Technician A says you should place the air ratchet setting to
clockwise to loosen a fastener. Technician B says a fastener
must be set to the proper torque after using an air ratchet. Who
is correct?

Manufacturing technology and manufacturing systems are two closely related concepts in the manufacturing industry.

On the other hand, manufacturing systems refer to the processes and procedures used to manage the entire manufacturing process.

Manufacturing technology refers to the tools, machines, and equipment used to produce goods. T While they share some similarities, they also have some significant differences. Here's a comparison and contrast of manufacturing technology and manufacturing systems:

Manufacturing technology can be categorized into several sub-categories such as materials processing technology, assembly technology, computer-aided manufacturing (CAM) technology, and more.

Manufacturing systems involve the integration of different elements such as people, machines, and materials to create a cohesive production process. Manufacturing systems can include different types of systems such as production control systems, quality control systems, inventory management systems, and more. The primary goal of manufacturing systems is to ensure that the manufacturing process is optimized to produce high-quality goods at the lowest possible cost.

Therefore, One of the key differences between manufacturing technology and manufacturing systems is that technology refers to the physical tools used to produce goods, whereas systems refer to the overall process used to manage the manufacturing process.

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Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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Explanation:

D the answer is D and anyone can answer this Question

Based on the provided options, the scientific expression that is the same as 1545.5347 is 154553.4e3. Therefore, the correct option is option D.

A scientific expression, often known as scientific notation, is a method of representing extremely big or extremely small integers. It is often used to simplify the representation of such numbers in scientific and mathematical operations. A number is expressed in scientific notation as a product of two parts: a coefficient and a power of ten.

The coefficient is a value between 1 and 10, and the power of 10 determines how far the decimal point should be moved. The "e3" signifies multiplying the integer by 10 raised to the power of 3, which is similar to moving the decimal point three places to the right in this formula. As a result, 154553.4e3 equals 154553.4103, which simplifies to 154553400.

Therefore, the correct option is option D.

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Answer:

Explanation:

7. False

8. True

9. True

10.True

11. True

Hope this helps...........

A microcontroller having an 8-bit data bus and a 16-bit address bus can address 216 bytes of data, which is equal to 64 KB, in a single address (kilobytes).

Each address on the microcontroller's 16-bit address bus is represented by 16 bits of data. Each address corresponds to a byte of data on the 8-bit data bus, and the 16-bit address bus may address up to 216 = 65,536 different unique addresses. A 16-bit address can therefore individually address each byte of data.

65,536 bytes, A processor having 16-bit memory addresses can directly access 64 KB (65,536 bytes) of byte-addressable memory because 216 is 65,536 bytes. More can be accessed if a system utilizes segmentation with 16-bit segment offsets.

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The benefits of observing good safety measures in relation to an increase in productivity within a pharmaceutical laboratory is that:

A laboratory is known to be one that is known to have a lot of potential risks that is said to often arise due to  a person's exposure to chemicals that are corrosive and toxic, flammable solvents, high pressure gases and others.

So,  A little care and working in line to all the prescribed safety guidelines will help a person to be able to avoid laboratory mishaps.

Therefore, the act of adhering to all these policies helps a lot of employees to hinder the  spills of chemicals and other kinds of  accidents, as well as reduce the damage to the environment that is outside of the lab.

Hence, The benefits of observing good safety measures in relation to an increase in productivity within a pharmaceutical laboratory is that:

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Answer:

Both a and b.

Explanation:

HID headlamps require high voltage ignition to start just like street lamps. It requires almost 25,000 volts to start HID head lamps but require only 80 to 90 volts to keep it operating.

Efficient and reliable communication and tracking system.

In the aviation industry, having an efficient and reliable communication and tracking system is crucial for ensuring safe and smooth operations. This advanced system enables real-time communication between pilots, air traffic controllers, and ground personnel, allowing for timely updates, instructions, and emergency responses. It also facilitates the tracking and monitoring of aircraft, enhancing situational awareness and enabling proactive measures in case of any deviations or emergencies.

Implementing such advanced communication and tracking systems requires the collaboration of airlines and aviation companies with technology providers and regulatory authorities. They need to invest in the development and deployment of cutting-edge technologies like satellite-based communication systems, ADS-B (Automatic Dependent Surveillance-Broadcast), and data link systems.

These systems should be capable of transmitting and receiving large volumes of data securely and seamlessly. Additionally, airlines and aviation companies need to ensure proper training and familiarization of their personnel with these systems to maximize their effectiveness and utilization in day-to-day operations.

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Answer:

10.5

Explanation:

Measuring a Brake Drum, the Brake Micrometer is set to a Base Drum Diameter of 10 Inches plus four notches, and the dial reads 22.  Diameter of the drum is 10.5.

Any straight line segment that cuts through the center of a circle and has ends that are on the circle is considered a circle's diameter in geometry. It is also known as the circle's longest chord.

The diameter of a sphere can be defined using either of the two methods. In more recent usage, the diameter can also refer to a diameter's length, or displaystyle d.

As opposed to a diameter, which refers to the line segment itself, one uses the term "diameter" in this context since all diameters of a circle or sphere have the same length, which is equal to twice the radius "displaystyle r.

Therefore, Measuring a Brake Drum, the Brake Micrometer is set to a Base Drum Diameter of 10 Inches plus four notches, and the dial reads 22.  Diameter of the drum is 10.5.

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Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)

Without specific dimensions and material properties, it is not possible to provide precise values. However, normal stress is determined by the axial load divided by the area perpendicular or parallel to the grains.

Therefore:
σ = 288 NN / 100 cm² = 2.88 N/cm²
To determine the shear stress, we can use the formula:
τ = F/A
Where τ is the shear stress. Assuming the board has a thickness of 2cm, the area would be 20cm². Therefore:
τ = 288 NN / 20 cm² = 14.4 N/cm²
In summary, if the board is subjected to an axial load of 288 NN, the normal stress acting perpendicular to the grain would be 2.88 N/cm², while the shear stress acting parallel to the grain would be 14.4 N/cm².

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The list of common malfunctions given in the question belongs to the 'impulse tubing' sensor-related instrument.

Impulse is referred to the sensing process of medium pressure, and tubing that directly connects this sensing process tapping to the transmitters is called impulse tubing. Impulse tubing is used to transmit the pressure signal from a process to a transmitter. Impulse tubing can be affected by several common malfunctions such as leakage, plugged or partially plugged tubing, improperly sized tubing, heat tracing too hot or too cold, excessive vibration, and mechanical damage.

"

Correct question is:

The following list of common malfunctions are for which sensor related instrument?

List of common malfunctions is as follows:

"

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Engineers play a crucial role in developing and implementing technological innovations to cater to the needs of society. However, if the engineering solutions do not comply with established codes of ethics and professional standards, the legal implications can be significant.

Engineers are expected to follow ethical standards to ensure that their engineering solutions meet safety, quality, and environmental criteria. The Code of Ethics of Engineers outlines the ethical principles, values, and practices that engineers should follow in their professional duties.

A violation of the Code of Ethics or a failure to comply with professional standards can lead to legal consequences. If an engineer's solution is not compliant with safety standards, the individual or company responsible for implementing that solution may face fines, penalties, or legal action. One real-life example of legal consequences resulting from engineering solutions is the Deepwater Horizon oil spill. In 2010, an explosion on the Deepwater Horizon oil rig caused a massive oil spill in the Gulf of Mexico, resulting in significant environmental and economic damage.

Investigations revealed that several engineering solutions that were implemented on the rig were not in compliance with safety standards. Engineers had also failed to follow established procedures for ensuring safety and environmental protection. As a result, BP, the company responsible for the rig, faced significant legal consequences, including fines, penalties, and legal action by affected parties. Engineers involved in the project also faced legal consequences, including loss of license and potential criminal charges.

Engineers have a professional obligation to ensure that their solutions meet safety, quality, and environmental criteria. This means that they should adhere to established codes of ethics, follow established procedures for ensuring safety, and ensure that their solutions are in compliance with relevant laws and regulations. They also have a responsibility to report any violations or issues that could impact the safety or environmental impact of their solutions. Failure to meet these obligations can lead to legal consequences and impact public trust in the engineering profession.

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Answer:

A big hazard is falling, whether it be people or equipment. This is why OSHA requires that workers wear hard hats when doing certain jobs.

Answer:

7.5 feet

Explanation:

45 divided by 6 is 7.5

Answer:

7.5 feet

Explanation:

45 divided by 6 is 7.5

Answer:

search up factors of 2450 and divide by two

The number of ways 2450 can be written as a product of 2 factors is 9 ways

Factors of 2,450 = 1, 2, 5, 7, 10, 14, 25, 35, 49, 50, 70, 98, 175, 245, 350, 490, 1225, 2450

The number of ways 2450 can be written as a product of 2 factors = number of factors / 2

= 18/2

= 9 wats

This means, taking the product of two factors such as;

1 × 2450

2 × 1225

5 × 490

7 × 350

10 × 245

14 × 175

25 × 98

35 × 70

50 × 98

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The angular velocity of the wheel 6 seconds after starting from rest, under the influence of the given couple moment, is 37.5 rad/s.

To solve this problem, we can apply the principle of conservation of angular momentum. The initial angular momentum of the wheel is zero since it starts from rest. The final angular momentum is the product of the moment of inertia and the angular velocity.
Given:
Mass of the wheel (m): 300 kg
Radius of gyration (k₀): 400 mm (0.4 m)
Couple moment (M): 300 N.m
Time (t): 6 s
First, we need to calculate the moment of inertia (I) of the wheel about its mass center using the formula:
I = m * k₀²
I = 300 kg * (0.4 m)²
I = 48 kg.m²
Next, we can use the equation for angular momentum to find the angular velocity (ω):
Initial angular momentum = Final angular momentum
0 = I * ω_initial - M * t
Since the wheel starts from rest, the initial angular velocity (ω_initial) is zero.
0 = 48 kg.m² * 0 - 300 N.m * 6 s
0 = -1800 N.m.s
To solve for the final angular velocity (ω), we rearrange the equation:
ω = M * t / I
ω = 300 N.m * 6 s / 48 kg.m²
ω = 37.5 rad/s
Therefore, the angular velocity of the wheel 6 seconds after starting from rest, under the influence of the given couple moment, is 37.5 rad/s.

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Answer:

22 Ω

Explanation:

0) to re=write the given schema;

1) to write common equation of U[V];

2) to calculate the value of the current I₁ [A];

3) to write the common equation of current I [A];

4) to calculate the value of the current I₂₃ [A];

5) to calculate the value of R₃ [Ω] using the common equation of U.

A variable is a value in programming that is subject to change based on external factors or data that has been passed into the program.

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Answer:

It's to ensure a driver's safety.

Designing a user manual for a snack vending machine requires careful consideration of the audience and communication guidelines. Here are the steps to create an effective user manual:

1. Introduction:
  - Begin with a brief overview of the snack vending machine.
  - Explain its purpose and benefits to engage the audience.

2. Getting Started:
  - Provide clear instructions on how to power on the machine.
  - Explain how to insert cash, credit cards, or special cards.
  - Describe any security measures to ensure user safety.

3. Menu Selection:
  - Explain how to navigate the menu options.
  - Describe different categories or types of snacks available.
  - Provide clear instructions on selecting desired items.

4. Payment Process:
  - Guide users on how to complete the payment process.
  - Include steps for using cash, credit cards, or special cards.
  - Highlight any additional charges or discounts.

5. Dispensing Snacks:
  - Explain the process of selecting and receiving snacks.
  - Describe any buttons or touchscreens involved.
  - Provide troubleshooting tips for any issues that may arise.

6. Maintenance and Troubleshooting:
  - Explain how to refill snacks and beverages.
  - Provide guidelines for machine cleaning and maintenance.
  - Address common issues and offer troubleshooting solutions.

7. Conclusion:
  - Summarize the key points covered in the manual.
  - Include contact information for customer support or queries.
  - Encourage users to provide feedback for future improvements.

Remember to use clear and concise language, include relevant visuals and diagrams, and organize the manual in a logical manner. Adhere to any brand guidelines or style requirements.

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Answer:

The correct answer is "1020 K".

Explanation:

The given values:

\(n_{th} = 0,25\)

\(n_2=0.50\)

Now,

⇒ \(n_{th}(rev) = \frac{n_{th}}{n_2}\)

By putting the values, we get

                 \(=\frac{0.25}{0.50}\)

                 \(=0.50\)

As we know,

⇒ \(n_{th} (rev)=1-\frac{TL}{TH}\)

or,

⇒ \(TH=\frac{TL}{1-n_{th} (rev)}\)

          \(=\frac{510}{1-0.50}\)

          \(=\frac{510}{0.5}\)

          \(=1020 \ K\)  

Note that with respect to the prompt on wiring, Option C, "the service legs are out of phase," is the correct answer.

In a three-wire 120 V system, there are two "hot" wires that are 180 degrees out of phase with each other and one neutral wire. The voltage between each hot wire and the neutral wire is 120 V. However, the voltage between the two hot wires is 240 V, which is twice the voltage between a hot wire and the neutral wire.

This is because the two hot wires are out of phase with each other. When one hot wire is at its maximum positive voltage, the other hot wire is at its maximum negative voltage. Therefore, the voltage difference between the two hot wires is the sum of their individual voltages, which is 240 V.

So, the correct statement is that the 240 V in a three-wire 120 V system is due to the service legs being out of phase.

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The flow rate, in kilograms per second, of the stream entering the 3-cm-diameter pipe at 80 bar and 700°C with a velocity of 150 m/s is 11.3 kg/s.

To determine the mass flow rate of the stream, we need to use the mass conservation equation, which states that the mass flow rate is constant along a stream tube:

ρAV = constant

where ρ is the density of the stream, A is the cross-sectional area of the pipe, and V is the velocity of the stream.

First, we need to determine the density of the stream using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

Assuming the stream is an ideal gas and using the given values, we can solve for the density:

ρ = (P / RT)

where:

Then the density is:

ρ = (8 x 10⁶ Pa) / (8.314 J/(mol K) x 973.15 K) = 106.2 kg/m³

Next, we can calculate the cross-sectional area of the pipe using the formula for the area of a circle:

A = πr²

where r is the radius of the pipe, which is half the diameter.

r = 1.5 cm = 0.015 m

A = π(0.015 m)² = 7.07 x 10⁻⁴ m²

Finally, we can use the mass conservation equation to solve for the mass flow rate:

ρAV = constant

flow rate = ρAV

flow rate = (106.2 kg/m³)(7.07 x 10^⁻⁴ m²)(150 m/s) = 11.3 kg/s

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Answer:

nsnsndndnndndndnhhhh