Tell any one condition how can we calculate potential difference in a circuit ?​

Given data:

Initial speed of the car;

Final speed of the car;

Time;

The acceleration of the car is given as,

Substituting all known values,

Therefore, the acceleration of the car is 3.625 m/s².

Answer:

439.6 THz

Explanation:

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.

A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length.  Spring balance works with the principle of Hooks law.

The stretching is made by the elasticity of the spring which make it in a wave like motion.

Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:

weight required  = (100 g × 1.8 cm) /2.7 cm

                            = 150 g.

A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.

Hence, 50 ml of water should be poured to the glass.

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Answer-

mk thats kool.

Answer:

Force Friction

Explanation:

The weight of the object at distance 3R from the Earth is 10 N if the weight at center of the Earth is 90N.

According to Newton's law of gravitation,

Weight W = m × g; where m is the mass of the object and

g is the acceleration due to gravity.

Also,

\(g = \dfrac{GM}{R^{2}}\)

where G=gravitational constant, M=mass of earth, R=radius of earth.

Hence,

\(W = m \times \dfrac{GM}{R^{2}}\)

Weight is inversely proportional to the square of radius R.

Weight of objects at the surface of the earth is 90 N.

Let W be the weight at a distance of 3 R from the center.

\(\dfrac{W}{90} = \dfrac{R^{2}}{(3R)^{2}}\\\dfrac{W}{90} = \dfrac{1}{9}\\W = 10\)

Weight at a distance 3 R is 10 N.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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One of the first ultraviolet and X-ray detectors was the satellite Copernicus.

The largest and most complex space observatory of its time, the Copernicus satellite was launched by NASA on August 21, 1972 from Launch Facility 36B, now located at Space Force Station Cape Canaveral, Florida.

Copernicus was probably NASA's first multi-wavelength observatory, with the largest ultraviolet telescope ever orbited and his four her X-ray sensors arranged side-by-side.

It can therefore be considered a precursor to modern space telescopes, such as NASA's Neil Gehrels Swift Observatory, which use visible, ultraviolet and X-ray radiation to monitor the sky.

Copernicus ceased activity in 1981, but has provided UV and X-ray measurements for 8.25 years. It has lost its role at the forefront of space astronomy as more advanced observatories such as Einstein and the International Ultraviolet Explorer have emerged.

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Answer:

3

5

4

Explanation:

x = (8=(9+9)

(9+9) = 4, 5, 3

Answer:

50m

Explanation:im just smart thank me later

The range is 80 meter and  the stone is 4.04 second in air​.

When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.

Given that: maximum height obtained by the projectile; H = 20 m.

Let initial velocity = u

For maximum range:

H = u²/4g

u = √(4gH) = 28 m/s

and  the range  of the projectile = u²/g = 4H = 4 ×20 m = 80 m.

Total time of flight = √2· u/g = √2 ×28/9.8 = 4.04 second.

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The process through which UV light bleaches pigments, textiles, or other things is known as photo deterioration. UV radiation is used to disinfect surfaces, destroy microorganisms, and remove stains from clothing.

It is a chemical procedure that causes the fabric's molecules to disintegrate and release the natural oils by the application of ultraviolet light. By dissolving the fabric's molecules, releasing natural oils, and eradicating bacteria, it kills germs when applied to clothing. A colorant's lightfastness—a radiation that specifies how resistant it is to fading when exposed to light—can be described as a dye or pigment. Dyes and pigments are employed, for instance, in the production of paints and printing inks as well as the dying of fabrics, polymers, and other materials. Colorant molecules go through several chemical steps throughout the fading.

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Photo degradation is the process by which UV light bleaches textiles, pigments, and other materials. Surfaces are cleaned with UV radiation, which also eliminates bacteria and gets stains out of clothes.

By using UV light, a chemical process forces the fabric's molecules to break down and release its natural oils. When applied to garments, it kills germs by dissolving the fabric's molecules, releasing natural oils, and eliminating bacteria. An indicator of a colorant's lightfastness, also known as a dye or pigment, is how resistant it is to fading when exposed to light. For example, dyes and pigments are used to colour fabrics, polymers, and other materials in addition to producing paints and printing inks.

The majority of UVC rays are absorbed by the atmosphere's nitrogen, oxygen, and ozone, and the remainder are scattered, preventing them from reaching the earth's surface.

Skin lesions are brought on by UVC. During the fading process, colorant molecules go through a number of chemical processes.

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Answer:

m₁ = 0.37 kg

Explanation:

According to Law of conservation of energy:

Heat Lost by Aluminum = Heat Gained by Water

m₁C₁ΔT₁ = m₂C₂ΔT₂

where,

m₁ = mass of piece of aluminum = ?

C₁ = specific heat capacity of aluminum = 900 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 250°C - 22°C = 228°C

m₂ = mass of water = 9 kg

C₂ = specific heat capacity of water = 4200 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 22°C - 20°C = 2°C

Therefore,

m₁(900 J/kg.°C)(228 °C) = (9 kg)(4200 J/kg.°C)(2°C)

m₁ = (75600 J)/(205200 J/kg)

m₁ = 0.37 kg

Answer:

Stars are the light bulbs of the universe.

Answer:

Stars are the recycling centers of the universe

Explanation:

I just did on edge C

The frequency of the wave of the rain dropping is 10 Hz.

