Answers
it's similar to your question hope it is helpful for you
Related Questions
A certain green light bulb emits at a single wavelength of 550 nm. It consumes 55 W of electrical power and is 75% efficient in converting electrical energy into light. (a) How many photons does the bulb emit in one hour? (b) Assuming the emitted photons to be distributed uniformly in space, how many photons per second strike a 10 cm by 10 cm paper held facing the bulb at a distance of 1.0 m?
Answers
Answer:
a) #_total = 4 10²³ photons / h, b) # _photon_area = 3 10²² photons
Explanation:
a) Let's start by calculating the energy of an emitted photon
E₀ = h f
c = λ f
substituting
E₀ = h c /λ
E₀ = \(\frac{6.62 \ 10^{-34} \ 3 \ 10^{8} }{550 \ 10^{9} }\)
E₀ = 3.6 10⁻¹⁹ J
Let's use a direct proportion rule (res rule) if a photon has Eo, how many photons are there in 55W
#_foton = 55 / E₀
# _photon = 55 / 3.6 10⁻¹⁹ = 15.27 10¹⁹ photons
This version is with 100% if the conversion is 75%, how many footnes are there
#_foton_real = # _foton 75/100
#real_photon = 15.27 10¹⁹ 0.75
# _real_photon = 11.45 10¹⁹ photons
this is the broadcast in a second
#_total = # _real_photon t
#_total = 11.45 10¹⁹ 3600
#_total = 4.1 10²³ photons / h
#_total = 4 10²³ photons / h
b) This number of photons is constant, so after being emitted they are distributed on the surface of a sphere, in this case of radius r = 1.0 m
the volume of a sphere is
A = 4π r²
A = 4π 1²
A = 12,566 m²
the area of the plate is
A₁ = l₁ l₂
A₁ = 0.10 0.10
A₁ = 1 10⁻² m
Let's use a direct proportion rule, if there are 4.1 10²³ photons in an area A, how much are there in an area A₁
# _photon_area = #_total A₁ / A
# _photon_area = \(4.1 \ 10^{23} \ \frac{1 \ 10^{-2} }{12.566}\)
# _photon_area = 3.26 10²²
as the number of photons must be a whole number
# _photon_area = 3 10²² photons
1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
Answers
2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.
state the law of conservation of energy
Answers
Answer:
energy can neither be created nor be destroyed. Although, it may be transformed from one form to another.
Explanation:
mark brainiest?
Answer:
According the law of conservation of energy , energy is not created or destroyed
two parallel wires carrying equal currents of 10A attract each other with a force of 1mN. If both currents are doubled, what will be the force of attraction?
Answers
Answer:
F (force) can be written F/L = K I1 I2 where K is some constant
F1 = 4 F1 if I1 and I2 are each doubled
If both currents are doubled, the new force of attraction between the wires will be 0.4 mN.
The force of attraction between two parallel wires carrying equal currents is given by Ampere's law, which states that the force is directly proportional to the product of the currents and inversely proportional to the square of the distance between the wires. Given that the current in each wire is 10A and the force of attraction is 1mN, we can use this information to calculate the distance between the wires.
Let's assume the distance between the wires is "d".
Using the formula for the force of attraction between the wires:
F = (μ₀ * I₁ * I₂) / (2πd)
where F is the force, μ₀ is the permeability of free space, I₁ and I₂ are the currents, and d is the distance between the wires.
Rearranging the formula, we can solve for d: d = (μ₀ * I₁ * I₂) / (2πF)
We know that F = 1mN, I₁ = I₂ = 10A, and μ₀ = 4π x 10^(-7) N/A².
Substituting these values into the formula, we can find the distance between the wires:
d = (4π x 10^(-7) N/A² * 10A * 10A) / (2π * 1mN)
Simplifying the expression, we find: d = (4 x 10^(-6) N/A² * 100 A²) / (2 x 10^(-3) N)
d = 200 x 10^(-6) m
d = 0.2 mm
Now, if both currents are doubled to 20A, we can calculate the new force of attraction between the wires using the same formula:
F' = (μ₀ * I₁' * I₂') / (2πd)
where F' is the new force, I₁' and I₂' are the new currents, and d is the distance between the wires.
Substituting the values, we get: F' = (4π x 10^(-7) N/A² * 20A * 20A) / (2π * 0.2mm)
Simplifying the expression, we find: F' = (4 x 10^(-6) N/A² * 400 A²) / (4 x 10^(-4) N)
F' = 400 x 10^(-6) N
F' = 0.4 mN
Therefore, the new force of attraction between the wires will be 0.4 mN, if both currents are doubled.
Learn more about Force of Attraction here:
https://brainly.com/question/3390243
#SPJ2
A mass of M-kg rests on a frictionless ramp inclined at 30°. A string with a linear mass density of μ=0.025" kg/m" is attached to the M-kg mass. The string passes over a frictionless pulley of negligible mass and is attached to a hanging mass (m). The system is in static equilibrium. A wave is induced on the string and travels up the ramp.
(a) Show that the mass of M is equal to twice the mass of the hanging mass: M = 2m.
(b) and at what wave speed does the wave travel up the string, if m = 5 kg?
Answers
Answer:
44.3 m/s
Explanation:
a) Draw a free body diagram of the mass M. There are three forces:
Weight force mg pulling down,
Normal force N pushing perpendicular to the ramp,
and tension force T pulling parallel up the ramp.
Sum of forces in the parallel direction:
∑F = ma
T − Mg sin 30° = 0
T = Mg sin 30°
T = Mg / 2
Draw a free body diagram of the hanging mass m. There are two forces:
Weight force mg pulling down,
and tension force T pulling up.
Sum of forces in the vertical direction:
∑F = ma
T − mg = 0
T = mg
Substitute:
mg = Mg / 2
m = M / 2
M = 2m
b) Velocity of a standing wave in a string is:
v = √(T / μ)
T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N. Therefore:
v = √(49 N / 0.025 kg/m)
v = 44.3 m/s
Can toe touches help you improve flexibility? Yes/No
Answers
Answer:
Yes. It helps so you can be able to do harder things like backflips and stuff like that. And to become more flexible.
Explanation:
what is a U.S state you can visit a desert in
Answers
A 4-lb collar can slide without friction along a horizontal rod and is in equilibrium at A when it is pushed 1 in. to the right and released from rest. The springs are undeformed when the collar is at A and the constant of each spring is 2800 lb/in. Determine the maximum velocity of the collar.
Answers
The maximum velocity of the collar is 0.335 m/s.
Maximum velocity of simple harmonic motion
The maximum velocity of a simple harmonic motion occurs when the object is in equilibrium position.
K.E = U
¹/₂mv² = ¹/₂kx²
mv² = kx²
where;
k is spring constant = 2800 lb/in = 316.36 N/mx is extension = 1 in = 0.0254 mm is mass = 4 lb = 1.81 kg\(v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{316.36 \times 0.0254^2}{1.81} }\\\\v = 0.335 \ m/s\)
Thus, the maximum velocity of the collar is 0.335 m/s.
Learn more about maximum velocity of SHM here: https://brainly.com/question/20595261
Describe the relationship between temperature and kinetic
energy.
Answers
Answer:
temperatures is directly proportional to kinetic energy
Explanation:
in increasing the temperature,kinetic energy also increases
hope it helps...
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
To learn more about acceleration
https://brainly.com/question/2303856
#SPJ8
The force F acting on a body varies with the displacement s from a point O as shown in the graph.
(a) Calculate the work done when the body is displaced
(i) from s=0 to s = 0.4 m
(ii) from s=0 to s =0.8 m
(b) If the mass of the body is 0.20 kg and its initial velocity is 2.00 m/s, find its velocity
(i) when s = 0.4 m
(ii) when s = 0.8 m
Answers
The work done when the body is displaced
(i) from s = 0 to s = 0.4 m is 0.8 J
(ii) from s = 0 to s = 0.8 m is 0.4 J
b. The velocity is
(i) when s = 0.4 m is 2.0 m/s
(ii) when s = 0.8 m is 2.0 m/s
What is the formula for work done?The formula for work done is given below as follows:
Work done = force * distance
Hence, the work done is the area under the force-displacement graph.
The work done when the body is displaced
(i) from s = 0 to s = 0.4 m is :
Work done = ¹/₂* 4 * 0.4
Work done = 0.8 J
(ii) from s = 0 to s = 0.8 m
Work done = ¹/₂* 4 * 0.4 + {¹/₂* (-2) * 0.4}
Work done = 0.4 J
b. The velocity is calculated as follows:
v = √(u² + 2as)
where;
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacementt
Also;
a = F/m
where;
F is force and m is mass
(i) when s = 0.4 m
a = 0/0.20
a = 0
v = √2.0²
v = 2.0 m/s
(ii) when s = 0.8 m
a = 0/0.20
a = 0
v = √2.0²
v = 2.0 m/s
Learn more about velocity and force at: https://brainly.com/question/30317885
#SPJ1
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
Know more about potential energy here:
https://brainly.com/question/21175118
#SPJ8
A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.
Answers
The motorcycle had covered a distance of 16 meters in half the total time.
a) To calculate the acceleration, we can use the formula:
a = (v - u) / t
where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.
Given:
u = 0 m/s (initial velocity)
v = ? (final velocity)
t = 4 s (time)
s = 64 m (distance)
Using the equation of motion:
s = ut + 1/2at^2
We can rearrange the equation to solve for acceleration:
a = 2s / t^2
a = 2(64) / (4)^2
a = 128 / 16
a = 8 m/s^2
Therefore, the acceleration of the motorcycle is 8 m/s^2.
b) To find the final velocity, we can use the formula:
v = u + at
v = 0 + (8)(4)
v = 32 m/s
Therefore, the final velocity of the motorcycle is 32 m/s.
c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:
s = ut + 1/2at^2
32 = 0 + 1/2(8)t^2
16 = 4t^2
t^2 = 4
t = 2 s
Therefore, the motorcycle had covered half the total distance at 2 seconds.
d) To calculate the distance covered in half the total time, we use the formula:
s = ut + 1/2at^2
s = 0 + 1/2(8)(2)^2
s = 0 + 1/2(8)(4)
s = 0 + 16
s = 16 m
for such more questions distance
https://brainly.com/question/26550516
#SPJ11
What is the diameter of a sphere with a volume of 78006 in 3 , 78006 in 3 , to the nearest tenth of an inch?.
Answers
Answer:
42.84 inches.
Explanation:
To find the diameter of a sphere with a volume of 78006 cubic inches, we can use the formula for the volume of a sphere, which is:
V = (4/3) * π * r^3
Where V is the volume of the sphere, π is the mathematical constant pi (approximately 3.14), and r is the sphere's radius.
First, we can rearrange the formula to solve for the radius:
r^3 = (3/4) * V / π
r = (3/4) * V / π^(1/3)
Substituting the given volume of 78006 cubic inches:
r = (3/4) * 78006 in^3 / π^(1/3)
r ≈ 21.42 inches (rounded to two decimal places)
Finally, we can find the diameter of the sphere by doubling the radius:
d = 2 * r
d ≈ 42.84 inches (rounded to two decimal places)
The diameter of a sphere with a volume of 78006 cubic inches is approximately 42.84 inches.
6. The work done in pushing a 40 kg chair from the kitchen table to 10 meters down the
hall would be about_
,neglecting friction.
A. 40J
B. 4000J
C. OJ
D. 0.25J
Answers
Answer:
B
Explanation:
W = f * d
= mg * d
= 40(9.81)(10) =~4000 J
5. Use the algebraic technique for adding vectors to find the total displacement of a person who walks the following three paths (displacements-on a flat field. First, she walks 25.0 m in a direction 49.00 north of east. Then she walks 23.0 m heading 15.00 north of east. Finally, she turns and walks 32.0 m in a direction 68.0° south of east.
Answers
Answer:
jjjjjjjjjjjjjjjj
Explanation:
I need help I’ve been stuck for over an hour
Answers
The interaction with the highest electrostatic potential energy is the +2 and -2 particle separated by a distance of 5 nm. This is because the electrostatic potential energy between two charged particles is directly proportional to the product of the charges and inversely proportional to the distance between them. In this case, the product of the charges (+2 and -2) is 4, which is higher than any other combination given in the options. Additionally, the distance between them (5 nm) is smaller than any other option, further increasing the electrostatic potential energy.
What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Answers
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
for more questions on heliocentric
https://brainly.com/question/21113123
#SPJ8
A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. The ball travels 50 meters down the field before another player stops the ball. How much work was done during the kick?
Answers
The total work done on the ball by the soccer player is 50,200 J.
Work done by applied forceThe work done by the applied force is the product of the applied of the applied force and the displacement of the object.
The work on the ballThe work done on the ball is calculated as follows;
W = Fd
W = 1000 x (0.2 + 50)
W = 50,200 J
Thus, the total work done on the ball by the soccer player is 50,200 J.
Learn more about work done here: https://brainly.com/question/8119756
HITLOW
SS
1/6
A5 kg body is having a Kinetic energy of 250 J. What is the velocity of the body?
15 m/s
20 m/s
40 m/s
10 m/s
ME
Answers
Answer:
10 m/s
Explanation:
KE = 1/2 • m • v^2
250 J = 1/2 • 5 kg • v^2
(2 • 250 J / 5 kg )^1/2 = v
(100)^1/2 = v
10 = v
What is a possible evelation for the surface of darry lin lake?
1)228 feet
2)242 feet
3)255 feet
4)268 feet
Answers
Answer:
2) 242. 100 percent sure.
Explanation:
255 feet
I just did it
When scientists look at very distant galaxies through powerful telescopes, they see the galaxies as they were millions or billions of year ago. Why is this?
Answers
Answer:
speed of light
Explanation:
the sun's light is 8 mins behind imaging that a billion fold
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
Learn more about earthquakes from the given link.
https://brainly.com/question/25843505
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
Answers
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
Learn more about wavelength here:https://brainly.com/question/10728818
#SPJ1
How much heat will change 10 g of ice at 0 ºC to water at 0 ºC?
Answers
How much heat will change 10 g of ice at 0 C to
water at 0 C?
Collect information about the most modern techniques adapted by Nagaland and Manipur to conserve water
Answers
Answer: Nagaland use an indigenous system of conservation of rain water known as the 'Zabo' or 'Ruza' system. In this system, rain water is collected and stored in catchments along mountain slopes for irrigation and other purposes. The system combines water conservation with forestry, agriculture and animal care.
Manipur: The rainwater can be collected from various hard surfaces such as rooftops and other hard surfaces above ground surfaces. Rains are the main sources of water in Manipur and if rainwater is harvested, the scarcity of water in the state can beeliminated or minimize the water stress in the state during the dormant season.
D 4.8
This is a harder question based on the Law of Conservation of Momentum. Take the time to work
your way through it. Start with a diagram.
A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150 kg piece moves off to the
east with a velocity of 150 m s². A 100 kg piece moves off with a velocity of 200 m s at a direction of
south 60° west. What is the velocity of the third piece?
It is possible
Answers
The velocity of the third piece is v₃ = -12500 kg·m/s / m₃
How do we calculate?The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.
velocity of the third piece = v₃.
The total initial momentum before the explosion = 0
The total final momentum after the explosion= 0
Initial momentum = 0 kg·m/s (since the bomb is at rest)
Final momentum = m₁v₁ + m₂v₂ + m₃v₃
m₁ = mass of the first piece = 150 kg
v₁ = velocity of the first piece = 150 m/s (to the east)
m₂ = mass of the second piece = 100 kg
v₂ = velocity of the second piece = 200 m/s (south 60° west)
m₃ = mass of the third piece = unknown
v₃ = velocity of the third piece = unknown
0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)
final momentum = 0 and hence v₃ is found as :
0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)
-12500 kg·m/s = (m₃)(v₃)
v₃ = -12500 kg·m/s / m₃
Learn more about law of conservation of momentum at:
https://brainly.com/question/1113396
#SPJ1
g A small ball is tied to one end of a light 2.5-m wire, and the other end of the wire is hooked to the ceiling. A person pulls the ball to the side until the wire makes an angle of 35° with the plane of the ceiling and then gently releases it. What is the angular speed of the ball, in rad/s, as it swings through its lowest point?
Answers
The angular speed of the ball as it swings through its lowest point is 1.8 rad/s.
The given parameters;
radius of the circular path, r = 2.5 m
angle with the vertical, θ = 35⁰
The angular speed of the ball, as it swings through its lowest point is calculated as follows;
\(Tcos \theta = m\omega ^2 r\\\\mgcos \theta = m \omega ^2 r\\\\gcos \theta = \omega ^2 r\\\\\omega ^2 = \frac{gcos \theta }{r} \\\\\omega = \sqrt{\frac{gcos \theta }{r} } \\\\\omega = \sqrt{\frac{9.8 \times cos (35) }{2.5} } \\\\\omega = 1.8 \ rad/s\)
Thus, the angular speed of the ball as it swings through its lowest point is 1.8 rad/s.
Learn more here:https://brainly.com/question/12898117
12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
Answers
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
For more questions on travelled
https://brainly.com/question/750474
#SPJ8
Naming covalent compounds
P4S5
Answers
Answer:
what the heck is sakurfa
Explanation: