please help quick i will give brainlist!!!!!!

The given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants.

Mutually exclusive and exhaustive variables: A variable is mutually exclusive and exhaustive if it includes all possible outcomes and each outcome can only be assigned to one variable category.a. Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday - Mutually exclusive and exhaustiveb. Days: Weekday and Weekend - Mutually exclusive and exhaustive c. Letters: Vowels and Consonants - Mutually exclusive and exhaustive. Letters: Alphabets and Consonants - Not mutually exclusive and exhaustiveThe given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants. Hence, the options a and c are correct.

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We can conclude that -

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Given is that the regular price on a pair of jeans is $54. The store advertises a back-to-school sale at 40% off the regular price of the jeans. Two weeks later, the store advertises a sale at an additional off the sale price of these jeans at 5%.

Original price -

$54

Cost after 40% discount -

54 - {40% of 54}

54 - {40/100 x 54}

54 - {2/5 x 54}

54 - 21.6

$32.4

Cost after 5% discount -

32.4 - {5% of 32.4}

32.4 - {5/100 x 32.4}

32.4 - 1.62

$30.78

{ 3 } -

Calculating 60% of new price -

60% of 30.78

(60/100) x 30.78

18.5

Calculating 40% of new price -

40% of 30.78

(40/100) x 30.78

12.4

So, 60% of new price is greater than calculating 40%.

So, Manny is correct.

Therefore, we can conclude that -

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Answer:

x=70 y=110 z=30

Step-by-step explanation:

Answer:

second one

Step-by-step explanation:

The measures of position among the options provided are the quartiles, deciles, and median.

The standard deviation is not a measure of position but rather a measure of dispersion.

Measures of position are statistical indicators that provide information about the relative location or position of data points within a dataset. Among the options provided, the measures of position are:

a. The quartiles:

Quartiles divide a dataset into four equal parts.

The first quartile (Q1) represents the 25th percentile, the second quartile (Q2) corresponds to the median or 50th percentile, and the third quartile (Q3) represents the 75th percentile.

They help understand the spread and distribution of the data.

b. The deciles:

Deciles divide a dataset into ten equal parts.

Each decile represents a specific percentile, such as the first decile (D1) representing the 10th percentile, the second decile (D2) representing the 20th percentile, and so on.

Deciles provide more granularity in analyzing the position of data points within the dataset.

c. The median:

The median is the middle value of a dataset when arranged in ascending or descending order.

It divides the dataset into two equal halves, with 50% of the data falling below the median and 50% above.

The median provides a measure of central tendency and position within the dataset.

d. The standard deviation:

The standard deviation is not a measure of position.

It quantifies the dispersion or variability of data points from the mean.

It provides information about the spread of the data but does not indicate the specific position of data points within the dataset.

In summary, the measures of position among the options provided are the quartiles, deciles, and median.

The standard deviation is not a measure of position but rather a measure of dispersion.

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The required length of the road is given as 87.5 meters.

Given that,

A map of a city uses a scale of 1cm =3.5 meters. A road shown on the maps runs for 25cm how long is the road is to be determined.

We know that,

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,

1 cm = 3.5 meters,

For a road of 25 cm on the map,

Length of the road = 25 × 3.5

Length of the road = 87.5 meters

Thus, the required length of the road is given as 87.5 meters.

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Answer:

Hi,

You haven't included the data chart or what you need to solve.

Then only I will be able to help you!

Step-by-step explanation:

Answer:

Ahmed shoevked more than sheldon

a) The magnitude of an earthquake that has an intensity that is 39.25 is 5.6 unit.

b) The magnitude of earthquake that has intensity of 4.4 is 4.64 units.

Magnitude:

Magnitude is a measure of the amount of energy released in an earthquake. It is often described using the Richter scale. To calculate the magnitude, measure the amplitude of the waves on the seismometer and correct for the distance between the recorder and the epicenter of the earthquake.

The magnitude of an Earthquake can be calculated by the following formula -

M = log ( I / S )

Where ,

M = magnitude

I = Intensity

S = standard earthquake intensity i.e. 10 ⁻⁴

Hence ,

To calculate the magnitude of the earthquake of intensity = 32.75 ,

The above formula is used as -

M = log ( I / S )

M = log ( 39.25/  10 ⁻⁴ )

M = log ( 39.25 × 10⁴ )

M = log ( 3925000 )

M = 5.59 ≈5.6

Hence , the value of magnitude is 5.6.

b) To calculate the magnitude of the earthquake of intensity = 32.75 ,

The above formula is used as -

M = log ( I / S )

M = log ( 4.4/  10 ⁻⁴ )

M = log ( 4.4 × 10⁴ )

M = log ( 44000 )

M = 4.64

Hence , the value of magnitude is 4.64.

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Answer:

No, Yes, No, Yes

Step-by-step explanation:

1. 24

Answer:

m<TQS=23

Step-by-step explanation:

(3x-5)+(x+1)

4x-4=180

   +      +

4x=184

---    ----

4       4

x= 46

46/2

=23

If a ray QT bisects <RQS, then \(m<TQS=23.5\) °

Given :

a ray QT bisects <RQS

<PQR and <RQS is a linear pair . It makes and angle 180 degree

\(m<PQR+m<RQS=180\)

From the diagram,

m<PQR=3x-5, and m<RQS=x+1

Substitute the expression and solve for x

\(m<PQR+m<RQS=180\\3x-5+x+1=180\\4x-4=180\\4x=180+4\\4x=184\\Divide \; by \; 4\\x=46\)

now ,  \(m<RQS = x+1 =46+1=47\)

Given  QT bisects <RQS. it means QT divides RQS equally

\(m<TQS= \frac{m<RQS}{2} \\m<TQS= \frac{47}{2} \\\\m<TQS=23.5\)

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Answer:

x = -1

y = -8

Step-by-step explanation:

2x+3y= −26

5x+3y= −29

Time the first equation by -1

-2x - 3y = 26

5x + 3y = -29

3x = -3

x = -1

Now put -1 in for x and solve for y

2(-1) + 3y = - 26

-2 + 3y = -26

3y = -24

y = -8

Let's check

2(-1) + 3(-8) = -26

-2 - 24 = -26

-26 = -26

So, x = -1 and y = -8 is the correct answer.

\(2x + 3y = - 26 \\ \implies \: 2x + 3y + 26 = 0\)

\(5x + 3y = - 29 \\ \implies \: 5x + 3y + 29 = 0\)

For finding what sort of solution the pair of equations give , we need to check the type of equality between

\( \frac{ a_{1}}{ a_{2} \: } , \: \frac{ b_{1} }{ b_{2} } , \: \frac{ c_{1}}{ c_{2} } \\ \)

The following results can be obtained ,

\(if \: \: \frac{ a_{1} }{a _{2} } \neq \: \frac{ b_{1}}{ b_{2}} \\ \\ \implies \: we \: obtain \: a \: unique \: solution\)

\(if \: \: \frac{ a_{1} }{a _{2} } = \: \frac{ b_{1}}{ b_{2}} \: \neq \: \frac{ c_{1}}{ c_{2}} \\ \\ \implies \:we \: obtain \: no \: solution\)

\(if \: \: \frac{ a_{1} }{a _{2} } = \: \frac{ b_{1}}{ b_{2}} \: = \: \frac{ c_{1}}{ c_{2}} \\ \\ \implies \:we \: obtain \: infinitely \: many \: \: solutions\)

Considering the equations provided ,

\( a_{1} = 2 \: \: , \: \: b_{1} = 3 \: \: , \: \: c_{1} = 26 \\ a_{2} = 5 \: \: , \: \: b_{2} = 3 \: \: , \: \: c_{2} = 29\)

\(\therefore \frac{ a_{1}}{ a_{2} } = \frac{2}{5} \: \: \: , \: \: \: \frac{ b_{1}}{ b_{2} } = \frac{3}{3} = \frac{1}{1} \: \: \: , \: \: \: \frac{ c_{1} }{ c_{2} } = \frac{26}{29} \\ \)

Since ,

\( \frac{ a_{1} }{ a_{2}} \neq \: \frac{ b_{1} }{ b_{2}} \\ \)

The system of equations has a unique solution .

On further calculations done by elimination method , the solution of the equations comes out to be

\(\boxed{x = - 1} \\ \boxed{y = - 8}\)

let's have a look at how it'll be done now.

the equations given in the question are -

\(2x + 3y + 26 = 0 \: ...(1) \\ 5x + 3y + 29 = 0...(2) \\ \\ multiplying \: equation \: (1) \: by \: - 1 \\ \implies \: - 2x - 3 - 26 = 0...(3) \\ \\ solving \: eqs. \: (2) \: and \: (3) \\ \\ 5x + \cancel{3y} + 29 = 0 \\ \underline{ - 2x \cancel{- 3y} - 26 = 0} \\ 3x + 3 = 0 \\ \\ \implies \: 3x = - 3 \\ \implies \: \boxed{x = - 1} \)

substiting the value of x in equation 1

\(2( - 1) + 3y + 26 = 0 \\ 3y + 26 - 2 = 0 \\ 3y + 24 = 0 \\ 3y = - 24 \\ \implies \: \boxed{y = - 8}\)

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Answer:

4 / 21 spoonful of vanilla

Step-by-step explanation:

3 1/2 dozens = 42 cookies

Let x = spoonful of vanilla for 1 dozen of cookies

2/3 : 42 cookies

x : 12 cookies

2/3 ÷ 42 = x ÷ 12

2/3 × 1/42 = x / 12

2 / 126 = x / 12

Cross product

2*12 = 126*x

24 = 126x

Divide both sides by 126

x = 24 / 126

= 4 / 21

x = 4 / 21 spoonful of vanilla

Per dozen of cookies requires 4/21 spoonful of vanilla

Check:

4/21 per dozen × 3 1/2 dozens

4/21 × 7/2

28 / 42

2/3 spoonful for 3 1/2 dozens

The total amount of dozen cookies = \(3\dfrac{1}{2}\)

Stephanie requires \(\dfrac{2}{3} \ tablespoons\) to make \(\mathsf{3\dfrac{1}{2}\ dozen \ cookies}\)

Let assume that:

Then; we can equate both equations together as follows:

\(\dfrac{2}{3} \ tablespoons\) =  \(\mathsf{3\dfrac{1}{2}\ dozen \ cookies}\)

x tablespoon = 1 dozen cookies

By cross multiply and making (x) the subject of the formula, we have:

\(\mathbf{x \times 3\dfrac{1}{2} dozen \ cookies = \dfrac{2}{3} \ tablespoons \times 1 \ dozen \ cookies}\)

\(\mathbf{x =\dfrac{ \dfrac{2}{3} \ tablespoons \times 1 \ dozen \ cookies}{3\dfrac{1}{2} dozen \ cookies}}\)

\(\mathbf{x =\dfrac{ \dfrac{2}{3} \ tablespoons}{3\dfrac{1}{2} }}\)

\(\mathbf{x =\dfrac{ \dfrac{2}{3} \ tablespoons}{\dfrac{7}{2} }}\)

\(\mathbf{x = \dfrac{2}{3} \ tablespoons} \div {\dfrac{7}{2} }\)

\(\mathbf{x = \dfrac{2}{3} \ tablespoons} \times {\dfrac{2}{7} }\)

\(\mathbf{x = \dfrac{4}{21} \ tablespoons}}\)

Therefore, the amount of tablespoons Stephaine will need to prepare a dozen cookies is: \(\mathbf{ = \dfrac{4}{21} \ tablespoons}}\)

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Step-by-step explanation:

\(( \frac{2 \frac{3}{3} }{4} - \frac{3}{10} ) \times \frac{3}{17} \\ = ( \frac{ \frac{9}{3} }{4} - \frac{3}{10}) \times \frac{3}{17} \\ = ( \frac{9}{3 \times 4} - \frac{3}{10}) \times \frac{3}{17} \\ = ( \frac{9}{12} - \frac{3}{10} ) \times \frac{3}{17} \\ = ( \frac{9 \times 5}{12 \times 5} - \frac{3 \times 6}{10 \times 6} ) \times \frac{3}{17} \\ = ( \frac{45 - 18}{60} ) \times \frac{3}{17} \\ = \frac{27}{60} \times \frac{3}{17} \\ = \frac{81}{1020} \\ = \frac{27}{340} \)

\(\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘\)

Answer:

The answer to your question is going to be c

Answer:

10

Step-by-step explanation:

Answer:

the value of the number is 10.

Explanation:

Let the number be x,

given 28 subtracted from the product ( 5 * x ) and equals to 22

solve:

5x - 28 = 22

5x = 22 + 28

5x = 50

x = 10

Answer:

2 in the hundredths place is greater

Step-by-step explanation:

2 in the hundredths place is 10 times the thousands place

Answer:

i have the same quetion i really need help

Step-by-step explanation:

Answer:

Choose a marble from a group of 3 red marbles and 1 blue marble. Replace the marble and repeat.

Answer:

78kg

Step-by-step explanation:

76×5= 380kg

380-72-74-75-81= 78kg

Answer:

13.4%

Step-by-step explanation:

(52-45)/52

7/52

13.4%

Answer: 13%

Step-by-step explanation: 52 - 45 = 7 | 7/52 = .13 | 13%

From the polar coordinates, the integrate value of f(x,y), f( x,y) = 2xy ; x,y ≥ 0, x² + y² = 25 over D using polar coordinates is equals to the \( \frac{625}{4}\). The sketch of D is in attached figure.

The equation of a circumference in rectangular coordinates and origin as centre is x² +y² =R² , where R is the radius of the circumference. In polar coordinates, x² + y² = ρ, ρ is the polar radius. We have function f( x,y) = 2xy ; x,y ≥ 0, x² + y² = 25. It is an equation of a circle with radius 5 centered at the origin, however, since x and y must both be greater than or equal to 0, the region D is restricted to the portion of the circle in the first quadrant. So, the sketch of D is present in attached figure.

Now, we convert the cylindrical coordinates, r will span from 0 to 5 and θ will span from 0 to π/2. The integrand, f(x,y) = 2xy then f(r, θ) = 2(r sin(θ))(r cos(θ)) = 2r²sin(θ)cos(θ) = r²sin(2θ) and the double integral is \(\int_{0}^{\frac{π}{2}}\int_{0}^{5} r³sin(2θ)drdθ\)

\(= \int_{0}^{\frac{π}{2}}[\frac{ r⁴}{4}sin(2θ)]_{0}^{5}dθ\)

\(= \int_{0}^{\frac{π}{2}}[\frac{5⁴}{4}sin(2θ)]dθ\)

\(= \frac{5⁴}{4}[\frac{ -cos(2θ)}{2}]_{0}^{\frac{π}{2}}\)

\(= -\frac{5⁴}{8}[ cos(π) - cos(0°)]\)

\(= - \frac{5⁴}{8}[ -1 - 1 ]\)

\(= \frac{625}{4}\)

Hence, required value is \( \frac{625}{4}\).

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Step-by-step explanation:

Maybe you should flip flop

Answer: The mean will increase and the median would not change

Step-by-step explanation:

Recorded data by Priya :

Data: 1,8,6,2,4

Mean of data = (1+8+6+2+4)/5

=21/5 = 4.2

Median of data = 1,2,4,6,8

Median = 4

Correct data: 1,18,6,2,4

Mean of data = (1+18+6+2+4)/5

=31/5 = 6.2

Median of data = 1,2,4,6,18

Median = 4

Therefore ; according to the evaluation above, the median will remain unchanged, but the mean increased from 4.20 to 6.20.

Answer:

16

Step-by-step explanation:

adding any two sides of a triangle is allways greater than the third side.

Given the above condition, the result may translate to "Sample size and effect size."

What is Effect Size in Research?

Increasing the sample size always increases the likelihood of finding a statistically significant impact, regardless of how tiny the effect is in the actual world. In contrast, effect sizes are not affected by sample size. To compute effect sizes, just the data is utilized.

In contrast to significance tests, the effect size is not affected by sample size. Statistical significance, on the other hand, is determined by both the sample size and the effect size.

The greater the impact size, the greater the difference between the typical person in each group. A d of 0.2 or less is regarded a minor impact size, a d of roughly 0.5 is considered a medium effect size, and a d of 0.8 or above is considered a high effect size.

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The incorrect option is the value of the critical ratio which is given as 0.6.**

The critical ratio is the ratio of the expected cost of underage to the expected cost of overage. In this case, the expected cost of underage is $15 million and the expected cost of overage is $10 million, so the critical ratio is 1.5.

The critical ratio is the ratio of the expected cost of underage to the expected cost of overage. In this case, the expected cost of underage is $15 million and the expected cost of overage is $10 million, so the critical ratio is 1.5.

This means that Aventis is willing to accept a 5% chance of a stock-out (i.e., not having enough vaccines to meet demand) in order to avoid a 15% increase in the cost of manufacturing vaccines.

A critical ratio of 0.6 would mean that Aventis is willing to accept a 60% chance of a stock-out in order to avoid a 15% increase in the cost of manufacturing vaccines. This is a much higher risk than Aventis is likely to be willing to accept.

Hence, the incorrect option is critical ratio is 0.6

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28+19x=-8+15x​

Move the variable terms ( the one with "x" ) to the left side of the equation.

19x-15x = -8-28

4 x = -36

Divide both sides by 4:

4x/4 = -36/4

x= -9

Answer:

3: 14

4: 2/25

Step-by-step explanation:

Answer:

Step-by-step explanation:

Since it's a right angled triangle we can use trigonometric ratios to find the value of x

To find the value of x we can use either sine or cosine

\( \sin(30) = \frac{5}{x} \\ x \sin(30) = 5 \\ x = \frac{5}{ \sin(30) } \\ x = \frac{5}{0.5} \\ \\ \\ \boxed{x = 10}\)

\( \cos(60) = \frac{5}{x} \\ x \cos(60) = 5 \\ x = \frac{5}{ \cos(60) } \\ x = \frac{5}{0.5} \\ \\ \\ \boxed{x = 10}\)

Hope this helps you