The given parameters;

The frequency of the wave of the rain dropping is calculated as follows;

v = fλ

\(f = \frac{v}{\lambda} \\\\f = \frac{0.5}{0.05} \\\\f = 10 \ Hz\)

Thus, the frequency of the wave of the rain dropping is 10 Hz.

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Answer:

I think then answer for this question is number c. the South pole

The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].

The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.

The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.

To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]

Y = 4.95sin[π(3.80x - 1180t - 0.206)]

The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.

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-- The given question is incomplete, the complete question is

"Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]

Y2 : 4.95sin[π(3.80x-1180t-0.250)]

Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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Answer:

C

Explanation:

Up to 230 homes could be heated by the performance of the power plant.

By definitions of energy efficiency (\(\eta\)), no unit, and principle of energy conservation, the amount of waste heat rate (\(\dot Q_{waste}\)), in megawatts, is equal to the difference between the energy input and the useful output, that is to say:

\(\dot Q_{waste} = \left(\frac{1}{\eta} -1\right)\cdot \dot E_{out}\) (1)

Where \(\dot E_{out}\) is the useful output, in watts.

According to the statement, an average home uses 70 GJ of energy per year for heating and home heating takes place at a steady rate for half a year, then the number of homes (\(n\)), no unit, benefited by the co-generation plant is calculated by this formula derived from physical definition of power:

\(n = \frac{\dot Q_{waste}\cdot \Delta t}{Q_{home}}\) (2)

Where:

Now we proceed to find the number of houses: (\(\dot E_{out} = 1.9\times 10^{6}\,W\), \(\eta = 0.65\), \(\Delta t = 1.577\times 10^{7}\,s\), \(Q_{home} = 7\times 10^{10}\,J\))

By (1):

\(\dot Q_{waste} = \left(\frac{1}{0.65}-1 \right)\cdot (1.9\times 10^{6}\,W)\)

\(\dot Q_{waste} = 1.023\times 10^{6}\,W\)

By (2):

\(n = \frac{(1.577\times 10^{7}\,s)\cdot (1.023\times 10^{6}\,W)}{7\times 10^{10}\,J}\)

\(n = 230.467\)

Up to 230 homes could be heated by the performance of the power plant. \(\blacksquare\)

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The weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.

To calculate the weight of a male African elephant on the moon, we need to use the formula:

Weight = mass × acceleration due to gravity

The mass of the elephant is given as 7,000 kg. However, the acceleration due to gravity on the moon is approximately 1/6th (0.1667) of the acceleration due to gravity on Earth, which is approximately 9.8 m/s².

Weight on the Moon = 7,000 kg × 0.1667 × 9.8 m/s²

Weight on the Moon = 7,000 kg × 1.6386 m/s²

Weight on the Moon ≈ 11,470.2 Newtons

Therefore, the weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.

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Answer:

10.2 km

Explanation:

Displacement is the shortest distance from your original position after movement.

Now, the Zambeef delivery truck moves 18 km north and then 10 km east and then 16 km south.

This means that vertically the truck is 2km short of the 18 km he travelled north..

So we can find the displacement using pythagoras theorem..

Let d be the distance from the current position to the initial position.

Thus;

d² = 2² + 10²

d² = 4 + 100

d = √104

d ≈ 10.2 km

I have attached a diagram showing the direction of this displacement

c) one degree Farenheit

to solve this let's convert 1° C into kelvin and Celsiuts, then,let's compare

Step 1

a) convert 1 °C into Kelvin:

to do that, we need to use the formula

hence

so, one degree Kelvin is smaller than aone degree celsius ( note that 1° C= 238 °K)

Step 2

now, let's convert 1° C into Farenheit

we need to use the formula:

replace and calculate

so

so, one degree Fahrenheit is smaller than aone degree celsius ( note that 1° C= 38.3 °F)

Step 3

finally, compare °F and °K

so, the measure in °F is six times the measure in °K

therefore,

the smaller unit is

c) one degree Fahrenheit

I hope this helps you

Answer:

150   kg-m/s

Explanation:

momentum = m * v

50 * 3 = 150

Answer:

F= 36 N

Explanation:

F= mv^2/r

F= .5*12^2/2

F= ( .5 * 144 )/2

F= 72 / 2

F= 36

The masses of the two objects MA and MB in the binary system are 4 Mo respectively.

The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.

Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:

MA + MB = 8 Mo

We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:

d(A to B) / d(Binary System) = 1/3

We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:

d(A to B) + d(B to binary system) = d(Binary system)

Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):

d(A to B) + 1/3d = d(Binary system)

3d(A to B) + d = 3d(Binary system)

Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:

3d(A to B) + d = 3(d(A to B) + d(B to binary system))

2d(A to B) = 2d(B to binary system)

d(A to B) / d(B to binary system) = 1

So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:

MA = MB

Substituting this into the first equation, we get:

2MA = 8 Mo

MA = MB = 4 Mo

Therefore, the mass of each object is 4 Mo.

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A) When the cord is stretched 16.7 m, the tension in the cord is 18537 N.

b) The work that must be done against the elastic force of the bungee cord to stretch it 16.7 m is 15.48 kJ.

The tension or force in an elastic string is given by the formula:

a) The force or tension in the cord = 111 N/m × 16.7

Tension = 18537 N

b) Work done in a string = ke²/2

where k = 111 N/m, e = 16.7

Work done = 111 × 16.7²/2 = 15,478.395 J

Work done = 15.48 kJ

In conclusion, the force constant of the cord is required to calculate the tension and work done against the elastic force of the cord.

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Answer:

0.00000408

Explanation: