How would you make a science essay funny

Answer:

D) Previous models

Got it right on USTestPrep

Answer:

previous models

Explanation:

I did it

Answer:

20 meters

Explanation:

The bike is moving at a rate of 4 meters per second. In 5 seconds, the bike would have gone 20 meters

4 m/s x 5s = 20 m

Answer:

20 miles

Explanation:

Answer:

The pointer pointing to the grey and white balls are either proton or nuetron i van't really tell cause their grey and white.

The whole clster of balls is the Nucleus

The black balls on the lines are electrons

And the lines are the energy level

Explanation:

Answer:

Explanation:

To calculate the pH and oxalate concentration of a 1.0 M solution of oxalic acid at 25°C, we need to use the dissociation constants (Ka) of oxalic acid. Oxalic acid is a diprotic acid, which means it can donate two protons in solution.

The dissociation constants for oxalic acid are:

Ka1 = 5.90 × 10^-2

Ka2 = 5.90 × 10^-5

To calculate the pH of a 1.0 M solution of oxalic acid, we need to first determine the concentration of hydrogen ions (H+) in solution. This can be done by considering the equilibrium reactions:

H2C2O4 ⇌ H+ + HC2O4-

HC2O4- ⇌ H+ + C2O42-

The equilibrium expressions for these reactions are:

Ka1 = [H+][HC2O4-]/[H2C2O4]

Ka2 = [H+][C2O42-]/[HC2O4-]

Since the concentration of oxalic acid is 1.0 M, the concentration of HC2O4- and C2O42- can be assumed to be negligible compared to the initial concentration of oxalic acid. Therefore, we can simplify the equilibrium expressions to:

Ka1 = [H+][HC2O4-]/1.0 M

Ka2 = [H+][C2O42-]/[HC2O4-]

Rearranging these equations and solving for [H+], we get:

[H+] = √(Ka1Ka2)/(1.0 M)

Plugging in the values for Ka1 and Ka2, we get:

[H+] = √(5.90 × 10^-2 × 5.90 × 10^-5)/(1.0 M) = 1.08 × 10^-3 M

Using the equation pH = -log[H+], we can calculate the pH of the solution:

pH = -log(1.08 × 10^-3) = 2.97

To calculate the concentration of oxalate ions (C2O42-) in solution, we can use the equilibrium expression for the second dissociation of oxalic acid:

Ka2 = [H+][C2O42-]/[HC2O4-]

We already know the concentration of hydrogen ions ([H+]) from the previous calculation, and we can assume that the concentration of HC2O4- is equal to the initial concentration of oxalic acid (1.0 M). Therefore, we can solve for [C2O42-]:

[C2O42-] = (Ka2 × [HC2O4-])/[H+]

Plugging in the values for Ka2, [HC2O4-], and [H+], we get:

[C2O42-] = (5.90 × 10^-5 × 1.0 M)/(1.08 × 10^-3 M) = 5.46 × 10^-3 M

Therefore, the concentration of oxalate ions in solution is 5.46 × 10^-3 M.

To calculate the concentrations of other species in the equilibrium, we can use the equilibrium expressions for each of the dissociation reactions and the conservation of mass balance:

[H2C2O4] = [H+] + [HC2O4-]

[HC2O4-] = [H2C2O4]/(1 + Ka1/[H+])

[C2O42-] = [HC2O4-] × Ka2/[H+]

Pl

Answer:

diffusion is the answer

Explanation:

The net force on particle 3 due to the presence of particle 1 and particle 2 on the same straight line is 50.5 N to the right.

The force between the two particles is determined from Coulomb's law as shown below;

F = kq₁q₂/r²

F(1,2) = -(9 x 10⁹ x 28.1 x 10⁻⁶ x 25.5 x 10⁻⁶) / (0.3)²

F(1,2) = - 71.66 N

F(2,3) = + (9 x 10⁹ x 25.5 x 10⁻⁶ x 47.9 x 10⁻⁶) / (0.3)²

F(2,3) = + 122.15 N

The net force on particle 3 is determined as follows;

F(net) = 122.15 N - 71.66 N

F(net) = + 50.5 N

Thus, the net force on particle 3 due to the presence of particle 1 and particle 2 on the same straight line is 50.5 N to the right.

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Answer:

The correct answer is B. Cs+ represents a cesium ion.

Answer:

Explanation:

we know that density=mass/volume

mass=240.90 g

volume=200.00 ml

now

density=240.90 g/200.00

density=1.2045 g/ml

another way

1 dm^3 =1000 ml

200.00 ml =200.00/1000

200.00 ml=0.2 dm^3

now density=240.90 g/0.2 dm^3

density=1204.5 g/dm^3

The percentage yield recovery formula is a way to calculate the efficiency of a chemical reaction. It is used to determine how much of the desired product is actually produced during a reaction, and it is expressed as a percentage. The formula is:

Percentage Yield Recovery = (Actual yield of product / Theoretical yield of product) x 100

The actual yield of product is the amount of product that is actually produced during the reaction, while the theoretical yield of product is the maximum amount of product that could be produced based on the amounts of reactants used in the reaction.

For example, let's say that a chemical reaction was performed with a theoretical yield of 100 grams of product, but only 80 grams of product were actually produced. To calculate the percentage yield recovery, you would use the following calculation:

(80 / 100) x 100 = 80%

This means that the reaction had an 80% recovery rate. This means that 80% of the product that could be made was made and the remaining 20% is lost.

It's important to note that the percentage yield recovery may be affected by various factors such as the purity of the reactants, the reaction conditions, and the presence of impurities. Therefore, it's important to take these factors into consideration when performing a chemical reaction and interpreting the results.

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The mole fraction of potassium permanganate (KMnO4) in the solution is 0.00806.

The mole fraction of potassium permanganate in the given solution can be determined using the formula for mole fraction which is:
Mole fraction = Number of moles of solute/ Total number of moles in the solution
To find the mole fraction, we first need to find the number of moles of potassium permanganate (KMnO4) in the solution.
We can use the formula for calculating the number of moles as shown
Number of moles of solute = mass of solute/molar mass of solute
The molar mass of potassium permanganate (KMnO4) is calculated as follows
Molar mass of KMnO4 = (1 x Atomic mass of K) + (1 x Atomic mass of Mn) + (4 x Atomic mass of O)= (1 x 39.1 g/mol) + (1 x 54.9 g/mol) + (4 x 16.0 g/mol)= 39.1 + 54.9 + 64.0= 158.0 g/mol

Now, we can calculate the number of moles of potassium permanganate in the solution as follows
Number of moles of KMnO4 = Mass of KMnO4 / Molar mass of KMnO4
Mass of KMnO4 = 7.1 g
Molar mass of KMnO4 = 158.0 g/mol
Number of moles of KMnO4 = 7.1 g / 158.0 g/mol= 0.04493 mol
Next, we need to find the total number of moles in the solution.
The total number of moles is the sum of the number of moles of potassium permanganate (KMnO4) and the number of moles of water (H2O).
Number of moles of water (H2O) = mass of water / molar mass of water
The mass of water is 100.0 g, and the molar mass of water is 18.0 g/mol.
Number of moles of water = 100.0 g / 18.0 g/mol= 5.5556 mol
Now, we can find the mole fraction of potassium permanganate (KMnO4) as follows:
Mole fraction of KMnO4 = Number of moles of KMnO4 / Total number of moles in the solution= 0.04493 mol / (0.04493 mol + 5.5556 mol)= 0.00806 (rounded to five decimal places)Therefore, the mole fraction of potassium permanganate (KMnO4) in the given solution is 0.00806.

Thus, the mole fraction of potassium permanganate (KMnO4) in the solution is 0.00806 .

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The skeletal rearrangement of the forma- tion of epoxide 2 from bromohydrin 1.

Skeletal rearrangement reactions, which contain a exchange of connectivity of the substrate thru cleavage of carbon-carbon, carbon-heteroatom, and heteroatom-heteroatom bonds, have attracted plenty interest as a synthetic method of highly substituted organic.

Intermediate is a 3-membered ring (halonium ion). Halohydrin formation (specifically chlorohydrin and bromohydrin formation) is the end result of the addition of a halogen (Cl or Br--less substituted side) and a hydroxyl institution (greater substituted aspect) across an alkene.

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Answer:

0.35moles

Explanation:

when 156g of Al reacts with 2molesof Al2O3 then 27g of Al reacts with what then u cross multiply and solve ur answer

0.35moles of  Al\(_2\)O\(_3\)  will be formed when 27 grams of Al reacts completely with O\(_2\). A mole consists of precisely 6.022× 10²³particles.

A mole is just a measuring scale. In reality, it's one of the International System of Units' seven foundation units (SI). When already-existing units are insufficient, new ones are created. The levels at which chemical reactions frequently occur exclude the use of grams, yet utilizing actual numbers of atoms, molecules, or ions would also be unclear.

A mole consists of precisely 6.022× 10²³particles. The "particles" might be anything, from tiny things like electrons and atoms to enormous things like stars or elephants.

4 Al + 3 O\(_2\) → 2 Al\(_2\)O\(_3\)

moles of aluminium = 27 /26=1.03moles

The mole ratio between Al and  Al\(_2\)O\(_3\) is 2:1

mole of  Al\(_2\)O\(_3\)= 0.35moles

Therefore, 0.35moles of  Al\(_2\)O\(_3\)  will be formed when 27 grams of Al reacts completely with O\(_2\).

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Answer:

No definite shape

Explanation:

All of the examples listed could be considered to exhibit well-designed structures supporting well-designed functions, but the level at which they are designed may differ.

A squirrel's teeth and jaws are well-designed structures that allow them to strip open sunflower seeds, which is a well-designed function for obtaining food. Similarly, an otter's use of a pebble as a tool to break into a mussel shell is also an example of well-designed structures supporting well-designed functions.

A molecule of the correct dimensions storing information is an example of a well-designed structure at the molecular level that supports the well-designed function of storing genetic information. Likewise, enzymes are also well-designed structures that catalyze specific chemical reactions, and the breaking of a specific covalent bond to generate a specific molecular product is an example of a well-designed function.

Therefore, the correct answer is: all of the above.

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The question is: Give the systematic name of \(SiF_{2}\).

Answer: The systematic name of \(SiF_{2}\) is silicon difluoride.

Explanation:

The given compound has chemical formula \(SiF_{2}\). It shows that there is one atom of silicon and two atoms of fluorine are present.

So, the number "two" will be represented by the prefix "di" while naming this compound.

Hence, systematic name of this compound is silicon difluoride.

Thus, we can conclude that systematic name of \(SiF_{2}\) is silicon difluoride.

Answer:

Explanation:

The reasons that cities boomed during the Middle Ages are more employment opportunities, increased trade, and growing interest in culture and art.

Answer:

Explanation:

By the High Middle Ages, towns were growing again. One reason for their growth was improvements in agriculture. Farmers were clearing forests and adopting better farming methods. As a result, they had a surplus of crops to sell in town markets.

Also, as the amount of trade increased between Europe and other continents. Trade began to grow in Europe after the Crusades. Most of this trade was controlled by merchants from Italy and Northern Europe.

The solubility of AgBrO3 in water at 25°C is approximately 0.0073 M.

At 25°C, the solubility of AgBrO3 in water can be calculated using its Ksp value, which is 5.38 x 10^-5. The Ksp expression for AgBrO3 is AgBrO3(s) ⇌ Ag+(aq) + BrO3-(aq), which gives the equilibrium constant expression Ksp = [Ag+][BrO3-]. Since AgBrO3 is a sparingly soluble salt, its solubility is expected to be low. Therefore, let's assume that x moles of AgBrO3 dissolve in water to produce x moles of Ag+ and x moles of BrO3-. Substituting these values in the Ksp expression gives Ksp = x^2. Solving for x gives the solubility of AgBrO3, which is the square root of Ksp.

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Answer:

Ⓓ The process follows the law of conservation of mass and energy is found in the product

Explanation:

This question depicts PHOTOSYNTHESIS, which is the process employed by green plants to manufacture their food in form of sugars (glucose). The general equation, which was given in the question is as follows:

6CO2 + 6H2O + energy → C6H12O6 + 6O2

This chemical reaction follows the LAW OF CONSERVATION OF MASS, which states that the amount of matter in reactant must equate that of the product. In this case, each element contains the same number of atoms in both reactant side and product side.

Also, energy is contained in the product but stored in the chemical bonds of the glucose molecule formed.

The Bronsted-Lowry acids are OH- and H2O, while the Bronsted-Lowry bases are NH3 and NH2-.

