Plis answer me this question is do tomorrow

Answer:

w > 3

Step-by-step explanation:

5w - 4 > 11

5w  > 15

w > 3

I think the answer is w= 6 or more

Step-by-step explanation:

I think it's this bc if u do 5 times 6 equals 30 then minus 4 is 26. 26 or more is greater than 11

Answer:

This should explain it

Step-by-step explanation:

If its the graph question I think it is this is the answer screenshot.

If Dominic bought 4 pencils and 3 highlighters for $9.80. it will cost Micha $5.50 to buy 2 pencils and 2 highlighters.

Set up two equations based on the purchases made by Dominic and Zoe:

Equation 1: 4p + 3h = 9.80

Equation 2: 3p + 5h = 10.65

Multiplying Equation 1 by 3 and Equation 2 by 4

Equation 3: 12p + 9h = 29.40

Equation 4: 12p + 20h = 42.60

Subtracting Equation 3 from Equation 4

(12p + 20h) - (12p + 9h) = 42.60 - 29.40

11h = 13.20

h = 13.20 / 11

h = 1.20

Substituting the value of h back into Equation 1

4p + 3(1.20) = 9.80

4p + 3.60 = 9.80

4p = 9.80 - 3.60

4p = 6.20

p = 6.20 / 4

p = 1.55

So,

Cost:

Cost = (2 * p) + (2 * h)

= (2 * $1.55) + (2 * $1.20)

= $3.10 + $2.40

= $5.50

Therefore it will cost Micha $5.50 to buy 2 pencils and 2 highlighters.

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Answer:

3+32+60+16= 111 sides.

Step-by-step explanation:

Make sure to multiply each number of a singular shape by its number of sides then add them all together at the end :)

Answer:

slope:35/70

y=0.5x +0

Step-by-step explanation:

Answer:

(x^2 + 4)(x - 3).

Step-by-step explanation:

I'm guessing you want to factor this.

You can do it by grouping:

x^3 - 3x^2 + 4x - 12

= x^2(x - 3) + 4(x - 3)

= (x^2 + 4)(x - 3).

To find the depth that will provide a maximum cross-sectional area for the rain gutter and allow the most water to flow, we can use optimization techniques.

Let's assume the depth of the rain gutter is represented by 'x' inches. The width of the gutter is fixed at 10 inches, and by turning up the edges 90 degrees, the cross-sectional shape becomes a rectangle with dimensions x by 10 - 2x.

The area of the cross-section, A, is given by A = x(10 - 2x) = 10x - 2x^2.

To find the maximum cross-sectional area, we need to maximize the function A(x). We can achieve this by finding the critical points of the function, which occur when the derivative of A with respect to x is equal to zero.

Taking the derivative of A(x) with respect to x, we get dA/dx = 10 - 4x.

Setting dA/dx = 0, we find the critical point: 10 - 4x = 0, which gives x = 2.5.

To determine if this critical point corresponds to a maximum, we can check the second derivative of A. Taking the second derivative, we have d^2A/dx^2 = -4.

Since the second derivative is negative, the critical point x = 2.5 corresponds to a maximum.

Therefore, the depth of 2.5 inches will provide a maximum cross-sectional area and allow the most water to flow through the rain gutter.

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To find the depth that will provide a maximum cross-sectional area for the rain gutter and allow the most water to flow, we can use optimization techniques.

Let's assume the depth of the rain gutter is represented by 'x' inches. The width of the gutter is fixed at 10 inches, and by turning up the edges 90 degrees, the cross-sectional shape becomes a rectangle with dimensions x by 10 - 2x.

The area of the cross-section, A, is given by A = x(10 - 2x) = 10x - 2x^2.

To find the maximum cross-sectional area, we need to maximize the function A(x). We can achieve this by finding the critical points of the function, which occur when the derivative of A with respect to x is equal to zero.

Taking the derivative of A(x) with respect to x, we get dA/dx = 10 - 4x.

Setting dA/dx = 0, we find the critical point: 10 - 4x = 0, which gives x = 2.5.

To determine if this critical point corresponds to a maximum, we can check the second derivative of A. Taking the second derivative, we have d^2A/dx^2 = -4.

Since the second derivative is negative, the critical point x = 2.5 corresponds to a maximum.

Therefore, the depth of 2.5 inches will provide a maximum cross-sectional area and allow the most water to flow through the rain gutter.

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Answer:

The answer would be A.

Step-by-step explanation:

You would take 9 x 10^5 = 900000 and divide that by 16 to get 56250.

After that, you move the decimal over by 4 to make it a number with only one number above zero in front of the decimal to make 5.625 (negate the 0 bc it does not mean anything after you moved the decimal over)

Since you moved it over by four places, the exponent next to the 10 will be 4, making the final answer 5.625 x 10^4

Good luck and hope this helps!!

To determine the number of ways you can achieve a 5-card hand without repeats from a deck of 52 cards, we can use the formula for combinations:

C(52, 5) = 52! / (5! * (52-5)!) = 2,598,960

This means that there are 2,598,960 ways to draw a 5-card hand without repeats from a standard deck of 52 cards.

In order to find the number of ways you can achieve a specific 5-card hand from a standard deck of 52 cards, you'll need to use combinations in discrete math. Combinations are used to calculate the number of ways to choose a certain number of items from a larger set, without considering the order of the items.

In this case, you want to choose 5 cards from a deck of 52 cards. Using the combination formula, you can determine the number of ways to do this:

C(n, k) = n! / (k!(n-k)!)

Where n is the total number of items (52 cards), k is the number of items you want to choose (5 cards), and ! represents the factorial function (e.g., 5! = 5 x 4 x 3 x 2 x 1).

Using the formula for your situation:

C(52, 5) = 52! / (5!(52-5)!)
C(52, 5) = 52! / (5!47!)

Calculating the factorials and dividing, you get:

C(52, 5) = 2,598,960

So, there are 2,598,960 ways to draw a 5-card hand from a standard deck of 52 cards without repeats.

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Answer:

5 to 25 25:5 5:25

Step-by-step explanation:

this is what I got so I hope it helps you

draw a straight line through (4.3,0) and (0,-6)

Answer:

D.

tangent = opp over adj

Step-by-step explanation:

Answer:

y=22

Step-by-step explanation:

set 6y-3 equal to 129 and then solve

Answer: B. x(x−5)(x+7)

Step-by-step explanation: LCD...Apex

Answer:

122

Step-by-step explanation:

hope this helps plz like and star

-mercury

Answer:

(-6,8)

Step-by-step explanation:

Step-by-step explanation:

the original price of the mirror is not known so we will call it x for now.

The discount on the original price is a 40% discount, so it is 40% of x or 0.4x

We are told that the discount is $6, so 0.2x will = 6. So now we will solve the equation for x.

0.4x = 6

x= 6/0.4

x= 15

The original price is $15

The regular price of the mirror is $15.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given that, a shop owner offered a 40% discount off the regular price of a mirror.

Let the regular price of a mirror be x.

The amount of the discount is $6.

Now, 40% of x=6

40/100 ×x=6

0.04x=6

x=6/0.4

x=15

Therefore, the regular price of the mirror is $15.

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Answer: The answer is 5 units

Step-by-step explanation:

If you plot it on a graph and what not it comes out to 5 units, going diagonally.

In a city, the distance between the library and the post office is three units. This may be calculated by counting the gaps between the two points on the grid illustrated above. The Library is in position 1 and the Post Office is in position 4, therefore the distance between them is three units.

The amount of space between two locations is defined as distance. It is commonly measured in meters, kilometers, miles, or feet. Distance is used to compute the length of a journey, the time required to go a specific distance, and the speed of an item moving a specific distance. It may also be used to determine the dimensions of an item. In trigonometry, distance is also used to measure angles, such as the angle between two points on a circle. Distance may be present in practically every facet of our daily lives, from city distances to item sizes. Distance is an important term to grasp in both physics and mathematics.

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Answer:

2 irrational solutions

Step-by-step explanation:

using the quadratic formula:

\( \frac{ -b \:± \sqrt{b {}^{2} - 4ac } }{2a} \)

3x²−x−5=0

where a = 3, b = -1 and c = -5, plug in those values in the quadratic formula

\( \frac{ - ( - 1)±\sqrt{(1) {}^{2} - 4(3)( - 5) } }{2(3)} \)

you get two solutions:

\( \frac{1 + \sqrt{61} }{6} \: and \: \frac{1 - \sqrt{61} }{6} \)

both can be written as:

\( \frac{1± \sqrt{61} }{6} \)

They are irrational as they cannot be written in the form p/q where p and q are whole numbers (integers)

Answer:

Domain: {7, 4, 0} Range: {-8, 4, 1, 8}

Step-by-step explanation:

the domain is just the x values and the range is just the y values when just a list of cordinates are given.

The point on the surface that ensures the tangent plane contains (3,0,0) is (1/2, 0, 1/4).To find a point on a surface that ensures the tangent plane contains the point (3,0,0), we need to use the following steps:

Find the gradient vector of the surface at a general point (x,y,z).

Set the gradient vector equal to the normal vector of the tangent plane passing through (3,0,0). Since the normal vector of the tangent plane is perpendicular to the plane, it must be orthogonal to the gradient vector.

Solve the resulting system of equations for x, y, and z to find the specific point on the surface that satisfies the condition.

For example, let's consider the surface defined by the equation z = x^2 + y^2. The gradient vector of this surface is given by <2x, 2y, -1>. Setting this equal to the normal vector of the tangent plane passing through (3,0,0), which is <1,0,0>, gives us the following system of equations:

2x = 1

2y = 0

-1 = 0

Solving for x and y, we get x = 1/2 and y = 0. Plugging these values into the original equation of the surface, we get z = (1/2)^2 + 0^2 = 1/4. Therefore, the point on the surface that ensures the tangent plane contains (3,0,0) is (1/2, 0, 1/4).

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The parametrization of the circle of radius 5 in the xy-plane, centered at the origin, oriented clockwise is: x(t) = 5 * cos(t). y(t) = -5 * sin(t).

To parametrize the circle of radius 5 in the xy-plane, centered at the origin and oriented clockwise, we can use the trigonometric functions sine and cosine.

The equation of a circle with radius r centered at the origin can be written as:

x^2 + y^2 = r^2.

In this case, since the radius is 5, the equation becomes:

x^2 + y^2 = 25.

To parametrize the circle, we can express x and y in terms of the angle θ, where θ is measured counterclockwise from the positive x-axis. Since we want the circle to be oriented clockwise, we need to use the angle -θ.

Let's express x and y in terms of θ:

x = r * cos(-θ) = 5 * cos(θ).

y = r * sin(-θ) = -5 * sin(θ).

Therefore, the parametrization of the circle is:

x(t) = 5 * cos(t).

y(t) = -5 * sin(t).

Here, we have used t as the parameter instead of θ, where t represents the parameterization of the circle. The point (5, 0) corresponds to t = 0.

So, the parametrization of the circle of radius 5 in the xy-plane, centered at the origin, oriented clockwise is:

x(t) = 5 * cos(t).

y(t) = -5 * sin(t).

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Answer:

sinple interest= principle*rate*time/100

SI= 2400*3*1.5/100

SI= 108

AMOUNT= SI + PRICIOLE

AMOUNT= 108+2400

AMOUNT= 2508

{ I converted 18 months to 1.5 years}

The area of the given triangle is 87.55 square centimeter.

From the given triangle, base=17 cm and height=10.3 cm.

The basic formula for the area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h.

Here, area of a triangle = 1/2 ×17×10.3

= 87.55 square centimeter

Therefore, area of the given triangle is 87.55 square centimeter.

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The value of x is 10.

Given triangle is a right-angled triangle.

Let the lengths of not mentioned lengths be 2p(hypotenuse) and 2q (other side).

There are two triangles in the given picture.

Consider the smaller triangle.

Apply Pythagoras theorem to that i.e.,

\(p^{2}\) = \((3x)^{2} + q^{2}\)

(Here, total hypotenuse is 2p length and the smaller triangle has half of its length. So, length is p. Similarly in case of q)

\(p^{2} = 9x^{2} + q^{2}\)  (Equation 1)

Now, consider the large triangle.

Apply Pythagoras theorem to that i.e.,

\((2p)^{2} = (4x + 20)^{2} + (2q)^{2}\)

\(4p^{2} = (16x^{2} + 160x + 400) + 4q^{2}\)

Substitute \(p^{2}\) from Equation 1

\(4(9x^{2} + q^{2} ) = 16x^{2} + 160x + 400 + 4q^{2}\\\)

\(36x^{2} + 4q^{2} = 16x^{2} + 160x + 400 + 4q^{2}\)

\(36x^{2} = 16x^{2} + 160x + 400\)  (\(4q^{2}\) from both sides got cancelled)

\(20x^{2} - 160x - 400 = 0\)

Solving the quadratic equation,

\(20x^{2} - 200x + 40x - 400 = 0\)

\(20x(x - 10) + 40(x - 10) = 0\)

\((20x+ 40)(x - 10) = 0\)

So, 20x + 40 = 0 or x - 10 = 0

i.e., x = -2 or 1o

But \(x \neq -2\) because angles cannot be negative.

So, x is 10.

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Answer:

5600 pounds

Step-by-step explanation:

first find the number of workers attending:

70%of 800 = 560

Next find the number of people attending:

560 x 2 = 1120

Now, Calculate the money raised:

5 X 1120 = 5600

Hope this helps

Good Luck

To find the expression for the length of ribbon Margot needs for both pillows, we first need to find the perimeter of each pillow.

For the first pillow with a side length of 2x+1 inches, the perimeter is calculated by multiplying the side length by 4:
Perimeter of first pillow = 4 * (2x+1) = 8x + 4 inches.

For the second pillow with a side length of 4x-7 inches, the perimeter is calculated in the same way:
Perimeter of second pillow = 4 * (4x-7) = 16x - 28 inches.

To find the expression for the length of ribbon needed for both pillows, we add the perimeters together:
Expression for total length of ribbon = Perimeter of first pillow + Perimeter of second pillow
= (8x + 4) + (16x - 28)
= 24x - 24 inches.

Now, to find the length of the ribbon if x = 3, we substitute x = 3 into the expression:
Length of ribbon if x = 3
= 24(3) - 24
= 72 - 24
= 48 inches.

The expression for the length of ribbon Margot needs for both pillows is 24x - 24 inches. If x = 3, the length of the ribbon is 48 inches. To find the expression for the length of ribbon needed for both pillows, we calculated the perimeter of each pillow. The first pillow has a side length of 2x+1 inches, so its perimeter is 4 * (2x+1) = 8x + 4 inches. The second pillow has a side length of 4x-7 inches, so its perimeter is 4 * (4x-7) = 16x - 28 inches. To find the total length of ribbon needed, we added the perimeters together: (8x + 4) + (16x - 28) = 24x - 24 inches. To find the length of the ribbon if x = 3, we substituted x = 3 into the expression: 24(3) - 24 = 48 inches. Therefore, the expression for the length of ribbon Margot needs for both pillows is 24x - 24 inches, and if x = 3, the length of the ribbon is 48 inches.

The expression for the length of ribbon Margot needs for both pillows is 24x - 24 inches. If x = 3, the length of the ribbon is 48 inches.

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The null and alternative hypothesis for testing to see if there is a relatonsip between age and opinion for the question asked by gallup is Divorce Opinions and Gender I.

We introduce the results of a

May 2010 Gallup poll of 1029 US adults. When asked if they view divorce as “morally acceptable”,

71% of the men and 67% of the women in the sample responded yes. In the test for a difference in

proportions, a randomization distribution gives a p-value of 0.165. Does this indicate a significant

Solution

If we use a 5% significance level, the p-value of 0.165 is not less than α = 0.05 so we would not

reject H0 : pf = pm. This means the data do not show significant evidence of a difference in the

proportions of men and women that view divorce as “morally acceptable”

Solution

(a) The p-value (0.003) is small so the decision is to reject H0 and conclude that the mean recall

for sleep (¯xs = 15.25) is different from the mean recall for caffeine (¯xc = 12.25). Since the mean

for the sleep group is higher than the mean for the caffeine group, we have sufficient evidence to

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A scatter plot is also referred to as scatter chart, scatter diagram or scattergram and it can be defined as a type of graph which is used for the graphical representation of the values of two (2) variables, with the resulting points showing any association (correlation) between the data set.

A quadratic function can be defined as a mathematical expression (equation) that can be used to define and represent the relationship that exists between two or more variable on a graph.

In Mathematics, the standard form of a quadratic equation is given by;

ax² + bx + c = 0

By critically observing the graph (see attachment) which models the data in the given table, we can infer and logically deduce that the polynomial function is given by:

y = -0.4908x² + 5.8845x + 1.3572

For the number of students that are absent 10 days after the outbreak, we have:

y = -0.4908(10)² + 5.8845(10) + 1.3572

y = -0.4908(100) + 58.845 + 1.3572

y = -49.08 + 58.845 + 1.3572

y = 11.12 ≈ 11 students.

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