by the lamppost.
In summary, the possible positions of the observer (point H) relative to the mirror showcase are:
To the right of the person and to the left of the lamppost, to see the person to the left of the lamppost. To the left of the person and to the right of the lamppost, to see the person to the right of the lamppost. To the left or right of the lamppost, behind it, to see the obstruction of the person caused by the lamppost.
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Complete question:
Using the given information, determine the possible positions of the observer (point H) relative to the mirror showcase such that the following are observed:
1 - The person is to the left of the lamppost (point C) as seen in the window.
2 - The person is to the right of the lamppost (point C) as seen in the window.
3 - The lamppost (point C) obstructs the view of the person as seen in the window.
A gas always spreads out to fill all available space.
True or False
Science Hw
Answer:
true
Explanation:
i know this im in 6th grade
This is True. Gases spread around freely and take up any available space. For example, there is oxygen. Oxygen is a gas we breathe in and spreads around freely, taking up any space.
On a fake planet, you find that on a certain day at noon no shadow is cast. At the same time your friend sees a shadow due to the Sun being 12 degrees away from the Zenith. Knowing the distance between you and your friend is 500 km, what is the circumference of this fake planet
Answer:
In 250 BC, Eratosthenes measured the circumference to be about 24,500 miles:
by this method, 12 deg = 12 / 360 = 1/30 of the planet's surface\
30 * 500 km = 15,000 km in circumference, about 9,200 miles
Which of the following statements from Dalton's atomic theory is no longer true, according to modern atomic theory?
the statement from Dalton's atomic theory that is no longer true is "Atoms are indivisible and cannot be divided into smaller particles."
Dalton's atomic theory, proposed in the early 19th century, stated that atoms were indivisible and indestructible particles, meaning they could not be further divided into smaller particles. However, with advancements in scientific understanding and the development of subatomic particle physics, it has been discovered that atoms are not indivisible. Atoms are composed of subatomic particles, namely protons, neutrons, and electrons. Protons and neutrons reside in the nucleus at the center of the atom, while electrons orbit around the nucleus. Furthermore, scientists have identified even smaller particles within the nucleus, such as quarks and gluons. Hence, the concept of atoms being indivisible, as proposed in Dalton's atomic theory, is no longer valid based on modern atomic theory.
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Which of the following statements from Dalton's atomic theory is no longer true, according to modern atomic theory?
A) All atoms of a given element are identical.
B) Atoms are not created or destroyed in chemical reactions.
C) Elements are made up of tiny particles called atoms.
D) Atoms are indivisible and cannot be divided into smaller particles.
True or False: if a sound wave's frequency changes, its speed stays the same
A 25N force is acting on a body moving on a straight line with Initial momentum 20 kam's. Find the final momentum after 4 seconds. (Fxt=Pr-Pi)
The final momentum of the body is equal to 120 Kg.m/s.
What is momentum?Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.
If m is an object's mass and v is its velocity then the object's momentum p is: \({\displaystyle \mathbf {p} =m\mathbf {v}\) . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.
Given the initial momentum of the body = Pi = 20 Kg.m/s
The force acting on the body, Pf = 25 N
The time, Δt = 4-0 = 4s
The Force is equal to the change in momentum: F ×Δt = ΔP
25 × 4 = P - 20
100 = P - 20
P = 100 + 20 = 120 Kg.m/s
Therefore, the final momentum of a body is 120 Kg.m/s.
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the tiny ripples in the background radiation cobe found are due to
The tiny ripples in the background radiation COBE found are due to the quantum fluctuations that occurred during cosmic inflation.
What is COBE?
The Cosmic Background Explorer (COBE) is a satellite that was launched in 1989 to study the cosmic microwave background radiation. It was the first satellite mission dedicated solely to cosmology, and it provided groundbreaking insights into the early universe.
What is the cosmic microwave background radiation?
The cosmic microwave background radiation is a faint glow of electromagnetic radiation that permeates the entire universe. It is thought to be the remnant of the Big Bang, and it has been detected in every direction of the sky.
What are quantum fluctuations?
Quantum fluctuations are tiny variations in the energy density of the early universe. They are a natural consequence of the uncertainty principle in quantum mechanics, and they played a crucial role in the formation of the large-scale structure of the universe.
What is cosmic inflation?
Cosmic inflation is a period of exponential expansion that occurred in the early universe. It is thought to have happened within the first 10^-32 seconds after the Big Bang, and it is responsible for the large-scale homogeneity and isotropy of the universe. Cosmic inflation was proposed in the early 1980s to solve some of the problems with the Big Bang model.
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A low energy photon hits
the electron in the image.
What happens to the
electron if the energy is
below the threshold for
absorption?
A low energy photon hits the electron in the image therefore the photon will bounce off the electron if the energy is below the threshold for absorption.
What is a Photon?This is referred to as a particle representing a quantum of light or other electromagnetic radiation and it carries energy proportional to the radiation frequency but has zero rest mass.
When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level and bounces of if the energy is below the threshold for absorption.
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Compared with the photons of light that shines on glass, the emerging photons are: a) Refracted at a larger angle b) Refracted at a smaller angle c) Not refracted d) Absorbed by the glass
Compared with the photons of light that shines on glass, the emerging photons are b) Refracted at a smaller angle.
When light shines on glass, the photons of light are refracted, meaning they change direction as they pass through the glass.
The angle of refraction depends on the angle of incidence (the angle at which the light hits the glass) and the refractive index of the glass.
Generally, the emerging photons are refracted at a smaller angle than the incident photons, which means they bend towards the normal (a line perpendicular to the surface of the glass).
Therefore, the correct answer is b) Refracted at a smaller angle.
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I need help with this. I think I got it correct, but I wanna make sure.
Answer:
A because the bigger it is the the more force needs to act apond it
Explanation:
Answer:
ur answer is correct good job
Explanation:
Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed into other types but is not itself produced?
Kinetic energy
Chemical energy
Gravitational energy
Heat energy
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
The Correct choice is :
Kinetic Energybecause the ball comes in motion as the boy kicks the ball.
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a capacitor consists of a set of two parallel plates of area ???? separated by a distance ????. this capacitor is connected to a battery that maintains a
The correct answer is option D: halved
Energy becomes half i.e. E' = E/2 if the distance between the plates is doubled.
Let's say the area of parallel plates = A
The distance between plates = d
The potential difference between Plates = V
Now, the capacitance is given by
C = ∈\(o\) A / d
If the separation between the plates is doubled then the value of capacitance will become half.
C' = ∈\(o\) A / 2d
C' = C/2
Now, we can determine the electrical energy stored in the capacitor which is given by
E = \(\frac{1}{2}\) \(CV^{2}\)
When the distance between the plates is doubled then energy becomes
E' = \(\frac{1}{2}\) x \(\frac{C}{2}\) x \(V^{2}\)
E' = E/2
Thus, energy becomes half i.e. E' = E/2 if the distance between the plates is doubled.
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The complete question is:
A capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is connected to a battery that maintains a constant potential difference V across the plates. If the separation between the plates is doubled, the electrical energy stored in the capacitor will be: _______
a- doubled
b- unchanged
c- quadrupled
d- quartered
e- halved
A wire carrying a 35.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.55 N force on the 3.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet
Answer:
7.65 T
Explanation:
From the question,
Using,
F = BILsinФ......................... Equation 1
Where F = Force, B = magnetic field strength, I = current, L = Length, Ф = Angle.
Make B the subject of the equation
B = F/ILsinФ........................Equation 2
Given: F = 2.55 N, I = 32 A, L = 3.00 cm = 0.03 m, Ф = 90° (perpendicular)
Substitute into equation 2
B = 2.55/(32×0.03×sin90°)
B = 2.55/0.96
B = 7.65 T
A 20 gram bullet strikes a block of wood that has a mass of 2 kg causing the two to move together at 2.5 m/s. How fast was the bullet originally moving out of the gun?
Answer:
V1i=252.5m/s
Explanation:
Inelastic collision
so the equation should be: m1v1i+m2v2i=(m1+m2)Vf
plug the numbers into the equation: 0.02(v1i)+2(0)=(0.02+2)2.5
so the answer should be: V1i=252.5m/s
(a) an electron has a kinetic energy of 6.37 ev. find its wavelength. nm (b) a photon has energy 6.37 ev. find its wavelength. nm
If an electron has a kinetic energy of 6.37 ev, then the wavelength of the electron is 9.82 nm. The wavelength of the photon is 1.956 nm.
(a) To find the wavelength of an electron using kinetic energy, we use the de Broglie equation as follows: λ = h / p
where λ = wavelength
h = Planck's constant = 6.626 x 10^-34 J s
E = kinetic energy of the electron
p = momentum of the electron = sqrt(2mE) where m = mass of the electron = 9.11 x 10^-31 kg
Given: E = 6.37 eV = 6.37 x 1.6 x 10^-19 J = 1.0192 x 10^-18 J
Using the above equations, we get: p = sqrt(2 x 9.11 x 10^-31 kg x 1.0192 x 10^-18 J) = 6.737 x 10^-20 kg m/sλ = 6.626 x 10^-34 J s / 6.737 x 10^-20 kg m/s = 9.82 nm
Therefore, the wavelength of the electron is 9.82 nm.
(b) To find the wavelength of a photon using energy, we use the equation: E = hc / λ
where E = energy of the photon
h = Planck's constant = 6.626 x 10^-34 J s
λ = wavelength
c = speed of light = 3 x 10^8 m/s
Given: E = 6.37 eV = 6.37 x 1.6 x 10^-19 J = 1.0192 x 10^-18 J
Using the above equation, we get:
λ = hc / E = 6.626 x 10^-34 J s x 3 x 10^8 m/s / 1.0192 x 10^-18 J = 1.956 nm
Therefore, the wavelength of the photon is 1.956 nm.
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help in solving this question please
(question is on the picture )
Answer:
Jesus
Explanation:
he is the way
How do you find a wavelength?
62. Two forces are acting on the ring in Figure 22. What is the net force acting on the ring?
We have that force forces on a plane we Resolve to the x plane and the y plane then we derive the corresponding result using the equation
\(R=\sqrt{(\sum fx)^2+(\sum fy)^2}\)From the question we are told
Two forces are acting on the ring in Figure 22. What is the net force acting on the ring.ForceGenerally the equation for the Net Force is mathematically given as
\(R=\sqrt{(\sum fx)^2+(\sum fy)^2}\)
Therefore
For two forces
We Resolve to the x plane and the y plane then we derive the corresponding result using the equationFor more information on Force visit
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Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s
The first step is to find the frequency heard by each aircraft as they approach each other. Let's call the frequency heard by each aircraft.
What speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency?According to the Doppler effect formula for sound, the frequency heard by an observer moving towards a stationary source is given by:
f' = (v + vs) / (v + vd) * f
where f is the emitted frequency, v is the speed of sound, vs is the speed of the source (aircraft in this case), and vd is the speed of the observer (also an aircraft in this case).
Since both aircraft are approaching each other at the same speed, we can assume that their speeds are equal and call it v_a. Therefore, we have:
f' = (v + v_a) / (v - v_a) * f
We are given that the frequency heard by each aircraft is 2 times the emitted frequency, so we can write:
2f = (v + v_a) / (v - v_a) * f
Simplifying this equation, we get:
2 = (v + v_a) / (v - v_a)
2(v - v_a) = v + v_a
v = 3v_a
Now we can substitute this value of v into the speed of sound formula to get the speed of each aircraft:
343 m/s = (3v_a + v_a)
v_a = 343 / 4 = 85.75 m/s
Finally, we can convert this speed to km/hr:
85.75 m/s * 60 s/min * 60 min/hr / 1000 m/km = 308.7 km/hr
Therefore, each aircraft must have a speed of approximately 308.7 km/hr in order for the pitch they both hear to be 2 times the emitted frequency.
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As much as you love high school, especially your Physics class, you're super excited for 2026 when the US and Mexico will host the World Cup. In order to jump 5 years into the future you charter a spaceship that moves at 0.92c (92% the speed of light). How long will you be on the ship for?
0.35 years
1.96 years
2.67 years
3.63 years
4.28 years
5.90 years
Answer:
If I had to guess I would guess 3.63 years
Explanation:
Two 2.10 cm × 2.10 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC .
Part A
What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm ?
Part B
What is potential difference across the capacitor if the spacing between the plates is 1.30 mm ?
Part C
What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm ?
Part D
What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm ?
The electric field strength inside the capacitor does not depend on the distance between plates. Hence, Potential difference and Electric field strength is -234V and -1.8 x 10^5 V/m respectively.
What does "permittivity of open space" mean?The ability of electrical fields to pass through a conventional vacuum is represented by the physical constant known as the permittivity of free space. The constant has a relative standard uncertainty of 1.5 x 10-10 and is equal to around 8.854 x 10-12 F/m (farad per metre).
Q= charge => ± 0.708 nC
E => electric field strength = Q/Aεο
A=> area of plates 2.10x 2.10 cm2.
εο = > 8.854 x 10-12 F/m.
E= -0.708 x10^-9/ (2.1 x 2.1 x 8.854 x 10^-4 x 10^-12)
= -1.8 x 10^5 V/m.
Potential difference = Ed => -1.8 x 10^5 x 1.3 x 10^-3 => -2.34 x 10^2V
=> -234V.
How strong is the electric field?
The intensity of an electric field at a specific location is expressed quantitatively as "electric field strength." The volt per metre (V/m or Vm-1) is the common unit.
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All of the forces that act on an object add up to equal________________
Group of answer choices
mass
net force
volume
speed
Volume of 10 coin is 25ml what is the volume of 1 coin
Answer: 2.5 ML
Explanation:
10 ÷ 10 = 1
25 ÷ 10 = 2.5
The volume of 1 coin is 2.5 ML
How much does it take for a student running at an average speed of 5 m/s to cover a distance of 2 km
Answer:
400 min
Explanation:
Average speed = Distance ÷ Time
According to the question,
We have to find time which takes run the given distance.
Time = Distance ÷ Speed
Time = 2 × 1000 m ÷ 5 m/s
Time = 2000 ÷ 5
Time = 400 minutes
It takes 400 minutes.
If we find it in hours,
400 ÷ 60 h = 6.67 hours
Hope this helps you :-)
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four point charges, each of magnitude 9.66 µc, are placed at the corners of a square 87.1 cm on a side. if three of the charges are positive and one is negative, find the magnitude of the force experienced by the negative charge. the value of coulomb’s constant is 8.98755 × 109 n · m2 /c 2 .
The magnitude of the force experienced by the negative charge is 0.198N.
The Coulombs law is an expression that states that magnitude of the force between two charges q and Q separated by a distance r is given by
F=k|Q|q|r2
where k is Coulomb constant.
Answer and Explanation:
Let us visualize corners of the square as four points on the xy-axis. The four points would be origin (0,0), then (78.9 cm, 0), then (0, 78.9 cm) and (78.9 cm, 78.9 cm). These points are corners of the square described in the question. Let negative charge be at origin. Let charge 1 be located at (78.9 cm, 0), that is, its located along x-axis, a distance 78.9 cm away from the negative charge. The force due to this charge 1 acts in positive x-direction as the two charges attract. Let charge 2 be at point (0, 78.9 cm) and the force due to this charge acts in the positive y-direction. Charge 2 is also 78.9 cm away from negative charge. Let charge 3 be located at point (78.9 cm, 78.9 cm). Force due to this charge has the x and y-components. The angle this force makes with positive x-axis is 45 degrees since this is a square. The distance between charge 3 and negative charge is
√(78.9cm)2+(78.9 cm)2 =111.5814501cm.
Now we can calculate force on the negative charge due to each individual positive charge. Force due to the charge 1 is \(F_{1} =k|+q||-q| r^{2}(8.98755*109N.m^{2}/C^{2})*(2.68*106)*(2.68*106)^{2}(0.789m)^{2} =0.1036947816N\)
in positive x-direction. Force due to the charge 2 has same magnitude as force due to charge 1, but acts in the positive y-direction.
F2 =0.1036947816N
The force due to the charge 3 is
\(F_{3}=k|+q||-q| r^{2} =(8.98755*109N.m^{2}/C^{2})*2.68*10^{-6} )^{2}(1.115814501m)^{2}= 0.05184739076N\)
The x and y-components of force due to charge 3 are
F3,x=F3cos45=(0.05184739076√22)N=0.03666164159N
in positive x-direction, and
F3,y=F3sin45=(0.05184739076√22)N=0.03666164159N
in positive y-direction.
Therefore, x-component of the resultant force experienced by the negative charge is
Fx=F1+F3,x=0.1036947816N+0.03666164159N=0.1403564232N
and y-component is
Fy=F2+F3,y=0.1036947816N+0.03666164159N=0.1403564232N
Therefore, magnitude of the force experienced by the negative charge is
\(F= \sqrt{Fx_{2}+F_{2y} }= \sqrt{(0.1403564232N)^{2}+(0.140356432N)^{2} } =0.198493973N\) =0.198N
correct to the three significant figures.
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Please help me i need help with this question
Answer:
for the first time in the future of our games are based on your car advertising
Explanation:
for the first time in the fhgvhbgj tire and wheel drive automatic captions and subtitles for the first time in the future of our games of