The Bronsted-Lowry definition of an acid is a substance that donates a proton, while a Bronsted-Lowry base is a substance that accepts a proton. The reaction below represents the reaction between ammonia and hydroxide ions: NH3(aq) + OH-(aq) ⇌ NH2-(aq) + H2O(l)In the forward reaction, ammonia (NH3) is acting as a Bronsted-Lowry base since it is accepting a proton from the hydroxide ion (OH-).

On the other hand, the hydroxide ion (OH-) is acting as a Bronsted-Lowry acid since it is donating a proton to ammonia. In the reverse reaction, the NH2- ion is acting as a Bronsted-Lowry base by accepting a proton from the H2O molecule. At the same time, the H2O molecule is acting as a Bronsted-Lowry acid since it is donating a proton to the NH2- ion. Therefore, the Bronsted-Lowry acids in the reaction are OH- and H2O, while the Bronsted-Lowry bases are NH3 and NH2-.

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Answer: -8 would be his yield answer

Explanation:

The partial pressure of H2(g) that would be required for the reaction to be in equilibrium is 1.3x10^16 atm.

a) To determine the molar Gibbs energy of the reaction, we first need to calculate the standard Gibbs energy of the reaction (ΔG°) using the standard Gibbs energy of formation of butyrate (ΔGf°):

ΔG° = ΔGf°(products) - ΔGf°(reactants)
ΔG° = (2 x ΔGf°(C2H3O2-) + 2 x ΔGf°(H2) + ΔGf°(H+)) - (ΔGf°(C4H7O2-) + 2 x ΔGf°(H2O))
ΔG° = (2 x -485.8 kJ/mol + 2 x 0 kJ/mol + 0 kJ/mol) - (-352.6 kJ/mol + 2 x -237.1 kJ/mol)
ΔG° = -619.0 kJ/mol

Next, we use the equation for the Gibbs energy of a reaction at non-standard conditions (ΔG):

ΔG = ΔG° + RT ln(Q)

Where R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (298 K), and Q is the reaction quotient:

Q = ([C2H3O2-]^2 [H2]^2 [H+]) / ([C4H7O2-] [H2O]^2)
Q = (0.01^2 x 5x10^-6^2 x 10^-7) / (0.01 x 1^2)
Q = 2.5x10^-18

Plugging in the values for ΔG°, R, T, and Q into the equation for ΔG:

ΔG = -619000 J/mol + (8.314 J/mol·K)(298 K) ln(2.5x10^-18)
ΔG = -619000 J/mol + (-95.3 J/mol)
ΔG = -619095.3 J/mol

Therefore, the molar Gibbs energy of the reaction is -619095.3 J/mol or -619.1 kJ/mol.

b) To calculate the partial pressure of H2(g) that would be required for the reaction to be in equilibrium, we need to use the equation for the Gibbs energy of a reaction at equilibrium (ΔG = 0):

0 = ΔG° + RT ln(Q)

Rearranging the equation to solve for Q:

Q = e^(-ΔG°/RT)

Plugging in the values for ΔG°, R, and T:

Q = e^(-(-619000 J/mol)/(8.314 J/mol·K)(298 K))
Q = 1.8x10^32

Since Q is the reaction quotient:

Q = ([C2H3O2-]^2 [H2]^2 [H+]) / ([C4H7O2-] [H2O]^2)

We can rearrange the equation to solve for the partial pressure of H2(g):

[H2]^2 = (Q [C4H7O2-] [H2O]^2) / ([C2H3O2-]^2 [H+])
[H2] = sqrt((Q [C4H7O2-] [H2O]^2) / ([C2H3O2-]^2 [H+]))

Plugging in the values for Q, [C4H7O2-], [H2O], [C2H3O2-], and [H+]:

[H2] = sqrt((1.8x10^32 x 0.01 x 1^2) / (0.01^2 x 10^-7))
[H2] = 1.3x10^16
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Answer:

d) 1.8 atm

Explanation:

According to Boyle's Law,

Here, we are given :

Solving

Answer:

A

Explanation:

at thermal equilibrium, temperature of 2 substances remain constant during heat transfer.

Answer:

I think it's trees

Explanation:

I'm not 100% sure tho

Answer:

its ability to lose electron

The reactivity of an alkali metal is determined by its ability to loose electrons.

The alkali metals are highly electropositive. They easily loose electron to form a univalent positive ion.

This ability to form a univalent positive ion increases down the group hence cesium is the most electropositive element in nature.

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Answer:

3.0059572661984113e-24

Explanation: