Solve for x what is x^2-9=55

Answer:

6 times

Step-by-step explanation:

\( \frac{1}{6} \times 36 = 6\)

Answer:

7. The area should be 32. Multiply 5 by 4 to get 20. Find the missing length to multiply by 3, which is 4, and multiply. 3 * 4 = 12. Add 20 + 12 and get 32 cm.

8. The area should be 70. You did pretty well, but when finding the area of a triangle, divide the product by 2, or multiply by 0.5. 5 * 8 = 40/2 or 40 * 0.5 which both equal 20. 50, plus the area of the triangle, 20, will get you 70.

The interest rate for the savings account is 5% after 4 years, $20,000 deposited in a savings account with simple interest earned $800 in interest.

We can use the formula for simple interest to solve the problem:

Simple interest = (Principal * Rate * Time) / 100

where Principal is the initial amount deposited, Rate is the interest rate, and Time is the time period for which the interest is calculated.

We know that the Principal is $20,000 and the time period is 4 years. We are also given that the interest earned is $800. So we can plug in these values and solve for the interest rate:

$800 = (20,000 * Rate * 4) / 100

Multiplying both sides by 100 and dividing by 20,000 * 4, we get:

Rate = $800 / (20,000 * 4 / 100) = 0.05 or 5%

Therefore, the interest rate for the savings account is 5%.

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so we know that the factors of (x-6) and (x+2) will yield a remainder of -14, thus by the remainder theorem we can say that the values of x = 6 and x = -2 will yield -14, that is for our function f(6) = f(-2) = -14, so let's plug those two values and see what we get for our "k" and "f"

\(\boxed{x=6}\hspace{5em}f(6)=-x^3+fx^2+kx-62\\\\\\ -14=-(6)^3+f(6)^2+k(6)-62\implies -14=36f+6k-278 \\\\\\ 264=36f+6k\implies 264=6(6f+k)\implies \cfrac{264}{6}=6f+k \\\\\\ 44=6f+k\implies 44-6f=k \\\\[-0.35em] ~\dotfill\\\\ \boxed{x=-2}\hspace{5em} f(-2)=-x^3+fx^2+kx-62\\\\\\ -14=-(-2)^3+f(2)^2-k(2)-62\implies -14=8+4f-2k-62 \\\\\\ -14=4f-2k-54\implies 40=4f-2k\implies 40=2(2f-k)\)

\(\cfrac{40}{2}=2f-k \implies 20=2f-k\implies \stackrel{\textit{substituting from the equation above}}{20=2f-(44-6f)} \\\\\\ 20=2f-44+6f\implies 64=2f+6f\implies 64=8f\implies \cfrac{64}{8}=f \\\\\\ \boxed{8=f}\hspace{5em}\stackrel{\textit{since we know that}}{44-6f=k}\implies 44-6(8)=k\implies \boxed{-4=k}\)

Answer:

0.5

Step-by-step explanation:

Answer:

0.5= 1/2

Explanation:

Hope that helps

Answer:

p=18

Step-by-step explanation:

if 4(p-7) = 44,

Then you can use distributive property to solve

4p-28=44

add 28 to both sides. So,

4p=72

Divide 4 from both sides.

p= 18.

(a)Therefore: P(X > 5) = 1 - P(X ≤ 5)= 1 - 0.0336= 0.9664 . (b)The Poisson probability mass function: P(X = 4) = (λ4/4!) e-λ= (54/4!) e-5= 0.1755. (c)Therefore: P(Y ≥ 3) = P(Y = 3) + P(Y = 4)= 0.4042 + 0.1785= 0.5827.

a. Probability that there are more than 5 returned items in a certain day. The expected value of the returned items per day is 5 and this is also equal to the variance (σ2) since it is a Poisson distribution.

Hence λ = 5.The probability that there are more than 5 returned items can be calculated as:P(X > 5) = 1 - P(X ≤ 5)where P(X ≤ 5) is the cumulative probability that there are less than or equal to 5 returned items.

This can be calculated using the Poisson probability mass function:P(X ≤ 5) = Σ (λk/k!) e-λ for k = 0, 1, 2, 3, 4, 5= (e-5/0!) + (5e-5/1!) + (25e-5/2!) + (125e-5/3!) + (625e-5/4!) + (3125e-5/5!)= 0.0336

Therefore: P(X > 5) = 1 - P(X ≤ 5)= 1 - 0.0336= 0.9664

b. Probability that there are 4 returned items in a certain day. The probability of getting exactly 4 returned items can be calculated using the Poisson probability mass function: P(X = 4) = (λ4/4!) e-λ= (54/4!) e-5= 0.1755

c. Probability that there are 4 returned items and at least three have available replacements in a certain day. Let Y be the number of returned items with available replacements.

Since the probability that a returned item has an available replacement is 0.65, the probability that a returned item does not have an available replacement is 1 - 0.65 = 0.35. Hence Y is a binomial distribution with n = 4 and p = 0.65.

The probability that there are 4 returned items and at least three have available replacements can be calculated as:P(Y ≥ 3) = P(Y = 3) + P(Y = 4)where P(Y = 3) and P(Y = 4) can be calculated using the binomial probability mass function:

P(Y = 3) = (4C3) (0.65)3 (0.35)1= 0.4042P(Y = 4) = (4C4) (0.65)4 (0.35)0= 0.1785

Therefore:P(Y ≥ 3) = P(Y = 3) + P(Y = 4)= 0.4042 + 0.1785= 0.5827.

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Nearest Neighbor (NN) technique is a straightforward and robust classification algorithm that requires no training data and is useful for determining which class a new sample belongs to.

The classification rule of this algorithm is to assign the class label of the nearest training instance to a new observation, which is determined by the Euclidean distance between the new point and the training samples.To determine how many measurements will be correctly classified, let's go step by step:Let's use the first four measurements in each class for training, and the last three measurements for testing.```

Class 1: train = (0.4003,0.3985,0.3998,0.3997) test = (0.4015,0.3995,0.3991)
Class 2: train = (0.2554,0.3139,0.2627,0.3802) test = (0.3247,0.3360,0.2974)
Class 3: train = (0.5632,0.7687,0.0524,0.7586) test = (0.4443,0.5505,0.6469)```

We need to determine the class label of each test instance using the nearest neighbor rule by calculating its Euclidean distance to each training instance, then assigning it to the class of the closest instance.To do so, we need to calculate the distances between the test instances and each training instance:```
Class 1:
0.4015: 0.0028, 0.0020, 0.0017, 0.0018
0.3995: 0.0008, 0.0010, 0.0004, 0.0003
0.3991: 0.0004, 0.0006, 0.0007, 0.0006

Class 2:
0.3247: 0.0694, 0.0110, 0.0620, 0.0555
0.3360: 0.0477, 0.0238, 0.0733, 0.0442
0.2974: 0.0680, 0.0485, 0.0353, 0.0776

Class 3:
0.4443: 0.1191, 0.3246, 0.3919, 0.3137
0.5505: 0.2189, 0.3122, 0.4981, 0.2021
0.6469: 0.0837, 0.1222, 0.5945, 0.1083```We can see that the nearest training instance for each test instance belongs to the same class:```
Class 1: 3 correct
Class 2: 3 correct
Class 3: 3 correct```Therefore, we have correctly classified all test instances, and the accuracy is 100%.

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Answer:

x = 13

Step-by-step explanation:

call the missing number x

8 - x = - 5                        Subtract 8 from both sides

8-8 - x = -5-8                  Combine

-x = - 13                           Multiply by -1

x = 13

Answer:

35 degrees

Step-by-step explanation:

All angles of a triangle add up to 180 degrees.

180-120-25 = ?

? = 35

Answer:

35

Step-by-step explanation:

Answer:

269.013 fluid ounce

Step-by-step explanation:

7 pints each of apple juice and cranberry juice is 14 pints in total. 14 pints into fluid ounces is 269.013. why ? because you multiply the volume value by 19.215.

The magnitude of the net magnetic field at the square's center is \(= (7.94 * 10^{-4}N/m)i+(-7.94 * 10^{-4}N/m)j\).

Using \(dB=\frac{u_0i}{4\pi} \frac{sin\theta}{r^2}\) the force on say, wire 1 (the wire at the upper left of the figure) is along the diagonal (pointing toward wire 3, which is at the lower right). Only the forces (or their components) along the diagonal direction contribute. With θ=45°, we find the force per unit meter on wire 1 to be

\(f_1 = |F_{12}+F_{13}+F_{14}|\\\\= 2F_{12}cos\theta+f_{13}\\\\=2(\frac{u_0i^2}{2\pi a} )cos45^0+\frac{u_0i^2}{2\sqrt{2}\pi a }\)

\(=\frac{3}{2\sqrt{2}\pi }(\frac{u_0i^2}{0})\\\\=\frac{3}{2\sqrt{2}\pi } \frac{(4\pi*10^{-7}T.m/A)(15.0A)^2} {(8.50*10^{-2}m)}\)

\(= 1.12 * 10^{-3}N/m\)

The direction of F1​ ​ is along r^=(i^=j^​)/sqrt2. In unit-vector notation, we have

\(F_1 = \frac{(1.12 * 10^{-3}N/m)}{\sqrt{2} }(i - j) \\\\= (7.94 * 10^{-4}N/m)i+(-7.94 * 10^{-4}N/m)j\)

Hence the answer is the magnitude of the net magnetic field at the square's center is \(= (7.94 * 10^{-4}N/m)i+(-7.94 * 10^{-4}N/m)j\).

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The perimeter of her garden is 4g² -34g - 2 cm.

It is important to note that the perimeter of a triangle is the addition of all its side. This will be illustrated thus:

In this case, Josh has a triangular garden with sides represented with 15g²- 6g + 8. The other sides are -17g² - 22g - 13 and the third side represented by 6g² - 6g + 3.

The perimeter will be:

= 15g²- 6g + 8 -17g² - 22g - 13 + 6g² - 6g + 3.

= 4g² -34g - 2

The perimeter is (4g² -34g - 2)cm.

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The value of the integral ∬ y dV over region D is 2/3.

We have,

To evaluate the integral ∬D y dV, where D is the region defined as D = {(x, y, z): x² + y² ≤ 1, x ≥ 0, y ≥ 0, 0 ≤ z ≤ 2}, we need to set up the integral and then compute it.

Since the region D is described in cylindrical coordinates, we will use cylindrical coordinates for the integral.

Region D corresponds to a quarter of a cylinder of radius 1 and height 2.

The integral can be set up as follows:

∬D y dV = ∫∫∫_D y dz dy dx

To evaluate this triple integral, we integrate with respect to z first, then y, and finally x.

First, let's set up the limits of integration for each variable.

For z, the limits are from 0 to 2, as specified in region D.

For y, the limits are from 0 to √(1 - x²), since x² + y² ≤ 1 implies y ≤ √(1 - x²).

For x, the limits are from 0 to 1, as specified in region D.

Now, we can set up and compute the integral:

∬D y dV = ∫[0 to 1]∫[0 to √(1 - x²)]∫[0 to 2] y dz dy dx

Integrating with respect to z, we have:

∬D y dV = ∫[0 to 1]∫[0 to √(1 - x²)] [yz] [0 to 2] dy dx

= ∫[0 to 1]∫[0 to √(1 - x²)] 2y dy dx

Integrating with respect to y, we have:

∬D y dV = ∫[0 to 1] [y²] [0 to √(1 - x²)] dx

= ∫[0 to 1] (1 - x²) dx

Now, we can evaluate the remaining integral:

∬D y dV = ∫[0 to 1] (1 - x²) dx

= [x - (x³/3)] [0 to 1]

= (1 - (1/3)) - (0 - 0)

= 2/3

Therefore,

The value of the integral ∬ y dV over the region D is 2/3.

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The complete question:

Evaluate the integral ∬D y dV, where D is the region defined as

D = {(x, y, z): x² + y² ≤ 1, x ≥ 0, y ≥ 0, 0 ≤ z ≤ 2}.

Tyler drank a total of 9 2/21 liters of water altogether.  

Tyler drank a fraction of 9 5/21 liters of water altogether. To find the total amount of water Tyler drank, we need to add the 2 3 liters of water he drank before jogging and the 3 7 liters of water he drank after jogging. To add these fractions, we need to find a common denominator, which is 21.

For the first fraction, we need to multiply both the numerator and denominator by 7 to get 14/21. For the second fraction, we need to multiply both the numerator and denominator by 3 to get 9/21. Now, we can add these two fractions:

14/21 + 9/21 = 23/21

This is an improper fraction, so we can simplify it to a mixed number by dividing the numerator by the denominator:

23 ÷ 21 = 1 remainder 2

So, Tyler drank a total of 9 2/21 liters of water altogether.

Drinking enough water is essential for staying hydrated and healthy, especially during exercise. It is recommended to drink at least 8 cups (64 ounces or 1.9 liters) of water per day, but this can vary depending on factors such as age, gender, weight, and physical activity level. Drinking enough water can help prevent dehydration, regulate body temperature, flush out toxins, and improve overall health and well-being.
 

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The probability that the sum is a multiple of three is 0.2778

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating that the event will not occur and 1 indicating that the event will definitely occur.

If a pair of six-sided dice is rolled, and the sum is recorded, then the possible sum is the numbers from (1 + 1) = 2 to (6 + 6) = 12.

From 1 to 12, the multiples of 3 are 3, 6, 9, and 12. These can be resulted from having the following dice rolled.

3 : 1 & 2, 2 & 1

6 : 1 & 5, 2 & 4, 3 & 3, 4 & 2, 5 & 1

9 : 3 & 6, 6 & 3

12 : 6 & 6

Since there are 10 possible outcomes wherein the sum is a multiple of 3, and there are (6 x 6) total outcomes, then the probability is

p = 10 / 36 = 0.2778

Hence, the probability that this sum is a multiple of three is 0.2778.

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Answer:

Hello! answer:

140, 140 and 40

Step-by-step explanation:

140 + 140 + 40 + 40 = 360

The other three angles would measure to 140, 140 and 40 Hope that helps!

Answer:

x= 7

Step-by-step explanation:

3x -15 =6

+15 +15

3× = 21

3/21

× = 7

From the given information provided, the probability of event F given that event E has occurred is 0.5.

Conditional probability is probability of an event A occurring with given that event B has occurred. It is denoted as P(A|B) and is calculated as follows:

P(A|B) = P(A and B) / P(B)

To find P(F/E), we use the conditional probability formula:

P(F/E) = P(E and F) / P(E)

We are given that P(E and F) = 0.1 and P(E) = 0.2. Substituting the given values in the formula, we get:

P(F/E) = 0.1 / 0.2

Simplifying this expression, we get:

P(F/E) = 0.5

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Answer:

The mode = 24

Probability = 0.14

Probability = 0.74

Step-by-step explanation:

Mode is 24 because it has the highest frequency.

The probability of winning a score of 25 = 7/50 = 0.14 = 14%

Probability of winning sore of 23+ = 37/50 = 74% = 0.74

Hope this helps.

Good luck

Answer:

a) mode: 24

b) 14%

c) 74%

Step-by-step explanation:

a) had the most winning games that received that score.

b) 7/50

c) 37/50 10+14+7+4+2=37 total past 23.

37 past 23 divided by total amount 50=0.74 or 74%

Answer:

-2k

Step-by-step explanation:

Answer: You combine like terms

2k^3-2k^4

Answer:

Fill it with number but do it on paper

Step-by-step explanation:

Answer:

y = \(\frac{1}{2}\)x + 3

Step-by-step explanation:

Put two points on the line, which I'm using (0,3) and (2,4) into the point-slope form: \(\frac{4 - 3}{2 - 0}\) and solve to get \(\frac{1}{2}\), which is your slope, or, when put into the y =mx + equation, it is m. Now your equation looks like y = \(\frac{1}{2}\)x + b.

Substitute x and y from one of the ordered pairs, which I'm using (2,4) into the equation, which will look like this: 4 = 1/2 · 2 + b

Then solve: 4 = 1 + b

3 = b

Now you have your equation, y = \(\frac{1}{2}\)x + 3

The recurrence relation for p(n) is p(n) = p(n-1) + p(n-2), valid for n ≥ 3.

To find the recurrence relation for p(n), we can consider the possible choices for the first square in the checkerboard.

When the first square is painted gold, the remaining (n-1) squares can be painted in p(n-1) ways because there are no restrictions on consecutive white squares.

When the first square is painted white, the second square must be painted gold to satisfy the rule. Then, the remaining (n-2) squares can be painted in p(n-2) ways.

Therefore, the total number of ways to paint the checkerboard of size n is the sum of these two cases: p(n) = p(n-1) + p(n-2).

This recurrence relation is valid for n ≥ 3 because for n = 1 and n = 2, the number of ways to paint the checkerboard can be determined separately.

The recurrence relation for p(n) is p(n) = p(n-1) + p(n-2), valid for n ≥ 3. This relation allows us to calculate the number of ways to paint a 1 x n checkerboard subject to the rule that no two consecutive squares can be painted white.

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Answer:

because they all have 3 corners

Answer:

Option A that is best describes the given scenario is option A that is “LaTricia is not correct. The word product does mean to multiply, but 12 should be the product and 3 should be one of the factors.”

Step-by-step explanation:

Given that LaTricia wrote a sentence as an equation.  Given sentence is “Twelve is the product of three and a number”

Expression written by LaTricia =

Lets first concentrate on sentence and we will create our expression based on sentence and check it against the expression created by LaTricia.  Let the number represented by variable w.

So product of 3 and the number will be represented by

And as Twelve is the product of three and a number

That is three is one of the factor and result product is 12. Hence option A that is best describes the given scenario is option A that is “LaTricia is not correct. The word product does mean to multiply, but 12 should be the product and 3 should be one of the factors.”

Brad needs to score between 72 and 79 on the fourth test in order to get a C for the semester.

To explain why this is so, we need to first understand how the grade for the semester is calculated.Since the final course grade depends entirely on the average of four equally weighted 100-point tests, this means that each test will count for 25% of Brad’s final grade. Therefore, Brad needs to get an average score of 70-79 (inclusive) on the four tests combined in order to get a C for the semester.

In order to calculate what range of scores Brad needs to get on the fourth test in order to get a C for the semester, we need to look at the scores he has already obtained on the first three tests. Brad has scored 87, 89 and 78 on the first three tests. This gives him a total score of 254 (87+89+78=254). This means that Brad needs to get a score of between 70 and 79 on the fourth test in order to reach a total score of between 280-309 (inclusive), which will result in an average score of between 70-79 (inclusive), and give Brad a C for the semester.

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Answer and Step-by-step explanation:

Solve for the middle side, then  for x using Pythagorean Theorem.

\(A^2 + B^2 = C^2\\\\\\6^2 + 8^2 = C^2\\\\100 = C^2\\\\C = 10\\\\\\\\A^2 + 10^2 = 12^2\\\\A^2 + 100 = 144\\\\A^2 = 44\\\\A^2 = 2\sqrt{11} <-Answer\)

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